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  • XSL Template - reducing replication

    - by Chris
    Hey Sorry about the extremely vague question title (any suggestions for improvements welcome) I have an XSL document that, currently, has lots of replication that I want to reduce. Here is the following XML snippet I am working with <Unit Status="alive"> I am currently using the following XSL to show images based on the status of the Unit <xsl:choose> <xsl:when test="@Status = 'alive'"> <img src="/web/resources/graphics/accept.png" /> </xsl:when> <xsl:when test="@Status = 'missingUnit'"> <img src="/web/resources/graphics/error.png" /> </xsl:when> <xsl:when test="@Status = 'missingNode'"> <img src="/web/resources/graphics/exclamation.png" /> </xsl:when> <xsl:when test="@Status = 'unexpectedUnit'"> <img src="/web/resources/graphics/exclamation_blue.png" /> </xsl:when> <xsl:otherwise> <!-- Should never get here --> <img src="/web/resources/graphics/delete.png" /> </xsl:otherwise> </xsl:choose> How do I put this code in a template or stylesheet that will allow me to stop copying / pasting this everywhere. Thanks

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  • Count end points in XML using XSL

    - by Chris
    I want to be able to count "end points" in an XML file using XSL. By endpoint I mean tag's with no children that contain data. i.e. <xmlsnippet> <tag1>NOTENOUGHDAYS</tag1> <tag2>INVALIDINPUTS</tag2> <tag3> <tag4> <tag5>2</tag5> <tag6>1</tag6> </tag4> </tag3> </xmlsnippet> This XML should return 4 as there are 4 "end points"

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  • Filtering most out of XML with XSL?

    - by Gnudiff
    I need to transform a lot of XML files (Fedora export) into a different kind of XML. Trying to do it with XSL stylesheets and checking with the msxsl transformer. Supposedly I have xml file like this (assuming there are actually other nodes inside AAA, OBJ, amd all other nodes), Source.XML: <DOC> <AAA> <STUFF>example</STUFF> <OBJ> <OBJVERS id="A1" CREATED="2008-02-18T13:28:08.245Z"/> <OBJVERS id="A2" CREATED="2008-02-19T10:42:41.965Z"/> <OBJVERS id="A13" CREATED="2009-03-16T12:43:11.703Z"/> </OBJ> </AAA> <FFF/> <GGG/> <DDD> <FILE /> </DDD> </DOC> Which I need to look something like this (Target.XML): <MYOBJ> <ELEM>contents of OBJVERS with the biggest id OR creation date (whichever is easier to do) go here</ELEM> <IMAGE> contents of <FILE> node go here</IMAGE> </MYOBJ> The main problem that I have is that since I am new to XSL (and for this particular task do not have enough time to learn it properly) is that I can't understand how to tell XSL processor not to process anything else, I keep getting output from , for example. Update: basically, I solved this problem meanwhile. I will post my own answer and close the question. Update2: OK, Andrew's answer works, too, so I am just accepting it. :)

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  • xsl : getting specific node values from a table

    - by prashant rao
    My XML Code <DBE:Attribute name="Test1" type="Table"> <DBE:Table> <DBE:TableHeader> <DBE:TableColumn>t1</DBE:TableColumn> <DBE:TableColumn>t2</DBE:TableColumn> <DBE:TableColumn>t3</DBE:TableColumn> <DBE:TableColumn>t4</DBE:TableColumn> <DBE:TableColumn>t5</DBE:TableColumn> <DBE:TableColumn>t6</DBE:TableColumn> <DBE:TableColumn>t7</DBE:TableColumn> <DBE:TableColumn>t8</DBE:TableColumn> <DBE:TableColumn>t9</DBE:TableColumn> <DBE:TableColumn>t10</DBE:TableColumn> <DBE:TableColumn>t11</DBE:TableColumn> <DBE:TableColumn>t12</DBE:TableColumn> <DBE:TableColumn>t13</DBE:TableColumn> </DBE:TableHeader> <DBE:TableRow> <DBE:TableData>0300 </DBE:TableData> <DBE:TableData/> <DBE:TableData>25</DBE:TableData> <DBE:TableData>25</DBE:TableData> <DBE:TableData>2009/09/03</DBE:TableData> <DBE:TableData/> <DBE:TableData>BAG</DBE:TableData> <DBE:TableData>rrr</DBE:TableData> <DBE:TableData>Yes</DBE:TableData> <DBE:TableData>12</DBE:TableData> <DBE:TableData>2009/03/09</DBE:TableData> <DBE:TableData>GO</DBE:TableData> <DBE:TableData/> </DBE:TableRow> </DBE:Table> </DBE:Attribute> I would like my output to be - t7 t5 t1 t13 --> Header --------------------------------------------------------------- BAG 2009/09/03 0300 GO --> ROW1 .............................................................. --> ROW2 and so on My XSL code -- (for only selected values to be displayed) <xsl:for-each select="DBE:Attribute[@name='Test1']/DBE:Table/DBE:TableRow"> <tr bgcolor="white"> <xsl:for-each select="DBE:TableData"> <td> <xsl:value-of select="node()|*"> </xsl:value-of> </td> </xsl:for-each> </tr> </xsl:for-each>

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  • DotNetNuke + XPath = Custom navigation menu DNNMenu HTML render

    - by Rui Santos
    I'm developing a skin for DotNetNuke 5 using the Component DNN Done Right menu by Mark Alan which uses XSL-T to convert the XML sitemap into an HTML navigation. The XML sitemap outputs the following structure: <Root > <root > <node id="40" text="Home" url="http://localhost/dnn/Home.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="0" > <node id="58" text="Child1" url="http://localhost/dnn/Home/Child1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="1" > <keywords >Child1</keywords> <description >Child1</description> <node id="59" text="Child1 SubItem1" url="http://localhost/dnn/Home/Child1/Child1SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child1 SubItem1</keywords> <description >Child1 SubItem1</description> </node> <node id="60" text="Child1 SubItem2" url="http://localhost/dnn/Home/Child1/Child1SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="0" only="0" depth="2" > <keywords >Child1 SubItem2</keywords> <description >Child1 SubItem2</description> </node> <node id="61" text="Child1 SubItem3" url="http://localhost/dnn/Home/Child1/Child1SubItem3.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child1 SubItem3</keywords> <description >Child1 SubItem3</description> </node> </node> <node id="65" text="Child2" url="http://localhost/dnn/Home/Child2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="1" > <keywords >Child2</keywords> <description >Child2</description> <node id="66" text="Child2 SubItem1" url="http://localhost/dnn/Home/Child2/Child2SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child2 SubItem1</keywords> <description >Child2 SubItem1</description> </node> <node id="67" text="Child2 SubItem2" url="http://localhost/dnn/Home/Child2/Child2SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child2 SubItem2</keywords> <description >Child2 SubItem2</description> </node> </node> </node> </root> </Root> My Goal is to render this XML block into this HTML Navigation structure only using UL's LI's, etc.. <ul id="topnav"> <li> <a href="#" class="home">Home</a> <!-- Parent Node - Depth0 --> <div class="sub"> <ul> <li><h2><a href="#">Child1</a></h2></li> <!-- Parent Node 1 - Depth1 --> <li><a href="#">Child1 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem2</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem3</a></li ><!-- ChildNode - Depth2 --> </ul> <ul> <li><h2><a href="#">Child2</a></h2></li> <!-- Parent Node 2 - Depth1 --> <li><a href="#">Child2 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child2 SubItem2</a></li> <!-- ChildNode - Depth2 --> </ul> </div> </li> </ul> Can anyone help with the XSL coding? I'm just starting now with XSL..

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  • In xpath why can I use greater-than symbol > but not less-than <

    - by runrunraygun
    Using c#3 compiled transforms the following seems to work just fine... <xsl:choose> <xsl:when test="$valA > $valB"> <xsl:value-of select="$maxUnder" /> </xsl:when> <xsl:when test="$valA &lt; $valC"> <xsl:value-of select="$maxOver" /> </xsl:when> </xsl:choose> However if i dare use a < in place of &lt; it gives an error... <xsl:choose> <xsl:when test="$valA > $valB"> <xsl:value-of select="$maxUnder" /> </xsl:when> <xsl:when test="$valA < $valC"> <xsl:value-of select="$maxOver" /> </xsl:when> </xsl:choose> System.Xml.XmlException: '<', hexadecimal value 0x3C, is an invalid attribute character. So why is > ok and not < ?

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  • MOSS ItemStyle.xsl parameter

    - by nav
    Hi, I am trying feed the site URL as a path into HTML rendered by the ItemStyle.xsl. Could anyone please give me some pointers? I need to know how I can extract the site URL from ItemStyle.xsl. Many Thanks, Nav

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  • How do I prevent duplicates, in XSL?

    - by LOlliffe
    How do I prevent duplicate entries into a list, and then ideally, sort that list? What I'm doing, is when information at one level is missing, taking the information from a level below it, to building the missing list, in the level above. Currently, I have XML similar to this: <c03 id="ref6488" level="file"> <did> <unittitle>Clinic Building</unittitle> <unitdate era="ce" calendar="gregorian">1947</unitdate> </did> <c04 id="ref34582" level="file"> <did> <container label="Box" type="Box">156</container> <container label="Folder" type="Folder">3</container> </did> </c04> <c04 id="ref6540" level="file"> <did> <container label="Box" type="Box">156</container> <unittitle>Contact prints</unittitle> </did> </c04> <c04 id="ref6606" level="file"> <did> <container label="Box" type="Box">154</container> <unittitle>Negatives</unittitle> </did> </c04> </c03> I then apply the following XSL: <xsl:template match="c03/did"> <xsl:choose> <xsl:when test="not(container)"> <did> <!-- If no c03 container item is found, look in the c04 level for one --> <xsl:if test="../c04/did/container"> <!-- If a c04 container item is found, use the info to build a c03 version --> <!-- Skip c03 container item, if still no c04 items found --> <container label="Box" type="Box"> <!-- Build container list --> <!-- Test for more than one item, and if so, list them, --> <!-- separated by commas and a space --> <xsl:for-each select="../c04/did"> <xsl:if test="position() &gt; 1">, </xsl:if> <xsl:value-of select="container"/> </xsl:for-each> </container> </did> </xsl:when> <!-- If there is a c03 container item(s), list it normally --> <xsl:otherwise> <xsl:copy-of select="."/> </xsl:otherwise> </xsl:choose> </xsl:template> But I'm getting the "container" result of <container label="Box" type="Box">156, 156, 154</container> when what I want is <container label="Box" type="Box">154, 156</container> Below is the full result that I'm trying to get: <c03 id="ref6488" level="file"> <did> <container label="Box" type="Box">154, 156</container> <unittitle>Clinic Building</unittitle> <unitdate era="ce" calendar="gregorian">1947</unitdate> </did> <c04 id="ref34582" level="file"> <did> <container label="Box" type="Box">156</container> <container label="Folder" type="Folder">3</container> </did> </c04> <c04 id="ref6540" level="file"> <did> <container label="Box" type="Box">156</container> <unittitle>Contact prints</unittitle> </did> </c04> <c04 id="ref6606" level="file"> <did> <container label="Box" type="Box">154</container> <unittitle>Negatives</unittitle> </did> </c04> </c03> Thanks in advance for any help!

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  • Why does this XSL fails to retrieve value from xml ?

    - by Pavitar
    Following is an extract of the XSL stylesheet that I have written. It says my '.xsl' is well formed but it somehow does not retrieve values from the xml,instead jus pastes the header and table headings. EDIT <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:template match="/" > <html> <head> <title>GlenMark Pharma</title> </head> <h1 align="center"><font face="Monotype Corsiva" color="red">GlenMarkPharma</font></h1> <body> <table> <tbody> <tr> <th>ID</th> <th>ENAME</th> <th>Mobile</th> <th>EMAIL</th> <th>PWD</th> </tr> <xsl:for-each select="employees/employee"> <tr> <td><xsl:value-of select="@empID" /></td> <td><xsl:value-of select="name" /></td> <td><xsl:value-of select="mobile" /></td> <td><xsl:value-of select="email" /></td> <td><xsl:value-of select="pwd" /></td> </tr> </xsl:for-each> </tbody> </table> </body> </html> </xsl:template> </xsl:stylesheet> Here is my XML doc: <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="MyfirstXsl.xsl"?> <!DOCTYPE employees SYSTEM "Mydtd.dtd"> <me:employees xmlns:me="[email protected]" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="[email protected] Mycomplex.xsd"> <me:employee empID="EMP101"> <me:name>Vicky</me:name> <me:mobile>9870582356</me:mobile> <me:email>[email protected]</me:email> <me:pwd>&defPWD;</me:pwd> </me:employee> </me:employees> I have also tried writing: <xsl:for-each select="employees/employee"> <tr> <td><xsl:value-of select="@empID" /></td> <td><xsl:value-of select="me:name" /></td> in the XSL since I have an alias to the namespace in my XML Doc.But it gives me an error of Invalid Pre-fix.I don't know what I'm doing wrong.

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  • move xsl sibling node inside parent?

    - by user288929
    How can I get from this: <Include xmlns="http://schemas.microsoft.com/wix/2006/wi"> <Component Feature="toplevel"> <File Id="fil8A88F8B155E29670FCA1B83F0E99E635" /> <TypeLib Id="{DC88F377-25DD-49C8-99D9-1FD8AE484362}" > <Interface Id="{5D12ED70-0B5A-49C4-A8A3-FC4C209295BA}" /> <Interface Id="{73E8EDB7-4293-496D-8ABD-F973F002A033}" /> </TypeLib> <TypeLib Id="{F3C9A192-17C2-4E25-ADB9-89FFEEC0403E}"> <Interface Id="{89FF44C6-979D-49B6-AF56-EC9509001DE4}" /> </TypeLib> </Component> </Include> to this: <Include xmlns="http://schemas.microsoft.com/wix/2006/wi"> <Component Feature="toplevel"> <File Id="fil8A88F8B155E29670FCA1B83F0E99E635" > <TypeLib Id="{DC88F377-25DD-49C8-99D9-1FD8AE484362}" > <Interface Id="{5D12ED70-0B5A-49C4-A8A3-FC4C209295BA}" /> <Interface Id="{73E8EDB7-4293-496D-8ABD-F973F002A033}" /> </TypeLib> <TypeLib Id="{F3C9A192-17C2-4E25-ADB9-89FFEEC0403E}"> <Interface Id="{89FF44C6-979D-49B6-AF56-EC9509001DE4}" /> </TypeLib> </File> </Component> </Include> (move <TypeLib>s inside <File>...) Thanks,

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  • Display different xsl:attribute depending on the ending of a string

    - by Johann
    Dear All, I have the following xsl code in an xsl document <A target="_blank" style="text-decoration=none"> <xsl:attribute name="href">viewdoc.aspx?doc=<xsl:value-of select="URLFilePath"/>&amp;mode=inline</xsl:attribute> <xsl:attribute name="prefix"><xsl:value-of select="FileName"/>: </xsl:attribute> <IMG src="images/word_small.gif" border="0"/> </A> and in the code-behind I am doing this newItemNode = xmlDocument.CreateElement("URLFilePath") newItemNode.InnerText = correctedPath xmlItemNode.ParentNode.AppendChild(newItemNode) Now that works fine for word documents. However I need a way in code to check the extension of the file, and display the correct Image and xsl:attribute depending on the If statement. So the If statement will be like this:- If correctedPath.ToLower.Contains(".doc") Then //display the word icon and attributes Else //display the excel icon and attributes End If Can you please give me some tips and help on how I can achieve this? Thanks

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  • how to get child nodes in xsl

    - by ppp
    here my code- <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="ArrayOfLinkEntity" name="bindLink"> <ul> <xsl:for-each select="LinkEntity[ParentLinkId=0]"> <li> <xsl:variable name="linkId" select="LinkId"/> <xsl:variable name="child" select="count(/ArrayOfLinkEntity/LinkEntity[ParentLinkId=$linkId])"/> <xsl:value-of select="$child"/> <xsl:choose> <xsl:when test="($child &gt; 0)"> <a href="#" data-flexmenu="flexmenu1" onclick="javascript:setPageLinkId({$linkId});"> <xsl:value-of select="LinkTitle"/> <img src="../images/down.gif" border="0"/> </a> </xsl:when> <xsl:otherwise > <a href="#" onclick="javascript:setPageLinkId({$linkId});"> <xsl:value-of select="LinkTitle"/> </a> </xsl:otherwise> </xsl:choose> </li> </xsl:for-each> </ul> </xsl:template> </xsl:stylesheet> but I am getting $child=0 always.but there exists children. my xml structure- <ArrayOfLinkEntity xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <LinkEntity> <EntityId>00000000-0000-0000-0000-000000000000</EntityId> <LinkId>1</LinkId> <SequenceNo>1</SequenceNo> <ParentLinkId>0</ParentLinkId> <LinkTitle>Home</LinkTitle> <SubLink /> </LinkEntity> ... </ArrayOfLinkEntity> What should I do? Please suggest.

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  • XSL: Get variable data without exslt:node-set

    - by Louis W
    Using native XSL lib in PHP. Is it possible to get a node value inside a variable without having to call it through exslt:node-set every time.... it long and ugly. <xsl:variable name="mydata"> <foo>1</foo> <bar>2</bar> </xsl:variable> <!-- How currently being done --> <xsl:value-of select="exslt:node-set($mydata)/foo" /> <!-- I want to be able to do this --> <xsl:value-of select="$mydata/foo" />

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  • XSL: Dead or not dead

    - by Seattle Leonard
    I'm currently taking on a new project at home. In this project I'm going to be generating HTML emails. For this purpose, I believe XSL to be a good candidate. However, I have heard people say that XSL is a dead language, and if it's not that it is on it's way out. In fact, MS has been very leary to support XSL 2.0. Personally I feel that any time you are going from text to text, it is a great tool. Such as: Generating HTML e-mails Creating Open Office Docs Generating another XML doc What are your thoughts? Is it dead, or is it still a viable, usefull tool?

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  • xsl:variable contains nodeset. How to output nth node of variable?

    - by dnagirl
    I am transforming an XML document. There is an attribute @prettydate that is a string similar to "Friday, May 7, 2010". I want to split that string and add links to the month and the year. I am using the exslt:strings module and I can add any other necessary EXSLT module. This is my code so far: <xsl:template match="//calendar"> <xsl:variable name="prettyparts"> <xsl:value-of select="str:split(@prettydate,', ')"/> </xsl:variable> <table class='day'> <thead> <caption><xsl:value-of select="$prettyparts[1]"/>, <a> <xsl:attribute name='href'><xsl:value-of select="$baseref"/>?date=<xsl:value-of select="@highlight"/>&amp;per=m</xsl:attribute> <xsl:value-of select='$prettyparts[2]'/> </a> <xsl:value-of select='$prettyparts[3]'/>, <a> <xsl:attribute name='href'><xsl:value-of select="$baseref"/>?date=<xsl:value-of select="@highlight"/>&amp;per=y</xsl:attribute> <xsl:value-of select='$prettyparts[4]'/> </a> </caption> <!--etcetera--> I have verified, by running $prettyparts through a <xml:for-each/> that I am getting the expected nodeset: <token>Friday</token> <token>May</token> <token>7</token> <token>2010</token> But no matter which way I attempt to refer to a particular <token> directly (not in a foreach) I get nothing or various errors to do with invalid types. Here's some of the syntax I've tried: <xsl:value-of select="$prettyparts[2]"/> <xsl:value-of select="$prettyparts/token[2]"/> <xsl:value-of select="exsl:node-set($prettyparts/token[2])"/> <xsl:value-of select="exsl:node-set($prettyparts/token)[2]"/> Any idea what the expression ought to be?

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  • How to sort an XML file by date in XLST

    - by AdRock
    I am trying to sort by date and get an error message about the stylesheet can't be loaded I found an answer on how others have suggested but it doesn't work for me Here is where it is supposed to sort. The commented out line is where the sort should occur <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template name="hoo" match="/"> <html> <head> <title>Registered Festival Organisers and Festivals</title> <link rel="stylesheet" type="text/css" href="userfestival.css" /> </head> <body> <h1>Registered Festival Organisers and Festivals</h1> <xsl:for-each select="folktask/member"> <xsl:if test="user/account/userlevel='3'"> <!--<xsl:sort select="concat(substring(festival/event/datefrom,1,4),substring(festival/event/datefrom, 6,2),substring(festival/event/datefrom, 9,2))" data-type="number" order="ascending"/>--> Sample node from XML <festival id="1"> <event> <eventname>Oxford Folk Festival</eventname> <url>http://www.oxfordfolkfestival.com/</url> <datefrom>2010-04-07</datefrom> <dateto>2010-04-09</dateto> <location>Oxford</location> <eventpostcode>OX1 9BE</eventpostcode> <coords> <lat>51.735640</lat> <lng>-1.276136</lng> </coords> </event> </festival>

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  • need help transforming an XML file, whose part of it is with escape sequences, into html

    - by shlomi
    hello, i need help transforming the following XML <?xml-stylesheet type=text/xsl href=XSL_17.xsl?> <Root> <Book> <Author>John smith</Author> <Genre>Novel</Genre> <Details>&lt;?xml version="1.0" encoding="utf-16"?&gt;&lt;Dets&gt;&lt;Ds&gt;&lt;D DN="Pages" DV="381" /&gt;&lt;D DN="Binding" DV="Hardcover" /&gt;&lt;D DN="Rate" DV="7.8" /&gt;&lt;/Ds&gt;&lt;/Dets&gt;</Details> </Book> <Car> <Year>2010</Year> <Name>Charger</Name> <Manufacturer>Dodge</Manufacturer> </Car> </Root> to the following HTML <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> </head> <body> <table> <tr> <td><strong>Book</strong></td> </tr> <tr> <td><strong>Name</strong></td> <td><strong>Value</strong></td> </tr> <tr> <td>Author</td> <td>John smith</td> </tr> <tr> <td>Genre</td> <td>Novel</td> </tr> <tr> <td>Details</td> <td> <table> <tr> <td><strong>Name</strong></td> <td><strong>Value</strong></td> </tr> <tr> <td>Pages</td> <td>381</td> </tr> <tr> <td>Binding</td> <td>Hardcover</td> </tr> <tr> <td>Rate</td> <td>7.8</td> </tr> </table> </td> </tr> </table> <table> <tr> <td><strong>Car</strong></td> </tr> <tr> <td><strong>Name</strong></td> <td><strong>Value</strong></td> </tr> <tr> <td>Year</td> <td>2010</td> </tr> <tr> <td>Name</td> <td>Charger</td> </tr> <tr> <td>Manufacturer</td> <td>Dodge</td> </tr> </table> </body> </html> i.e. i need to represent both normal XML and escaped XML in HTML tables.

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  • XSL transformation and special XML entities escaping

    - by Tomas R
    I have an XML file which is transformed with XSL. Some elements have to be changed, some have to be left as is - specifically, text with entities &quot;, &amp;, &apos;, &lt;, &gt; should be left as is, and in my case &quot; and &apos; are changed to " and ' accordingly. Test XML: <?xml version="1.0" encoding="UTF-8" ?> <root> <element> &quot; &amp; &apos; &lt; &gt; </element> </root> transformation file: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" encoding="UTF-8" omit-xml-declaration="no" indent="no" /> <xsl:template match="element"> <xsl:copy> <xsl:value-of disable-output-escaping="no" select="." /> </xsl:copy> </xsl:template> </xsl:stylesheet> result: <?xml version="1.0" encoding="UTF-8"?> <element> " &amp; ' &lt; &gt; </element> desired result: <?xml version="1.0" encoding="UTF-8"?> <element> &quot; &amp; &apos; &lt; &gt; </element> I have 2 questions: why does some of those entities are transformed and other not? how can I get a desired result?

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