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  • problem with enable/disable button using javascript

    - by LiveEn
    Im am trying to add a check box that will enable/disable the edit button. Im retrieving a price list and displaying it inside a table. When i add the javascript into the php code it doesn't work. Below is my code <table border="1"> <tr> <td width="100">Fee % </td> <td width="100">Price</td> <td width="100">Total</td> <td width="102">&nbsp;</td> </tr> <tr> <?php $sql1="select * from pricelist"; $result1=mysql_query($sql1) or die(mysql_error()); while ($row=mysql_fetch_array($result1)) { $id=$row['id']; $price=$row['h_price']; $a=0; print "<form id='form1' name='$a+' method='post' action=''>"; print "<td><input name='fees' value ='$fees' type='text' size='4' /></td>"; print "<td><input name='price' value ='$price' type='text' size='15' /></td>"; echo "<td><input type='checkbox' onclick='this.$a+.disabled = !this.checked;'><td>"; print"<td><input type='submit' name='$a+' value='Submit' disabled='disabled' /></td>"; print "</tr>"; print "</form>"; } ?> </table> Can someone please tell me what am i doing wrong? Thanks

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  • Problem with parsing strings

    - by Peter Small
    I am trying to put a line of dialog on each of a series of images. To match the dialog line with the correct image, I end each line with a forward slash (/) followed by a number to identify the matching image. I then parse each line to get the dialog and then the reference number for the image. It all works fine except that when I put the dialog line into a textView I get the whole line in the textView instead of the dialog part. What is confusing is that the console seems to indicate that the parsing of the dialog line has been carried out correctly. Here are the details of my coding: @interface DialogSequence_1ViewController : UIViewController { IBOutlet UIImageView *theImage; IBOutlet UITextView *fullDialog; IBOutlet UITextView *selectedDialog; IBOutlet UIButton *test_1; IBOutlet UIButton *test_2; IBOutlet UIButton *test_3; NSArray *arrayLines; IBOutlet UISlider *readingSpeed; NSArray *cartoonViews; NSMutableString *dialog; NSMutableArray *dialogLineSections; int lNum; } @property (retain,nonatomic) UITextView *fullDialog; @property (retain,nonatomic) UITextView *selectedDialog; @property (retain,nonatomic) UIButton *test_1; @property (retain,nonatomic) UIButton *test_2; @property (retain,nonatomic) UIButton *test_3; @property (retain,nonatomic) NSArray *arrayLines; @property (retain,nonatomic) NSMutableString *dialog; @property (retain,nonatomic) NSMutableArray *dialogLineSections; @property (retain,nonatomic) UIImageView *theImage; @property (retain,nonatomic) UISlider *readingSpeed; -(IBAction)start:(id)sender; -(IBAction)counter:(id)sender; -(IBAction)runNextLine:(id)sender; @end @implementation DialogSequence_1ViewController @synthesize fullDialog; @synthesize selectedDialog; @synthesize test_1; @synthesize test_2; @synthesize test_3; @synthesize arrayLines; @synthesize dialog; @synthesize theImage; @synthesize readingSpeed; @synthesize dialogLineSections; -(IBAction)runNextLine:(id)sender{ //Get dialog line to display from the arrayLines array NSMutableString *dialogLineDetails; dialogLineDetails =[arrayLines objectAtIndex:lNum]; NSLog(@"dialogLineDetails = %@",dialogLineDetails); //Parse the dialog line dialogLineSections = [dialogLineDetails componentsSeparatedByString: @"/"]; selectedDialog.text =[dialogLineSections objectAtIndex: 0]; NSLog(@"Dialog part of line = %@",[dialogLineSections objectAtIndex: 0]); NSMutableString *imageBit; imageBit = [dialogLineSections objectAtIndex: 1]; NSLog(@"Image code = %@",imageBit); //Select right image int im = [imageBit intValue]; NSLog(@"imageChoiceInteger = %i",im); //------more code } I get a warning on the line: dialogLineSections = [dialogLineDetails componentsSeparatedByString: @"/"]; warning: incompatible Objective-C types assigning 'struct NSArray *', expected 'struct NSMutableArray *' I don't quite understand this and have tried to change the types but to no avail. Would be grateful for some advice here.

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  • problem with Infopath web services

    - by AB
    I want to have some url for my infopath form and give that link to user instead of going to form library and click new...how is it possible? Also when I created Infopath form I have given some text fields and button, I don't want the Infopath services buttons(Save,save as...) how I cna remove those? Any suggestions would really be appreciated...Thanks

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  • Problem in getting Http Response in chrome

    - by Bhaskasr
    Am trying to get http response from php web service in javascript, but getting null in firefox and chrome. plz tell me where am doing mistake here is my code, function fetch_details() { if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest() alert("first"); } else { xhttp=new ActiveXObject("Microsoft.XMLHTTP") alert("sec"); } xhttp.open("GET","url.com",false); xhttp.send(""); xmlDoc=xhttp.responseXML; alert(xmlDoc.getElementsByTagName("Inbox")[0].childNodes[0].nodeValue); } I have tried with ajax also but am not getting http response here is my code, please guide me var xmlhttp = null; var url = "url.com"; if (window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); alert(xmlhttp); //make sure that Browser supports overrideMimeType if ( typeof xmlhttp.overrideMimeType != 'undefined') { xmlhttp.overrideMimeType('text/xml'); } } else if (window.ActiveXObject) { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); } else { alert('Perhaps your browser does not support xmlhttprequests?'); } xmlhttp.open('GET', url, true); xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState == 4) { alert(xmlhttp.responseXML); } }; } // Make the actual request xmlhttp.send(null); I am getting xmlhttp.readyState = 4 xmlhttp.status = 0 xmlhttp.responseText = "" plz tell me where am doing mistake

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  • Accessing database problem

    - by anarche
    Ok, so I've got an SQLiteOpenHelper that prepares and returns a SQLiteDatabase object; this is written singleton-pattern, so the database is opened once and only closed when the Activity closes. From there I have three database wrappers encapsulating the queries (some returning cursors to datasets, some inserting data) used by the Activity. I want to insert data from one View, then have that automatically update in another View on the same Dialogue. I'm writing this on a notepad and testing on the phone (since the emulator crashes the notepad...), so I can't pull up stacktraces atm. So questions: 1) are there limitations to writing to a database, when there are cursors open on the database? 2) Does a Cursor.requery()? call update the ListView with the cursor as a data connector?

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  • problem with python script

    - by hidayat
    I want to run a csh file from a python scrip, example, #!/usr/bin/python import os os.system("source path/to/file.csh") and I want this file to run in the same shell as I am running the python script, because the file.csh script is settings some environment variables that I need. Does anyone know how to do this in Python?

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  • Strange problem with simple multithreading program in Java

    - by Elizabeth
    Hello, I am just starting play with multithreading programming. I would like to my program show alternately character '-' and '+' but it doesn't. My task is to use synchronized keyword. As far I have: class FunnyStringGenerator{ private char c; public FunnyStringGenerator(){ c = '-'; } public synchronized char next(){ if(c == '-'){ c = '+'; } else{ c = '-'; } return c; } } class ThreadToGenerateStr implements Runnable{ FunnyStringGenerator gen; public ThreadToGenerateStr(FunnyStringGenerator fsg){ gen = fsg; } @Override public void run() { for(int i = 0; i < 10; i++){ System.out.print(gen.next()); } } } public class Main{ public static void main(String[] args) throws IOException { FunnyStringGenerator FSG = new FunnyStringGenerator(); ExecutorService exec = Executors.newCachedThreadPool(); for(int i = 0; i < 20; i++){ exec.execute(new ThreadToGenerateStr(FSG)); } } } EDIT: I also testing Thread.sleep in run method instead for loop.

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  • Problem with running JavaME

    - by Jamie
    Hi guys, I'm getting angry - I cant run the emulator (under vista x64). I still get the following error: Starting emulator in execution mode * Error * Failed to connect to device 2! Reason: Emulator 2 terminated while waiting for it to register! BUILD FAILED (total time: 26 seconds) I was trying to change the port to 1999, localhost to ip address and such stuff. Do you have any ideas what to do? Thank you in advance! Cheers

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  • Asp.Net(C#) inline coding problem

    - by oraclee
    Hi all; <% int i = Eval("NAME").ToString().IndexOf("."); string str = Eval("NAME").ToString().Substring(i + 1); %> <img src="../images/img_<%= str %>.gif" alt="" /> EVAL("test.txt") I need "txt" how to make ? Please Help Thank you

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  • a problem in socket programing in perl

    - by isu
    I write this code : #!/usr/local/bin/perl use strict; use LWP::UserAgent; my $ua = new LWP::UserAgent(agent => 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.0.5) Gecko/20060719 Firefox/1.5.0.5'); $ua->proxy([qw(http https)] => 'http://203.185.28.228:1080' #that is just socks:port); my $response = $ua->get("http://www.google.com"); print $response->code,' ', $response->message,"\n"; but when i execute it i get this error: 500 Can't connect to 203.185.28.228:1080 (connect: timeout) what am i going to do ?

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  • Problem with sys.argv[1] when unittest module is in a script

    - by chrissygormley
    Hello, I have a script that does various things and access paramenters using sys.argv but when the script gets to the unittest part of the code it says there is no module for this. The script that I have is: class MyScript(): def __init__(self): self.value = sys.argv[1] def hello(self): print self.value def suite(self): modules_to_test = ('external_sanity_onvif', 'starttest') alltests = unittest.TestSuite() for module in map(__import__, modules_to_test): alltests.addTest(unittest.findTestCases(module)) return alltests if __name__ == '__main__': Run = MyScript() Run.hello() log_file = 'log_file.txt' test_file = open(log_file, "w") runner = unittest.TextTestRunner(test_file) unittest.main(defaultTest='Run.suite', testRunner=runner) Say I enter ./script.py Hello in the command line. The error I get is: AttributeError: 'module' object has no attribute 'Hello' If I remove the unittest module it works. Also if I remove the testrunner log and leave it at: unittest.main(defaultTest='Run.suite') This still doesn't work. Can anyone help. Thanks

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  • Problem at JUnit test with generics

    - by Tom Brito
    In my utility method: public static <T> T getField(Object obj, Class c, String fieldName) { try { Field field = c.getDeclaredField(fieldName); field.setAccessible(true); return (T) field.get(obj); } catch (Exception e) { e.printStackTrace(); fail(); return null; } } The line return (T) field.get(obj); gives the warning "Type safety: Unchecked cast from Object to T"; but I cannot perform instanceof check against type parameter T, so what am I suppose to do here?

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  • Hibernate collection mapping Problem

    - by Geln Yang
    Hi, There is a table Item like, code,name 01,parent1 02,parent2 0101,child11 0102,child12 0201,child21 0202,child22 Create a java object and hbm xml to map the table.The Item.parent is a Item whose code is equal to the first two characters of its code : class Item{ String code; String name; Item parent; List<Item> children; .... setter/getter.... } <hibernate-mapping> <class name="Item" table="Item"> <id name="code" length="4" type="string"> <generator class="assigned" /> </id> <property name="name" column="name" length="50" not-null="true" /> <many-to-one name="parent" class="Item" not-found="ignore"> <formula> <![CDATA[ (select i.code,r.name from Item i where (case length(code) when 4 then i.code=SUBSTRING(code,1,2) else false end)) ]]> </formula> </many-to-one> <bag name="children"></bag> </class> </hibernate-mapping> I try to use formula to define the many-to-one relationship,but it doesn't work!Is there something wrong?Or is there other method? Thanks! ps,I use mysql database.

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  • Problem with writing a file to excel with spreadsheet

    - by winter sun
    I am trying to write excel file by using ruby 1.9 spreadsheet version 0.6.4.1 on windows. Everything is going ok, until I get to the book.write statement when I write book.write "c:/spreadsheet/excel-file.xls I keep getting the following error No such file or directory - c:/spreadsheet/excel-file.xls Can anyone tell me what I should change in this path name?

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  • PHP problem with die()

    - by ThinkingInBits
    So, I have this code: } else { $photograph_moderation = new PhotographModeration($this->photograph_id); $photograph_moderation->purgePhotograph(); //eventually take to an error page die('image is not big enough to upload'); } the purgePhotograph() function gets called properly when this condition is met, but the script never appears to die. Is there a reason why die wouldn't get called here? purgePhotograph() has no script killing commands either.

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  • PHP & MySQL Image deletion problem?

    - by IMAGE
    I have this script that deletes a users avatar image that is stored in a folder name thumbs and another named images and the image name is stored in a mysql database. But for some reason the script deletes all the users info for example if the users id is 3 all of the users info like first name last name age and so are deleted as well, basically everything is deleted including the user how do I fix this so only the images and image name is deleted? Here is the code. $user_id = '3'; if (isset($_POST['delete_image'])) { $a = "SELECT * FROM users WHERE avatar = '". $avatar ."' AND user_id = '". $user_id ."'"; $r = mysqli_query ($mysqli, $a) or trigger_error("Query: $a\n<br />MySQL Error: " . mysqli_error($mysqli)); if ($r == TRUE) { unlink("../members/" . $user_id . "/images/" . $avatar); unlink("../members/" . $user_id . "/images/thumbs/" . $avatar); $a = "DELETE FROM users WHERE avatar = '". $avatar ."' AND user_id = '". $user_id ."'"; $r = mysqli_query ($mysqli, $a) or trigger_error("Query: $a\n<br />MySQL Error: " . mysqli_error($mysqli)); } }

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  • How to solve problem when use jquery datepicker and validation in the same time

    - by uyquoc
    When I used datepicker with trigger icon so that users could choose date from clicking this icon or type directly in textbox (txtDate), I also used jquery validation to require textbox must be not empty. But when a user submit the form with empty textbox (txtDate.Text=""), the error message of validation push trigger icon to the right. Could you tell me the solution? Thank you very much!

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  • Printer Page Size Problem

    - by mRt
    I am trying to set a custom paper size by doing: Printer.Height = 2160 Printer.Width = 11900 But it doesn't seen to have any effect. After setting this up, i ask for that values and it returns the default ones. And this: Printer.PaperSize = 256 Returns an error... Any ideas??

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  • Problem with sending out variable to serial port using api JAVA

    - by sjaakensjon
    We are developing a java program for school. But we are experiencing problems with sending out a variable created by 3 sliders. The idea is that we have 3 sliders. One slider for every color. Red green and blue. The variable has to have a value between 0 and 255. Everytime the value of the slider changes is has to send a variable for the channel, that value is 1, 2 ,3. And after that it has to send the value of the slider through the serial port. Could you please help us out by creating an example program? Below is our code so far. Thanks in advance. Sjaak package main; import javax.swing.*; import javax.swing.event.*; import java.awt.*; import app.Com; import app.Parameters; public class menu{ JSlider sliderblauw; JLabel hoeveelblauw; JLabel blauw; JLabel rood; JSlider sliderrood; JLabel hoeveelrood; JLabel groen; JLabel hoeveelgroen; JSlider slidergroen; public menu(){ Frame venster = new JFrame("Color control"); JPanel blauwinstel = new JPanel(); ((JFrame) venster).setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); venster.setSize(500, 500); venster.setVisible(true); sliderblauw = new JSlider(JSlider.VERTICAL, 0, 255, 0); sliderblauw.addChangeListener(new veranderingblauw()); hoeveelblauw = new JLabel ("0"); blauwinstel.add(sliderblauw); blauwinstel.add(hoeveelblauw); venster.add(blauwinstel, BorderLayout.WEST); sliderblauw.setMajorTickSpacing(10); sliderblauw.setPaintTicks(true); JPanel roodinstel = new JPanel(); sliderrood = new JSlider(JSlider.VERTICAL, 0, 255, 0); sliderrood.addChangeListener(new veranderingrood()); hoeveelrood = new JLabel ("0"); roodinstel.add(sliderrood); roodinstel.add(hoeveelrood); venster.add(roodinstel, BorderLayout.EAST); sliderrood.setMajorTickSpacing(10); sliderrood.setPaintTicks(true); JPanel groeninstel = new JPanel(); slidergroen = new JSlider(JSlider.VERTICAL, 0, 255, 0); slidergroen.addChangeListener(new veranderinggroen()); hoeveelgroen = new JLabel ("0"); groeninstel.add(slidergroen); groeninstel.add(hoeveelgroen); venster.add(groeninstel, BorderLayout.CENTER); slidergroen.setMajorTickSpacing(10); slidergroen.setPaintTicks(true); } public class veranderingblauw implements ChangeListener{ public void stateChanged(ChangeEvent ce){ int value = sliderblauw.getValue(); String waarde_blauw = Integer.toString(value); hoeveelblauw.setText(waarde_blauw); }} public class veranderingrood implements ChangeListener{ public void stateChanged(ChangeEvent ce){ int value = sliderrood.getValue(); String waarde_rood = Integer.toString(value); hoeveelrood.setText(waarde_rood); }} public class veranderinggroen implements ChangeListener{ public void stateChanged(ChangeEvent ce){ int value = slidergroen.getValue(); String waarde_groen = Integer.toString(value); hoeveelgroen.setText(waarde_groen); }} public static void main( String[] args) { new menu(); } }

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  • js regexp problem

    - by Alexander
    I have a searching system that splits the keyword into chunks and searches for it in a string like this: var regexp_school = new RegExp("(?=.*" + split_keywords[0] + ")(?=.*" + split_keywords[1] + ")(?=.*" + split_keywords[2] + ").*", "i"); I would like to modify this so that so that I would only search for it in the beginning of the words. For example if the string is: "Bbe be eb ebb beb" And the keyword is: "be eb" Then I want only these to hit "be ebb eb" In other words I want to combine the above regexp with this one: var regexp_school = new RegExp("^" + split_keywords[0], "i"); But I'm not sure how the syntax would look like. I'm also using the split fuction to split the keywords, but I dont want to set a length since I dont know how many words there are in the keyword string. split_keywords = school_keyword.split(" ", 3); If I leave the 3 out, will it have dynamic lenght or just lenght of 1? I tried doing a alert(split_keywords.lenght); But didnt get a desired response

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  • GCC problem with raw double type comparisons

    - by Monomer
    I have the following bit of code, however when compiling it with GCC 4.4 with various optimization flags I get some unexpected results when its run. #include <iostream> int main() { const unsigned int cnt = 10; double lst[cnt] = { 0.0 }; const double v[4] = { 131.313, 737.373, 979.797, 731.137 }; for(unsigned int i = 0; i < cnt; ++i) { lst[i] = v[i % 4] * i; } for(unsigned int i = 0; i < cnt; ++i) { double d = v[i % 4] * i; if(lst[i] != d) { std::cout << "error @ : " << i << std::endl; return 1; } } return 0; } when compiled with: "g++ -pedantic -Wall -Werror -O1 -o test test.cpp" I get the following output: "error @ : 3" when compiled with: "g++ -pedantic -Wall -Werror -O2 -o test test.cpp" I get the following output: "error @ : 3" when compiled with: "g++ -pedantic -Wall -Werror -O3 -o test test.cpp" I get no errors when compiled with: "g++ -pedantic -Wall -Werror -o test test.cpp" I get no errors I do not believe this to be an issue related to rounding, or epsilon difference in the comparison. I've tried this with Intel v10 and MSVC 9.0 and they all seem to work as expected. I believe this should be nothing more than a bitwise compare. If I replace the if-statement with the following: if (static_cast<long long int>(lst[i]) != static_cast<long long int>(d)), and add "-Wno-long-long" I get no errors in any of the optimization modes when run. If I add std::cout << d << std::endl; before the "return 1", I get no errors in any of the optimization modes when run. Is this a bug in my code, or is there something wrong with GCC and the way it handles the double type?

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  • Write problem - lossing the original data

    - by John
    Every time I write to the text file I will lose the original data, how can I read the file and enter the data in the empty line or the next line which is empty? public void writeToFile() { try { output = new Formatter(myFile); } catch(SecurityException securityException) { System.err.println("Error creating file"); System.exit(1); } catch(FileNotFoundException fileNotFoundException) { System.err.println("Error creating file"); System.exit(1); } Scanner scanner = new Scanner (System.in); String number = ""; String name = ""; System.out.println("Please enter number:"); number = scanner.next(); System.out.println("Please enter name:"); name = scanner.next(); output.format("%s,%s \r\n", number, name); output.close(); }

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  • Mysql table data problem?

    - by DaTeNtImE
    I'm new to mysql and was wondering how can I add the users birthdate in the following HTML format to the MYSQL table data listed below? How would the structure look like for example email VARCHAR(80) NOT NULL,? Here is the HTML code below. <li><label>Date of Birth: </label> <label for="month">Month: </label> <select name="month" id="month"> <option value="January">January</option> <option value="February">February</option> <option value="March">March</option> <option value="April">April</option> <option value="May">May</option> <option value="June">June</option> <option value="July">July</option> <option value="August">August</option> <option value="September">September</option> <option value="October">October</option> <option value="November">November</option> <option value="December">December</option> </select> <label for="day">Day: </label> <select id="day" name="day"> <option value="0" selected="selected">Day</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <label for="year">Year: </label><input type="text" name="year" id="year" /></li> Here is the MySQL table data. CREATE TABLE users ( user_id INT UNSIGNED NOT NULL AUTO_INCREMENT, first_name VARCHAR(20) NOT NULL, last_name VARCHAR(40) NOT NULL, email VARCHAR(80) NOT NULL, pass CHAR(40) NOT NULL, user_level TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, active CHAR(32), registration_date DATETIME NOT NULL, PRIMARY KEY (user_id), UNIQUE KEY (email), INDEX login (email, pass) );

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  • Just a small problem regarding javscript BOM question

    - by caramel1991
    The question is this: Create a page with a number of links. Then write code that fires on the window onload event, displaying the href of each of the links on the page. And this is my solution <html> <body language="Javascript" onload="displayLink()"> <a href="http://www.google.com/">First link</a> <a href="http://www.yahoo.com/">Second link</a> <a href="http://www.msn.com/">Third link</a> <script type="text/javascript" language="Javascript"> function displayLink() { for(var i = 0;document.links[i];i++) { alert(document.links[i].href); } } </script> </body> </html> This is the answer provided by the book <html> <head> <script language=”JavaScript” type=”text/javascript”> function displayLinks() { var linksCounter; for (linksCounter = 0; linksCounter < document.links.length; linksCounter++) { alert(document.links[linksCounter].href); } } </script> </head> <body onload=”displayLinks()”> <A href=”link0.htm” >Link 0</A> <A href=”link1.htm”>Link 2</A> <A href=”link2.htm”>Link 2</A> </body> </html> Before I get into the javascript tutorial on how to check user browser version or model,I was using the same method as the example,by acessing the length property of the links array for the loop,but after I read through the tutorial,I find out that I can also use this alternative ways,by using the method that the test condition will evalute to true only if the document.links[i] return a valid value,so does my code is written using the valid method??If it's not,any comment regarding how to write a better code??Correct me if I'm wrong,I heard some of the people say "a good code is not evaluate solely on whether it works or not,but in terms of speed,the ability to comprehend the code,and could posssibly let others to understand the code easily".Is is true??

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