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  • Python: How to get a value of datetime.today() that is "timezone aware"?

    - by mindthief
    Hi, I am trying to subtract one date value from the value of datetime.today() to calculate how long ago something was. But it complains: TypeError: can't subtract offset-naive and offset-aware datetimes The value datetime.today() doesn't seem to be "timezone aware", while my other date value is. How do I get a value of datetime.today() that is timezone aware? Right now it's giving me the time in local time, which happens to be PST, i.e. UTC-8hrs. Worst case, is there a way I can manually enter a timezone value into the datetime object returned by datetime.today() and set it to UTC-8? Of course, the ideal solution would be for it to automatically know the timezone. Thanks!

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  • how to diff / align Python lists using arbitrary matching function?

    - by James Tauber
    I'd like to align two lists in a similar way to what difflib.Differ would do except I want to be able to define a match function for comparing items, not just use string equality, and preferably a match function that can return a number between 0.0 and 1.0, not just a boolean. So, for example, say I had the two lists: L1 = [('A', 1), ('B', 3), ('C', 7)] L2 = ['A', 'b', 'C'] and I want to be able to write a match function like this: def match(item1, item2): if item1[0] == item2: return 1.0 elif item1[0].lower() == item2.lower(): return 0.5 else: return 0 and then do: d = Differ(match_func=match) d.compare(L1, L2) and have it diff using the match function. Like difflib, I'd rather the algorithm gave more intuitive Ratcliff-Obershelp type results rather than a purely minimal Levenshtein distance.

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  • Comments on this assumption about running on dev server vs a real instance in app engine (python)?

    - by Jacob Oscarson
    Hello app engineers! I'm on an app engine project where I'd like to put in a link to a Javascript test runner that I'd like to only exist when running the development server. I've made some experiments on a local shell with configuration loaded using the technique found in NoseGAE versus live on the 'App Engine Console' [1] and it looks to me like a distinction btw real instance and dev server is the presence of the module google.appengine.tools. Which lead me to this utility function: def is_dev(): """ Tells us if we're running under the development server or not. :return: ``True`` if the code is running under the development server. """ try: from google.appengine import tools return True except ImportError: return False The question (finally!) would be: is this a bad idea? And in that case, can anyone suggest a better approach? [1] http://con.appspot.com/console/ (try it! very handy indeed)

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  • Python: When passing variables between methods, is it necessary to assign it a new name?

    - by Anthony
    I'm thinking that the answer is probably 'no' if the program is small and there are a lot of methods, but what about in a larger program? If I am going to be using one variable in multiple methods throughout the program, is it smarter to: Come up with a different phrasing for each method (to eliminate naming conflicts). Use the same name for each method (to eliminate confusion) Just use a global variable (to eliminate both) This is more of a stylistic question than anything else. What naming convention do YOU use when passing variables?

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  • I'm doing a lot of lists and dictionary sorting...and this is causing memory errors in Python websit

    - by alex
    I retrieved data from the log table in my database. Then I started finding unique users, comparing/sorting lists, etc. In the end I got down to this. stats = {'2010-03-19': {'date': '2010-03-19', 'unique_users': 312, 'queries': 1465}, '2010-03-18': {'date': '2010-03-18', 'unique_users': 329, 'queries': 1659}, '2010-03-17': {'date': '2010-03-17', 'unique_users': 379, 'queries': 1845}, '2010-03-16': {'date': '2010-03-16', 'unique_users': 434, 'queries': 2336}, '2010-03-15': {'date': '2010-03-15', 'unique_users': 390, 'queries': 2138}, '2010-03-14': {'date': '2010-03-14', 'unique_users': 460, 'queries': 2221}, '2010-03-13': {'date': '2010-03-13', 'unique_users': 507, 'queries': 2242}, '2010-03-12': {'date': '2010-03-12', 'unique_users': 629, 'queries': 3523}, '2010-03-11': {'date': '2010-03-11', 'unique_users': 811, 'queries': 4274}, '2010-03-10': {'date': '2010-03-10', 'unique_users': 171, 'queries': 1297}, '2010-03-26': {'date': '2010-03-26', 'unique_users': 299, 'queries': 1617}, '2010-03-27': {'date': '2010-03-27', 'unique_users': 323, 'queries': 1310}, '2010-03-24': {'date': '2010-03-24', 'unique_users': 352, 'queries': 2112}, '2010-03-25': {'date': '2010-03-25', 'unique_users': 330, 'queries': 1290}, '2010-03-22': {'date': '2010-03-22', 'unique_users': 329, 'queries': 1798}, '2010-03-23': {'date': '2010-03-23', 'unique_users': 329, 'queries': 1857}, '2010-03-20': {'date': '2010-03-20', 'unique_users': 368, 'queries': 1693}, '2010-03-21': {'date': '2010-03-21', 'unique_users': 329, 'queries': 1511}, '2010-03-29': {'date': '2010-03-29', 'unique_users': 325, 'queries': 1718}, '2010-03-28': {'date': '2010-03-28', 'unique_users': 340, 'queries': 1815}, '2010-03-30': {'date': '2010-03-30', 'unique_users': 329, 'queries': 1891}} It's not a big dictionary. But when I try to do one last thing...it craps out on me. for k, v in stats: mylist.append(v) too many values to unpack What the heck does that mean??? TOO MANY VALUES TO UNPACK.

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  • How to remove certain lists from a list of lists using python?

    - by seaworthy
    I can not figure out why my code does not filter out lists from a predefined list. I am trying to remove specific list using the following code. data = [[1,1,1],[1,1,2],[1,2,1],[1,2,2],[2,1,1],[2,1,2],[2,2,1],[2,2,2]] data = [x for x in data if x[0] != 1 and x[1] != 1] print data My result: data = [[2, 2, 1], [2, 2, 2]] Expected result: data = [[1,2,1],[1,2,2],[2,1,1],[2,1,2],[2,2,1],[2,2,2]]

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  • How to add values accordingly of the first indices of a dictionary of tuples of a list of strings? Python 3x

    - by TheStruggler
    I'm stuck on how to formulate this problem properly and the following is: What if we had the following values: {('A','B','C','D'):3, ('A','C','B','D'):2, ('B','D','C','A'):4, ('D','C','B','A'):3, ('C','B','A','D'):1, ('C','D','A','B'):1} When we sum up the first place values: [5,4,2,3] (5 people picked for A first, 4 people picked for B first, and so on like A = 5, B = 4, C = 2, D = 3) The maximum values for any alphabet is 5, which isn't a majority (5/14 is less than half), where 14 is the sum of total values. So we remove the alphabet with the fewest first place picks. Which in this case is C. I want to return a dictionary where {'A':5, 'B':4, 'C':2, 'D':3} without importing anything. This is my work: def popular(letter): '''(dict of {tuple of (str, str, str, str): int}) -> dict of {str:int} ''' my_dictionary = {} counter = 0 for (alphabet, picks) in letter.items(): if (alphabet[0]): my_dictionary[alphabet[0]] = picks else: my_dictionary[alphabet[0]] = counter return my_dictionary This returns duplicate of keys which I cannot get rid of. Thanks.

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  • How to make if-elif-else statement in python more space-saving?

    - by Neverland
    I have a lot of if-elif-else statements in my code if message == '0' or message == '3' or message == '5' or message == '7': ... elif message == '1' or message == '2' or message == '4' or message == '6' or message == '8': ... else: ... Is it possible to format this in a more space-saving way? I tried it this way: if message == '0' or '3' or '5' or '7': ... elif message == '1' or '2' or '4' or '6' or '8': ... else: ... But without success.

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  • Python: How to extract xml embedded in a html file?

    - by georgehu
    I have a html file with xml snipped embedded, the source code is pasted in the pastbin: http://pastebin.com/Hy0QaWk8 my task is to extract the text enclosed in the first textarea, which is a xml snippet, from the html. Without any change to the original snippet. I'm able to get it by using the BeautifulSoup, but it changes all the tag names into lower case.

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  • What's the non brute force way to filter a Python dictionary?

    - by Thierry Lam
    I can filter the following dictionary like: data = { 1: {'name': 'stackoverflow', 'traffic': 'high'}, 2: {'name': 'serverfault', 'traffic': 'low'}, 3: {'name': 'superuser', 'traffic': 'low'}, 4: {'name': 'mathoverflow', 'traffic': 'low'}, } traffic = 'low' for k, v in data.items(): if v['traffic'] == traffic: print k, v Is there an alternate way to do the above filtering?

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  • How to make a function retun after 5 second passes in python?

    - by alwbtc
    I want to write a function which will return after 5 seconds no matter what: def myfunction(): while passed_time < 5_seconds: do1() do2() do3() . . return I mean, this function run for 5 seconds only, after 5 seconds, it should end, and continue with other function: myfunction() otherfunction() ----> This should start 5 seconds after myfunction() is executed. Best Regards

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  • Python - How to wake up a sleeping process- multiprocessing?

    - by user1162512
    I need to wake up a sleeping process ? The time (t) for which it sleeps is calculated as t = D/S . Now since s is varying, can increase or decrease, I need to increase/decrease the sleeping time as well. The speed is received over a UDP procotol. So, how do I change the sleeping time of a process, keeping in mind the following:- If as per the previous speed `S1`, the time to sleep is `(D/S1)` . Now the speed is changed, it should now sleep for the new time,ie (D/S2). Since, it has already slept for D/S1 time, now it should sleep for D/S2 - D/S1. How would I do it? As of right now, I'm just assuming that the speed will remain constant all throughout the program, hence not notifying the process. But how would I do that according to the above condition? def process2(): p = multiprocessing.current_process() time.sleep(secs1) # send some packet1 via UDP time.sleep(secs2) # send some packet2 via UDP time.sleep(secs3) # send some packet3 via UDP Also, as in threads, 1) threading.activeCount(): Returns the number of thread objects that are active. 2) threading.currentThread(): Returns the number of thread objects in the caller's thread control. 3) threading.enumerate(): Returns a list of all thread objects that are currently active. What are the similar functions for getting activecount, enumerate in multiprocessing?

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  • Given a pickle dump in python how to I determine the used protocol?

    - by SmCaterpillar
    Assume that I have a pickle dump - either as a file or just as a string - how can I determine the protocol that was used to create the pickle dump automatically? And if so, do I need to read the entire dump to figure out the protocol or can this be achieved in O(1)? By O(1) I think about some header information at the beginning of the pickle string or file whose read out does not require processing the whole dump. Thanks a lot!

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  • How do I create a list of timedeltas in python?

    - by eunhealee
    I've been searching through this website and have seen multiple references to time deltas, but haven't quite found what I'm looking for. Basically, I have a list of messages that are received by a comms server and I want to calcuate the latency time between each message out and in. It looks like this: 161336.934072 - TMsg out: [O] enter order. RefID [123] OrdID [4568] 161336.934159 - TMsg in: [A] accepted. ordID [456] RefNumber [123] Mixed in with these messages are other messages as well, however, I only want to capture the difference between the Out messages and in messages with the same RefID. So far, to sort out from the main log which messages are Tmessages I've been doing this, but it's really inefficient. I don't need to be making new files everytime.: big_file = open('C:/Users/kdalton/Documents/Minicomm.txt', 'r') small_file1 = open('small_file1.txt', 'w') for line in big_file: if 'T' in line: small_file1.write(line) big_file.close() small_file1.close() How do I calculate the time deltas between the two messages and sort out these messages from the main log?

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  • Is there a better way to write this URL Manipulation in Python?

    - by dnolen
    I'm curious if there's a simpler way to remove a particular parameter from a url. What I came up with is the following. This seems a bit verbose. Libraries to use or a more pythonic version appreciated. parsed = urlparse(url) if parsed.query != "": params = dict([s.split("=") for s in parsed.query.split("&")]) if params.get("page"): del params["page"] url = urlunparse((parsed.scheme, None, parsed.path, None, urlencode(params.items()), parsed.fragment,)) parsed = urlparse(url)

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  • Elegent way to collapse or expand sub-sequences of a list in Python?

    - by forgot
    I want to collapse or expand sub-sequences of a list e.g. ['A', 'B', 'D', 'E', 'H'] -> ['AB', 'DE', 'H'] and vice versa currently I wrote some ugly code like: while True: for i, x in enumerate(s): if x == 'A' and s[i+1] == 'B': s[i:i+2] = 'AB' break else: break For people who asking 'why do that thing': Actually I'm working on a optimizing compiler and this is the peephole part. Writing pattern matching is a little annoying.

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