Search Results

Search found 57910 results on 2317 pages for 'html form post'.

Page 242/2317 | < Previous Page | 238 239 240 241 242 243 244 245 246 247 248 249  | Next Page >

  • cannot set a variable to base on user input post method

    - by user1318960
    Hello i´m trying to set info from a post method into a variable that sets a session named name the value that the user input. I get the following error: Notice: Undefined index: name in F:\xampp\htdocs\Impossible game\index.php on line 18 This is line 18: $session = $_POST['name']; <form action="ms1.php" method="POST"> Name <input type="text" name="name"> <input type="Submit" value="Begin"> </form> <?php $session = $_POST['name']; session_start(); $_SESSION['name'] = $session;

    Read the article

  • How to post XML document to HTTP with VB.Net

    - by Joshua McGinnis
    I'm looking for help with posting my XML document to a url in VB.NET. Here's what I have so far ... Public Shared xml As New System.Xml.XmlDocument() Public Shared Sub Main() Dim root As XmlElement root = xml.CreateElement("root") xml.AppendChild(root) Dim username As XmlElement username = xml.CreateElement("username") username.InnerText = _username root.AppendChild(username) xml.Save(Console.Out) Dim url = "https://mydomain.com" Dim req As WebRequest = WebRequest.Create(url) req.Method = "POST" req.ContentType = "application/xml" req.Headers.Add("Custom: API_Method") Console.WriteLine(req.Headers.ToString()) This is where things go awry: I want to post the xml, and then print the results to console. Dim newStream As Stream = req.GetRequestStream() xml.Save(newStream) Dim response As WebResponse = req.GetResponse() Console.WriteLine(response.ToString()) End Sub

    Read the article

  • list all likes to a certain post coming from my friends

    - by Max Favilli
    I know I can get posts (paginated, 25 at times) of a certain user with this: https://graph.facebook.com/575128756/posts And the likes of a certain post (paginated, 25 at times) with this GRAPH api call (I omit the first part of the url): /575128756_176517292390301/likes But if I want to get the likes from friends of the post user only? FQL could be an alternative (from table like and subqueries for friend and stream), but FQL seems so buggy in my tests I don't feel comfortable using it in a productive system. Is there anyway to achieve my target using the GRAPH api?

    Read the article

  • jQuery blockUI and AJAX POST

    - by oompahloompah
    I am using jQuery BlockUI in a project. For a particular user action, I want to block the UI, and then POST data to the server. When the timeout event occurs OR the server returns, I want to unblock the page. I can't seem to implement this behaviour. This is what I have so far (not working) $(document).ready(function(){ $('#test').click(function(event){ $.blockUI({ message: $('#syntax-chk') }); $.ajax({ type: 'POST', url: 'www.example.com', data: somedata, dataType: "json" }); setTimeout(function() { $.unblockUI({ onUnblock: function(){ alert('onUnblock'); } }); }, 2000); }); can anyone spot what I may be doing wrong?

    Read the article

  • JQuery post to php

    - by RussP
    Why is it that I can never get JQuery serialize to work properly. I guess I must be missing something. I can serialize a form data and it shows in an alert: var forminfo = $j('#frmuserinfo').serialize(); alert(forminfo); I then post to my PHP page thus: $j.ajax({ type: "POST", url: "cv-user-process.php", data: "forminfo="+forminfo, cache: false, complete: function(data) { } }); But WHENEVER (not the first time) I try to insert/update the data in the DB I only ever get 1 varaible passed: Here is my PHP script: $testit = mysql_query("UPDATE cv_usersmeta SET inputtest='".$_POST['forminfo']."' WHERE user='X'"); the data passed only ever gets the first variable. why? I think it is more the way I deal with the php but it drives me nuts and always takes me far too long to find where I am going wrong.

    Read the article

  • php cURL POST how to follow location

    - by One Stuck Pixel
    I am in a bit of a rut with a cURL issue. The post works greate, the data is POSTED just fine and received ok, but the url of the posted page never appears in the browser after the cURL session is executed, for example look at the following code: $ch = curl_init("http://localhost/eterniti/cart-step-1.php"); curl_setopt($ch, CURLOPT_HEADER, false); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, "error=1&em=$em&fname=$fname&lname=$lname&email1=$email1&email2=$email2&code=$code&area=$area&number=$num&mobile=$mobile&address1=$address1&address2=$address2&address3=$address3&suburb=$suburb&postcode=$postcode&country=$country"); curl_exec($ch); curl_close($ch); The post works fine and I am taken to the cart-step-1.php where I can process the posted data, HOWEVER the location in the URL address bar of the browser remains that of the script page, in this case proc_xxxxxx.php Any ideas how to get the URL address to reflect the page I am actually POSTED to? Thanks a mill

    Read the article

  • WHY HAVE YOU ROMOVED MY POST? [closed]

    - by Eddy Freeman
    I posted a question about how to rotate a tile in BufferedImage. I did it in the morning and you removed it. Why have you removed it again? What is wrong with the posts? Tell me before i become angry. You have removed the post twice without informing/telling me the problem. with the posts What is wrong? Tell me. Reply to this post and tell me what is wrong.

    Read the article

  • ajax post sending parameter failed

    - by kawtousse
    hi, in order to send to servlet parameter in post methos i am using ajax like the following: var xhr = getXhr(); xhr.onreadystatechange = function(){ if(xhr.readyState == 4 && xhr.status == 200) {alert("ok"); } }; xhr.open("POST","ServletEdition",true); xhr.setRequestHeader('Content-Type','application/x-www-form-urlencoded'); id = document.getElementById('idIdden').value; xhr.send("id="+id) In the servet the following: String hd=request.getParameter("id"); System.out.println("idDailyTimeSheet est::" +hd); But it failes every time and the problem that i didn't see the cause. thanks

    Read the article

  • Post and Comment with the same Model.

    - by xRobot
    I have created a simple project where everyone can create one or more Blog. I want to use this models for Post and for Comment: class Post_comment(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField(_('object ID')) content_object = generic.GenericForeignKey() # Hierarchy Field parent = models.ForeignKey('self', null=True, blank=True, default=None, related_name='children') # User Field user = models.ForeignKey(User) # Date Fields date_submitted = models.DateTimeField(_('date/time submitted'), default = datetime.now) date_modified = models.DateTimeField(_('date/time modified'), default = datetime.now) title = models.CharField(_('title'), max_length=60, blank=True, null=True) post_comment = models.TextField(_('post_comment')) markup = models.IntegerField(choices=MARKUP_CHOICES, default=DEFAULT_MARKUP, null=True, blank=True) if it is a comment the parent is not null. So in most case the text field will contain a little bit of text. Can I use this model for both Post and Comment ?

    Read the article

  • Post values in PHP Headers

    - by kumar
    Hi.. I want send some data to a remote webpage from my site. Actually it can be achieved through form hidden variables. but for security reason, i want set as post variables in header and then send to that webpage. i use this code $post_data = 'var1=123&var2=456'; $content_length = strlen($post_data); header('POST http://localhost/testing/test.php HTTP/1.1'); header('Host: localhost'); header('Connection: close'); header('Content-type: application/x-www-form-urlencoded'); header('Content-length: ' . $content_length); header($post_data); but my code doesn't work properly. help me...

    Read the article

  • display result in status after it post

    - by nisardotnet
    my question is continuation of what i have posted here i want to know how to display a result status based on my return result from Web Method here is my post code: beforeSubmit: function(data) { var myData = { "firstName": escape($('#txtFirstName').val()), "lastName": escape($('#txtLastName').val()) }; $.ajax(<br> { type: "POST", url: "VisitorWS.asmx/AddVisitors", data: JSON.stringify(myData), contentType: "application/json; charset=utf-8", dataType: "json", success: function(data) { $("#status").fadeTo(500, 1, function() { $(this).html("You are now registered!").fadeTo(5000, 0); }) }, error: function(data) { $("#status").fadeTo(5000, 1, function() { $(this).html("Failed!").fadeTo(5000, 0); }) } }); WebMethod [WebMethod] public bool AddVisitors(string firstName, string lastName) { if (firstName == "test") { return true; } return false; } so based on true or false i want to display a message on the client side.

    Read the article

  • jquery, ajax, load post result to div

    - by mike
    Hello, I have a form that I need to post and show the result in a div. I'm not having any problems making the ajax call but I can't seem to figure out how to load the result to a div. I have tried: $.ajax({ type: 'POST', data: $('#someForm').serialize(), url: 'http://somedomain.com/my/url', success: function(data) { $('#someDiv').load(data); } }); but it does not seem to work properly. I'm nit sure if this should even work but the result is the the page i'm posting from being loaded into the div and not the url I'm posting to. Any help would be great! Thanks!

    Read the article

  • PHP Form (post) Repeating input in a tabel

    - by Sef
    Hello, I have a form (with post method) that takes the following input: - a certain name - a number - 3 checkboxes All this input gets generated and calculated in a table.(html code within the php) Everything gets properly calculated and displayed in a table. So my question: How do i make it possible after giving all those input to give in more input? Meaning i have made a hyperlink that goes back to the form itself (where i can give the input). So i can give in new data, and after submiting that again the table now contains 2 rows of values insteed of just 1. Not really sure what exactly i need for this. Regards.

    Read the article

  • $.post is not working

    - by BEBO
    i am trying to post data to Mysql using jquery $.post and php page. my code is not running and nothing is added to the mysql table. I am not sure if the path i am creating is wrong but any help would be appreciated. Jquery location: f_js/tasks/TaskTest.js <script type="text/javascript"> $(document).ready(function(){ $("#AddTask").click(function(){ var acct = $('#acct').val(); var quicktask = $('#quicktask').val(); var user = $('#user').val(); $.post('addTask.php',{acct:acct,quicktask:quicktask,user:user}, function(data){ $('#result').fadeIn('slow').html(data); }); }); }); </script> addTask.php (runs the jqeury code) <?php include 'dbconnect.php'; include 'sessions.php'; $acct = $_POST['acct']; $task = $_POST['quicktask']; $taskstatus = 'Active'; //get task Creator $user = $_POST['user']; //query task creator from users table $allusers = mysql_query("SELECT * FROM users WHERE username = '$user'"); while ($rows = mysql_fetch_array($allusers)) { //get first and last name for task creator $taskOwner = $rows['user_firstname']; $taskOwnerLast = $rows['user_lastname']; $taskOwnerFull = $taskOwner." ".$taskOwnerLast; mysql_query("INSERT INTO tasks (taskresource, tasktitle, taskdetail, taskstatus, taskowner, taskOwnerFullName) VALUES ('$acct', '$task', '$task', '$taskstatus', '$user', '$taskOwnerFull' )"); echo "inserted"; } ?> Accountview.php finally the front page <html> <div class="input-cont "> <input type="text" class="form-control col-lg-12" placeholder="Add a quick Task..." name ="quicktask" id="quicktask"> </div> <div class="form-group"> <div class="pull-right chat-features"> <a href="javascript:;"> <i class="icon-camera"></i> </a> <a href="javascript:;"> <i class="icon-link"></i> </a> <input type="button" class="btn btn-danger" name="AddTask" id="AddTask" value="Add" /> <input type="hidden" name="acct" id="acct" value="<?php echo $_REQUEST['acctname']?>"/> <input type="hidden" name="user" id="user" value="<?php $username = $_SESSION['username']; echo $username?>"/> <div id="result">result</div> </div> </div> <!-- js placed at the end of the document so the pages load faster --> <script src="js/jquery.js"></script> <script src="f_js/tasks/TaskTest.js"></script> <!--common script for all pages--> <script src="js/common-scripts.js"></script> <script type="text/javascript" src="assets/gritter/js/jquery.gritter.js"></script> <script src="js/gritter.js" type="text/javascript"></script> <script> </html> Firebug reponse: Response Headers Connection Keep-Alive Content-Length 0 Content-Type text/html Date Fri, 08 Nov 2013 21:48:50 GMT Keep-Alive timeout=5, max=100 Server Apache/2.4.4 (Win32) OpenSSL/0.9.8y PHP/5.4.16 X-Powered-By PHP/5.4.16 refresh 5; URL=index.php Request Headers Accept */* Accept-Encoding gzip, deflate Accept-Language en-US,en;q=0.5 Content-Length 13 Content-Type application/x-www-form-urlencoded; charset=UTF-8 Cookie PHPSESSID=6gufl3guiiddreg8cdlc0htnc6 Host localhost Referer http://localhost/betahtml/AccountView.php?acctname=client%201 User-Agent Mozilla/5.0 (Windows NT 6.3; WOW64; rv:25.0) Gecko/20100101 Firefox/25.0 X-Requested-With XMLHttpRequest

    Read the article

  • InputStreamBody in HttpMime 4.0.3 settings for content-length

    - by Ram
    I am trying to send a multi part formdata post through my java code. Can someone tell me how to set Content Length in the following?? There seem to be headers involved when we use InputStreamBody which implements the ContentDescriptor interface. Doing a getContentLength on the InputStreamBody gives me -1 after i add the content. I subclassed it to give contentLength the length of my byte array but am not sure if other headers required by ContentDescriptor will be set for a proper POST. HttpClient httpclient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(myURL); ContentBody cb = new InputStreamBody(new ByteArrayInputStream(bytearray), myMimeType, filename); //ContentBody cb = new ByteArrayBody(bytearray, myMimeType, filename); MultipartEntity mpentity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); mpentity.addPart("key", new StringBody("SOME_KEY")); mpentity.addPart("output", new StringBody("SOME_NAME")); mpentity.addPart("content", cb); httpPost.setEntity(mpentity); HttpResponse response = httpclient.execute(httpPost); HttpEntity resEntity = response.getEntity();

    Read the article

  • post selextbox values to php page in jquery

    - by JPro
    I am using jquery button click to post all the values in a selectbox to a PHP page, but this code does not seem to work. Can anyone please help? <script type="text/javascript"> $(function() { $("#btn1").click(function () { var arr= new Array; $("#target_select option").each (function () { // You can push the array on an array arr.push( $(this).val() ); //alert( $(this).val() ); not getting the alert to display too }); $.post("test.php", { name: arr } ); }); }); </script> Generate

    Read the article

  • Java - Post to Twitter

    - by Ibolit
    Hi. I've written a simple web application, which i want to post tweets. I have seen some java libraries for working with twitter, and they all seem like too much of work for something that seemingly simple. But it is possible that i am missing something. And I am yet to make any of them work... Is there any simple way to post a tweet in twitter from a web-app in java with only a few lines of code? Thank you very much.

    Read the article

  • Customizing the post to facebook in Sharekit2.0

    - by laksh
    I have integrated the latest code in sharekit into my project. I am able to click in to go to the facebook and able to see the text i am going to post. The image looks like this: I would like to change two things. Firstly, I am not able to see the cancel or post button because of my app picture at top. So i would like to set the view to be scrollable. How do i change that? Secondly, I would like to remove the keyboard after i press return, or i want a way to remove the keyboard. Need some help on this..Thanks..

    Read the article

  • Django forms: where is POST data received?

    - by Rosarch
    I have a widget that allows user to enter data for a model field. The data in the form can't be directly converted to Python - it requires some coercion. Where do I put this code? Is the widget responsible for translating its post data to a python value? The field itself? I thought that maybe value_from_datadict() would be correct, but now it looks like that serves a different purpose. (I'm using the form in the admin interface, if it makes any difference.)

    Read the article

  • Accessing ajax POST response in javascript

    - by mike44
    I'm making ajax POST request from javascript function: function UpdateMetrics() { $.ajax({ type: "POST", url: "MyHandler.ashx?Param1=value1", data: "{}", contentType: "text/json; charset=utf-8", dataType: "text", success: function (msg) { var jsonUpdatedData = msg; ... } }); } From my handler, I'm sending json string with: context.Response.write(json); I think I'll get it in msg. I also want to send other string (count). So I'm trying to use header info along with json data. So I added this line: context.Response.Headers.Add("MaxCount",Convert.ToString(tempList.Count)); If this is right way to do it, how can I access it in my success function?

    Read the article

< Previous Page | 238 239 240 241 242 243 244 245 246 247 248 249  | Next Page >