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  • How to color HTML elements based on a user command string

    - by Anonymous the Great
    When you type something like "red:Hi:" it will type "Hi" in red. The following script does not work and I do not know why, (The one who made the sorting PHP function is Graphain, thanks again!) <?php function getit($raw) { # If the value was posted $raw = isset($raw) ? $raw : ""; # Split it based on ':' $parsed = explode(':', $raw); $colorClass = ""; $text = ""; if (count($parsed) >= 2) { $colorClass = $parsed[0]; $text = $parsed[1]; $text = "~~~" . $text . "~~~" . $colorClass; return $text; } } ?> <script type="text/javascript"> function postit() { var preview = document.getElementById("preview").value; var submit = document.getElementById("post").value; var text = <?php getit(submit); ?> var t = text[0]; preview = t; } </script> <textarea id="preview" cols=70 rows=5 readonly>Preview box</textarea> <p> <textarea id="post" cols=70 rows=5/>Submit box</textarea> <p> <input type="button" onclick="postit();" value="Submit"/>

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  • pagination in css/php

    - by fusion
    two questions: --1-- it displays all the number of pages. but i'd like it to display as: << Prev . . 3 4 [5] 6 7 . . Next --2-- when i hover on the current page no, it should change color or increase the font-size, but when i modify the css of a:hover, all the page nos change color or size instead of the one which i'm pointing to. also, when modifying a:active, nothing happens. this is my paging code in php: $self = $_SERVER['PHP_SELF']; $limit = 2; //Number of results per page $numpages=ceil($totalrows/$limit); $query = $query." ORDER BY idQuotes LIMIT " . ($page-1)*$limit . ",$limit"; $result = mysql_query($query, $conn) or die('Error:' .mysql_error()); ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> <div class="searchmain"> <?php //Create and print the Navigation bar $nav=""; $next = $page+1; $prev = $page-1; if($page > 1) { $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('','$prev'); return false;\" href=\"$self?page=" . $prev . "&q=" .urlencode($search_result) . "\">< Prev</a></span>"; $first = "<span class=\"searchpage\"><a onclick=\"showPage('','1'); return false;\" href=\"$self?page=1&q=" .urlencode($search_result) . "\"> << </a></span>" ; } else { $nav .= "&nbsp;"; $first = "&nbsp;"; } for($i = 1 ; $i <= $numpages ; $i++) { if($i == $page) { $nav .= "<span class=\"searchpage\">$i</span>"; }else{ $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('',$i); return false;\" href=\"$self?page=" . $i . "&q=" .urlencode($search_result) . "\">$i</a></span>"; } } if($page < $numpages) { $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('','$next'); return false;\" href=\"$self?page=" . $next . "&q=" .urlencode($search_result) . "\">Next ></a></span>"; $last = "<span class=\"searchpage\"><a onclick=\"showPage('','$numpages'); return false;\" href=\"$self?page=$numpages&q=" .urlencode($search_result) . "\"> >> </a></span>"; } else { $nav .= "&nbsp;"; $last = "&nbsp;"; } echo $first . $nav . $last; ?> </div> and this is how it displays currently: css: .searchmain { margin:30px; text-align: center; } .searchpage { border: solid 1px #ddd; background: #fff; text-align:left; font-size: 16px; padding:9px 12px; color: #FEBE33; margin-left:2px; } .searchpage a{ text-decoration: none; color: #808080; } .searchpage a:hover { color: #FEBE33; border-color: #036; text-decoration: none; } .searchpage a:visited { color: #808080; }

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  • highlighting search results in php error

    - by fusion
    i'm trying to figure out what is wrong in this code. it either doesn't highlight the search result OR it outputs html tags surrounding the highlighted text. . $search_result = ""; $search_result = trim($search_result); $special_cases = array( '%', '_', '+' ); $search_result = str_replace( $special_cases, '', $_GET["q"] ); //Check if the string is empty if ($search_result == "") { echo "<p>Search Error</p><p>Please enter a search...</p>" ; exit(); } $result = mysql_query('SELECT cQuotes, vAuthor, cArabic, vReference FROM thquotes WHERE cQuotes LIKE "%' . mysql_real_escape_string($search_result) .'%" ORDER BY idQuotes DESC', $conn) or die ('Error: '.mysql_error()); //eliminating special characters function h($s) { echo htmlspecialchars($s, ENT_QUOTES); } function highlightWords($string, $word) { $string = str_replace($word, "<span style='background-color: #FFE066;font-weight:bold;'>".$word."</span>", $string); /*** return the highlighted string ***/ return $string; } ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords($row['cQuotes'], $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php h($cQuote); ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> on the browser, it is outputted as: A good <span style='background-color: #FFE066;font-weight:bold;'>action</span> is an ever-remaining store and a pure yield or if a div is used with class: A good <div class='highlight'>action</div> is an ever-remaining store and a pure yield

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  • Cannot send HTML Emails

    - by Zen Savona
    Well I'm trying to send a HTML email using gmail smtp from CI, and it seems to reject my emails when they have any amount of tables. No error is given, they just do not appear in my inbox. If I send an email with light HTML and no tables, they go through. Anyone have any insight? $config = Array( 'protocol' => 'smtp', 'smtp_host' => 'ssl://smtp.googlemail.com', 'smtp_port' => 465, 'smtp_user' => '[email protected]', 'smtp_pass' => '--------', 'mailtype' => 'html', 'charset' => 'iso-8859-1' ); $this->load->library('email', $config); $this->email->set_newline("\r\n"); $this->email->from('myEmail', 'myName'); $this->email->to($this->input->post('email')); $this->email->subject('mySubject'); $msg = $this->load->view('partials/email', '', true); $this->email->message($msg); $this->email->send();`

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  • PHP code displayed in browser

    - by Drake
    so, I'm working on a databases project, and i'm trying to code incrementally. the problem is, when i go to test the php in browser, it displays the php code after my use of "-". the html printing is displayed properly, which is AFTER the point where the - is. here is the php: <?php function getGraphicNovel(){ include_once("./connect.php"); $db_connection = new mysqli($SERVER, $USERNAME, $PASSWORD, $DATABASE); if (mysqli_connect_errno()) { echo("Can't connect to MySQL Server. Error code: " . mysqli_connect_error()); return null; } $stmt = $db_connection->stmt_init(); $returnValue = "invalid"; if($stmt.prepare("select series from graphic_novel_main natural join graphic_novel_misc")) { $stmt->execute(); $stmt->bind_result($series); while ($stmt->fetch()) { echo "<tr><td>" . $series . "</td></tr>"; } $stmt->close(); } $db_connection->close(); } getGraphicNovel(); ?> here is a link to the page. hopefully it works for people outside the school's network. http://plato.cs.virginia.edu/~paw5k/cainedb/viewall.html if anyone knows why this is happening, your input would be great!

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  • PHP database selection issue

    - by Citroenfris
    I'm in a bit of a pickle with freshening up my PHP a bit, it's been about 3 years since I last coded in PHP. Any insights are welcomed! I'll give you as much information as I possibly can to resolve this error so here goes! Files config.php database.php news.php BLnews.php index.php Includes config.php - news.php database.php - news.php news.php - BLnews.php BLnews.php - index.php Now the problem with my current code is that the database connection is being made but my database refuses to be selected. The query I have should work but due to my database not getting selected it's kind of annoying to get any data exchange going! database.php <?php class Database { //------------------------------------------- // Connects to the database //------------------------------------------- function connect() { if (isset($dbhost) && isset($dbuser) && isset($dbpass)) { $con = mysql_connect($dbhost, $dbuser, $dbpass) or die("Could not connect: " . mysql_error()); } }// end function connect function selectDB() { if (isset($dbname) && isset($con)) { $selected_db = mysql_select_db($dbname, $con) or die("Could not select test DB"); } } } // end class Database ?> News.php <?php // include the config file and database class include 'config.php'; include 'database.php'; ... ?> BLnews.php <?php // include the news class include 'news.php'; // create an instance of the Database class and call it $db $db = new Database; $db -> connect(); $db->selectDB(); class BLnews { function getNews() { $sql = "SELECT * FROM news"; if (isset($sql)) { $result = mysql_query($sql) or die("Could not execute query. Reason: " .mysql_error()); } return $result; } ?> index.php <?php ... include 'includes/BLnews.php'; $blNews = new BLnews(); $news = $blNews->getNews(); ?> ... <?php while($row = mysql_fetch_array($news)) { echo '<div class="post">'; echo '<h2><a href="#"> ' . $row["title"] .'</a></h2>'; echo '<p class="post-info">Posted by <a href="#"> </a> | <span class="date"> Posted on <a href="#">' . $row["date"] . '</a></span></p>'; echo $row["content"]; echo '</div>'; } ?> Well this is pretty much everything that should get the information going however due to the mysql_error in $result = mysql_query($sql) or die("Could not execute query. Reason: " .mysql_error()); I can see the error and it says: Could not execute query. Reason: No database selected I honestly have no idea why it would not work and I've been fiddling with it for quite some time now. Help is most welcomed and I thank you in advance! Greets Lemon

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  • How to get session variables from php server with Ajax function? (PHP HTML JS Ajax)

    - by Ole Jak
    so in my php I have something like this $_SESSION['opened'] = true; But It will not be set to true until user will perform some actions with some other html\php pages So I need on some Ajax function to be able get this session variable. And some PHP sample of function to get variable in form ready for Ajax to get it. so I need something to AJAX requesting to an action (to some simple php code) which will return a value from $_SESSION. How to do such thing?

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  • odd url, and difficulty in following the php page flow

    - by sdfor
    I'm trying to understand code that I bought so I can modify it. In the index.php there are picture links: <a href="test10,10"><img title="" border=1 src="makethumb.php?pic=product_images/test101.jpg&amp;w=121&amp;sq=N" / ></a> I don't understand the href since it is not pointing to a page. test10 is an id of a picture. I assumed it was going back to the index.php and the code would extract the test10,10 from the url, but it's not. I know that because I put in trace code as the first line. The question is, where is the link going to? I know it that it somewhere in the process it executes a page called profile.php, but nowhere in the source code (doing a global search) is there an explicit call to profile.php. As a related question, is there a way to profile the code to see what pages it's calling without using xdebug, which for the life of me I can't get working after many hours of trying every suggestion I found here and else where. (I'm using xampp) thanks

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  • undefined offset error in php

    - by user225269
    I don't know why but the code below is working when I have a different query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <?php list($year,$month,$day)=explode("-", $row['BIRTHDAY']); ?> <tr> <td width="30" height="35"><font size="2">Month:</td> <td width="30"><input name="mm" type="text" id="mm" onkeypress="return handleEnter(this, event)" value="<?php echo $month;?>"> <td width="30" height="35"><font size="2">Day:</td> <td width="30"><input name="dd" type="text" id="dd" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $day;?>"> <td width="30" height="35"><font size="2">Year:</td> <td width="30"><input name="yyyy" type="text" id="yyyy" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $year;?>"> And it works when this is my query: $idnum = mysql_real_escape_string($_POST['idnum']); mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); Please help, why do I get the undefined offset error when I use this query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") I assume that the query is the problem because its the only thing that's different between the two.

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  • PHP Ajax not working

    - by Kostis
    I have 3 buttons on my page and depending on which one the user is clickingi want to run through ajax call a delete query in my database. When the user clicks on a button the javascript function seems to work but it doesn't run the query in php script. The html page: <?php session_start(); ?> <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-7"> <script> function myFunction(name) { var r=confirm("Are you sure? This action cannot be undone!"); if (r==true) { alert(name); // check if is getting in if statement and confirm the parameter's value var xmlhttp; if (str.length==0) { document.getElementById("clearMessage").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("clearMessage").innerHTML= responseText; } } xmlhttp.open("GET","clearDatabase.php?q="+name,true); xmlhttp.send(); } else alert('pff'); } </script> </head> <body> <div id="wrapper"> <div id="header"></div> <div id="main"> <?php if (session_is_registered("username")){ ?> <!--<a href="#">???a????s? pa?a??? µ???µ?t??</a><br /> <a href="#">???a????s? pa?a??? s??ed????</a><br /> <a href="#">???a????s? push notifications</a><br />--> <input type="button" value="???a????s? pa?a??? µ???µ?t??" onclick="myFunction('messages')" /> <input type="button" value="???a????s? pa?a??? s??ed????" onclick="myFunction('conferences')" /> <input type="button" value="???a????s? push notifications" onclick="myFunction('notifications')" /> <div id="clearMessage"></div> <?php } else echo "Login first."; ?> </div> <div id="footer"></div> </div> </body> </html> and the php script: <?php if (isset($_GET["q"])) $q=$_GET["q"]; $host = "localhost"; $database = "dbname"; $user = "dbuser"; $pass = "dbpass"; $con = mysql_connect($host,$user,$pass) or die(mysql_error()); mysql_select_db($database,$con) or die(mysql_error()); if ($q=="messages") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="conferences") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="notifications") { $query = "DELETE FROM push_friend WHERE time_sent IS NOT NULL"; } $res = mysql_query($query,$con) or die(mysql_error()); if ($res) echo "success"; else echo "failed"; mysql_close($con); ?>

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  • showing error on uploading a big file using php

    - by user1489969
    I have created a php code to display the upload option to upload multiple files as below: <?php $f_id= $_GET["id"]; ?> <title>Upload File</title> <form enctype="multipart/form-data" method="post" action="upload_hal_mult.php?id=<?php echo $f_id;?>" > <input type="hidden" name="MAX_FILE_SIZE" value="10000000"> <input id="infile" type="file" name="infile[]" multiple="true" /> <input type="submit" value="upload" name="file_uploaded" / > <br> <br> </form> So this will call "upload_hal_mult.php" when "upload" button is clicked. And the code for that is as follows: <title>Upload Results</title> <?php define("MAX_SIZE",10000000); $f_id= $_GET["id"]; $dir_name="dir_hal_".$f_id; $u=0; if (!is_dir($dir_name)) mkdir($dir_name); $dir=$dir_name."/"; $file_realname = $_FILES['infile']['name']; for ($i = 0; $i < count($_FILES['infile']['name']); $i++) { $ext = substr(strrchr($_FILES['infile']['name'][$i], "."), 1); $fname = substr($_FILES['infile']['name'][$i],0,strpos($_FILES['infile']['name'][$i], ".")); $fPath = $fname."_(".substr(md5(rand() * time()),0,4).")".".$ext"; echo "files size=".$_FILES["infile"]["size"][$i]."\n"; if($_FILES["infile"]["size"][$i]>MAX_SIZE) echo('File uploaded exceeds maximum upload size.'); if(($_FILES['infile']['error'][i]==0) && move_uploaded_file($_FILES['infile']['tmp_name'][$i], $dir . $fPath)) { $u=$u+1; ?> <!--<script type="text/javascript">setTimeout("window.close();", 1300);</script>--> <?php echo "Upload is successful\n"; } else echo "if stmt failed so error \n"; } if($u!=count($_FILES['infile']['name'])) echo "Error"; else echo "count is correct"; ?> This upload works correctly for files of size<10MB. But for files of size10MB, it's not echoing 'File uploaded exceeds maximum upload size.' as expected. Its also not uploading the file of size10MB. But the $u gets incremented. But none of the statements like "Upload is successful" or "if stmt failed so error" are being echoed as well. However the statement "count is correct" is being displayed, and this shows the $u got incremented somehow even though the echo statements didnt work! Can someone please point out the error I am doing here? I thought its simply a matter of 'if/else' statements but it seems more than that to me. Please help me out if you have any clue. Thanks

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  • Possible to view PHP code of a website?

    - by Camran
    Is it possible to somehow view another websites php files/codes? Or to rephrase the question, Can my php codes be viewed by anybody except for those who have access to the file? If so, how cant I best prevent this? Thanks Ps: Server OS is Ubuntu 9.10 and PHP version is 5+ (Apache2)

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  • Change HTML DropDown Default Value with a MySQL value

    - by fzr11017
    I'm working on a profile page, where a registered user can update their information. Because the user has already submitted their information, I would like their information from the database to populate my HTML form. Within PHP, I'm creating the HTML form with the values filled in. However, I've tried creating an IF statement to determine whether an option is selected as the default value. Right now, my website is giving me a default value of the last option, Undeclared. Therefore, I'm not sure if all IF statements are evaluation as true, or if it is simply skipping to selected=selected. Here is my HTML, which is currently embedded with PHP(): <select name="Major"> <option if($row[Major] == Accounting){ selected="selected"}>Accounting</option> <option if($row[Major] == Business Honors Program){ selected="selected"}>Business Honors Program</option> <option if($row[Major] == Engineering Route to Business){ selected="selected"}>Engineering Route to Business</option> <option if($row[Major] == Finance){ selected="selected"}>Finance</option> <option if($row[Major] == International Business){ selected="selected"}>International Business</option> <option if($row[Major] == Management){ selected="selected"}>Management</option> <option if($row[Major] == Management Information Systems){ selected="selected"}>Management Information Systems</option> <option if($row[Major] == Marketing){ selected="selected"}>Marketing</option> <option if($row[Major] == MPA){ selected="selected"}>MPA</option> <option if($row[Major] == Supply Chain Management){ selected="selected"}>Supply Chain Management</option> <option if($row[Major] == Undeclared){ selected="selected"}>Undeclared</option> </select>

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  • Easiest way to submit data via PHP?

    - by Abijah
    I'm new to PHP, and have spent 10 hours trying to figure this problem out. The goal is to take all data entered into this order form, and send it to my email via PHP. I have 2 questions: 1. I can get PHP to send data from a single menu item (example: Mexican Tortas), but how do I get PHP to send data from multiple items (example: Mexican Tortas, Fish Sandwich and Hamburger)? 2. How do I tell PHP to not send data from menu items that don't have the "How Many?" or "Customize It?" text fields filled out? If you could provide a super simple example (or a link to a learning resource) I would really appreciate it. Thank you, Abijah PHP <?php if(isset($_POST['submit'])) { $to = "[email protected]"; $subject = "New Order"; $name_field = $_POST['name']; $phone_field = $_POST['phone']; $item = $_POST['item']; $quantity = $_POST['quantity']; $customize = $_POST['customize']; } $body = "Name: $name_field\nPhone: $phone_field\n\nItem: $item\nQuantity: $quantity\nCustomize: $customize"; echo "Data has been submitted to $to!"; mail($to, $subject, $body); ?> HTML <form action="neworder.php" method="POST"> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/mexicantortas.jpg"> <h1>Mexican Torta - $8.50</h1> <input name="item" type="hidden" value="Mexican Torta"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/fishsandwich.jpg"> <h1>Fish Sandwich - $8.50</h1> <input name="item" type="hidden" value="Fish Sandwich"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/hamburgers.jpg"> <h1>Hamburger w/ Fries - $7.00</h1> <input name="item" type="hidden" value="Fish Sandwich"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class="horizontal_form"> <div class="form"> <h2>Place Your Order Now: <font size="3"><font color="#037B41">Fill in the form below, and we'll call you when your food is ready to be picked up...</font></font></h2> <p class="name"> <input type="text" name="name" id="name" style="text-align:center;" onClick="this.value='';" value="Enter your name"/> </p> <p class="phone"> <input type="text" name="phone" id="phone" style="text-align:center;" onClick="this.value='';" value="Enter your phone #"/> </p> <p class="submit"> <input type="submit" value="Place Order" name="submit"/> </p> </div><!-- FORM --> </div><!-- HORIZONTAL_FORM --> </form>

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  • Pass a variable from javascript to php in the same session OnClickFunction

    - by MickyScion
    I was seeing through stackoverflow the solutions for this kind of problems but any of them are executing the code of javascript in the same session...please i want some help with this...i have this in my session <script> function show_alert() { var ProdAntes = document.getElementById("productoseleccionado").value; var CantAntes = document.getElementById("cantidadantes").value; var PrecAntes = document.getElementById("precioantes").value; var FecAntes = document.getElementById("fechaantes").value; var ProdAhora = document.getElementById("SoyaProductorProduccionProducto").value; var CantAhora = document.getElementById("SoyaProductorProduccionCantidadtm").value; var PrecAhora = document.getElementById("SoyaProductorProduccionPreciodolar").value; var FecAhora = document.getElementById("select_date").value; } </script> and in my html stuff i have this <?php echo $this->Form->create('SoyaProductorProduccion');?> <fieldset> <?php echo $this->Form->hidden('id', array('value' => $this->data['SoyaProductorProduccion']['id'])); echo $this->Form->input('operacion', array('type' => 'hidden', 'value'=>'Produccion')); //-------------------------------------------------------------- $productoseleccionado = $this->data['SoyaProductorProduccion']['producto']; echo $this->Form->input('productoseleccionado', array('type' => 'hidden','style'=>'width:500px; height:30px;','id' => 'productoseleccionado' , 'value' => $productoseleccionado)); echo $this->Form->input('producto', array( 'options' => array( $productoseleccionado => $productoseleccionado, 'Torta solvente de soya' => 'Torta solvente de soya', 'Torta solvente de girasol' => 'Torta solvente de girasol', 'Harina integral de soya' => 'Harina integral de soya', 'Harina de girasol' => 'Harina de girasol', 'Cascarilla de soya' => 'Cascarilla de soya', 'Cascarilla de girasol' => 'Cascarilla de girasol', 'Aceite de soya refinado' => 'Aceite de soya refinado', 'Aceite de soya crudo' => 'Aceite de soya crudo', 'Aceite de girasol refinado' => 'Aceite de girasol refinado', 'Aceite de girasol crudo' => 'Aceite de girasol crudo', ),'label'=>'Tipo de Producto' )); foreach ($soyacambiodolares as $soyacambiodolar): $dolar=$soyacambiodolar['SoyaCambioDolar']['cambio']; endforeach; echo $this->Form->input('cambio', array('type' => 'hidden','value' => $dolar)); //----------------------------------------------------------------------------- $cantidadantes = $this->data['SoyaProductorProduccion']['cantidadtm']; echo $this->Form->input('cantidadantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $cantidadantes,'id' => 'cantidadantes')); echo $this->Form->input('cantidadtm', array('label' => 'Cantidad en tonelada(s) métrica(s) del producto (TM)','style'=>'width:500px; height:30px;')); //----------------------------------------------------------------------------- $precioantes = $this->data['SoyaProductorProduccion']['preciodolar']; echo $this->Form->input('precioantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $precioantes,'id' => 'precioantes')); echo $this->Form->input('preciodolar', array('label' => 'Precio en Dolares Americanos por tonelada métrica (TM / $us)','style'=>'width:500px; height:30px;')); //----------------------------------------------------------------------------- ?> <table style="width: 600px"> <tr> <td > <?php //---------------------------------------------------------------- $fechaantes = $this->data['SoyaProductorProduccion']['fecharegistro']; echo $this->Form->input('fechaantes', array('type' => 'hidden','style'=>'width:500px; height:30px;', 'value' => $fechaantes, 'id' => 'fechaantes')); //---------------------------------------------------------------- echo $this->Form->input("fecharegistro", array( 'label' => '<strong>Periodo al que corresponde la declaración</strong>', 'type' => 'text', 'style' => 'width: 110px', 'class' => 'fl tal vat w300p', 'error' => false , 'id' => 'select_date')); ?> <?php echo $this->Html->div('datepicker_img w100p fl pl460p pa', $this->Html->image('datepicker_calendar_icon.gif'),array('id' => 'datepicker_img')); ?> <?php echo $this->Html->div('datepicker fl pl460p pa', ' ' ,array('id' => 'datepicker')); ?> </td> </tr> </table> <?php echo $this->Form->submit('Modificar Existencia', array('class' => 'form-submit', 'title' => 'Presione aqui para agregar datos', 'onclick' => 'return show_alert();')); ?> </fieldset> <?php echo $this->Form->end(); ?> my function is ok but i want these: when i click the submit button i want to compare wich field had been changed, and i want to create a chain of detailed changes like "change in the field 1, change in the fiel 2.--" and so on...and this has to be saved in my database so i have to pass to a variable in my php before saving...thanks!

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  • Possibly simple PHP/MYSQL issue with retrieving and showing data

    - by envoys
    I have been racking my brains over this for a while now. Here is the data i have in the sql data base as an example: ID | TYPE | DATA 1 | TXT | TEST 2 | PHP | php 3 | JS | JAVASCRIPT That is just an example, there are multiple listing for TXT, PHP and JS throughout the table. What I want to do is retrive all the data and display it all into separate drop down/select boxes. Meaning, select box one would list all data with type TXT, select box two would list all data with type PHP and select box 3 would list all data with type JS. The only way I have came about doing this is doing individual sql queries for each different type. I know there is a way to do it all in 1 query and then display it the way I want to but I just can't seem to figure out how and I know its going to drive me nuts when someone helps and I see just how they did it. Thanks for the input.

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  • How can I make this script output each categories item per category [closed]

    - by Duice352
    Ok so here is the deal currently this script outputs all the products in a parent category as well as the products in the child categories. What i would like to do is seperate the output based on child categories. All the child categories are in the array $children and the string $childs. The parent category is the first array element of $children with the following ones being the actual children. The category names are stored in the database $result as " $cat_name ". I want to first Display the cat_name then the products that fall in that category and then display the next child cat_name and items, ect. Any suggestions of how to manipulate the while loop that cylcles through the rows? <?php $productsPerRow = 3; $productsPerPage = 15; //$productList = getProductList($catId); $children = array_merge(array($catId), getChildCategories(NULL, $catId)); $childs = ' (' . implode(', ', $children) . ')'; $sql = "SELECT pd_id, pd_name, pd_price, pd_thumbnail, pd_qty, c.cat_id, c.cat_name FROM tbl_product pd, tbl_category c WHERE pd.cat_id = c.cat_id AND pd.cat_id IN $childs ORDER BY pd_name"; $result = dbQuery(getPagingQuery($sql, $productsPerPage)); $pagingLink = getPagingLink($sql, $productsPerPage, "c=$catId"); $numProduct = dbNumRows($result); // the product images are arranged in a table. to make sure // each image gets equal space set the cell width here $columnWidth = (int)(100 / $productsPerRow); ?> <p><?php if(isset($_GET['m'])){echo "You must select a model first! After you select your model you can customize your dragster parts.";} ?> </p> <p align="center"><?php echo $pagingLink; ?></p> <table width="100%" border="0" cellspacing="0" cellpadding="20"> <?php if ($numProduct > 0 ) { $i = 0; while ($row = dbFetchAssoc($result)) { extract($row); if ($pd_thumbnail) { $pd_thumbnail = WEB_ROOT . 'images/product/' .$pd_thumbnail; } else { $pd_thumbnail = 'images/no-image-small.png'; } if ($i % $productsPerRow == 0) { echo '<tr>'; } // format how we display the price $pd_price = displayAmount($pd_price); echo "<td width=\"$columnWidth%\" align=\"center\"><a href=\"" . $_SERVER['PHP_SELF'] . "?c=$catId&p=$pd_id" . "\"><img src=\"$pd_thumbnail\" border=\"0\"><br>$pd_name</a><br>Price : $pd_price <br> $cat_id - $cat_name"; // if the product is no longer in stock, tell the customer if ($pd_qty <= 0) { echo "<br>Out Of Stock"; } echo "</td>\r\n"; if ($i % $productsPerRow == $productsPerRow - 1) { echo '</tr>'; } $i += 1; } if ($i % $productsPerRow > 0) { echo '<td colspan="' . ($productsPerRow - ($i % $productsPerRow)) . '">&nbsp;</td>'; }

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  • How can I change the color of the text in my iFrame? [closed]

    - by VinylScratch
    I have code here: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title>Frag United Banlist</title> </head> <body> <h1>Tekkit Banlist</h1> <?php // change these things $server = "server-host"; $dbuser = "correct-user"; $dbpass = "correct-password"; $dbname = "correct-database"; mysql_connect($server, $dbuser, $dbpass); mysql_select_db($dbname); $result = mysql_query("SELECT * FROM banlist ORDER BY id DESC"); //This will display the most recent by id edit this query how you see fit. Limit, Order, ect. echo "<table width=100% border=1 cellpadding=3 cellspacing=0>"; echo "<tr style=\"font-weight:bold\"> <td>ID</td> <td>User</td> <td>Reason</td> <td>Admin/Mod</td> <td>Time</td> <td>Ban Length</td> </tr>"; while($row = mysql_fetch_assoc($result)){ if($col == "#eeeeee"){ $col = "#ffffff"; }else{ $col = "#eeeeee"; } echo "<tr bgcolor=$col>"; echo "<td>".$row['id']."</td>"; echo "<td>".$row['user']."</td>"; echo "<td>".$row['reason']."</td>"; echo "<td>".$row['admin']."</td>"; //Convert Epoch Time to Standard format $datetime = date("F j, Y, g:i a", $row['time']); echo "<td>$datetime</td>"; $dateconvert = date("F j, Y, g:i a", $row['length']); if($row['length'] == "0"){ echo "<td>None</td>"; }else{ echo "<td>$dateconvert</td>"; } echo "<td>".$row['id']."</td>"; echo "</tr>"; } echo"</table>" ?> </div> </body></html> And I am trying to make it so that when I put it in this iframe: <iframe src="http://bans.fragunited.net/" width="100%" length="100%"><p>Your browser does not support iframes.</p></iframe> But if you go to this page, fragunited.net/bans, (not bans.fragunited.net) the text is black and I want it to be white so you can actually see it. Sorry for the large amount of code, however I don't know where you have to put the code to change the color.

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  • Re: How can Django/WSGI and PHP share / on Apache?

    - by Bogdan
    in response to: How can Django/WSGI and PHP share / on Apache? Hello, could you please post the complete config file from /sites-available I am having a problem seems like rewrite engine redirects all requests to django, so static and php files are not served and instead i see the django 404 page. If I get rid of rewrite rule then static files and php works. here is my apache config file from /sites-available <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /home/www/django <Directory /> Options +FollowSymLinks ExecCGI Indexes AllowOverride None DirectoryIndex index.php AddHandler wsgi-script .wsgi </Directory> RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ /mysite.wsgi/$1 [QSA,PT,L] ~ and my .wsgi file: import site site.addsitedir('/home/user/.virtualenvs/url.com/lib/python2.6/site-packages') import os, sys path = '/home/www/django' if path not in sys.path: sys.path.append(path) os.environ['DJANGO_SETTINGS_MODULE'] = 'mysite.settings' sys.path.append(path + '/mysite') import django.core.handlers.wsgi _application = django.core.handlers.wsgi.WSGIHandler() import posixpath def application(environ, start_response): # Wrapper to set SCRIPT_NAME to actual mount point. environ['SCRIPT_NAME'] = posixpath.dirname(environ['SCRIPT_NAME']) if environ['SCRIPT_NAME'] == '/': environ['SCRIPT_NAME'] = '' return _application(environ, start_response) the document root directory on disk (/home/www/django) contains php files, images, and the mysite.wsgi file.. thanks for your help

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  • How to install PHP, Pear, PECL, and APC with Homebrew on Mac OS X?

    - by Andrew
    I'm trying to install APC for PHP 5.3 in the easiest way possible. I love Homebrew so I started down that route. I was able to install PHP 5.3.6 with this command: brew install https://github.com/adamv/homebrew-alt/raw/master/duplicates/php.rb --with-mysql I think this is supposed to install PHP, Pear, and PECL. It seems to install these just fine. Now when I try to install APC: $ pecl install apc downloading APC-3.1.9.tgz ... Starting to download APC-3.1.9.tgz (155,540 bytes) .................................done: 155,540 bytes Warning: require_once(Archive/Tar.php): failed to open stream: No such file or directory in PackageFile.php on line 305 Warning: require_once(Archive/Tar.php): failed to open stream: No such file or directory in /usr/local/Cellar/php/5.3.6/lib/php/PEAR/PackageFile.php on line 305 Fatal error: require_once(): Failed opening required 'Archive/Tar.php' (include_path='/usr/local/Cellar/php/5.3.6/lib/php') in /usr/local/Cellar/php/5.3.6/lib/php/PEAR/PackageFile.php on line 305 How can I fix this?

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  • Nginx redirect all request that does not match a file to a php file

    - by cyrbil
    I'm trying to get all request to: http://mydomain.com/downloads/* redirect to http://mydomain.com/downloads/index.php except if the requested file exist in /downloads/ ex: http://mydomain.com/downloads = /downloads/index.php http://mydomain.com/downloads/unknowfile = /downloads/index.php http://mydomain.com/downloads/existingfile = /downloads/existingfile My current problem is I have either the redirection to php working but static files not served or the opposite. Here is my current vhost conf: (which redirect fine but static files are send to php and fail) server { listen 80; ## listen for ipv4; this line is default and implied server_name domain.com; root /data/www; index index.php index.html; location / { try_files $uri $uri/ /index.html; } error_page 404 /404.html; # redirect server error pages to the static page /50x.html error_page 500 502 503 504 /50x.html; location = /50x.html { root /usr/share/nginx/www; } location ^~ /downloads { fastcgi_pass unix:/var/run/php5-fpm.sock; fastcgi_split_path_info ^(.+\.php)(/.+)$; fastcgi_index index.php; include fastcgi_params; try_files $uri @downloads; } location @downloads { rewrite ^ /downloads/index.php; } # pass the PHP scripts to FastCGI server # location ~ \.php$ { try_files $uri =404; fastcgi_split_path_info ^(.+\.php)(/.+)$; fastcgi_pass unix:/var/run/php5-fpm.sock; fastcgi_index index.php; include fastcgi_params; } } Precision: static files are symlinks created by /downloads/index.php Thank you for your help.

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  • Working with different PHP version at the same time, php_value extension_dir not working?

    - by Gremo
    I need both PHP 5.4.7 and 5.3.17 running on Windows 7 x64 with Apache 2.2.23. This is my virtual host configuration: <VirtualHost *:80> DocumentRoot "C:/WAMP/Apache/htdocs/php54" ServerName php54.local PHPIniDir "C:/WAMP/PHP54" LoadModule php5_module "C:/WAMP/PHP54/php5apache2_2.dll" php_value extension_dir "C:/WAMP/PHP54/ext" <Directory "C:/WAMP/Apache/htdocs/php54"> Order allow,deny Allow from all </Directory> </VirtualHost> The PHPIniDir and LoadModule directives work fine and using phpinfo() inside my script prints the right PHP version. But I need to load extensions, and this is where it fails. php_value extension_dir should be C:/WAMP/PHP54/ext but it's (default one) C:/php. What I'm missing here? EDIT: Of course I can set this value directly in C:/WAMP/PHP54/php.ini, but I prefer passing it using vhost configuration: ; Directory in which the loadable extensions (modules) reside. ; http://php.net/extension-dir ; extension_dir = "./" ; On windows: extension_dir = "C:/WAMP/PHP54/ext"

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