Search Results

Search found 36756 results on 1471 pages for 'mysql real query'.

Page 230/1471 | < Previous Page | 226 227 228 229 230 231 232 233 234 235 236 237  | Next Page >

  • In MYSQL is it better to have one big table or many smaller tables

    - by user307922
    Hi All, I am making a database of my client's customers to send email promotions to. The database will include all about 12 of my clients and each of them has an average of 2100 customers. I was wondering if it would be better to have a table in the db for each one of my clients that contains a list of their customers or if I should just make one big table... The customers will be queried daily. I know it is a broad question but any advice would be appreciated. Cheers, Chuck

    Read the article

  • Strange use of the index in Mysql

    - by user309067
    explain SELECT feed_objects.* FROM feed_objects WHERE (feed_objects.feed_id IN (165,160,159,158,157,153,152,151,150,149,148,147,129,128,127,126,125,124,122,121,120,119,118,117,116,115,114,113,111,110)) ; +----+-------------+--------------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+--------------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | feed_objects | ALL | by_feed_id | NULL | NULL | NULL | 188 | Using where | +----+-------------+--------------+------+---------------+------+---------+------+------+-------------+ Not used index 'by_feed_id' But when I point less than the values in the "WHERE" - everything is working right explain SELECT feed_objects.* FROM feed_objects WHERE (feed_objects.feed_id IN (165,160,159,158,157,153,152,151,150,149,148,147,129,128,127,125,124)) ; +----+-------------+--------------+-------+---------------+------------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+--------------+-------+---------------+------------+---------+------+------+-------------+ | 1 | SIMPLE | feed_objects | range | by_feed_id | by_feed_id | 9 | NULL | 18 | Using where | +----+-------------+--------------+-------+---------------+------------+---------+------+------+-------------+ Used index 'by_feed_id' What is the problem?

    Read the article

  • mysql query help please

    - by moustafa
    i have forum_topics table and have topics_posts table now i want to select from forum_topics where have no posts from topics_posts can any one give me the one syntax like this selct from * forum_topics where have no rows in topics_posts table

    Read the article

  • PHP MySQL Select multiple tables

    - by Jordan Pagaduan
    Is it posibble to select 3 tables at a time in 1 database? Table 1: employee -- employee_id -- first_name -- last_name -- middle_name -- birthdate -- address -- gender -- image -- salary Table 2: logs -- log_id -- full_name -- employee_id -- date -- time -- status Table 2: logout -- log_id -- full_name -- employee_id -- date -- time -- status I wanted to get the value of employee table where $id of selected. Then the $id also get the value of log.time, log.date, logout.time, and logout.date. I already try using UNION but nothing happens.

    Read the article

  • Why won't this sql update query work?

    - by Wesley
    I have a table that has 5,000(table1) lines in it. Currently, 3,000 of them are filled up with data. The remaining values are currently null. In a separate table(table2), I have the remaining 2,000 rows of data. I am simply trying to take the values in table2 and put them in table1, but this statement isn't working: Update table1 Set field1 = (Select field1 From table2 Where table1.id = table2.id) Where Exists(Select field1 From table2 Where table1.id = table2.id) It looks like this should be working, but I am getting an error from Base, the db program I am using that just says error Near " ": syntax error...any help?? Thanks!

    Read the article

  • mysql insert and buffers, is this possible

    - by Grumpy
    how is this possible first i do insert into table2 select * from table1 where table1.id=1 ( 50k records should be moved 6 indexes has to be updated ) second delete from table1 where id=1 ( 50k records are removed ) How is it possible that only 45k of records are moved? Im scratching my head over this and cant find a right answer Is it possible that the insert is still active and delete already started

    Read the article

  • How to query MYSQL when clicked?

    - by Sam
    Hello, I have a while statement, echoing my whole database that match a WHERE parameter. How can I make it so when I click on something (anything for the moment), it updates that specific row. Here's my code. while($request = mysql_fetch_array( $request_db )) { echo "<tr><td style=\"width:33%;padding:1px;\">"; echo $request['SongName']; echo "</td><td style=\"width:33%;\">"; echo $request['Artist']; echo "</td><td style=\"width:33%;\">"; echo $request['DedicatedTo']; echo "</td><td style=\"width:33%;\">"; echo "UPDATE A ROW's 'Hasplayed' value to '1'."; echo "</td></tr>"; } echo "</table>"; Thanks!

    Read the article

  • mysql stored funtion usage

    - by shikhar
    I just wrote a stored function to calculate the working days between two dates. This works select CountWeekDays('2010-03-07','2010-04-07') This doesn't work select CountWeekDays(o.order_date,o.created_date) from orders o; Any idea how to make this one work ?? function definition delimiter $$; CREATE FUNCTION CountWeekDays (sdate VARCHAR(50), edate VARCHAR(50)) RETURNS INT BEGIN DECLARE wdays, tdiff, counter, thisday smallint; DECLARE newdate DATE; SET newdate := sdate; SET wdays = 0; if DATEDIFF(edate, sdate) = 0 THEN RETURN 1; END IF; if DATEDIFF(edate, sdate) < 0 THEN RETURN 0; END IF; label1: LOOP SET thisday = DAYOFWEEK(newdate); IF thisday BETWEEN 2 AND 6 THEN SET wdays := wdays + 1; END IF; SET newdate = DATE_ADD(newdate, INTERVAL 1 DAY); IF DATEDIFF(edate, newdate) < 0 THEN LEAVE label1; END IF; END LOOP label1; RETURN wdays; END

    Read the article

  • csv file upload and update mysql db

    - by Indra
    I am very to new to php. i am using the following code to open a csv file and update my database. i need to check the value of first row-first column of the csv file. if it is matching "some text 1", then i need to run code1, if it is "some text 2", run code2, else code3. I can use if else condition but since i am using while loop It fails. Can anyone help me. $handle = fopen($file_tmp,"r"); while(($fileop = fgetcsv($handle,",")) !== false) { // I need to check here $companycode = mysql_real_escape_string($fileop[0]); $Item = mysql_real_escape_string($fileop[3]); $pack = preg_replace('/[^A-Za-z0-9\. -]/', '', $fileop[4]); $lastmonth = mysql_real_escape_string($fileop[5]); $ltlmonth = mysql_real_escape_string($fileop[6]); $op = mysql_real_escape_string($fileop[9]); $pur = mysql_real_escape_string($fileop[10]); $sale = mysql_real_escape_string($fileop[12]); $bal = mysql_real_escape_string($fileop[17]); $bval = mysql_real_escape_string($fileop[18]); $sval = mysql_real_escape_string($fileop[19]); $sq1 = mysql_query("INSERT INTO `sas` (companycode,Item,pack,lastmonth,ltlmonth,op,pur,sale,bal,bval,sval) VALUES ('$companycode','$Item','$pack','$lastmonth','$ltlmonth','$op','$pur','$sale','$bal','$bval','$sval')"); }

    Read the article

  • MySQL: SELECT highest column value when WHERE finds similar entries

    - by Ike
    My question is comparable to this one, but not quite the same. I have a database with a huge amount of books, with different editions of some of the same book titles. I'm looking for an SQL statement giving me the highest edition number of each of the titles I'm selecting with a WHERE clause (to find specific book series). Here's what the table looks like: |id|title |edition|year| |--|-------------------------|-------|----| |01|Serie One Title One |1 |2007| |02|Serie One Title One |2 |2008| |03|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |05|Serie One Title Three |1 |2008| |06|Serie One Title Three |2 |2009| |07|Serie One Title Three |3 |2010| |08|Serie One Title Three |4 |2011| |--|-------------------------|-------|----| The result I'm looking for is this: |id|title |edition|year| |--|-------------------------|-------|----| |03|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |08|Serie One Title Three |4 |2011| |--|-------------------------|-------|----| The closest I got was using this statement: select id, title, max(edition), max(year) from books where title like "serie one%" group by name; but it returns the highest edition and year and includes the first id it finds: |--|-----------------------|-------|----| |01|Serie One Title One |3 |2009| |04|Serie One Title Two |1 |2001| |05|Serie One Title Three |4 |2011| |--|-----------------------|-------|----| This fancy join also comes close, but doesn't give the right result: select b.id, b.title, b.edition, b.year from books b inner join (select name, max(edition) as maxedition from books group by title) g on b.edition = g.maxedition where b.title like "serie one%" group by title; Using this I'm getting unique titles, but mostly old editions.

    Read the article

  • select mysql data using MAX

    - by JPro
    I have a testdata like this: DROP TABLE SELECT_PASS; CREATE TABLE SELECT_PASS(ID INT(20),TESTCASE VARCHAR(20),RESULT VARCHAR(20)); INSERT INTO SELECT_PASS VALUES(1,"TC1","PASS"); INSERT INTO SELECT_PASS VALUES(2,"TC2","PASS"); INSERT INTO SELECT_PASS VALUES(3,"TC3","INCONC"); INSERT INTO SELECT_PASS VALUES(4,"TC1","FAIL"); INSERT INTO SELECT_PASS VALUES(5,"TC21","FAIL"); INSERT INTO SELECT_PASS VALUES(6,"TC4","PASS"); INSERT INTO SELECT_PASS VALUES(7,"TC3","PASS"); INSERT INTO SELECT_PASS VALUES(8,"TC2","PASS"); INSERT INTO SELECT_PASS VALUES(9,"TC1","TIMEOUT"); SELECT TESTCASE, MAX(RESULT) FROM SELECT_PASS GROUP BY TESTCASE; The resultset I get is : TC1 TIMEOUT TC2 PASS TC21 FAIL TC3 PASS TC4 PASS Basically I want to see those testcases which never passed. Any way to do it? Thanks.

    Read the article

  • SQL query: Last but one rank for user

    - by Derk
    My table structure looks like this: create table rankings ( id IDENTITY NOT NULL, user_id INT NOT NULL, game_poule_id INT NOT NULL, rank INT NOT NULL, insertDate DATETIME NOT NULL, FOREIGN KEY (user_id) REFERENCES users(id) ON DELETE CASCADE, FOREIGN KEY (game_poule_id) REFERENCES game_poules(id) ON DELETE CASCADE ); All old rankings of users per game are saved in this table. Now I want to have the last but one rank in the table for all users in a gamepoule. Has someone an idea how to achive this? Thanks

    Read the article

  • Failed to execute stored procedure from the JDBC code using mysql connection

    - by Purushotham
    Hi, I have one database. I executed a stored procedure on it. I wrote some JDBC code to connect to this database. When I am calling this stored procedure from my JDBC code it is throwing SQLException. One interesting thing I found is that I have one user other than root user. This user has all the privileges to this database where the stored procedure is present. When I use the root user I am able to call the stored procedure successfully. But with the other user I am getting SQLexception. I am not able to find why it happens like this. For sure I want this user(other than root) has to call this stored procedure successfully. Thanks in advance.

    Read the article

  • Adding with PHP to a MySQL database

    - by shinjuo
    I am pretty new to PHP and I am trying to make an inventory database. I have been trying to make it so that a user can enter a card ID and then amount the want to add to the inventory and have it update the inventory. For example someone could type in test and 2342 and it would update test. Here is what I have been trying with no success: add.html <body> <form action="add.php" method="post"> Card ID: <input type="text" name="CardID" /> Amount to Add: <input type="text" name="Add" /> <input type="submit" /> </form> </body> </html> add.php <?php $link = mysql_connect('tulsadir.ipowermysql.com', 'cbouwkamp', '!starman1'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("tdm_inventory", $link); $add = $_POST[Add] mysql_query("UPDATE cardLists SET AmountLeft = '$add' WHERE cardID = 'Test'"); echo "test successful"; mysql_close($link); ?>

    Read the article

  • mysql get table based on common column between two tables

    - by Zentdayn
    while trying to learn sql i came across "Learn SQL The Hard Way" and i started reading it. Everything was going fine then i thought ,as a way to practice, to make something like given example in the book (example consists in 3 tables pet,person,person_pet and the person_pet table 'links' pets to their owners). I made this: report table +----+-------------+ | id | content | +----+-------------+ | 1 | bank robbery| | 2 | invalid | | 3 | cat on tree | +----+-------------+ notes table +-----------+--------------------+ | report_id | content | +-----------+--------------------+ | 1 | they had guns | | 3 | cat was saved | +-----------+--------------------+ wanted result +-----------+--------------------+---------------+ | report_id | report_content | report_notes | +-----------+--------------------+---------------+ | 1 | bank robbery | they had guns | | 2 | invalid | null or '' | | 3 | cat on tree | cat was saved | +-----------+--------------------+---------------+ I tried a few combinations but no success. My first thought was SELECT report.id,report.content AS report_content,note.content AS note_content FROM report,note WHERE report.id = note.report_id but this only returns the ones that have a match (would not return the invalid report). after this i tried adding IF conditions but i just made it worse. My question is, is this something i will figure out after getting past basic sql or can this be done in simple way? Anyway i would appreciate any help, i pretty much lost with this. Thank you. EDIT: i have looked into related questions but havent yet found one that solves my problem. I probably need to look into other statements such as join or something to sort this out.

    Read the article

  • JSON Array Created in PHP/MySQL incorrectly decoded using JQuery

    - by Zak
    I am attempting to make an AJAX call to a very small PHP script that should return me an array that could be echo'd and decoded using JQuery. Here is what I have: My PHP page called to by AJAX: $web_q=mysql_query("select * from sec_u_g where uid='$id' "); $rs = array(); while($rs[] = mysql_fetch_assoc($web_q)) { } print_r(json_encode($rs)); This outputs: [{"id":"3","uid":"39","gid":"16"},{"id":"4","uid":"39","gid":"4"},{"id":"5","uid":"39","gid":"5"},{"id":"6","uid":"39","gid":"6"},{"id":"7","uid":"39","gid":"7"},{"id":"8","uid":"39","gid":"8"},{"id":"9","uid":"39","gid":"9"},false] I don't understand the "false" at the end for one .. But then I send to to JQuery and use: $.each(json.result, function(i, object) { $.each(object, function(property, value) { alert(property + "=" + value); }); }); This just fails. I try to alert "result" by itself which is set by: $.post("get_ug.php",{id:txt},function(result){ }); My output alerts are as follows: 1) The key is '0' and the value is '[' 2) The key is '1' and the value is 'f' 3) The key is '2' and the value is 'a' 4) The key is '3' and the value is 'l' 5) The key is '4' and the value is 's' 6) The key is '5' and the value is 'e' 7) The key is '6' and the value is ']' 8) The key is '7' and the value is ' ' (<-- Yes the line break is there in the alert) I am exhausted from trying different ideas and scripts. Other than setting a delimiter myself and concatenating my own array and decoding it with a custom script, does anyone have any ideas?? Thank you!!

    Read the article

  • MySQL: 4 Table "has-many-through" Join?

    - by Nebs
    Let's say I have the following 4 tables (for examples' sake): Owners, Trucks, Boxes, Apples. An owner can have many trucks, a truck can have many boxes and a box can have many apples. Owners have an id. Trucks have an id and owner_id. Boxes have an id and truck_id. Apples have an id and box_id. Let's say I want to get all the apples "owned" by an owner with id = 34. So I want to get all the boxes that are in boxes that are in trucks that owner 34 owns. There is a "hierarchy" if you will of 4 tables that each only has reference to its direct "parent". How can I quickly filter boxes while satisfying conditions across the other 3 tables? I hope that made sense somewhat. Thanks.

    Read the article

< Previous Page | 226 227 228 229 230 231 232 233 234 235 236 237  | Next Page >