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  • Java regex basic usage problem

    - by Ernelli
    The following code works: String str= "test with foo hoo"; Pattern pattern = Pattern.compile("foo"); Matcher matcher = pattern.matcher(str); if(matcher.find()) { ... } But this example does not: if(Pattern.matches("foo", str)) { ... } And neither this version: if(str.matches("foo")) { ... } In the real code, str is a chunk of text with multiple lines if that is treated differently by the matcher, also in the real code, replace will be used to replace a string of text. Anyway, it is strange that it works in the first version but not the other two versions.

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  • Problem creating folder?

    - by Starx
    I am trying to create folder like this $destination = "../enumesis.com/_pcode/../_compile"; mkdir($destination); But this gives error UPDATE What i am doing is, taking ../enumesis.com/_pcode as input from user and I want to create a folder outside the _pcode Directory Here is my error Warning: mkdir() [function.mkdir]: No such file or directory in G:\wamp\www\tools\compile.php on line 57 ../enumesis.com/_pcode/../_compile

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  • Problem with setVisible (true)

    - by Jessy
    The two examples shown below are same. Both are supposed to produce same result e.g. generate the coordinates of images displayed on JPanel. Example 1, works perfectly (print the coordinates of images), however example 2 returning 0 for the coordinate. I was wondering why because, I have put the setvisible (true) after adding the panel, in both examples. The only difference is that example 1 used extends JPanel and example 2 extends JFrame EXAMPLE 1: public class Grid extends JPanel{ public static void main(String[] args){ JFrame jf=new JFrame(); jf.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); final Grid grid = new Grid(); jf.add(grid); jf.pack(); Component[] components = grid.getComponents(); for (Component component : components) { System.out.println("Coordinate: "+ component.getBounds()); } jf.setVisible(true); } } EXAMPLE 2: public class Grid extends JFrame { public Grid () { setLayout(new GridBagLayout()); GridBagLayout m = new GridBagLayout(); Container c = getContentPane(); c.setLayout (m); GridBagConstraints con = new GridBagConstraints(); //construct the JPanel pDraw = new JPanel(); ... m.setConstraints(pDraw, con); pDraw.add (new GetCoordinate ()); // call new class to generate the coordinate c.add(pDraw); pack(); setVisible(true); } public static void main(String[] args) { new Grid(); } }

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  • crazy jquery problem working with mozilla and not in others

    - by moustafa
    i have this code $(function() { $('#ans_vote a span').click(function(){alert('working');return false;});}); and this html <div id="ans_vote"> <a href='#'><span>one</span></a> </div> <div id="ans_vote"> <a href='#'><span>two</span></a> </div> when click one and two in mozilla its working but when click one in ie its working but when click two its not working

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  • Problem writing HTML content to Word document in ASP.NET

    - by saran
    I am trying to export the HTML page contents to Word. My Html display page is: What is your favourite color? NA List the top three school ? one National two Devs three PS And a button for click event. The button click event will open MS word and paste the page contents in word. The word page contains the table property of html design page. It occurs only in Word 2003. But in word 2007 the word document contains the text with out table property. How can I remove this table property in word 2003. I am not able to add the snapshots. Else i will make you clear. I am designing the web page by aspx. I am exporting the web page content by the following code. protected void Button1_Click(object sender, EventArgs e) { Response.ContentEncoding = System.Text.Encoding.UTF7; System.Text.StringBuilder SB = new System.Text.StringBuilder(); System.IO.StringWriter SW = new System.IO.StringWriter(); System.Web.UI.HtmlTextWriter htmlTW = new System.Web.UI.HtmlTextWriter(SW); tbl.RenderControl(htmlTW); string strBody = "<html>" + "<body>" + "<div><b>" + htmlTW.InnerWriter.ToString() + "</b></div>" + "</body>" + "</html>"; Response.AppendHeader("Content-Type", "application/msword"); Response.AppendHeader("Content-disposition", "attachment; filename=" + fileName); Response.ContentEncoding = System.Text.Encoding.UTF7; string fileName1 = "C://Temp/Excel" + DateTime.Now.Millisecond.ToString(); BinaryWriter writer = new BinaryWriter(File.Open(fileName1, FileMode.Create)); writer.Write(strBody); writer.Close(); FileStream fs = new FileStream(fileName1, FileMode.Open, FileAccess.Read); byte[] renderedBytes; // Create a byte array of file stream length renderedBytes = new byte[fs.Length]; //Read block of bytes from stream into the byte array fs.Read(renderedBytes, 0, System.Convert.ToInt32(fs.Length)); //Close the File Stream fs.Close(); FileInfo TheFile = new FileInfo(fileName1); if (TheFile.Exists) { File.Delete(fileName1); } Response.BinaryWrite(renderedBytes); Response.Flush(); Response.End(); }

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  • Edit problem on asp.net mvc

    - by ognjenb
    <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<IEnumerable<MvcKVteam.Models.transporter>>" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server"> Transporters </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <h2>Transporters</h2> <table class="data-table" id=""> <tr> <th> Id </th> <th> ContactId </th> <th> Name </th> <th> Notes </th> <th> PreferredCurrency </th> <th> PriceList </th> <th> SeviceTypeAvailible </th> <th> Contact </th> </tr> <% foreach (var item in Model) { %> <tr> <td> <%= Html.Encode(item.Id) %> </td> <td> <%= Html.Encode(item.ContactId) %> </td> <td> <%= Html.Encode(item.Name) %> </td> <td> <%= Html.Encode(item.Notes) %> </td> <td> <%= Html.Encode(item.PreferredCurrency) %> </td> <td> <%= Html.Encode(item.PriceList) %> </td> <td> <%= Html.Encode(item.SeviceTypeAvailible) %> </td> <td> <%= Html.ActionLink("View contact info", "Edit", new { id = item.ContactId }) %> </td> </tr> <% } %> </table> <p> <%= Html.ActionLink("Create New", "Create") %> </p> This action for Edit: public ActionResult Edit(int id) { var FilesQuery1 = from i in FilesEntities.contact where i.Id == id select i; return View(FilesQuery1); } When click on "View contact info" link I have this error: The model item passed into the dictionary is of type 'System.Data.Objects.ObjectQuery`1[MvcKVteam.Models.contact]', but this dictionary requires a model item of type 'MvcKVteam.Models.contact'.

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  • problem with VS 2005

    - by persistence911
    I have a program I converted from vs 2003 to vs 2005 . It has worked fine so far until I changed one of the Dlls. Funny enough I had just One error . Maximum Number of errrors Exceeded and No other indication of other Error. Please I have been trying to fix these for like 2 days now.

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  • Creating SSL on IIS - Remote access problem

    - by ile
    I followed these instructions: http://www.visualwin.com/SelfSSL/ When I type https://localhost/ than it works, but when I try to access it remotely (i set up my router to port forward to localhost), for example https://myip the page does not load. Also, I noticed one other thing. When I access localhost locally then I am asked to enter user/pass, but if I access remotely the I get the following warning: Under Construction The site you were trying to reach does not currently have a default page. It may be in the process of being upgraded and configured. ... I don't know if it is related with this but I hope someone know the answer. Thanks, Ile

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  • How could i configure Rmagick gem or ImageMagick to solve following problem

    - by chs
    I am getting following error while running local script/server of my rails project /usr/lib/ruby/gems/1.8/gems/rmagick-2.13.1/lib/RMagick2.so: This installation of RMagick was configured with ImageMagick 6.6.1 but ImageMagick 6.4.5 is in use. (RuntimeError) and RMagick2.so is blank. and identify --version command shows following result Version: ImageMagick 6.6.1-10 2010-05-21 Q8 http://www.imagemagick.org So, my question is how and where should i make changes to work it fine; I had already reinstall ImageMagick but didnt work for me, so any suggestions Thanks in advance

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  • memory problem with metapost

    - by yCalleecharan
    Hi, I'm using gnuplot to plot a graph to the mp format and then I'm converting it to eps via the command: mpost --sprologues=3 -soutputtemplate=\"%j-%c.eps\" myfigu.mp But I don't get the eps output; instead I get this message: This is MetaPost, version 1.208 (kpathsea version 3.5.7dev) (mem=mpost 2009.12.12) 6 MAY 2010 23:16 **myfigu.mp (./myfigu.mp ! MetaPost capacity exceeded, sorry [main memory size=3000000]. _wc-withpen .currentpen.withcolor.currentcolor gpdraw-...ptpath[(EXPR0)]_sms((EXPR1),(EXPR2))_wc .else:_ac.contour.ptpath[(... l.48052 gpdraw(0,517.1a,166.4b) ; If you really absolutely need more capacity, you can ask a wizard to enlarge me. How do I tweak in order to get more memory. The file from which I'm plotting has two columns of 189,200 values each. These values are of type long double (output from a C program). The text file containing these two column values is about 6 MB. Thanks a lot...

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  • Problem setting up Direct X for C++

    - by Josh
    I've downloaded Direct X SDK from the microsoft website but when I try to compile my code i'm getting this error: Error 1 error LNK2019: unresolved external symbol _Direct3DCreate9@4 referenced in function "void __cdecl initD3D(struct HWND__ *)" (?initD3D@@YAXPAUHWND__@@@Z) C:\Users\Josh\Desktop\Tutorial\Tutorial\Tutorial.obj Tutorial I have added Direct X to my C++ build directories like that: $(DXSDK_DIR)include $(DXSDK_DIR)Lib\x64 I've googled it and found out that most of the time people were forgetting this line: #pragma comment (lib, "d3dx9.lib") But it's there for me here are my includes and lib: #include <windows.h> #include <windowsx.h> #include <d3d9.h> #include <d3dx9.h> #pragma comment (lib, "d3d9.lib") #pragma comment (lib, "d3dx9.lib") Can anyone help me with this? I'm using Visual studio 2010 Professional on win7 x64

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  • jquery problem with simple code

    - by moustafa
    why this code is not working var name = $("#name").val(); var email = $("#email").val(); var web = $("#web").val(); var comment = $("#comment").val(); if(name.length < 5){ $("#name").css("border-color","red"); } elseif (email.length < 5) { $("#email").css("border-color","red"); } elseif (web.length < 5) { $("#web").css("border-color","red"); } elseif (comment.length < 10) { $("#comment").css("border-color","red"); }else{ alert('ok'); } and each val for one like this <input id="name" type="text" size="24" />

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  • Strange Problem with RPy2

    - by jrara
    Hello, After installing RPy2 from http://rpy.sourceforge.net/rpy2.html I'm trying to use it in Python 2.6 IDLE but I'm getting this error: >>> import rpy2.robjects as robjects >>> robjects.r['pi'] <RVector - Python:0x0121D8F0 / R:0x022A1760> What I'm doing wrong?

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  • Custom field type:problem in page layout

    - by AB
    I have created a custom field type and its working properly but when I am adding it on page layout ,its not displaying any data in there.I am getting data from one of the list.I have added that field in list and its displaying all the data I want to select but on page layout its blank..... Any idea where i m getting wrong...?

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  • Facebook Graph API authorization problem

    - by kujawk
    If I load the following URL in Firefox and login to Facebook, I'm getting a page displaying "An invalid next or cancel parameter was specified." https://graph.facebook.com/oauth/authorize?client_id=c8caf78d724d142ee82334131ef5c9ce&redirect_uri=http://www.facebook.com/connect/login_success.html&type=user_agent&display=touch&scope=offline_access,publish_stream But if I change the display parameter to display=page I no longer get this error. Any ideas as to why?

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  • boost::asio::async_resolve Problem

    - by Moo-Juice
    Hi All, I'm in the process of constructing a Socket class that uses boost::asio. To start with, I made a connect method that took a host and a port and resolved it to an IP address. This worked well, so I decided to look in to async_resolve. However, my callback always gets an error code of 995 (using the same destination host/port as when it worked synchronously). code: Function that starts the resolution: // resolve a host asynchronously template<typename ResolveHandler> void resolveHost(const String& _host, Port _port, ResolveHandler _handler) const { boost::asio::ip::tcp::endpoint ret; boost::asio::ip::tcp::resolver::query query(_host, boost::lexical_cast<std::string>(_port)); boost::asio::ip::tcp::resolver r(m_IOService); r.async_resolve(query, _handler); }; // eo resolveHost Code that calls this function: void Socket::connect(const String& _host, Port _port) { // Anon function for resolution of the host-name and asynchronous calling of the above auto anonResolve = [this](const boost::system::error_code& _errorCode, boost::asio::ip::tcp::resolver_iterator _epIt) { // raise event onResolve.raise(SocketResolveEventArgs(*this, !_errorCode ? (*_epIt).host_name() : String(""), _errorCode)); // perform connect, calling back to anonymous function if(!_errorCode) connect(*_epIt); }; // Resolve the host calling back to anonymous function Root::instance().resolveHost(_host, _port, anonResolve); }; // eo connect The message() function of the error_code is: The I/O operation has been aborted because of either a thread exit or an application request And my main.cpp looks like this: int _tmain(int argc, _TCHAR* argv[]) { morse::Root root; TextSocket s; s.connect("somehost.com", 1234); while(true) { root.performIO(); // calls io_service::run_one() } return 0; } Thanks in advance!

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  • Java MySQL Query Problem MySQLSyntaxErrorException When Creating a Table

    - by Aqib Mushtaq
    I fairly new to MySQL with Java, but I have executed a few successful INSERT queries however cannot seem to get the CREATE TABLE query to execute without getting the 'MySQLSyntaxErrorException' exception. My code is as follows: import java.sql.*; Statement stmt; Class.forName("com.mysql.jdbc.Driver"); String url = "jdbc:mysql://localhost:3306/mysql"; Connection con = DriverManager.getConnection(url, "root", "password"); stmt = con.createStatement(); String tblSQL = "CREATE TABLE IF NOT EXISTS \'dev\'.\'testTable\' (\n" + " \'id\' int(11) NOT NULL AUTO_INCREMENT,\n" + " \'date\' smallint(6) NOT NULL\n" + ") ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;"; stmt.executeUpdate(tblSQL); stmt.close(); con.close(); And the error is as follows: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''dev'.'testTable' ( 'id' int(11) NOT NULL AUTO_INCREMENT, 'date' smallint(6) N' at line 1 I would appreciate it if anyone could spot the mistake in this query, as I've tried executing this within phpMyAdmin and it works as it should. Thanks in advance.

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  • Using inheritance and polymorphism to solve a common game problem

    - by Barry Brown
    I have two classes; let's call them Ogre and Wizard. (All fields are public to make the example easier to type in.) public class Ogre { int weight; int height; int axeLength; } public class Wizard { int age; int IQ; int height; } In each class I can create a method called, say, battle() that will determine who will win if an Ogre meets and Ogre or a Wizard meets a Wizard. Here's an example. If an Ogre meets an Ogre, the heavier one wins. But if the weight is the same, the one with the longer axe wins. public Ogre battle(Ogre o) { if (this.height > o.height) return this; else if (this.height < o.height) return o; else if (this.axeLength > o.axeLength) return this; else if (this.axeLength < o.axeLength) return o; else return this; // default case } We can make a similar method for Wizards. But what if a Wizard meets an Ogre? We could of course make a method for that, comparing, say, just the heights. public Wizard battle(Ogre o) { if (this.height > o.height) return this; else if (this.height < o.height) return o; else return this; } And we'd make a similar one for Ogres that meet Wizard. But things get out of hand if we have to add more character types to the program. This is where I get stuck. One obvious solution is to create a Character class with the common traits. Ogre and Wizard inherit from the Character and extend it to include the other traits that define each one. public class Character { int height; public Character battle(Character c) { if (this.height > c.height) return this; else if (this.height < c.height) return c; else return this; } } Is there a better way to organize the classes? I've looked at the strategy pattern and the mediator pattern, but I'm not sure how either of them (if any) could help here. My goal is to reach some kind of common battle method, so that if an Ogre meets an Ogre it uses the Ogre-vs-Ogre battle, but if an Ogre meets a Wizard, it uses a more generic one. Further, what if the characters that meet share no common traits? How can we decide who wins a battle?

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  • Spring Dispatcher Servlet Not Found Problem

    - by hamam
    I'm trying to build a simple spring web application but I get the following error when I run it on Apache Tomcat 6.0 Class Not Found Exception org.springframework.web.servlet.DispatcherServlet I'm using maven to handle libraries. At first I thought it was maven's fault but it adds spring and other libraries succesfully. I tried to import "org.springframework.web.servlet.DispatcherServlet" in a source file and my project has the right package and classes. My development environment : Ubuntu 10.4 Eclipse IDE Tomcat 6.0 I'd appreciate any help

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  • problem with fork()

    - by john
    I'm writing a shell which forks, with the parent reading the input and the child process parsing and executing it with execvp. pseudocode of main method: do{ pid = fork(); print pid; if (p<0) { error; exit; } if (p>0) { wait for child to finish; read input; } else { call function to parse input; exit; } }while condition return; what happens is that i never seem to enter the child process (pid printed is always positive, i never enter the else). however, if i don't call the parse function and just have else exit, i do correctly enter parent and child alternatingly. full code: int main(int argc, char *argv[]){ char input[500]; pid_t p; int firstrun = 1; do{ p = fork(); printf("PID: %d", p); if (p < 0) {printf("Error forking"); exit(-1);} if (p > 0){ wait(NULL); firstrun = 0; printf("\n> "); bzero(input, 500); fflush(stdout); read(0, input, 499); input[strlen(input)-1] = '\0'; } else exit(0); else { if (parse(input) != 0 && firstrun != 1) { printf("Error parsing"); exit(-1); } exit(0); } }while(strcmp(input, "exit") != 0); return 0; }

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  • Transaction & Locks Problem

    - by jay
    with in do transaction, i defined a label and in this label i am accessing a table with exclusive-lock.and at the end of label i have done all the changes in that table. bt now i am with in transaction block. Now, i tried to access that same table in another session.then it show an error, Table used by another user. So is it possible that, can we release teh table with in transaction,so another user can access it. Exe Session1) DO TRANSACTION: loopb: repeat: -- --------------------- control is here right now. end. /repeat/ -- end /do transaction/ Session2) I tried to access same table,bt it show an error,that table locked by another user.

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  • PHP - DOM class - numbered entities and encodings problem

    - by user343607
    Hi guys, I'm having some difficult with PHP DOM class. I am making a sitemap script, and I need the output of $doc-saveXML() to be like <?xml version="1.0" encoding="UTF-8"?> <root> <url> <loc>http://www.somesite.com/servi&#xE7;os/redesign</loc> </url> </root> or <?xml version="1.0" encoding="UTF-8"?> <root> <url> <loc>http://www.somesite.com/servi&#231;os/redesign</loc> </url> </root> but I am getting: <?xml version="1.0" encoding="UTF-8"?> <root> <url> <loc>http://www.somesite.com/servi&amp;#xE7;os/redesign</loc> </url> </root> This is the closet I could get, using a replace named to numbered entities function. I was also able to reproduce <?xml version="1.0" ?> <root> <url> <loc>http://www.somesite.com/servi&amp;#xE7;os/redesign</loc> </url> </root> But without the encoding specified. The best solution (the way I think the code should be written) would be: <?php $myArray = array(); // do some stuff to populate the with URL strings $doc = new DOMDocument('1.0', 'UTF-8'); // here we modify some property. Maybe is the answer I am looking for... $urlset = doc->createElement("urlset"); $urlset = $doc->appendChild($urlset); foreach($myArray as $address) { $url = $doc->createElement("url"); $url = $urlset->appendChild($url); $loc = $doc->createElement("loc"); $loc = $url->appendChild($loc); $valueContent = $doc->createTextNode($value); $valueContent = $loc->appendChild($address); } echo $doc->saveXML(); ?> Notes: Server response header contains charset as UTF-8; PHP script is saved in UTF-8; URLs read are UTF-8 strings; Above script contains encoding declaration on DOMDocument constructor, and does not use any convert functions, like htmlentities, urlencode, utf8_encode... I've tried changing the DOMDocument properties DOMDocument::$resolveExternals and DOMDocument::$substituteEntities values. None combinations worked. And yes, I know I can made all process without specifying the character set on DOMDocument constructor, dump string content into a variable and make a very simple string substitution with string replace functions. This works. But I would like to know where I am slipping, how can this be made using native API's and settings, or even if this is possible. Thanks in advance.

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  • Problem with "scopes" of variables in try catch blocks in Java

    - by devoured elysium
    Could anyone explain me why in the last lines, br is not recognized as variable? I've even tried putting br in the try clause, setting it as final, etc. Does this have anything to do with Java not support closures? I am 99% confident similar code would work in C#. private void loadCommands(String fileName) { try { final BufferedReader br = new BufferedReader(new FileReader(fileName)); while (br.ready()) { actionList.add(CommandFactory.GetCommandFromText(this, br.readLine())); } } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { if (br != null) br.close(); //<-- This gives error. It doesn't // know the br variable. } } Thanks

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