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• another file_exists with special chars problem

  - by Camran

  I have some folders with special characters in their names. I run currently at a test-computer with Windows OS, but later I will use LINUX. My problem is that the folders with special chars in their names cannot be recognized somehow. ex: file_exists('../Bilar/27733691_1.jpg') // TRUE file_exists('../Båtar/27733691_1.jpg') // FALSE because of the special char in folder name... How should I solve this? I plan to run LINUX in the future when website is online... would that matter? Please explain thoroughly because I am a newb at this Thanks

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• Data not transfred from form to mysql table (updating of data is not happening)

  - by Jimson

  Hi all and thanks in advance to all for this I tired and was unable to find the answer i am looking for an answer. my problem is that i am unable to update the values enterd in the form. I have attached all the files i'm using MYSQL database to fetch data. what happens is that i'm able to add and delete records from form using ajax and PHP scripts to MYSQL database, but i am not able to update data which was retrived from database. the file structure is as follows index.php is a file with ajax functions where it displays form for adding new data to MYSQL using save.php file and list of all records are view without refrishing page (calling load-list.php to view all records from index.php works fine, and save.php to save data from form) - *Delete*is an ajax function called from index.php to delete record from mysql database (function calling delete.php works fine) - Update is an ajax function called from index.php to update data using update-form.php by retriving specific record from mysql tabel, (works fine) Problem lies in updating data from update-form.php to update.php (in which update query is wrriten for mysql) i had tried in many ways at last i had figured out that data is not being transfred from update-form.php to update.php there is a small problem in jquery ajax function where it is not transfering data to update.php page. can any one correct this ????? i will be greatfull to them..... please find the link below for all files link to get my form files

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• How to plan a PHP based project with DB involved in the below scenario? [closed]

  - by San

  I'm starting a project on web monitoring where other websites can be monitored. Recently, I have found codeIgniter, yii, kohana frameworks online, but I'm confused as to whether to choose any of those or start directly. Moreover, this is my first big project that I'm planning for. So can anyone give me suggestions on how to start, how to plan, what books to refer to, to start this kind of web application and share some links to understand for myself on how to work on this project?

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• how to pass value to controller??

  - by rajesh

  When I try to pass url value to controller action, action is not getting the required value. I'm sending the value like this: function value(url,id) { alert(url); document.getElementById('rating').innerHTML=id; var params = 'artist='+id; alert(params); // var newurl='http://localhost/songs_full/public/eslresult/ratesong/userid/1/id/27'; var myAjax = new Ajax.Request(newurl,{method: 'post',parameters:params,onComplete: loadResponse}); //var myAjax = new Ajax.Request(url,{method:'POST',parameters:params,onComplete: load}); //alert(myAjax); } function load(http) { alert('success'); } and in the controller I have: public function ratesongAction() { $user=$_POST['rating']; echo $user; $post= $this->getRequest()->getPost(); //echo $post; $ratesongid= $this->_getParam('id'); } But still not getting the result. I am using zend framework.

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• designing solution to dynamically load class

  - by dot

  Background Information I have a web app that allows end users to connect to ssh-enabled devices and manipulate them. Right now, i only support one version of firmware. The logic is something like this: user clicks on a button to run some command on device. web application looks up the class name containing the correct ssh interface for the device, using the device's model name. (because the number of hardware models is so small, i have a list that's hardcoded in my web app) web app creates a new ssh object using the class loaded in step 2. ssh command is run and session closed. command results displayed on web page. This all works fine. Now the end user wants me to be able to support multiple versions of firmware. But the catch is, they don't want to have to document the firmware version anywhere becuase the amount of overhead this will create in maintaining the system database. In other words, I can't look up the firmware version based on the device. The good news is that it sounds like at most, I'll have to support two different versions of firmware per device. One option is to name the the classes like this: deviceX.1.php deviceX.2.php deviceY.1.php deviceY.2.php where "X" and "Y" represent the model names, and 1 and 2 represent the firmware versions. When a user runs a command, I will first try it with one of the class files, if it fails, i can try with the second. I think always try the newer version of firmware first... so let's say in the above example, I would load deviceX.2.php before deviceX.1.php. This will work, but it's not very efficient. But I can't think of another way around this. Any suggestions?

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• Next Div Does not appear correctly after floating two divs to right and left

  - by user3703669

  I have floated two divs to left and right...But the next div after those two divs does not appear correctly... My code is follows #Div1{ position: relative; float: left; } #Div2{ position: relative; float: right; } And the display as follows <div id="Div1">This is aligned to left on the same x axis</div> <div id="Div2">This is aligned to right on the same x axis</div> <div style="color: red;">After the alignment this div does not align</div> The output is as follows http://i.stack.imgur.com/8A6hz.png But I expect something like this http://i.stack.imgur.com/wVGN6.png Anyway to accomplish this task ?? Please HELP!! Urgent help needed!!!

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• CSS Pop up box that works in all browsers

  - by waliany

  I want to display a pop up box when a visitor clicks on my google map marker. I already have the text I want to display when they click the marker.

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• Assign a static function to a variable in PHP

  - by Felipe Almeida

  I would like to assign a static function to a variable so that I can send it around as a parameter. For example: class Foo{ private static function privateStaticFunction($arg1,$arg2){ //compute stuff on the args } public static function publicStaticFunction($foo,$bar){ //works $var = function(){ //do stuff }; //also works $var = function($someArg,$someArg2){ //do stuff }; //Fatal error: Undefined class constant 'privateStaticFunction' $var = self::privateStaticMethod; //same error $var = Foo::privateStaticFunction; //compiles, but errors when I try to run $var() somewhere else, as expected //Fatal error: Call to private method Foo::privateStaticMethod() from context '' $var = function(){ return Foo::privateStaticMethod(); }; } } I've tried a few more variations but none of them worked. I don't even expect this sort of functional hacking to work with PHP but hey, who knows? Is it possible to do that in PHP or will I need to come up with some hack using eval? P.S.: LawnGnome on ##php mentioned something about it being possible to do what I want using array('Foo','privateStaticMethod') but I didn't understand what he meant and I didn't press him further as he looked busy.

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• PHP download page: file_exists() returns true, but browser returns 'page not found'

  - by Chris

  I'm using PHP for a file download page. Here's a snippet of the problem code: if (file_exists($attachment_location)) { header($_SERVER["SERVER_PROTOCOL"] . " 200 OK"); header("Cache-Control: public"); // needed for i.e. header("Content-Type: application/zip"); header("Content-Transfer-Encoding: Binary"); header("Content-Length:".filesize($attachment_location)); header("Content-Disposition: attachment; filename=file.zip"); readfile($attachment_location); die("Hooray"); } else { die("Error: File not found."); } This code works absolutely fine when testing locally, but after deploying to the live server the browser returns a 'Page not found' error. I thought it might be an .htaccess issue, but all .htaccess files on the live server are identical to their local counterparts. My next guess would be the live server's PHP configuration, but I have no idea what PHP setting might cause this behaviour. The file_exists() function always returns true - I've checked this on the live server and it's always correctly picking up the file, its size etc., so it does have a handle on the file. It just won't perform the download! The main site is a Wordpress site, but this code isn't part of a Wordpress page - it's in a standalone directory within the site root. UPDATE: is_file() and is_readable() are both returning true for the file, so that's not the problem. The specific line that is causing the problem is: readfile($attachment_location) Everything up until that point is super happy.

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• PHP include taking too long

  - by wxiiir

  I have a php file with around 100mb which is full of arrays (only arrays). I've made a script that includes this file (for processing), first it exhausted the default Xampp 128mb memory limit, i've raised it to 1024mb but it just takes forever and doesn't do anything. I'm sure the problem is being created by the sheer size of the file because i've tried removing all lines of code and just leaving the include and an echo for me to know when it finishes executing, and it does the same thing (which is taking forever), i've also tried to run the 100mb file in separate and same thing again. A 10mb file is taking forever as well but a similar 1mb file is almost instantly read and executed so the problem must be more than just the file size. I was avoiding using c++ for a simple project as this and would rather not to as php is easier for me and the task that will be executed doesn't need to benefit from the added speed that it would have if it had been done in c++ but if i have no luck in solving this problem i guess i'll have to. EDIT Reasons for not using a database: 1-Whoever made it didn't used a database and it will be pretty hard to store this in an organized database if i'm not able to do something with it first, like just reading it, copying parts from it or putting in memory or something. 2-I don't have experience working with databases as pretty much all stuff i've ever done in php didn't needed large amounts of stored data, 50kb at best, if i was thinking about a big project or huge chunks of data as this one, i definitely would, but i didn't made this mess to start with and now i have to undo it. 3-The logic for having to store a small portion of data like 10mb in hard drive when now every computer has pretty much enough ram to fit the whole OS in it is pretty much incomprehensible unless someone gives a good explanation about it, if i had to access a lot of said files simultaneously i would understand but like i said, this is a simple project, this is the only file that will be accessed at a given time this isn't even to make some kind of website, it's to run a few times and be done with it.

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• PHP & MySQL Pagination Update Help

  - by TaG

  Its been a while since I updated my pagination on my web page and I'm trying to add First and Last Links to my pagination as well as the ... when the search results are to long. For example I'm trying to achieve the following in the example below. Can some one help me fix my code so I can update my site. Thanks Previous First 1 2 3 4 5 6 7 ... 199 200 Last Next I currently have the following displayed using my code. Previous 1 2 3 4 5 6 7 Next Here is the part of my pagination code that displays the links. if ($pages > 1) { echo '<br /><p>'; $current_page = ($start/$display) + 1; if ($current_page != 1) { echo '<a href="index.php?s=' . ($start - $display) . '&p=' . $pages . '">Previous</a> '; } for ($i = 1; $i <= $pages; $i++) { if ($i != $current_page) { echo '<a href="index.php?s=' . (($display * ($i - 1))) . '&p=' . $pages . '">' . $i . '</a> '; } else { echo '<span>' . $i . '</span> '; } } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($start + $display) . '&p=' . $pages . '">Next</a>'; } echo '</p>'; }

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• sql query selecting one name no matter how many rows it was mentioned in

  - by Baruch

  Basically what I'm trying to do is get the information from column x no matter how many times it was mentioned. means that if I have this kind of table: x | y | z ------+-------+-------- hello | one | bye hello | two | goodbye hi | three | see you so what I'm trying to do is create a query that would get all of the names that are mentions in the x column without duplicates and put it into a select list. my goal is that I would have a select list with TWO not THREE options, hello and hi this is what I have so far which isn't working. hope you guys know the answer to that: function getList(){ $options="<select id='names' style='margin-right:40px;'>"; $c_id = $_SESSION['id']; $sql="SELECT * FROM names"; $result=mysql_query($sql); $options.="<option value='blank'>-- Select something --</option>" ; while ($row=mysql_fetch_array($result)) { $name=$row["x"]; $options.="<option value='$name'>$name</option>"; } $options.= "</SELECT>"; return "$options"; } Sorry for confusing... i edited my source

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• Using AJAX to POST data to PHP database, then refresh

  - by cb74656

  Currently I have a button: <ul> <li><button onclick="display('1')">1</button></li> <li><button onclick="display('2')">2</button></li> <li><button onclick="display('3')">3</button></li> </ul> That when pressed, calls a javascript function, and displays PHP based on which button is pressed using AJAX. I figured this out all on my own. The AJAX gets a PHP file with a postgres query that outputs a table of data to a div. Now I want to be able to add, via form, new data and have it refresh (without reloading the page, yannknow?). I've tried a couple of things, and have hit roadblocks every time. My initial idea was to have the form submit the data using a javascript function and AJAX, then call my "display()" function after the query to reload the content. I just can't figure it out using GoogleFu. Based on my current idea, I'd like help with the following: How do I pass the form data to a javascript function. How do I use POST to pass that data to PHP using AJAX? I'm super new to javascript and AJAX. I've looked into jquery as it seems like that's the way to go, but I can't figure it out. If there's a better way to do this, I'm open to suggestions. Please forgive any misuse of nomenclature. EDIT: Once I solve this problem..., I'll have all the tools needed to finish the project preliminarily.

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• PHP header() redirect not working after shortening URL using bit.ly

  - by Fabian Kreiser

  Hi, I have a problem with php header redirect. I already spent hours trying to fix it. The problem doesn't occur when the bit.ly api is not used in the script, I have no clue why. <?php if (strlen($_GET['url']) > 26) { $shortenedURL = $_GET['url']; if (isset($_GET['login']) && isset($_GET['apikey'])) { $shortenedURL = file_get_contents('http://api.bit.ly/v3/shorten?format=txt&login='.urlencode($_GET['login']).'&apiKey='.$_GET['apikey'].'&uri='.urlencode($_GET['url'])); } else { $shortenedURL = file_get_contents('http://icbrd.net/shorten.php?longurl='.$_GET['url']); } if (strlen($shortenedURL) > 0) { header( 'Location: icebird://compose?status='.$shortenedURL.'%20' ); exit(); } else { header( 'Location: icebird://compose?status='.$_GET['url'].'%20' ); exit(); } } else { header( 'Location: icebird://compose?status='.$_GET['url'].'%20' ); exit(); } ?> I hope you can help me, as this is driving me crazy. Regards

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• How to make flash file not downloadable?

  - by Nitz

  Hey friends, I want that my flash file on my website, can't be downloaded by anyone. Is there any way that i can do that? As Firefox and many browser has many add-ones which easily detect out flash content and after they can download the flash file?

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• PHP: Need a double check on an error in this small code

  - by Josh K

  I have this simple Select box that is suppose to store the selected value in a hidden input, which can then be used for POST (I am doing it this way to use data from disabled drop down menus) <body> <?php $Z = $_POST[hdn]; ?> <form id="form1" name="form1" method="post" action="test.php"> <select name="whatever" id="whatever" onchange="document.getElementById('hdn').value = this.value"> <option value="1">1Value</option> <option value="2">2Value</option> <option value="3">3Value</option> <option value="4">4Value</option> </select> <input type="hidden" name ='hdn' id="hdn" /> <input type="submit" id='submit' /> <?php echo "<p>".$Z."</p>"; ?> </form> </body> The echo call works for the last 3 options (2,3,4) but if I select the first one it doesnt output anything, and even if i change first one it still doesnt output anything. Can someone explain to me whats going on, I think it might be a syntax issue.

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• Two forms but only 1 jsp file

  - by joshft91

  Here's what I've got going on. I have one .jsp file. However, I have two forms with multiple inputs inside those forms. What is the best way to detect that one form was submitted but not the other? Here's an example: I have this form: <form name = "login" action="index.jsp" method="get"> Username: <input id="username" name="username" type="text"/><br/> Password: <input id="password" name="password" type="password"/> <input type="submit" Value="Login" ></input> </form> If that button is clicked, I'd like to run this code: String username = request.getParameter("username"); String password = request.getParameter("password"); if((username!= null && !username.trim().equals("")) && (password != null && !username.trim().equals(""))) { DBentry DBentry=new DBentry(); boolean flag = DBentry.isTaken(username); if(flag) {%><script type="text/javascript">alert("Login Successful!");</script><% } else { %><script type="text/javascript">alert("Unrecognized username. Please register!");</script><% } } else { %><script type="text/javascript">alert("Please enter both a username and password!");</script><% } Further down I would have something exactly like it but submitting a different form. Thanks!

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• How to make this very long url appear short?

  - by Camran

  I have made most my site SE friendly, but one part of my site bugs me... I have a HUGE form in one of the pages, and when submitting the form (action=php_page) URL is so long it covers half a word document in one line with all the passing variables... This is very ugly... Is there any way to make this long URL appear short? Or some other solution you know of? Let me know if you need more input... Thanks

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• Warning ,i can not solving in PHP code

  - by user318068

  hi , in code there Warning Warning: mysql_fetch_array() expects parameter 1 to be resource, string given in C:\xampp\htdocs\Join.php on line 69 but i can not solving where exactly can you help me where the error in this code . <?php 51. include("connect.php"); 53. $email = mysql_query("select MemberEmail from members where MemberID= '$id' "); 54. while ($row = mysql_fetch_array($email)) 55. { 57. $memEmail=$row['MemberEmail']; } 62. $sql = mysql_query("select * from ninvite where recieverMemberEmail ='$memEmail' and viwed= '0' order by RoomID desc"); 64. $num =mysql_num_rows($sql); 67. if ($sql and $num >0 ) { 69. while($row=mysql_fetch_array($sql)) { 71. $sender=$row['SenderMemberID']; 73. $room=$row['RoomID']; 77. $sql2 =mysql_query("select MemberName from members where MemberID ='$sender' "); 78. $sql1 =mysql_query("select RoomName,RoomLogo from rooms where RoomID ='$room' "); 79. while($row=mysql_fetch_array($sql2)) { $mem =$row['MemberName']; } 84. while($rows=mysql_fetch_array($sql1)) { $Ro =$rows['RoomName']; $logo = $rows['RoomLogo']; } 89. ?> Thanks alot

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• regular expression for validation not working

  - by Camran

  I have a "description textarea" inside a form where user may enter a description for an item. This is validated with javascript before the form beeing submitted. One of the validation-steps is this: else if (!fld.value.match(desExp)){ And desExp: var desExp = /^\s*(\w[^\w]*){3}.*$/gm; Now my problem, this works fine on all cases except for descriptions where the description BEGINS with a special character of the swedish language (å, ä, ö). This wont work: åäö hello world But this will: hello world åäö Any fixes? Thanks

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• How to embed a google map with a changeable area?

  - by Tom

  I haven't worded this very well But basically, I'd like to embed a map on my site - but the area it shows will change. I've tried doing this, but it never seems to work as it will focus on the wrong area - the old area, rather than the new area. Basically, I'd like a google map code that uses $place as a location. Thanks.

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• How do I show the selected item in an HTML <select> at the top

  - by Michael Meadows

  I have an HTML select that looks something like this (values are fake) <select size="40"> <option value="1">What would you do if I sang out of tune,</option> <option value="2">Would you stand up and walk out on me?</option> ... more <option value="156">Lend me your ears, and I'll sing you a song,</option> <option selected="selected" value="157">I will try not to sing out of key.</option> <option value="158">Oh, I get by with a little help from my friends.</option> ... more <option value="507">I get high with a little help from my friends.</option> <option value="509">Gonna' try with a little from my friends.</option> </select> The problem that I have is that when displaying the list after loading the page and the selected option is in the middle of the very long list, IE scrolls the selected option to the top of the list (which is what I want). Firefox, Chrome, Opera, and Safari show it at the bottom (which I don't want). I have to assume that IE is doing it wrong since everyone else shows it at the bottom. How can I force the browsers to display the selected item at the top of the list. I do not want to put it at the top of the list, I just want it to scroll such that the selected option is at the top. bonus, it would be even better if I can put it fourth from the top, but I can live without that if it's too difficult.

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• Hide 'Would you like to remember password' iFrame

  - by nsilva

  Basically I have a website called http://yellow-taxis.uk/ which features an online booking system that is placed on the web site within an iFrame. On the online booking, it automatically logs the user in as a 'Guest' for credit card payments. When the site loads it comes up with a window asking the viewer if they 'would like to remember the password'. I was wondering if there was anyway possible to not display this window as it would be a much simpler option than changing a lot of the code within the online booking. Just to add, the iFrame is hosted on the same server as the web site (not sure if this makes a difference) Any help would be much appreciated.

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• JQuery: After adding some AJAX, some of the jquery code no longer works

  - by fwaokda

  Here's a pastebin link to my entire jQuery code. [ http://pastebin.com/w57ma5Gx ] The "Thumbnails" section was working fine before I added the ajax sections. Anyone can help me with why it quit working? And if I need to I can post another question but figured I'd try it here first. Whats a better way of writing the ajax code where it executes once upon loading the page and then every time I click the $("a#next") link afterwards? Right now I just repasted the code outside of the next link and that works, but seems silly to have the same code in two different places like that. Thanks!

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• in_array() - help on what specifically would return true

  - by Kerri

  I am using in_array, and I'm trying to use it in a way where it will only return true if it's an exact match of one of the objects in the array, not just if it's "in" the array. e.g. 1. $sample_array = array('123', '234', '345'); 2. $sample_array = array('23', '34', '45'); in_array('23', $sample_array); In the above example, I would only want version 2 to return true, because it has the exact string, '23'. Version 1 returns true as well though, because the array contains instances of the string '23'. How would I get this to work so that only version 2 returns true? Am I even using the right function?

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