Search Results

Search found 26207 results on 1049 pages for 'django users'.

Page 242/1049 | < Previous Page | 238 239 240 241 242 243 244 245 246 247 248 249  | Next Page >

  • Problem with load testing Web Service - VSTS 2008

    - by Carlos
    Hello, I have a webtest with makes a simple call to a WebService which looks like that: MyWebService webService = new MyWebService(); webService.Timeout = 180000; webService.myMethod(); I am not using ThinkTimes, also the Run Duration is set to 5 minutes. When I ran this test simulating only 1 user, I check the counters and I found something like that: Tests Total: 4500 Network Interface\Bytes sent (agent machine): 35,500 Then I ran the same tests, but this time simulating 2 users and I got something like that: Tests Total: 2225 Network Interface\Bytes sent (agent machine): 30,500 So when I increased the numbers of users the tests/sec was half than when I use only 1 user and the bytes sent by the agent was also lower. I think it is strange, because it doesn't seems I have a bottleneck in my agent machine since CPU is never higher than 30% and I have over 1.5GB of RAM free, also my network utilization is like 0.5% of its capacity. In order to troubleshot this I ran a test using Step Pattern, the simulated users went from 20 to 800 users. When I check the requests/sec it is practically constant through the whole test, so it is clear there is something in my test or my environment which is preventing the number of requests from gets higher. It would be a expected behavior if the "response time" was getting higher because it would tell me the requests wasn't been processed properly, but the strange thing is the response time is practically constant all the time and it is pretty low actually. I have no idea why my agent can't send more requests when I increase the numbers of users, any help/tip/guess would be really appreciate.

    Read the article

  • MOSS 2007 - list permission

    - by nav
    Hi All, I have configured my list so that users can only read and edit items they have created. I now need to configure this list so that a particular group of users can edit and read all items on this list. I know users with the 'Manage Lists' permission would be able to do this. My question is can this be configured to be even more granular to apply a permission that works like the 'Manage Lists' permission but only for a particular list, rather than all lists? Many Thanks, Nav

    Read the article

  • Publishing news feeds automatically

    - by Joel
    Hello, I have a website which generates hourly updates to users. I want to allow these updates to show up as News feeds in Facebok. I opened a Facebook Connect application. Through my site I receive the extended persmission to post news to the users' news feeds. My question is can I automatically post news feeds to these users without them being logged in to my site? That is, sending hourly news feed to all users using a cron job. Thanks, Joel

    Read the article

  • Tag/Keyword based recommendation

    - by Hellnar
    Hello I am wondering what algorithm would be clever to use for a tag driven e-commerce enviroment: Each item has several tags. IE: Item name: "Metallica - Black Album CD", Tags: "metallica", "black-album", "rock", "music" Each user has several tags and friends(other users) bound to them. IE: Username: "testguy", Interests: "python", "rock", "metal", "computer-science" Friends: "testguy2", "testguy3" I need to generate recommendations to such users by checking their interest tags and generating recommendations in a sophisticated way. Ideas: A Hybrid recommendation algorithm can be used as each user has friends.(mixture of collaborative + context based recommendations). Maybe using user tags, similar users (peers) can be found to generate recommendations. Maybe directly matching tags between users and items via tags. Any suggestion is welcome. Any python based library is also welcome as I will be doing this experimental engine on python language.

    Read the article

  • how do simple SQLAlchemy relationships work?

    - by Carson Myers
    I'm no database expert -- I just know the basics, really. I've picked up SQLAlchemy for a small project, and I'm using the declarative base configuration rather than the "normal" way. This way seems a lot simpler. However, while setting up my database schema, I realized I don't understand some database relationship concepts. If I had a many-to-one relationship before, for example, articles by authors (where each article could be written by only a single author), I would put an author_id field in my articles column. But SQLAlchemy has this ForeignKey object, and a relationship function with a backref kwarg, and I have no idea what any of it MEANS. I'm scared to find out what a many-to-many relationship with an intermediate table looks like (when I need additional data about each relationship). Can someone demystify this for me? Right now I'm setting up to allow openID auth for my application. So I've got this: from __init__ import Base from sqlalchemy.schema import Column from sqlalchemy.types import Integer, String class Users(Base): __tablename__ = 'users' id = Column(Integer, primary_key=True) username = Column(String, unique=True) email = Column(String) password = Column(String) salt = Column(String) class OpenID(Base): __tablename__ = 'openid' url = Column(String, primary_key=True) user_id = #? I think the ? should be replaced by Column(Integer, ForeignKey('users.id')), but I'm not sure -- and do I need to put openids = relationship("OpenID", backref="users") in the Users class? Why? What does it do? What is a backref?

    Read the article

  • How do you implement paging in ASP.NET MVC?

    - by Kevin Pang
    Currently, I'm using a strategy found on many blog posts. Basically, the URL contains the page number (e.g. /Users/List/5 will give you the users on page 5 of your paged list of users). However, I'm not running into a situation where one page must list two separate paged lists. How do I go about doing this using ASP.NET MVC? Do I simply provide two url parameters (e.g. /Users/List?page1=1&page2=2)? Is there a better way by using partial views?

    Read the article

  • Algorithm for scoring user activity

    - by ManBugra
    I have an application where users can: Write reviews about products Add comments to products Up / Down vote reviews Up / Down vote comments Every Up/Down vote is recorded in a db table. What i want to do now is to create a ranking of the most active users in the last 4 weeks. Of course good reviews should be weighted more than good comments. But also e.g. 10 good comments should be weighted more than just one good review. Example: // reviews created in recent 4 weeks //format: [ upVoteCount, downVoteCount ] var reviews = [ [120,23], [32,12], [12,0], [23,45] ]; // comments created in recent 4 weeks // format: [ upVoteCount, downVoteCount ] var comments = [ [1,2], [322,1], [0,0], [0,45] ]; // create weight vector // format: [ reviewWeight, commentsWeight ] var weight = [0.60, 0.40]; // signature: activties..., activityWeight var userActivityScore = score(reviews, comments, weight); ... update user table ... List<Users> users = "from users u order by u.userActivityScore desc"; How would a fair scoring function look like? How could an implementation of the score() function look like? How to add a weight g to the function so that reviews are weighted heavier? How would such a function look like if, for example, votes for pictures would be added?

    Read the article

  • username and password check linq query in c#

    - by b0x0rz
    this linq query var users = from u in context.Users where u.UserEMailAdresses.Any(e1 => e1.EMailAddress == userEMail) && u.UserPasswords.Any(e2 => e2.PasswordSaltedHash == passwordSaltedHash) select u; return users.Count(); returns: 1 even when there is nothing in password table. how come? what i am trying to do is get the values of email and passwordHash from two separate tables (UserEMailAddresses and UserPasswords) linked via foreign keys to the third table (Users). it should be simple - checking if email and password mach from form to database. but it is not working for me. i get 1 (for count) even when there are NO entries in the UserPasswords table. is the linq query above completely wrong, or...?

    Read the article

  • osx rvm ruby 1.8.7 nokogiri 1.4.1 - ERROR: Failed to build gem native extension.

    - by tommasop
    I'm stuck with this problem. cat ~/.rvm/gems/ruby-1.8.7-p249/gems/nokogiri-1.4.1/ext/nokogiri/mkmf.log Gives this errors (clipped) conftest.c:3: error: 'xmlParseDoc' undeclared (first use in this function) conftest.c:3: error: (Each undeclared identifier is reported only once conftest.c:3: error: for each function it appears in.) For several libraries which are found in the system. If I manually go into ~/.rvm/gems/ruby-1.8.7-p249/gems/nokogiri-1.4.1/ext/nokogiri/ And compile and install everything goes fine ruby extconf.rb make make install mkdir -p /Users/tommasop/.rvm/rubies/ruby-1.8.7-p249/lib/ruby/site_ruby/1.8/i686-darwin9.8.0/nokogiri /usr/bin/install -c -m 0755 nokogiri.bundle /Users/tommasop/.rvm/rubies/ruby-1.8.7-p249/lib/ruby/site_ruby/1.8/i686-darwin9.8.0/nokogiri except that on script/server: ? script/server --debugger => Booting Mongrel => Rails 2.3.5 application starting on http://0.0.0.0:3000 ./script/../config/../vendor/rails/railties/lib/rails/gem_dependency.rb:119:Warning: Gem::Dependency#version_requirements is deprecated and will be removed on or after August 2010. Use #requirement The following gems have native components that need to be built nokogiri You're running: ruby 1.8.7.249 at /Users/tommasop/.rvm/rubies/ruby-1.8.7-p249/bin/ruby rubygems 1.3.6 at /Users/tommasop/.rvm/gems/ruby-1.8.7-p249, /Users/tommasop/.rvm/gems/ruby-1.8.7-p249%global Run `rake gems:build` to build the unbuilt gems. Any help greatly appreciated!

    Read the article

  • Finds in Rails 3 and ActiveRelation

    - by TheDelChop
    Guys, I'm trying to understand the new arel engine in Rails 3 and I've got a question. I've got two models, User and Task class User < ActiveRecord::Base has_many :tasks end class Task < ActiveRecord::Base belongs_to :user end here is my routes to imply the relation: resources :users do resources :tasks end and here is my Tasks controller: class TasksController < ApplicationController before_filter :load_user def new @task = @user.tasks.new end private def load_user @user = User.where(:id => params[:user_id]) end end Problem is, I get the following error when I try to invoke the new action: NoMethodError: undefined method `tasks' for #<ActiveRecord::Relation:0x3dc2488> I am sure my problem is with the new arel engine, does anybody understand what I'm doing wrong? Sorry guys, here is my schema.db file: ActiveRecord::Schema.define(:version => 20100525021007) do create_table "tasks", :force => true do |t| t.string "name" t.integer "estimated_time" t.datetime "created_at" t.datetime "updated_at" t.integer "user_id" end create_table "users", :force => true do |t| t.string "email", :default => "", :null => false t.string "encrypted_password", :limit => 128, :default => "", :null => false t.string "password_salt", :default => "", :null => false t.string "reset_password_token" t.string "remember_token" t.datetime "remember_created_at" t.integer "sign_in_count", :default => 0 t.datetime "current_sign_in_at" t.datetime "last_sign_in_at" t.string "current_sign_in_ip" t.string "last_sign_in_ip" t.datetime "created_at" t.datetime "updated_at" t.string "username" end add_index "users", ["email"], :name => "index_users_on_email", :unique => true add_index "users", ["reset_password_token"], :name => "index_users_on_reset_password_token", :unique => true add_index "users", ["username"], :name => "index_users_on_username", :unique => true end Thank you, Joe

    Read the article

  • SQL 2005: Select top N, group by ID with joins

    - by Suzy Fresh
    I'm having real difficulty with a query involving 3 tables. I need to get the 3 newest users per department grouped by department names. The groups should be sorted by the users.dateadded so the department with the newest activity is first. The users can exist in multiple departments so Im using a lookup table that just contains the userID and deptID. My tables are as follows. Department - depID|name Users - userID|name|dateadded DepUsers - depID|userID The output I need would be Receiving John Doe - 4/23/2010 Bill Smith - 4/22/2010 Accounting Steve Jones - 4/22/2010 John Doe - 4/21/2010 Auditing Steve Jones - 4/21/2010 Bill Smith - 4/21/2010

    Read the article

  • How to map to tables in database PHPMyAdmin

    - by thegrede
    I'm working now on a project which a user can save their own coupon codes on the websites, so I want to know what is the best to do that, Lets say, I have 1 table with the users, like this, userId | firstName | lastName | codeId and then I have a table of the coupon codes, like this, codeId | codeNumber So what I can do is to connect the codeId to userId so when someone saves the coupons goes the codeId from the coupon table into the codeId of the users table, But now what if when a user have multiple coupons what do I do it should be connected to the user? I have 2 options what to do, Option 1, Saving the codeId from coupons table into the codeId of users table like 1,2,3,4,5, Option 2 To make a new row into the coupons table and to connect the user to the code with adding another field in the coupon table userId and putting into it the user which has added the coupon his userId of the users table, So what of the two options is better to do? Thanks you guys.

    Read the article

  • How to pre-check checkboxes in formtastic

    - by trustfundbaby
    I have a form I'm trying to set up ... Users can have many posts, and each post can have many people watching it. The Watch model is set up polymorphically as 'watchable' so it can apply to different types of models. It has a user_id, watchable_id, watchable_type and timestamps as attributes/fields. This is soley so that when people comment on a post, users watching the post can get an email about it. What I'm trying to do is show the user a list of users that they can tag on each post, which is not problem. This is what I'm using right now http://pastie.org/940421 The problem with this, is that when you go to edit an update/post ... all the checkboxes are prechecked ... I want it to pre-check only users who are currently watching the post.

    Read the article

  • Logout solution (ASP.NET)

    - by Irgat
    I programmed a web site, prepared a login mechanism(via textbox, not Login tools), users want to logout, they click logout button. However, my problem is that if users don't click logout button or close web page or switch another one, How can I understand this situation? According my mechanism, when users logout ,in DB some insertion and delete operation are making. I also want to do this with closing page,switch another one. Thanks.

    Read the article

  • Textmate cucumber bundle issues - 'Run Feature' producing errors.

    - by Evolve
    From a cucumber feature file when I go to 'Run features' Im getting the error below in the popup box that appears. How do I fix this? /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in gem_original_require': no such file to load -- /Users/evolve/Projects/i9/Tornelo/.bundle/environment (LoadError) from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:inrequire' from /Users/evolve/Library/Application Support/TextMate/Bundles/Cucumber.tmbundle/Support/lib/cucumber/mate/../mate.rb:10 from /Users/evolve/Library/Application Support/TextMate/Bundles/Cucumber.tmbundle/Support/lib/cucumber/mate/feature_helper.rb:1:in require' from /Users/evolve/Library/Application Support/TextMate/Bundles/Cucumber.tmbundle/Support/lib/cucumber/mate/feature_helper.rb:1 from /tmp/cucumber-906.rb:2:inrequire' from /tmp/cucumber-906.rb:2

    Read the article

  • max count with joins

    - by trixet
    I have 3 tables: users: Id Login 1 John 2 Bill 3 Jim computers: Id Name 1 Computer1 2 Computer2 3 Computer3 4 Computer4 5 Computer5 sessions: UserId ComputerId Minutes 1 2 47 2 1 32 1 4 15 2 5 5 1 2 7 1 1 40 2 5 31 I would like to display this resulting table: Login Total_sess Total_min Most_freq_computer Sess_on_most_freq Min_on_most_freq John 4 109 Computer2 2 54 Bill 3 68 Computer5 2 36 Jim - - - - - Myself I can only cover first 3 columns with: SELECT Login, COUNT(sessions.UserId), SUM(Minutes) FROM users LEFT JOIN sessions ON users.Id = sessions.UserId GROUP BY users.Id And some kind of other columns with: SELECT main.* FROM (SELECT UserId, ComputerId, COUNT(*) AS cnt ,SUM(Minutes) FROM sessions GROUP BY UserId, ComputerId) AS main INNER JOIN ( SELECT ComputerId, MAX(cnt) AS maxCnt FROM ( SELECT ComputerId, UserId, COUNT(*) AS cnt FROM sessions GROUP BY ComputerId, UserId ) AS Counts GROUP BY ComputerId) AS maxes ON main.ComputerId = maxes.ComputerId AND main.cnt = maxes.maxCnt But I need to get whole resulting table in one query. I feel I'm doing something completely wrong. Need help.

    Read the article

  • Kohana 3 ORM limitations

    - by yoda
    Hi, What are the limitations of Kohana 3 ORM regarding table relationships? I'm trying to modify the build-in Auth module in order to accept groups of users in adition, having now the following tables : groups groups_users roles roles_groups users user_tokens By default, this module is set to work without groups, and linking the users and roles using a third table named roles_users, but I need to add groups to it. I'm linking, as you can see by the names, the groups to users and the roles to groups, but I'm failing building the ORM code for it, so that's pretty much the question here, if ORM is limited to 2 relationships or if it can handle 3 in this case. Cheers!

    Read the article

  • How transform this find_by_sql to named_scope?

    - by keruilin
    How can I possibly turn into named_scope? def self.hero_badge_awardees return User.find_by_sql("select users.*, awards.*, badges.badge_type from users, awards, badges where awards.user_id = users.id and badges.id = awards.badge_id and badges.badge_type = 'HeroBadge'") end

    Read the article

  • How to have multiple paths display URL as root

    - by Verdi Erel Ergün
    I want users#new and tasks#index to display as the root path URL, i.e. / When a user logs in on the path users#new (set as root) they are redirected to tasks#index and URL does not change. Can this be done in the routes.rb file? This is my routes.rb file: Todo::Application.routes.draw do resources :sessions resources :subscriptions resources :users resources :tasks do collection do post :sort end end root :to => "users#new" match "sessions#new" => "tasks#index" match "sessions#" => "tasks#index"

    Read the article

  • MySQL calling in Username to show instead of ID!

    - by Jess
    I have a users table, books table and authors table. An author can have many books, while a user can also have many books. (This is how my DB is currently setup). As I'm pretty new to So far my setup is like bookview.php?book_id=23 from accessing authors page, then seeing all books for the author. The single book's details are all displayed on this new page...I can get the output to display the user ID associated with the book, but not the user name, and this also applies for the author's name, I can the author ID to display, but not the name, so somewhere in the query below I am not calling in the correct values: SELECT users.user_id, authors.author_id, books.book_id, books.bookname, books.bookprice, books.bookplot FROM books INNER JOIN authors on books.book_id = authors.book_id INNER JOIN users ON books.book_id = users.user_id WHERE books.book_id=" . $book_id; Could someone help me correct this so I can display the author name and user name both associated with the book! Thanks for the help :)

    Read the article

  • mysql GROUP_CONCAT

    - by user301766
    I want to list all users with their corropsonding user class. Here are simplified versions of my tables CREATE TABLE users ( user_id INT NOT NULL AUTO_INCREMENT, user_class VARCHAR(100), PRIMARY KEY (user_id) ); INSERT INTO users VALUES (1, '1'), (2, '2'), (3, '1,2'); CREATE TABLE classes ( class_id INT NOT NULL AUTO_INCREMENT, class_name VARCHAR(100), PRIMARY KEY (class_id) ); INSERT INTO classes VALUES (1, 'Class 1'), (2, 'Class 2'); And this is the query statement I am trying to use but is only returning the first matching user class and not a concatenated list as hoped. SELECT user_id, GROUP_CONCAT(DISTINCT class_name SEPARATOR ",") AS class_name FROM users, classes WHERE user_class IN (class_id) GROUP BY user_id; Actual Output +---------+------------+ | user_id | class_name | +---------+------------+ | 1 | Class 1 | | 2 | Class 2 | | 3 | Class 1 | +---------+------------+ Wanted Output +---------+---------------------+ | user_id | class_name | +---------+---------------------+ | 1 | Class 1 | | 2 | Class 2 | | 3 | Class 1, Class 2 | +---------+---------------------+ Thanks in advance

    Read the article

  • Is a .Net membership database portable, or are accounts somehow bound to the originating Web site or

    - by Deane
    I have an ASP.Net Web site using .Net Membership with a SQL Server provider, so the users and roles are stored in the SQL tables created by Aspnet_regsql.exe. Is this architecture totally self-contained and portable, or are users in it somehow bound to the specific Web site on which they create their account? Put another way, if we create a bunch of users in dev or UAT, the back up and restore this database to another server, accessed under another domain name, should it still work just fine? We're seeing some odd behavior when we move the database, like users losing group affiliation and such, and I'm curious how portable and environment-agnostic this database really is. I have a sneaking suspicion that something is bound to the machine key or the domain.

    Read the article

  • How to optimize this user ranking query

    - by James Simpson
    I have 2 databases (users, userRankings) for a system that needs to have rankings updated every 10 minutes. I use the following code to update these rankings which works fairly well, but there is still a full table scan involved which slows things down with a few hundred thousand users. mysql_query("TRUNCATE TABLE userRankings"); mysql_query("INSERT INTO userRankings (userid) SELECT id FROM users ORDER BY score DESC"); mysql_query("UPDATE users a, userRankings b SET a.rank = b.rank WHERE a.id = b.userid"); In the userRankings table, rank is the primary key and userid is an index. Both tables are MyISAM (I've wondered if it might be beneficial to make userRankings InnoDB).

    Read the article

< Previous Page | 238 239 240 241 242 243 244 245 246 247 248 249  | Next Page >