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  • MySQL - JOINS (excepts)

    - by user2529899
    I'm trying to find 2 different result via JOINS. Table look like; SELECT id,member_id,registered_year FROM records; I can listing which members registered in 2012 and also in 2013 with; SELECT member_id FROM records a INNER JOIN records b ON a.member_id=b.member_id WHERE a.registered_year='2013' AND b.registered_year='2012'; But I can't list revers of It. How can I list which members were registered in 2012 but not in 2013? Thnx in advance.

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  • mysql codeigniter active record m:m deletion

    - by sea_1987
    Hi There, I have a table 2 tables that have a m:m relationship, what I can wanting is that when I delete a row from one of the tables I want the row in the joining table to be deleted as well, my sql is as follow, Table 1 CREATE TABLE IF NOT EXISTS `job_feed` ( `id` int(11) NOT NULL AUTO_INCREMENT, `body` text NOT NULL, `date_posted` int(10) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; Table 2 CREATE TABLE IF NOT EXISTS `job_feed_has_employer_details` ( `job_feed_id` int(11) NOT NULL, `employer_details_id` int(11) NOT NULL, PRIMARY KEY (`job_feed_id`,`employer_details_id`), KEY `fk_job_feed_has_employer_details_job_feed1` (`job_feed_id`), KEY `fk_job_feed_has_employer_details_employer_details1` (`employer_details_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; So what I am wanting to do is, if the a row is deleted from table1 and has an id of 1 I want the row in table to that also has that idea as part of the relationship also. I want to do this in keeping with codeigniters active record class I currently have this, public function deleteJobFeed($feed_id) { $this->db->where('id', $feed_id) ->delete('job_feed'); return $feed_id; }

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  • mySQL JOIN wont return results with 0 count

    - by MPC
    SELECT categories.*, COUNT(categoryID) AS kritCount FROM categories AS categories LEFT JOIN krits ON categories.id = categoryID WHERE (krits.approved = '1') GROUP BY categories.id So this works great except that it does not return a category that has a 0 count of krits in the category. It will if I remove the WHERE statement but I need the WHERE to only select the krits where the field approved = 1

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  • How to Download my MYSQL Backup?

    - by NiCk Newman
    Okay I use this script here to make a backup of my database: mysqldump -u root -h localhost -pPASSWORD forums | gzip -9 > backup-$(date +%Y-%m-%d).sql.gz This is used in a cron daily. But I need to download this remotely or through a ftp program every day as well so I have a physical copy of it on my home hard drive, is this possible? I know it is, can anyone tell me a quick way to do it?

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  • Creating CFArray from MySQL Result Array

    - by Andrew
    Is there an easy way to dump an array returned from mysql_fetch_row into a CFArray? (part of the PHP implementation of CFPropertyList) I'm bummed by the lack of documentation on CFPropertyList for PHP. Iterating through each item in the array seems inefficient. I'm open to using a different mysql_fetch_... command. I'd like to just say: $NewArray = new CFArray( $ResultArray ) But that deosn't seem to work. This is my current code: $plist = new CFPropertyList(); $ResultRow = mysqli_fetch_row( $result ); $plist-add( $TableRow = new CFArray() ); foreach ( $ResultRow as $Item ){ $TableRow-add( new CFString( $Item ) ); }

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  • how to remove mysql root password

    - by nectar
    I want to remove password for user root in localhost how can I do that?by mistake I have set the password of root user thats why phpmyadmin is giving error- #1045 - Access denied for user 'root'@'localhost' (using password: NO)

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  • Help me with query string parameters (Rails)

    - by Martin Petrov
    Hi, I'm creating a newsletter. Each email contains a link for editing your subscription: <%= edit_user_url(@user, :secret => @user.created_at.to_i) %> :secret = @user.created_at.to_i prevents users from editing each others profiles. def edit @user = user.find(params[:id]) if params[:secret] == @user.created_at.to_i render 'edit' else redirect_to root_path end end It doesn't work - you're always redirected to root_path. It works if I modify it like this: def edit @user = user.find(params[:id]) if params[:secret] == "1293894219" ... 1293894219 is the "created_at.to_i" for a particular user. Do you have any ideas why?

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  • how store date in mysql database?

    - by Syom
    i have date in dd/mm/yyyy format. how can i store it in databse, if i fant to do some operations on them after? for example i must find out the rows, where date > something what type i must set to date field? thanks

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  • mysql_num_rows(): supplied argument is not a valid MySQL result resource

    - by php-b-grader
    I am getting this error when I pass an invalid SQL string... I spent the last hour trying to find the problem assuming - It's not my SQL it must be the db handle... ANyway, I've now figured out that it was bad SQL... What I want to do is test the result of the mysql_query() for a valid resultset. I am simply using empty($result)... Is this the most effective test? Is there a more widely accepted method of testing a resultset for a valid result?

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  • Query to check the consistency of records

    - by orunner
    I have four tables TableA: id1 id2 id3 value TableB: id1 desc TableC: id2 desc TableD: id3 desc What I need to do is to check if all combinations of id1 id2 id3 from table B C and D exist in the TableA. In other words, table A should contain all possible combinations of id1 id2 and id3 which are stored in the other three tables.

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  • Selecting distinct values from mysql with largest timestamp

    - by user987048
    I am building a mail system. The inbox is only supposed to grab the last message (one with the highest time value) of a concatenation of user and sender, where the user or sender is the user ID. Here is the table structure: CREATE TABLE IF NOT EXISTS `mail` ( `user` int(11) NOT NULL, `sender` int(11) NOT NULL, `body` text NOT NULL, `new` enum('0','1') NOT NULL default '1', `time` int(11) NOT NULL, KEY `user` (`user`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; So, with a table with the following data: user sender new time ***************************************** 1 0 0 5 1 0 0 6 2 1 0 7 1 0 1 8 1 2 0 9 1 0 1 11 1 2 1 12 I want to select the following: WHERE USER OR SENDER = X (in this case, 1) user sender new time ***************************************** 2 1 0 7 1 2 0 9 1 0 1 11 How would I go about doing something like this?

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  • MySQL: group by and IF statement

    - by notset
    By default, parent_id = 0. I want to select all records with parent_id = 0 and only the last ones with parent_id 0. I tried this, but it didn't work: SELECT * FROM `articles` IF `parent_id` > 0 THEN GROUP BY `parent_id` HAVING COUNT(`parent_id`) >= 1 END; ORDER BY `time` DESC What could be the solution?

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  • onUpdate in MySQL means?

    - by ajsie
    i know that if you create a foreign key on a field (parent_id) in a child table that refer to a parent table's primary key (id), then if this parent table is deleted the child class will be deleted as well if you set onDelete to cascade when creating the foreign key in the child class. but what happens if i set it to onUpdate = cascade?

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  • Duplication in mysql/php

    - by user1334095
    I have a problem in the code.i have two tables 'sms' and 'bd_paid_bribe'.sms table has a column 'Message' and bd_paid_bribe table has a column 'c_addi_info'.when i execute the code first time all the values of Message column are inserted into c_addi_info column.when i enter a record for the second time instead of inserting the new record, all the records of Message column are inserted into bd_paid_bribe column.can u modify the code and provide a solution to avoid duplication and to insert only the newly added record. <?php $con=mysql_connect('localhost','root',''); if(!$con) { die("couldn't connect"); } mysql_select_db("ipab2",$con); $rs2=mysql_query(" select max(sms_index) from tab3"); do { $rs=mysql_query("insert into tab3(sms_index)select max(sms_index) from sms"); $rs3=mysql_query("SELECT max(sms_index) FROM sms"); $rs1=mysql_query("insert into bd_paid_bribe(c_addi_info) select Message from sms "); }while($rs2>$rs3); ?>

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  • javascript - query object graph?

    - by Scott
    Given an object like this: var obj = { first:{ second:{ third:'hi there' } } }; And a key like this "first.second.third" How can I get the value of the nested object "hi there"? I think maybe the Array.reduce function could help, but not sure.

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  • how to change a while sql query loop into an array loop

    - by Mac Taylor
    hey guys i record number of queries of my website and in page the below script runs , 40 extra queries added to page . how can I change this sql connection into a propper and light one function tree_set($index) { //global $menu; Remove this. $q=mysql_query("select id,name,parent from cats where parent='$index'"); if(mysql_num_rows($q) === 0) { return; } // User $tree instead of the $menu global as this way there shouldn't be any data duplication $tree = $index > 0 ? '<ul>' : ''; // If we are on index 0 then we don't need the enclosing ul while($arr=mysql_fetch_assoc($q)) { $subFileCount=mysql_query("select id,name,parent from cats where parent='{$arr['id']}'"); if(mysql_num_rows($subFileCount) > 0) { $class = 'folder'; } else { $class = 'file'; } $tree .= '<li>'; $tree .= '<span class="'.$class.'">'.$arr['name'].'</span>'; $tree .=tree_set("".$arr['id'].""); $tree .= '</li>'."\n"; } $tree .= $index > 0 ? '</ul>' : ''; // If we are on index 0 then we don't need the enclosing ul return $tree; } i heard , this can be done by changing it into an array , but i don't know how to do so thanks in advance

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  • Need a MYSQL query to compare two tables and only output non matching results

    - by ee12csvt
    I have two tables in my database, one contains a list of items with other information on these items. The other table is contains a list of photographs of these items. The items table gives each item a unique identifier,which is used in the photographs table to identifier which item has been photographed. I need to output a list of items that are not linked to a photograph in the second table. Any ideas on how I can do this?

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