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  • Any way to create a hidden main window in C#?

    - by Bill
    I just want a c# application with a hidden main window that will process and respond to window messages. I can create a form without showing it, and can then call Application.Run() without passing in a form, but how can I hook the created form into the message loop? Is there another way to go about this? Thanks in advance for any tips!

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  • Using input type="submit" to change content

    - by Conti
    Okay, I'm pretty sure I'm missing something very obvious here, but I just couldn't find a proper solution so far. What I'm trying to do is simple: Have a user write something into a form, have him submit the form, and write that input into a textarea on the same page. This is my code: <html><head></head> <body> <form name='registration'> <label for="input">Input:</label> <input type="text" id="input"/> <input type="submit" id="submit" value="Submit" onclick="execute()"/> </form> <div id="results"> <span>Result</span> <span><textarea cols="30" rows="5" id="resulttext" readonly="readonly"></textarea> </span> </div> <script> function execute() { var result = document.getElementById("input").value document.getElementById("resulttext").value=result; } </script> </body> </html> Now what happens if I enter something into the form is that the textarea briefly shows my input before reverting back to showing nothing. My guess is that the textarea field is only changed for the duration of the execute() function. When I change input type="submit" to a <button> everything works as intended, but I'm pretty sure I'm not supposed to do that.

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  • iframe change event

    - by acidzombie24
    i have an iframe with a form that the user fills and submits. When the form is finished submitting i would like some js code using jquery to tell the main page (which holds this iframe) that the user has submitted the form. What event can i use to check this? i tried .change(function () without success

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  • more radio problems * sighs * been at this for one week now

    - by jeansymolanza
    hi guys really i don't know what im doing wrong... i am trying to process multiple radios with mysql. the first step has involved me echoing the results on the process page. each time i select any radio option it simply displays the first row result. this is that i see after trying to submit the form: Notifications Thank you. The notifications have been updated successfully. statusid: 14 notc2: 1 Return this is the code for the form: <div style="padding: 15px;"> <span class="loginfail" style="font-size:24px; font-weight: bold">Notifications</span><p> <?php include("progress_insertcomment.php"); ?> <?php // Make a MySQL Connection mysql_select_db("speedycm_data") or die(mysql_error()); $query_comment = "select * from tbl_alert order by id desc limit 1"; $comment = mysql_query($query_comment, $speedycms) or die(mysql_error()); $row_comment = mysql_fetch_assoc($comment); $totalRows_comment = mysql_num_rows($comment); ?> <!--- add notification ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <span id="sprytextarea1"> <textarea id='comment' name="comment" style="height: 75px; width:330px;"><?php echo $row_comment['comment']; ?></textarea> </span> <p> <button type="submit">Add</button> <input type="hidden" name="notc" value="1"/> </form> <!--- notification history ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <table border="0" cellspacing="2" cellpadding="2"> <?php if ( $row_comment == 0 ) { echo "<span style='font-size: 11px;'>No current alerts.</span>"; } else { // Get all the data from the "example" table $result = mysql_query("SELECT * FROM tbl_alert ORDER BY id DESC") or die(mysql_error()); while($rows=mysql_fetch_array($result)){ ?> <tr> <td> <?php echo "<div class='bubble'><div class='pimped'> <blockquote>" . $rows['comment'] . " </blockquote></div> <cite><strong>" . $rows['user'] . "</strong> @ " . $rows['date'] . "</cite> <span style='font-size: 10px;'> <p> <a href='editalert.php?id=". $rows['id'] ."' class='form' >Edit</a>&nbsp;&#8226;&nbsp;<a href='deletealert.php?id=". $rows['id'] ."' class='form'>Delete</a> </span> </div> "; ?> </td> <td valign="top" align="center"><div style="padding-left: 30px;"><span style="font-size: 10px;">Completed?</span> <p class="field switch"> <!--- determine status of notification ---> <?php $status = $rows['status']; $id = $rows['id']; ?> <input type="radio" name="selstatus[<?php echo $id; ?>]" value="no" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="radio" name="selstatus[<?php echo $id; ?>]" value="yes" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="hidden" name="statusid" value="<?php echo $id; ?>"/> <label for="radio1" class="cb-enable <?php if($status == 'yes') {echo 'selected';} else {echo '';} ?>"><span>Yes</span></label> <label for="radio2" class="cb-disable <?php if($status == 'no') {echo 'selected';} else {echo '';} ?>"><span>No</span></label> </p> </div></td> </tr> <tr> <td></td> <?php } } ?> <td align="center"><div style="padding-left: 30px;"> <button type="submit">Update</button> <input type="hidden" name="notc2" value="1"/> </div></td> </tr> </table> </form> </div> this is the code for the processing page: <?php // 6) update notifications if (array_key_exists('notc2',$_POST)) { $update = $_POST['selstatus']; echo "<p style='font-size: 12px;'>Thank you. The notifications have been updated successfully.<p>"; foreach($_POST as $key => $value){ echo $key . ': ' . $value . '<br>'; } echo "<p><span style='font-size: 12px;'> <a onClick=\"history.go(-1)\" class='form'>Return</a></p> <p></span> "; exit; }; ?> how do i resolve this problem? please any help would be appreciated. i would like to display the id and value of the selected checkbox on the processing page before inserting it into the table. thanking you in advance. GOD BLESS

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  • Check for state change in objects using serialization?

    - by sev7n
    I have a form that is bind to an object, and when the user trying to leave the form, I want to warn them if anything on the form has been changed, and prompt them to save. My question is, is there any way to achieve this without implementing IComparar for all my classes in the binded object? I was thinking if there is a way I can serialize my object when loading the form, and do a simple comparison against the change object that also get serialized. Something like a string comparison. Hope that make sense, Thanks

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  • Can Grails exceptionHandler support the following Error Handling Flow

    - by Andrew
    In my rails app that I am porting to grails whenever an unexpected error occurs I intercept the error automatically and display a form to the user informing them that an error has occured and asking them for further information. Meanwhile, as the form is rendered I write the stack trace and other information about who was logged in to a database table. Then if the form is submitted I add that information to the error report. I cannot tell from the exceptionHandler documentation and BootStrap examples whether that will allow me to grab all the information including various session and request parameters and then stuff them into a database and then post a form. Any thoughts?

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  • Specifying Struts templates source

    - by Chris
    Say I'm using a form with a text-field. <@s.form action="login" <@s.textfield label="E-mail" name="email"/ <@s.submit value="send"/ How can I specify that the text-form should be generated by a custom template (text_login.ftl) rather than the standard text.ftl?

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  • Jquery toggle with two elements

    - by Jesse
    I am using a toggle on a graphic to slide out a contact form. The problem is, the contact form can cover up the graphic element on low resolutions. I thought a solution would be to include a "close this" inside the form, that would use the same toggle effect. When I add the close this element to the code, instead of working in tandem with the original graphic element, it starts the chain back over, and slides the contact form even further out. Site is here: http://www.tritonloyaltysupport.com/status Code for toggle here: $(this).html(div_form); //show / hide function $('div.contactable').toggle( function() { $('#overlay').css({display: 'block'}); $('#contactForm').animate({"marginRight": "-=0px"}, "fast"); $('#contactForm').animate({"marginRight": "+=390px"}, "slow"); }, function() { $('#contactForm').animate({"marginRight": "-=390px"}, "slow"); $('#overlay').css({display: 'none'}); } );

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  • How to store data using core data in iphone?

    - by Warrior
    I am new to iphone development.I want to show a form a and store the contents in to a core data database after clicking the submit button.I have created a form.xcdatamodel and class events.h and events.m with reference to the apple docs.In some Sample codes the values are stored statically in the delegate class and they use core data delegate methods. But in my case the form view come after passing 2 views. I want to store the data entered here .How can i achieve it.Please help me out.Thanks.

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  • Loop results executing twice

    - by ozzysmith
    I creating a simple site with PHP where the users can submit blogs and other users (who are logged in) can post comments on them. I have made a link called "comments" below each blog that when clicked will show / hide all the comments relevant to the specific blog (also if the user is logged in, it will show a form field in which they can submit new comments). So basically each blog will have multiple comments. I have done two different codes for this but they both have the same problem that each comment appears twice (everything else works fine). Could anyone point out why? mysql_select_db ("ooze"); $result = mysql_query ("select * from blog") or die(mysql_error()); $i = 1; while($row = mysql_fetch_array($result)) { echo "<h1>$row[title]</h1>"; echo "<p class ='second'>$row[blog_content]</p> "; echo "<p class='meta'>Posted by .... &nbsp;&bull;&nbsp; $row[date] &nbsp;&bull;&nbsp; <a href='#' onclick=\"toggle_visibility('something$i'); return false\">Comments</a><div id='something$i' style='display: none;'>"; $i++; $a = $row["ID"]; $result2 = mysql_query ("select * from blog, blogcomment where $a=blogID") or die(mysql_error()); while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username]</p><p>said:</p> <p>$sub[comment]</p>"; } if ( isset ($_SESSION["gatekeeper"])) { echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn); //second version of inner loop:// if ( isset ($_SESSION["gatekeeper"])) { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn);

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  • mdi child forms slow to draw when visibility changed

    - by dandan78
    My application has the following UI configuration: The main form is an MDI container. Its child forms are attached to a tabstrip. Each user has his set of child forms. Depending on the active user, only that user's child forms are displayed, together with tabs. This is achieved by going through the main form's MdiChildren and setting their Visible property to false/true depending on the active user. This has two undesired effects. One is that every child form gets redrawn in succession, which is ugly and slow. The other is that for some reason the forms go from maximized to normal, effectively undocking them from the main form. Is there any way to display just one of the child forms, such as the one the user was previously looking at, and get the others to stay in the background? The maximize/normal thing is not that big a deal because I can maximize them again manually.

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  • JqueryUI serialize data not working on first record

    - by peace
    I am using jqueryUI v1.8. I have created a modal dialog form to edit records of a table. When the edit link on the record is clicked the record data is displayed on the form and the user edits the record. When the user submits this form the data is serialized and posted via ajax to update the database. This works well with all records except the first one. Nothing is posted to server for update only for the first record. alert(serializeddata); is empty. Similarly, The first form element in every record chosen for editing does not show the actual value the first time. Once you cancel editing and close the dialog and reopen you can see the fields accurate data. How do I resolve this?

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  • why my website not ranking in first page of google? [on hold]

    - by India SEO Analyst
    Iam handling website www.usamovingandstorage.com and targeting keywords "chicago movers", but my website is on third page. But my website has nice backlink, and recently i removed irrelevant backlinks also. I compared my competitors' websites such as www.ampolmoving.com, www.chicagomovers.com and have no such big backlinks, but they are ranking first page in google. I compared the three websites in www.opensiteexplorer.org. In that my site has good results. Then How is it happened? I need full comparison, why my site is ranking in third page? what are the actions i need to take to rank in first page.

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  • PHP: How to forward on $_FILES using cURL

    - by Toby
    Hi. I'm trying to use cURL to forward on a http request from a form in a web application I'm developing. Essentially I need to submit the same form twice on different servers, for the second server I'm adding some security measures to the post data. I can receive $_POST information on the second form perfectly fine, however I'm having major troubles with my $_FILES - I've tried separating the two so there's a separate request for post and files data but still no luck. Is this possible?

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  • Muliple Models in a single django ModelForm?

    - by BigJason
    Is it possible to have multiple models included in a single ModelForm in django? I am trying to create a profile edit form. So I need to include some fields from the User model and the UserProfile model. Currently I am using 2 forms like this class UserEditForm(ModelForm): class Meta: model = User fields = ("first_name", "last_name") class UserProfileForm(ModelForm): class Meta: model = UserProfile fields = ("middle_name", "home_phone", "work_phone", "cell_phone") Is there a way to consolidate these into one form or do I just need to create a form and handle the db loading and saving myself?

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  • Firefox handles xxx.submit(), Safari doesn't ... what can be done?

    - by Prairiedogg
    I'm trying to make a pull down menu post a form when the user selects (releases the mouse) on one of the options from the menu. This code works fine in FF but Safari, for some reason, doesn't submit the form. I re-wrote the code using jquery to see if jquery's .submit() implementation handled the browser quirks better. Same result, works in FF doesn't work in safari. The following snippets are from the same page, which has some django template language mixed in. Here's the vanilla js attempt: function formSubmit(lang) { if (lang != '{{ LANGUAGE_CODE }}') { document.getElementById("setlang_form").submit(); } } Here's the jquery attempt: $(document).ready(function() { $('#lang_submit').hide() $('#setlang_form option').mouseup(function () { if ($(this).attr('value') != '{{ LANGUAGE_CODE }}') { $('#setlang_form').submit() } }); }); and here's the form: <form id="setlang_form" method="post" action="{% url django.views.i18n.set_language %}"> <fieldset> <select name="language"> {% for lang in interface_languages %} <option value="{{ lang.code }}" onmouseup="formSubmit('{{ lang.name }}')" {% ifequal lang.code LANGUAGE_CODE %}selected="selected"{% endifequal %}>{{ lang.name }}</option> {% endfor %} </select> </fieldset> </form> My question is, how can I get this working in Safari?

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  • Poplate html drop down box

    - by csU
    how do you populate a drop down html box within a form, but populate it with values from a php array for example <form name="mname" action="index.php" method="post"> <select name='values'> <option> </option> <option> </option> </form> i can do it by echoing it out, thus not needing the form, but i really need to get at the value i am echoing in the drop down box later, so was hoping someone could show me how it can be done like this, using php

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  • Processing forms that generate many rows in DB

    - by Zack
    I'm wondering what the best approach to take here is. I've got a form that people use to register for a class and a lot of times the manager of a company will register multiple people for the class at the same time. Presently, they'd have to go through the registration process multiple times and resubmit the form once for every person they want to register. What I want to do is give the user a form that has a single <input/> for one person to register with, along with all the other fields they'll need to fill out (Email, phone number, etc); if they want to add more people, they'll be able to press a button and a new <input/> will be generated. This part I know how to do, but I'm including it to best describe what I'm aiming to do. The part I don't know how to approach is processing that data the form submits, I need some way of making a new row in the Registrant table for every <input/> that's added and include the same contact information (phone, email, etc) as the first row with that row. For the record, I'm using the Django framework for my back-end code. What's the best approach here? Should it just POST the form x times for x people, or is there a less "brute force" way of handling this?

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  • how to swap array-elements to transfer the array from a column-like into a row-like representation

    - by Christian Ammer
    For example: the array a1, a2, a3, b1, b2, b3, c1, c2, c3, d1, d2, d3 represents following table a1, b1, c1, d1 a2, b2, c2, d2 a3, b3, c3, d3 now i like to bring the array into following form a1, b1, c1, d1, a2, b2, c2, d2, a3, b3, c3, d3 Does an algorithm exist, which takes the array (from the first form) and the dimensions of the table as input arguments and which transfers the array into the second form? I thougt of an algorithm which doesn't need to allocate additional memory, instead i think it should be possible to do the job with element-swap operations.

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  • Trying to created a tabled layout won't work with CSS

    - by ct2k7
    Hello, I'm trying to recreate a sort of table layout of a contact form. Here's the current form: http://www.radonsystems.net/contact-us and this is what the work-in-progress is like http://www.radonsystems.net/newsite/?do=contact-us As you can see, there is an issue with the second form - I just don't know how to fix it. Any ideas on what I'm doing wrong? The style (CSS) for that part, is nearly 100% copied over, only that I've changed the font, but kept within same family.

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  • Think this is a naming problem

    - by RussP
    Must be really dumb today - sorry in advance; anyhow have this unordered list <ul> <li><div class="openuserform" >Info</div> <div class="userform"></div></li> <li><div class="openuserform" >Appearence</div> <div class="userform"></div></li> <li><div class="openuserform" >Pages</div> <div class="userform"></div></li> <li><div class="openuserform" >Services</div> <div class="userform"></div></li> <li><div class="openuserform" >Community</div> <div class="userform"></div></li> </ul> which on click <div class="openuserform" > I want to load a separate form e.g. $('.openusersform').live('click',(function(){ $('.userform').load('form page.php'); }); OK I can get the forms to load in the right div using $(this).next('.userform').show(); $('.userform').load('form page.php'); but it's very ugly (I think) and I can only every get the first form to process propery. It is laid out like (ul,li etc.) this so I can have each loaded form aligned under the relevant li. But I think there has to be a better way as I do not seem to get any if(){} stemnents working to process the forms i.e. if(form1){ $.ajax etc } if (form2) {more ajax} Suggestions please - thanks

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  • Can I change properties of inherited controls at design time?

    - by Jeff Stock
    I am using visual inheritance and was wondering if there is a way to change the properties of inherited controls at design time, preferably in the form designer. If not, then in the designer code. I have my control declared as Public in the base class. I can access it in the child form code, but not in the form designer. Is this just not possible?

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  • How to save/export a DOM element to an image?

    - by Don Don
    Hi, I have a web page which has a form element (with its ID known) and inside the form there are multiple DIVs, and the position of each div may be changed. What I'd like to do is: a) Save the current state of this form // var currentForm=document.forms['myFrm'].innerHTML; would probably suffice... b) Save or export the entire form with the most current position of each DIV to an image file. // how to save/export the javascript var of currentForm to an image file is the key question. Any help/pointer would be appreciated.

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