Search Results

Search found 12055 results on 483 pages for 'password complexity'.

Page 230/483 | < Previous Page | 226 227 228 229 230 231 232 233 234 235 236 237  | Next Page >

  • Getting rid of the Expires node (xml) in the WS security header

    - by Nick
    From the snippet below, how do i get rid of the (xml node) <wsu:Expires> tag? I want to either get rid of it or pass it in as a empty element. It is a read only property in objClient.RequestSoapContext.Security.Timestamp.Expires. Any help is appreciated. <wsse:Security soap:mustUnderstand="1"> <wsu:Timestamp wsu:Id="Timestamp-26d09d54-10ef-4141-aa2c-11c75ed8172b"> <wsu:Created>2010-03-08T15:32:16Z</wsu:Created> <wsu:Expires>2010-03-08T15:37:16Z</wsu:Expires> </wsu:Timestamp> <wsse:UsernameToken xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" wsu:Id="SecurityToken-7c9b80ec-98e9-4e41-af2e-ad37070cbdd3"> <wsse:Username>bubba</wsse:Username> <wsse:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordDigest">dsfdfsdfsfs+-dasdf=</wsse:Password> <wsse:Nonce>QQ3C4HUfO2CyGx7HrjzMzg==</wsse:Nonce> <wsu:Created>2010-03-08T15:32:16Z</wsu:Created> </wsse:UsernameToken> </wsse:Security>

    Read the article

  • Can't send an email using a google apps account with PHPMailer

    - by Chris
    I'm trying to simply send an email using my google apps account with php. I am able to send an email in a .net application using the port 587 host smtp.googlemail.com and SSL enabled. The username is my full email address. require_once('PHPMailer_v5.1\class.phpmailer.php'); try { $mail = new PHPMailer(); $mail->Mailer = 'smtp'; $mail->SMTPSecure = 'tls'; $mail->Host = $host; $mail->Port = 587; $mail->SMTPAuth = true; $mail->Username = $from; $mail->Password = $password; $mail->AddAddress($to, $to_name); $mail->From = $from; $mail->FromName = $from_name; $mail->Subject = $subject; $mail->MsgHTML($body); $mail->IsHTML(true); $mail->Send(); } catch (phpmailerException $e) { echo $e->errorMessage(); } catch (Exception $e) { echo $e->getMessage(); } Haven't been able to get this to work, but I've tried several different variations of this. $mail->SMTPSecure = 'ssl'; // Error: Could not connect to SMTP host. $mail->SMTPSecure = 'tls'; // Takes forever, then I get "this stream does not support SSL/crypto PHPMailer_v5.1\class.smtp.php" I don't care how, but I need to send an email using gmail here. It can be with this library or a different one.

    Read the article

  • Problem in encoding and decoding the string in Iphone sdk

    - by monish
    HI Guys, Here I am having a problem In encoding/decoding the strings. Actually I had a string which I am encoding it using the base64.which was working fine. And now I need to decode the string that was encoded before and want to print it. I code I written as: I imported the base64.h and base64.m files into my application which contains the methods as: + (NSData *) dataWithBase64EncodedString:(NSString *) string; - (id) initWithBase64EncodedString:(NSString *) string; - (NSString *) base64EncodingWithLineLength:(unsigned int) lineLength; And the code in my view controller where I encode the String is: - (id)init { if (self = [super init]) { // Custom initialization userName = @"Sekhar"; password = @"Bethalam"; } return self; } -(void)reloadView { NSString *authStr = [NSString stringWithFormat:@"%@:%@",userName,password]; NSData *authData = [authStr dataUsingEncoding:NSASCIIStringEncoding]; NSString *authValue = [NSString stringWithFormat:@"%@", [authData base64EncodingWithLineLength:30]]; NSLog(authValue); //const char *str = authValue; //NSString *decStr = [StringEncryption DecryptString:authValue]; //NSLog(decStr); //NSData *decodeData = [NSData decode:authValue]; //NSString *decStr = [NSString stringWithFormat:@"%@",decodeData]; //NSStr //NSLog(decStr); } -(void)viewWillAppear:(BOOL)animated { [self reloadView]; } and now I want to decode the String that I encoded. But I dont know How to do that.can anyone suggest me with code how to get it. Anyone's help will be much appreciated. Thank you, Monish.

    Read the article

  • Http Digest Authentication, Handle different browser char-sets...

    - by user160561
    Hi all, I tried to use the Http Authentication Digest Scheme with my php (apache module) based website. In general it works fine, but when it comes to verification of the username / hash against my user database i run into a problem. Of course i do not want to store the user´s password in my database, so i tend to store the A1 hashvalue (which is md5($username . ':' . $realm . ':' . $password)) in my db. This is just how the browser does it too to create the hashes to send back. The Problem: I am not able to detect if the browser does this in ISO-8859-1 fallback (like firefox, IE) or UTF-8 (Opera) or whatever. I have chosen to do the calculation in UTF-8 and store this md5 hash. Which leads to non-authentication in Firefox and IE browsers. How do you solve this problem? Just do not use this auth-scheme? Or Store a md5 Hash for each charset? Force users to Opera? (Terms of A1 refer to the http://php.net/manual/en/features.http-auth.php example.) (for digest access authentication read the according wikipedia entry)

    Read the article

  • Using Javascript to submit forms.

    - by Razor Storm
    I am using a jQuery function to submit a form when a certain button is pressed, however this seems to have no effect on the form. My code is as follows: HTML: <form id="loginForm" action="" method="POST"> <input class="loginInput" type="hidden" name="action" value="login"> <input id="step1a" class="loginInput" type="text" name="username"> <input id="step2a" class="loginInput" type="password" name="password" style="display:none;"> <input id="step1b" class="loginSubmit" onclick="loginProceed();" type="button" name="submit" value="Proceed" title="Proceed" /> <input id="step2b" class="loginSubmit" onclick="submitlogin();" type="button" value="Validate" title="Validate" style="display:none;" /> Javascript: function submitlogin() { $("form").submit(); } However, when I press the button, absolutely nothing occurs. PS. This function may seem meaningless since I can just use a input type="submit" but I originally intended this to have some more functionality, I stripped the function to its bare bones for testing purposes.

    Read the article

  • Populate table with JQuery

    - by Talkar
    I need to populate some data into a table. The data i have is something i get in response from my ASP.NET MVC site, when i make a json post call there. Yet i can't seem to find a way to actually display the data i get back in response. Here is my code so far. Any help would be much appreciated: $(document).ready(function () { var uName = '<%= Session["UserName"].ToString()%>'; var pWord = '<%= Session["Password"].ToString()%>'; var data = { UserName:uName,Password:pWord}; $.ajax( { type: 'POST', url: "http://someurl.goes.here/", crossDomain: true, data: data, dataType: 'jsonp', success: function(myData) { $.each(myData, function (index, element) { $("#ClassTable").append('<tr><td> ' + element[0] + ' </td> <td> ' + element[1] + '</td></tr>'); }) } }); }); myData looks like this: [Object { IsActive = True, ObjectId=1, ObjectString="someString", etc... etc... } ]

    Read the article

  • How to remove a status message added by the seam security module?

    - by Joshua
    I would like to show a different status message, when a suspended user tries to login. If the user is active we return true from the authenticate method, if not we add a custom StatusMessage message mentioning that the "User X has been suspended". The underlying Identity authentication also fails and adds a StatusMessage. I tried removing the seam generated statusMessage with the following methods, but it doesn't seem to work and shows me 2 different status messages (my custom message, seam generated). What would be the issue here? StatusMessages statusMessages; statusMessages.clear() statusMessages.clearGlobalMessages() statusMessages.clearKeyedMessages(id) EDIT1: public boolean authenticate() { log.info("Authenticating {0}", identity.getCredentials().getUsername()); String username = identity.getCredentials().getUsername(); String password = identity.getCredentials().getPassword(); // return true if the authentication was // successful, false otherwise try { Query query = entityManager.createNamedQuery("user.by.login.id"); query.setParameter("loginId", username); // only active users can log in query.setParameter("status", "ACTIVE"); currentUser = (User)query.getSingleResult(); } catch (PersistenceException ignore) { // Provide a status message for the locked account statusMessages.clearGlobalMessages(); statusMessages.addFromResourceBundle( "login.account.locked", new Object[] { username }); return false; } IdentityManager identityManager = IdentityManager.instance(); if (!identityManager.authenticate(username, "password")) { return false; } else { log.info("Authenticated user {0} successfully", username); } }

    Read the article

  • SQL query in JSP file pulling variable from VXML file

    - by s1066
    Hi I'm trying to get an SQL query to work within a JSP file. The JSP file is pulled by a VXML file here is my JSP file code: <?xml version="1.0"?> <%@ page import="java.util.*" %> <%@ page import="java.sql.*" %> <% boolean success = true; // Always optimistic String info = ""; String schoolname = request.getParameter("schoolname"); String informationtype = request.getParameter("informationtype"); try { Class.forName("org.postgresql.Driver"); String connectString = "jdbc:postgresql://localhost:5435/N0176359"; String user = "****"; String password = "*****"; Connection conn = DriverManager.getConnection(connectString, user, password); Statement st = conn.createStatement(); ResultSet rsvp = st.executeQuery("SELECT * FROM lincolnshire_school_information_new WHERE school_name=\'"+schoolname+"\'"); rsvp.next(); info = rsvp.getString(2); }catch (ClassNotFoundException e) { success = false; // something went wrong } %> As you can see I'm trying to insert the value of the variable declared as "schooname" into the end of the SQL query. However when I come to run the jsp file it doesn't work and I get an error "ResultSet not positioned properly". When I put a standard query in (without trying to make it value of the variable it works fine) Hope that makes sense, and thank you for any help!

    Read the article

  • Powershell invoke-command with PSCredential in line

    - by jaffa
    I need to be able to run a command on another server. This script acts as a bootstrap to another script which is run on the actual server. This works great on servers on the same domain, but if I need to run this script on a remote server, I need to specify credentials. The command is kicked off from a Msbuild targets file like so: <Target Name="PreDeployment" Condition="true" BeforeTargets="MSDeployPublish"> <Exec Command="powershell.exe -ExecutionPolicy Bypass invoke-command bootstrapScript.ps1 -computername $(MyServer) -argumentlist param1, param2" /> </Target> However, I need to be able to supply the credentials by creating a new PSCredentials object with a secure password for my deployment script to run on a remote server: <Target Name="PreDeployment" Condition="true" BeforeTargets="MSDeployPublish"> <Exec Command="powershell.exe -ExecutionPolicy Bypass invoke-command bootstrapScript.ps1 -computername $(MyServer) -credential New-Object System.Management.Automation.PSCredential ('admin', (convertto-securestring $(Password) -asplaintext -force)) -argumentlist param1, param2" /> </Target> When I run the build, a dialog pops up with the username set to System.Management.Automation.PSCredential. I need to be able to create the credentials in-line on the executable target. How do I accomplish this?

    Read the article

  • Network Authentication when running exe from WMI

    - by Andy
    Hi, I have a C# exe that needs to be run using WMI and access a network share. However, when I access the share I get an UnauthorizedAccessException. If I run the exe directly the share is accessible. I am using the same user account in both cases. There are two parts to my application, a GUI client that runs on a local PC and a backend process that runs on a remote PC. When the client needs to connect to the backend it first launches the remote process using WMI (code reproduced below). The remote process does a number of things including accessing a network share using Directory.GetDirectories() and reports back to the client. When the remote process is launched automatically by the client using WMI, it cannot access the network share. However, if I connect to the remote machine using Remote Desktop and manually launch the backend process, access to the network share succeeds. The user specifed in the WMI call and the user logged in for the Remote Desktop session are the same, so the permissions should be the same, shouldn't they? I see in the MSDN entry for Directory.Exists() it states "The Exists method does not perform network authentication. If you query an existing network share without being pre-authenticated, the Exists method will return false." I assume this is related? How can I ensure the user is authenticated correctly in a WMI session? ConnectionOptions opts = new ConnectionOptions(); opts.Username = username; opts.Password = password; ManagementPath path = new ManagementPath(string.Format("\\\\{0}\\root\\cimv2:Win32_Process", remoteHost)); ManagementScope scope = new ManagementScope(path, opts); scope.Connect(); ObjectGetOptions getOpts = new ObjectGetOptions(); using (ManagementClass mngClass = new ManagementClass(scope, path, getOpts)) { ManagementBaseObject inParams = mngClass.GetMethodParameters("Create"); inParams["CommandLine"] = commandLine; ManagementBaseObject outParams = mngClass.InvokeMethod("Create", inParams, null); }

    Read the article

  • A way to specify a different host in an SSH tunnel from the host in use

    - by Tom
    I am trying to setup an SSH tunnel to access Beanstalk (to bypass an annoying proxy server). I can get this to work, but with one caveat: I have to map my Beanstalk host URL (username.svn.beanstalkapp.com) in my hosts file to 127.0.0.1 (and use the ip in place of the domain when setting up the tunnel). The reason (I think) is that I am creating the tunnel using the local SSH instance (on Snow Leopard) and if I use localhost or 127.0.0.1 when talking to Beanstalk, it rejects the authorisation credentials. I believe this is because Beanstalk use the hostname specified in a request to determine which account the username / password combination should be checked against. If localhost is used, I think this information is missing (in some manner which Beanstalk requires) from the requests. At the moment I dig the IP for username.svn.beanstalkapp.com, map username.svn.beanstalkapp.com to 127.0.0.1 in my hosts file, then for the tunnel I use the command: ssh -L 8080:ip:443 -p 22 -l tom -N 127.0.0.1 I can tell Subversion that the repo. is located at: https://username.svn.beanstalkapp.com:8080/repo-name This uses my tunnel and the username and password are accepted. So, my question is if there is an option when setting up the SSH tunnel which would mean I wouldn't have to use my hosts file workaround?

    Read the article

  • how to read an arraylist from a txt file in java?

    - by lox
    how to read an arraylist from a txt file in java? my arraylist is the form of: public class Account { String username; String password; } i managed to put some "Accounts" in the a txt file, but now i don't know how to read them. this is how my arraylist look in the txt file: username1 password1 | username2 password2 | etc this is a part of the code i came up with, but it doesn't work. it looks logic to me though... :) . public static void RdAc(String args[]) { ArrayList<Account> peoplelist = new ArrayList<Account>(50); int i,i2,i3; String[] theword = null; try { FileReader fr = new FileReader("myfile.txt"); BufferedReader br = new BufferedReader(fr); String line = ""; while ((line = br.readLine()) != null) { String[] theline = line.split(" | "); for (i = 0; i < theline.length; i++) { theword = theline[i].split(" "); } for(i3=0;i3<theline.length;i3++) { Account people = new Account(); for (i2 = 0; i2 < theword.length; i2++) { people.username = theword[i2]; people.password = theword[i2+1]; peoplelist.add(people); } } } } catch (IOException ex) { System.out.println("Could not read from file"); } }

    Read the article

  • sending email with codeigniter

    - by Maru
    I have this MODEL and I get the email which I want to send class Cliente_Model extends CI_Model{ public function getInfo($id){ $this->db->select('*'); $this->db->from('pendientes'); $query = $this->db->get(); if($query->num_rows() > 0) { foreach ($query->result_array() as $row) { return $row['email']; } } else { return FALSE; } } } CONTROLLER $this->load->model('cliente_model', 'client'); $clientInfo = $this->client->getInfo($id); $this->email->from('[email protected]', 'Demo'); $this->email->to($clientInfo); $this->email->subject('Email Test'); $this->email->message('your user is '.$clientInfo.' and your password is '.$clave); $this->email->send(); and I need some help here, I can get the email and it can send it perfectly but in the message I need to send the password also and I don't know how I can get it from the model. thanks in advance!

    Read the article

  • Proper use of HttpRequestInterceptor and CredentialsProvider in doing preemptive authentication with

    - by Preston
    I'm writing an application in Android that consumes some REST services I've created. These web services aren't issuing a standard Apache Basic challenge / response. Instead in the server-side code I'm wanting to interrogate the username and password from the HTTP(S) request and compare it against a database user to make sure they can run that service. I'm using HttpClient to do this and I have the credentials stored on the client after the initial login (at least that's how I see this working). So here is where I'm stuck. Preemptive authenticate under HttpClient requires you to setup an interceptor as a static member. This is the example Apache Components uses. HttpRequestInterceptor preemptiveAuth = new HttpRequestInterceptor() { @Override public void process( final HttpRequest request, final HttpContext context) throws HttpException, IOException { AuthState authState = (AuthState) context.getAttribute(ClientContext.TARGET_AUTH_STATE); CredentialsProvider credsProvider = (CredentialsProvider) context.getAttribute( ClientContext.CREDS_PROVIDER); HttpHost targetHost = (HttpHost) context.getAttribute(ExecutionContext.HTTP_TARGET_HOST); if (authState.getAuthScheme() == null) { AuthScope authScope = new AuthScope(targetHost.getHostName(), targetHost.getPort()); Credentials creds = credsProvider.getCredentials(authScope); if (creds != null) { authState.setAuthScheme(new BasicScheme()); authState.setCredentials(creds); } } } }; So the question would be this. What would the proper use of this be? Would I spin this up as part of the application when the application starts? Pulling the username and password out of memory and then using them to create this CredentialsProvider which is then utilized by the HttpRequestInterceptor? Or is there a way to do this more dynamically?

    Read the article

  • ldap_bind_s returning LDAP_SUCCESS with wrong credentials

    - by rezna
    Hi guys, I have this little problem. I want to authenticate user against LDAP (Windows Active Directory), everything works OK, but the combination (good user, good password, wrong domain). LDAP* ldap = ldap_init(L"myserver", 389); ULONG ldap_version = 3; ULONG ret = LDAP_SUCCESS; ret = ldap_set_option(ldap, LDAP_OPT_PROTOCOL_VERSION, (void*)&ldap_version); ret = ldap_connect(ldap, NULL); SEC_WINNT_AUTH_IDENTITY ai; ai.Domain = (unsigned short*)BAD_DOMAIN; ai.DomainLength = wcslen(BAD_DOMAIN); ai.User = (unsigned short*)OK_USER; ai.UserLength = wcslen(OK_USER); ai.Password = (unsigned short*)OK_PASS; ai.PasswordLength = wcslen(OK_PASS); ai.Flags = SEC_WINNT_AUTH_IDENTITY_UNICODE; ret = ldap_bind_s(ldap, NULL, (PWCHAR) &ai, LDAP_AUTH_NTLM); // !!! HERE !!! ret = ldap_unbind_s(ldap); On the line marke '!!! HERE !!!' I'd expect 0x31 or any other error returned. Instead I get LDAP_SUCCESS :( Any suggestions? Thx, Milan

    Read the article

  • C# Uploading files to file server

    - by JustFoo
    Hello All, Currently I have an application that receives an uploaded file from my web application. I now need to transfer that file to a file server which happens to be located on the same network (however this might not always be the case). I was attempting to use the webclient class in C# .NET. string filePath = "C:\\test\\564.flv"; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.28\\Files\\test.flv"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } The machine located at 192.168.1.28 is a file server and has a share c:\Files. As of right now I am receiving an error of Login failed bad user name or password, but I can open explorer and type in that path login successfully. I can also login using remote desktop, so I know the user account works. Any ideas on this error? Is it possible to transfer a file directly like that? With the webclient class or maybe some other class? Thanks

    Read the article

  • how to add data to database from rails console

    - by rails_guy
    I have a User model. >> @u = User.new => #<User id: nil, userid: nil, password: nil, created_at: nil, updated_at: nil, user_first_name: nil, user_last_name: nil, user_status: nil, user_type: nil> I am not able to add data to the Users table from the console. I am doing the following: >> @u.userid="test1" => "test1" >> @u.password="test2" => "test2" >> @u.user_first_name="test3" => "test3" >> @u.user_last_name="test4" => "test4" >> @u.user_status="test5" => "test5" >> @u.user_type="test6" => "test6" >> @u.save NoMethodError: undefined method `userid' for nil:NilClass what am i doing wrong? I just simply want to add one row of data to the app.

    Read the article

  • Can't connect to SQL Server 2005 Express from an ASP.NET C# page

    - by Aviv
    Hey guys, I have an MS SQL Server 2005 Express running on a VPS. I'm using pymssql in Python to connect to my server with the following code: conn = pymssql.connect(host='host:port', user='me', password='pwd', database='db') and it works perfectly. When I try to connect to the server from an ASP.NET C# page with the following code: SqlConnection myConnection = new SqlConnection("Data Source=host,port;Network Library=DBMSSOCN; Initial Catalog=db;User ID=me;Password=pwd;"); myConnection.Open(); When I run the ASP.NET page I get the following exception at myConnection.Open();: A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: TCP Provider, error: 0 - A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond.) I tried restarting the SQL Server but I had no luck. Can anyone point me out to what I'm missing here? Thanks!

    Read the article

  • widget within module in Yii

    - by Karolis
    I'm trying to create a widget within the module and then load that widget from 'outside' of the module. More particularly I'm using user module written by someone else. I don't want to have a separate page for displaying a login form, therefore I tried to make a CPortlet/widget (confusion) displaying the login form. Basically, I've moved the code from LoginController into that widget. Then I try to display the widget on some random page by <?php $this->widget('user.components.LoginForm'); ?> However, I get an error CWebApplication does not have a method named "encrypting". in UserIdentity class in this line: else if(Yii::app()->controller->module->encrypting($this->password)!==$user->password) This happens, because I'm basically trying to execute this code within context of the app and not the module. Thus the "Yii::app()-controller-module" trick doesn't really work as expected. What am I doing wrong:-\ Is there a better way to achieve this. I.e. display that login form in some other page, which is normally displayed by accessing login controller within user module (user/login) or is a widget the right way of doing it? Thanks.

    Read the article

  • Maven build fails on an Ant FTP task failure

    - by fraido
    I'm using the FTP Ant task with maven-antrun-plugin <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-antrun-plugin</artifactId> <executions> <execution> <id>ftp</id> <phase>generate-resources</phase> <configuration> <tasks> <ftp action="get" server="${ftp.server.ip}" userid="${ftp.server.userid}" password="${ftp.server.password}" remotedir="${ftp.server.remotedir}" depends="yes" verbose="yes" skipFailedTransfers="true" ignoreNoncriticalErrors="true"> <fileset dir="target/test-classes/testdata"> <include name="**/*.html" /> </fileset> </ftp> </tasks> </configuration> <goals> <goal>run</goal> </goals> </execution> </executions> ... the problem is that my build fails when the folder ${ftp.server.remotedir} doesn't exist. I tried to specify skipFailedTransfers="true" ignoreNoncriticalErrors="true but these don't fix the problem and the build keeps failing. An Ant BuildException has occured: could not change remote directory: 550 /myBadDir: The system cannot find the file specified. Do you know how to instruct my maven build to don't care about this Ant task error

    Read the article

  • Displaying emails in a JTable (Java Swing)

    - by Paul
    Hi I'm new to all this. I have been trying to display fetched emails in a JTable using the JavaMail add-on. However when I ask the program to set the value it never does. I have been working in NetBeans if that is any help? the fetchMail class finds all may on a server. The gui class is used to display all emails in a table as well as creating mail. You will probably think that I have tried it like a bull in a china shop, I am new to Java and trying to give myself a challenge. Any help/advice would be greatly appreciated fetchMail: package mail; import java.util.; import java.io.; import java.text.DateFormat; import java.text.SimpleDateFormat; import javax.mail.; import javax.mail.internet.; import javax.mail.search.; import javax.activation.; public class fetchMail { public void fetch(String username, String pass, String search){ MessagesTableModel tableModel = new MessagesTableModel(); String complete; DateFormat df = new SimpleDateFormat("dd/MM/yyyy"); gui gui = new gui(); // SUBSTITUTE YOUR ISP's POP3 SERVER HERE!!! String host = "imap.gmail.com"; // SUBSTITUTE YOUR USERNAME AND PASSWORD TO ACCESS E-MAIL HERE!!! String user = username; String password = pass; // SUBSTITUTE YOUR SUBJECT SUBSTRING TO SEARCH HERE!!! String subjectSubstringToSearch = search; // Get a session. Use a blank Properties object. Session session = Session.getInstance(new Properties()); Properties props = System.getProperties(); props.setProperty("mail.store.protocol", "imaps"); props.setProperty("mail.imap.socketFactory.class", "javax.net.ssl.SSLSocketFactory"); props.setProperty("mail.imap.socketFactory.fallback", "false"); try { // Get a Store object Store store = session.getStore("imaps"); store.connect(host, user, password); // Get "INBOX" Folder fldr = store.getFolder("INBOX"); fldr.open(Folder.READ_WRITE); int count = fldr.getMessageCount(); System.out.println(count + " total messages"); // Message numebers start at 1 for(int i = 1; i <= count; i++) { // Get a message by its sequence number Message m = fldr.getMessage(i); // Get some headers Date date = m.getSentDate(); int pos = i - 1; String d = df.format(date); Address [] from = m.getFrom(); String subj = m.getSubject(); String mimeType = m.getContentType(); complete = date + "\t" + from[0] + "\t" + subj + "\t" + mimeType; //tableModel.setMessages(m); gui.setDate(d, pos); // System.out.println(d + " " + i); } // Search for e-mails by some subject substring String pattern = subjectSubstringToSearch; SubjectTerm st = new SubjectTerm(pattern); // Get some message references Message [] found = fldr.search(st); System.out.println(found.length + " messages matched Subject pattern \"" + pattern + "\""); for (int i = 0; i < found.length; i++) { Message m = found[i]; // Get some headers Date date = m.getSentDate(); Address [] from = m.getFrom(); String subj = m.getSubject(); String mimeType = m.getContentType(); //System.out.println(date + "\t" + from[0] + "\t" + // subj + "\t" + mimeType); Object o = m.getContent(); if (o instanceof String) { // System.out.println("**This is a String Message**"); // System.out.println((String)o); } else if (o instanceof Multipart) { // System.out.print("**This is a Multipart Message. "); Multipart mp = (Multipart)o; int count3 = mp.getCount(); // System.out.println("It has " + count3 + // " BodyParts in it**"); for (int j = 0; j < count3; j++) { // Part are numbered starting at 0 BodyPart b = mp.getBodyPart(j); String mimeType2 = b.getContentType(); // System.out.println( "BodyPart " + (j + 1) + // " is of MimeType " + mimeType); Object o2 = b.getContent(); if (o2 instanceof String) { // System.out.println("**This is a String BodyPart**"); // System.out.println((String)o2); } else if (o2 instanceof Multipart) { // System.out.print( // "**This BodyPart is a nested Multipart. "); Multipart mp2 = (Multipart)o2; int count2 = mp2.getCount(); // System.out.println("It has " + count2 + // "further BodyParts in it**"); } else if (o2 instanceof InputStream) { // System.out.println( // "**This is an InputStream BodyPart**"); } } //End of for } else if (o instanceof InputStream) { // System.out.println("**This is an InputStream message**"); InputStream is = (InputStream)o; // Assumes character content (not binary images) int c; while ((c = is.read()) != -1) { // System.out.write(c); } } // Uncomment to set "delete" flag on the message //m.setFlag(Flags.Flag.DELETED,true); } //End of for // "true" actually deletes flagged messages from folder fldr.close(true); store.close(); } catch (MessagingException mex) { // Prints all nested (chained) exceptions as well mex.printStackTrace(); } catch (IOException ioex) { ioex.printStackTrace(); } } } gui: /* * gui.java * * Created on 13-May-2010, 18:29:30 */ package mail; import java.text.DateFormat; import java.text.FieldPosition; import java.text.ParsePosition; import java.text.SimpleDateFormat; import java.util.Date; import java.util.Vector; import javax.mail.Address; import javax.swing.JScrollPane; import javax.swing.JTable; import javax.swing.ListSelectionModel; import javax.swing.event.ListSelectionEvent; import javax.swing.event.ListSelectionListener; import javax.swing.event.TableModelListener; import javax.swing.table.DefaultTableModel; import javax.swing.table.TableModel; public class gui extends javax.swing.JFrame { private MessagesTableModel tableModel; // Table listing messages. private JTable table; String date; /** Creates new form gui */ public gui() { initComponents(); } @SuppressWarnings("unchecked") private void initComponents() { recieve = new javax.swing.JButton(); jButton1 = new javax.swing.JButton(); jScrollPane1 = new javax.swing.JScrollPane(); inboxTable = new javax.swing.JTable(); setDefaultCloseOperation(javax.swing.WindowConstants.EXIT_ON_CLOSE); recieve.setText("Receve"); recieve.addActionListener(new java.awt.event.ActionListener() { public void actionPerformed(java.awt.event.ActionEvent evt) { recieveActionPerformed(evt); } }); jButton1.setText("new"); jButton1.addActionListener(new java.awt.event.ActionListener() { public void actionPerformed(java.awt.event.ActionEvent evt) { jButton1ActionPerformed(evt); } }); inboxTable.setModel(new javax.swing.table.DefaultTableModel( new Object [][] { {null, null, null}, {null, null, null}, {null, null, null}, {null, null, null} }, new String [] { "Date", "subject", "sender" } ) { Class[] types = new Class [] { java.lang.String.class, java.lang.String.class, java.lang.String.class }; public Class getColumnClass(int columnIndex) { return types [columnIndex]; } }); jScrollPane1.setViewportView(inboxTable); inboxTable.getColumnModel().getColumn(0).setResizable(false); inboxTable.getColumnModel().getColumn(1).setResizable(false); inboxTable.getColumnModel().getColumn(2).setResizable(false); javax.swing.GroupLayout layout = new javax.swing.GroupLayout(getContentPane()); getContentPane().setLayout(layout); layout.setHorizontalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(layout.createSequentialGroup() .addGap(39, 39, 39) .addGroup(layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jScrollPane1, javax.swing.GroupLayout.PREFERRED_SIZE, 558, javax.swing.GroupLayout.PREFERRED_SIZE) .addGroup(layout.createSequentialGroup() .addComponent(recieve) .addGap(18, 18, 18) .addComponent(jButton1, javax.swing.GroupLayout.PREFERRED_SIZE, 75, javax.swing.GroupLayout.PREFERRED_SIZE))) .addGap(73, 73, 73)) ); layout.setVerticalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(layout.createSequentialGroup() .addGap(31, 31, 31) .addGroup(layout.createParallelGroup(javax.swing.GroupLayout.Alignment.BASELINE) .addComponent(recieve) .addComponent(jButton1)) .addGap(18, 18, 18) .addComponent(jScrollPane1, javax.swing.GroupLayout.PREFERRED_SIZE, 258, javax.swing.GroupLayout.PREFERRED_SIZE) .addContainerGap(179, Short.MAX_VALUE)) ); pack(); }// </editor-fold> private void recieveActionPerformed(java.awt.event.ActionEvent evt) { fetchMail fetch = new fetchMail(); fetch.fetch(email goes here, password goes here, search goes here); } private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) { createMail create = new createMail(); centerW center = new centerW(); //create.attVis(); center.center(create); create.setVisible(true); } public void setDate(String Date, int pos){ //pos = pos + 1; String [] s = new String [5]; s[pos] = Date; inboxTable.setValueAt(Date, pos, 0); } public String getDate(){ return date; } /** * @param args the command line arguments */ public static void main(String args[]) { java.awt.EventQueue.invokeLater(new Runnable() { public void run() { new gui().setVisible(true); } }); } // Variables declaration - do not modify private javax.swing.JTable inboxTable; private javax.swing.JButton jButton1; private javax.swing.JScrollPane jScrollPane1; private javax.swing.JButton recieve; // End of variables declaration }

    Read the article

  • how avoids deadlock condition

    - by rima
    Hi I try to write a program like a compiler.In this case I must simulate these codes of SQLPL(This one can be just for example).for example in command prompt i wana do these: c:\> sqlplus .... Enter User-Name:(here we must enter username) xxxx Enter password:(same up)yyyyy ... sql>(now i want to send my sql command to shell)prompt "rima"; "rima" [<-output] sql> prompt "xxxx" sql> exit very simple. I try to use this code: ProcessStartInfo psi = new ProcessStartInfo( @"sqlplus"); psi.UseShellExecute = false; psi.CreateNoWindow = true; psi.RedirectStandardInput = true; psi.RedirectStandardOutput = true; //psi.RedirectStandardError = true; Process process = new Process(); process.StartInfo = psi; bool started = process.Start(); if (started) { process.StandardInput.WriteLine("user/password"); process.StandardInput.Flush(); string ret = process.StandardOutput.ReadLine(); // <-- stalls here System.Console.WriteLine("sqlplus says :" + ret + "\"."); } i find out it form here but as if u read this code has problem!DEADLOCK Condition problem! this is my second time i ask my question,every time my knowledge growing,but i cant get how I can solve my problem at last!!! So I kindly kiss your hand,please help me,these process is not clear for me.any one can give me a code that handle my problem?Already i look at all codes,also I try to use ProcessRunner that in my last post some one offer me,but I cant use it also,i receive an error. I hope by first example u find out what i want,and solve the second code problem... thanks I use C# for implemantation

    Read the article

  • How can I prevent default_environment variables from getting set by Capistrano's sudo action?

    - by Logan Koester
    My deploy.rb sets some environment variables to use the regular user's local Ruby rather than the system-wide one. set :default_environment, { :PATH => '/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games', :RUBY_VERSION => 'ruby-1.9.1-p378', :GEM_HOME => '/home/myapp/.rvm/gems/ruby-1.9.1-p378', :GEM_PATH => '/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global' } Naturally, when a task is using sudo, I would expect the system-wide ruby to be used instead. But it seems the environment variables are being set anyway, which is obviously invalid for the root user and returns an error: executing "sudo -p 'sudo password: ' /etc/init.d/god stop" servers: ["myapp.com"] [myapp.com] executing command command finished failed: "env PATH=/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games RUBY_VERSION=ruby-1.9.1-p378 GEM_HOME=/home/myapp/.rvm/gems/ruby-1.9.1-p378 GEM_PATH=/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global sh -c 'sudo -p '\\''sudo password: '\\'' /etc/init.d/god stop'" on myapp.com It makes no difference whether I use capistrano's sudo "system call" or the regular run "sudo system call". How can I avoid this?

    Read the article

  • Running RSpec Files From ruby code

    - by Brian D.
    I'm trying to run RSpec tests straight from ruby code. More specifically, I'm running some mysql scripts, loading the rails test environment and then I want to run my rspec tests (which is what I'm having trouble with)... I'm trying to do this with a rake task. Here is my code so far: require"spec" require "spec/rake/spectask" RAILS_ENV = 'test' namespace :run_all_tests do desc "Run all of your tests" puts "Reseting test database..." system "mysql --user=root --password=dev < C:\\Brian\\Work\\Personal\\BrianSite\\database\\BrianSite_test_CreateScript.sql" puts "Filling database tables with test data..." system "mysql --user=root --password=dev < C:\\Brian\\Work\\Personal\\BrianSite\\database\\Fill_Test_Tables.sql" puts "Starting rails test environment..." task :run => :environment do puts "RAILS_ENV is #{RAILS_ENV}" # Run rspec test files here... require "spec/models/blog_spec.rb" end end I thought the require "spec/models/blog_spec.rb" would do it, but the tests aren't running. Anyone know where I'm going wrong? Thanks for any help.

    Read the article

  • Voting on Hacker News stories programmatically?

    - by igorgue
    I decided to write an app like: http://michaelgrinich.com/hackernews/ but for Android devices, my idea will use a web application backend (because I rather code in Python and for the web than completely in Java for Android devices). What I have right now implemented is something like this: $ curl -i http://localhost:8080/stories.json?page=1\&stories=1 HTTP/1.0 200 OK Date: Sun, 25 Apr 2010 07:59:37 GMT Server: WSGIServer/0.1 Python/2.6.5 Content-Length: 296 Content-Type: application/json [{"title": "Don\u2019t talk to aliens, warns Stephen Hawking", "url": "http://www.timesonline.co.uk/tol/news/science/space/article7107207.ece?", "unix_time": 1272175177, "comments": 15, "score": 38, "user": "chaostheory", "position": 1, "human_time": "Sun Apr 25 01:59:37 2010", "id": "1292241"}] The next step (and final I think) is voting, my design is doing something like this: $ curl -i http://localhost:8080/stories/1?vote=up -u username:password Will vote up and: $ curl -i http://localhost:8080/stories/1?vote=down -u username:password Down. I have no idea how to do it though... I was planning to use Twill but the login link is always different, e.g.: http://news.ycombinator.com/x?fnid=7u89ccHKln Later the Android app will consume this API. Any experience with programmatically browsing Hacker News?

    Read the article

< Previous Page | 226 227 228 229 230 231 232 233 234 235 236 237  | Next Page >