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  • PHP - Open or copy a file when knowing only part of its name?

    - by Gary Willoughby
    I have a huge repository of files that are ordered by numbered folders. In each folder is a file which starts with a unique number then an unknown string of characters. Given the unique number how can i open or copy this file? for example: I have been given the number '7656875' and nothing more. I need to interact with a file called '\server\7656800\7656875 foobar 2x4'. how can i achieve this using PHP?

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  • Are there any way to link my program with Wine-compiled part?

    - by seas
    I am trying to use windows dll functionality in Linux. My current solution is a compilation of a separate wine application, that uses dll and transfer requests/responses between dll and main application over IPC. This works, but is a real overhead comparing to a simple dll calls. I see that wine-compiled program usually is a bootstrapping-script and some .so, which (according to file utility) is normal linux dynamically linked library. Are there any way to link that .so directly to my application? Are there any manual?

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  • What happens when I instantiate class in Python?

    - by Konstantin
    Could you clarify some ideas behind Python classes and class instances? Consider this: class A(): name = 'A' a = A() a.name = 'B' # point 1 (instance of class A is used here) print a.name print A.name prints: B A if instead in point 1 I use class name, output is different: A.name = 'B' # point 1 (updated, class A itself is used here) prints: B B Even if classes in Python were some kind of prototype for class instances, I'd expect already created instances to remain intact, i.e. output like this: A B Can you explain what is actually going on?

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  • Magic Method __set() on a Instantiated Object

    - by streetparade
    Ok i have a problem, sorry if i cant explaint it clear but the code speaks for its self. i have a class which generates objects from a given class name; Say we say the class is Modules: public function name($name) { $this->includeModule($name); try { $module = new ReflectionClass($name); $instance = $module->isInstantiable() ? $module->newInstance() : "Err"; $this->addDelegate($instance); } catch(Exception $e) { Modules::Name("Logger")->log($e->getMessage()); } return $this; } The AddDelegate Method: protected function addDelegate($delegate) { $this->aDelegates[] = $delegate; } The __call Method public function __call($methodName, $parameters) { $delegated = false; foreach ($this->aDelegates as $delegate) { if(class_exists(get_class($delegate))) { if(method_exists($delegate,$methodName)) { $method = new ReflectionMethod(get_class($delegate), $methodName); $function = array($delegate, $methodName); return call_user_func_array($function, $parameters); } } } The __get Method public function __get($property) { foreach($this->aDelegates as $delegate) { if ($delegate->$property !== false) { return $delegate->$property; } } } All this works fine expect the function __set public function __set($property,$value) { //print_r($this->aDelegates); foreach($this->aDelegates as $k=>$delegate) { //print_r($k); //print_r($delegate); if (property_exists($delegate, $property)) { $delegate->$property = $value; } } //$this->addDelegate($delegate); print_r($this->aDelegates); } class tester { public function __set($name,$value) { self::$module->name(self::$name)->__set($name,$value); } } Module::test("logger")->log("test"); // this logs, it works echo Module::test("logger")->path; //prints /home/bla/test/ this is also correct But i cant set any value to class log like this Module::tester("logger")->path ="/home/bla/test/log/"; The path property of class logger is public so its not a problem of protected or private property access. How can i solve this issue? I hope i could explain my problem clear.

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  • SQL Database Schema Design For Large 3 Billion Relationship Database.

    - by K-Bell
    Get your geek on. Can you solve this? I am designing a products database for SQL Server 2008 R2 Ed. (not Enterprise Ed.) that will be used to store custom product configurations for over 30,000 distinct products. The database will have up to 500 users at a time. Here is the design problem… Each Product has a collection of Parts (up to 50 parts per product). So if I have 30,000 Products and each of them can have up to 50 Parts, that’s 1.5 million distinct Product-to-Part relationships …or as an equation… 30,000 (Products) X 50 (Parts) = 1.5 million Product-to-Parts records. …and If… Each Part can have up to 2000 finish options (A finish is a paint color). NOTE: Only one finish will be selected by a user at run-time. The 2000 finish options I need to store are the allowed options for a specific part on a specific product. So if I have 1.5 million distinct product-to-part relationships/records and each of those parts can have up to 2,000 finishes that is 3 billion allowable product-to-part-to finish relationships/records …or as an equation… 1.5 million (Parts) x 2,000 (Finishes) = 3 Billion Product-to-Part-to-Finishes records. How can I design this database so that I can execute fast and efficient queries for a specific product and return its list of Parts and all the allowable Finishes for each part without 3 Billion Product-to-Part-to-Finish records? Read time is more important then write time. Please post your thoughts/suggestions if you have experience with large databases. Thanks!

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  • How can I store large amount of data from a database to XML (speed problem, part three)?

    - by Andrija
    After getting some responses, the current situation is that I'm using this tip: http://www.ibm.com/developerworks/xml/library/x-tipbigdoc5.html (Listing 1. Turning ResultSets into XML), and XMLWriter for Java from http://www.megginson.com/downloads/ . Basically, it reads date from the database and writes them to a file as characters, using column names to create opening and closing tags. While doing so, I need to make two changes to the input stream, namely to the dates and numbers. // Iterate over the set while (rs.next()) { w.startElement("row"); for (int i = 0; i < count; i++) { Object ob = rs.getObject(i + 1); if (rs.wasNull()) { ob = null; } String colName = meta.getColumnLabel(i + 1); if (ob != null ) { if (ob instanceof Timestamp) { w.dataElement(colName, Util.formatDate((Timestamp)ob, dateFormat)); } else if (ob instanceof BigDecimal){ w.dataElement(colName, Util.transformToHTML(new Integer(((BigDecimal)ob).intValue()))); } else { w.dataElement(colName, ob.toString()); } } else { w.emptyElement(colName); } } w.endElement("row"); } The SQL that gets the results has the to_number command (e.g. to_number(sif.ID) ID ) and the to_date command (e.g. TO_DATE (sif.datum_do, 'DD.MM.RRRR') datum_do). The problems are that the returning date is a timestamp, meaning I don't get 14.02.2010 but rather 14.02.2010 00:00:000 so I have to format it to the dd.mm.yyyy format. The second problem are the numbers; for some reason, they are in database as varchar2 and can have leading zeroes that need to be stripped; I'm guessing I could do that in my SQL with the trim function so the Util.transformToHTML is unnecessary (for clarification, here's the method): public static String transformToHTML(Integer number) { String result = ""; try { result = number.toString(); } catch (Exception e) {} return result; } What I'd like to know is a) Can I get the date in the format I want and skip additional processing thus shortening the processing time? b) Is there a better way to do this? We're talking about XML files that are in the 50 MB - 250 MB filesize category.

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  • cannot set a variable to base on user input post method

    - by user1318960
    Hello i´m trying to set info from a post method into a variable that sets a session named name the value that the user input. I get the following error: Notice: Undefined index: name in F:\xampp\htdocs\Impossible game\index.php on line 18 This is line 18: $session = $_POST['name']; <form action="ms1.php" method="POST"> Name <input type="text" name="name"> <input type="Submit" value="Begin"> </form> <?php $session = $_POST['name']; session_start(); $_SESSION['name'] = $session;

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  • KnockoutJS showing a sorted list by item category

    - by Darksbane
    I just started learning knockout this week and everything has gone well except for this one issue. I have a list of items that I sort multiple ways but one of the ways I want to sort needs to have a different display than the standard list. As an example lets say I have this code var BetterListModel = function () { var self = this; food = [ { "name":"Apple", "quantity":"3", "category":"Fruit", "cost":"$1", },{ "name":"Ice Cream", "quantity":"1", "category":"Dairy", "cost":"$6", },{ "name":"Pear", "quantity":"2", "category":"Fruit", "cost":"$2", },{ "name":"Beef", "quantity":"1", "category":"Meat", "cost":"$3", },{ "name":"Milk", "quantity":"5", "category":"Dairy", "cost":"$4", }]; self.allItems = ko.observableArray(food); // Initial items // Initial sort self.sortMe = ko.observable("name"); ko.utils.compareItems = function (l, r) { if (self.sortMe() =="cost"){ return l.cost > r.cost ? 1 : -1 } else if (self.sortMe() =="category"){ return l.category > r.category ? 1 : -1 } else if (self.sortMe() =="quantity"){ return l.quantity > r.quantity ? 1 : -1 }else { return l.name > r.name ? 1 : -1 } }; }; ko.applyBindings(new BetterListModel()); and the HTML <p>Your values:</p> <ul class="deckContents" data-bind="foreach:allItems().sort(ko.utils.compareItems)"> <li><div style="width:100%"><div class="left" style="width:30px" data-bind="text:quantity"></div><div class="left fixedWidth" data-bind="text:name"></div> <div class="left fixedWidth" data-bind="text:cost"></div> <div class="left fixedWidth" data-bind="text:category"></div><div style="clear:both"></div></div></li> </ul> <select data-bind="value:sortMe"> <option selected="selected" value="name">Name</option> <option value="cost">Cost</option> <option value="category">Category</option> <option value="quantity">Quantity</option> </select> </div> So I can sort these just fine by any field I might sort them by name and it will display something like this 3 Apple $1 Fruit 1 Beef $3 Meat 1 Ice Cream $6 Dairy 5 Milk $4 Dairy 2 Pear $2 Fruit Here is a fiddle of what I have so far http://jsfiddle.net/Darksbane/X7KvB/ This display is fine for all the sorts except the category sort. What I want is when I sort them by category to display it like this Fruit 3 Apple $1 Fruit 2 Pear $2 Fruit Meat 1 Beef $3 Meat Dairy 1 Ice Cream $6 Dairy 5 Milk $4 Dairy Does anyone have any idea how I might be able to display this so differently for that one sort?

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  • Struts2 Hibernate Login with User table and group table

    - by J2ME NewBiew
    My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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  • Can a MAC address be used as a reliable part of a rights management (DRM) scheme?

    - by Jarrod Mosen
    We're currently writing some software that we want to protect. We thought that registering a user's MAC address in a database upon activation of the software seemed viable; we can profile and grab that with a Java applet, (is there a better way?) so getting it isn't too much of a problem. However, we want their computer to only run the application, and download application files/updates from the server when their MAC address has been verified with their one on-file. We understand that this means a lockdown to one computer, but special changes can be made on request. What would be the best way to verify their MAC address, to see if it exists in the database, and then serve them the files to run the application? (And to simply run it on subsequent requests, to prevent re-downloading.)

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  • How do I select the last child of a div with only a certain name using only CSS?

    - by Jared
    Hello, I have been using the following CSS to apply an effect at the bottom of elements in a menu: .leftMenuProductWrapper div:last-child{margin-bottom:20px;} This works fine initially, however after adding more elements in the menu, I realized it was a problem. I really only want to select the last div with .leftMenuProductButton within .leftMenuProductWrapper Anyway to do this without using Jquery, just pure CSS?

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  • How do I use the Enum value from a class in another part of code?

    - by ChiggenWingz
    Coming from a C# background from a night course at a local college, I've sort of started my way in C++. Having a lot pain getting use to the syntax. I'm also still very green when it comes to coding techniques. From my WinMain function, I want to be able to access a variable which is using an enum I declared in another class. (inside core.h) class Core { public: enum GAME_MODE { INIT, MENUS, GAMEPLAY }; GAME_MODE gameMode; Core(); ~Core(); ...OtherFunctions(); }; (inside main.cpp) Core core; int WINAPI WinMain(...) { ... startup code here... core.gameMode = Core.GAME_MODE.INIT; ...etc... } Basically I want to set that gameMode to the enum value of Init or something like that from my WinMain function. I want to also be able to read it from other areas. I get the error... expected primary-expression before '.' token If I try to use core.gameMode = Core::GAME_MODE.INIT;, then I get the same error. I'm not fussed about best practices, as I'm just trying to get the basic understanding of passing around variables in C++ between files. I'll be making sure variables are protected and neatly tucked away later on once I am use to the flexibility of the syntax. If I remember correctly, C# allowed me to use Enums from other classes, and all I had to do was something like Core.ENUMNAME.ENUMVALUE. I hope what I'm wanting to do is clear :\ As I have no idea what a lot of the correct terminology is.

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  • Problem formatting in Eclipse

    - by fastcodejava
    I have a method in Eclipse as below. public String toString() { return "HouseVo [ " + "Name : " + this.name == null ? "" : this.name + "Address : " + this.address == null ? "" : this.address; } When I format it becomes: return "HouseVo [ " + "Name : " + this.name == null ? "" : this.name + "Address : " + this.address == null ? "" : this.address; Any way to fix it so it correctly formats?

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  • How can I right a regular expression to check if the 2 properties in an asp.net control have the same name?

    - by xaisoft
    I have the following asp.net custom validator: <asp:CustomValidator runat="server" ClientValidationFunction="valUCRRequired" ID="valUCRRequired" ErrorMessage="Field 7-Date/Time Between is Required" ControlToValidate="DTE_FROM" /> Notice that the ID and ClientValidationFunction have the same value. I want to do a regular expression search where they are the same. Right now, I am just searching for all CustomValidators.

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  • Android Organizing Strings.xml

    - by Neb
    I'm making an android app and since I've just started I want to try get the most organised code/resources. In my strings.xml file so far I have this: <?xml version="1.0" encoding="utf-8"?> <resources> <string name="app_name">GameController</string> <string name="stop">Stop</string> <string name="start">Start</string> <string name="preferences">Preferences</string> <string name="back">Back</string> </resources> All of the strings except app_name are used in an options menu. But since I will be adding much more strings I was thinking that it might be better to do something like this: <?xml version="1.0" encoding="utf-8"?> <resources> <string name="app_name">GameController</string> <string name="menu_stop">Stop</string> <string name="menu_start">Start</string> <string name="menu_preferences">Preferences</string> <string name="menu_back">Back</string> </resources> Is it the best way or should I use another system?

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  • Retrieving xml value into a string

    - by DelvinK
    Hello, In the following XML structure how do i retrieve the name value and put this into a string? (i am using a XPathNavigator in my method) <testsystem> <test> <name>one</name> </test> </testsystem> I was able to get a attribute with a syntax alike this: (but when changing the xml struture it no longer holds a attribute value) string name = nav.GetAttribute("name", "") But have no luck getting the value with a nav as of yet. The purpose is to be able to use it for the following object so i can put name into it. test t = new test() { Name = name, Questions= new List<Questions>() }; Best regards.

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  • What do you name the "other" kind of view-model in an MVVM project?

    - by DanM
    With MVVM, I think of a view-model as a class that provides all the data and commands that a view needs to bind to. But what happens when I have a database entity object, say a Customer, and I want to build a class that shapes or flattens the Customer class for use in a data grid. For example, maybe this special Customer object would have a property TotalOrders, which is actually calculated using a join with a collection of Order entities. My question is, what do I call this special Customer class? In other situations, I'd be tempted to call it a CustomerViewModel, but I feel like "overloading" the notion of a view-model like this would be confusing in an MVVM project. What would you suggest?

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