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  • In .NET Xml Serialization, is it possible to serialize a class with an enum property with different

    - by Lasse V. Karlsen
    I have a class, containing a list property, where the list contains objects that has an enum property. When I serialize this, it looks like this: <?xml version="1.0" encoding="ibm850"?> <test> <events> <test-event type="changing" /> <test-event type="changed" /> </events> </test> Is it possible, through attributes, or similar, to get the Xml to look like this? <?xml version="1.0" encoding="ibm850"?> <test> <events> <changing /> <changed /> </events> </test> Basically, use the property value of the enum as a way to determine the tag-name? Is using a class hierarchy (ie. creating subclasses instead of using the property value) the only way? Edit: After testing, it seems even a class-hierarchy won't actually work. If there is a way to structure the classes to get the output I want, even with sub-classes, that is also an acceptable answer. Here's a sample program that will output the above Xml (remember to hit Ctrl+F5 to run in Visual Studio, otherwise the program window will close immediately): using System; using System.Collections.Generic; using System.Xml.Serialization; namespace ConsoleApplication18 { public enum TestEventTypes { [XmlEnum("changing")] Changing, [XmlEnum("changed")] Changed } [XmlType("test-event")] public class TestEvent { [XmlAttribute("type")] public TestEventTypes Type { get; set; } } [XmlType("test")] public class Test { private List<TestEvent> _Events = new List<TestEvent>(); [XmlArray("events")] public List<TestEvent> Events { get { return _Events; } } } class Program { static void Main(string[] args) { Test test = new Test(); test.Events.Add(new TestEvent { Type = TestEventTypes.Changing }); test.Events.Add(new TestEvent { Type = TestEventTypes.Changed }); XmlSerializer serializer = new XmlSerializer(typeof(Test)); XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); ns.Add("", ""); serializer.Serialize(Console.Out, test, ns); } } }

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  • Django: Is it possible to attach media files (css, javascript etc) to a View-class?

    - by mrmclovin
    I can't fins any information on how to define css or javascript files in a view like: class MyView(View): .... class Media: css = { 'all' : 'mystyle.css' } If you have a form you can do like: class MyForm(ModelForm): .... class Media: css = { 'all' : 'mystyle.css' } And then in the template you can print the files like; {{ form.media.css }} I like that Syntax very much and I like to keep the View-specific css files in the app-directory. Does anyone know if it's possible? Thanks!

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  • How to set title and class in the HTML for the options of a ModelChoiceField?

    - by celopes
    I have a model class MyModel(models.Model): name = models.CharField(max_length=80, unique=True) parent = models.ForeignKey('self', null=True, blank=True) I want to render a ModelChoiceField for that model that looks like: <select name="mymodel" id="id_mymodel"> <option value="1" title="Value 1" class="">Value 1</option> <option value="2" title="Value 2" class="Value 1">Value 2</option> </select> The differences between this output and the default output for a ModelChoiceField are the title and class elements in the OPTION tag. They don't exist in ModelChoiceField's default output. For my purposes: The title element is supposed to be the Option Name. The class element is supposed to be self.parent.name. (this is my problem) So, in the HTML snippet above, Value 1 has no parent and Value 2 has a parent of Value 1. What is the best mechanism to change ModelChoiceField's default HTML output? EDIT: I understand how to create a new Widget for rendering HTML. The problem is how to render a value from the underlying model in each of the options.

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  • How can I make my password fields always empty?

    - by ggfan
    I have a form field where users can change their passwords, but if they set their settings to remember passwords, their password shows up. Is there a way to make the field always empty? So that they always have to type their password. <label for="oldpassword" class="styled">Old password:</label> <input type="password" id="oldpassword" name="oldpassword"/><br />

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  • How do I reference a pointer from a different class?

    - by Justagruvn
    First off, I despise singletons with a passion. Though I should probably be trying to use one, I just don't want to. I want to create a data class (that is instantiated only once by a view controller on loading), and then using a different class, message the crap out of that data instance until it is brimming with so much data, it smiles. So, how do I do that? I made a pointer to the instance of the data class when I instantiated it. I'm now over in a separate view controller, action occurs, and I want to update the initial data object. I think I need to reference that object by way of pointer, but I have no idea how to do that. Yes, I've set properties and getters and setters, which seem to work, but only in the initial view controller class. Peace Love applesauce.

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  • In what package should a "Settings" class be placed?

    - by Tom
    I'm in the middle of building an application but found myself too easily creating new packages without keeping the project's structure in mind. Now, I'm trying to redo the whole project structure on paper first. I am using a Settings class with public properties, accessed as settings for several other classes around the project. Now, since this Settings class applies for the whole project, I am unsure if it should be packaged and if so, in what kind of package should it exist? Or should it be in the root (the default package) with the main application class? I've been thinking about putting it in my utils package, then again I don't think it really is an utlity. Any strategies on how to decide on such package structure for example for a Settings class?

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  • How to access a superclass method from a nested class?

    - by m01
    I hope this code explains the problem: class Foo { void a() { / *stuff */ } } class Bar extends Foo { void a() { throw new Exception("This is not allowed for Bar"); } class Baz { void blah() { // how to access Foo.a from here? } } } I know that I may be doing something wrong, because inheritance perhaps shouldn't be used in such way. But it's the easiest way in my situation. And, beside that, I'm just curious. Is it possible?

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  • Is there anything else other than class, interface or Enum?

    - by GK
    As we know to generate a class file there should be atleast one class or interface or an Enum should be declared in the java file. So i was curious that is there anything else as well other the mentioned which can cause a class file generation. Or did anybody think that as we can declare the above mentioned, we can declare this(Which you think) as well ?

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  • Are there any "gotchas" to watch for in using a Class (object) within itself?

    - by Clay Nichols
    I've got a Registry class and there are a few Registry values that I want to access from within that Registry class. (There is a bit of a calculation with these values so I thought I'd just put all that code right in the Registry Class itself). So we might have something within our RegistryRoutine.cls like: Function GetMyValue() as integer Dim R as new RegistryRoutine <calculations> GetMyValue=R.GetRegisetryValue (HKEY, key, value, etc.) End Function

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  • Pointers and collection of pointers in C++. How to properly delete.

    - by Julen
    Hello, This is a newbe question but I have alwasy doubts with pointers in C++. This is the situation. I have a class A which as a collection (a vector actually) of pointers of class B. This same class A has another collection of pointers to class C. Finally the objects of class B have also a collection to pointers to class C which point to the same instances the class A points to. My question is, if I delete a member of class-C-type pointer in class B, what happens to the pointer in class A that points to the deleted instance of class C? How this situation has to be treated? Thanks a lot in advance! Julen.

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  • Setting an attribute property to the type of the decorated class.

    - by cmaduro
    Is it possible to get the decorated class' type inside of the custom attribute's class? For example: [MetadataAttribute] [AttributeUsage(AttributeTargets.Class | AttributeTargets.Property, AllowMultiple = false)] public class ViewAttribute : ExportAttribute { public object TargetRegion { get; set; } public Type ViewModel { get; set; } public Type Module { get; set; } public ViewAttribute() : base(typeof(UserControl)) { Module = GetDecoratedClassType(); //I need this method } } In the following example GetDecoratedClassType() would return HomeView [View] HomeView MyHomeView { get; set; }

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  • Restrict type of method parameter with two or more class names?

    - by Kirzilla
    Hello, We can restrict type of method parameters; for example, we should say that function parameter should be an instance of object described in class with name "Some Class". function some_function(Some_Class $object) { } Is there any php native posibilities to restrict method parameter with two or more classes? For examle, "Some Class" or "Some Class2" or "Some Class3". Or maybe there is any way to restrict method parameter with classes which implements interface with name "Some_Interface"? Thank you.

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  • How to retrieve CSS style object by CSS class name?

    - by Chir
    Hi, Is it possible to get all properties of a css class associated with an element? e.g. .hightligh { font-weight: bold; border: 1px solid red; padding-top:10px; } Lets say the css class "hightlight" is assigned to div element <div class='highlight'></div> Now using JavaScript, I need to iterate through all style properties of css class "highlight" associated with the div element. Basically, I want to treat it as a JavaScript object whose properties can be accessed using iterator or for loop. Thanks in advance

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