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  • How do I drop 'NOT NULL' from a column in MySQL?

    - by Will
    A show create table command shows the following: 'columnA' varchar(6) NOT NULL DEFAULT ''; How do I modify that column so that the not null is removed? I need it to be: 'columnA' varchar(6) DEFAULT NULL; I thought the following would work, but it has no effect: ALTER TABLE tbl_name MODIFY columnA varchar(6) DEFAULT NULL;

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  • how to compare two tables fields name with another value in mysql?

    - by I Like PHP
    I have two tables table_school school_open_time|school_close_time|school_day 8:00 AM | 9:00PM | Monday 10:00 AM | 7:00PM | Wednesday table_college college_open_time|college_close_time|college_day 10:00 AM | 8:00PM | Monday 10:00 AM | 9:00PM | Tuesday 10:00 AM | 5:00PM | Wednesday Now I want to select school_open_time school_close time, college_open_time and college_close_time according to today (means college_day=school_day=today), and also if there is no row for a specific day in any of one table then it display blank field ( LEFT JOIN , I think I can use). Please suggest me best and optimized query for this. UPDATE: if there is no open time and close time for school then college_open_time and college_close_time has to be returned( not to be filled in database,just return) as school_open_time and school_close_time. and there always must be college_open_time and college_close_time for a given day MORE UPDATE: i m using below query SELECT college_open_time,college_close_time ,school_open_time, school_close_time FROM tbl_college LEFT JOIN tbl_school ON school_owner_id=college_owner_id WHERE college_owner_id='".$_session['user_id']."' AND college_day='".date('l',time())."'"; it return single row (left hand having some value and right hand having blank value) when there is no row of a given day in table_school, BUT display seven rows with same value on left hand side(college_open_time, college_close_time) and 6 blank row on right hand side (school_open_time and school_close_time) i need only one row when both table have a row of a given day but using above query take only first row of corresponding table_school where school_owner_id is 50(let), it not see the condition that school_day name should be given day

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  • MySQL only returning one result. Im Baffled.

    - by Tapha
    Here is te code: <?php //Starting session session_start(); //Includes mass includes containing all the files needed to execute the full script //Also shows homepage elements without customs require_once ('includes/mass.php'); $username = $_SESSION['username']; if (isset($username)) { //Query database for the users networths $sq_l = "SELECT * FROM user"; $sql_query_worth = mysql_query($sq_l); while ($row = mysql_fetch_assoc($sql_query_worth)) { $dbusername = $row['username']; } echo $dbusername; } ?>

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  • MySQL - Combine two fields to create a unix timestamp?

    - by Dan
    Hi, I'm trying to retrieve a UNIX timestamp from a query by combining a date and a time field in the table, however it keeps returning as zero. SELECT *, UNIX_TIMESTAMP(startdate starttime) AS start, UNIX_TIMESTAMP(enddate endtime) AS end FROM mytable; Can anyone help me out? Thanks.

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  • How do I update the members of a MySQL SET Type?

    - by MachinationX
    I have a table of values, with one of the columns being of type SET. If it currently has the members ('a', 'b', 'c', 'd'), how do I add 'e' to the possible values? I realize that using a SET type is a little strange, and I'm unclear why one would use it instead of a foreign key to another table with the values of the set, but I didn't design the database in question, and can't change it that much. Thanks for your help!

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  • How to insert the last id from a table into another table in MySQL?

    - by James
    I want to take the id of the most recent item in a database, increment it by one and insert that new id in to another table. I tried: $select = mysql_query("SELECT id FROM tableName ORDER BY id DESC"); while ($return = mysql_fetch_assoc($select)) { $id = $return['id']; $newId = $id++; } mysql_query("INSERT INTO anotherTable (someColumn) VALUES ('$newId')"); But it didn't work. How can this be done?

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  • MYSQL - SQL query Getting single record for the similar records and populating other columns with which has more length

    - by Bujji
    Here is my case , I have a database table with below fields name place_code email phone address details estd others and example data if you look at the above example table First three records are talking about XYZ and place code 1020 . I want create a single record for these three records based on substring(name,1,4) place_code ( I am lucky here for all the similar records satisfies this condition and unique in the table .) For the other columns which record column length has max . For example again for the above 3 records email should be [email protected] , phone should be 657890 and details should be "testdetails" This should be done for all the table . (Some has single records and some has max 10 records ) Any help on query that helps me to get the desired result ? Thank You Regards Kiran

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  • MySQL - accessing a table sum and compare to another table?

    - by assignment_operator
    This is for a homework assignment. I just plain don't understand how to do it. The instructions for this particular question is: List the branch name for all branches that have at least one book that has at least 4 copies on hand. Where the tables in question are: Branch: BranchName | BranchId Henry Downtown | 1 16 Riverview | 2 Henry On The Hill | 3 Inventory: BookId | BranchId | OnHand 1 | 1 | 2 2 | 3 | 4 3 | 1 | 8 4 | 3 | 1 5 | 1 | 2 6 | 2 | 3 From what I understand, I can get the number of OnHand per branch name with: SELECT BranchName, SUM(OnHand) FROM Branch B, Inventory I WHERE B.BranchId = I.BranchId GROUP BY BranchName; but I don't get how I'd do the comparison between the sum of OnHand per branch and 4. Any help would be appreciated, guys!

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  • MYSQL Insert: How to save Query in the database only one time - duplicate key doesn't work!

    - by elmaso
    hello, I want to save a query only one time in the database, this is my code: $querystat = mysql_real_escape_string($_GET['q']); $datetime = time(); if( ($querystat != $_SESSION['prev_search']) OR ( ($datetime - $_SESSION['datetime']) > 60) ) { $insertquery = "INSERT INTO `query` ( `searchquery` , `datetime`) VALUES ( '$querystat' , '$datetime') ON DUPLICATE KEY UPDATE searchquery='$querystat';"; mysql_query($insertquery, $db); } maybe something with == 0 ?

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  • MySQL: How to copy rows, but change a few fields?

    - by Andrew
    I have a large number of rows that I would like to copy, but I need to change one field. I can select the rows that I want to copy: select * from Table where Event_ID = "120" Now I want to copy all those rows and create new rows while setting the Event_ID to 155. How can I accomplish this?

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  • PHP, MySQL - would results-array shuffle be quicker than "select... order by rand()"?

    - by sombe
    I've been reading a lot about the disadvantages of using "order by rand" so I don't need update on that. I was thinking, since I only need a limited amount of rows retrieved from the db to be randomized, maybe I should do: $r = $db->query("select * from table limit 500"); for($i;$i<500;$i++) $arr[$i]=mysqli_fetch_assoc($r); shuffle($arr); (i know this only randomizes the 500 first rows, be it). would that be faster than $r = $db->("select * from table order by rand() limit 500"); let me just mention, say the db tables were packed with more than...10,000 rows. why don't you do it yourself?!? - well, i have, but i'm looking for your experienced opinion. thanks!

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  • MySQL: Query to obtain recipes using all given ingredients.

    - by John_A
    hi I have the following simplified tables: CREATE TABLE recipe(id int, name varchar(25)); CREATE TABLE ingredient(name varchar(25)); CREATE TABLE uses_ingredient(recipe_id int, name varchar(25)); I want to make a query that returns all id's of recipes that contain both Chicken and Cream. I have tried SELECT recipe_id FROM uses_ingredient INNER JOIN (SELECT * FROM ingredient WHERE name="Chicken" OR name="Cream") USING (name) GROUP BY recipe_id HAVING COUNT(recipe_id) >= (SELECT COUNT(*) FROM theme); which gives me :"ERROR 1248 (42000): Every derived table must have its own alias" and is probably wrong too. Next I tried SELECT recipe_id FROM (SELECT * FROM ingredient WHERE name="Chicken" OR name="Cream") AS t INNER JOIN uses_ingredient USING (name) GROUP BY recipe_id HAVING COUNT(recipe_id)>= (SELECT COUNT(*) FROM t); which gives "ERROR 1146 (42S02): Table 'recipedb.t' doesn't exist" I want to avoid creating temporary tables including using ENGINE=MEMORY.

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  • INSERT INTO ... SELECT ... vs dumping/loading a file in MySQL

    - by Daniel Huckstep
    What are the implications of using a INSERT INTO foo ... SELECT FROM bar JOIN baz ... style insert statement versus using the same SELECT statement to dump (bar, baz) to a file, and then insert into foo by loading the file? In my messing around, I haven't seen a huge difference. I would assume the former would use more memory, but the machine that this runs on has 8GB of RAM, and I never even see it go past half used. Are there any huge (or long term) performance implications that I'm not seeing? Advantages/disadvantages of either?

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  • MySQL is there a Single Select to Query Various Unrelated Values from a database?

    - by zzapper
    I saw somewhere what seemed to be nested selects, one "master" select on the "outside" and a series of selects inside- is this possible? I'm not talking about joins as there is particular relation between the selects. I seem not to be explaining myself very well. I want to do a single query which will pull out a series of stats from various tables latest order, latest customer, largest order. Obviously I can do that with a series of selects. The example I saw was something like select ( select ... from tbl_1 where .., select ... from tbl_2 where .., select ... from tbl_3 where .., ... )

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  • Setting an empty default value for a char-column in MySQL?

    - by user281434
    Hi In phpMyAdmin I have a char(32) column that has no default value(ie. Default: None). When I try to insert data through a SQL query, it throws out an error saying that the column "doesn't have a default value". I need it to be empty, so instead I've just set it's default value as "As defined: " and then nothing in the value field. Is this a bad idea? And is it any better than simply throwing in an empty value for the column in the SQL query? Thanks for your time.

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  • MySQL Order By Problem, Why is 1000 being seen as Smaller than 2?

    - by Jack
    I have a strange problem, I am trying to order the output of a set of records by a field called displayOrder. Now even though record A has a displayOrder of 2 and record B has a displayOrder of 1000, record B still shows up before record A. Here's my select statement: SELECT * FROM items ORDER BY displayOrder ASC It works fine until I have a record greater than 9, then 10, 11, 12, etc are seen as smaller than 2, 3, 4 because they start with the number 1. Any way to fox this?

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  • "Remember" last three MySql queries; Cookie, passed variable or other method?

    - by Camran
    I have a classified website, with pretty sophisticated searching, and I am about to implement a function where the last three queries is displayed for the user, so that the user can go back easier through the queries. This because for each query the user has to provide a lot of input. I have four questions for you: I wonder, how can I save the actual query (SELECT * FROM etc etc)...? Do I need to add some form of encryption to be on the safe side? How will this affect performance? (I don't like the fact that cookies slow websites down) Anything else to think about? If you need more input, let me know... Btw, the website is PHP based. Thanks

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