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  • label as dynamic navigation

    - by KareemSaad
    I Made label to had value from database and linked it . but the problem was it had only one value and i want it keep value when navigation thought site as. xyz.... this is my code < if (Request.QueryString["Category_Id"] != null) { Banar.ImageUrl = "Handlers/Banner.ashx?Category_Id=" + Request.QueryString["Category_Id"] + ""; using (SqlConnection conn = Connection.GetConnection()) { SqlCommand cmd = new SqlCommand(); cmd.Connection = conn; cmd.CommandType = CommandType.StoredProcedure; cmd.CommandText = "Navcategory"; cmd.Parameters.Add(Parameter.NewInt("@Category_Id", Request.QueryString["Category_Id"])); SqlDataReader dr = cmd.ExecuteReader(); if (dr.Read()) { LblNavigaton.Visible = true; LblNavigaton.Text = dr[i].ToString(); NavHref.HRef = "ListView.aspx?Category_Id=" + Request.QueryString["Category_Id"] + ""; } } } else if (Request.QueryString["ProductCategory_Id"] != null) { Banar.ImageUrl = "Handlers/ProCatBanner.ashx?ProductCategory_Id=" + Request.QueryString["ProductCategory_Id"] + ""; using (SqlConnection conn = Connection.GetConnection()) { SqlCommand cmd = new SqlCommand(); cmd.Connection = conn; cmd.CommandType = CommandType.StoredProcedure; cmd.CommandText = "NavProductcategory"; cmd.Parameters.Add(Parameter.NewInt("@ProductCategory_Id", Request.QueryString["ProductCategory_Id"])); SqlDataReader dr = cmd.ExecuteReader(); if (dr.Read()) { LblNavigaton.Visible = true; LblNavigaton.Text = dr["Name"].ToString(); NavHref.HRef = "ListView.aspx?ProductCategory_Id=" + Request.QueryString["ProductCategory_Id"] + ""; } else { LblNavigaton.Visible = true; LblNavigaton.Text = Page.Title; } }

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  • What are the attack vectors for passwords sent over http?

    - by KevinM
    I am trying to convince a customer to pay for SSL for a web site that requires login. I want to make sure I correctly understand the major scenarios in which someone can see the passwords that are being sent. My understanding is that at any of the hops along the way can use a packet analyzer to view what is being sent. This seems to require that any hacker (or their malware/botnet) be on the same subnet as any of the hops the packet takes to arrive at its destination. Is that right? Assuming some flavor of this subnet requirement holds true, do I need to worry about all the hops or just the first one? The first one I can obviously worry about if they're on a public Wifi network since anyone could be listening in. Should I be worried about what's going on in subnets that packets will travel across outside this? I don't know a ton about network traffic, but I would assume it's flowing through data centers of major carriers and there's not a lot of juicy attack vectors there, but please correct me if I am wrong. Are there other vectors to be worried about outside of someone listening with a packet analyzer? I am a networking and security noob, so please feel free to set me straight if I am using the wrong terminology in any of this.

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  • Grep... What patterns to extract href attributes, etc. with PHP's preg_grep?

    - by inktri
    Hi, I'm having trouble with grep.. Which four patterns should I use with PHP's preg_grep to extract all instances the "____" stuff in the strings below? 1. <h2><a ....>_____</a></h2> 2. <cite><a href="_____" .... >...</a></cite> 3. <cite><a .... >________</a></cite> 4. <span>_________</span> The dots denote some arbitrary characters while the underscores denote what I want. An example string is: </style></head> <body><div id="adBlock"><h2><a href="https://www.google.com/adsense/support/bin/request.py?contact=afs_violation&amp;hl=en" target="_blank">Ads by Google</a></h2> <div class="ad"><div><a href="http://www.google.com/aclk?sa=L&amp;ai=C4vfT4Sa3S97SLYO8NN6F-ckB5oq5sAGg6PKlDaT-kwUQASCF4p8UKARQtobS9AVgyZbRhsijoBnIAQGqBBxP0OSEnIsuRIv3ZERDm8GiSKZSnjrVf1kVq-_Y&amp;num=1&amp;sig=AGiWqtwG1qHnwpZ_5BNrjrzzXO5Or6EDMg&amp;q=http://www.crackle.com/c/Spider-Man_The_New_Animated_Series/%3Futm_source%3Dgoogle%26utm_medium%3Dcpc%26utm_campaign%3DGST_10016_CRKL_US_PRD_S_TeleV_SPID_Tele_Spider-Man%26utm_term%3Dspiderman%26utm_content%3Ds264Yjg9f_3472685742_487lrz1638" class="titleLink" target="_parent">Spider-<b>Man</b> Animated Serie</a></div> <span>See Your Favorite Spiderman <br> Episodes for Free. Only on Crackle.</span> <cite><a href="http://www.google.com/aclk?sa=L&amp;ai=C4vfT4Sa3S97SLYO8NN6F-ckB5oq5sAGg6PKlDaT-kwUQASCF4p8UKARQtobS9AVgyZbRhsijoBnIAQGqBBxP0OSEnIsuRIv3ZERDm8GiSKZSnjrVf1kVq-_Y&amp;num=1&amp;sig=AGiWqtwG1qHnwpZ_5BNrjrzzXO5Or6EDMg&amp;q=http://www.crackle.com/c/Spider-Man_The_New_Animated_Series/%3Futm_source%3Dgoogle%26utm_medium%3Dcpc%26utm_campaign%3DGST_10016_CRKL_US_PRD_S_TeleV_SPID_Tele_Spider-Man%26utm_term%3Dspiderman%26utm_content%3Ds264Yjg9f_3472685742_487lrz1638" class="domainLink" target="_parent">www.Crackle.com/Spiderman</a></cite></div> <div class="ad"><div><a href="http://www.google.com/aclk?sa=l&amp;ai=CnQFi4Sa3S97SLYO8NN6F-ckB3M7nQtyU2PQEq6bCBRACIIXinxQoBFCm15KB-f____8BYMmW0YbIo6AZoAHiq_X-A8gBAaoEIU_Q9JKLiy1MiwdnHpZoBnmpR1J8pP2jpTwMx2uj2nN4WA&amp;num=2&amp;sig=AGiWqtwDrI5pWBCncdDc80FKt32AJMAQ6A&amp;q=http://www.costumeexpress.com/browse/TV-Movies/_/N-1z141uu/Ntt-batman/results1.aspx%3FREF%3DKNC-CEgoogle" class="titleLink" target="_parent">Kids <b>Batman</b> Costumes</a></div> <span>Great Selection of <b>Batman</b> &amp; Batgirl <br> Costumes For Kids. Ships Same Day!</span> <cite><a href="http://www.google.com/aclk?sa=l&amp;ai=CnQFi4Sa3S97SLYO8NN6F-ckB3M7nQtyU2PQEq6bCBRACIIXinxQoBFCm15KB-f____8BYMmW0YbIo6AZoAHiq_X-A8gBAaoEIU_Q9JKLiy1MiwdnHpZoBnmpR1J8pP2jpTwMx2uj2nN4WA&amp;num=2&amp;sig=AGiWqtwDrI5pWBCncdDc80FKt32AJMAQ6A&amp;q=http://www.costumeexpress.com/browse/TV-Movies/_/N-1z141uu/Ntt-batman/results1.aspx%3FREF%3DKNC-CEgoogle" class="domainLink" target="_parent">www.CostumeExpress.com</a></cite></div> <div class="ad"><div><a href="http://www.google.com/aclk?sa=l&amp;ai=CAMYT4Sa3S97SLYO8NN6F-ckB3ZnWmgGdoNLrDaumwgUQAyCF4p8UKARQrqSVxwdgyZbRhsijoBmgAZH77uwDyAEBqgQYT9DU7oqLLEyLB2dHlxZFnQzyeg-yHt88&amp;num=3&amp;sig=AGiWqtzqAphZ9DLDiEFBJlb0Ou_1HyEyyA&amp;q=http://www.OfficialBatmanCostumes.com" class="titleLink" target="_parent"><b>Batman</b> Costume</a></div> <span>Official <b>Batman</b> Costumes. <br> Huge Selection &amp; Same Day Shipping!</span> <cite><a href="http://www.google.com/aclk?sa=l&amp;ai=CAMYT4Sa3S97SLYO8NN6F-ckB3ZnWmgGdoNLrDaumwgUQAyCF4p8UKARQrqSVxwdgyZbRhsijoBmgAZH77uwDyAEBqgQYT9DU7oqLLEyLB2dHlxZFnQzyeg-yHt88&amp;num=3&amp;sig=AGiWqtzqAphZ9DLDiEFBJlb0Ou_1HyEyyA&amp;q=http://www.OfficialBatmanCostumes.com" class="domainLink" target="_parent">www.OfficialBatmanCostumes.com</a></cite></div> <div class="ad"><div><a href="http://www.google.com/aclk?sa=l&amp;ai=C767t4Sa3S97SLYO8NN6F-ckBkZfSfoOppaMHq6bCBRAEIIXinxQoBFDX2bw6YMmW0YbIo6AZoAHpprP8A8gBAaoEG0_QhJSMiytMiwdnHpZoF3g0Uj8_Vl2r4TpI_g&amp;num=4&amp;sig=AGiWqtyGO2DnFq_jMhP6ufj8pufT9sWQWA&amp;q=http://www.discountsuperherocostumes.com/batman-costumes.html" class="titleLink" target="_parent">Discount <b>Batman</b> Costumes</a></div> <span>Discount adult and kids <b>batman</b> <br> superhero costumes.</span> <cite><a href="http://www.google.com/aclk?sa=l&amp;ai=C767t4Sa3S97SLYO8NN6F-ckBkZfSfoOppaMHq6bCBRAEIIXinxQoBFDX2bw6YMmW0YbIo6AZoAHpprP8A8gBAaoEG0_QhJSMiytMiwdnHpZoF3g0Uj8_Vl2r4TpI_g&amp;num=4&amp;sig=AGiWqtyGO2DnFq_jMhP6ufj8pufT9sWQWA&amp;q=http://www.discountsuperherocostumes.com/batman-costumes.html" class="domainLink" target="_parent">www.discountsuperherocostumes.com</a></cite></div></div></body> <script type="text/javascript"> var relay = ""; </script> <script type="text/javascript" src="/uds/?file=ads&amp;v=1&amp;packages=searchiframe&amp;nodependencyload=true"></script></html> Thanks!

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    Hi all, Im new to ofbiz.So is my question is have any mistake forgive me for my mistakes.Im new to ofbiz so i did not know some terminologies in ofbiz.Sometimes my question is not clear because of lack of knowledge in ofbiz.So try to understand my question and give me a good solution with respect to my level.Because some solutions are in very high level cannot able to understand for me.So please give the solution with good examples. My problem is i created a project inside the ofbiz/hot-deploy folder namely "productionmgntSystem".Inside the folder "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem" i created a .ftl file namely "app_details_1.ftl" .The following are the coding of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml" ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file "ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java" package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server.The file is get from user "<input type="file"..> tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1".But the file is not uploaded. Give me a good solution for uploading a file to the server. Thanks & Regards, Sivakumar.J

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  • Why do i need PUT or DELETE Http Verbs ?

    - by Barbaros Alp
    After the release of MVC 2, i have started to check and play with the new features. But i couldnt understand that why do i need to use PUT or DELETE verbs ? I have searched about it and read some articles but i couldnt get it. What is the main purpose of DELETE and PUT (and do they have any advantages rather than using a GET or POST method) even though i can handle all of the requests with GET and POST...

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  • How to log in to craigslist using c#

    - by kosikiza
    i m using the following code to log in to craigslist, but haven't succeeded yet. string formParams = string.Format("inputEmailHandle={0}&inputPassword={1}", "[email protected]", "removed"); //string postData = "[email protected]&inputPassword=removed"; string uri = "https://accounts.craigslist.org/"; HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri); request.KeepAlive = true; request.ProtocolVersion = HttpVersion.Version10; request.Method = "POST"; byte[] postBytes = Encoding.ASCII.GetBytes(formParams); request.ContentType = "application/x-www-form-urlencoded"; request.ContentLength = postBytes.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(postBytes, 0, postBytes.Length); requestStream.Close(); HttpWebResponse response = (HttpWebResponse)request.GetResponse(); cookyHeader = response.Headers["Set-cookie"]; string pageSource; string getUrl = "https://post.craigslist.org/del"; WebRequest getRequest = WebRequest.Create(getUrl); getRequest.Headers.Add("Cookie", cookyHeader); WebResponse getResponse = getRequest.GetResponse(); using (StreamReader sr = new StreamReader(getResponse.GetResponseStream())) { pageSource = sr.ReadToEnd(); }

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  • iPhone ASIHttpRequest - can't POST variables asynchronously

    - by Eamorr
    Greetings, I'm trying to simply POST data to a url using ASIHttpRequest. Here is my code: __block ASIHTTPRequest *request=[ASIHTTPRequest requestWithURL:url]; [request setPostBody:[NSMutableData dataWithData:[@"uname=Hello" dataUsingEncoding:NSUTF8StringEncoding]]]; [request setDelegate:self]; [request setCompletionBlock:^{ NSString *response=[request responseString]; UIAlertView *msg=[[UIAlertView alloc] initWithTitle:@"Response" message:response delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil]; [msg show]; [msg release]; }]; [request setFailedBlock:^{ NSError *error =[request error]; }]; [request startAsynchronous]; Basically, my url is xxx.xxx.xxx.xxx/login.php, when I dump the PHP $_POST variable, I just get an empty array - i.e. no POST parameters are sent! The rest of the PHP is tested and working fine. I've looked through the allseeing-i.com documentation and examples and can't seem to resolve this problem. Any insight greatly appreciated. Many thanks in advance,

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  • Spring Security 3.0 - Intercept-URL - All pages require authentication but one

    - by gav
    Hi All, I want any user to be able to submit their name to a volunteer form but only administrators to be able to view any other URL. Unfortunately I don't seem to be able to get this correct. My resources.xml are as follows; <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <http realm = "BumBumTrain Personnel list requires you to login" auto-config="true" use-expressions="true"> <http-basic/> <intercept-url pattern="/person/volunteer*" access=""/> <intercept-url pattern="/**" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_ADMIN"/> </user-service> </authentication-provider> </authentication-manager> </beans:beans> Specifically I am trying to achieve the access settings I described via; <intercept-url pattern="/person/volunteer*" access=""/> <intercept-url pattern="/**" access="isAuthenticated()" /> Could someone please describe how to use intercept-url to achieve the outcome I've described? Thanks Gav

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  • How to implement Session timeout in Web Server Side?

    - by Morgan Cheng
    I beheld a web framework implementing in-memory session in this way. The session object is added to Cache with timeout. When the time is out, the session is removed from Cache automatically. To protect race condition, each request should acquire lock on given session object to proceed. Each request will "touch" the session in Cache to refresh the timeout. Everything looks fine, until this scenario is discovered. Say, one operation takes a long time, longer than timeout. Another request comes and wait on session lock which is currently hold by the long-time request. Finally, the long-time request is over, it releases the lock. But, since it already takes longer time than timeout, the session object is already removed from Cache. This is obvious because the only request holding the lock doesn't have a chance to "touch" the session object in cache. The second request gets the lock but cannot retrieve the expired Session object. Oops... To fix this issue, the second request has to re-create the Session object. But, this is just like digging a buried dead body from tomb and try to bring it back to life. It causes buggy code. I'm wondering what's the best way to implement timeout in session to handle such scenario. I know that current platform must have good session mechanism. I just want to know the under-the-hood how.

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  • Is there a solution that lets Node.js act as an HTTP reverse proxy?

    - by Igor Zinov'yev
    Our company has a project that right now uses nginx as a reverse proxy for serving static content and supporting comet connections. We use long polling connections to get rid of constant refresh requests and let users get updates immediately. Now, I know there is a lot of code already written for Node.js, but is there a solution that lets Node.js act as a reverse proxy for serving static content as nginx does? Or maybe there is a framework that allows to quickly develop such a layer using Node.js?

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  • Starting ActiveMQ message listener in Tomcat?

    - by Nick Swarr
    I've created an ActiveMQ MessageListener and configured it using Spring. I'm hosting the listener in Tomcat. When I start up the web application (that features only the listener), should the listener automatically start? Or do I need additional configuration? Here's what I have. First, updated the web.xml to allow spring to configure itself on startup, <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/classes/spring/applicationContext.xml</param-value> </context-param> </web-app> Then I created the applicationContext.xml to configure the ActiveMQ listener, <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:amq="http://activemq.apache.org/schema/core" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <context:annotation-config /> <context:component-scan base-package="com.somepackage"/> <context:property-placeholder location="classpath:env.properties"/> <bean id="jmsFactory" class="org.apache.activemq.ActiveMQConnectionFactory"> <property name="brokerURL" value="tcp://localhost:61616" /> </bean> <bean id="documentListener" class="com.somepackage.SomeListener" /> <bean id="container" class="org.springframework.jms.listener.DefaultMessageListenerContainer"> <property name="connectionFactory" ref="cachingConnectionFactory"/> <property name="messageListener" ref="documentListener"/> <property name="destinationName" value="STOCKS.MSFT" /> </bean> <bean id="cachingConnectionFactory" class="org.springframework.jms.connection.CachingConnectionFactory"> <property name="targetConnectionFactory" ref="jmsFactory" /> <property name="sessionCacheSize" value="1" /> </bean> </beans> And that's it. Based on what I've seen around the web, I can't tell if that's all I need? Maybe I need some other configuration in Tomcat to kick off the listener?

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  • Problem with urllib

    - by Eva
    I wrote this code: import urllib proxies = {'http': 'http://112.65.135.54:8080/'} opener = urllib.FancyURLopener(proxies) r = opener.open("http://www.python.org/") print r.read() and when I execute it this program works fine, and send for me source code of python.org But when i use this: import urllib proxies = {'http': 'http://80.176.245.196:1080/'} opener = urllib.FancyURLopener(proxies) r = opener.open("http://www.python.org/") print r.read() this program does not send me the source code of python.org What am I going to do?

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  • Website does not resolve in browser but traceroute is successful

    - by Colum
    I am trying to figure out an issue. My internet is working fine, but this one website is not resolving. It works via a proxy, traceroute works: 1 192.168.1.1 (192.168.1.1) 4.205 ms 0.568 ms 0.510 ms 2 * * * 3 67.59.255.13 (67.59.255.13) 10.583 ms 7.949 ms 7.557 ms 4 67.59.255.61 (67.59.255.61) 10.256 ms 9.576 ms 13.083 ms 5 64.15.8.126 (64.15.8.126) 9.943 ms 11.929 ms 11.452 ms 6 64.15.0.217 (64.15.0.217) 14.655 ms 14.092 ms 13.771 ms 7 64.15.0.118 (64.15.0.118) 33.201 ms 34.875 ms 36.544 ms 8 xe-6-0-3.ar1.ord1.us.nlayer.net (69.31.111.169) 34.027 ms 34.957 ms 34.231 ms 9 ae1-30g.cr1.ord1.us.nlayer.net (69.31.111.133) 82.683 ms 35.138 ms 37.592 ms 10 xe-3-0-0.cr2.iad1.us.nlayer.net (69.22.142.26) 41.657 ms 34.063 ms 34.519 ms 11 ae2-30g.ar2.iad1.us.nlayer.net (69.31.31.186) 35.780 ms 36.361 ms 33.968 ms 12 as33597.xe-3-0-7.ar2.iad1.us.nlayer.net (69.31.30.230) 35.086 ms as33597.xe-3-0-7.ar2.iad1.us.nlayer.net (69.31.30.234) 38.031 ms as33597.xe-3-0-7.ar2.iad1.us.nlayer.net (69.31.30.230) 36.833 ms 13 cr1.iad2.inforelay.net (66.231.176.246) 32.595 ms cr2.iad1.inforelay.net (66.231.176.10) 31.771 ms cr1.iad2.inforelay.net (66.231.176.246) 32.622 ms 14 cr1.iad2.inforelay.net (66.231.176.246) 32.956 ms 33.625 ms !X 41.058 ms 15 * cr1.iad2.inforelay.net (66.231.176.246) 35.312 ms !X * 16 * cr1.iad2.inforelay.net (66.231.176.246) 32.814 ms !X * 17 cr1.iad2.inforelay.net (66.231.176.246) 35.459 ms !X * 53.137 ms !X Ping returns this: Request timeout for icmp_seq 0 Request timeout for icmp_seq 1 Request timeout for icmp_seq 2 Request timeout for icmp_seq 3 Request timeout for icmp_seq 4 Request timeout for icmp_seq 5 Request timeout for icmp_seq 6 But what I can not figure out is why my browsers (Firefox, Safari, Opera) can not resolve the domain. I am on a Wifi connection. What could be the problem? BTW I am on a Mac (10.6.5)

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  • while creating archetype getting following error

    - by munna
    D:\Training\workspace\vppsourcemvn archetype:generate -B -DarchetypeGroupId=org .appfuse.archetypes -DarchetypeArtifactId=appfuse-modular-struts-archetype -Darc hetypeVersion=2.1.0-M1 -DgroupId=com.vmware -DartifactId=vpp [INFO] Scanning for projects... [INFO] Searching repository for plugin with prefix: 'archetype'. [INFO] ------------------------------------------------------------------------ [INFO] Building Maven Default Project [INFO] task-segment: [archetype:generate] (aggregator-style) [INFO] ------------------------------------------------------------------------ [INFO] Preparing archetype:generate [INFO] No goals needed for project - skipping [INFO] [archetype:generate {execution: default-cli}] [INFO] Generating project in Batch mode [WARNING] Error reading archetype catalog http://repo1.maven.org/maven2 org.apache.maven.wagon.TransferFailedException: Error transferring file: Connect ion timed out: connect at org.apache.maven.wagon.providers.http.LightweightHttpWagon.fillInputD ata(LightweightHttpWagon.java:143) at org.apache.maven.wagon.StreamWagon.getInputStream(StreamWagon.java:11 6) at org.apache.maven.wagon.StreamWagon.getIfNewer(StreamWagon.java:88) at org.apache.maven.wagon.StreamWagon.get(StreamWagon.java:61) at org.apache.maven.archetype.source.RemoteCatalogArchetypeDataSource.ge tArchetypeCatalog(RemoteCatalogArchetypeDataSource.java:97) at org.apache.maven.archetype.DefaultArchetypeManager.getRemoteCatalog(D efaultArchetypeManager.java:195) at org.apache.maven.archetype.DefaultArchetypeManager.getRemoteCatalog(D efaultArchetypeManager.java:184) at org.apache.maven.archetype.ui.DefaultArchetypeSelector.getArchetypesB yCatalog(DefaultArchetypeSelector.java:278) at org.apache.maven.archetype.ui.DefaultArchetypeSelector.selectArchetyp e(DefaultArchetypeSelector.java:69) at org.apache.maven.archetype.mojos.CreateProjectFromArchetypeMojo.execu te(CreateProjectFromArchetypeMojo.java:186) at org.apache.maven.plugin.DefaultPluginManager.executeMojo(DefaultPlugi nManager.java:490) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoals(Defa ultLifecycleExecutor.java:694) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeStandalone Goal(DefaultLifecycleExecutor.java:569) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoal(Defau ltLifecycleExecutor.java:539) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoalAndHan dleFailures(DefaultLifecycleExecutor.java:387) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeTaskSegmen ts(DefaultLifecycleExecutor.java:284) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.execute(DefaultLi fecycleExecutor.java:180) at org.apache.maven.DefaultMaven.doExecute(DefaultMaven.java:328) at org.apache.maven.DefaultMaven.execute(DefaultMaven.java:138) at org.apache.maven.cli.MavenCli.main(MavenCli.java:362) at org.apache.maven.cli.compat.CompatibleMain.main(CompatibleMain.java:6 0) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl. java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAcces sorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.codehaus.classworlds.Launcher.launchEnhanced(Launcher.java:315) at org.codehaus.classworlds.Launcher.launch(Launcher.java:255) at org.codehaus.classworlds.Launcher.mainWithExitCode(Launcher.java:430) at org.codehaus.classworlds.Launcher.main(Launcher.java:375) Caused by: java.net.ConnectException: Connection timed out: connect at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:333) at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:195) at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:182) at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:366) at java.net.Socket.connect(Socket.java:529) at java.net.Socket.connect(Socket.java:478) at sun.net.NetworkClient.doConnect(NetworkClient.java:163) at sun.net.www.http.HttpClient.openServer(HttpClient.java:394) at sun.net.www.http.HttpClient.openServer(HttpClient.java:529) at sun.net.www.http.HttpClient.(HttpClient.java:233) at sun.net.www.http.HttpClient.New(HttpClient.java:306) at sun.net.www.http.HttpClient.New(HttpClient.java:323) at sun.net.www.protocol.http.HttpURLConnection.getNewHttpClient(HttpURLC onnection.java:860) at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConne ction.java:801) at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection .java:726) at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLCon nection.java:1049) at java.net.HttpURLConnection.getResponseCode(HttpURLConnection.java:373 ) at org.apache.maven.wagon.providers.http.LightweightHttpWagon.fillInputD ata(LightweightHttpWagon.java:115) ... 28 more [WARNING] No archetype found in Remote catalog. Defaulting to internal Catalog [INFO] ------------------------------------------------------------------------ [ERROR] BUILD FAILURE [INFO] ------------------------------------------------------------------------ [INFO] [INFO] ------------------------------------------------------------------------ [INFO] For more information, run Maven with the -e switch [INFO] ------------------------------------------------------------------------ [INFO] Total time: 46 seconds [INFO] Finished at: Wed Jun 09 16:11:07 IST 2010 [INFO] Final Memory: 11M/28M [INFO] ------------------------------------------------------------------------

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  • Unable to aquire image through ImageIO.read(url) because of connection timed out.

    - by Jake Frederix
    Following code always fails URL url = new URL("http://userserve-ak.last.fm/serve/126/8636005.jpg"); Image img = ImageIO.read(url); System.out.println(img); I've manually checked the url, and it is valid, and contains a valid jpg image. The problem I get is; Exception in thread "main" javax.imageio.IIOException: Can't get input stream from URL! at javax.imageio.ImageIO.read(ImageIO.java:1385) at maestro.Main2.main(Main2.java:25) Caused by: java.net.ConnectException: Connection timed out at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:310) at java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:176) at java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:163) at java.net.Socket.connect(Socket.java:546) at java.net.Socket.connect(Socket.java:495) at sun.net.NetworkClient.doConnect(NetworkClient.java:174) at sun.net.www.http.HttpClient.openServer(HttpClient.java:409) at sun.net.www.http.HttpClient.openServer(HttpClient.java:530) at sun.net.www.http.HttpClient.(HttpClient.java:240) at sun.net.www.http.HttpClient.New(HttpClient.java:321) at sun.net.www.http.HttpClient.New(HttpClient.java:338) at sun.net.www.protocol.http.HttpURLConnection.getNewHttpClient(HttpURLConnection.java:814) at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:755) at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection.java:680) at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1005) at java.net.URL.openStream(URL.java:1029) at javax.imageio.ImageIO.read(ImageIO.java:1383) ... 1 more Java Result: 1 What does this mean? Funny thing is, if I change my internet-connection to that of the neighbour's wireless, it suddenly does work.

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  • ASP.NET custom routes for simple requirements management tool

    - by Andrew
    I am implementing a very simple requirements management tool. I want the URLs to look like this: Shows home page for "Project One": http://projectmanager/Project/Project%20One Shows a list of requirements being worked on for "Project One" http://projectmanager/Project/Project%20One/Requirements Shows requirement 1 for "Project One" http://projectmanager/Project/Project%20One/Requirement/1 How could I set up routes so that http://projectmanager/Project/Project%20One is handled by the project controller http://projectmanager/Project/Project%20One/Requirements and http://projectmanager/Project/Project%20One/Requirements/1 is handled by the requirements controller. Is it even possible?

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  • problem with crawl many url in .net: Server IP not ping. maybe bandwidth or http connection limit ex

    - by Hamid
    Hi to all I develop web crawling service (windows service / multi-thread) . its work fine, but sometimes my server network not response. and i can't ping server IP (from internet), but can ping by other network card (local ip) that not access to internet. after i open server with remote desktop and stop crawling service. i could ping. What's my problem? Bandwidth limit or max connection limit exceed or ??? how to prevent this issue? Note: when this problem occur, i open browser for browse web site, but can't open any website!!! Could you please help me. Thanks in advanced

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  • How to access Youtube_it ruby query results?

    - by spectro
    I am trying to implement the youtube_it youtube api wrapper for ruby and have it working except I'm stumped as to how the query results should be accessed. Here is my query: client.videos_by(:query => "penguin", :max_results => 1) Submitting request [url=http://gdata.youtube.com/feeds/api/videos?max-results=1&start-index=1&vq=penguin]. => #<YouTubeIt::Response::VideoSearch:0xb6c41b14 @feed_id="http://gdata.youtube.com/feeds/api/videos", @updated_at=Wed Nov 03 18:01:39 UTC 2010, @videos=[#<YouTubeIt::Model::Video:0xb6c424d8 @thumbnails=[#<YouTubeIt::Model::Thumbnail:0xb6c6b694 @url="http://i.ytimg.com/vi/oSbLpQEZP1Y/2.jpg", @width=120, @height=90, @time="00:01:34">, #<YouTubeIt::Model::Thumbnail:0xb6c6b248 @url="http://i.ytimg.com/vi/oSbLpQEZP1Y/1.jpg", @width=120, @height=90, @time="00:00:47">, #<YouTubeIt::Model::Thumbnail:0xb6c6a988 @url="http://i.ytimg.com/vi/oSbLpQEZP1Y/3.jpg", @width=120, @height=90, @time="00:02:21">, #<YouTubeIt::Model::Thumbnail:0xb6c69e34 @url="http://i.ytimg.com/vi/oSbLpQEZP1Y/0.jpg", @width=320, @height=240, @time="00:01:34">], @categories=[#<YouTubeIt::Model::Category:0xb6ca5d6c @term="Music", @label="Music">], @noembed=false, @racy=false, @favorite_count=7862, @duration=188, @author=#<YouTubeIt::Model::Author:0xb6c9942c @name="wili", @uri="http://gdata.youtube.com/feeds/api/users/wili">, @updated_at=Tue Nov 02 08:45:25 UTC 2010, @longitude=nil, @position=nil, @view_count=1682350, @html_content="penguin", @media_content=[#<YouTubeIt::Model::Content:0xb6c770d4 @url="http://www.youtube.com/v/oSbLpQEZP1Y?f=videos&app=youtube_gdata", @duration=188, @format=#<YouTubeIt::Model::Video::Format:0xb656d108 @name=:swf, @format_code=5>, @default=true, @mime_type="application/x-shockwave-flash">, #<YouTubeIt::Model::Content:0xb6c766d4 @url="rtsp://v5.cache3.c.youtube.com/CiILENy73wIaGQlWPxkBpcsmoRMYDSANFEgGUgZ2aWRlb3MM/0/0/0/video.3gp", @duration=188, @format=#<YouTubeIt::Model::Video::Format:0xb656d11c @name=:rtsp, @format_code=1>, @default=false, @mime_type="video/3gpp">, #<YouTubeIt::Model::Content:0xb6c75d38 @url="rtsp://v8.cache3.c.youtube.com/CiILENy73wIaGQlWPxkBpcsmoRMYESARFEgGUgZ2aWRlb3MM/0/0/0/video.3gp", @duration=188, @format=#<YouTubeIt::Model::Video::Format:0xb656d0f4 @name=:three_gpp, @format_code=6>, @default=false, @mime_type="video/3gpp">], @description="penguin", @latitude=nil, @title="penguin", @published_at=Mon May 08 18:11:01 UTC 2006, @player_url="http://www.youtube.com/watch?v=oSbLpQEZP1Y&feature=youtube_gdata_player", @rating=#<YouTubeIt::Model::Rating:0xb6c5eb4c @min=1, @max=5, @average=4.676985, @rater_count=2746>, @keywords=["pigloo", "penguin"], @video_id="http://gdata.youtube.com/feeds/api/videos/oSbLpQEZP1Y", @where=nil>], @total_result_count=291282, @offset=1, @max_result_count=1> I would like to retrieve the URL and thumbnail links. Any ideas?

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  • how to login to criaglist through c#

    - by kosikiza
    i m using the following code to login to criaglist, but hav't successsed yet. string formParams = string.Format("inputEmailHandle={0}&inputPassword={1}", "[email protected]", "pakistan01"); //string postData = "[email protected]&inputPassword=pakistan01"; string uri = "https://accounts.craigslist.org/"; HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri); request.KeepAlive = true; request.ProtocolVersion = HttpVersion.Version10; request.Method = "POST"; byte[] postBytes = Encoding.ASCII.GetBytes(formParams); request.ContentType = "application/x-www-form-urlencoded"; request.ContentLength = postBytes.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(postBytes, 0, postBytes.Length); requestStream.Close(); HttpWebResponse response = (HttpWebResponse)request.GetResponse(); cookyHeader = response.Headers["Set-cookie"]; string pageSource; string getUrl = "https://post.craigslist.org/del"; WebRequest getRequest = WebRequest.Create(getUrl); getRequest.Headers.Add("Cookie", cookyHeader); WebResponse getResponse = getRequest.GetResponse(); using (StreamReader sr = new StreamReader(getResponse.GetResponseStream())) { pageSource = sr.ReadToEnd(); }

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  • Response.Redirect doesn't work in .net 4

    - by Stephen lacy
    where used on http://localhost:8692/Contacts/Default.aspx Response.Redirect("http://www.google.com") redirects to http://localhost:8692/Contacts/http%3a%2f%2fwww.google.com The problem just appeared once I upgraded to .Net 4 Edit: Response.Redirect("~/Contacts/MemberDetails.aspx?Id=3") goes to http://localhost:8692/Contacts/%2fContacts%2fMemberDetails.aspx%3fId%3d1 I found one mention of this on the web but no solution and it was for the release candidate http://forums.asp.net/t/1527814.aspx

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  • spring 3 uploadify giving 404 Error

    - by Rajkumar
    I am using Spring 3 and implementing Uploadify. The problem is, the files are updating properly but it is giving HTTP Error 404, on completion of file upload. I tried every possible solution, but none of them works. The files are uploaded. Values are storing in DB properly, only that i am getting HTTP Error 404. Any help is appreciated and Thanks in advance. The JSP Page $(function() { $('#file_upload').uploadify({ 'swf' : 'scripts/uploadify.swf', 'fileObjName' : 'the_file', 'fileTypeExts' : '*.gif; *.jpg; *.jpeg; *.png', 'multi' : true, 'uploader' : '/photo/savePhoto', 'fileSizeLimit' : '10MB', 'uploadLimit' : 50, 'onUploadStart' : function(file) { $('#file_upload').uploadify('settings', 'formData', {'trip_id' :'1', 'trip_name' :'Sample Trip', 'destination_trip' :'Mumbai','user_id' :'1','email' :'[email protected]','city_id' :'12'}); }, 'onQueueComplete' : function(queueData) { console.log('queueData : '+queueData); window.location.href = "trip/details/1"; } }); }); The Controller @RequestMapping(value="photo/{action}", method=RequestMethod.POST) public String postHandler(@PathVariable("action") String action, HttpServletRequest request) { if(action.equals("savePhoto")) { try{ MultipartHttpServletRequest multipartRequest = (MultipartHttpServletRequest)request; MultipartFile file = multipartRequest.getFile("the_file"); String trip_id = request.getParameter("trip_id"); String trip_name = request.getParameter("trip_name"); String destination_trip = request.getParameter("destination_trip"); String user_id = request.getParameter("user_id"); String email = request.getParameter("email"); String city_id = request.getParameter("city_id"); photo.savePhoto(file,trip_id,trip_name,destination_trip,user_id,email,city_id); photo.updatetrip(photo_id,trip_id); }catch(Exception e ){e.printStackTrace();} } return ""; } spring config <bean class="org.springframework.web.multipart.commons.CommonsMultipartResolver" id="multipartResolver"> <property name="maxUploadSize" value="10000000"/> </bean>

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  • How to view ASMX SOAP using Fiddler2?

    - by outer join
    Does anyone know if Fiddler can display the raw SOAP messages for ASMX web services? I'm testing a simple web service using both Fiddler2 and Storm and the results vary (Fiddler shows plain xml while Storm shows the SOAP messages). See sample request/responses below: Fiddler2 Request: POST /webservice1.asmx/Test HTTP/1.1 Accept: */* Referer: http://localhost.:4164/webservice1.asmx?op=Test Accept-Language: en-us User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 1.1.4322; .NET CLR 2.0.50727; .NET CLR 3.0.04506.30; .NET CLR 3.0.04506.648; .NET CLR 3.5.21022; .NET CLR 3.0.4506.2152; .NET CLR 3.5.30729; InfoPath.2; MS-RTC LM 8) Content-Type: application/x-www-form-urlencoded Accept-Encoding: gzip, deflate Host: localhost.:4164 Content-Length: 0 Connection: Keep-Alive Pragma: no-cache Fiddler2 Response: HTTP/1.1 200 OK Server: ASP.NET Development Server/9.0.0.0 Date: Thu, 21 Jan 2010 14:21:50 GMT X-AspNet-Version: 2.0.50727 Cache-Control: private, max-age=0 Content-Type: text/xml; charset=utf-8 Content-Length: 96 Connection: Close <?xml version="1.0" encoding="utf-8"?> <string xmlns="http://tempuri.org/">Hello World</string> Storm Request (body only): <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <Test xmlns="http://tempuri.org/" /> </soap:Body> </soap:Envelope> Storm Response: Status Code: 200 Content Length : 339 Content Type: text/xml; charset=utf-8 Server: ASP.NET Development Server/9.0.0.0 Status Description: OK <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <TestResponse xmlns="http://tempuri.org/"> <TestResult>Hello World</TestResult> </TestResponse> </soap:Body> </soap:Envelope> Thanks for any help.

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  • Trouble with piping through sed

    - by Joel
    I am having trouble piping through sed. Once I have piped output to sed, I cannot pipe the output of sed elsewhere. wget -r -nv http://127.0.0.1:3000/test.html Outputs: 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/test.html [99/99] -> "127.0.0.1:3000/test.html" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/robots.txt [83/83] -> "127.0.0.1:3000/robots.txt" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/shop [22818/22818] -> "127.0.0.1:3000/shop.29" [1] I pipe the output through sed to get a clean list of URLs: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' Outputs: http://127.0.0.1:3000/test.html http://127.0.0.1:3000/robots.txt http://127.0.0.1:3000/shop I would like to then dump the output to file, so I do this: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' > /tmp/DUMP_FILE I interrupt the process after a few seconds and check the file, yet it is empty. Interesting, the following yields no output (same as above, but piping sed output through cat): wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' | cat Why can I not pipe the output of sed to another program like cat?

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  • Not able to show video with html5

    - by shin
    I am testing html 5 video tag. I am using http://www.kaltura.org/project/HTML5_Video_Media_JavaScript_Library and http://camendesign.co.uk/. I downloaded the creative common video. When I use an external link, it plays the video. So I uploaded the video to my server but it does not play. It asks if I want to save it or asking an application to play. When I go to the external link, http://cdn.kaltura.org/apis/html5lib/kplayer-examples/media/bbb400p.ogv, it plays it on the browser automatically. I also tested locally, but it does not play either. I am hoping someone gives me why and how to solve the problem. This code works. <figure> <video id="vid1" width="500" height="300" style="position:absolute" poster="http://cdn.kaltura.org/apis/html5lib/kplayer-examples/media/bbb480.jpg" durationHint="33" controls = "true"> <source src="http://cdn.kaltura.org/apis/html5lib/kplayer-examples/media/bbb400p.ogv" /> <source src="http://cdn.kaltura.org/apis/html5lib/kplayer-examples/media/bbb_trailer_iphone.m4v"/> </video> </figure> This does not. <figure> <video id="vid1" width="500" height="300" style="position:absolute" poster="http://cdn.kaltura.org/apis/html5lib/kplayer-examples/media/bbb480.jpg" durationHint="33" controls = "true"> <source src="http://www.mywebsite.com/media/bbb400p.ogv" /> <source src="http://www.mywebsite.com/media/bbb_trailer_iphone.m4v"/> </video> </figure> This does not work either. <figure> <video id="vid1" width="500" height="300" style="position:absolute" poster="http://cdn.kaltura.org/apis/html5lib/kplayer-examples/media/bbb480.jpg" durationHint="33" controls = "true"> <source src="http://127.0.0.1/html5videotest/media/bbb400p.ogv" /> <source src="http://127.0.0.1/html5videotest/media/bbb_trailer_iphone.m4v"/> </video> </figure>

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  • help on ejb stateless datagram and message driven beans

    - by Kemmal
    i have a client thats sending a message to the ejbserver using UDP, i want the server(stateless bean) to echo back this message to the client but i cant seem to do this. or can i implement the same logic by using JMS? please help and enlighten. this is just a test, in the end i want a midp to be sending the message to the ejb using datagrams. here is my code. @Stateless public class SessionFacadeBean implements SessionFacadeRemote { public SessionFacadeBean() { } public static void main(String[] args) { DatagramSocket aSocket = null; byte[] buffer = null; try { while(true) { DatagramPacket request = new DatagramPacket(buffer, buffer.length); aSocket.receive(request); DatagramPacket reply = new DatagramPacket(request.getData(), request.getLength(), request.getAddress(), request.getPort()); aSocket.send(reply); } } catch (SocketException e) { System.out.println("Socket: " + e.getMessage()); } catch (IOException e) { System.out.println("IO: " + e.getMessage()); } finally { if(aSocket != null) aSocket.close(); } } } and the client: public static void main(String[] args) { DatagramSocket aSocket = null; try { aSocket = new DatagramSocket(); byte [] m = "Test message!".getBytes(); InetAddress aHost = InetAddress.getByName("localhost"); int serverPort = 6789; DatagramPacket request = new DatagramPacket(m, m.length, aHost, serverPort); aSocket.send(request); byte[] buffer = new byte[1000]; DatagramPacket reply = new DatagramPacket(buffer, buffer.length); aSocket.receive(reply); System.out.println("Reply: " + new String(reply.getData())); } catch (SocketException e) { System.out.println("Socket: " + e.getMessage()); } catch (IOException e) { System.out.println("IO: " + e.getMessage()); } finally { if(aSocket != null) aSocket.close(); } } please help.

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