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• php and mysql site design question

  - by Jacksta

  I am trying to build a website with mysql and php. This is the first site I have attempted so I want to write a little plan and get some feedback. The site allows users to add some text in a text field as a “comment”. Once the comment has been entered into the site it is added to the database where it can be voted for by other users. When a new comment has been added to the database it needs to create a new page, e.g. www.xxxxx.com/commentname or www.xxxxxx.com/?id=99981. There will be a list of "Comments" in the database along with the number of votes for each comment. The home page will have two functions. 1) Allow users to add a "comment" 2) Display two tables, each with 20 rows containing most "popular comments" and "recent comments" Each comment will generate its one page where the comment will be displayed. Here users can read the comment and Vote for the comment if they wish. Please help me out by explaining how to do the following. -Generate a new page whenever a comment is added to the database -Add a vote to the vote count in the comment database. -Display the top 20 most popular comments as per number of votes.

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• PHP Array saved to Text file

  - by coffeemonitor

  I've saved a response from an outside server to a text file, so I don't need to keep running connection requests. Instead, perhaps I can use the text file for my manipulation purposes, until I'm read for re-connecting again. (also, my connection requests are limited to this outside server) Here is what I've saved to a text file: records.txt Array ( [0] => stdClass Object ( [id] => 552 [date_created] => 2012-02-23 10:30:56 [date_modified] => 2012-03-09 18:55:26 [date_deleted] => 2012-03-09 18:55:26 [first_name] => Test [middle_name] => [last_name] => Test [home_phone] => (123) 123-1234 [email] => [email protected] ) [1] => stdClass Object ( [id] => 553 [date_created] => 2012-02-23 10:30:56 [date_modified] => 2012-03-09 18:55:26 [date_deleted] => 2012-03-09 18:55:26 [first_name] => Test [middle_name] => [last_name] => Test [home_phone] => (325) 558-1234 [email] => [email protected] ) ) There's actually more in the Array, but I'm sure 2 are fine. Since this is a text file, and I want to pretend this is the actual outside server (sending me the same info), how do I make it a real array again? I know I need to open the file first: <?php $fp = fopen('records.txt', "r"); // open the file $theData = fread($fh, filesize('records.txt')); fclose($fh); echo $theData; ?> So far $theData is a string value. Is there a way to convert it back to the Array it originally came in as?

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• MySQL SELECT Statement not working when executed from PHP

  - by Andrew K

  Hello all, I have the following piece of code, executing a pretty simple MySQL query: $netnestquery = 'SELECT (`nested`+1) AS `nest` FROM `ipspace6` WHERE `id`<='.$adaddr.' AND `subnet`<='.$postmask.' AND `type`="net" AND `addr` NOT IN(SELECT `id` FROM `ipspace6` WHERE `addr`<'.$adaddr.' AND `type`="broadcast") ORDER BY `id`,`subnet` DESC LIMIT 1'; $netnestresults = mysql_query($netnestquery); $netnestrow = mysql_fetch_array($netnestresults); $nestlvl = $netnestrow['nest']; echo '<br> NESTQ: '.$netnestquery; Now, when I execute this in PHP, I get no results; an empty query. However, when I copy and paste the query echoed by my code (for debug purposes) into the mysql command line, I get a valid result: mysql> SELECT (`nested` + 1) AS `nest` FROM `ipspace6` WHERE `id`<=50552019054038629283648959286463168512 AND `subnet`<=36 AND `type`='net' AND `addr` NOT IN (SELECT `id` FROM `ipspace6` WHERE `addr`<50552019054038629283648959286463168512 AND `type`='broadcast') ORDER BY `id`,`subnet` DESC LIMIT 1; +------+ | nest | +------+ | 1 | +------+ 1 row in set (0.00 sec) Can anybody tell me what I'm doing wrong? I can't put quotes around my variables, as then MySQL will try to evaluate the variable as a string, when it is, in fact, a very large decimal. I think I might just be making a stupid mistake somewhere, but I can't tell where.

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• Sending mail through PHP

  - by Angeline Aarthi

  I'm trying to sends mails in PHP. The code I used for sending a mail in CakePHP is given below. I get the message 'Simple Email Sent' in my web page but the mail is not delivered to my inbox. Am I missing something? The values in the to, subject and link fields are set with the values entered in the user interface. $this->set('to',$this->params['form']['to']); $this->set('subject',$this->params['form']['subject']); $this->set('link',$this->params['form']['link']); $this->Email->to = to; $this->Email->subject = subject; $this->Email->from = '[email protected]'; $this->Email->delivery= 'mail'; $this->Email->sendAs='text'; $this->Email->template = 'simple_message'; //$this->Email->send(link); if ( $this->Email->send(link) ) { $this->Session->setFlash('Simple email sent'); } else { $this->Session->setFlash('Simple email not sent'); }

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• PHP & MYSQL: How can i neglect empty variables from select

  - by cash-cash

  hello all; if i have 4 variables and i want to select DISTINCT values form data base <?php $var1 = ""; //this variable can be blank $var2 = ""; //this variable can be blank $var3 = ""; //this variable can be blank $var4 = ""; //this variable can be blank $result = mysql_query("SELECT DISTINCT title,description FROM table WHERE **keywords ='$var1' OR author='$var2' OR date='$var3' OR forums='$var4'** "); ?> note: some or all variables ($var1,$var2,$var3,$var4) can be empty what i want: i want to neglect empty fields lets say that $var1 (keywords) is empty it will select all empty fileds, but i want if $var1 is empty the result will be like $result = mysql_query("SELECT DISTINCT title,description FROM table WHERE author='$var2' OR date='$var3' OR forums='$var4' "); if $var2 is empty the result will be like $result = mysql_query("SELECT DISTINCT title,description FROM table WHERE keywords ='$var1' OR date='$var3' OR forums='$var4' "); if $var1 and $var2 are empty the result will be like $result = mysql_query("SELECT DISTINCT title,description FROM table WHERE date='$var3' OR forums='$var4' "); and so on

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• Restrict allowed file upload types PHP

  - by clang1234

  Right now I have a function which takes my uploaded file, checks the extension, and if it matches an array of valid extensions it's processed. It's a contact list importer. What I need to figure out is how to be sure that file (in this case a .csv) is actually what it says it is (ex. not an excel file that just got renamed as a .csv). Our servers run PHP 5.2.13 Here's the current validation function I have public static function validateExtension($file_name,$ext_array) { $extension = strtolower(strrchr($file_name,".")); $valid_extension="FALSE"; if (!$file_name) { return false; } else { if (!$ext_array) { return true; } else { foreach ($ext_array as $value) { $first_char = substr($value,0,1); if ($first_char <> ".") { $extensions[] = ".".strtolower($value); } else { $extensions[] = strtolower($value); } } foreach ($extensions as $value) { if ($value == $extension) { $valid_extension = "TRUE"; } } if ($valid_extension==="TRUE") { return true; } else { return false; } } } }

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• Filtering a PHP array containing dates into a yearly summary

  - by privateace

  I'm looking at a way to create a summary of transactions within a certain month based on the contents of a PHP array. Intended outcome (excusing layout): ------------------------------------------- | December 2009 | 12 | | January 2010 | 02 | | February 2010 | 47 | | March 2010 | 108 | | April 2010 | 499 | ------------------------------------------- Based on my array: Array ( [0] => Array ( [name] => 2009-10-23 [values] => Array ( [0] => INzY2MTI4ZWM4OGRm ) ) [1] => Array ( [name] => 2009-10-26 [values] => Array ( [0] => IYmIzOWNmMmU3OWQz ) ) [2] => Array ( [name] => 2009-11-23 [values] => Array ( [0] => INTg4YzgxYWU1ODkx [1] => IMjhkNDZkY2FjNDhl ) ) [3] => Array ( [name] => 2009-11-24 [values] => Array ( [0] => INTg4YzgxYWU1ODkx [1] => INTg4YzgxYWU1ODkx ) ) [4] => Array ( [name] => 2009-12-01 [values] => Array ( [0] => IMWFiODk5ZjU1OTFk ) ) I've had absolutely no luck no matter what I've tried. Especially with adding months that do not contain any variables.

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• DOM manipulation in PHP

  - by bluedaniel

  Hello everyone, Im trying to use the DOM in PHP to do a pretty specific job and Ive got no luck so far, the objective is to take a string of HTML from a Wordpress blog post (from the DB, this is a wordpress plugin). And then out of that HTML replace <div id="do_not_edit">old content</div>" with <div id="do_not_edit">new content</div>" in its place. Saving anything above and below that div in its structure. Then save the HTML back into the DB, should be simple really, I have read that a regex wouldnt be the right way to go here so Ive turned to the DOM instead. The problem is I just cant get it to work, cant extract the div or anything. Help me!! UPDATE The HTML coming out of the wordpress table looks like: Congratulations on finding us here on the world wide web, we are on a mission to create a website that will show off your culinary skills better than any other website does. <div id="do_not_edit">blah blah</div> We want this website to be fun and easy to use, we strive for simple elegance and incredible functionality.We aim to provide a 'complete package'. By this we want to create a website where people can meet, share ideas and help each other out. After several different (incorrect) workings all Ive got below is: $content = ($wpdb->get_var( "SELECT `post_content` FROM $wpdb->posts WHERE ID = {$article[post_id]}" )); $doc = new DOMDocument(); $doc->validateOnParse = true; $doc->loadHTMLFile($content); $element = $doc->getElementById('do_not_edit'); echo $element;

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• Dynamically including multiple files within php for image descriptions

  - by Steve Jones

  Working on implementing image descriptions to a php run gallery and can't seem to figure out how to call each text file for each individual image. //total number of images $total = 77; //max number of thumbnails per page $max = 9; //what image do we want to start from? $startcount = $_GET["start"]; //if there is not a defined starting image, we start with the first if(empty($startcount)) { $startcount = 0; } //start off the loop at 1 $loop = 1; //start the loop while($loop <= $max) { //for the picture labels $num = $startcount + $loop; if($num > $total) { $num = $num - 1; break; } // Add class="last" to every third list item if(is_int($num / 3)) { $last = ' class="last"'; } else { $last = ""; } //the code for the image echo ' <li'.$last.'><a href="images/portfolio/pic-'.$num.'.jpg" rel="milkbox[gall1]"><img src="images/portfolio/thumbs/pic-'.$num.'-thumb.jpg" width="256" height="138" alt="Thumbnail of image '.$num.'" /></a><div>'.$num.'</div></li>'; I see that I can call the text files by number using '.$num.' (I have 77 individual text files with a phrase in each) but how do I tell it to call the files?

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• alternatyve in php (from java)

  - by Valdas

  I have some problem have class in java. But now need have in php. it's possible rewrite? Code: public class RealityStream { public RealityStream(byte abyte0[]) { m_dstream = null; m_dstream = new DataInputStream(new ByteArrayInputStream(abyte0)); } public int available() throws IOException { return m_dstream.available(); } public float readFloat() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); byte byte2 = m_dstream.readByte(); byte byte3 = m_dstream.readByte(); int i = (byte3 & 0xff) << 24 | (byte2 & 0xff) << 16 | (byte1 & 0xff) << 8 | byte0 & 0xff; return Float.intBitsToFloat(i); } public int readInt() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); byte byte2 = m_dstream.readByte(); byte byte3 = m_dstream.readByte(); return (byte3 & 0xff) << 24 | (byte2 & 0xff) << 16 | (byte1 & 0xff) << 8 | byte0 & 0xff; } public int readShort() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); return byte1 << 8 | byte0 & 0xff; } public int readUnsignedChar() throws IOException { return m_dstream.readUnsignedByte(); } private DataInputStream m_dstream; } very need. very thaks.

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• JQuery Tabbed Nav Menu and PHP Forms Question?

  - by SlAcKeR

  I'm using a JQuery Tabbed Menu which holds different types of forms and when I select a different form located under a different tab and submit the form the tab will jump to the default tab instead of the current tab the form is located in. I was wondering how would I go about fixing this so that when the form is submitted the current tab is still selected, is it the JQuery or PHP problem? Here is the JQuery. $(document).ready(function() { //When page loads... $(".form-content").hide(); //Hide all content var firstMenu = $("#home-menu ul li:first"); firstMenu.show(); firstMenu.find("a").addClass("selected-link"); //Activate first tab $(".form-content:first").show(); //Show first tab content //On Click Event $("#home-menu ul li").click(function() { $("#home-menu ul li a").removeClass("selected-link"); //Remove any "selected-link" class $(this).find("a").addClass("selected-link"); //Add "selected-link" class to selected tab $(".form-content").hide(); //Hide all tab content var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the selected-link tab + content $(activeTab).fadeIn(); //Fade in the selected-link ID content return false; }); });

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• using 'or' operator not working for menu

  - by John Wilkes

  In my code here, I have a CSS class called "active" which I use if the $_GET['page'] == tutorials, php, mysql, etc... The problem is, even if the 'page' variable is not equal to any of these values, the Tutorials button in this case is still active for some reason. Any ideas why this would be happening? Am I using the 'or' (||) operand incorrectly? <?php if($_GET['page'] == 'tutorials' || 'php' || 'mysql' || 'html' || 'css' || 'js') { ?> <li class="active"> <?php } else { ?> <li> <?php } ?> <a href="index.php?page=tutorials">Tutorials</a> <ul> <li><a href="index.php?page=php">PHP</a></li> <li><a href="index.php?page=mysql">MySQL</a></li> <li><a href="index.php?page=html">HTML</a></li> <li><a href="index.php?page=css">CSS</a></li> <li><a href="index.php?page=js">JS</a></li> </ul> </li>

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• How to compare two file structures in PHP?

  - by OM The Eternity

  I have a function which gives me the complete file structure upto n-level, function getDirectory($path = '.', $ignore = '') { $dirTree = array (); $dirTreeTemp = array (); $ignore[] = '.'; $ignore[] = '..'; $dh = @opendir($path); while (false !== ($file = readdir($dh))) { if (!in_array($file, $ignore)) { if (!is_dir("$path/$file")) { //display of file and directory name with their modification time $stat = stat("$path/$file"); $statdir = stat("$path"); $dirTree["$path"][] = $file. " === ". date('Y-m-d H:i:s', $stat['mtime']) . " Directory == ".$path."===". date('Y-m-d H:i:s', $statdir['mtime']) ; } else { $dirTreeTemp = getDirectory("$path/$file", $ignore); if (is_array($dirTreeTemp))$dirTree = array_merge($dirTree, $dirTreeTemp); } } } closedir($dh); return $dirTree; } $ignore = array('.htaccess', 'error_log', 'cgi-bin', 'php.ini', '.ftpquota'); //function call $dirTree = getDirectory('.', $ignore); //file structure array print print_r($dirTree); Now here my requirement is , I have two sites The Development/Test Site- where i do testing of all the changes The Production Site- where I finally post all the changes as per test in development site Now, for example, I have tested an image upload in the Development/test site, and i found it appropriate to publish on Production site then i will completely transfer the Development/Test DB detail to Production DB, but now I want to compare the files structure as well to transfer the corresponding image file to Production folder. There could be the situation when I update the image by editing the image and upload it with same name, now in this case the image file would be already present there, which will restrict the use of "file_exist" logic, so for these type of situations....HOW CAN I COMPARE THE TWO FILE STRUCTURE TO GET THE SYNCHRONIZATION DONE AS PER REQUIREMENT??

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• PHP using a passed value to open a dir, not working

  - by HadoukenGr

  This is my code <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>Gallery</title> <script src="js/jquery-1.7.2.min.js"></script> <script src="js/lightbox.js"></script> <link href="css/lightbox.css" rel="stylesheet" /> </head> <body> <?php $value=$_GET["value"]; $handle = opendir("content/$value/gallery/"); while($file = readdir($handle)) { if($file !== '.' && $file !== '..') { do_something; } } ?> </body> </html> Passing value "?a??????", gives Warning: opendir(content/?a??????/gallery/): failed to open dir: No such file or directory. But if i do this : $handle = opendir("content/?a??????/gallery/"); it works fine. Something to do with character encoding? How could i solve this? Thank you.

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• Check if date is allowed weekday in php?

  - by moogeek

  Hello! I'm stuck with a problem how to check if a specific date is within allowed weekdays array in php. For example, function dateIsAllowedWeekday($_date,$_allowed) { if ((isDate($_date)) && (($_allowed!="null") && ($_allowed!=null))){ $allowed_weekdays=json_decode($_allowed); $weekdays=array(); foreach($allowed_weekdays as $wd){ $weekday=date("l",date("w",strtotime($wd))); array_push($weekdays,$weekday); } if(in_array(date("l",strtotime($_date)),$weekdays)){return TRUE;} else {return FALSE;} } else {return FALSE;} } ///////////////////////////// $date="21.05.2010"; $wd="[0,1,2]"; if(dateIsAllowedWeekday($date,$wd)){echo "$date is within $wd weekday values!";} else{echo "$date isn't within $wd weekday values!"} I have input dates formatted as "d.m.Y" and an array returned from database with weekday numbers (formatted as 'Numeric representation of the day of the week') like [0,1,2] - (Sunday,Monday,Tuesday). The returned string from database can be "null", so i check it too. Them, the isDate function checks whether date is a date and it is ok. I want to check if my date, for example 21.05.2010 is an allowed weekday in this array. My function always returns TRUE and somehow weekday is always 'Thursday' and i don't know why... Is there any other ways to check this or what can be my error in the code above? thx

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• Is there a way to access Joomla 1.5 user variables (like user id) from a Flex 4 application using a PHP Data Service?

  - by Zachary G. Schroeder

  I have written a script (in two files) that correctly displays a Joomla user id, like this: //this is testy.php define( '_JEXEC', 1 ); define('JPATH_BASE', dirname(FILE)); define( 'DS', DIRECTORY_SEPARATOR ); require_once ( JPATH_BASE .DS.'includes'.DS.'defines.php' ); require_once ( JPATH_BASE .DS.'includes'.DS.'framework.php' ); $mainframe =& JFactory::getApplication('site'); $id = JFactory::getUser()-id; The above file is located in the Joomla root folder. The other file is in a different directory and is as follows: //this is testid.php include '../../joomla/testy.php'; echo $id; However, and here is the rub, when I change the "echo" to a "return" and put the second code snippet inside my Flex 4 Data Service script file, like this... function getUserId() { include '../../joomla/testy.php'; return $id; } ...I get a Flex error that says this: Fatal error: Class 'JRequest' not found in /var/www/html/joomla/libraries/joomla/import.php on line 33 I am extremely confused by this error and would appreciate any suggestions that the stackoverflow community may have. Thanks so much! Zach

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• PHP's fopen is terminally failing

  - by Skittles

  Okay, I have GOT to be missing something totally rudimentary here. I have an extremely simple use of PHP's fopen function, but for some reason, it will not open the file no matter what I do. The odd part about this is that I use fopen in another function in the same script and it's working perfectly. I'm using the fclose in both functions. So, I know it's not a matter of a rogue file handle. I have confirmed the file's path and the existence of the target file also. I'm running the script at the command-line as root, so I know it's not apache that's the cause. And since I am running the script as root, I am fairly confident that permissions are not the issue. So, what on earth am I missing here? function get_file_list() { $file = '/home/site/tmp/return_files_list.txt'; $fp = fopen($file, 'r') or die("Could not open file: /home/site/tmp/return_files_list.txt for reading.\n"); $files_list = array(); while($line = fgets($fp)) { $files_list[] = $line; } fclose($fp); return $files_list; } function num_records_in_file($filename) { $fp = fopen( $filename, 'r' ); # or die("Could not open file: $filename\n"); $counter = 0; if ($fp) { while (!feof( $fp )) { $line = fgets( $fp ); $arr = explode( '|', $line ); if (( ( $arr[0] != 'HDR' && $arr[0] != 'TRL' ) && $arr[0] != '' )) { ++$counter; continue; } } } fclose( $fp ); return $counter; } As requested, here's both functions. The second function is passed an absolute path to the file. That is what I used to confirm that the file is there and that the path is correct.

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• PHP hashing function not working properly

  - by Jordan Foreman

  So I read a quick PHP login system securing article, and was trying to sort of duplicate their hashing method, and during testing, am not getting the proper output. Here is my code: function decryptPassword($pw, $salt){ $hash = hash('sha256', $salt . hash('sha256', $pw)); return $hash; } function encryptPassword($pw){ $hash = hash('sha256', $pw); $salt = substr(md5(uniqid(rand(), true)), 0, 3); $hash = hash('sha265', $salt . $hash); return array( 'salt' => $salt, 'hash' => $hash ); } And here is my testing code: $pw = $_GET['pw']; $enc = encryptPassword($pw); $hash = $enc['hash']; $salt = $enc['salt']; echo 'Pass: ' . $pw . '<br />'; echo 'Hash: ' . $hash . '<br />'; echo 'Salt: ' . $salt . '<br />'; echo 'Decrypt: ' . decryptPassword($hash, $salt); Now, the output of this should be pretty obvious, but unfortunately, the $hash variable always comes out empty! I'm trying to figure out what the problem could be, and my only guess would be the second $hash assignment line in the encryptPassword(..) function. After a little testing, I've determined that the first assignment works smoothly, but the second does not. Any suggestions? Thanks SO!

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• PHP SDK for Facebook: Uploading an Image for an Event created using the Graph API

  - by wenbert

  Can anyone shed some light on my problem? <?php $config = array(); $config['appId'] = "foo"; $config['secret'] = "bar"; $config['cookie'] = true; $config['fileUpload'] = true; $facebook = new Facebook($config); $eventParams = array( "privacy_type" => $this->request->data['Event']['privacy'], "name" => $this->request->data['Event']['event'], "description" => $this->request->data['Event']['details'], "start_time" => $this->request->data['Event']['when'], "country" => "NZ" ); //around 300x300 pixels //I have set the permissions to Everyone $imgpath = "C:\\Yes\\Windows\\Path\\Photo_for_the_event_app.jpg"; $eventParams["@file.jpg"] = "@".$imgpath; $fbEvent = $facebook->api("me/events", "POST", $eventParams); var_dump($fbEvent); //I get the event id I also have this in my "scope" when the user is asked to Allow the app to post on his behalf: user_about_me,email,publish_stream,create_event,photo_upload This works. It creates the event with all the details I have specified. EXCEPT for the event image. I have been to most of Stackoverflow posts related to my problem but all of them are not working for me. (EG: http://stackoverflow.com/a/4245260/66767) I also do not get any error. Any ideas? THanks!

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• PHP Session variable isset(..)=1 after session_start()

  - by Nicsoft

  Hello! I guess I am not understanding the scope of session variables, or the session itself, in PHP, hence this question: This is my code if(!session_id()==""){ echo "Getting rid of session"."</br>"; session_destroy(); } echo "Before session_start(): ".isset($_SESSION["first_date_of_week"])."</br>"; session_start(); echo "After session_start(): ".isset($_SESSION["first_date_of_week"])." ".$_SESSION["first_date_of_week"]->format("Y-m-d")."</br>"; The output is: Before session_start(): After session_start(): 1 2011-01-09 How come that when doing the isset(..) on the session variable it is set directly after starting the session, even though I haven't even used it or set it yet? It does, however, still have the same value as before. Also, session_id()="" since the if-clause is never triggered. I never kill the session, how come it is set to ""? I.e. I refresh the page and expects the session to still be alive. Using the isset(..) function is then pretty useless testing if it has been set already... Thanks in advance! /Niklas

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• PHP Combo Box AJAX Refresh

  - by bhs

  I have a PHP page that currently has 4 years of team positions in columns on the page. The client wants to select the players in positions and have first, second and thrid choices. Currently the page shows 4 columns with sets of combos for each position. Each combo has a full set of players in it and the user chooses the player he wants from the combos. On submit the player positions are stored in the database. However, the client now wants to change the page so that when he selects a player in a year and position then the player is removed from the combo and can no longer be selected for that year. I've used a bit of AJAX but was wondering if anyone had any thoughts/suggestions. The page is currently quite slow so they want it speeded up as well. The page layout is currently like this POISTION YEAR1 YEAR2 YEAR3 YEAR4 1 COMBOC1 COMBOC1 COMBOC1 COMBOC1 COMBOC2 COMBOC2 COMBOC2 COMBOC2 COMBOC3 COMBOC3 COMBOC3 COMBOC3 2 same as above COMBOC1, 2 and 3 all currently have the same players - when a player is selected it needs to be removed for all combos below it. I was thinking of starting by changing the page design and having text boxes for the players and a single player select under each year like this: POISTION YEAR1 YEAR2 YEAR3 YEAR4 1 <PLAYER><POSITION><CHOICE> ... [TEXT BOX CHOICE1] [TEXT BOX CHOICE2] [TEXT BOX CHOICE3] 2 ... Then I only have 1 combo box for each year to worry about - I do however have the same problem of refreshing the combo box and removing the player that has been selected, and I'd prefer to do it withough a page submit. Sorry for the long posting - cheers

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• PHP driven site needs password change.

  - by Drea

  I have inherited a website that needs the password changed that accesses the database. I can see that there are two tables within the database but neither of them have username or password info. The previous web guy moved out of the country and can't be reached. I am not up-to-speed enough to figure this out. I have gone through all the files to try and find the answer but can't get it. It's hosted by goDaddy.com and I have changed the passwords there but it didn't change this login info. www.executivehomerents.com/cpanel <-this brings up the prompt for the username & password which I won't give out but the page only gives you 5 choices and none of them deal with changing the password. They are simply to change the data in the tables. If you go to: http://www.websitedatabases.com/ <=this is the company that the PHPMagic program was purchased from-- They have no contact number. Here is another page that might help: http://www.executivehomerents.com/cpanel/dbinput/setup.php I don't think I'll get an answer to this but it's worth a try... thanks.

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• I'm trying to make a php Curl call to formstack api, but I get nothing

  - by Oskar Calvo

  This is one of my first curls code, so it can have mistakes I'm trying to be able to make calls to form/:id/submissions https://www.formstack.com/developers/api/resources/submission#form/:id/submission_GET If I load: https://www.formstack.com/api/v2/form/1311091/submission.json?oauth_token=44eedc50d015b95164897f5e408670f0&min_time=2012-09-01%2000:01:01&max_time=2012-10-27%2000:01:01 If works great. If I try this code: <?php $host = 'https://www.formstack.com/api/v2/'; // TODO this should manage dinamics values or build an action in every method. $action = 'form/1311091/submission.json'; $url = $host . $action; // TODO this values will arrive like an array with values $postData['oauth_token']= '44eedc50d015b95164897f5e408670f0'; $postData['min_time'] ='2012-09-01 00:01:01'; $postData['max_time'] ='2012-10-27 00:01:01'; // TODO make a method with this action function getElements($postData) { $elements = array(); foreach ($postData as $name=>$value) { $elements[] = "{$name}=".urlencode($value); } } $curl = curl_init(); curl_setopt($curl, CURLOPT_URL, $url); curl_setopt($curl, CURLOPT_HTTPGET, true); curl_setopt($curl, CURLOPT_POSTFIELDS, $elements); $result = curl_exec($curl) ; curl_close($curl); var_dump($result); ?>

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• PHP modifying and combining array

  - by Industrial

  Hi everyone, I have a bit of an array headache going on. The function does what I want, but since I am not yet to well acquainted with PHP:s array/looping functions, so thereby my question is if there's any part of this function that could be improved from a performance-wise perspective? I tried to be as complete as possible in my descriptions in each stage of the functions which shortly described prefixes all keys in an array, fill up eventual empty/non-valid keys with '' and removes the prefixes before returning the array: $var = myFunction ( array('key1', 'key2', 'key3', '111') ); function myFunction ($keys) { $prefix = 'prefix_'; $keyCount = count($keys); // Prefix each key and remove old keys for($i=0;$i<$keyCount; $i++){ $keys[] = $prefix.$keys[$i]; unset($keys[$i]); } // output: array('prefix_key1', 'prefix_key2', 'prefix_key3', '111) // Get all keys from memcached. Only returns valid keys $items = $this->memcache->get($keys); // output: array('prefix_key1' => 'value1', 'prefix_key2' => 'value2', 'prefix_key3'=>'value3) // note: key 111 was not found in memcache. // Fill upp eventual keys that are not valid/empty from memcache $return = $items + array_fill_keys($keys, ''); // output: array('prefix_key1' => 'value1', 'prefix_key2' => 'value2', 'prefix_key3'=>'value3, 'prefix_111' => '') // Remove the prefixes for each result before returning array to application foreach ($return as $k => $v) { $expl = explode($prefix, $k); $return[$expl[1]] = $v; unset($return[$k]); } // output: array('key1' => 'value1', 'key2' => 'value2', 'key3'=>'value3, '111' => '') return $return; } Thanks a lot!

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• Weird problem with PHP mail() under Linux.

  - by Vilx-

  This is the case when it "works on my machine". Except that my machine is Windows, and the target is some sort of Linux. The idea is that the mail() function puts a newline between the MIME-Version and Content-Type headers, thus breaking the whole thing. Here's the code, simpliefied as much as possible: <?php $HTMLPart = chunk_split(base64_encode('<html><body style="color: red">Test.</body></html>')); $PlaintextPart = chunk_split(base64_encode('>>> TEST <<<')); $Headers =<<<AKAM From: "My Test" <[email protected]> Reply-To: [email protected] MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="9-1410065408-1410065408=:27514" AKAM; $Body =<<<AKAM This is a multi-part message in MIME format. --9-1410065408-1410065408=:27514 Content-Type: text/plain; charset="windows-1252" Content-Transfer-Encoding: base64 $PlaintextPart --9-1410065408-1410065408=:27514 Content-Type: text/html; charset="windows-1252" Content-Transfer-Encoding: base64 $HTMLPart --9-1410065408-1410065408=:27514-- AKAM; echo 'Try 3: '; echo mail('[email protected]', 'Testmail', $Body, $Headers) ? 'WIN' : 'FAIL'; ?>

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