Search Results

Search found 6679 results on 268 pages for 'echo'.

Page 231/268 | < Previous Page | 227 228 229 230 231 232 233 234 235 236 237 238  | Next Page >

  • CakePHP: Custom Function in bootstrap that uses $ajax->link not working

    - by nekko
    Hello I have two questions: (1) Is it best practice to create global custom functions in the bootstrap file? Is there a better place to store them? (2) I am unable use the following line of code in my custom function located in my bootstrap.php file: $url = $ajax->link ( 'Delete', array ('controller' => 'events', 'action' => 'delete', 22 ), array ('update' => 'event' ), 'Do you want to delete this event?' ); echo $url; I receive the following error: Notice (8): Undefined variable: ajax [APP\config\bootstrap.php, line 271] Code } function testAjax () { $url = $ajax->link ( 'Delete', array ('controller' => 'events', 'action' => 'delete', 22 ), array ('update' => 'event' ), 'Do you want to delete this event?' ); testAjax - APP\config\bootstrap.php, line 271 include - APP\views\event\queue.ctp, line 19 View::_render() - CORE\cake\libs\view\view.php, line 649 View::render() - CORE\cake\libs\view\view.php, line 372 Controller::render() - CORE\cake\libs\controller\controller.php, line 766 Dispatcher::_invoke() - CORE\cake\dispatcher.php, line 211 Dispatcher::dispatch() - CORE\cake\dispatcher.php, line 181 [main] - APP\webroot\index.php, line 91 However it works as intended if I place that same code in my view: <a onclick=" event.returnValue = false; return false;" id="link1656170149" href="/shout/events/delete/22">Delete</a> Please help :) Thanks in advance!!

    Read the article

  • Exporting Maven properties from Ant code

    - by Gili
    I've embedded the following code within my POM: <plugin name="test"> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-antrun-plugin</artifactId> <executions> <execution> <phase>validate</phase> <configuration> <tasks> <pathconvert targetos="unix" property="project.build.directory.portable"> <path location="${project.build.directory}"/> </pathconvert> </tasks> </configuration> <goals> <goal>run</goal> </goals> </execution> </executions> </plugin> I then reference ${project.build.directory.portable} from the run project action but it comes back as null. Executing <echo> within the Ant block shows the correct value. What am I doing wrong?

    Read the article

  • phpUnit - mock php extended exception object

    - by awongh
    I'm testing some legacy code that extends the default php exception object. This code prints out a custom HTML error message. I would like to mock this exception object in such a way that when the tested code generates an exception it will just echo the basic message instead of giving me the whole HTML message. I cannot figure out a way to do this. It seems like you can test for explicit exceptions, but you can't change in a general way the behavior of an exception, and you also can't mock up an object that extends a default php functionality. ( can't think of another example of this beyond exceptions... but it would seem to be the case ) I guess the problem is, where would you attach the mocked object?? It seems like you can't interfere with 'throw new' and this is the place that the object method is called.... Or if you could somehow use the existing phpunit exception functionality to change the exception behavior the way you want, in a general way for all your code... but this seems like it would be hacky and bad....

    Read the article

  • How to return value using ajax

    - by Priyanka
    Hello. I have Ajax file in which code has written to accept values form user and then these values are taken in a Ajax function as follows: $(document).ready(function(){ $("#newsletterform").validate(); $('#Submit').click(function(){ var name = $('#newsletter_name').val(); var email = $('#newsletter_email').val(); sendValue(email,name); }); }); The function for paasing values and getting values from other file: function sendValue(str,name){ $.post( "newsletter/subscribe.php", //Ajax file { sendValue: str, sendVal: name }, function(data2){ $('#display').html(data2.returnValue); }, //How you want the data formated when it is returned from the server. "json" ); } and these values are passed to another file called "subscribe.php" in which insertion code to database is written and again I return the value to my first ajax function as follows: echo json_encode(array("returnValue"=$msg)); The msg is ging to contain my message to be displayed. But now, this works fine on localhost, I get the return values nad message properly but when I upload it on server this gives me an error as: data2 is null [Break on this error] $('#display').html(data2.returnValue); This only gives error for return value but insertion, sending mail functionality works fine. Please provide me with a good solution wherein I can be able to get back the return values without any error. Thanks in advance.

    Read the article

  • Why is my PHP string being converted to 1?

    - by animuson
    Ok, so here's the quick rundown. I have a function to generate the page numbers. This: <?php die($ani->e->tmpl->pages("/archive", 1, 15, 1, true)); ?> will output Single Page like expected. But this: <?php $page_numbers = $ani->e->tmpl->pages("/archive", 1, 15, 1, true); ?> <?= $page_numbers ?> will output a simple 1 to the page. Why is it getting converted to a 1? I would expect it to store the 'Single Page' string to the page_numbers variable and then output it (like an echo) exactly the same. EDIT: Running a var_dump($page_numbers) returns int(1)... Here is the entire function in context: <?php // other functions... function show_list() { global $ani; $page_numbers = $ani->e->tmpl->pages("/archive", 1, 15, 1, true); ob_start(); ?> <!-- content:start --> <?php $archive_result = $ani->e->db->build(array("select" => "*", "from" => "animuson_archive", "orderby" => "0-time", "limit" => 15)); while ($archive = $ani->e->db->fetch($archive_result)) { ?> <h2><a href="/archive/article/<?= $archive['aid'] ?>/<?= $archive['title_nice'] ?>"><?= $archive['title'] ?></a></h2> <!-- breaker --> <?php } ?> <?= var_dump($page_numbers) ?> <!-- content:stop --> <?php $ani->e->tmpl->process("box", ob_get_clean()); } // other functions... ?>

    Read the article

  • Reading a Wordpress function description

    - by Casebash
    I want to be able to understand the standard function description that is provided for Wordpress functions. In particular, could someone explain the following example from here: Usage <?php wp_list_categories( $args ); ?> Default Usage <?php $args = array( 'show_option_all' => , 'orderby' => 'name', 'order' => 'ASC', 'show_last_update' => 0, 'style' => 'list', 'show_count' => 0, 'hide_empty' => 1, 'use_desc_for_title' => 1, 'child_of' => 0, 'feed' => , 'feed_type' => , 'feed_image' => , 'exclude' => , 'exclude_tree' => , 'include' => , 'current_category' => 0, 'hierarchical' => true, 'title_li' => __( 'Categories' ), 'number' => NULL, 'echo' => 1, 'depth' => 0 ); ?> I can guess most of it, but in particular I can't guess: What does blank after the comma mean? Empty string? What is the __? How do I call the function? Keyword like python, positional arguments or do I have to pass an array? Is there anything else about Wordpress function descriptions which isn't covered in this example? Thanks, Chris

    Read the article

  • change prototype script to jquery one

    - by steve
    I have this form submit code: Event.observe(window, 'load', init, false); function init() { Event.observe('addressForm', 'submit', storeAddress); } function storeAddress(e) { $('response').innerHTML = 'Adding email address...'; var pars = 'address=' + escape($F('address')); var myAjax = new Ajax.Updater('response', 'ajaxServer.php', {method: 'get', parameters: pars}); Event.stop(e); } How can I change it to work with jQuery? Here is the html form: <form id="addressForm" action="index.php" method="get"> <b>Email:</b> <input type="text" name="address" id="address" size="25"><br> <input name="Submit" value="Submit" type="submit" /> <p id="response"><?php echo(storeAddress()); ?></p> </form> and this is php code at start of document: <?php require_once("inc/storeAddress.php"); ?>

    Read the article

  • php (rar) i want to rar a folder using rar on Ubuntu (linux) by php (on dedi server) noob

    - by Steve
    hey guyz i want rar (not tar) my folder on my server by using php RAR RAR 3.93 Copyright (c) 1993-2010 Alexander Roshal 15 Mar 2010 Registered to my real name OS Ubuntu Release (Karmic) kernel linux 2.6.32.2-xxxx-grs-ipv4-32 Gnome 2.28.1 latest php an lighthttpd i have tried these things http://php.net/manual/en/function.escapeshellarg.php // may be wrong code http://php.net/manual/en/function.exec.php http://php.net/manual/en/function.shell-exec.php my command (working in ssh and nautilus script) rar a -m0 /where/file/will/saved/file_name.rar /location/ti/data/dir/datafolder php code $log=Shell_exec("rar a -m0 /where/file/will/saved/file_name.rar /location/ti/data/dir/datafolder"); echo $log; one method is left which i don't know how to use and its working on server that is by somefile_to_execute_command.sh i have to execute .sh file from php need to send some variables (command) and i tried this method can rar file with a script named RapidLeech but its rar from only its own files dir only :( but i want to do in different directories. Rapid Leech rar class http://paste2.org/p/791668 i m able run shell command with php (cp(copy),mv(move),ls(directory list),rm(remove aka delete)) but got failed to run rar i gives no output i also tried to given path rar and i used alot commands with php Shell_exec function and working like they work with ssh and i have tried almost 80 % method given on net and failed from last 3days i m over now plz help me i need php script file working plz reply if u have any info n code and experience about rar and this kinda :( problem i m 99% noob just used code mean search Google collect script make my own working thing (for personal use only) n now i m failed to rar folder and file :(( now plz provide me code plz don't talk in technical language because i m just reading my first php book (for dummies :D) mean noob and 0.1 plz help me as much u can thankx

    Read the article

  • Handle order dependence in loops

    - by Matt
    Hey all, I'm making a templating system where I instantiate each tag using a foreach loop. The issue is that some of the tags rely on each other so, I'm wondering how to get around that ordering from the looping. Here's an example: Class A { public $width; __construct() { $this->width = $B->width; // Undefined! Or atleast not set yet.. } } Class B { public $width; __construct() { $this->width = "500px"; } __tostring() { return "Hello World!"; } } Template.php $tags = array("A", "B"); foreach ($tags as $tag) { $TagObj[$tag] = new $tag(); } echo $TagObj['A']->width; // Nadamundo! EDIT: Ok just to clarify.. My main problem is that Class A relies on Class B, but class A is instantiated before class B, so therefore width has not yet been defined in class B. I am looking for a good way to make sure all the classes are loaded for everyone allowing the interdependencies to exist. For the future, please don't consider any syntax errors.. I just made up this example on the spot. Also assume that I have access to class B from class A after class B gets instantiated. I know this has applications elsewhere and I'm sure this has been solved before, if someone could enlighten me or point me in the right direction that'd be great! Thanks! Matt Mueler

    Read the article

  • i am getting error like mysql_connect() acces denied for system@localhost(using password NO)

    - by user309381
    class MySQLDatabase { public $connection; function _construct() { $this->open_connection();} public function open_connection() {$this->connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if(!$this->connection){die("Database Connection Failed" . mysql_error());} else{$db_select = mysql_select_db(DB_NAME,$this->connection); if(!$db_select){die("Database Selection Failed" . mysql_error()); } }} public function close_connection({ if(isset($this->connection)){ mysql_close($this->connection); unset($this->connection);}} public function query(/*$sql*/){ $sql = "SELECT*FROM users where id = 1"; $result = mysql_query($sql); $this->confirm_query($result); //return $result;while( $found_user = mysql_fetch_assoc($result)) { echo $found_user ['username']; } } private function confirm_query($result) { if(!$result) { die("The Query has problem" . mysql_error()); } } } $database = new MySQLDatabase(); $database->open_connection(); $database->query(); $database->close_connection(); ?>

    Read the article

  • Correlate GROUP BY and LEFT JOIN on multiple criteria to show latest record?

    - by Sunbird
    In a simple stock management database, quantity of new stock is added and shipped until quantity reaches zero. Each stock movement is assigned a reference, only the latest reference is used. In the example provided, the latest references are never shown, the stock ID's 1,4 should have references charlie, foxtrot respectively, but instead show alpha, delta. How can a GROUP BY and LEFT JOIN on multiple criteria be correlated to show the latest record? http://sqlfiddle.com/#!2/6bf37/107 CREATE TABLE stock ( id tinyint PRIMARY KEY, quantity int, parent_id tinyint ); CREATE TABLE stock_reference ( id tinyint PRIMARY KEY, stock_id tinyint, stock_reference_type_id tinyint, reference varchar(50) ); CREATE TABLE stock_reference_type ( id tinyint PRIMARY KEY, name varchar(50) ); INSERT INTO stock VALUES (1, 10, 1), (2, -5, 1), (3, -5, 1), (4, 20, 4), (5, -10, 4), (6, -5, 4); INSERT INTO stock_reference VALUES (1, 1, 1, 'Alpha'), (2, 2, 1, 'Beta'), (3, 3, 1, 'Charlie'), (4, 4, 1, 'Delta'), (5, 5, 1, 'Echo'), (6, 6, 1, 'Foxtrot'); INSERT INTO stock_reference_type VALUES (1, 'Customer Reference'); SELECT stock.id, SUM(stock.quantity) as quantity, customer.reference FROM stock LEFT JOIN stock_reference AS customer ON stock.id = customer.stock_id AND stock_reference_type_id = 1 GROUP BY stock.parent_id

    Read the article

  • speed string search in PHP

    - by Marc
    Hi! I have a 1.2GB file that contains a one line string. What I need is to search the entire file to find the position of an another string (currently I have a list of strings to search). The way what I'm doing it now is opening the big file and move a pointer throught 4Kb blocks, then moving the pointer X positions back in the file and get 4Kb more. My problem is that a bigger string to search, a bigger time he take to got it. Can you give me some ideas to optimize the script to get better search times? this is my implementation: function busca($inici){ $limit = 4096; $big_one = fopen('big_one.txt','r'); $options = fopen('options.txt','r'); while(!feof($options)){ $search = trim(fgets($options)); $retro = strlen($search);//maybe setting this position absolute? (like 12 or 15) $punter = 0; while(!feof($big_one)){ $ara = fgets($big_one,$limit); $pos = strpos($ara,$search); $ok_pos = $pos + $punter; if($pos !== false){ echo "$pos - $punter - $search : $ok_pos <br>"; break; } $punter += $limit - $retro; fseek($big_one,$punter); } fseek($big_one,0); } } Thanks in advance!

    Read the article

  • How to get database table header information into an CSV File.

    - by Rachel
    I am trying to connect to the database and get current state of a table and update that information into csv file, with below mentioned piece of code, am able to get data information into csv file but am not able to get header information from database table into csv file. So my questions is How can I get Database Table Header information into an CSV File ? $config['database'] = 'sakila'; $config['host'] = 'localhost'; $config['username'] = 'root'; $config['password'] = ''; $d = new PDO('mysql:dbname='.$config['database'].';host='.$config['host'], $config['username'], $config['password']); $query = "SELECT * FROM actor"; $stmt = $d->prepare($query); // Execute the statement $stmt->execute(); var_dump($stmt->fetch(PDO::FETCH_ASSOC)); $data = fopen('file.csv', 'w'); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo "Hi"; // Export every row to a file fputcsv($data, $row); } Header information meaning: Vehicle Build Model car 2009 Toyota jeep 2007 Mahindra So header information for this would be Vehicle Build Model Any guidance would be highly appreciated.

    Read the article

  • Passing PHP variables trough functions?

    - by Mateus Nunes
    I'm facing some troubles to pass php variables value trough functions,every time i try to use a variable inside one of my functions its value becomes nil,let me be more specific.I have the following code in my php file: $myvar = $Session['username']; function updateuserinformation(){ if(trim($_FILES["fileUpload"]["tmp_name"]) != ""){ $images = $_FILES["fileUpload"]["tmp_name"]; $new_images = "thumbnails_".$_FILES["fileUpload"]["name"]; copy($_FILES["fileUpload"]["tmp_name"],"Photos/".$_FILES["fileUpload"]["name"]); $width=200; //*** Fix Width & Heigh (Autu caculate) ***// $size=GetimageSize($images); $height=round($width*$size[1]/$size[0]); $images_orig = ImageCreateFromJPEG($images); $photoX = ImagesX($images_orig); $photoY = ImagesY($images_orig); $images_fin = ImageCreateTrueColor($width, $height); ImageCopyResampled($images_fin, $images_orig, 0, 0, 0, 0, $width+1, $height+1, $photoX, $photoY); ImageJPEG($images_fin,"Photos/".$new_images); ImageDestroy($images_orig); ImageDestroy($images_fin); print $data["foo"]; echo"$myvar"; mysql_query("UPDATE users SET userpictureaddress = 'http://www.litsdevelopment.com/litsapplication/userimages/MATEUS' WHERE username = 'Mateus' "); } } I trying to use the $myvar value in my function but every time i run the code it just doesn't work,i've already tried global,globals,arrays and session for nothing worked.Of corse i'm making a little mistake in some part of it,but anyone know what is the correct way to do this?

    Read the article

  • PHP - Select from database the same query

    - by How to PHP
    I created a table that contains the name of the user and his job, and created PHP page that shows me all the users that works doctor, I entered doctor into a variable then I selected from the table where Jobs equal to $doctor, that is great, but I need it to get the same Jobs into a table in the page and the other same jobs into a table in the same page. this is my code that shows only the users works doctor in one table, <html> <h1>Doctors</h1> </html> <?php mysql_connect('localhost','root',''); mysql_select_db('data'); $doctor='doctor'; $query= mysql_query("SELECT * FROM `users` WHERE `job` = '$doctor'")or die(mysql_error()); while ($arr = mysql_fetch_array($query)) $name= $arr['name']; echo $name; } ?> That shows me doctors when I put doctor in a variable I want to show all same Jobs in a table. Is there is a way to do this? Thanks :)

    Read the article

  • Error loading shared libraries

    - by user459811
    Hi, I'm running eclipse on Ubuntu using a g++ compiler and I'm trying to run a sample program that utilizes xerces. The build produced no errors however, when i attempted to run the program, I would receive this error: "error while loading shared libraries: libxerces-c-3.1.so: cannot open shared object file: No such file or directory" libxerces-c-3.1.so is in the directory /opt/lib which I have included as a library in eclipse. The file is there when I checked the folder. When I perform an 'echo $LD_LIBRARY_PATH', /opt/lib is also listed. Any ideas into where the problem lies? Thanks. An 'ldd libxerces-c-3.1.so' command yields the following output: linux-vdso.so.1 => (0x00007fffeafff000) libnsl.so.1 => /lib/libnsl.so.1 (0x00007fa3d2b83000) libpthread.so.0 => /lib/libpthread.so.0 (0x00007fa3d2966000) libstdc++.so.6 => /usr/lib/libstdc++.so.6 (0x00007fa3d265f000) libm.so.6 => /lib/libm.so.6 (0x00007fa3d23dc000) libc.so.6 => /lib/libc.so.6 (0x00007fa3d2059000) libgcc_s.so.1 => /lib/libgcc_s.so.1 (0x00007fa3d1e42000) /lib64/ld-linux-x86-64.so.2 (0x00007fa3d337d000)

    Read the article

  • Wordpress Event list

    - by kwek-kwek
    Hi I have followed a tutorial to create and event list in wordpress using post and Custom Fields view demo here is my code: <?php // Get today's date in the right format $todaysDate = date('M d'); ?> <?php query_posts('showposts=5&category_name=events&meta_key=Date&meta_compare=>=&meta_value='.$todaysDate.'&orderby=meta_value=order=ASC'); ?> <ul> <?php if (have_posts()) : while (have_posts()) : the_post(); $eventMeta = get_post_meta($post->ID, 'Date', true); $eventDate = strtotime($eventMeta); $displayDate = date ('M d', $eventDate);?> <li> <span class="date"><?php echo $displayDate ; ?></span> <span><a href="<?php the_permalink(); ?>" title="<?php the_title(); ?>"><?php the_title(); ?></a></span> </li> <?php endwhile; else: ?> <li>Sorry, no upcoming events!</li> <?php endif; ?> </ul> <?php wp_reset_query(); ?> Now my problem is that it doesn't show any events for the future events e.g. (June, July etc. ...). On one of the the discussion there someone had said about putting "In your query_posts, just use the parameter ‘post_status=future’ ". Can you please let me know exactly where? I have added it but nothing happened.

    Read the article

  • Symfony 1.3: how to force as inline the choices generated by renderLabel()

    - by user248959
    Hi, this line: <li><?php echo $form['genero']->renderLabel() ?></li> is generating <li> <label for="usuario_genero">Genero</label> <ul class="radio_list"> <li> <!-- this li doesn't have any id--> <input type="radio" checked="checked" id="usuario_genero_0" value="0" name="usuario[genero]">&nbsp;<label for="usuario_genero_0">Chico</label> </li> <li> <!-- this li doesn't have any id--> <input type="radio" id="usuario_genero_1" value="1" name="usuario[genero]">&nbsp;<label for="usuario_genero_1">Chica</label> </li> </ul> </li> I'd like to force the choices as inline, but the li's generated don't have the 'id' attribute. What should i do? Regards Javi

    Read the article

  • How spoof referrer using curl

    - by golu molu
    I am using curl code below to spoof referrer , it works fine but there is error on every page - Curl error: $url = somesite.com function doMagic($url) { $curl = curl_init(); $header[0] = "Accept: text/xml,application/xml,application/xhtml+xml,"; $header[0] .= "text/html;q=0.9,text/plain;q=0.8,image/png,*/*;q=0.5"; $header[] = "Cache-Control: max-age=0"; $header[] = "Connection: keep-alive"; $header[] = "Keep-Alive: 300"; $header[] = "Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7"; $header[] = "Accept-Language: en-us,en;q=0.5"; $header[] = "Pragma: "; curl_setopt($curl, CURLOPT_URL, $url); curl_setopt($curl, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:7.0.1) Gecko/20100101 Firefox/7.0.12011-10-16 20:23:00"); curl_setopt($curl, CURLOPT_HTTPHEADER, $header); curl_setopt($curl, CURLOPT_REFERER, "http://www.facebook.com"); curl_setopt($curl, CURLOPT_ENCODING, "gzip,deflate"); curl_setopt($curl, CURLOPT_AUTOREFERER, true); curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl, CURLOPT_TIMEOUT, 30); curl_setopt($curl, CURLOPT_FOLLOWLOCATION,true); $html = curl_exec($curl); echo 'Curl error: '. curl_error($curl); curl_close($curl); return $html; } $text = doMagic($url); print("$text"); what i'm doing wrong?

    Read the article

  • How to get MySQL database to appear on index.php

    - by Teddy Truong
    Hi, I have a submission form on my website (index.php) and I have the data(user submissions) being stored into a MySQL database. Right now, I have the user submitting a post and then the page directs them to an update.php which shows what they inputed. However, I want all of the data in the database in MySQL to be shown on the index.php. It's a lot like a comment system. User submits a post... and sees their post above the other submitted posts all on the same page. I think I'm missing AJAX... ? Here is the code for index.php <div align="center"> <p>&nbsp;</p> <h2 align="center" class="Title"><em><strong>REDACTED</strong></em></h2> <form id="form1" name="form1" method="post" action="update.php"> <hr /> <label><br /> <form action="update.php" method="post"> REDACTED: <input type="text" name="text" /> <input type="submit" /> </form> </label> </form> </div> On update.php I have this: ?php $text = $_POST['text']; $myString = "REDACTED"; mysql_connect ("db----.net", "-----3", "------------") or die ('Error: ' . mysql_error()); mysql_select_db ("-----------"); $query="INSERT INTO TextArea (ID, text) VALUES ('NULL', '".$text."')"; mysql_query($query) or die ('Error updating database'); echo " $myString "," $text "; ?> Thanks a lot!

    Read the article

  • wordpress displaying the post in a specific categories

    - by Juliver Galleto
    I have this php code below for displaying the post from the specific categories. <ul id="sliderx"> <?php query_posts('category_name=slideshow&showposts=10'); while (have_posts()) : the_post(); echo "<li>".the_content()."</li>"; endwhile;?> </ul> as you can see, it display those post in the category slideshow and the structure of that should be this. <ul id="sliderx"> <li>the post 1</li> <li>the post 2</li> <li>the post 3</li> </ul> but the output that is generated is this. <ul id="sliderx"> <p>three</p> <li></li><p>two</p> <li></li><p>one</p> <li></li> </ul> and the generated structure should not look like that and it looks nasty at all, so im having a problem on this on how to display it properly like to display into this structure. <ul id="sliderx"> <li>the post 1</li> <li>the post 2</li> <li>the post 3</li> </ul> So Im wondering if there's someone who could tell me how to fix this. Im open into any suggestions, recommendations and suggestions. Thank you.

    Read the article

  • Windows batch - loop over folder string and parse out last folder name

    - by Tim Peel
    Hi, I need to grab the folder name of a currently executing batch file. I have been trying to loop over the current directory using the following syntax (which is wrong at present): set mydir = %~p0 for /F "delims=\" %i IN (%mydir%) DO @echo %i Couple of issues in that I cannot seem to pass the 'mydir' variable value in as the search string. It only seems to work if I pass in commands; I have the syntax wrong and cannot work out why. My thinking was to loop over the folder string with a '\' delimiter but this is causing problems too. If I set a variable on each loop then the last value set will be the current folder name. For example, given the following path: C:\Folder1\Folder2\Folder3\Archive.bat I would expect to parse out the value 'Folder3'. I need to parse that value out as its name will be part of another folder I am going to create further down in the batch file. Many thanks if anyone can help. I may be barking up the wrong tree completely so any other approaches would be greatly received also. Tim

    Read the article

  • php curl login not work

    - by Massimo Zampieri
    Hi i have a problem with the curl. I watched an old post Remote Login not Working With Curl, but it not work. I followed baba's advice but the code enter in the if statement. Sorry for my bad english. Can anyone help me? This is the code: $url="http://hipfile.com/"; $urllog="http://hipfile.com/login.html"; $postdata = "login=bnnoor&password=########&op=login"; $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_REFERER, $urllog); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); if (!$result) { $http_code = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); // make sure we closeany current curl sessions die($http_code.' Unable to connect to server. Please come back later.'); } echo $result; curl_close($ch);

    Read the article

  • PHP Overloading, singleton instance

    - by jamalali81
    I've sort of created my own MVC framework and am curious as to how other frameworks can send properties from the "controller" to the "view". Zend does something along the lines of $this->view->name = 'value'; My code is: file: services_hosting.php class services_hosting extends controller { function __construct($sMvcName) { parent::__construct($sMvcName); $this->setViewSettings(); } public function setViewSettings() { $p = new property; $p->banner = '/path/to/banners/home.jpg'; } } file: controller.php class controller { public $sMvcName = "home"; function __construct($sMvcName) { if ($sMvcName) { $this->sMvcName = $sMvcName; } include('path/to/views/view.phtml'); } public function renderContent() { include('path/to/views/'.$this->sMvcName.'.phtml'); } } file: property.php class property { private $data = array(); protected static $_instance = null; public static function getInstance() { if (null === self::$_instance) { self::$_instance = new self(); } return self::$_instance; } public function __set($name, $value) { $this->data[$name] = $value; } public function __get($name) { if (array_key_exists($name, $this->data)) { return $this->data[$name]; } } public function __isset($name) { return isset($this->data[$name]); } public function __unset($name) { unset($this->data[$name]); } } In my services_hosting.phtml "view" file I have: <img src="<?php echo $this->p->banner ?>" /> This just does not work. Am I doing something fundamentally wrong or is my logic incorrect? I seem to be going round in circles at the moment. Any help would be very much appreciated.

    Read the article

  • Facebook API - delete status

    - by Simon R
    In PHP, I'm using curl to send a delete to the fb graph api - and yet I'm getting the following error; {"error":{"type":"GraphMethodException","message":"Unsupported delete request."}} The code I'm using is; $ch = curl_init("https://graph.facebook.com/" . $status_id . ""); curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_TIMEOUT, 120); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $query); curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "DELETE"); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt($ch, CURLOPT_CAINFO, NULL); curl_setopt($ch, CURLOPT_CAPATH, NULL); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 0); $result = curl_exec($ch); echo $result; $query contains the access token.

    Read the article

< Previous Page | 227 228 229 230 231 232 233 234 235 236 237 238  | Next Page >