Search Results

Search found 33321 results on 1333 pages for 'php qt'.

Page 235/1333 | < Previous Page | 231 232 233 234 235 236 237 238 239 240 241 242  | Next Page >

  • I don't know where to start with WSDL and SOAP in PHP 5.2+

    - by xaguilars
    Hello, I'm a web services newbie and I've tried to learn it looking for tutorials in google... but I didn't found anything really helpfull... Do you know any tutorial / web page / documentation for web services using PHP 5 native SOAP client? I need to implement a SOAP client for fetch/send data from a IIS server (for hotels reservations). Is there some server that I can make tests with? Thank you!

    Read the article

  • MOOTOOLS calling sexy.error() from PHP

    - by Mikey1980
    I am very inexperienced with PHP and I've having trouble calling a mootools function. Here's my code: echo '<script language="JavaScript">'; echo "Sexy.error('Test!');"; echo '</script>'; When I try it with a simple alert('test') it works just fine.. I'm confused?!?

    Read the article

  • Updating an integer defined column in a MySQL DB with PHP

    - by Zloy Smiertniy
    I have a table defined like this: create table users ( id int(10), age int(3), name varchar (50) ) I want to use a query to update just age, which is an integer, that comes from an html form. When it arrives to the method that updates it, it comes as a string, so I change it to integer with PHP and try to update the table, but it doesn't work $age = intval($age); $q2 = "UPDATE users SET age='$age' where username like '$username';"; mysql_query($q2,$con);

    Read the article

  • Undefined function in php

    - by Bidyut
    I wrote three methods in a class and one is calling another, but when I call the function outside through the object, it is showing an undefined function error for the second function. Here's my code: function resize_image(){ } function image_resize(){ $a = resize_image(); } When I run this, it shows resize_image() as undefined. Here's the error: Fatal error: Call to undefined function resize_image() in /home/vacayge/public_html/Major/Alpha1/classes/cUserImages.php on line 2090

    Read the article

  • Return current web path in PHP

    - by BenTheDesigner
    Hi All Currently developing a PHP framework and have ran into my first problem. I need to be able to drop the framework into any folder on a server, no matter how many folders deep, and need to find that directory to use as a base URL. For example, it currently works if I put the framework in the root of the server (http://cms.dev/), but if I were to put it in http://cms.dev/folder/ it does not work. Please advise, any comments welcome. BenTheDesigner

    Read the article

  • Facebook Photo upload using PHP/Java

    - by shyam
    Is there a way I can post photos to my facebook profile using my username and password only? The code may be in PHP or Java. I dont want to make a facebook app and allow it to post photos to my profile. Any help is much appreciated. Thanks in advance.

    Read the article

  • Asynchronous PHP calls?

    - by UltimateBrent
    Is there a way to PHP make asynchronous http calls? I don't care about the response, I just want to do something like file_get_contents(), but not wait on the request to finish before executing the rest of my code. This would be super useful for setting off "events" of a sort in my application, or triggering long processes. Any ideas?

    Read the article

  • php - clean URL

    - by tibin mathew
    Hai I want to create a web site with pure php. I want to hide the url parameters. I.e. I want to make my web site with clean urls. Is there is any way to do this with out using any framework? Is it curl help full to do this? Does any one give me a solution.

    Read the article

  • PHP class function.

    - by Jordan Pagaduan
    What is wrong with this code? <?php class users { var $user_id, $f_name, $l_name, $db_host, $db_user, $db_name, $db_table; function user_input() { $this->$db_host = 'localhost'; $this->$db_user = 'root'; $this->$db_name = 'input_oop'; $this->$db_table = 'users'; } function userInput($f_name, $l_name) { $dbc = mysql_connect($this->db_host , $this->db_user, "") or die ("Cannot connect to database : " .mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "insert into $this->db_table values (NULL, \"$f_name\", \"$l_name\")"; $result = mysql_query($query); if(!$result) die (mysql_error()); $this->userID = mysql_insert_id(); mysql_close($dbc); $this->first_name = $f_name; $this->last_name = $l_name; } function userUpdate($new_f_name, $new_l_name) { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "UPDATE $this->db_table set = \"$new_f_name\" , \"$new_l_name\" WHERE user_id = \"$this->user_id\""; $result = mysql_query($query); $this->f_name = $new_f_name; $this->l_name = $new_l_name; $this->user_id = $user_id; mysql_close($dbc); } function userDelete() { $dbc = mysql_connect($this->db_host, $this->db_user, "") or die (mysql_error()); mysql_select_db($this->db_name) or die (mysql_error()); $query = "DELETE FROM $this->db_table WHERE $user_id = \"$this->user_id\""; mysql_close($dbc); } } ?> The error is: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\jordan_pagaduan\class.php on line 21 Cannot connect to database : Access denied for user 'ODBC'@'localhost' (using password: NO) The code cannot define this "$this->db_host" as "localhost".

    Read the article

  • limit PHP script to one domain per license

    - by Mac Os
    what is the best way to make my php code working on one domain and sure i will encode the whole code by ioncube i want function like function domain(){ } if($this_domain <> domain()){ exit('no'); } or $allowed_hosts = array('foo.example.com', 'bar.example.com'); if (!isset($_SERVER['HTTP_HOST']) || !in_array($_SERVER['HTTP_HOST'], $allowed_hosts)) { header($_SERVER['SERVER_PROTOCOL'].' 400 Bad Request'); exit; } now i want know the best way to do that may be will user strpos

    Read the article

  • How do I detect the directory a php file is in

    - by Eric
    I have a PHP file that I need it to detect it's directory it's in. In my case I want it to return C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\ I think that this is pretty straightforward but if there is something you don't understand just comment

    Read the article

  • Unpack/extract zip file with PHP without relying on any extension

    - by seventeen
    Is there any way to unpack or extract a zip file with PHP that does not rely on any installed extension? Has anyone written a class or something that can handle it? Alternatively, is there a solution that uses an extension that is relatively commonly installed on most servers? I need this to work on as many different servers that I have no control over as possible. Thanks for any help!

    Read the article

  • MySQLi Insert prepared statement via PHP

    - by Jimmy
    Howdie do, This is my first time dealing with MySQLi inserts. I had always used mysql and directly ran the queries. Apparently, not as secure as MySQLi. Anywho, I'm attempting to pass two variables into the database. For some reason my prepared statement keeps erroring out. I'm not sure if it's a syntax error, but the insert just won't work. I've updated the code to make the variables easier to read Also, the error is specifically, Error preparing statement. I've updated the code, but it's not a pHP error. It's a MySQL error as the script runs but fails at the execution of: if($stmt = $mysqli - prepare("INSERT INTO subnets (id, subnet, mask, sectionId, description, vrfId, masterSubnetId, allowRequests, vlanId, showName, permissions, pingSubnet, isFolder, editDate) VALUES ('', ?, ?, '1', '', '0', '0', '0', '0', '0', '{"3":"1","2":"2"}', '0', '0', 'NULL')")) { I'm going to enable MySQL error checking. I honestly didn't know about that. <?php error_reporting(E_ALL); function InsertIPs($decimnal,$cidr) { error_reporting(E_ALL); $mysqli = new mysqli("localhost","jeremysd_ips","","jeremysd_ips"); if(mysqli_connect_errno()) { echo "Connection Failed: " . mysqli_connect_errno(); exit(); } if($stmt = $mysqli -> prepare("INSERT INTO subnets (id, subnet, mask,sectionId,description,vrfld,masterSubnetId,allowRequests,vlanId,showName,permissions,pingSubnet,isFolder,editDate) VALUES ('',?,?,'1','','0','0','0','0','0', '{'3':'1','2':'2'}', '0', '0', NULL)")) { $stmt-> bind_param('ii',$decimnal,$cidr); if($stmt-> execute()) { echo "Row added successfully\n"; } else { $stmt->error; } $stmt -> close; } } else { echo 'Error preparing statement'; } $mysqli -> close(); } $SUBNETS = array ("2915483648 | 18"); foreach($SUBNETS as $Ip) { list($TempIP,$TempMask) = explode(' | ',$Ip); echo InsertIPs($Tempip,$Tempmask); } ?> This function isn't supposed to return anything. It's just supposed to perform the Insert. Any help would be GREATLY appreciated. I'm just not sure what I'm missing here

    Read the article

  • .htaccess authentication from a php script to prevent a browser dialog box

    - by digitalbart
    Using php I authenticate a user, then behind the scenes,they are then again authenticated a second time with a single .htaccess username & password. This would be the same for all users, but I would not want them to have to enter a username and password again and they would now be allowed to enter the password protected directory. I prefer not to use http://username@password:somedomain.com. Any thoughts?

    Read the article

  • [php] call_user_func_array problems

    - by Knarf
    I have a class with this in self::$DB = new PDO("mysql:dbname=$dbname;host:=127.0.0.1" , 'root' , ''); and then this public static function __callStatic($name, $arguments) { return call_user_func_array(array('self::$DB', $name), $arguments); } How does I make it right/work? Warning: call_user_func_array() expects parameter 1 to be a valid callback, class 'self::$DB' not found in D:\Mine Dokumenter\My Dropbox\www\Framework 3\database.class.php on line 19

    Read the article

  • retrive data from mysql using php and jquery

    - by user313835
    i have a menu, it contains multiple items, each menu item will retrieve data from the database. i want to do it without the page refresh, i want like an area that will change when the user clicks on the menu link. How should i send data to the php script and how should i get it from there and preview it on the page. if you can send me any information, references or examples that will be great Thanks in advance.

    Read the article

< Previous Page | 231 232 233 234 235 236 237 238 239 240 241 242  | Next Page >