Executing an exe with arguments using Powershell
- by Chris Charge
This is what I want to execute:
c:\Program Files (x86)\SEQUEL ViewPoint\viewpoint.exe /Setvar((POSTSTR $POSTSTR)(POSTEND $POSTEND)) /G:C:\viewpointfile.vpt /D:C:($BEGDATE to $TODDATE).xls
This is what I have tried:
$a = "/Setvar((POSTSTR $POSTSTR)(POSTEND $POSTEND))"
$b = "/G:C:\viewpointfile.vpt"
$c = "/D:C:($BEGDATE to $TODDATE).xls"
$Viewpoint = "c:\Program Files (x86)\SEQUEL ViewPoint\viewpoint.exe"
&$Viewpoint $a $b $c
When I execute this I receive an error stating:
File C:\viewpointfile.vpt "/D:C:($BEGDATE to $TODDATE).xls" not found!
I'm not sure where it gets the extra quotes from. If I run the command with just $a and $b it runs fine.
Any help would be greatly appreciated. Thanks! :)
Update
manojlds suggested echoargs so here it the output from it:
&./echoargs.exe $viewpoint $a $b $c
Arg 0 is C:\Program Files (x86)\SEQUEL ViewPoint\viewpoint.exe
Arg 1 is /Setvar((POSTSTR 20101123)(POSTEND 20111123))
Arg 2 is /G:C:\viewpointfile.vpt
Arg 3 is /D:C:(2010-11-23 to 2011-11-23 PM).xls
It appears that all the arguments are being passed properly. When I run this as a command in cmd.exe it executes perfectly. So something on Powershells end must be messing up the output.
Is there any other way to go about executing this command using Powershell?
