How to add XmlInclude attribute dynamically
- by Anindya Chatterjee
I have the following classes
[XmlRoot]
public class AList
{
public List<B> ListOfBs {get; set;}
}
public class B
{
public string BaseProperty {get; set;}
}
public class C : B
{
public string SomeProperty {get; set;}
}
public class Main
{
public static void Main(string[] args)
{
var aList = new AList();
aList.ListOfBs = new List<B>();
var c = new C { BaseProperty = "Base", SomeProperty = "Some" };
aList.ListOfBs.Add(c);
var type = typeof (AList);
var serializer = new XmlSerializer(type);
TextWriter w = new StringWriter();
serializer.Serialize(w, aList);
}
}
Now when I try to run the code I got an InvalidOperationException at last line saying that
The type XmlTest.C was not expected. Use the XmlInclude or SoapInclude attribute to specify types that are not known statically.
I know that adding a [XmlInclude(typeof(C))] attribute with [XmlRoot] would solve the problem. But I want to achieve it dynamically. Because in my project class C is not known prior to loading. Class C is being loaded as a plugin, so it is not possible for me to add XmlInclude attribute there.
I tried also with
TypeDescriptor.AddAttributes(typeof(AList), new[] { new XmlIncludeAttribute(c.GetType()) });
before
var type = typeof (AList);
but no use. It is still giving the same exception.
Does any one have any idea on how to achieve it?
