Search Results

Search found 55732 results on 2230 pages for 'php html'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 247/2230 | < Previous Page | 243 244 245 246 247 248 249 250 251 252 253 254  | Next Page >

  • What to know - for building a form with PHP and MySQL

    - by Tal Galili
    Hello all, I have three weeks to perform the following basic task. I wish to create an online form in PHP that will get 5 numbers and with them: save the numbers to a MySQL DB do a simple computation on the numbers and return them as an output to the visitor I already have a domain, hosting and a MySQL database+user. I don't know PHP, or SQL or databases. I do have prior knowledge in C and R (which means I have some of the basics of programming, and I am not intimidated of a new languages). My question are: Am I missing something? is there some other skill I should have for this task that I don't know of? What is a good way to learn the skills needed for the task I described? Hope the question isn't too basic/general. Thanks!

    Read the article

  • Creating thumbnails PHP problem

    - by Wayne
    I have this source code where I got it from net tutsplus. I have configured it and made it work in one PHP file. It does work by transferring the original image, but it does not generate to the thumbnails folder. <?php $final_width_of_image = 100; $path_to_image_directory = "../../img/events/" . urldecode($_GET['name']) . "/"; $path_to_thumbs_directory = "../../img/events/" . urldecode($_GET['name']) . "/thumbnails/"; function createThumbnail($filename) { if(preg_match('/[.](jpg)$/', $filename)) { $im = imagecreatefromjpeg($path_to_image_directory . $filename); } elseif(preg_match('/[.](gif)$/', $filename)) { $im = imagecreatefromgif($path_to_image_directory . $filename); } elseif(preg_match('/[.](png)$/', $filename)) { $im = imagecreatefrompng($path_to_image_directory . $filename); } $ox = imagesx($im); $oy = imagesy($im); $nx = $final_width_of_image; $ny = floor($oy * ($final_width_of_image / $ox)); $nm = imagecreatetruecolor($nx, $ny); imagecopyresized($nm, $im, 0,0,0,0,$nx,$ny,$ox,$oy); imagejpeg($nm, $path_to_thumbs_directory . $filename); $tn = '<img src="' . $path_to_thumbs_directory . $filename . '" alt="image" />'; echo $tn; } if(isset($_FILES['fupload'])) { if(preg_match('/[.](jpg)|(gif)|(png)$/', $_FILES['fupload']['name'])) { $filename = $_FILES['fupload']['name']; $source = $_FILES['fupload']['tmp_name']; $target = $path_to_image_directory . $filename; move_uploaded_file($source, $target); createThumbnail($filename); } } ?> Basically it is supposed to generate a thumbnail of the uploaded image and store the original image into a different folder. The paths are correct, it works by getting the folder name in the URL, it does work, but nothing works for the thumbnails folder. BEFORE you ask this related question, yes, thumbnails generation does work on my server by the PHP GD, I have tested it separately. So this is not the problem. :) How do I get this to work? :(

    Read the article

  • PHP: How To call Standard Library Functions

    - by Andi
    Hi, I'm starting with PHP for dynamic web pages. I have some libaries written in ANSI C for getting/setting parameters and other proprietary stuff. I wonder, is there a simple solution to use a wrapper inside PHP to call this funtions? Is there a already existing class/library? What would be the best practice to do this on my own? I don't want do make calls to external applications and use stdin/stdout! Is there a simple example available? I don't want to dig through the Zend documentation for now, I only need a feeling for the complexity. Thanks, kind regards, Andi

    Read the article

  • ZipArchive php Class - Is it built-in to PHP?

    - by SoLoGHoST
    Ok, just wondering on the versions of PHP that this class is built into. And if they are built into all platforms (OS's). I'm wanting an approach to search through a zip file and place files using file_put_contents in different filepaths within the webroot. In any case, I'm familiar with how to do this with the ZipArchive class, but I'm wondering if using this class would be a good solution and support MOST, if not ALL servers?? I mean, I'd rather not use a method that requires the Server to have it installed. I'm looking for a solution to this that will support at least MOST servers without having to install the class... Thanks :) Also, I'd like to support opening tar.gz and/or .tgz files if possible, but I don't think the ZipArchive class supports this, but perhaps a different built-in php class does??

    Read the article

  • setting a cookie in php

    - by Jacksta
    I am trying to set a cookie, whas wrong with this as I am getting an error. Warning: setcookie() expects parameter 3 to be long, string given in /home/admin/domains/domain.com.au/public_html/setcookie.php on line 6 <?php $cookie_name = "test_cookie"; $cookie_value = "test_string"; $cookie_expire = "time()+86400"; $cookie_domain = "localhost"; setcookie($cookie_name, $cookis_value, $cookie_expire, "/", $cookie_domain, 0); ?> <HTM> <HEAD> </HEAD> <BODY> <h1>cookie mmmmmmm</h1> </BODY> </HTML>

    Read the article

  • Php mysqli and stored-procedure

    - by Mneva skoko
    I have a stored procedure: Create procedure news(in dt datetime,in title varchar(10),in desc varchar(200)) Begin Insert into news values (dt,title,desc); End Now my php: $db = new mysqli("","","",""); $dt = $_POST['date']; $ttl = $_POST['title']; $desc = $_POST['descrip']; $sql = $db-query("CALL news('$dt','$ttl','$desc')"); if($sql) { echo "data sent"; }else{ echo "data not sent"; } I'm new with php please help thank you

    Read the article

  • Javascript to PHP, mysql uploading, one button pressing solution

    - by user2897858
    my program is generating buttons from a mysql database.When one of the button is pressed, it would uplod the current time and the gps coordinate. Sadly, it only works if the same button is pressed twice, but its not an option, because the button has to dissappear. I would like to have some help in coding how to make that possible the user only need to press the button once for the correct upload.Thanks in advance Here is the full code of my my file: <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>title</title> </head> <?php $maidatum=date("Ymj"); echo "<script>getLocation();</script>"; //Az adatbázishoz való csatlakozás $conn = mysql_connect("localhost","root","asd"); if(!($conn))die("Nincs conn a kiszolgálóval!".mysql_error()); $adatbazisneve="schtrans"; mysql_select_db($adatbazisneve,$conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); //Combobox $sql = "SELECT Jaratszam,Vezeto FROM user"; $rs = mysql_query($sql) or die(mysql_error()); echo "<form action=\"\" method=\"post\">"; echo<<<nev <select name='Lista'> nev; while($row = mysql_fetch_array($rs)){ echo "<option value='".$row["Jaratszam"]."'>".$row["Vezeto"]."</option>"; }mysql_free_result($rs); echo "</select>"; ///Combox vége echo<<<lekerd <form action="" method="post"> <input type="submit" name="bekuldes" value="Lekérdez" /> </form> </form> lekerd; echo<<<gps <form action="" method="post"> <input type="hidden" name= "longitude" id="longitude"> <input type= "hidden" name ="latitude" id="latitude"> </form> gps; if(isset($_POST["bekuldes"])) { $jaratszam = $_POST['Lista']; $_SESSION['jaratsz']=$jaratszam; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } if(isset($_POST["ido"])) { $hanyadik=$_POST["ido"]; $longitudee="longitude$hanyadik"; $latitudee="latitude$hanyadik"; ?> <script> var x=document.getElementById("log"); function getLocation() { if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(showPosition); } else{x.innerHTML="GPS szolgáltatás nem müködik ezen a böngészon, kérlek értesítsd a rendszergazdát!";} } function showPosition(position) { var latitude = position.coords.latitude; var longitude = position.coords.longitude; document.getElementById("<?php echo $longitudee;?>").value = longitude; document.getElementById("<?php echo $latitudee;?>").value = latitude; } </script> <?php echo "<script>getLocation();</script>"; $latitude=$_POST["latitude"]; $longitude=$_POST["longitude"]; print_r($_POST); $currentime=date("H:i:s"); $acim=$_SESSION['adatok0'][$hanyadik]; $idofeltolt_parancs="UPDATE cim_$maidatum SET ido='$currentime',lat='$latitude',longi='$longitude' WHERE cimid='$acim';"; $feltoltes=mysql_query($idofeltolt_parancs, $conn) or die(mysql_error()); //tryy $jaratszam=$_SESSION['jaratsz']; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } mysql_close($conn); ?> </html>

    Read the article

  • pdf file creation in php

    - by pavun_cool
    Actually I have used following code , for creating the simple pdf file . It executed fine in the browsers. But I am not able to get the pdf file . But it gives me some output when I am running the code in CLI . my doubt is , where I need specify pdf file name ( creation file ) . <?php require('fpdf.php'); $pdf=new FPDF(); $pdf->AddPage(); $pdf->SetFont('Arial','B',16); $pdf->Cell(40,10,'Hello World!'); $pdf->Output(); ?> CLI output: 2 0 obj << /Type /Page /Parent 1 0 R /Contents 3 0 R endobj 3 0 obj << /Length 4 0 R stream 2.834646 0 0 2.834646 0 841.9 cm 2 J 0.2 w BT /F1 5.64 Tf ET BT 11 -16.692 Td (Hello World!) Tj ET

    Read the article

  • Getting JSON data in PHP

    - by domagoj412
    I have a JSON data like this: { "hello": { "first":"firstvalue", "second":"secondvalue" }, "hello2": { "first2":"firstvalue2", "second2":"secondvalue2" } } I know how to retrieve data from object "first" (firstvalue) and second (secondvalue) but I would like to loop trough this object and as a result get values: "hello" and "hello2"... This is my PHP code: <?php $jsonData='{"hello":{"first":"firstvalue","second":"secondvalue"},""hello2":{"first2":"firstvalue2","second2":"secondvalue2"}}'; $jsonData=stripslashes($jsonData); $obj = json_decode($jsonData); echo $obj->{"hello"}->{"first"}; //result: "firstvalue" ?> Can it be done?

    Read the article

  • Content-type not working in PHP

    - by Industrial
    Hi everyone, I have some issues with a PHP file that is not working properly. The Content-type does not get recieved by any browser at all. Firebug interprets the file as text/html instead of css. Here's the file : <?php header('Content-Type: text/css; charset=UTF-8'); error_reporting(E_ALL | E_STRICT); ini_set('display_errors', 'On'); /* CSS goes on from here */ I tested to put a row with echo 'TEST'; before the header line, and was expecting to see the classic "headers already sent" error, but nothing appears! What can I do to sort this out?

    Read the article

  • Add parameter to PHP

    - by proyb2
    When I sent an image to the code below, uploadImage.php, through a POST method, how do I add a String parameter? <?php $hasError = false; foreach( $_FILES as $i=>$file ) { if ( $file['error'] ) { $hasError = true; } } if ( ! $hasError ) { $myFilePath = '_uploads/'.'_'.$file["name"]; $dta = file_get_contents($file['tmp_name']); file_put_contents($myFilePath, $dta); } else { echo('Stick custom error message here'); } ?>

    Read the article

  • PHP Session code work differently on two servers

    - by williamsdb
    I have some code which works fine on one server but is giving a session header warning: Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent on another. I have checked the php.ini settings on the two servers and they are identical. I know that the warning message is supposed to suggest that something has been outputted before the session_start but what I don't understand is why the same code works on one server but not the other. Is there anything else that could be explaining it other than the php.ini settings?

    Read the article

  • PHP upload file using PUT instead of POST

    - by Marco Demaio
    I read something about this on PHP docs, but it's not celar to me: Do the most widely used browsers (IE, FF, Chrome, Safari, Opera, ...) support this PUT method to uplaod files? What HTML should I write to make the browser call the server via PUT request. I mean do I need to write a FORM with an INPUT file field and just replace the attribute method="POST" with the method="PUT"? On the PHP docs (link above) they say a PUT request is much simplier than a POST request when uploading file, along with this advantage, what other advantages/disadvanatges do the PUT has comapred to teh POST? Thanks!

    Read the article

  • How to strip a GET property from the URL using PHP

    - by James
    I have the following function that get's the current page URL: <?php // get current page url function currentPageUrl() { $pageURL = 'http'; if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";} $pageURL .= "://"; if ($_SERVER["SERVER_PORT"] != "80") { $pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"]; } else { $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"]; } echo $pageURL; } ?> Which prints: http://localhost/gallery.php?id=23&type=main I want to remove "&type=main" which is present in the url. So before echoing $pageURL I add the following line: $pageUrl = preg_replace("&type=main", "", $pageURL); But it still returns the full url including type=main. How can I get rid of that from the url?

    Read the article

  • First programming language: PHP, Ruby, Python?

    - by Victor
    I've been a Web developer for over 5 years and am looking to start building more complex Web apps. Currently, I know HTML/CSS/Javascript but I feel it's time to start learning something else. I work with a lot of applications based on PHP. I created a vBulletin forum on my own time and I would definitely want to build off of that since it has gained a bit of popularity. I also work with Wordpress quite often. All of the software I work with tends to be based on PHP but I hear a lot of people say Ruby or Python is better. Since I'm starting out, I really don't care which one I learn but I want to start right. Any recommendations for someone with HTML/CSS/Javascript knowledge but wants to branch out?

    Read the article

  • Lightweight PHP library alternative to common MVC frameworks

    - by artarad
    Hi hi, I'm looking for a easy to learn php library to use for my coming web app project. I've recently finished a web app with fully handwritten raw php code and it's absolutely hard to be done again for another project. even though I have the recent project code snippets to be used again, but due to their non-structural arrangement (not object oriented), i have no passion to use 'em again. I have no experience with common frameworks like ZF, CakePhp, CodeIgniter, so I think to get my hands on a multipurpose OO library for my web app and the framework learning will be the next step! any suggestion? UPDATE: Many thanks guys, I have not enough time to get through the depth of every lib or framework you have kindly introduced. Since I'm going one step further I'm going to use ZF as famous framework which could provide me more job opportunities perhaps. thankssss :)

    Read the article

  • PHP While() Stop Looping

    - by Axel
    Hi, i have a php loop which displays only one record even if there is hundreds. here is the code: <?php $result1 = mysql_query("SELECT * FROM posts") or die(mysql_error()); $numexem = mysql_num_rows($result1); $s="0"; while($s<$numexem){ $postid=mysql_result($result1,$s,"id"); echo "Post id:".$postid; $result2 = mysql_query("SELECT * FROM pics WHERE postid='$postid'") or die(mysql_error()); $rows = mysql_fetch_array($result2) or die(mysql_error()); $pnum = mysql_num_rows($result2); echo " There is ".$pnum." Attached Pictures"; $s++; } ?> I'm wondering if the loop stop because there is other SQL query inside it or what? and i don't think so. Thanks

    Read the article

  • PHP fastest method of reading server response

    - by Peter John
    Hi there, im having some real problems with the lag produced by using fgets to grab the server's response to some batch database calls im making. Im sending through a batch of say, 10,000 calls and ive tracked the lag down to fgets causing the hold up in the speed of my application as the response for each call needs to be grabbed. I have found this thread http://bugs.php.net/bug.php?id=32806 which explains the problem quite well, but hes reading a file, not a server response so fread could be a bit tricky as i could get part of the next line, and extra stuff which i dont want. Any help much appreciated!

    Read the article

  • What some good PHP jobs?

    - by ggfan
    I am no professional PHP coder or anything, in fact I am fairly new. I can develop sites but nothing too crazy or fancy with PHP,Mysql,CSS,HTML,javascript. Up to now, all I have been doing is practice coding from books and websites. I am now looking for a 'real-life' experience. Besides going to a company and getting an interview, are there any other options in which I can get paid to code? I have posted some ads on craiglists but that's about it. And because this is my first time going to the 'real-word' and can make mistakes, am I liable if...a site I made for someone gets hacked and that person losses information?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 243 244 245 246 247 248 249 250 251 252 253 254  | Next Page >