Search Results

Search found 14206 results on 569 pages for 'compressed folder'.

Page 233/569 | < Previous Page | 229 230 231 232 233 234 235 236 237 238 239 240  | Next Page >

  • Why is C++ fwrite() producing larger output in release?

    - by waffleShirt
    I recently wrote an implementation of the Canonical Huffman compression algorithm. I have a 500kb test file that can be compressed to about 250kb when running the debug and release builds from within Visual Studio 2008. However when I run the release build straight from the executeable the test file only compresses to about 330kb. I am assuming that something is going wrong when the file is written using fwrite(). I have tested the program and confirmed that uncompressing the files always produces the correct uncompressed file. Does anyone know why this could possibly be? How could the same executeable file be producing different sized outputs based on where it is launched from?

    Read the article

  • Just an experiment changing the application data path

    - by Arthur
    When I change the Appication Data path in windows xp registry to a network folder I get this error message on the next system startup: "windows cannot load the user's profile but has logged you with the default profile system" The registry keys are: "[HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Explorer\Shell Folders]" "[HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Explorer\User Shell Folders]" under the names "AppData" and "Local AppData" I dont care if "Windows logins you with the default profile system" but is there a way to disable that message, or change the message timeout form 30 seconds to 0?,or maybe create an script that changes the Application Data path every system startup? P.S. The computer with the shared folder is always on.

    Read the article

  • How do I make a project in Django? Beginner

    - by ggfan
    Okay I just started with Django and it's totally different from PHP. I installed Python 2.6 and Django. Both are located in my C drive. C: Django build django docs Python26 I am doing the django site tutorial and when they say to write django-admin.py startproject mysite from my Python command line, I keep getting: Syntax error: invalid syntax >>>django-admin.py startproject mysite FILE "<stdin>", line 1 django-admin.py startproject mysite ^ My django-admin.py is in the django/bin folder. I installed Python via python setup.py. Am I suppose to use my window's CP? When I do that, I get window's can't open a .py file. I thought I was just creating a folder? How do I create a project with django? Thanks :)

    Read the article

  • Drupal does not recognize my website has been installed

    - by Marcos Buarque
    After a successful Drupal install, I was trying to follow the security recommendations and reverted the settings.php file to 444 permissions (read, read, read). Then, all of a sudden, right after doing that, Drupal does not recognize the installation process was completed. It went back to the install screen. Worst of all. I did chmod back to 666 (write, write, write) but it does not work any more. When I move forward as if I was going to install Drupal again, he tells me he does not have permissions to create the files folder under sites/default... But since the installation has already been completed... the files folder is already there... I am puzzled... Could it be some sort of server caching? Since this is one of my first adventures with a Linux server, I am a bit confused. Any help appreciated... Thanks.

    Read the article

  • Is PNG the most economically sound file format to store pictures in?

    - by raoulsson
    I am looking for an economically sound solution to store pictures long time. I read about the PNG file format that it has superior characteristics compared to JPEG, namely in these categories: no patents, no licenses, no royalities no quality loss yet compressed I have a lot of big ESP's from PhotoShop that contain tons of metadata, like layers and color profiles that I don't need to store (those were handy for the designer, when he worked with it). I want to convert these images without that hidden data, to a new target file format. Another side condition to my question is that the target file format has to be displayable in the browser. So I guess my options are limited anyway: GIF, JPEG, PNG. Am I missing something or is PNG the best fit for my case?

    Read the article

  • NSDirectoryEnumerator And Subfolders

    - by Matthew Roberts
    I have an iPhone app that searches a folder, collates an an array of all the audio files, and lets them be played back. The problem is that if there is a subfolder within the folder I am searching, it will just skip over it/not go into its contents. My code is as follows: NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); NSString *documentsDirectory = [paths objectAtIndex:0]; NSDirectoryEnumerator *direnum = [[NSFileManager defaultManager] enumeratorAtPath:documentsDirectory]; NSString *pname; while (pname = [direnum nextObject]) { [musicArray addObject:[pname stringByDeletingPathExtension]]; } What I want to do is continue to search its subfolders, how would I go about doing that?

    Read the article

  • Any way to chunk gzip with Apache and PHP

    - by donatJ
    I have a web application on a site that takes a while (~10 seconds) to complete a portion of the page near the bottom - it has been as optimized as it can be, and caching is not an option. We have compression enabled on the server via an .htaccess directive SetOutputFilter DEFLATE the problem is this causes the whole page to be held until completion before it starts outputting to the user, this is not optimal as the user sees nothing until the page completes. I have also tried it via the php ob_start("ob_gzhandler"); method. Currently I have a <FilesMatch > in my .htaccess restricting this specific script from being compressed. Basically my question is this - Is there a way to say chunk gzip or deflate so that the user gets it in pieces, so they can see that the page has begun loading?

    Read the article

  • Is gzip compression useful for mobile devices?

    - by Savageman
    Hi SO, I'm wondering if anyone has a clue on whether the gzip compression is as much useful on mobile devices than it is on a desktop computer. Will the phone use more battery? Or will it save some because of the bandwidth saving? Will the page page load faster or is the uncompress process slow on those limited devices? Does the compressed data actually reach the end-user or is it uncompressed somewhere by the 3G provider? (this may be a stupid question, sorry). Thank you.

    Read the article

  • Class-Dump Installation

    - by sj-dev
    So this may sound like a really stupid question and I HAVE looked at the how-to from the parent website, but no matter what I do, I cannot get this program to even start to install... I tried entering: cd /opt/local/bin/portslocation/dports/class-dump which returned a "this file/director doesnt exist" error, so i tried to get to it folder by folder. when i got all the way to: cd /opt/local/bin/ i cannot go any further. when i check the contents of the bin directory, the only files i can find are (and i cannot access these apparently either): "daemondo port portf portindex portmirror" i have tried doing this on 2 computers so far to no avail, macports is installed on both like the website said and i am having trouble finding any support for it. please and thank you!!

    Read the article

  • NoClassDefFoundError when running java tool under Xcode

    - by pancake
    Hi all, I'm trying to create a Java Tool by using Xcode. I've already changed my build.xml to have Xcode target java 1.6 and not 1.3 so I can use generics. I'm getting no build errors and using 'javac' and 'java' in the terminal works. Now I want it to work in Xcode as well. I keep getting the following error: Exception in thread "main" java.lang.NoClassDefFoundError: MyClass where 'MyClass' is the class containing the main method. It probably has something to do with the classpath, which as the build.xml prescribes is "${bin}". There is a bin folder in my project folder, and it contains all the .class files needed to run the program. If anybody could help me, it'd be great!

    Read the article

  • Good File Organization Suggestions for Developer

    - by Paul
    I am struggling a little with folder organization to organize the many projects that I work on. I work on OS X - right now I am using ~/Development/ as the root folder, and I have many types of projects. For example, I have my iPhone apps under ~/Development/Xcode I develop in many languages, from PHP, to Ruby, to Python, to Objective-C. So, for example, I might have a couple of open-source apps based on PHP where I am using the Zend framework. Some of these projects are for clients, others are tests/experiments when learning a new language or general experimenting. I am really interested in how other developers have organized code/projects and could pass along some advice to make it very easy to navigate through code/projects related to many languages and types of projects.

    Read the article

  • How can I add a .jar to my build path in Eclipse?

    - by Roman
    I try to do it the following way: Right click on the name of the project. Click on Build Path in the drop dawn menu. Click on "Configure Build Path" And then I do not know what to do. Should I select "Source", "Projects", "Libraries", "Order and Export"? In "Libraries" I have "Add JARs..." and "Add External JARs...". What should I select? (I have already a .jar file in the lib folder of my project.) ADDED: If I click on "Add JARs" in the "Libraries" tab, I see the "lib" sub-folder but if I go there I do not see my .jar file there (and I know that it is there).

    Read the article

  • web site in pure php with clean url

    - by Testadmin
    Hi I have enabled mod_rewrite in my Xampp apache. When I run my php info page, I saw mod_rewrite under Loaded Modules. So I think it's enabled. Then I create a folder clean-url under htdocs. Inside clean-url folder I have 3 files 1) index.php here I put Welcome 2) Test. php 3) .htaccess Here I put RewriteEngine On RewriteRule ^([a-z]+)/([a-z-]+)$ /$1/$2.php [L] I want to run the index page, and by clicking on that hyper link I want to display the test.php page with URL mydomain/clean-url/test I know I am in a wrong path. Does any one help me? Or correct me? ALso i don't know any idea about url rewriting and .htaccess. Please help me.

    Read the article

  • wordpress mu image speed problem

    - by InnateDev
    I have an mu install with the typical blogs.dir folder storing files for each blog. When loading these images however they take forever to appear, but they eventually do. It seems that wpmu uses php to serve each image which is ludicrous. When using images from the same domain but in a root folder, the images are displayed quickly. Is there a workaround the blogs.php for rendering files? Could there be something else wrong in the settings of my install?

    Read the article

  • Python preprocessing imports

    - by FiloSottile
    I am managing a quite large python code base (2000 lines) that I want anyway to be available as a single runnable python script. So I am searching for a method or a tool to merge a development folder, made of different python files into a single running script. The thing/method I am searching for should take code split into different files, maybe with a starting __init___.py file that contains the imports and merge it into a single, big script. Much like a preprocessor. Best if a near-native way, better if I can anyway run from the dev folder. I have already checked out pypp and pypreprocessor but they don't seem to take the point. Something like a strange use of __import__() or maybe a bunch of from foo import * replaced by the preprocessor with the code? Obviously I only want to merge my directory and not common libraries.

    Read the article

  • Asp.net loading a file encounters "Access to the path … is denied" in development on Windows 7

    - by ray247
    Hi there, I have an Asp.net app that simply reads an xml file and this code used to work fine on Vista with VS2008, now I just moved to Windows 7 and I migrated the code to VS2010, I encoutered “Access to the path [path to my webapp folder] is denied". Nothing else is changed, I tried to change folder perms even though I didn't think it got anything to do with that since the same code used to work fine, but still didn't get around this problem. Could someone please shed some light on why this may be happening and how to fix it? Thanks, Ray.

    Read the article

  • frequent updates of a Tomcat application

    - by Erel Segal Halevi
    I have an application that runs on a Tomcat 7 server on a Windows machine. In its current stage, I have to frequently update and fix it. Whenever I need to update the application, I do all this: Build a new war file; Go to the Windows server, stop the Tomcat service; download the file, put it under webapps; Remove the old application folder under webapps; Remove the old application folder under work/Catalina/localhost (otherwise it keeps the old version cached). Restart the Tomcat service. I am sure there is a way to do all this automatically. What is it?

    Read the article

  • Why isn't my File.Move() working?

    - by yeahumok
    I'm not sure what exactly i'm doing wrong here...but i noticed that my File.Move() isn't renaming any files. Also, does anybody know how in my 2nd loop, i'd be able to populate my .txt file with a list of the path AND sanitized file name? using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.IO; using System.Text.RegularExpressions; namespace ConsoleApplication2 { class Program { static void Main(string[] args) { //recurse through files. Let user press 'ok' to move onto next step string[] files = Directory.GetFiles(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); foreach (string file in files) { Console.Write(file + "\r\n"); } Console.WriteLine("Press any key to continue..."); Console.ReadKey(true); //End section //Regex -- find invalid chars string pattern = " *[\\~#%&*{}/<>?|\"-]+ *"; string replacement = " "; Regex regEx = new Regex(pattern); string[] fileDrive = Directory.GetFiles(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing", "*.*", SearchOption.AllDirectories); List<string> filePath = new List<string>(); //clean out file -- remove the path name so file name only shows string result; foreach(string fileNames in fileDrive) { result = Path.GetFileName(fileNames); filePath.Add(result); } StreamWriter sw = new StreamWriter(@"C:\Documents and Settings\jane.doe\Desktop\~Test Folder for [SharePoint] %testing\File_Renames.txt"); //Sanitize and remove invalid chars foreach(string Files2 in filePath) { try { string sanitized = regEx.Replace(Files2, replacement); sw.Write(sanitized + "\r\n"); System.IO.File.Move(Files2, sanitized); System.IO.File.Delete(Files2); } catch (Exception ex) { Console.Write(ex); } } sw.Close(); } } } I'm VERY new to C# and trying to write an app that recurses through a specific drive, finds invalid characters (as specified in the RegEx pattern), removes them from the filename and then write a .txt file that has the path name and the corrected filename. Any ideas?

    Read the article

  • Bash - Adding 0's in the middle of a file name

    - by user596691
    I have a bunch of files which are named: mem0.csv mem1.csv . . . . mem153.csv . . . They are all in the same folder. When I do ls in the folder they appear in an order of mem0.csv mem1.csv mem10.csv mem100.csv . . . mem2.csv mem20.csv . . . I want to create a bash script to push 0's between mem and the number. I figure that I need to add 0's until all the filenames are of the same length only problem is that I don't know how to do this.

    Read the article

  • Django template tag basic question

    - by ninja123
    It looks like this template tag works like a charm for most people: http://blog.localkinegrinds.com/2007/09/06/digg-style-pagination-in-django/ For some reason I get this error: Caught an exception while rendering: 'is_paginated' I use this template tag in my template like so: {% load digg_paginator %} {% digg_paginator %} Where digg_paginator.py is in my app/templatetags folder and the included template context digg_paginator.html is in my app/templates folder. The queryset that needs pagination is called 'destinations'. If i just specify {% digg_paginator %}, how does it know what variable to paginate?? I feel I am missing something important here or just plain stupid :P Someone please help, or explain to me how this should be done. Thanks

    Read the article

  • Creating a iso file from a set of img files

    - by cafebabe1991
    So i have started building android from scratch and after lot of effort finally landed up to a point where i have the OUT folder consisting of all the required IMG files for an emulator to run. Like the system.img ramdisk.img userdata-qemu.img So after that i ran the emulator command so that means the OUT directory was valid and could easily be used to create any other bootable medium. What i want to accomplish Creating the iso file from all those img files found at the end of building process,or a way to just create an iso out of that complete OUT folder. any help in this regard would be greatly appreciated.

    Read the article

  • Multiple calls to /dev/stdin using python subprocess (*nix)

    - by Alex Leach
    Hi, I have a python subprocess call which I would like to link up to three pipes (two standard in and one standard out). I know that there is only one /dev/stdin, but there's all those other devices in /dev I don't know about, and don't know of any python os, sys or subprocess modules that will utilise them in a manner which allows me to give the device path to subprocess.Popen. The reason I ask is because I would like to pipe information from a mysql database or tar archive rather than a directory structure I currently have which has 28,000 directories in. The directory names alone uses a LOT of space! The alternative is to tar / gunzip the entire directory structure and manoeuvre through the compressed archive. With either solution, mysql or tar, I would still like to have two pipes into subprocess.Popen and one out, so that I can bypass the HDD. Any need for an example??

    Read the article

  • .rdlc reporting bound to Object Data Source in Three layer Application

    - by Saeedouv
    Hi, i have the following situation, i have a Reporting layer(stand alone) in asp.net application(NOT website, this means NO App_Code folder exists), and i want just to create Object Data Source to take an Object in a separate layer(lets say from Data Access Layer), and then to use that Object Data Source to create a report, i have spent my whole day working around that, tons of work around's and articles on the web, but does not mention what i really want to do, any answer is appriciated... just to make things more clear here, assume the following: i have a solution with the follwoing layers, UI Reporting(has NO Employees object) just a reference Business Logic Data Access Layer(Employees--GetEmployees(), all i need is as mentioned above, i want to create Object Data Source from Reporting layer, to take Employee object from DAL, and then use it's GetEmployees method to be added to report, i think its more clear now, since also Reporting layer has NO App_Code folder.

    Read the article

  • Where to place log4j.xml

    - by Farid
    Hi , How can we specify were log4j has to look at when trying to find its xml configuration file ? It seems that by default, log4j looks into the root of a class folder, I can say that using the debug log4j functionality and running my application from the IDE. However, I don't have any class folder in my jar anymore. And the log4j.xml file is at the root of the jar. I have already tried to set the option -Dlog4j.configuration=log4j.xml but it doesn't work. Here is the global structure of my application at the moment : com lib meta-inf log4j.xml Thanks !

    Read the article

< Previous Page | 229 230 231 232 233 234 235 236 237 238 239 240  | Next Page >