Search Results

Search found 34638 results on 1386 pages for 'linear linked list'.

Page 24/1386 | < Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >

  • searching a list of tuples in python

    - by hdx
    So I have a list of tuple like: [(1,"juca"),(22,"james"),(53,"xuxa"),(44,"delicia")] I want this list for a tuple whose number value is equal to something. So that if I do search(53) it will return 2 Is is an easy way to do that?

    Read the article

  • Java - Adding a Node in a doubly-linked list.

    - by jacobnlsn
    Hi, I am working on some code were I need to add a Node into a doubly linked-list, this is the code I have so far: Node tempNext = cursor.getNext(); temp = new Node(item, null, cursor, tempNext); tempNext.setPrev(temp); cursor is the Node that is right before the new added Node should go.

    Read the article

  • Remove duplicates from a list

    - by Mercer
    Hello i want to remove duplicates from a list i do this but not working List<Customer> listCustomer = new ArrayList<Customer>(); for (Customer customer: tmpListCustomer) { if (!listCustomer.contains(customer)) { listCustomer.add(customer); } }

    Read the article

  • Erlang : flattening a list of strings

    - by ErJab
    I have a list like this: [["str1","str2"],["str3","str4"],["str5","str6"]] And I need to convert it to ["str1", "str2", "str3", "str4", "str5", "str6"] How do I do this? The problem is that I'm dealing with lists of strings, so when I do lists:flatten([["str1","str2"],["str3","str4"],["str5","str6"]]) I get "str1str2str3str4str5str6" However, if the elements of the original list where just atoms, then lists:flatten would have given me what I needed. How do I achieve the same with strings?

    Read the article

  • Sikuli List of Functions & Operators

    - by PPTim
    Hello, I've just discovered Sikuli, and would like to see a comprehensive functions list without digging through the online-examples and demos. Has anyone found such a list? Furthermore, apparently Sikuli supports more complex loops and function calls as well, and seems to be based in Python(!!). Examples would be great. Thanks.

    Read the article

  • has any simply way to delete a value in list of python

    - by zjm1126
    a=[1,2,3,4] b=a.index(6) del a[b] print a it show error: Traceback (most recent call last): File "D:\zjm_code\a.py", line 6, in <module> b=a.index(6) ValueError: list.index(x): x not in list so i have to do this : a=[1,2,3,4] try: b=a.index(6) del a[b] except: pass print a but this is not simple,has any simply way ? thanks

    Read the article

  • RegEx to reverse order of list?

    - by quantomcat
    Is there a singular regular expression that can be used in, say, a text editor's search/replace dialog to reverse the order of the items in a list? For instance, take this list: First item Second item Third item Select it in a text editor like EditPad, bring up the search and replace box, apply a regex (run as a loop or not) and turn it into: Third item Second item First item Can this be done?

    Read the article

  • asp.net mvc2 - update list of objects

    - by ile
    I want to display list of objects from database, and on the same page have option to edit them. When submitting, I'd like to submit changes to all of them. I found this link: http://haacked.com/archive/2008/10/23/model-binding-to-a-list.aspx and http://www.hanselman.com/blog/ASPNETWireFormatForModelBindingToArraysListsCollectionsDictionaries.aspx but there is no description how to handle posted data in controller. Thanks in advance!

    Read the article

  • Ensuring the contacts in a Distribution List are displayed with both name and email address

    - by hawbsl
    How can I ensure the contacts I add to an Outlook distribution list are displayed with both name and email address? These contacts may not exist in any other address book, just the distribution list. Currently they show up just as an email address (in both columns). Here's roughly the VBA we're using: Do Until RS.EOF //here's where we want to inject RS!FirstName, RS!Surname etc objRecipients.Add RS!Email objRecipients.Resolve RS.MoveNext Loop Set objDistList = contactsFolder.Items.Add("IPM.DistList") objDistList.DLName = "Whatever" objDistList.AddMembers objRecipients objDistList.Save etc

    Read the article

  • c# array vs generic list

    - by L G
    Hi, i basically want to know the differences or advantages in using a generic list instead of an array in the below mentioned scenario Class Employee { private _empName; Public EmpName { get{return _empName;} set{_empName = value;} } } 1. Employee[] emp 2. List<Employee> emp can anyone please tell me the advantages or disadvaatges and which one to prefer

    Read the article

  • Query a SharePoint List from InfoPath web form in code

    - by dawsonweb
    I'm writing an InfoPath web form, using C# code behind. The form is a holiday request, after the user inputs the start and end dates I want the code to query a bank-holiday sharepoint list and count occurrences between the dates. I've added the sharepoint list as a second datasource however I'm now stuck. Any ideas?

    Read the article

  • How to determine whether a linked list contains a loop?

    - by ET
    During a preparation for a job interview, I encountered the following question: How can you determine whether a linked list (of any type) contains a loop, using additional space complexity of O(1)? You cannot assume that the loop starts at the first node (and of course, the loop doesn't have to contain all nodes). I couldn't find the answer, though I have the feeling it's quite simple...

    Read the article

  • Returning all "positions" of a list

    - by Daymor
    I Have a list with "a" and "b" and the "b"'s are somewhat of a path and "a"'s are walls. Im writing a program to make a graph of all the possible moves. I got the code running to check the first "b" for possible moves, but i have NO Idea how im going to find all "b"'s , even less check them all without repeating. Major issue im having is getting the tuple coordinates of the "b"'s out of the list. Any pointers/tips?

    Read the article

  • Convert list of dicts to string

    - by John
    I'm very new to Python, so forgive me if this is easier than it seems to me. I'm being presented with a list of dicts as follows: [{'directMember': 'true', 'memberType': 'User', 'memberId': '[email protected]'}, {'directMember': 'true', 'memberType': 'User', 'memberId': '[email protected]'}, {'directMember': 'true', 'memberType': 'User', 'memberId': '[email protected]'}] I would like to generate a simple string of memberIds, such as [email protected], [email protected], [email protected] but every method of converting a list to a string that I have tried fails because dicts are involved. Any advice?

    Read the article

  • Linked Measure Groups and Local Dimensions

    - by ekoner
    Mulling over something I've been reading up on. According to Chris Webb, A linked measure group can only be used with dimensions from the same database as the source measure group. So I took this to mean as long as two cubes share a database, a linked measure group can be used with a dimension. So I created a new cube and added a local measure group, a local dimension and a linked measure group. However, I can't create a relationship between the linked measure group and the local dimension even though they are within the same database. I get the message below: Regular relationships in the current database between non-linked (local) dimensions and linked measure groups cannot be edited. These relationship can only be created through the wizard. This dialog can be used to delete these relationships. I see that I can go to the original cube and add the dimension there, but does the message below mean I have an alternative? I just know it's going to be something simple and trivial! Thanks for reading.

    Read the article

  • How can I merge two lists and sort them working in 'linear' time?

    - by Sergio Tapia
    I have this, and it works: # E. Given two lists sorted in increasing order, create and return a merged # list of all the elements in sorted order. You may modify the passed in lists. # Ideally, the solution should work in "linear" time, making a single # pass of both lists. def linear_merge(list1, list2): finalList = [] for item in list1: finalList.append(item) for item in list2: finalList.append(item) finalList.sort() return finalList # +++your code here+++ return But, I'd really like to learn this stuff well. :) What does 'linear' time mean?

    Read the article

  • Using MVP, how to create a view from another view, linked with the same model object

    - by Dinaiz
    Background We use the Model-View-Presenter design pattern along with the abstract factory pattern and the "signal/slot" pattern in our application, to fullfill 2 main requirements Enhance testability (very lightweight GUI, every action can be simulated in unit tests) Make the "view" totally independant from the rest, so we can change the actual view implementation, without changing anything else In order to do so our code is divided in 4 layers : Core : which holds the model Presenter : which manages interactions between the view interfaces (see bellow) and the core View Interfaces : they define the signals and slots for a View, but not the implementation Views : the actual implementation of the views When the presenter creates or deals with views, it uses an abstract factory and only knows about the view interfaces. It does the signal/slot binding between views interfaces. It doesn't care about the actual implementation. In the "views" layer, we have a concrete factory which deals with implementations. The signal/slot mechanism is implemented using a custom framework built upon boost::function. Really, what we have is something like that : http://martinfowler.com/eaaDev/PassiveScreen.html Everything works fine. The problem However, there's a problem I don't know how to solve. Let's take for example a very simple drag and drop example. I have two ContainersViews (ContainerView1, ContainerView2). ContainerView1 has an ItemView1. I drag the ItemView1 from ContainerView1 to ContainerView2. ContainerView2 must create an ItemView2, of a different type, but which "points" to the same model object as ItemView1. So the ContainerView2 gets a callback called for the drop action with ItemView1 as a parameter. It calls ContainerPresenterB passing it ItemViewB In this case we are only dealing with views. In MVP-PV, views aren't supposed to know anything about the presenter nor the model, right ? How can I create the ItemView2 from the ItemView1, not knowing which model object is ItemView1 representing ? I thought about adding an "itemId" to every view, this id being the id of the core object the view represents. So in pseudo code, ContainerPresenter2 would do something like itemView2=abstractWidgetFactory.createItemView2(); this.add(itemView2,itemView1.getCoreObjectId()) I don't get too much into details. That just work. The problem I have here is that those itemIds are just like pointers. And pointers can be dangling. Imagine that by mistake, I delete itemView1, and this deletes coreObject1. The itemView2 will have a coreObjectId which represents an invalid coreObject. Isn't there a more elegant and "bulletproof" solution ? Even though I never did ObjectiveC or macOSX programming, I couldn't help but notice that our framework is very similar to Cocoa framework. How do they deal with this kind of problem ? Couldn't find more in-depth information about that on google. If someone could shed some light on this. I hope this question isn't too confusing ...

    Read the article

< Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >