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  • Knowledge and user generated content management system to track files, research, proposals, etc.?

    - by Eshwar
    I'll try keep it short. Here's the scenario: We have employees all over the world performing similar work i.e. research, generating powerpoint slides, word documents, graphics, etc. Many times a lot of this previous work can be reused for another future project. The current arrangement is email and phone calls which as you would agree is quick if you know where to look but otherwise archaic and very very inefficient. So I am looking for software that will allow me to do the following: Tag files e.g. an investor presentation on cellphone usage in kenya would be tagged investor, cellphone, kenya Manage references e.g. if we read something on the internet, should be able to paste that link in some fashion and tag it as above. Preferably cloud based so that it can be accessed by anybody and additionally would be nice (though NOT must) to have access levels (director, manager, everyone) A nice interface that non technically savvy folks can warm up to ;) A desktop app would be handy so that people don't always have to click upload or something A tree based system is inefficient in this case because content is usually linked across branches and also people might not quite agree on one format of a tree. Tagging works around this very nicely. What I have considered so far: Evernote (for its more professional look) Springpad (for its versatility with content) Mendeley (this is a research manager and in some ways ideal, but i fear its limited to PDFs) The goal is that when somebody wants to look for a document, they don't have to ask a colleague, they can just search with keywords and all relevant information shows up. Thanks!

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  • How to rename dir under Mac (10.6.4) via super user?

    - by user56990
    This is my dir list on my NFS: macbook-pro-andrey-k:Download Andrey$ ls 1289816143_PL_t1181913 1289816171_PL_t1183807 1290117075_BFD_DVD02(Drums) I can't delete "1290117075_BFD_DVD02(Drums)" using sudo rm -Rf 1290117075_BFD_DVD02(Drums) because I get error message -bash: syntax error near unexpected token `(' Hlp plz, how can I either rename the dir so that the error message would not show up or delete the dir right away omitting rename procedure? Thank you.

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  • What are potential reasons a user could be connected to a home network, but not to the internet?

    - by Matthew
    I have a friend that recently started using Ubuntu, and I've been answering his questions via the internet. However, I'm stuck on this one. He bought Linksys WPC11 wireless card, and says he was able to create a network connection, but was unable to ping or use a browser. I'm not quite sure where to start in figuring this out--what are some common causes of this sort of problem?

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  • How to convert different local float format to standard float format, using zend?

    - by Linto davis
    my local is 'en_IN' (ie Zend_Registry::get('Zend_Locale')) I have to convert the local value to standard float number format for example 1,235.23 = 1235.23 3.23 = 3.23 I have used the following code Zend_Locale_Format::getFloat($value, array('locale' = Zend_Registry::get('Zend_Locale'))); it working fine for 1,235.23, and i get the answer 1235.23. But when i give 3.23 , i get the error on this code And the error shown as 'No localized value in 3.23 found', This issue is happening in the browser opera, when we set the language is English(IN)(en-IN)

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  • Is Family Tree Maker 2011 the right upgrade for a FTM 11 user?

    - by bill weaver
    My father has used Family Tree Maker for years, but hasn't upgraded since version 11. It is difficult to tell from reviews at Amazon and other places whether upgrading to FTM 2011 is a good choice. File incompatibilities and upgrade woes sound like customer service is lacking, and i've read reports of it uploading your data to their database but then trying to sell you a download of data. Looking at the ancestry.com site makes me think it's solely about selling add-ons and upgrades. On the other hand, the feature set seems fairly rich and the software has a pretty strong following. I was able to get Gramps working on my system, but that's not going to work for my dad. Any advice on a good upgrade path?

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  • Where can I find the list of all SQL-standard-mandated aggregate functions? [on hold]

    - by einpoklum
    I know that different DBMSes support different aggregate functions; for example: MySQL's aggregates Oracle's aggregates I want to get the list of aggregates mandated by the SQL standard. Or, to be more precise, the lists of mandatory aggregates for SQL 1992, 1998, 2003, 2008 and 2011 - with 2011 being the most important to me. Edit: Of course if I buy a copy of the standards I could compile these lists myself. My question is whether they're accessible somewhere online.

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  • mysql subquery strangely slow

    - by aviv
    I have a query to select from another sub-query select. While the two queries look almost the same the second query (in this sample) runs much slower: SELECT user.id ,user.first_name -- user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); This query takes 1.2s Explain on this query results: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user index first_name 152 141192 Using where; Using index 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where The second query: SELECT -- user.id -- user.first_name user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); Takes 45sec to run, with explain: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user ALL 141192 Using where 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where Why is it slower if i query only by index fields? Why both queries scans the full length of the user table? Any ideas how to improve? Thanks.

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  • Is there any user-friendly way to deliver an In-app purchase subscription to multiple devices?

    - by mkvakin
    Hi everybody, Apple requires an in-app purchase subscription purchased on one device to be available on all devices associated with the user: “...subscriptions must be provided on all devices associated with a user. In App Purchase expects subscriptions to be delivered through an external server that you will provide. You must provide infrastructure to deliver subscriptions to multiple devices.” Is there any way to propagate a subscription to another device transparently without user having to create a server side user account and log in each time he needs to enable the subscription on another device? E.g. by reading a username from some kind of API and using it as a key on a server to store information about subscriptions. I tried to find an API for retrieving user account info but couldn't find any.

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  • CSS filter for IE6 standard mode and quirk mode?

    - by jackysee
    Is there any CSS filter can be applied to detect IE6's standard mode and quirk mode? The story is that a jQuery script is using $.support.boxModel to handle different rendering mode. But the CSS use the *width hack to define the dimension. But this hack can only filter whether the browser is IE but not the real rendering mode IE is on.

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  • Hibernate - strange order of native SQL parameters

    - by Xorty
    Hello, I am trying to use native MySQL's MD5 crypto func, so I defined custom insert in my mapping file. <hibernate-mapping package="tutorial"> <class name="com.xorty.mailclient.client.domain.User" table="user"> <id name="login" type="string" column="login"></id> <property name="password"> <column name="password" /> </property> <sql-insert>INSERT INTO user (login,password) VALUES ( ?, MD5(?) )</sql-insert> </class> </hibernate-mapping> Then I create User (pretty simple POJO with just 2 Strings - login and password) and try to persist it. session.beginTransaction(); // we have no such user in here yet User junitUser = (User) session.load(User.class, "junit_user"); assert (null == junitUser); // insert new user junitUser = new User(); junitUser.setLogin("junit_user"); junitUser.setPassword("junitpass"); session.save(junitUser); session.getTransaction().commit(); What actually happens? User is created, but with reversed parameters order. He has login "junitpass" and "junit_user" is MD5 encrypted and stored as password. What did I wrong? Thanks EDIT: ADDING POJO class package com.xorty.mailclient.client.domain; import java.io.Serializable; /** * POJO class representing user. * @author MisoV * @version 0.1 */ public class User implements Serializable { /** * Generated UID */ private static final long serialVersionUID = -969127095912324468L; private String login; private String password; /** * @return login */ public String getLogin() { return login; } /** * @return password */ public String getPassword() { return password; } /** * @param login the login to set */ public void setLogin(String login) { this.login = login; } /** * @param password the password to set */ public void setPassword(String password) { this.password = password; } /** * @see java.lang.Object#toString() * @return login */ @Override public String toString() { return login; } /** * Creates new User. * @param login User's login. * @param password User's password. */ public User(String login, String password) { setLogin(login); setPassword(password); } /** * Default constructor */ public User() { } /** * @return hashCode * @see java.lang.Object#hashCode() */ @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + ((null == login) ? 0 : login.hashCode()); result = prime * result + ((null == password) ? 0 : password.hashCode()); return result; } /** * @param obj Compared object * @return True, if objects are same. Else false. * @see java.lang.Object#equals(java.lang.Object) */ @Override public boolean equals(Object obj) { if (this == obj) { return true; } if (obj == null) { return false; } if (!(obj instanceof User)) { return false; } User other = (User) obj; if (login == null) { if (other.login != null) { return false; } } else if (!login.equals(other.login)) { return false; } if (password == null) { if (other.password != null) { return false; } } else if (!password.equals(other.password)) { return false; } return true; } }

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  • User not in the sudoers file. This incident will be reported

    - by Sergiy Byelozyorov
    I need to install a package. For that I need root access. However the system says that I am not in sudoers file. When trying to edit one, it complains alike! How I am supposed to add myself to the sudoers file if I don't have the right to edit one? I have installed this system and only administrator. What can I do? Edit: I have tried visudo already. It requires me to be in sudoers in the first place. amarzaya@linux-debian-gnu:/$ sudo /usr/sbin/visudo We trust you have received the usual lecture from the local System Administrator. It usually boils down to these three things: #1) Respect the privacy of others. #2) Think before you type. #3) With great power comes great responsibility. [sudo] password for amarzaya: amarzaya is not in the sudoers file. This incident will be reported. amarzaya@linux-debian-gnu:/$

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  • SQLAlchemy & Complex Queries

    - by user356594
    I have to implement ACL for an existing application. So I added the a user, group and groupmembers table to the database. I defined a ManyToMany relationship between user and group via the association table groupmembers. In order to protect some ressources of the app (i..e item) I added a additional association table auth_items which should be used as an association table for the ManyToMany relationship between groups/users and the specific item. item has following columns: user_id -- user table group_id -- group table item_id -- item table at least on of user_id and group_id columns are set. So it's possible to define access for a group or for a user to a specific item. I have used the AssociationProxy to define the relationship between users/groups and items. I now want to display all items which the user has access to and I have a really hard time doing that. Following criteria are used: All items which are owned by the user should be shown (item.owner_id = user.id) All public items should be shown (item.access = public) All items which the user has access to should be shown (auth_item.user_id = user.id) All items which the group of the user has access to should be shown. The first two criteria are quite straightforward, but I have a hard time doing the 3rd one. Here is my approach: clause = and_(item.access == 'public') if user is not None: clause = or_(clause,item.owner == user,item.users.contains(user),item.groups.contains(group for group in user.groups)) The third criteria produces an error. item.groups.contains(group for group in user.groups) I am actually not sure if this is a good approach at all. What is the best approach when filtering manytomany relationships? How I can filter a manytomany relationship based on another list/relationship? Btw I am using the latest sqlalchemy (6.0) and elixir version Thanks for any insights.

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  • Nested Resource testing RSpec

    - by Joseph DelCioppio
    I have two models: class Solution < ActiveRecord::Base belongs_to :owner, :class_name => "User", :foreign_key => :user_id end class User < ActiveRecord::Base has_many :solutions end with the following routing: map.resources :users, :has_many => :solutions and here is the SolutionsController: class SolutionsController < ApplicationController before_filter :load_user def index @solutions = @user.solutions end private def load_user @user = User.find(params[:user_id]) unless params[:user_id].nil? end end Can anybody help me with writing a test for the index action? So far I have tried the following but it doesn't work: describe SolutionsController do before(:each) do @user = Factory.create(:user) @solutions = 7.times{Factory.build(:solution, :owner => @user)} @user.stub!(:solutions).and_return(@solutions) end it "should find all of the solutions owned by a user" do @user.should_receive(:solutions) get :index, :user_id => @user.id end end And I get the following error: Spec::Mocks::MockExpectationError in 'SolutionsController GET index, when the user owns the software he is viewing should find all of the solutions owned by a user' #<User:0x000000041c53e0> expected :solutions with (any args) once, but received it 0 times Thanks in advance for all the help. Joe

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  • How to copy symbolic links?

    - by Basilevs
    I have directory that contains some symbolic links: user@host:include$ find .. -type l -ls 4737414 0 lrwxrwxrwx 1 user group 13 Dec 9 13:47 ../k0607-lsi6/camac -> ../../include 4737415 0 lrwxrwxrwx 1 user group 14 Dec 9 13:49 ../k0607-lsi6/linux -> ../../../linux 4737417 0 lrwxrwxrwx 1 user group 12 Dec 9 13:57 ../k0607-lsi6/dfc -> ../../../dfc 4737419 0 lrwxrwxrwx 1 user group 17 Dec 9 13:57 ../k0607-lsi6/dfcommon -> ../../../dfcommon 4737420 0 lrwxrwxrwx 1 user group 19 Dec 9 13:57 ../k0607-lsi6/dfcommonxx -> ../../../dfcommonxx 4737421 0 lrwxrwxrwx 1 user group 17 Dec 9 13:57 ../k0607-lsi6/dfcompat -> ../../../dfcompat I need to copy them to the current directory. The resulting links should be independent from their prototypes and lead directly to their target objects. cp -s creates links to links that is not appropriate behavior. cp -s -L refuses to copy links to directories cp -s -L -r refuses to copy relative links to non-working directory What should I do?

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  • How to cd into smb://[email protected] from terminal?

    - by John
    I am using ubuntu and gnome on my computer. When I open up File Browser, on the left hand rail, I see conveniently a folder called "Work Server". When I mouse over it, the following caption appears "smb://[email protected]". If I click on that folder, then I can see the contents of that folder. Everything is great. So now when I open up a terminal/shell, I type in cd smb://[email protected] I get an error saying the directory doesn't exist. How do I enter this directory via shell/terminal?

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