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  • Finding Specific Descendant Nodes With XSL:Key

    - by DBA_Alex
    Given the following code: <database> <table name="table1"> <column name="id"/> <column name="created_at"/> </table> <table name="table2"> <column name="id"/> <column name="updated_at"/> </table> </database> I want to be able to test using an xsl:key if specific table has a specific column by name. For instance, I want to know if a table has a 'created_at' column so I can write specific code within the transformation. I've gotten a general key that will test if any table has a given column by name, but have not figured out how to make it specific to the table the transformation is currently working with. <xsl:key name="columnTest" match="column" use="@name"/> <xsl:for-each select="database/table"> <xsl:choose> <xsl:when test="key('columnTest', 'created_at')"> <xsl:text>true</xsl:text> </xsl:when> <xsl:otherwise> <xsl:text>false</xsl:text> </xsl:otherwise> </xsl:choose> </xsl:for-each> So I end up with 'true' for all the tables. Any guidance would be appreciated.

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  • xsl transform: problem with Ampersand URL parameters

    - by Rac123
    I'm having issues with transforming XSL with parameters in a URL. I'm at a point that I can't change the C# code anymore, only can make changes to xsl file. C# code: string xml = "<APPLDATA><APPID>1052391</APPID></APPLDATA>"; XmlDocument oXml = new XmlDocument(); oXml.LoadXml(xml); XslTransform oXslTransform = new XslTransform(); oXslTransform.Load(@"C:\Projects\Win\ConsoleApps\XslTransformTest\S15033.xsl"); StringWriter oOutput = new StringWriter(); oXslTransform.Transform(oXml, null, oOutput) XSL Code: <body> <xsl:variable name="app"> <xsl:value-of select="normalize-space(APPLDATA/APPID)" /> </xsl:variable> <div id="homeImage" > <xsl:attribute name="style"> background-image:url("https://server/image.gif?a=10&amp;Id='<xsl:value-of disable-output-escaping="yes" select="$app" />'") </xsl:attribute> </div> </body> </html> URL transformed: https://server/image.gif?a=10&Id='1052391' URL Expected: https://server/image.gif?a=10&Id='1052391' How do I fix this? The output (oOutput.ToString()) is being used in an email template so it's taking the URL transformed literally. When you click on this request (with the correct server name of course), the 403 (Access forbidden) error is being thrown.

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  • Generate dynamic xmlns

    - by alexbf
    Hello, I would like to dynamically generate xmlns attributes. I want to generate this in XSL : <Common:MainPageBase xmlns:Common="clr-namespace:ThisPartIsDynamic;assembly=ThisPartIsDynamic" </Common:MainPageBase How can I do that in XSL? Thanks, Alex

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  • CUSTOM SORT XSL ?

    - by Nanda
    Hi This is my XML Structure like this input :- <MYDATA> <DETAILS> <DESCRIPTION>EASE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>COMPLEX</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>SIMPLE</DESCRIPTION> </DETAILS> </MYDATA> I want to display like this using xsl sort it mean custom sort i want to display firts simple second ease and third complex Output :- <MYDATA> <DETAILS> <DESCRIPTION>SIMPLE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>EASE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>COMPLEX</DESCRIPTION> </DETAILS> </MYDATA>

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  • DOCTYPE declaration getting lost when using XSL

    - by Rachel
    The input to my XSL is an XHTML. After applying the XSL the DOCTYPE declaration that was present in the input XHTML gets lost in the output. Do i have an option to copy/retain the DOCTYPE declaration in the output using XSL. The XSL processor that i am using is SAXON.

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  • Xalan redirect:write , use either of two element values to create name of new .xml file depending on

    - by Bilzac
    So I have the following code: <redirect:write select="concat('..\\folder\\,string(filename),'.xml')"> Where "filename" is a tag in the xml source. My problem occurs when filename is null or blank. And this is the case for several of the xml filename tags. So what I am trying to implement is a checking method. This is what I have done: <xsl-if test = "filename != ''"> <xsl:variable name = "tempName" select = "filename" /> </xsl-if> <xsl-if test ="filename = ''"> <xsl:variable name = "tempName" select = "filenameB"/> </xsl-if> <redirect:write select="concat('..\\folder\\,string($tempName),'.xml')"> I seem to be getting NPEs when I compile my Java code, saying the Variable not resolvable: tempName

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  • Filemaker XSL Select Column By Name

    - by Kevin Sylvestre
    I am looking to export from Filemaker using column names (instead of positions). Currently I export the following XSL stylesheet that exports by position with: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fm="http://www.filemaker.com/fmpxmlresult" exclude-result-prefixes="fm" > <xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/> <xsl:template match="/"> <people> <xsl:for-each select="fm:FMPXMLRESULT/fm:RESULTSET/fm:ROW"> <person> <name> <xsl:value-of select="fm:COL[01]/fm:DATA"/> </name> <location> <xsl:value-of select="fm:COL[02]/fm:DATA"/> </location> </person> </xsl:for-each> </people> </xsl:template> </xsl:stylesheet> Any ideas? Thanks.

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  • Access data of a XSL file from a JSF...

    - by Asela
    Hi all, I'm having 2 simple XML & XSL files as follows. form_1.xml <?xml version="1.0" encoding="windows-1252"?> <?xml-stylesheet type="text/xsl" href="form_1.xsl"?> <myform> </myform> form_1.xsl <?xml version="1.0" encoding="windows-1252"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="myform"> <html> <body> <form> <div align="center"> <h2>My first form in XSL</h2> <table cellspacing="1" cellpadding="1"> <tr> <td>First name : </td> <td> <input type="text"></input> </td> </tr> <tr> <td>Last name : </td> <td> <input type="text"></input> </td> </tr> <tr> <td>Address : </td> <td> <input type="text"></input> </td> </tr> </table> </div> </form> </body> </html> </xsl:template> </xsl:stylesheet> Now I have a JSF file where I have embeded the form_1.xml file inside an iFrame. Inside my JSF, I have submit & reset buttons as follows. myJsf.xhtml <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:utils="http://java.sun.com/jsf/composite/utils"> <h:head> <title>::: The form filler application :::</title> <link href="./css/styles.css" rel="stylesheet" type="text/css" /> </h:head> <h:body> <div align="center"> <table cellspacing="2" cellpadding="2"> <tr> <th class="title">&nbsp; My form filler &nbsp;</th> </tr> </table> <br /> <fieldset><legend>Fill appropriate data in the following form</legend> <h:form> <div align="center"> <table> <tr> <td colspan="2"><iframe src="form_1.xml" frameborder="0" width="500px" height="500px"></iframe></td> </tr> <tr></tr> <tr> <td align="right"><h:commandButton value="Save data" action="#{myManagedBean.printValuesEnteredInTheForm}" /></td> <td align="left"><h:commandButton type="reset" value="Clear" /></td> </tr> </table> </div> </h:form></fieldset> </div> </h:body> </html> Now my question is that upon clicking the Submit button in my JSF, how do I access the values which I have entered in the XSL file? Any help is greatly appreciated. Thanks in advance. Reagrds, Asela.

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  • XSL Reuse? YES! But: Element must not contain an xsl:import element! :-(

    - by Fedor Steeman
    I am using a heavy stylesheet with a lot of recurring transformations, so I thought it would be smart to reuse the same chunks of code, so I would not need to make the same changes at a bunch of different places. So I discovered , but -alas- it won't allow me to do it. When trying to run it in Sonic Workbench I get the following error: An xsl:for-each element must not contain an xsl:import element This is my stylesheet code: <xsl:template match="/"> <InboundFargoMessage> <EdiSender> <xsl:value-of select="TransportInformationMessage/SenderId"/> </EdiSender> <EdiReceiver> <xsl:value-of select="TransportInformationMessage/RecipientId"/> </EdiReceiver> <EdiSource>PORLOGIS</EdiSource> <EdiDestination>FARGO</EdiDestination> <Transportations> <xsl:for-each select="TransportInformationMessage/TransportUnits/TransportUnit"> <xsl:import href="TransportCDMtoFDM_V0.6.xsl"/> </xsl:for-each> <xsl:for-each select="TransportInformationMessage/Waybill/TransportUnits/TransportUnit"> <xsl:import href="TransportCDMtoFDM_V0.6.xsl"/> </xsl:for-each> </Transportations> </InboundFargoMessage> </xsl:template> </xsl:stylesheet> I will leave out the child xsl-sheets for now, as the problem appears to be happening at the base. If I cannot use xsl:import, is there any option of reuse?

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  • How to improve variable overriding/overwriting in XSL?

    - by ChrisBenyamin
    I want to do the following: Declare a variable Go into a if-statement Overwrite the variable XSL says I can't declare a variable twice, so what can I do to improve this step? Another approach was to check if a variable is set at all. I did this, because i skipped the first step and declared the variable in the if-statement. In another if-statement I wanted to check if the variable exists at all.

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  • Nodes set of the same type with if-test. Make it less.

    - by Kalinin
    How to make the code more beautiful (compact)? <xsl:template match="part"> <table class="part"> <xsl:if test="name != ''"> <tr> <td>????????</td><td><xsl:value-of select="name"/></td> </tr> </xsl:if> <xsl:if test="model != ''"> <tr> <td>??????</td><td><xsl:value-of select="model"/></td> </tr> </xsl:if> <xsl:if test="year != ''"> <tr> <td>???</td><td><xsl:value-of select="year"/></td> </tr> </xsl:if> <xsl:if test="glass_type != ''"> <tr> <td>???</td><td><xsl:value-of select="glass_type"/></td> </tr> </xsl:if> <xsl:if test="scancode != ''"> <tr> <td>???????</td><td><xsl:value-of select="scancode"/></td> </tr> </xsl:if> <xsl:if test="eurocode != ''"> <tr> <td>???????</td><td><xsl:value-of select="eurocode"/></td> </tr> </xsl:if> <xsl:if test="coment != ''"> <tr> <td>???????????</td><td><xsl:value-of select="coment"/></td> </tr> </xsl:if> <xsl:if test="glass_size != ''"> <tr> <td>??????</td><td><xsl:value-of select="glass_size"/></td> </tr> </xsl:if> <xsl:if test="vendor != ''"> <tr> <td>?????????????</td><td><xsl:value-of select="vendor"/></td> </tr> </xsl:if> <xsl:if test="trademark != ''"> <tr> <td>???????? ?????</td><td><xsl:value-of select="trademark"/></td> </tr> </xsl:if> <xsl:if test="fprice != ''"> <tr> <td>????</td><td><xsl:value-of select="fprice"/></td> </tr> </xsl:if> </table> </xsl:template> Update: i wrote: <my:translations xmlns:my="my:my"> <w e="name" r="????????"/> <w e="model" r="??????"/> <w e="year" r="???"/> <w e="glass_type" r="???"/> <w e="scancode" r="???????"/> <w e="eurocode" r="???????"/> <w e="comment" r="???????????"/> <w e="glass_size" r="??????"/> <w e="vendor" r="?????????????"/> <w e="trademark" r="???????? ?????"/> <w e="fprice" r="????"/> </my:translations> <xsl:value-of select="//w/@r"/> And have no result from this code. Is it normal? And how can i get new element w?

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  • How- XLST Transformation

    - by Yuan Ray
    Just wanted to ask on how to get the author names in the given xml sample below and put an attribut of eq="yes". EQ means Equal Contributors. This is the XML. <ArticleFootnote Type="Misc"> <Para>John Doe and Jane Doe are equal contributors.</Para> </ArticleFootnote> This should be the output in other form of XML. <AuthorGroups> <Authors eq="yes">John Doe</Authors> <Authors eq="yes">Jane Doe</Authors> </AuthorGroups> Assuming that JOhn Doe and Jane Doe are already defined in the list of authors but after the transformation, author tag should have the attribute eq="yes". Please help as I don't know much writing in xlst. Thanks in advance.

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  • Get subdomain of XML page from XSL

    - by fudgey
    I am working with a guild hosting site that provides an XML/XSL transformation widget where all I need to do is enter the URL for the XML and XSL and it does the rest. I have written an XSL transform to display a World of Warcraft armory page: Here is an example XML page (view source to see it) of the group I'm trying to help now. So, the user is entering their own XML page url (which has an eu subdomain in this case, but it is not within the XML itself). So when I make links to the character url, I need to add the entire url <a target="_blank" href="http://eu.wowarmory.com/character-sheet.xml?{@url}"> <xsl:value-of select="@name"/> </a> But I can't just set the domain to eu since there are multiple regions. Here are the possibilities: us = www, europe = eu, korea = kr, china = cn and taiwan = tw. Here is a snippet of the XML which shows the url parameters: <character achPoints="4275" classId="3" genderId="0" level="80" name="Virtex" raceId="4" rank="2" url="r=Drek%27Thar&amp;cn=Virtex"/> I guess I could just have the user add a small bit of HTML with their region in another part of their page, something like <div id="region">eu</div>, but I'm trying to make this work without any extra coding on their part. Edit: Ok, my question explicitly stated: How do I get the URL subdomain using XSL?

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  • What's the best way to only output a tag if it exists in XSL?

    - by Morinar
    I'm working on an interface with a 3rd party app that basically needs to take XML that was spat out by the app and convert it into XML our system can deal with. It's basically just applying a stylesheet to the original XML to make it looks like "our" XML. I've noticed that in other stylesheets we have, there are constructs like this: <xsl:for-each select="State"> <StateAbbreviation> <xsl:value-of select="."/> </StateAbbreviation> </xsl:for-each> Basically, the "in" XML has a State tag that I need to output as our recognized StateAbbreviation tag. However, I want to ONLY output the StateAbbreviation tag if the "in" XML contains the State tag. The block above accomplishes this just fine, but is not very intuitive (at least it wasn't to me), as every time I see a for-each I assume there is more than one, whereas in these cases there is 0 or 1. My question: is that a standard-ish construct? If not, is there a more preferred way to do it? I could obviously check the string length (which is also being done in other stylesheets), but would like to do it the same, "best" way everywhere (assuming of course that a "best" way exists. Advice? Suggestions?

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  • XSL: How to print an iterated node in for-each

    - by Shoaib
    xml: <skills> <skill>PHP</skill> <skill>CSS</skill> <skill>HTML</skill> <skill>XML</skill> </skills> XSL: <ul> <xsl:for-each select="skills/skill"> <li><xsl:value-of select="[what should be xpath here]" /></li </xsl:for-each> </ul> Here what should be the xpath to print each skill?

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  • Embedding XSL Stylesheet into XML

    - by user700996
    I have the following XML: <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="http://www.fakedomain.com/sally.xsl"?> And the following content in sally.xsl: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <xsl:for-each select="documentcollection/document"> <p> <xsl:for-each select="rss/channel/item"> <xsl:value-of select="title"/><br /> <xsl:value-of select="description"/><br /> <xsl:value-of select="link"/><br /> </xsl:for-each> </p> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet> However, the browser displays the XML as though the XSL line is not present. Do you know why the browser is ignoring the XSL stylesheet? Is the style sheet wrong? Thanks

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  • XPath ordered priority attribute search

    - by user94000
    I want to write an XPath that can return some link elements on an HTML DOM. The syntax is wrong, but here is the gist of what I want: //web:link[@text='Login' THEN_TRY @href='login.php' THEN_TRY @index=0] THEN_TRY is a made-up operator, because I can't find what operator(s) to use. If many links exist on the page for the given set of [attribute=name] pairs, the link which matches the most left-most attribute(s) should be returned instead of any others. For example, consider a case where the above example XPath finds 3 links that match any of the given attributes: link A: text='Sign In', href='Login.php', index=0 link B: text='Login', href='Signin.php', index=15 link C: text='Login', href='Login.php', index=22 Link C ranks as the best match because it matches the First and Second attributes. Link B ranks second because it only matches the First attribute. Link A ranks last because it does not match the First attribute; it only matches the Second and Third attributes. The XPath should return the best match, Link C. If more than one link were tied for "best match", the XPath should return the first best link that it found on the page.

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  • How do I get a less than in a javascript for loop in XSL to work?

    - by Kyle
    I am using CDATA to escape the script but in IE8's debugger I still get this message: "Expected ')'" in the for loop conditions. I am assuming it still thinks that the ; in the &lt; generated by CDATA is ending the loop conditions. Original script in my XSL template: <script type="text/javascript" language="javascript"> <![CDATA[ function submitform(form){ var oErrorArray = new Array(); for (i=0;i<form.length;i++) eval("oErrorArray["+i+"]=oError"+i); var goForm = true; for(i=0;i<form.length;i++) { oErrorArray[i].innerHTML = ""; if(form[i].value="")){ oErrorArray[i].innerHTML = "Error - input field is blank"; goForm = false; } } if(goForm == true) form.submit(); } function resetform(form){ form.reset(); } ]]> </script> Code generated after transformation (from IE8 debugger): <script type="text/javascript" language="javascript"> function submitform(form){ var oErrorArray = new Array(); for (i=0;i&lt;form.length;i++) eval("oErrorArray["+i+"]=oError"+i); goForm = true; for(i=0;i&lt;form.length;i++) { oErrorArray[i].innerHTML = ""; if(form[i].value="")){ oErrorArray[i].innerHTML = "Error - input field is blank"; goForm = false; } } if(goForm == true) form.submit(); } function resetform(form){ form.reset(); } </script> Error reported by IE8 debugger: Expected ')' login.xml, line 29 character 30 (which is right after the first "form.length")

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  • How to filter what is shown in the for-each loop in XSL

    - by Denoteone
    I thought it would be as easy as tell the for-each to only select top_coach_sales_vw that has "Site" equal to "PB" but when I run the script it does not loop through any of the data in the XML. I am escaping the single quotes because it is part of a php echo. <xsl:for-each select="NewDataSet/top_coach_sales_vw[Site==\'PB\']"> <td><xsl:value-of select="name"/></td> <td><xsl:value-of select="Site"/></td> <td><xsl:value-of select="Status"/></td> </xsl:for-each> XML: <NewDataSet> <top_coach_sales_vw> <name>Mike</name> <Site>PB</Site> <State>Ready</State> </top_coach_sales_vw> <top_coach_sales_vw> <name>Bill</name> <Site>EL</Site> <State>Talking</State> </top_coach_sales_vw> <top_coach_sales_vw> <name>Ted</name> <Site>PB</Site> <State>Ready</State> </top_coach_sales_vw> </NewDataSet>

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