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  • Emacs doesn't use ~/.ssh/config when accessing files on a remote machine

    - by Yotam
    I have a fresh install of arch Linux. I've installed Emacs from the rpos, and my home directory is mounted from a separate partition. I have old settings I've used on my ~/.ssh/config along with authentication keys I've regularly used before. Now, when I try to connect to a remote machine using Emacs, Emacs asks for my password and uses the wrong username. Clearly, Emacs doesn't access my config file. When I try to ssh or scp directly to the machine, things work fine. What do I need to update?

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  • Can't boot into my Windows 7 64-bit Acer laptop

    - by John Smith
    Boot normally -- it hangs on "Starting Windows" animation forever. Boot safe mode -- it bluescreens. Boot with a recovery CD (or try Repair Installation directly without a CD) -- it hangs on the green loading bar forever. I dual-boot Ubuntu and can get into the Ubuntu partition fine so I don't think anything is necessarily wrong with the harddrive, but the Ubuntu partition is tiny and I rarely use it and can't access my Windows files anyway. Is there anything I can try that'll help repair whatever happened? I just want to run a checkdisk utility or something similar that'll repair whatever got botched. My laptop: http://www.newegg.com/Product/Product.aspx?Item=N82E16834215206

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  • Problems with uninstallation of windows 8

    - by Wolvorin
    I installed windows 8's developer preview version dual boot with win 7 ultimate. I put my win 8's partition to 11 GB (almost), but now when I try to uninstall the win 8 it dont allow me to uninstall it saying no enough space. What to do ?? Then I try to login to win 7 and increase the size of the partition of win 8. This also is not possible. Please help me with it. I want to uninstall it but how and what to do?

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  • Key is not detected in xev neither showkey -k in Ubuntu 10.04 in a Virtualbox VM.

    - by Somebody still uses you MS-DOS
    My question mark key in my keyboard isn't working. ("?"). I've tried to use xev and showkey -k to try to identify at least it's code and manually use xmodmap to mao this key. Unfortunately, the keys aren't being detected in neither utilities. I'm using Ubuntu 10.04 in a Virtual Machine, and my Kernel is 2.6.32-22-generic. What can this be? It's not a special multimedia key, it's a simple one. I would like to understand what exactly is happening so at least I can try to better debug this issue.

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  • Creating video with audio and still image for YouTube

    - by scottlabs
    I'm running the following command: ffmpeg -i audio.mp3 -ar 44100 -f image2 -i logo.jpg -r 15 -b 1800 -s 640x480 foo.mov Which successfully outputs a video with my recorded audio and an image on it. When I try and upload this to YouTube it fails to process, regardless of the formats I try: .mov, .avi, .flv, .mp4 Is there some setting I'm missing in the above that would generate a format Youtube will accept? I've tried looking through the ffmpeg documentation but I'm in over my head. I did an experiment by putting a 2 second video with a 30 second mp3. When I uploaded to youtube, the resulting video was only 2 seconds long. So it may be that YouTube looks only to the video track for the length, and since a picture is only a frame long or whatever, maybe that borks it.

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  • New Kingson SSD drive fails after 1 week

    - by user35356
    I upgraded the hard disk in my notebook to a 128GB Kingston SSD V100. Everything worked fine for about a week then out of the blue the notebook would not boot up any more. A black dos-like screen was shown with the options to try and boot normally or attempt to repair windows. Neither option would do anything. When I removed the drive and tested it in an external usb case no other computers are able to access the drive either. Is there anything I can try to fix it myself? The drive is partitioned into three drives and when it's connected through an external usb case to another computer I can see the partitions, just can't access anything on them. Does this mean the drive might be recoverable?

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  • messed System Files on Mac PPC

    - by glider
    My buddy deleted her System folder from her PPC Mac wanting to get that space for something else. She copied it first in another drive (she had partitioned disk).She haven't emptied the Trash Bin yet. The screen just froze right after she moved the folder to Trash. We tried to use the install disk but even if we try Power-C on booting,it would try to continue,display the apple logo page then quickly follow it with black screen filled with dumps of hex codes and "We are hanging here..." We have a Windows-based PC that we tried to connect using ethernet cable but we can't find her computer from there. What should we do now???

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  • Isn't localhost simply 127.0.0.1 on Mac OS X 10.7 (Lion)?

    - by z-buffer
    I tried telnet localhost on Mac OS X Lion, and this is the output I got. Trying ::1... telnet: connect to address ::1: Connection refused Trying 127.0.0.1... telnet: connect to address 127.0.0.1: Connection refused Trying fe80::1%lo0... telnet: connect to address fe80::1%lo0: Connection refused telnet: Unable to connect to remote host: Connection refused It tries three different addresses. I would have expected it to only try 127.0.0.1, or at least to try it first. What are these other addresses?

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  • mongodb segmentation fault(11) macosx

    - by Wish
    I have problem, i cant figure out, how to fix.. So i am on MacOSX machine, running php 5.3.15 version, using mongo 1.3.1 version. When i try to execute php script, in which i try to connect to remote mongodb server, I get segmentation fault(11).. I installed php driver with sudo pecl install mongo I have seen, that this problem is quite popular, but havent found real solution yet.. I dont know if I am asking this question in correct stack site.. If you need anything else, just ask.

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  • iTunes Update 11.0 will not install on my Macbook

    - by joshkrz
    I try to update my iTunes to version 11 but every time I open iTunes after the restart it shows me an error message that states, "An Unknown Error Occurred (-42408)". The same thing happens when I try to install it using the stand alone installer from the apple website. iTunes still opens but remains as version 10.7 (21) and dosent update. I have tried this numerous times and I keep getting the same results. I have also looked all over online but none of them give me a solution that works. My system is a MacBook Pro (15-inch, Mid 2012), OS X Mountain Lion (10.8.2) Thanks.

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  • I can not sign in as a user to the Domain [closed]

    - by Dior
    i have installed 2 windows 7 3 windows server 2008 I am trying to sign in with the second windows 7 machine as a user but i can not. What is the solution ? Thank you ! I use Vmplayer. With the second macine (windows 7) i try to log in with one of the user name example:JOwens after hit enter i get user name or password not correct. I try with other user name i have 25 and the same . I could sing in only with one of them. I joied to the Domain. I can not sign in with the users.

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  • datagrid height issue in nested datagrid( when using three data grid)

    - by prince23
    hi, i have a nested datagrid(which is of three data grid). here i am able to show data with no issue. the first datagrid has 5 rows the main problem that comes here is when you click any row in first datagrid i show 2 datagrid( which has 10 rows) lets say i click 3 row in 2 data grid. it show further records in third datagrid. again when i click 5 row in 2 data grid it show further records in third datagrid. now all the recods are shown fine when u try to collpase the 3 row in 2 data grid it collpase but the issue is the height what the third datagrid which took space for showing the records( we can see a blank space showing between the main 2 datagrid and third data grid) in every grid first column i have an button where i am writing this code for expand and collpase this is the functionality i am implementing in all the datagrid button where i do expand collpase. hope my question is clear . any help would great private void btn1_Click(object sender, RoutedEventArgs e) { try { Button btnExpandCollapse = sender as Button; Image imgScore = (Image)btnExpandCollapse.FindName("img"); DependencyObject dep = (DependencyObject)e.OriginalSource; while ((dep != null) && !(dep is DataGridRow)) { dep = VisualTreeHelper.GetParent(dep); } // if we found the clicked row if (dep != null && dep is DataGridRow) { DataGridRow row = (DataGridRow)dep; // change the details visibility if (row.DetailsVisibility == Visibility.Collapsed) { imgScore.Source = new BitmapImage(new Uri("/Images/a1.JPG", UriKind.Relative)); row.DetailsVisibility = Visibility.Visible; } else { imgScore.Source = new BitmapImage(new Uri("/Images/a2JPG", UriKind.Relative)); row.DetailsVisibility = Visibility.Collapsed; } } } catch (System.Exception) { } } --------------------------------------- 2 datagrid private void btn2_Click(object sender, RoutedEventArgs e) { try { Button btnExpandCollapse = sender as Button; Image imgScore = (Image)btnExpandCollapse.FindName("img"); DependencyObject dep = (DependencyObject)e.OriginalSource; while ((dep != null) && !(dep is DataGridRow)) { dep = VisualTreeHelper.GetParent(dep); } // if we found the clicked row if (dep != null && dep is DataGridRow) { DataGridRow row = (DataGridRow)dep; // change the details visibility if (row.DetailsVisibility == Visibility.Collapsed) { imgScore.Source = new BitmapImage(new Uri("/Images/a1.JPG", UriKind.Relative)); row.DetailsVisibility = Visibility.Visible; } else { imgScore.Source = new BitmapImage(new Uri("/Images/a2JPG", UriKind.Relative)); row.DetailsVisibility = Visibility.Collapsed; } } } catch (System.Exception) { } } ----------------- 3 datagrid private void btn1_Click(object sender, RoutedEventArgs e) { try { Button btnExpandCollapse = sender as Button; Image imgScore = (Image)btnExpandCollapse.FindName("img"); DependencyObject dep = (DependencyObject)e.OriginalSource; while ((dep != null) && !(dep is DataGridRow)) { dep = VisualTreeHelper.GetParent(dep); } // if we found the clicked row if (dep != null && dep is DataGridRow) { DataGridRow row = (DataGridRow)dep; // change the details visibility if (row.DetailsVisibility == Visibility.Collapsed) { imgScore.Source = new BitmapImage(new Uri("/Images/a1.JPG", UriKind.Relative)); row.DetailsVisibility = Visibility.Visible; } else { imgScore.Source = new BitmapImage(new Uri("/Images/a2JPG", UriKind.Relative)); row.DetailsVisibility = Visibility.Collapsed; } } } catch (System.Exception) { } }**

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  • Perl CGI that sends a temporary loading page to client then later sends the actual results page

    - by Kurt W. Leucht
    I've wasted at least a half day of my company's time searching the Internet for an answer and I'm getting wrapped around the axle here. I can't figure out the difference between all the different technology choices (long polling, ajax streaming, comet, XMPP, etc.) and I can't get a simple hello world example working on my PC. I am running Apache 2.2 and ActivePerl 5.10.0. JavaScript is completely acceptable for this solution. All I want to do is write a simple Perl CGI script that when accessed, it immediately returns some HTML that tells the user to wait or maybe sends an animated GIF. Then without any user intervention (no mouse clicks or anything) I want the CGI script to at some time later replace the wait message or the animated GIF with the actual HTML results from their query. I know this is simple stuff and websites do it all the time, but I can't find a single working example that I can cut and paste onto my machine that will work. Here is my simple Hello World example that I've compiled from various Internet sources, but it doesn't seem to work. When I refresh this CGI URL in my web browser it prints nothing for 5 seconds, then it prints the PLEASE BE PATIENT web page, but not the results web page. What am I doing wrong? #!C:\Perl\bin\perl.exe use CGI; use CGI::Carp qw/fatalsToBrowser warningsToBrowser/; sub Create_HTML { my $html = <<EOHTML; <html> <head> <meta http-equiv="pragma" content="no-cache" /> <meta http-equiv="expires" content="-1" /> <script type="text/javascript" > var xmlhttp=false; /*@cc_on @*/ /*@if (@_jscript_version >= 5) // JScript gives us Conditional compilation, we can cope with old IE versions. // and security blocked creation of the objects. try { xmlhttp = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); } catch (E) { xmlhttp = false; } } @end @*/ if (!xmlhttp && typeof XMLHttpRequest!='undefined') { try { xmlhttp = new XMLHttpRequest(); } catch (e) { xmlhttp=false; } } if (!xmlhttp && window.createRequest) { try { xmlhttp = window.createRequest(); } catch (e) { xmlhttp=false; } } </script> <title>Ajax Streaming Connection Demo</title> </head> <body> Some header text. <p> <div id="response">PLEASE BE PATIENT</div> <p> Some footer text. </body> </html> EOHTML return $html; } my $cgi = new CGI; print $cgi->header; print Create_HTML(); sleep(5); print "<script type=\"text/javascript\">\n"; print "\$('response').innerHTML = 'Here are your results!';\n"; print "</script>\n";

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  • "Launch Failed. Binary Not Found." Snow Leopard and Eclipse C/C++ IDE issue.

    - by Alex
    Not a question, I've just scoured the internet in search of a solution for this problem and thought I'd share it with the good folks of SO. I'll put it in plain terms so that it's accessible to newbs. :) (Apologies if this is the wrong place -- just trying to be helpful.) This issue occurs with almost any user OS X Snow Leopard who tries to use the Eclipse C/C++ IDE, but is particularly annoying for the people (like me) who were using the Eclipse C/C++ IDE in Leopard, and were unable to work with Eclipse anymore when they upgraded. The issue occurs When users go to build/compile/link their software. They get the following error: Launch Failed. Binary Not Found. Further, the "binaries" branch in the project window on the left is simply nonexistent. THE PROBLEM: is that GCC 4.2 (the GNU Compiler Collection) that comes with Snow Leopard compiles binaries in 64-bit by default. Unfortunately, the linker that Eclipse uses does not understand 64-bit binaries; it reads 32-bit binaries. There may be other issues here, but in short, they culminate in no binary being generated, at least not one that Eclipse can read, which translates into Eclipse not finding the binaries. Hence the error. One solution is to add an -arch i686 flag when making the file, but manually making the file every time is annoying. Luckily for us, Snow Leopard also comes with GCC 4.0, which compiles in 32 bits by default. So one solution is merely to link this as the default compiler. This is the way I did it. THE SOLUTION: The GCCs are in /usr/bin, which is normally a hidden folder, so you can't see it in the Finder unless you explicitly tell the system that you want to see hidden folders. Anyway, what you want to do is go to the /usr/bin folder and delete the path that links the GCC command with GCC 4.2 and add a path that links the GCC command with GCC 4.0. In other words, when you or Eclipse try to access GCC, we want the command to go to the compiler that builds in 32 bits by default, so that the linker can read the files; we do not want it to go to the compiler that compiles in 64 bits. The best way to do this is to go to Applications/Utilities, and select the app called Terminal. A text prompt should come up. It should say something like "(Computer Name):~ (Username)$ " (with a space for you user input at the end). The way to accomplish the tasks above is to enter the following commands, entering each one in sequence VERBATIM, and pressing enter after each individual line. cd /usr/bin rm cc gcc c++ g++ ln -s gcc-4.0 cc ln -s gcc-4.0 gcc ln -s c++-4.0 c++ ln -s g++-4.0 g++ Like me, you will probably get an error that tells you you don't have permission to access these files. If so, try the following commands instead: cd /usr/bin sudo rm cc gcc c++ g++ sudo ln -s gcc-4.0 cc sudo ln -s gcc-4.0 gcc sudo ln -s c++-4.0 c++ sudo ln -s g++-4.0 g++ Sudo may prompt you for a password. If you've never used sudo before, try just pressing enter. If that doesn't work, try the password for your main admin account. OTHER POSSIBLE SOLUTIONS You may be able to enter build variables into Eclipse. I tried this, but I don't know enough about it. If you want to feel it out, the flag you will probably need is -arch i686. In earnest, GCC-4.0 worked for me all this time, and I don't see any reason to switch now. There may be a way to alter the default for the compiler itself, but once again, I don't know enough about it. Hope this has been helpful and informative. Good coding!

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  • WCF Service, Java JApplet client, transport error 405

    - by Juan Zamudio
    Hi all, I'm having a problem with a WCF Service and Java Client, I will try to give as much information as i can, thanks for your time. The Endpoint of the server is BasicHttpBinding, I tried hosting the server as a Windows Service and in IIS but nothing changed. The weird thing is that the Client works great if I use a simple class, in the moment I switch the class to an JApplet I get the problem mentioned. I'm using Eclipse as an IDE, I tried Axis and Metro to generate the stub with the same bad results. Here is an example of the Java class where everything is working public class TestSoaMetro { public String TestMethod(){ String result=null; IDigitalSignatureService aa = new DigitalSignatureService().getBasicHttpBindingEndpoint(); try { result= aa.getData("1", "id002962"); } catch (IDigitalSignatureServiceGetDataArgumentExceptionFaultFaultMessage e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IDigitalSignatureServiceGetDataInvalidOperationExceptionFaultFaultMessage e) { // TODO Auto-generated catch block e.printStackTrace(); } return result; } } Here is the example of the JApplet where I get the error: public class TestSoaMetroApplet extends JApplet { public void init() { Container content = getContentPane(); content.setBackground(Color.white); content.setLayout(new FlowLayout()); String result= this.TestMethod(); JLabel label = new JLabel(result); content.add(label); } public String TestMethod(){ String result=null; IDigitalSignatureService aa = null; try { aa = new DigitalSignatureService().getBasicHttpBindingEndpoint(); result= aa.getData("1", "id002962"); } catch (IDigitalSignatureServiceGetDataArgumentExceptionFaultFaultMessage e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IDigitalSignatureServiceGetDataInvalidOperationExceptionFaultFaultMessage e) { // TODO Auto-generated catch block e.printStackTrace(); } return result; } } In the moment the Applet loads I get the error, is the exact same call so I don't understand why I get the exception using the Applet. I Also tried to call this from a Silverlight client and I was getting a security exception, this is where I found out about clientaccesspolicy.xml and crossdomain.xml, I added clientaccesspolicy.xml to the service and the Silverlight Client works great, so I decided to try crossdomain.xml and nothing, the Applet still does not work. I will put the stack trace at the end, thanks all for your time. Juan Zamudio javax.xml.ws.WebServiceException: org.apache.axis2.AxisFault: Transport error: 405 Error: Method not allowed at org.apache.axis2.jaxws.ExceptionFactory.createWebServiceException(ExceptionFactory.java:175) at org.apache.axis2.jaxws.ExceptionFactory.makeWebServiceException(ExceptionFactory.java:70) at org.apache.axis2.jaxws.ExceptionFactory.makeWebServiceException(ExceptionFactory.java:128) at org.apache.axis2.jaxws.core.controller.impl.AxisInvocationController.execute(AxisInvocationController.java:559) at org.apache.axis2.jaxws.core.controller.impl.AxisInvocationController.doInvoke(AxisInvocationController.java:118) at org.apache.axis2.jaxws.core.controller.impl.InvocationControllerImpl.invoke(InvocationControllerImpl.java:82) at org.apache.axis2.jaxws.client.proxy.JAXWSProxyHandler.invokeSEIMethod(JAXWSProxyHandler.java:317) at org.apache.axis2.jaxws.client.proxy.JAXWSProxyHandler.invoke(JAXWSProxyHandler.java:159) at $Proxy12.getData(Unknown Source) at TestSoaMetroApplet.TestMethod(TestSoaMetroApplet.java:28) at TestSoaMetroApplet.init(TestSoaMetroApplet.java:19) at sun.applet.AppletPanel.run(Unknown Source) at java.lang.Thread.run(Unknown Source) Caused by: org.apache.axis2.AxisFault: Transport error: 405 Error: Method not allowed at org.apache.axis2.transport.http.HTTPSender.handleResponse(HTTPSender.java:295) at org.apache.axis2.transport.http.HTTPSender.sendViaPost(HTTPSender.java:190) at org.apache.axis2.transport.http.HTTPSender.send(HTTPSender.java:75) at org.apache.axis2.transport.http.CommonsHTTPTransportSender.writeMessageWithCommons(CommonsHTTPTransportSender.java:389) at org.apache.axis2.transport.http.CommonsHTTPTransportSender.invoke(CommonsHTTPTransportSender.java:222) at org.apache.axis2.engine.AxisEngine.send(AxisEngine.java:435) at org.apache.axis2.description.OutInAxisOperationClient.send(OutInAxisOperation.java:402) at org.apache.axis2.description.OutInAxisOperationClient.executeImpl(OutInAxisOperation.java:229) at org.apache.axis2.client.OperationClient.execute(OperationClient.java:165) at org.apache.axis2.jaxws.core.controller.impl.AxisInvocationController.execute(AxisInvocationController.java:554) ... 9 more

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  • asp.net image aspect ratio help

    - by StealthRT
    Hey all, i am in need of some help with keeping an image aspect ratio in check. This is the aspx code that i have to resize and upload an image the user selects. <%@ Page Trace="False" Language="vb" aspcompat="false" debug="true" validateRequest="false"%> <%@ Import Namespace=System.Drawing %> <%@ Import Namespace=System.Drawing.Imaging %> <%@ Import Namespace=System %> <%@ Import Namespace=System.Web %> <SCRIPT LANGUAGE="VBScript" runat="server"> const Lx = 500 ' max width for thumbnails const Ly = 60 ' max height for thumbnails const upload_dir = "/uptest/" ' directory to upload file const upload_original = "sample" ' filename to save original as (suffix added by script) const upload_thumb = "thumb" ' filename to save thumbnail as (suffix added by script) const upload_max_size = 512 ' max size of the upload (KB) note: this doesn't override any server upload limits dim fileExt ' used to store the file extension (saves finding it mulitple times) dim newWidth, newHeight as integer ' new width/height for the thumbnail dim l2 ' temp variable used when calculating new size dim fileFld as HTTPPostedFile ' used to grab the file upload from the form Dim originalimg As System.Drawing.Image ' used to hold the original image dim msg ' display results dim upload_ok as boolean ' did the upload work ? </script> <% randomize() ' used to help the cache-busting on the preview images upload_ok = false if lcase(Request.ServerVariables("REQUEST_METHOD"))="post" then fileFld = request.files(0) ' get the first file uploaded from the form (note:- you can use this to itterate through more than one image) if fileFld.ContentLength > upload_max_size * 1024 then msg = "Sorry, the image must be less than " & upload_max_size & "Kb" else try originalImg = System.Drawing.Image.FromStream(fileFld.InputStream) ' work out the width/height for the thumbnail. Preserve aspect ratio and honour max width/height ' Note: if the original is smaller than the thumbnail size it will be scaled up If (originalImg.Width/Lx) > (originalImg.Width/Ly) Then L2 = originalImg.Width newWidth = Lx newHeight = originalImg.Height * (Lx / L2) if newHeight > Ly then newWidth = newWidth * (Ly / newHeight) newHeight = Ly end if Else L2 = originalImg.Height newHeight = Ly newWidth = originalImg.Width * (Ly / L2) if newWidth > Lx then newHeight = newHeight * (Lx / newWidth) newWidth = Lx end if End If Dim thumb As New Bitmap(newWidth, newHeight) 'Create a graphics object Dim gr_dest As Graphics = Graphics.FromImage(thumb) ' just in case it's a transparent GIF force the bg to white dim sb = new SolidBrush(System.Drawing.Color.White) gr_dest.FillRectangle(sb, 0, 0, thumb.Width, thumb.Height) 'Re-draw the image to the specified height and width gr_dest.DrawImage(originalImg, 0, 0, thumb.Width, thumb.Height) try fileExt = System.IO.Path.GetExtension(fileFld.FileName).ToLower() originalImg.save(Server.MapPath(upload_dir & upload_original & fileExt), originalImg.rawformat) thumb.save(Server.MapPath(upload_dir & upload_thumb & fileExt), originalImg.rawformat) msg = "Uploaded " & fileFld.FileName & " to " & Server.MapPath(upload_dir & upload_original & fileExt) upload_ok = true catch msg = "Sorry, there was a problem saving the image." end try ' Housekeeping for the generated thumbnail if not thumb is nothing then thumb.Dispose() thumb = nothing end if catch msg = "Sorry, that was not an image we could process." end try end if ' House Keeping ! if not originalImg is nothing then originalImg.Dispose() originalImg = nothing end if end if %> What i am looking for is a way to just have it go by the height of what i set it: const Ly = 60 ' max height for thumbnails And have the code for the width just be whatever. So if i had an image... say 600 x 120 (w h) and i used photoshop to change just the height, it would keep it in ratio and have it 300 x 60 (w x h). Thats what i am looking to do with this code here. However, i can not think of a way to do this (or to just leave a wildcard for the width setting. Any help would be great :o) David

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  • KeepAliveException when using HttpWebRequest.GetResponse

    - by Lucas
    I am trying to POST an attachment to CouchDB using the HttpWebRequest. However, when I attempt "response = (HttpWebResponse)httpWebRequest.GetResponse();" I receive a WebException with the message "The underlying connection was closed: A connection that was expected to be kept alive was closed by the server." I have found some articles stating that setting the keepalive to false and httpversion to 1.0 resolves the situation. I am finding that it does not yeilding the exact same error, plus I do not want to take that approach as I do not want to use the 1.0 version due to how it handles the connection. Any suggestions or ideas are welcome. I'll try them all until one works! public ServerResponse PostAttachment(Server server, Database db, Attachment attachment) { Stream dataStream; HttpWebResponse response = null; StreamReader sr = null; byte[] buffer; string json; string boundary = "----------------------------" + DateTime.Now.Ticks.ToString("x"); string headerTemplate = "Content-Disposition: form-data; name=\"_attachments\"; filename=\"" + attachment.Filename + "\"\r\n Content-Type: application/octet-stream\r\n\r\n"; byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(headerTemplate); byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n"); HttpWebRequest httpWebRequest = (HttpWebRequest)WebRequest.Create("http://" + server.Host + ":" + server.Port.ToString() + "/" + db.Name + "/" + attachment.Document.Id); httpWebRequest.ContentType = "multipart/form-data; boundary=" + boundary; httpWebRequest.Method = "POST"; httpWebRequest.KeepAlive = true; httpWebRequest.ContentLength = attachment.Stream.Length + headerbytes.Length + boundarybytes.Length; if (!string.IsNullOrEmpty(server.EncodedCredentials)) httpWebRequest.Headers.Add("Authorization", server.EncodedCredentials); if (!attachment.Stream.CanRead) throw new System.NotSupportedException("The stream cannot be read."); // Get the request stream try { dataStream = httpWebRequest.GetRequestStream(); } catch (Exception e) { throw new WebException("Failed to get the request stream.", e); } buffer = new byte[server.BufferSize]; int bytesRead; dataStream.Write(headerbytes,0,headerbytes.Length); attachment.Stream.Position = 0; while ((bytesRead = attachment.Stream.Read(buffer, 0, buffer.Length)) > 0) { dataStream.Write(buffer, 0, bytesRead); } dataStream.Write(boundarybytes, 0, boundarybytes.Length); dataStream.Close(); // send the request and get the response try { response = (HttpWebResponse)httpWebRequest.GetResponse(); } catch (Exception e) { throw new WebException("Invalid response received from server.", e); } // get the server's response json try { dataStream = response.GetResponseStream(); sr = new StreamReader(dataStream); json = sr.ReadToEnd(); } catch (Exception e) { throw new WebException("Failed to access the response stream.", e); } // close up all our streams and response sr.Close(); dataStream.Close(); response.Close(); // Deserialize the server response return ConvertTo.JsonToServerResponse(json); }

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  • Need a little help with sound in a JApplet

    - by jacob schuschel
    I am working on a solitaire game in Java, and i need to implement sound when the desk is shuffled, card flipped, etc. I used the following sites as reference to try and get it to work, but i am getting Null Pointer Exceptions or mishandled URL exception (depending on what i tweak). here Also, i am using netbeans 6.7.1 as my IDE. I will try to break down the code and explain: package cardgame; import java.applet.*; import java.util.logging.Level; import java.util.logging.Logger; import javax.swing.JApplet; import javax.swing.*; import java.io.*; import java.net.*; /** * * @author jacob */ public class Sound extends JApplet { private AudioClip song; // Sound player private String URL = null; private URL songPath; // Sound path /* *sound_1 = shuffling cards *sound_2 = to discard *sound_3 = from discard *sound_4 = cardflip 1 *sound_5 = cardflip 2 */ Sound(String filename) { try { songPath = new URL(getCodeBase(),filename); // Get the Sound URL } catch (MalformedURLException ex) { Logger.getLogger(Sound.class.getName()).log(Level.SEVERE, null, ex); } song = getAudioClip(songPath); // Load the Sound } Sound(int i) { URL = "./sounds/sound_" + i + ".wav"; System.out.println(URL); try { songPath = new URL(URL); // Get the Sound URL song = getAudioClip(songPath); } catch (MalformedURLException ex) { Logger.getLogger(Sound.class.getName()).log(Level.SEVERE, null, ex); } } public void playSound() { song.loop(); // Play } public void stopSound() { song.stop(); // Stop } public void playSoundOnce() { song.play(); // Play only once } } The 2 different construcors are for different ways i tried to implement this. The first one creates the filepath, and passes it in. The second one builds the filepath in the constructor, given a sound # (i made a list of what numbers correspond to what sound for reference). I am getting the followig errors out: ./sounds/sound_1.wav Nov 16, 2009 4:14:13 PM cardgame.Sound ./sounds/sound_2.wav SEVERE: null java.net.MalformedURLException: no protocol: ./sounds/sound_1.wav ./sounds/sound_3.wav at java.net.URL.(URL.java:583) at java.net.URL.(URL.java:480) at java.net.URL.(URL.java:429) ./sounds/sound_4.wav ./sounds/sound_5.wav at cardgame.Sound.(Sound.java:46) at cardgame.Game.loadSounds(Game.java:712) at cardgame.Game.(Game.java:62) at cardgame.Main.main(Main.java:25) Nov 16, 2009 4:14:13 PM cardgame.Sound SEVERE: null java.net.MalformedURLException: no protocol: ./sounds/sound_2.wav at java.net.URL.(URL.java:583) at java.net.URL.(URL.java:480) at java.net.URL.(URL.java:429) at cardgame.Sound.(Sound.java:46) at cardgame.Game.loadSounds(Game.java:712) at cardgame.Game.(Game.java:62) at cardgame.Main.main(Main.java:25) Nov 16, 2009 4:14:13 PM cardgame.Sound SEVERE: null java.net.MalformedURLException: no protocol: ./sounds/sound_3.wav at java.net.URL.(URL.java:583) at java.net.URL.(URL.java:480) at java.net.URL.(URL.java:429) at cardgame.Sound.(Sound.java:46) at cardgame.Game.loadSounds(Game.java:712) at cardgame.Game.(Game.java:62) at cardgame.Main.main(Main.java:25) Nov 16, 2009 4:14:13 PM cardgame.Sound SEVERE: null java.net.MalformedURLException: no protocol: ./sounds/sound_4.wav at java.net.URL.(URL.java:583) at java.net.URL.(URL.java:480) at java.net.URL.(URL.java:429) at cardgame.Sound.(Sound.java:46) at cardgame.Game.loadSounds(Game.java:712) at cardgame.Game.(Game.java:62) at cardgame.Main.main(Main.java:25) Nov 16, 2009 4:14:13 PM cardgame.Sound SEVERE: null java.net.MalformedURLException: no protocol: ./sounds/sound_5.wav at java.net.URL.(URL.java:583) at java.net.URL.(URL.java:480) at java.net.URL.(URL.java:429) at cardgame.Sound.(Sound.java:46) at cardgame.Game.loadSounds(Game.java:712) at cardgame.Game.(Game.java:62) at cardgame.Main.main(Main.java:25) Thanks for those who read and more thanks to those who help. I know it is somewhat long, but i would rather get it all out there, than have 50 questions that come back or have people not answer due to lack of initial info. also only lets me post a single link right now, so the links are given below dreamincode.net/forums/showtopic14083.htm stackoverflow.com/questions/512436/java-playing-wav-sounds deitel.com/articles/java_tutorials/20060422/LoadingPlayingAudioClips/index.html

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  • Update MySQL table using data from a text file through Java

    - by Karthi Karthi
    I have a text file with four lines, each line contains comma separated values like below file My file is: Raj,[email protected],123455 kumar,[email protected],23453 shilpa,[email protected],765468 suraj,[email protected],876567 and I have a MySQL table which contains four fields firstname lastname email phno ---------- ---------- --------- -------- Raj babu [email protected] 2343245 kumar selva [email protected] 23453 shilpa murali [email protected] 765468 suraj abd [email protected] 876567 Now I want to update my table using the data in the above text file through Java. I have tried using bufferedReader to read from the file and used split method using comma as delimiter and stored it in array. But it is not working. Any help appreciated. This is what I have tried so far void readingFile() { try { File f1 = new File("TestFile.txt"); FileReader fr = new FileReader(f1); BufferedReader br = new BufferedReader(fr); String strln = null; strln = br.readLine(); while((strln=br.readLine())!=null) { // System.out.println(strln); arr = strln.split(","); strfirstname = arr[0]; strlastname = arr[1]; stremail = arr[2]; strphno = arr[3]; System.out.println(strfirstname + " " + strlastname + " " + stremail +" "+ strphno); } // for(String i : arr) // { // } br.close(); fr.close(); } catch(IOException e) { System.out.println("Cannot read from File." + e); } try { st = conn.createStatement(); String query = "update sampledb set email = stremail,phno =strphno where firstname = strfirstname "; st.executeUpdate(query); st.close(); System.out.println("sampledb Table successfully updated."); } catch(Exception e3) { System.out.println("Unable to Update sampledb table. " + e3); } } and the output i got is: Ganesh Pandiyan [email protected] 9591982389 Dass Jeyan [email protected] 9689523645 Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1 Gowtham Selvan [email protected] 9894189423 at TemporaryPackages.FileReadAndUpdateTable.readingFile(FileReadAndUpdateTable.java:35) at TemporaryPackages.FileReadAndUpdateTable.main(FileReadAndUpdateTable.java:72) Java Result: 1 @varadaraj: This is the code of yours.... String stremail,strphno,strfirstname,strlastname; // String[] arr; Connection conn; Statement st; void readingFile() { try { BufferedReader bReader= new BufferedReader(new FileReader("TestFile.txt")); String fileValues; while ((fileValues = bReader.readLine()) != null) { String[] values=fileValues .split(","); strfirstname = values[0]; // strlastname = values[1]; stremail = values[1]; strphno = values[2]; System.out.println(strfirstname + " " + strlastname + " " + stremail +" "+ strphno); } bReader.close(); } catch (IOException e) { System.out.println("File Read Error"); } // for(String i : arr) // { // } try { st = conn.createStatement(); String query = "update sampledb set email = stremail,phno =strphno where firstname = strfirstname "; st.executeUpdate(query); st.close(); System.out.println("sampledb Table successfully updated."); } catch(Exception e3) { System.out.println("Unable to Update sampledb table. " + e3); } }

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  • How to send web browser a loading page, then some time later a results page

    - by Kurt W. Leucht
    I've wasted at least a half day of my company's time searching the Internet for an answer and I'm getting wrapped around the axle here. I can't figure out the difference between all the different technology choices (long polling, ajax streaming, comet, XMPP, etc.) and I can't get a simple hello world example working on my PC. I am running Apache 2.2 and ActivePerl 5.10.0. JavaScript is completely acceptable for this solution. All I want to do is write a simple Perl CGI script that when accessed, it immediately returns some HTML that tells the user to wait or maybe sends an animated GIF. Then without any user intervention (no mouse clicks or anything) I want the CGI script to at some time later replace the wait message or the animated GIF with the actual results from their query. I know this is simple stuff and websites do it all the time using JavaScript, but I can't find a single working example that I can cut and paste onto my machine that will work in Perl. Here is my simple Hello World example that I've compiled from various Internet sources, but it doesn't seem to work. When I refresh this Perl CGI script in my web browser it prints nothing for 5 seconds, then it prints the PLEASE BE PATIENT web page, but not the results web page. So the Ajax XMLHttpRequest stuff obviously isn't working right. What am I doing wrong? #!C:\Perl\bin\perl.exe use CGI; use CGI::Carp qw/fatalsToBrowser warningsToBrowser/; sub Create_HTML { my $html = <<EOHTML; <html> <head> <meta http-equiv="pragma" content="no-cache" /> <meta http-equiv="expires" content="-1" /> <script type="text/javascript" > var xmlhttp=false; /*@cc_on @*/ /*@if (@_jscript_version >= 5) // JScript gives us Conditional compilation, we can cope with old IE versions. // and security blocked creation of the objects. try { xmlhttp = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); } catch (E) { xmlhttp = false; } } @end @*/ if (!xmlhttp && typeof XMLHttpRequest!='undefined') { try { xmlhttp = new XMLHttpRequest(); } catch (e) { xmlhttp=false; } } if (!xmlhttp && window.createRequest) { try { xmlhttp = window.createRequest(); } catch (e) { xmlhttp=false; } } </script> <title>Ajax Streaming Connection Demo</title> </head> <body> Some header text. <p> <div id="response">PLEASE BE PATIENT</div> <p> Some footer text. </body> </html> EOHTML return $html; } my $cgi = new CGI; print $cgi->header; print Create_HTML(); sleep(5); print "<script type=\"text/javascript\">\n"; print "\$('response').innerHTML = 'Here are your results!';\n"; print "</script>\n";

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  • is it right to call ejb bean from thread by ThreadPoolExecutor?

    - by kislo_metal
    I trying to call some ejb bean method from tread. and getting error : (as is glassfish v3) Log Level SEVERE Logger javax.enterprise.system.std.com.sun.enterprise.v3.services.impl Name-Value Pairs {_ThreadName=Thread-1, _ThreadID=42} Record Number 928 Message ID java.lang.NullPointerException at ua.co.rufous.server.broker.TempLicService.run(TempLicService.java Complete Message 35) at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) at java.lang.Thread.run(Thread.java:637) here is tread public class TempLicService implements Runnable { String hash; //it`s Stateful bean @EJB private LicActivatorLocal lActivator; public TempLicService(String hash) { this.hash= hash; } @Override public void run() { lActivator.proccessActivation(hash); } } my ThreadPoolExecutor public class RequestThreadPoolExecutor extends ThreadPoolExecutor { private boolean isPaused; private ReentrantLock pauseLock = new ReentrantLock(); private Condition unpaused = pauseLock.newCondition(); private static RequestThreadPoolExecutor threadPool; private RequestThreadPoolExecutor() { super(1, Integer.MAX_VALUE, 10, TimeUnit.SECONDS, new LinkedBlockingQueue<Runnable>()); System.out.println("RequestThreadPoolExecutor created"); } public static RequestThreadPoolExecutor getInstance() { if (threadPool == null) threadPool = new RequestThreadPoolExecutor(); return threadPool; } public void runService(Runnable task) { threadPool.execute(task); } protected void beforeExecute(Thread t, Runnable r) { super.beforeExecute(t, r); pauseLock.lock(); try { while (isPaused) unpaused.await(); } catch (InterruptedException ie) { t.interrupt(); } finally { pauseLock.unlock(); } } public void pause() { pauseLock.lock(); try { isPaused = true; } finally { pauseLock.unlock(); } } public void resume() { pauseLock.lock(); try { isPaused = false; unpaused.signalAll(); } finally { pauseLock.unlock(); } } public void shutDown() { threadPool.shutdown(); } //<<<<<< creating thread here public void runByHash(String hash) { Runnable service = new TempLicService(hash); threadPool.runService(service); } } and method where i call it (it is gwt servlet, but there is no proble to call thread that not contain ejb) : @Override public Boolean submitHash(String hash) { System.out.println("submiting hash"); try { if (tBoxService.getTempLicStatus(hash) == 1) { //<<< here is the call RequestThreadPoolExecutor.getInstance().runByHash(hash); return true; } } catch (NoResultException e) { e.printStackTrace(); } return false; } I need to organize some pool of submitting hash to server (calls of LicActivator bean), is ThreadPoolExecutor design good idea and why it is not working in my case? (as I know we can`t create thread inside bean, but could we call bean from different threads? ). If No, what is the bast practice for organize such request pool? Thanks. << Answer: I am using DI (EJB 3.1) soo i do not need any look up here. (application packed in ear and both modules in it (web module and ejb), it works perfect for me). But I can use it only in managed classes. So.. 2.Can I use manual look up in Tread ? Could I use Bean that extends ThreadPoolExecutor and calling another bean that implements Runnable ? Or it is not allowed ?

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  • Throwing a C++ exception from inside a Linux Signal handler

    - by SoapBox
    As a thought experiment more than anything I am trying to get a C++ exception thrown "from" a linux signal handler for SIGSEGV. (I'm aware this is not a solution to any real world SIGSEGV and should never actually be done, but I thought I would try it out after being asked about it, and now I can't get it out of my head until I figure out how to do it.) Below is the closest I have come, but instead of the signal being caught properly, terminate() is being called as if no try/catch block is available. Anyone know why? Or know a way I can actually get a C++ exception from a signal handler? The code (beware, the self modifying asm limits this to running on x86_64 if you're trying to test it): #include <iostream> #include <stdexcept> #include <signal.h> #include <stdint.h> #include <errno.h> #include <string.h> #include <sys/mman.h> using namespace std; uint64_t oldaddr = 0; void thrower() { cout << "Inside thrower" << endl; throw std::runtime_error("SIGSEGV"); } void segv_handler(int sig, siginfo_t *info, void *pctx) { ucontext_t *context = (ucontext_t *)pctx; cout << "Inside SIGSEGV handler" << endl; oldaddr = context->uc_mcontext.gregs[REG_RIP]; uint32_t pageSize = (uint32_t)sysconf(_SC_PAGESIZE); uint64_t bottomOfOldPage = (oldaddr/pageSize) * pageSize; mprotect((void*)bottomOfOldPage, pageSize*2, PROT_READ|PROT_WRITE|PROT_EXEC); // 48 B8 xx xx xx xx xx xx xx xx = mov rax, xxxx *((uint8_t*)(oldaddr+0)) = 0x48; *((uint8_t*)(oldaddr+1)) = 0xB8; *((int64_t*)(oldaddr+2)) = (int64_t)thrower; // FF E0 = jmp rax *((uint8_t*)(oldaddr+10)) = 0xFF; *((uint8_t*)(oldaddr+11)) = 0xE0; } void func() { try { *(uint32_t*)0x1234 = 123456789; } catch (...) { cout << "caught inside func" << endl; throw; } } int main() { cout << "Top of main" << endl; struct sigaction action, old_action; action.sa_sigaction = segv_handler; sigemptyset(&action.sa_mask); action.sa_flags = SA_SIGINFO | SA_RESTART | SA_NODEFER; if (sigaction(SIGSEGV, &action, &old_action)<0) cerr << "Error setting handler : " << strerror(errno) << endl; try { func(); } catch (std::exception &e) { cout << "Caught : " << e.what() << endl; } cout << "Bottom of main" << endl << endl; } The actual output: Top of main Inside SIGSEGV handler Inside thrower terminate called after throwing an instance of 'std::runtime_error' what(): SIGSEGV Aborted Expected output: Top of main Inside thrower caught inside func Caught : SIGSEGV Bottom of main

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  • Android: HttpURLConnection not working properly

    - by giorgiline
    I'm trying to get the cookies from a website after sending user credentials through a POST Request an it seems that it doesn't work in android this way. ¿Am I doing something bad?. Please help. I've searched here in different posts but there's no useful answer. It's curious that this run in a desktop Java implementation it works perfect but it crashes in Android platform. And it is exactly the same code, specifically when calling HttpURLConnection.getHeaderFields(), it also happens with other member methods. It's a simple code and I don't know why the hell isn't working. DESKTOP CODE: This goes just in the main() HttpURLConnection connection = null; OutputStream out = null; try { URL url = new URL("http://www.XXXXXXXX.php"); String charset = "UTF-8"; String postback = "1"; String user = "XXXXXXXXX"; String password = "XXXXXXXX"; String rememberme = "on"; String query = String.format("postback=%s&user=%s&password=%s&rememberme=%s" , URLEncoder.encode(postback, charset) , URLEncoder.encode(user,charset) , URLEncoder.encode(password, charset) , URLEncoder.encode(rememberme, charset)); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Accept-Charset", charset); connection.setDoOutput(true); connection.setFixedLengthStreamingMode(query.length()); out = connection.getOutputStream (); out.write(query.getBytes(charset)); if (connection.getHeaderFields() == null){ System.out.println("Header null"); }else{ for (String cookie: connection.getHeaderFields().get("Set-Cookie")){ System.out.println(cookie.split(";", 2)[0]); } } } catch (IOException e){ e.printStackTrace(); } finally { try { out.close();} catch (IOException e) { e.printStackTrace();} connection.disconnect(); } So the output is: login_key=20ad8177db4eca3f057c14a64bafc2c9 FASID=cabf20cc471fcacacdc7dc7e83768880 track=30c8183e4ebbe8b3a57b583166326c77 client-data=%7B%22ism%22%3Afalse%2C%22showm%22%3Afalse%2C%22ts%22%3A1349189669%7D ANDROID CODE: This goes inside doInBackground AsyncTask body HttpURLConnection connection = null; OutputStream out = null; try { URL url = new URL("http://www.XXXXXXXXXXXXXX.php"); String charset = "UTF-8"; String postback = "1"; String user = "XXXXXXXXX"; String password = "XXXXXXXX"; String rememberme = "on"; String query = String.format("postback=%s&user=%s&password=%s&rememberme=%s" , URLEncoder.encode(postback, charset) , URLEncoder.encode(user,charset) , URLEncoder.encode(password, charset) , URLEncoder.encode(rememberme, charset)); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Accept-Charset", charset); connection.setDoOutput(true); connection.setFixedLengthStreamingMode(query.length()); out = connection.getOutputStream (); out.write(query.getBytes(charset)); if (connection.getHeaderFields() == null){ Log.v(TAG, "Header null"); }else{ for (String cookie: connection.getHeaderFields().get("Set-Cookie")){ Log.v(TAG, cookie.split(";", 2)[0]); } } } catch (IOException e){ e.printStackTrace(); } finally { try { out.close();} catch (IOException e) { e.printStackTrace();} connection.disconnect(); } And here there is no output, it seems that connection.getHeaderFields() doesn't return result. It takes al least 30 seconds to show the Log: 10-02 16:56:25.918: V/class com.giorgi.myproject.activities.HomeActivity(2596): Header null

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  • Cannot find Package fop ( Ithink)

    - by efendioglu
    Hello friends I try to use fop engine programatically I search for an example and I find this class import java.io.File; import java.io.IOException; import java.io.OutputStream; import javax.xml.transform.Transformer; import javax.xml.transform.TransformerFactory; import javax.xml.transform.TransformerException; import javax.xml.transform.Source; import javax.xml.transform.Result; import javax.xml.transform.stream.StreamSource; import javax.xml.transform.sax.SAXResult; import org.apache.avalon.framework.ExceptionUtil; import org.apache.avalon.framework.logger.ConsoleLogger; import org.apache.avalon.framework.logger.Logger; import org.apache.fop.apps.Driver; import org.apache.fop.apps.FOPException; import org.apache.fop.messaging.MessageHandler; public class Invokefop { public void convertXML2PDF(File xml, File xslt, File pdf) throws IOException, FOPException, TransformerException { Driver driver = new Driver(); Logger logger = new ConsoleLogger(ConsoleLogger.LEVEL_INFO); driver.setLogger(logger); MessageHandler.setScreenLogger(logger); driver.setRenderer(Driver.RENDER_PDF); OutputStream out = new java.io.FileOutputStream(pdf); try { driver.setOutputStream(out); TransformerFactory factory = TransformerFactory.newInstance(); Transformer transformer = factory.newTransformer(new StreamSource(xslt)); Source src = new StreamSource(xml); Result res = new SAXResult(driver.getContentHandler()); transformer.transform(src, res); } finally { out.close(); } } public static void main(String[] args) { try { System.out.println("JAVA XML2PDF:: FOP ExampleXML2PDF\n"); System.out.println("JAVA XML2PDF:: Preparing..."); File base = new File("../"); File baseDir = new File(base, "in"); File outDir = new File(base, "out"); outDir.mkdirs(); File xmlfile = new File(baseDir, args[0]); File xsltfile = new File(baseDir, args[1]); File pdffile = new File(outDir, args[2]); System.out.println("JAVA XML2PDF:: Input: XML (" + xmlfile + ")"); System.out.println("JAVA XML2PDF:: Stylesheet: " + xsltfile); System.out.println("JAVA XML2PDF:: Output: PDF (" + pdffile + ")"); System.out.println(); System.out.println("JAVA XML2PDF:: Transforming..."); Invokefop app = new Invokefop(); app.convertXML2PDF(xmlfile, xsltfile, pdffile); System.out.println("JAVA XML2PDF:: Success!"); } catch (Exception e) { System.err.println(ExceptionUtil.printStackTrace(e)); System.exit(-1); } } } All the Libs from Fop are in the Classpath including the fop.jar in build directory. After I run thejavac Invokefop.java I get this error: > C:\....\fop>javac Invokefop.java Invokefop.java:21: cannot find symbol symbol : class Driver location: package org.apache.fop.apps import org.apache.fop.apps.Driver; ^ Invokefop.java:23: package org.apache.fop.messaging does not exist import org.apache.fop.messaging.MessageHandler; ^ Invokefop.java:31: cannot find symbol symbol : class Driver location: class Invokefop Driver driver = new Driver(); ^ Invokefop.java:31: cannot find symbol symbol : class Driver location: class Invokefop Driver driver = new Driver(); ^ Invokefop.java:36: cannot find symbol symbol : variable MessageHandler location: class Invokefop MessageHandler.setScreenLogger(logger); ^ Invokefop.java:39: cannot find symbol symbol : variable Driver location: class Invokefop driver.setRenderer(Driver.RENDER_PDF); ^ 6 errors I am relatively new to Java, but with this approach I try to execute the fop engine in c++ using this java class.. Have anybody some Idea, how to solve this errors... Thanx in advance..

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