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  • MySQL: Insert into multiple tables in same query with BEGIN&COMMIT

    - by strc
    I want to insert into multiple tables in same query by using BEGIN and COMMIT. It seems the error occur at begin. here is my SQL command BEGIN INSERT INTO Product (pName, pBrand, pCategory, pSize, pQuantity, pPrice, pDetail) VALUES('$name', '$brand', '$category', '$size', '$quantity', '$price', '$detail') INSERT INTO Image (iName, iExt, iSize, pID) VALUES('$img_name', '$img_ext', '$img_size', LAST_INSERT_ID()); COMMIT;

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  • MySQL GROUP BY with three tables

    - by Psaniko
    I have the following tables: posts (post_id, content, etc) comments (comment_id, post_id, content, etc) posts_categories (post_category_id, post_id, category_id) and this query: SELECT `p`.*, COUNT(comments.comment_id) AS cmts, posts_categories.*,comments.* FROM `posts` AS `p` LEFT JOIN `posts_categories` ON `p`.post_id = `posts_categories`.post_id LEFT JOIN `comments` ON `p`.post_id = `comments`.post_id GROUP BY `p`.`post_id` There are three comments on post_id=1 and four in total. In posts_categories there are two rows, both assigned to post_id=1. I have four rows in posts. But if I query the statement above I get a result of 6 for COUNT(comments.comment_id) at post_id=1. How is this possible? I guess the mistake is somewhere in the GROUP BY clause but I can't figure out where. Any suggestions?

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  • PHP MySQL query help

    - by user547794
    Hello, I am trying to use this query to return every instance where the variable $d['userID'] is equal to the User ID in a separate table, and then echo the username tied to that user ID. Here's what I have so far: $uid = $d['userID']; $result = mysql_query("SELECT u.username FROM users u LEFT JOIN comments c ON c.userID = u.id WHERE u.id = $uid;")$row = mysql_fetch_assoc($result); echo $row['username'];

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  • MySQL: How to do a conditional update?

    - by Tom
    Hi, I'm trying to a create an update statement along the following lines: TABLE car: id | owner_id | type | status An owner can have multiple cars. UPDATE car c SET c.type = 1 WHERE c.owner_id IN ($ids) AND c.status = [1 IF IT EXISTS, ELSE 0] $ids is reasonably small (under 50 values). It seems simple but I can't seem to get my head around it because I can't use a SELECT subquery with an UPDATE to the same table. Anyone? Thanks

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  • Creating an array from a MySQL table

    - by Rob
    I'm trying to create an array to use for a curl_multi_exec, but I can't seem to create the array properly. Here is my code: $SQL = mysql_query("SELECT url FROM urls") or die(mysql_error()); //Query the shell table while($resultSet = mysql_fetch_array($SQL)){ $urls[]=$resultSet; } echo $urls; //Test that the array works But when I run this script, all it does is echo "Array" I have no idea what I'm doing wrong, I've checked around google a bit, but can't figure it out. Any insight would be appreciated.

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  • Getting id of row just inserted into MySQL database

    - by James P
    I have my table columns set like this: likes(id, like_message, timestamp) id is the primary key that is auto incrementing. This is the SQL that I use to add a row: $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; Everything works, but now I need to throw back the id attribute of the newly inserted row. For example, if I insert a row and the id of that row is 13, I need to echo out 13 so my AJAX request can pick that up and use it. Any help would be appreciated, as well as related code samples. Thanks :)

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  • Mysql database structure...

    - by Patrick
    I'm creating a members site, and I'm currently working on the user Preference settings. Should I create a table with all the preference fields (about 17 fields) or should I include them in the main member table along with the account settings? Is there a limit as to how many fields I should have in a table? currently the member table has about 21 fields... not sure if its okay to add another 17 more fields when I can easily just put them in another table. It'll take more coding to pull up the data though... any sugguestions?

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  • Selecting two specific mysql table rows in a single query

    - by Scotta
    Lets say I have a table with 20 entries. They are sorted by date (date is a column name _) in descending order. How would I go about selecting ONLY the newest entry and the 15th oldest entry? I am getting all 15 results by doing the following query SELECT * FROM mytable m WHERE col1 = "zzz" ORDER BY date DESC LIMIT 15;

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  • MySQL: NOW() giving me zeros

    - by Tunji Gbadamosi
    I have a table which I want to record the timestamp of every order at every insertion time. However, I'm getting zero values for the timestamps. Here's my schema: CREATE TABLE IF NOT EXISTS orders( order_no VARCHAR(16) NOT NULL, volunteer_id VARCHAR(16) NOT NULL, date TIMESTAMP DEFAULT NOW(), PRIMARY KEY (order_no), FOREIGN KEY (volunteer_id) REFERENCES volunteer(id) ON UPDATE CASCADE ON DELETE CASCADE)

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  • MySQL join not returning rows

    - by John
    I'm attempting to create an anti-bruteforcer for the login page on a website. Unfortunately, my query is not working as expected. I would like to test how many times an IP address has attempted to login, and also return the ID of the user for my next step in the login process. However, I'm having a problem with the query... for one thing, this would only return rows if it was the same user as they had been trying to login to before. I need it to be any user. Secondly, regardless of whether I use LEFT JOIN, RIGHT JOIN, INNER JOIN or JOIN, it will not return the user's ID unless there is a row for the user in login_attempts. SELECT COUNT(`la`.`id`), `u`.`id` FROM `users` AS `u` LEFT JOIN `login_attempts` AS `la` ON `u`.`id` = `la`.`user_id` WHERE `u`.`username` = 'admin' AND `la`.`ip_address` = '127.0.0.1' AND `la`.`timestamp` >= '1'

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  • PHP & MySQL - Undefined variable problem?

    - by TaG
    I keep getting the following error Undefined variable: password on line 33 how do I correct this problem? So this error will stop showing. Here is the php code. $first_name = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['first_name'])))); $password1 = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($_POST['password1']))); $password2 = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($_POST['password2']))); // Check for a password and match against the confirmed password: if ($password1 == $password2) { $sha512 = hash('sha512', $password1); $password = mysqli_real_escape_string($mysqli, $sha512); } else { echo '<p class="error">Your password did not match the confirmed password!</p>'; } //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, password) VALUES ('$user_id', '$first_name', '$password')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', password = '$password' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; }

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  • Mysql ADDDATE() or DATE_ADD() with table columns?

    - by John
    How do I do something like the following SELECT ADDDATE(t_invoice.last_bill_date, INTERVAL t_invoice.interval t_invoice.interval_unit) FROM t_invoice ...where the column t_invoice.last_bill_date is a date, t_invoice.interval is an integer and t_invoice.interval_unit is a string. Basically, I want to determine a person's next bill date based on his desired billing frequency. Is there a better way to achieve this?

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  • PHP & MySQL Problem

    - by Fincha
    I Have a script, getting text from DB and post it on other DB. Problem is, if I have a Text lngen then 840 Words, I can't call this page. Get an error about "Not Found" or "Connection brocken" or what ever. In FF i get no error, only blank page. I found out the Problem is in lenght of the query i send... but how can i fix it??? My it be the Problem, if a query is longer then 6000 Characters?

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  • finding if an anniversary is coming up in n days in MySql

    - by user151841
    I have a table with anniversary dates. I want a query that returns me rows of anniversaries coming up in the next 10 days. For instance: birthdate --------- 1965-10-10 1982-05-25 SELECT birthdate FROM Anniversaries WHERE mystical_magical_mumbo_jumbo <= 10 +------------+ | birthdate | +------------+ | 1982-05-25 | +------------+ 1 row in set (0.01 sec) I'd like to keep the query in the form x <= 10, because I'll use that number 10 in other parts of the query, and if I set it to a variable, I can change it once everywhere by changing the variable, and not have to re-write the query.

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  • How to search mulitple value seperated by commas in mysql

    - by Fero
    Hi all, How to search multiple values separated by commas. ex: table name : searchTest id name keyword 1 trophy1 test1,test2,test3 2 trophy2 test2,test5 Points: If i search for test2 both results trophy1 and trophy2 should be display. If i search for trophy1 then trophy1 should be as result. How to solve this issue. thanks in advance

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  • MySQL: searh by host name in field containing urls

    - by Silver Light
    Hello! I have this database table: id | url ----------------------------------------- 1 | http://stackoverflow.com/ 2 | http://www.google.com 3 | http://example.com/somepage 4 | https://another.net?id=88 5 | http://hello.org/index.php?hello=2 6 | http://google.com?q=hello+world I need to search all fields, where URL belongs to a certain host. For example, if I give the query 'google.com', it will return rows 2 and 6 (www is ignored). I get the host using PHP parse_url() function. How this SQL query would look like?

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  • Select multiple unique lines in MySQL

    - by MartinW
    Hi, I've got a table with the following columns: ID, sysid, x, y, z, timereceived ID is a unique number for each row. sysid is an ID number for a specific device (about 100 different of these) x, y and z is data received from the device. (totally random numbers) timereceived is a timestamp for when the data was received. I need a SQL query to show me the last inserted row for device a, device b, device c and so on. I've been playing around with a lot of different Select statements, but never got anything that works. I manage to get unique rows by using group by, but the rest of the information is random (or at least it feels very random). Anyone able to help me? There could be hundreds of thousands records in this table.

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  • Order and group by date in Mysql

    - by Alexd2
    Hi all and thanks in advance. I have a small problem which can not resolve, I have this table, and I want to sort by date and group it (but I only show 1 per idCAT) | id | idcat | name | date | | 1 | 3 | xx | 2011-01-02 | | 2 | 4 | xf | 2011-01-02 | | 3 | 3 | cd | 2011-01-01 | | 4 | 1 | cg | 2011-01-04 | | 5 | 4 | ce | 2011-01-06 | would like to stay that way, try in a way but I can not | 2 | 4 | xf | 2011-01-01 | | 3 | 3 | cd | 2011-01-02 | | 4 | 1 | cg | 2011-01-04 |

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  • MySQL log files deletion

    - by aneez
    I have a master and slave database running on different nodes. The master DB is subjected to huge no. of inserts/updates. The master DB size is close to 6 GB, while the log files are now occupying a space of more than 120 GB. I am running out of disk space and need to get rid of the log files. Will deleting the log files in anyway affect the slave DB ? Presently, the slave is just a couple of seconds behind the master. Is there someplace where I can see what steps I need to follow to delete those files eg. 1)Shut down the slave 2)Shut down the master 3)Delete the log files 4)Start the Master 5)Start the Slave Do I need to inform the slave that the log files have been deleted ?? If yes, what is the way to do it ? Any help would be appreciated. Thanks

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  • Show the specific field on mysql table based on active date

    - by mrjimoy_05
    Suppose that I have 3 tables: A) Table UsrHeader ----------------- UsrID | UsrName ----------------- 1 | Abc 2 | Bcd B) Table UsrDetail ------------------------------- UsrID | UsrLoc | Date ------------------------------- 1 | LocA | 10 Aug 2012 1 | LocB | 15 Aug 2012 2 | LocA | 10 Aug 2012 C) Table Trx ----------------------------- TrxID | TrxDate | UsrID ----------------------------- 1 | 10 Aug 2012 | 1 2 | 16 Aug 2012 | 1 3 | 11 Aug 2012 | 2 What I want to do is to show the table like: --------------------------------------- TrxID | TrxDate | UsrID | UsrLoc --------------------------------------- 1 | 10 Aug 2012 | 1 | LocA 2 | 16 Aug 2012 | 1 | LocB 3 | 11 Aug 2012 | 2 | LocA Notice that there is one user but different location. That's based on the UsrDetail table that the user on a specified date has moved to another location. So, it should be show the user specific location on that date on every transaction. I have try this code but it is no luck: SELECT trx.TrxID, trx.TrxDate, trx.UsrID, User.UsrName, User.UsrLoc FROM trx INNER JOIN ( SELECT UsrHeader.UsrID, UsrHeader.UsrName, UserDetail.UsrLoc FROM UsrHeader INNER JOIN ( SELECT UsrDetail.UsrID, UsrDetail.UsrLoc, UsrDetail.Date FROM UsrDetail ) AS UserDetail ON UserDetail.UsrID = UsrHeader.UsrID ) AS User ON User.UsrID = trx.UsrID AND trx.TrxDate >= User.Date How to do that? Thanks..

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  • mysql select help

    - by user344766
    Hi I have a table that looks like this id : productid : featureid and would have the following data: (1, 1, 16) (2, 1, 21) (3, 1, 25) (4, 2, 16) (5, 2, 21) (6, 2, 27) where featureid is a foreign key to another table. I need to select products that have both featureids of 16 and 25, in which case productid 1 but not productid 2 Can someone show me an example of how to format this query.

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