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  • Efficient algorithm to find a maximum common subset of two sets?

    - by datasunny
    Each set contains bunch of checksums. For example: Set A: { 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f 07736dde2f8484a4a3af463e05f039e3 5b1e374ff2ba949ab49870ca24d3163a } Set B: { 6639e1da308fd7b04b7635a17450df7c 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f } The maximum common subset of A and B is: { 4445968d0e100ad08323df8c895cea15 a67f8052594d6ba3f75502c0b91b868f } A lot of this operations will be performed, so I'm looking for an efficient algorithm to do so. Thanks for your help.

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  • how to specify in xml schema that either one of two fields must be present?

    - by matti
    i want to specify that either fieldname or freetext is always present in xml files that apply to xsd. is there a way to define it? <xs:complexType name="tSome"> <xs:sequence> <!-- either of 2 below have 2 be present. --> <xs:element name="fieldname" type="xs:string" minOccurs="0" /> <xs:element name="freetext" type="xs:string" minOccurs="0" /> <xs:element name="dbtablename" type="xs:string" minOccurs="0" /> </xs:sequence> </xs:complexType> thanks & best regards: Matti

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  • Why doesn't a URL Route with two dashes resolve?

    - by Atomiton
    I'm trying to resolve this URL Route: Route articlesByCategory = new Route("articles/c{cid}-{category}", new Handler); However, it seems like the following url won't resolve to this route: // doesn't work www.site.com/articles/c24-this-is-the-category-title // This works www.site.com/articles/c24-category I assume it has to do with the dashes in the title, but can anyone tell me why this works this way? Is there a way to allow dashes in the title for a URL route like this?

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  • Why doesn't a URL with two hyphens ( in one segment ) match a Route in my Route Table?

    - by Atomiton
    I'm trying to resolve this URL Route: Route articlesByCategory = new Route("articles/c{cid}-{category}", new Handler); However, it seems like the following url won't resolve to this route: // doesn't work www.site.com/articles/c24-this-is-the-category-title // This works www.site.com/articles/c24-category I assume it has to do with the dashes in the title, but can anyone tell me why this works this way? Is there a way to allow dashes in the title for a URL route like this?

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  • How to get resultset with stored procedure calls over two linked servers?

    - by räph
    I have problems filling a temporary table with the resultset from a procedure call on a linked server, in which again a procedure on another server is called. I have a Stored Procedure sproc1 with the following code, which calls another procedure sproc2 on a linked server. SET @sqlCommand = 'INSERT INTO #tblTemp ( ModuleID, ParamID) ' + '( SELECT * FROM OPENQUERY(' + @targetServer + ', ' + '''SET FMTONLY OFF; EXEC ' + @targetDB + '.usr.sproc2 ' + @param + ''' ) )' exec ( @sqlCommand ) Now in the called sproc2 I again call a third procedure sproc3 on another linked server, which returns my resultset. SET @sqlCommand = 'EXEC ' + @targetServer +'.database.usr.sproc3 ' + @param exec ( @sqlCommand ) The whole thing doen't work, as I get an SQL error 7391 The operation could not be performed because OLE DB provider "%ls" for linked server "%ls" was unable to begin a distributed transaction. I already checked the hints at this microsoft article, but without success. But maybe, I can change the code in sproc1. Would there be some alternative to the temp table and the open query? Just calling stored procedures from server A to B to C and returning the resultset is working (I do this often in the application). But this special case with the temp table and openquery doesn't work! Or is it just not possible what I am trying to do? The microsft article states: Check the object you refer on the destination server. If it is a view or a stored procedure, or causes an execution of a trigger, check whether it implicitly references another server. If so, the third server is the source of the problem. Run the query directly on the third server. If you cannot run the query directly on the third server, the problem is not actually with the linked server query. Resolve the underlying problem first. Is this my case? PS: I can't avoid the architecture with the three servers.

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  • Why do I get two clicked or released signals when using a custom slot for a QPushButton ?

    - by Chris
    here's the main code at first I thought is was the message box but setting a label instead has the same effect. #include <time.h> #include "ui_mainwindow.h" #include <QMessageBox> class MainWindow : public QWidget, private Ui::MainWindow { Q_OBJECT public: MainWindow(QWidget *parent = 0); void makeSum(void); private: int r1; int r2; private slots: void on_pushButton_released(void); }; MainWindow::MainWindow(QWidget *parent) : QWidget(parent) { setupUi(this); } void MainWindow::on_pushButton_released(void) { bool ok; int a = lineEdit->text().toInt(&ok, 10); if (ok) { if (r1+r2==a) { QMessageBox::information( this, "Sums","Correct!" ); } else { QMessageBox::information( this, "Sums","Wrong!" ); } } else { QMessageBox::information( this, "Sums","You need to enter a number" ); } makeSum(); } void MainWindow::makeSum(void) { r1 = rand() % 10 + 1; r2 = rand() % 10 + 1; label->setText(QString::number(r1)); label_3->setText(QString::number(r2)); } int main(int argc, char *argv[]) { srand ( time(NULL) ); QApplication app(argc, argv); MainWindow mw; mw.makeSum(); mw.show(); return app.exec(); } #include "main.moc"

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  • How to insert into two different tables in one statement with Java and MySQL?

    - by MalcomTucker
    I am using Java, Spring (NamedParameterJdbcTemplate) and MySQL. My statement looks like this: INSERT INTO Table1 (Name) VALUES (?); INSERT INTO Table2 (Path, Table1Id) VALUES (?, LAST_INSERT_ID()) But it is throwing the following error: PreparedStatementCallback; bad SQL grammar [INSERT INTO Table1 (Name) VALUES (?); INSERT INTO Table2 (Path, Table1Id) VALUES (?, LAST_INSERT_ID())] ` Nested exception is: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO Table2 (Path, Table1Id' at line 1 The syntax works fine in MySQL but something is up when combining via the Spring template. Thanks!

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  • Is it possible to bind data asynchronously between two dropdownlists in a view?

    - by user252160
    I'd like to achieve the following effect using ASP.NET MVC and JQuery. I've got a drop down list displaying a list of Countries. I want to make it so that when I change the value of the country, a new drop down list appears below it, showing a list of companies whose country of origin is the particular selected company. The thing is that I do not want to rely too much on controller actions because I'm using it in a Template Helper which is a "headless" view. Can I bind it somehow?

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  • Connecting to TFS from iPhone

    - by Andrei
    Hi. I'm building this iPhone application to connect to a secured TFS server (one that requires authentication before letting you access its web services). When I access this server in a browser, the first thing it will do is ask me for credentials (username/password) and then connect me to the TFS server if those credentials are correct. I am using web services, as I don't think there is any other way to use TFS functionality for an outside platform...without changing stuff on the TFS host machine. So my questions are: Are there any web services that can be accessed to log into the TFS server? This authentication mechanism seems to be something common among multiple websites (I have seen it in other websites). Is there a way to replicate that authentication mechanism by sending an HTTP request? Is there a way to replicate this authentication procedure in any way? Thanks!

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  • Remote desktop in XP?

    - by vineth
    hi, I have enabled remote desktop in my xp sp3 system, (My problem) if my friend take my system in remote with out my authentication my system is connected to him.but few day before i get authentication message(attached in the below link) but nowadays i am not receiving this dialog box... please provide help to get this authentication dialog box.. Link : http://www.freeimagehosting.net/image.php?f9f04c5e0a.jpg Thanks in advance

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  • How do I update an xml file with msbuild with two namespaces?

    - by c3rin
    This msbuild below task can take into account one namespace, but in the case where I'm updating an mxml (flex) that has a mix of namespaces, can I use this task or another msbuild task to do the update? <XmlUpdate Prefix="fx" Namespace="http://ns.adobe.com/mxml/2009" XmlFileName="myFlexApp.mxml" Xpath="//mx:Application/fx:Declarations/fx:String[@id='stringId']" Value="xxxxx"> Here is the flex xml I'm trying to update: <mx:Application xmlns:fx="http://ns.adobe.com/mxml/2009" xmlns:mx="library://ns.adobe.com/flex/mx" xmlns:s="library://ns.adobe.com/flex/spark"> <fx:Declarations> <fx:String id="stringId">UPDATE_ME</fx:String> </fx:Declarations></mx:Application>

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  • Regex to extract a string between two delimeters WITHOUT also returning the delimeters?

    - by CSharp Noob
    Hello, I want to just extract the text between the brackets -- NOT the brackets, too! My code looks currently like this: var source = "Harley, J. Jesse Dead Game (2009) [Guard]" // Extract role with regex m = Regex.Match(source, @"[(.*)]"); var role = m.Groups[0].Value; // role is now "[Guard]" role = role.Substring(1, role.Length-2); // role is now "Guard" Can you help me to simplify this to just a single regex, instead of the regex, then the substring?

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  • Should I use two queries, or is there a way to JOIN this in MySQL/PHP?

    - by Jack W-H
    Morning y'all! Basically, I'm using a table to store my main data - called 'Code' - a table called 'Tags' to store the tags for each code entry, and a table called 'code_tags' to intersect it. There's also a table called 'users' which stores information about the users who submitted each bit of code. On my homepage, I want 5 results returned from the database. Each returned result needs to list the code's title, summary, and then fetch the author's firstname based on the ID of the person who submitted it. I've managed to achieve this much so far (woot!). My problem lies when I try to collect all the tags as well. At the moment this is a pretty big query and it's scaring me a little. Here's my problematic query: SELECT code.*, code_tags.*, tags.*, users.firstname AS authorname, users.id AS authorid FROM code, code_tags, tags, users WHERE users.id = code.author AND code_tags.code_id = code.id AND tags.id = code_tags.tag_id ORDER BY date DESC LIMIT 0, 5 What it returns is correct looking data, but several repeated rows for each tag. So for example if a Code entry has 3 tags, it will return an identical row 3 times - except in each of the three returned rows, the tag changes. Does that make sense? How would I go about changing this? Thanks! Jack

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  • How do I pass a string or data object between two view controllers?

    - by Jonathan
    In my last question i asked how to best send a string from one view controller to another, both which were on a navigation stack: http://stackoverflow.com/questions/2898860/pass-string-from-tableviewcontroller-to-viewcontroller-in-navigation-stack However I just realised I can either pass the path to the file in the app's document's folder as the first (the table view) has already accessed the data in the file should I pass viewcontroller the data to the pushed VC?

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  • Proguard and two projects using the same android library. broadcasting. ClassNotFoundException

    - by trololo
    The problem:I have got 2 apps. The interact with each other via broadcasting. I have parcelable class in the android library (they send content of class in the library). So after using Proguard I have got ClassNotFondException. How to solve it? 07-03 02:13:51.832: E/AndroidRuntime(6801): FATAL EXCEPTION: main 07-03 02:13:51.832: E/AndroidRuntime(6801): java.lang.RuntimeException: Unable to start receiver <appname>.<name>.ar.free.BRMain: java.lang.RuntimeException: Parcelable encounteredClassNotFoundException reading a Serializable object (name = <appname>.a.a.b) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.app.ActivityThread.handleReceiver(ActivityThread.java:2277) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.app.ActivityThread.access$1500(ActivityThread.java:140) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1303) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.os.Handler.dispatchMessage(Handler.java:99) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.os.Looper.loop(Looper.java:137) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.app.ActivityThread.main(ActivityThread.java:4898) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.lang.reflect.Method.invokeNative(Native Method) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.lang.reflect.Method.invoke(Method.java:511) 07-03 02:13:51.832: E/AndroidRuntime(6801): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1006) 07-03 02:13:51.832: E/AndroidRuntime(6801): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:773) 07-03 02:13:51.832: E/AndroidRuntime(6801): at dalvik.system.NativeStart.main(Native Method) 07-03 02:13:51.832: E/AndroidRuntime(6801): Caused by: java.lang.RuntimeException: Parcelable encounteredClassNotFoundException reading a Serializable object (name = <appname>.a.a.b) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.os.Parcel.readSerializable(Parcel.java:2148) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.os.Parcel.readValue(Parcel.java:2016) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.os.Parcel.readMapInternal(Parcel.java:2226) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.os.Bundle.unparcel(Bundle.java:223) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.os.Bundle.getInt(Bundle.java:922) 07-03 02:13:51.832: E/AndroidRuntime(6801): at <appname>.<name>.ar.free.BRMain.onReceive(BRMain.java:35) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.app.ActivityThread.handleReceiver(ActivityThread.java:2270) 07-03 02:13:51.832: E/AndroidRuntime(6801): ... 10 more 07-03 02:13:51.832: E/AndroidRuntime(6801): Caused by: java.lang.ClassNotFoundException: <appname>.a.a.b 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.lang.Class.classForName(Native Method) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.lang.Class.forName(Class.java:217) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.io.ObjectInputStream.resolveClass(ObjectInputStream.java:2301) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.io.ObjectInputStream.readNewClassDesc(ObjectInputStream.java:1660) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.io.ObjectInputStream.readClassDesc(ObjectInputStream.java:683) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.io.ObjectInputStream.readNewObject(ObjectInputStream.java:1803) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.io.ObjectInputStream.readNonPrimitiveContent(ObjectInputStream.java:787) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.io.ObjectInputStream.readObject(ObjectInputStream.java:2003) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.io.ObjectInputStream.readObject(ObjectInputStream.java:1960) 07-03 02:13:51.832: E/AndroidRuntime(6801): at android.os.Parcel.readSerializable(Parcel.java:2142) 07-03 02:13:51.832: E/AndroidRuntime(6801): ... 16 more 07-03 02:13:51.832: E/AndroidRuntime(6801): Caused by: java.lang.NoClassDefFoundError: <appname>/a/a/b 07-03 02:13:51.832: E/AndroidRuntime(6801): ... 26 more 07-03 02:13:51.832: E/AndroidRuntime(6801): Caused by: java.lang.ClassNotFoundException: <appname>.a.a.b 07-03 02:13:51.832: E/AndroidRuntime(6801): at dalvik.system.BaseDexClassLoader.findClass(BaseDexClassLoader.java:61) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.lang.ClassLoader.loadClass(ClassLoader.java:501) 07-03 02:13:51.832: E/AndroidRuntime(6801): at java.lang.ClassLoader.loadClass(ClassLoader.java:461) 07-03 02:13:51.832: E/AndroidRuntime(6801): ... 26 more

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  • How to make the height of two side-by-side elements extend to the remaining browser height?

    - by LedZeppelin
    In this example, http://jsfiddle.net/mnXH9/, the height of the content-display element and the height of the nav-menu-container are fixed. How do I make the height of the content-display and nav-menu-container elements extend to the remaining height of the browser window as the browser height is being adjusted by a user provided the height in the browser window is greater than 400px (The height of the header plus the nav-menu-container)? I would like for the scrollbar to be inside the nav-menu-content element if the total height in the browser is greater than the sum of the height of the header (100px) and the nav-menu-container element (300px). If the browser window's height is less than 400px then a scrollbar would appear in the browser window to allow scrolling throughout the 100px header and the 300px min-height of the below elements. EDIT Attached are photoshopped mockups of what the jsfiddle should look like. tab 1 when the browser height is less than 400px tab 1 when the browser height is greater than 400px tab 2 when the browser height is less than 400px tab 2 when the browser height is greater than 400px

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  • How do I join two git repos without a common root, where all modified files are the same?

    - by Evan Carroll
    I have a git-cpan-init of a repo which yielded a different root node from another already established git repo I found on github C:A:S:DBI. I've developed quite a bit on my repo, and I'd like to merge or replay my edits on a fork of the more authoritative repository. Does anyone know how to do this? I think it is safe to assume none of the file-contents of the modified files are different -- the code base hasn't been since Nov 08'. For clarity the git hub repo is the authoritative one. My local repo is the one I want to go up to git hub shown as a real git fork.

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  • What kind of storage with two-way replication for multi site C# application?

    - by twk
    Hi I have a web-based system written using asp.net backed by mssql. A synchronized replica of this system is to be run on mobile locations and must be available regardless of the state of the connection to the main system (few hours long interruptions happens). For now I am using a copy of the main web application and a copy of the mssql server with merge replication to the main system. This works unreliably, and setting the replication is a pain. The amount of data the system contains is not huge, so I can migrate to different storage type. For the new version of this system I would like to implement a new replication system. I am considering migration to db4o for storage with it's replication support. I am thinking about other possible solutions like couchdb which had native replication support. I would like to stay with C#. Could you recommend a way to go for such a distributed environment? PS. Master-Slave replication is not an option: any side must be allowed to add/update data.

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  • Can I join two tables whereby the joined table is sorted by a certain column?

    - by Ferdy
    I'm not much of a database guru so I need some help on a query I'm working on. In my photo community project I want to richly visualize tags by not only showing the tag name and counter (# of images inside them), I also want to show a thumb of the most popular image inside the tag (most karma). The table setup is as follow: Image table holds basic image metadata, important is the karma field Imagefile table holds multiple entries per image, one for each format Tag table holds tag definitions Tag_map table maps tags to images In my usual trial and error query authoring I have come this far: SELECT * FROM (SELECT tag.name, tag.id, COUNT(tag_map.tag_id) as cnt FROM tag INNER JOIN tag_map ON (tag.id = tag_map.tag_id) INNER JOIN image ON tag_map.image_id = image.id INNER JOIN imagefile on image.id = imagefile.image_id WHERE imagefile.type = 'smallthumb' GROUP BY tag.name ORDER BY cnt DESC) as T1 WHERE cnt > 0 ORDER BY cnt DESC [column clause of inner query snipped for the sake of simplicity] This query gives me somewhat what I need. The outer query makes sure that only tags are returned for which there is at least 1 image. The inner query returns the tag details, such as its name, count (# of images) and the thumb. In addition, I can sort the inner query as I want (by most images, alphabetically, most recent, etc) So far so good. The problem however is that this query does not match the most popular image (most karma) of the tag, it seems to always take the most recent one in the tag. How can I make sure that the most popular image is matched with the tag?

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  • When I'm iterating over two arrays at once, which one do I use as the limit?

    - by Martijn Courteaux
    Hi, I'm always struggling with something like the following Java example: String breads[] = {"Brown", "White", "Sandwich"}; int count[] = new int[breads.length]; for (int i = 0; i < ****; i++) { // Prompt the number of breads } ****: which array.length should I choose? I can choose between breads.length and count.length I know it would be the same result, but I don't know which one I shoud choose. There are many other examples where I get the same problem. I'm sure that you have encountered this problem as well in the past. What should you choose? Are there general agreements? Thanks

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