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  • mysql_close(): supplied argument is not a valid MySQL-Link resource

    - by maxedison
    I'm trying to get the hang of using custom session handlers to store session data in a MySQL database. However, I keep getting the following warning: mysql_close(): supplied argument is not a valid MySQL-Link resource Here's the code I'm using, which I got from here: function _open(){ global $_sess_db; $_sess_db = mysql_connect("localhost", "root", "******"); if ($_sess_db) { return mysql_select_db('style', $_sess_db); } return false; } function _close(){ global $_sess_db; return mysql_close($_sess_db); //error happens here } The full text of the error message ultimately points to the final "return mysql_close($_sess_db);" line. I can confirm that the mysql_connect info does in fact work, and I do have the rest of the session handler functions defined as well. And in case it helps, I get these errors immediately upon page load, without actually calling any of the session handler functions, and without having any current sessions open.

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  • mysql querying age from dob

    - by Confused
    My MySQL database has date of birth stored in the format yyyy-mm-dd, how do I query the database - without using php code - to show me results of people born within x years of now, and/or, who are y years of age? The table is called users, the colum is called dob. I've spent a while viewing the MySQL manual but I can't work out precisely how to form my query. So far I went for select * from users where dob... but I don't think that's the way to go.

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  • Getting deadlocks in MySQL

    - by at
    We're very frustratingly getting deadlocks in MySQL. It isn't because of exceeding a lock timeout as the deadlocks happen instantly when they do happen. Here's the SQL code that is executing on 2 separate threads (with 2 separate connections from the connection pool) that produces a deadlock: UPDATE Sequences SET Counter = LAST_INSERT_ID(Counter + 1) WHERE Sequence IS NULL Sequences table has 2 columns: Sequence and Counter The LAST_INSERT_ID allows us to retrieve this updated counter value as per MySQL's recommendation. That works perfect for us, but we get these deadlocks! Why are we getting them and how can we avoid them?? Thanks so much for any help with this.

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  • Way to store dates with missing days/months in mysql (php)

    - by Paul M
    I want to store dates in mysql so I set the table to be of type 'Date', which is fine but mysql requires that the full date is provided YYYY-MM-DD. However some of my data does not include day and some is missing the month. Now I could just use a varchar(10) field, but then its difficult to run date based queries on the data. Is there another date format which is not as strong and would allow me to use ?? or 00 where the day/month is not known?

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  • Get the Latest on MySQL Enterprise Edition

    - by monica.kumar
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text-indent:-.25in; font-family:Symbol;}ol {margin-bottom:0in;}ul {margin-bottom:0in;}--Oracle just announced MySQL 5.5 Enterprise Edition. MySQL Enterprise Edition is a comprehensive subscription that includes:- MySQL Database- MySQL Enterprise Backup- MySQL Enterprise Monitor- MySQL Workbench- Oracle Premier Support; 24x7, WorldwideNew in this release is the addition of MySQL Enterprise Backup and MySQL Workbench along with enhancements in MySQL Enterprise Monitor. Recent integration with MyOracle Support allows MySQL customers to access the same support infrastructure used for Oracle Database customers. Joint MySQL and Oracle customers can experience faster problem resolution by using a common technical support interface. Supporting multiple operating systems, including Linux and Windows, MySQL Enterprise Edition can enable customers to achieve up to 90 percent TCO savingsover Microsoft SQL Server. See what Booking.com is saying:“With more than 50 million unique monthly visitors, performance and uptime are our first priorities,” said Bert Lindner, Senior Systems Architect, Booking.com. “The MySQL Enterprise Monitor is an essential tool to monitor, tune and manage our many MySQL instances. It allows us to zoom in quickly on the right areas, so we can spend our time and resources where it matters.” Read the press release for detailson technology enhancements.

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  • MySQL - Installation

    - by Stuart Brierley
    In order to create a development environment for a project I am working on, I recently needed to install MySQL Server.  The first step was to download the msi. Running this presents you with the installer splash screen, detailing the version of MySQL that you are about to install - in this case MySQL Server 5.1. Next you can choose whether to install a Typical, Complete or Custom installation.  Although this is the first time I have installed MySQL and the Custom option states "Recommended for advanced users" I opted to carry out a Custom installation, specifically so that I could be sure of what features and components were installed. On the Custom Setup screen you can choose which components to install.  By default the Developer Components are not included, but I opted to include some of these elements. Next up is the ready to install screen and then the intsallation progress.   Following the completion of the installation you are shown a few screens with details of the MySQL Enterprise subscription option. Finally the installation is complete and you are offered the chance to configure and register MySQL. Next I will be looking at the configuration of MySQL Server 5.1.

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  • expecting tASSOC in a Rails file

    - by steven_noble
    I'm sure I've done something stupid here, but I just can't see it. I call the breadcrumb method in the application view. app/helpers/breadcrumbs_helper.rb says: module BreadcrumbsHelper def breadcrumb @crumb_list = [] drominay_crumb_builder project_crumb_builder content_tag(:div, :id => "breadcrumbs", @crumb_list.map { |list_item| crumb_builder(list_item) }) end def crumb_builder(list_item) if list_item == @crumb_list.last content_tag(:span, list_item['body'], :class => list_item['crumb']) else body = ["list_item['body']", "&nbsp;&#x2192;&nbsp;"].join link_to(body, list_item['url'], :class => list_item['crumb']) end end def drominay_crumb_builder list_item = Hash.new list_item['body'] = "Drominay" list_item['url'] = "root" @crumb_list << list_item end def project_crumb_builder end end Why oh why am I getting this "expecting tASSOC" error? (And what is a tASSOC anyway?) steven-nobles-imac-200:drominay steven$ script/server => Booting Mongrel (use 'script/server webrick' to force WEBrick) => Rails 2.2.2 application starting on http://0.0.0.0:3000 => Call with -d to detach => Ctrl-C to shutdown server ** Starting Mongrel listening at 0.0.0.0:3000 ** Starting Rails with development environment... Exiting /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require': /Users/steven/Drominay/app/helpers/breadcrumbs_helper.rb:7: syntax error, unexpected ')', expecting tASSOC (SyntaxError) /Users/steven/Drominay/app/helpers/breadcrumbs_helper.rb:29: syntax error, unexpected $end, expecting kEND from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:153:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:521:in `new_constants_in' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:153:in `require' from /Users/steven/Drominay/app/helpers/application_helper.rb:5 from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:382:in `load_without_new_constant_marking' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:382:in `load_file' from /Library/Ruby/Gems/1.8/gems/activesupport-2.2.2/lib/active_support/dependencies.rb:521:in `new_constants_in' ... 56 levels... from /Users/steven/.gem/ruby/1.8/gems/rails-2.2.2/lib/commands/server.rb:49 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from script/server:3

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  • Rack middleware deadlock

    - by Joel
    I include this simple Rack Middleware in a Rails application: class Hello def initialize(app) @app = app end def call(env) [200, {"Content-Type" => "text/html"}, "Hello"] end end Plug it in inside environment.rb: ... Dir.glob("#{RAILS_ROOT}/lib/rack_middleware/*.rb").each do |file| require file end Rails::Initializer.run do |config| config.middleware.use Hello ... I'm using Rails 2.3.5, Webrick 1.3.1, ruby 1.8.7 When the application is started in production mode, everything works as expected - every request is intercepted by the Hello middleware, and "Hello" is returned. However, when run in development mode, the very first request works returning "Hello", but the next request hangs. Interrupting webrick while it is in the hung state yields this: ^C[2010-03-24 14:31:39] INFO going to shutdown ... deadlock 0xb6efbbc0: sleep:- - /usr/lib/ruby/gems/1.8/gems/actionpack-2.3.5/lib/action_controller/reloader.rb:31 deadlock 0xb7d1b1b0: sleep:J(0xb6efbbc0) (main) - /usr/lib/ruby/1.8/webrick/server.rb:113 Exiting /usr/lib/ruby/1.8/webrick/server.rb:113:in `join': Thread(0xb7d1b1b0): deadlock (fatal) from /usr/lib/ruby/1.8/webrick/server.rb:113:in `start' from /usr/lib/ruby/1.8/webrick/server.rb:113:in `each' from /usr/lib/ruby/1.8/webrick/server.rb:113:in `start' from /usr/lib/ruby/1.8/webrick/server.rb:23:in `start' from /usr/lib/ruby/1.8/webrick/server.rb:82:in `start' from /usr/lib/ruby/gems/1.8/gems/rack-1.0.1/lib/rack/handler/webrick.rb:14:in `run' from /usr/lib/ruby/gems/1.8/gems/rails-2.3.5/lib/commands/server.rb:111 from /usr/local/lib/site_ruby/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /usr/local/lib/site_ruby/1.8/rubygems/custom_require.rb:31:in `require' from script/server:3 Something to do with the class reloader in development mode. There is also mention of deadlock in the exception. Any ideas what might be causing this? Any recommendations as to the best approach to debug this?

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  • "You have already activated" message even when using bundle exec

    - by juanpastas
    I am installing gems in my Gemfile in shared path as Capistrano does by default, and when I run: bundle exec rake assets:precompile RAILS_ENV=production I get: You have already activated rake 0.9.2.2, but your Gemfile requires rake 10.0.4. Using bundle exec may solve this. See that: cat Gemfile.lock | grep rake returns: rake (>= 0.8.7) rake (10.0.4) This is my gem environment output: - RUBYGEMS VERSION: 1.8.24 - RUBY VERSION: 1.9.3 (2013-06-27 patchlevel 448) [x86_64-linux] - INSTALLATION DIRECTORY: /home/bitnami/my_app/shared/bundle/ruby/1.9.1/ - RUBY EXECUTABLE: /opt/bitnami/ruby/bin/ruby - EXECUTABLE DIRECTORY: /home/bitnami/my_app/shared/bundle/ruby/1.9.1/bin - RUBYGEMS PLATFORMS: - ruby - x86_64-linux - GEM PATHS: - /home/bitnami/my_app/shared/bundle/ruby/1.9.1/ - GEM CONFIGURATION: - :update_sources => true - :verbose => true - :benchmark => false - :backtrace => false - :bulk_threshold => 1000 - "gemhome" => "/home/bitnami/my_app/shared/bundle/ruby/1.9.1/" - "gempath" => ["/home/bitnami/my_app/shared/bundle/ruby/1.9.1/"] - REMOTE SOURCES: - http://rubygems.org/ Update which -a rake /opt/bitnami/rvm/bin/rake /opt/bitnami/ruby/bin/rake Update 2 I tried giving full path to rake, but same problem

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  • Imperative vs. component based programming [closed]

    - by AlexW
    I've been thinking about how programming and more specifically the teaching of programming is advocated amongst the community (online). Often I've heard that Ruby and RoR is an ideal platform for learning to program. I completely disagree... RoR and Ruby are based on the application of the component based paradigm, which means they are ideal for rapid application development. This is much like the MVC model in PHP and ASP.NET But, learning a proper imperative language like Java or C/C++ (or even Perl and PHP) is the only way for a new programmer to explore logic itself, and not get too bogged down in architectural concerns like the need for separation of concerns, and the preference for components. Maybe it's a personal preference thing. I rather think that the most interesting aspects to programming are the procedural bits of code I write that actually do stuff rather than the project planning, and modelling that comes about from fully object oriented engineering or simply using the MVC model. I know this may sound confused to some of you. I feel strongly though that the best way for programming to be taught is through imperative and procedural methods. Architectural (component) methods come later, if at all. After all, none of the amazing algorithms that exist were based on OOP practice! It's all procedural code when it comes to the 'magic'. OOP is useful in creating products and utilities. Algorithms are what makes things happen, and move data around, and so imperative (and/or procedural) code are what matters most. When I see programmers recommending Ruby on Rails to newbie developers, I think it's just so wrong. Just because you write less code with Ruby does not make it easier to do! It's the opposite... you have to know loads more to appreciate its succinct nature. New coders who really want to understand the nuts and bolts of coding need to go away and figure out writing methods/functions (i.e. imperative programming) and working in procedural style, in order to grasp the fundamentals, first, before looking into architectural ways of working. So, my question is: should Ruby ever be recommended as a first language? I think no (obviously)... what arguments are there for it?

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  • Script throwing unexpected operator when using mysqldump

    - by Astron
    A portion of a script I use to backup MySQL databases has stopped working correctly after upgrading a Debian box to 6.0 Squeeze. I have tested the backup code via CLI and it works fine. I believe it is in the selection of the databases before the backup occurs, possibly something to do with the $skipdb variable. If there is a better way to perform the function then I'm will to try something new. Any insight would be greatly appreciated. $ sudo ./script.sh [: 138: information_schema: unexpected operator [: 138: -1: unexpected operator [: 138: mysql: unexpected operator [: 138: -1: unexpected operator Using bash -x script here is one of the iterations: + for db in '$DBS' + skipdb=-1 + '[' test '!=' '' ']' + for i in '$IGGY' + '[' mysql == test ']' + : + '[' -1 == -1 ']' ++ /bin/date +%F + FILE=/backups/hostname.2011-03-20.mysql.mysql.tar.gz + '[' no = yes ']' + /usr/bin/mysqldump --single-transaction -u root -h localhost '-ppassword' mysql + /bin/tar -czvf /backups/hostname.2011-03-20.mysql.mysql.tar.gz mysql.sql mysql.sql + rm -f mysql.sql Here is the code. if [ $MYSQL_UP = "yes" ]; then echo "MySQL DUMP" >> /tmp/update.log echo "--------------------------------" >> /tmp/update.log DBS="$($MYSQL -u $MyUSER -h $MyHOST -p"$MyPASS" -Bse 'show databases')" for db in $DBS do skipdb=-1 if [ "$IGGY" != "" ] ; then for i in $IGGY do [ "$db" == "$i" ] && skipdb=1 || : done fi if [ "$skipdb" == "-1" ] ; then FILE="$DEST$HOST.`$DATE +"%F"`.$db.mysql.tar.gz" if [ $ENCRYPT = "yes" ]; then $MYSQLDUMP -u $MyUSER -h $MyHOST -p"$MyPASS" $db > $db.sql && $TAR -czvf - $db.sql | $OPENSSL enc -aes-256-cbc -salt -out $FILE.enc -k $ENC_PASS && rm -f $db.sql else $MYSQLDUMP --single-transaction -u $MyUSER -h $MyHOST -p"$MyPASS" $db > $db.sql && $TAR -czvf $FILE $db.sql && rm -f $db.sql fi fi done fi

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  • MySQL to PostreSQL and Named Scope

    - by Lowgain
    I've got a named scope for one of my models that works fine. The code is: named_scope :inbox_threads, lambda { |user| { :include => [:deletion_flags, :recipiences], :conditions => ["recipiences.user_id = ? AND deletion_flags.user_id IS NULL", user.id], :group => "msg_threads.id" }} This works fine on my local copy of the app with a MySQL database, but when I push my app to Heroku (which only uses PostgreSQL), I get the following error: ActiveRecord::StatementInvalid (PGError: ERROR: column "msg_threads.subject" must appear in the GROUP BY clause or be used in an aggregate function: SELECT "msg_threads"."id" AS t0_r0, "msg_threads"."subject" AS t0_r1, "msg_threads"."originator_id" AS t0_r2, "msg_thr eads"."created_at" AS t0_r3, "msg_threads"."updated_at" AS t0_r4, "msg_threads"."url_key" AS t0_r5, "deletion_flags"."id" AS t1_r0, "deletion_flags"."user_id" AS t1_r1, "deletion_flags"."msg_thread_id" AS t1_r2, "deletion_flags"."confirmed" AS t1_r3, "deletion_flags"."created_at" AS t1_r4, "deletion_flags"."updated_at" AS t1_r5, "recipiences"."id" AS t2_r0, "recipiences"."user_id" AS t2_r1, "recipiences"."msg_thread_id" AS t2_r2, "recipiences"."created_at" AS t2_r3, "recipien ces"."updated_at" AS t2_r4 FROM "msg_threads" LEFT OUTER JOIN "deletion_flags" ON deletion_flags.msg_thread_id = msg_threads.id LEFT OUTER JOIN "recipiences" ON recipiences.msg_thread_id = msg_threads.id WHERE (recipiences.user_id = 1 AND deletion_flags.user_id IS NULL) GROUP BY msg_threads.id) I'm not as familiar with the working of Postgres, so what would I need to add here to get this working? Thanks!

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  • sudo ./starling start works well but sudo service starling start fails

    - by Keating Wang
    sudo ./starling start works well but sudo service starling start fails $ sudo ./starling start * Starting Starling Server... [ OK ] $ sudo ./starling stop * Stop Starling Server... [ OK ] $ sudo service starling stop * Starting Starling Server... /home/keating/.rvm/rubies/ruby-1.9.2-p290/lib/ruby/site_ruby/1.9.1/rubygems/dependency.rb:247:in `to_specs': Could not find starling (>= 0) amongst [minitest-1.6.0, rake-0.8.7, rdoc-2.5.8] (Gem::LoadError) from /home/keating/.rvm/rubies/ruby-1.9.2-p290/lib/ruby/site_ruby/1.9.1/rubygems/dependency.rb:256:in `to_spec' from /home/keating/.rvm/rubies/ruby-1.9.2-p290/lib/ruby/site_ruby/1.9.1/rubygems.rb:1229:in `gem' from /home/keating/.rvm/gems/ruby-1.9.2-p290/bin/starling:18:in `<main>' The error above is 'cannot find gem starling' Following the starling file(located in /etc/init.d, rwxrwxrwx): set -e LOGFILE=/var/log/starling/starling.log SPOOLDIR=/var/spool/starling PORT=22122 LISTEN=127.0.0.1 PIDFILE=/var/run/starling.pid NAME=starling DESC="Starling" INSTALL_DIR=/home/keating/.rvm/gems/ruby-1.9.2-p290/bin/ DAEMON=$INSTALL_DIR/$NAME SCRIPTNAME=/etc/init.d/$NAME OPTS="-d" . /lib/lsb/init-functions d_start() { log_begin_msg "Starting Starling Server..." start-stop-daemon --start --quiet --pidfile $PIDFILE --exec $DAEMON -- $OPTS || log_end_msg 1 log_end_msg 0 } d_stop() { log_begin_msg "Stopping Starling Server..." start-stop-daemon --stop --quiet --pidfile $PIDFILE || log_end_msg 1 log_end_msg 0 } case "$1" in start) d_start ;; stop) d_stop ;; restart|force-reload|reload) d_stop sleep 2 d_start ;; *) echo "Usage: $SCRIPTNAME {start|stop|restart|force-reload}" exit 3 ;; esac exit 0

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  • Rails 3 passenger nginx application spawner server error on Synology NAS

    - by peresleguine
    Question updated, please read UPD2. I'm trying to deploy app through passenger nginx module on DS710+ (ruby 1.9.2p0 installed). There is syntax error relative to has_and_belongs_to_many_association.rb file. Please look at the screenshot(deleted, question updated). I'm pretty sure the problem isn't in library file. App is running good via webrick. Could you please advise what to look for? UPD1 ruby -v ruby 1.9.2p0 (2010-08-18 revision 29036) [i686-linux] gem list -d passenger *** LOCAL GEMS *** passenger (3.0.6) Author: Phusion - http://www.phusion.nl/ Rubyforge: http://rubyforge.org/projects/passenger Homepage: http://www.modrails.com/ Installed at: /usr/lib/ruby/gems/1.9.1 Easy and robust Ruby web application deployment UPD2 I've decided to reinstall everything. It solved previous problem but caused another one. The error is: The application spawner server exited unexpectedly: Unexpected end-of-file detected. Here is screenshot. New output: ruby -v ruby 1.9.2p180 (2011-02-18 revision 30909) [x86_64-linux] gem list -d passenger *** LOCAL GEMS *** passenger (3.0.7) Author: Phusion - http://www.phusion.nl/ Rubyforge: http://rubyforge.org/projects/passenger Homepage: http://www.modrails.com/ Installed at: /usr/lib/ruby/gems/1.9.1 Nginx error.log: [ pid=5653 thr=32771 file=ext/common/Watchdog.cpp:128 time=2011-04-20 14:08:34.505 ]: waitpid() on Phusion Passenger helper agent return -1 with errno = ECHILD, falling back to kill polling [ pid=5654 thr=49156 file=ext/common/Watchdog.cpp:128 time=2011-04-20 14:08:34.506 ]: waitpid() on Phusion Passenger logging agent return -1 with errno = ECHILD, falling back to kill polling 2011/04/20 14:12:33 [notice] 7614#0: signal process started

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  • Multiple Rails apps on same subdomain?

    - by Derek
    I recently decided to try out Rails. When working with PHP, I simply had all of my PHP projects in the same directory. For example, I may have http://ubuntu/app1, http://ubuntu/app2, etc. I created a subdomain for Rails (http://ruby.ubuntu), installed Rails and Passenger and everything is working. However, I may be wrong, but it looks like I can only have one Rails app per subdomain? My VirtualHost is as follows: <VirtualHost *:80> ServerName ruby.ubuntu ServerAdmin webmaster@localhost DocumentRoot /var/www/ruby/blog/public <Directory /var/www/ruby/blog/public> Options Indexes FollowSymLinks MultiViews AllowOverride All Order allow,deny allow from all RailsEnv development </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog ${APACHE_LOG_DIR}/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog ${APACHE_LOG_DIR}/access.log combined </VirtualHost> All of my PHP and misc. files are stored in /var/www/main. I want to be able to store all of my Rails apps in /var/www/ruby. I tried changing DocumentRoot to /var/www/ruby, but I don't think it's as simple as that. When I browse to a Rails app's Welcome Aboard page and click on "About my application's environment," I get a 404 page, but when the DocumentRoot is set to the public directory, I get the expected result. I don't want to have to create a new subdomain every time I create a new project. Is there any way I can make it so I can store all of my apps in /var/www/ruby, and browsing to http://ruby.ubuntu will let me access all of my Rails apps there? That way if I want to create a new app, all I have to do is rails new app, no Apache .htaccess or VirtualHost configuration required.

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  • Need help to debug application using .Net and MySQL

    - by Tim Murphy
    What advice can you give me on how to track down a bug I have while inserting data into MySQL database with .Net? The error message is: MySql.Data.MySqlClient.MySqlException: Duplicate entry '26012' for key 'StockNumber_Number_UNIQUE' Reviewing of the log proves that StockNumber_Number of 26012 has not been inserted yet. Products in use. Visual Studio 2008. mysql.data.dll 6.0.4.0. Windows 7 Ultimate 64 bit and Windows 2003 32 bit. Custom built ORM framework (have source code). Importing data from Access 2003 database. The code works fine for 3000 - 5000 imports. The record being imported that causes the problem in a full run works fine if just importing by itself. I've also seen the error on other records if I sort the data to be imported a different way. Have tried import with and without transactions. Have logged the hell out of the system. The SQL command to create the table: CREATE TABLE `RareItems_RareItems` ( `RareItemKey` CHAR(36) NOT NULL PRIMARY KEY, `StockNumber_Text` VARCHAR(7) NOT NULL, `StockNumber_Number` INT NOT NULL AUTO_INCREMENT, UNIQUE INDEX `StockNumber_Number_UNIQUE` (`StockNumber_Number` ASC), `OurPercentage` NUMERIC , `SellPrice` NUMERIC(19, 2) , `Author` VARCHAR(250) , `CatchWord` VARCHAR(250) , `Title` TEXT , `Publisher` VARCHAR(250) , `InternalNote` VARCHAR(250) , `DateOfPublishing` VARCHAR(250) , `ExternalNote` LONGTEXT , `Description` LONGTEXT , `Scrap` LONGTEXT , `SuppressionKey` CHAR(36) NOT NULL, `TypeKey` CHAR(36) NOT NULL, `CatalogueStatusKey` CHAR(36) NOT NULL, `CatalogueRevisedDate` DATETIME , `CatalogueRevisedByKey` CHAR(36) NOT NULL, `CatalogueToBeRevisedByKey` CHAR(36) NOT NULL, `DontInsure` BIT NOT NULL, `ExtraCosts` NUMERIC(19, 2) , `IsWebReady` BIT NOT NULL, `LocationKey` CHAR(36) NOT NULL, `LanguageKey` CHAR(36) NOT NULL, `CatalogueDescription` VARCHAR(250) , `PlacePublished` VARCHAR(250) , `ToDo` LONGTEXT , `Headline` VARCHAR(250) , `DepartmentKey` CHAR(36) NOT NULL, `Temp1` INT , `Temp2` INT , `Temp3` VARCHAR(250) , `Temp4` VARCHAR(250) , `InternetStatusKey` CHAR(36) NOT NULL, `InternetStatusInfo` LONGTEXT , `PurchaseKey` CHAR(36) NOT NULL, `ConsignmentKey` CHAR(36) , `IsSold` BIT NOT NULL, `RowCreated` DATETIME NOT NULL, `RowModified` DATETIME NOT NULL ); The SQL command and parameters to insert the record: INSERT INTO `RareItems_RareItems` (`RareItemKey`, `StockNumber_Text`, `StockNumber_Number`, `OurPercentage`, `SellPrice`, `Author`, `CatchWord`, `Title`, `Publisher`, `InternalNote`, `DateOfPublishing`, `ExternalNote`, `Description`, `Scrap`, `SuppressionKey`, `TypeKey`, `CatalogueStatusKey`, `CatalogueRevisedDate`, `CatalogueRevisedByKey`, `CatalogueToBeRevisedByKey`, `DontInsure`, `ExtraCosts`, `IsWebReady`, `LocationKey`, `LanguageKey`, `CatalogueDescription`, `PlacePublished`, `ToDo`, `Headline`, `DepartmentKey`, `Temp1`, `Temp2`, `Temp3`, `Temp4`, `InternetStatusKey`, `InternetStatusInfo`, `PurchaseKey`, `ConsignmentKey`, `IsSold`, `RowCreated`, `RowModified`) VALUES (@RareItemKey, @StockNumber_Text, @StockNumber_Number, @OurPercentage, @SellPrice, @Author, @CatchWord, @Title, @Publisher, @InternalNote, @DateOfPublishing, @ExternalNote, @Description, @Scrap, @SuppressionKey, @TypeKey, @CatalogueStatusKey, @CatalogueRevisedDate, @CatalogueRevisedByKey, @CatalogueToBeRevisedByKey, @DontInsure, @ExtraCosts, @IsWebReady, @LocationKey, @LanguageKey, @CatalogueDescription, @PlacePublished, @ToDo, @Headline, @DepartmentKey, @Temp1, @Temp2, @Temp3, @Temp4, @InternetStatusKey, @InternetStatusInfo, @PurchaseKey, @ConsignmentKey, @IsSold, @RowCreated, @RowModified) @RareItemKey = 0b625bd6-776d-43d6-9405-e97159d172a6 @StockNumber_Text = 199305 @StockNumber_Number = 26012 @OurPercentage = 22.5 @SellPrice = 1250 @Author = SPARRMAN, Anders. @CatchWord = COOK: SECOND VOYAGE @Title = A Voyage Round the World with Captain James Cook in H.M.S. Resolution… Introduction and notes by Owen Rutter, wood engravings by Peter Barker-Mill. @Publisher = @InternalNote = @DateOfPublishing = 1944 @ExternalNote = The first English translation of Sparrman’s narrative, which had originally been published in Sweden in 1802-1818, and the only complete version of his account to appear in English. The eighteenth-century translation had appeared some time before the Swedish publication of the final sections of his account. Sparrman’s observant and well-written narrative of the second voyage contains much that appears nowhere else, emphasising naturally his interests in medicine, health, and natural history.&lt;br&gt;&lt;br&gt;One of 350 numbered copies: a handsomely produced and beautifully illustrated work. @Description = Small folio, wood-engravings in the text; original olive glazed cloth, top edges gilt, a very good copy. London, Golden Cockerel Press, 1944. @Scrap = @SuppressionKey = 00000000-0000-0000-0000-000000000000 @TypeKey = 93f58155-7471-46ad-84c5-262ab9dd37e8 @CatalogueStatusKey = 00000000-0000-0000-0000-000000000003 @CatalogueRevisedDate = @CatalogueRevisedByKey = c4f6fc06-956d-44c4-b393-0d5462cbffec @CatalogueToBeRevisedByKey = 00000000-0000-0000-0000-000000000000 @DontInsure = False @ExtraCosts = @IsWebReady = False @LocationKey = 00000000-0000-0000-0000-000000000000 @LanguageKey = 00000000-0000-0000-0000-000000000000 @CatalogueDescription = @PlacePublished = Golden Cockerel Press @ToDo = @Headline = @DepartmentKey = 529578a3-9189-40de-b656-eef9039d00b8 @Temp1 = @Temp2 = @Temp3 = @Temp4 = v @InternetStatusKey = 00000000-0000-0000-0000-000000000000 @InternetStatusInfo = @PurchaseKey = 00000000-0000-0000-0000-000000000000 @ConsignmentKey = @IsSold = True @RowCreated = 8/04/2010 8:49:16 PM @RowModified = 8/04/2010 8:49:16 PM Suggestions on what is causing the error and/or how to track down what is causing the problem?

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  • MySQL access classes in PHP

    - by Mike
    I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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  • Has anyone ever successfully make index merge work for MySQL?

    - by user198729
    Setup: mysql> create table t(a integer unsigned,b integer unsigned); mysql> insert into t(a,b) values (1,2),(1,3),(2,4); mysql> create index i_t_a on t(a); mysql> create index i_t_b on t(b); mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 3 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Is there something I'm missing? Update mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 1863 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Version: mysql> select version(); +----------------------+ | version() | +----------------------+ | 5.1.36-community-log | +----------------------+ Has anyone ever successfully make index merge work for MySQL? I'll be glad to see successful stories here:)

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  • PHP & MySQL database storing the name Array problem.

    - by comma
    I'm new to PHP & MySQL and I keep getting the word Array stored in my MySQL tables fields $skill, $experience, $yearsI was wondering how can I fix this problem? And I know I need to add mysqli_real_escape_string which I left out to make code more easier to read Hopefully. Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; if (isset($_POST['skill'][0]) && trim($_POST['skill'][0])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { for ($s = 0; $s < count($skill); $s++){ for ($x = 0; $x < count($experience); $x++){ for ($g = 0; $g < count($years); $g++){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $s . "', '" . $x . "', '" . $g . "')"); $id = mysqli_insert_id($mysqli); if ($query1 == TRUE) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query2 = mysqli_query($mysqli,"INSERT INTO users_skills (skill_id, user_id) VALUES ('$id', '$user_id')"); } } } } } } } Here is the XHTML code. <li><label for="skill">Skill: </label><input type="text" name="skill[0]" id="skill[0]" /> <label for="experience">Experience: </label> <?php echo '<select id="experience[0]" name="experience[0]">' . "\n"; foreach($experience_options as $option) { if ($option == $experience) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> <label for="years">Years: </label> <?php echo '<select id="years[0]" name="years[0]">' . "\n"; foreach($grade_options as $option) { if ($option == $years) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li>

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  • What every beginner should know about website development? [closed]

    - by user975234
    I am a novice at building websites and considering to make one. But there is a lot of confusion that's going on right now. I guess every beginner faces them. Few questions that come up are: I have an idea and a need a website. That's all i know right now. But how do i start ? HTML is for sure the basic language but there are a hell of other technologies too. What is actually asp, php, ruby etc? How do i choose the right one from them? Other than asp, php there is javascript and other languages under the same belt. What are they used for? Hosting. When i am choosing the host, what considerations i have to keep in mind ? What support do i need from them (other than getting some important space obviously!). I am considering of making the website in ruby on rails. I don't know about php and what effect it would have if i choose ruby over php. I thought about ruby just because its new and i dont want to learn some thing "not new"! :P Moreover what is a framework and how does a framework effect my development process? These three questions are just to explain my "confusion" better. There is obviously a lot more to it. Just to try to answer how the flow of website development goes keeping in mind my questions!

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  • Trying to move away from PHP/Yii: RoR, Python/Django or ASP.NET MVC? Your opinions please [closed]

    - by Örs
    I have a CS degree and I've been working as a web developer (front & backend) for about 2 years now. I've been working with PHP mostly because it was easy to pick up and find a job, but I've grown to dislike the language and want to try something new, and possibly get a better paying job. That last point is especially important because in my area (Romania/Eastern Europe) PHP jobs are mostly for people fresh out of college/high school, hence the pay is rather low. I've been working with the Yii framework which, if I understand correctly, borrows a lot from Ruby on Rails (convention over configuration, MVC, Active Record, scaffolding). Other than PHP I only know curly-brace languages (C/C++/Java) and bash so Python/Ruby might be a bit challenging. On the other hand I've been using Linux (with vim and recently Sublime Text 2) for almost 4 years now so Windows and a lack of a terminal would have its downsides as well. I'm leaning towards Python/Ruby because of my *nix bias (plus both look like fun), but I've heard great things about ASP.NET MVC as well. Any suggestions? PS: I think there are more jobs in ASP.NET around here, but that's not necessarily a plus, because there are a lot of CS graduates as well. tl;dr: Romanian PHP/Yii developer trying to move to Python/Django or Ruby/Rails or C#/ASP.NET MVC. Suggestions?

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  • Creating dynamic plots

    - by geoff92
    I'm completely new to web programming but I do have a programming background. I'd like to create a site that allows users to visit, enter some specifications into a form, submit the form, and then receive a graph. I have a few questions about this, only because I'm pretty ignorant: Is there a good framework I should start in? I know a lot of java, I'm okay with python, and I learned Ruby in the past. I figure I might use ruby on rails only because I hear of it so often and I think I've also heard it's easy. If anyone has some other recommendation, please suggest. The user will be entering data into a form. I'm guessing the request they'll be making should be one of a GET request, right? Because I don't intend for any of the data they're entering to modify my server (in fact, I don't intend on having a database). The data the user inputs will be used to perform calculations involving lots of matrices. I've written this functionality in python. If I use ruby on rails, should it be instead written in Ruby? Somewhere I've heard that you can either place the load of the work on your server or on the client's computer. Since the code performs heavy math, which option is preferable? How do I alter the setup to either make the client do the work or my server? Should I be using a "cgi-bin"? In the code that I have now, I use matplotlib, a python library, and then "show" the plot in order to see the graph. I specify the x and y limits, but I am able to "drag" the graph in order to see more data within the plot window. Ultimately, I want a graph to be shown on my site with the drag functionality. Is this possible? What if the client drags the graph so far, more computations must be made? Thanks!

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