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  • How to launch a browser in view source mode?

    - by JorgeLarre
    I want to open a file in a web browser (anyone will do) and I want to see it in the view source mode instead of in the standard browser window. This can be done in two steps, by opening the file and then go to the view source window (different shortcuts in each browser), but I want to directly go to the view source window. I have not found any such command line argument for Firefox nor Chrome. Is this possible just with the base browser functionality?

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  • How can I render an in-memory UIViewController's view Landscape?

    - by Aaron
    I'm trying to render an in-memory (but not in hierarchy, yet) UIViewController's view into an in-memory image buffer so I can do some interesting transition animations. However, when I render the UIViewController's view into that buffer, it is always rendering as though the controller is in Portrait orientation, no matter the orientation of the rest of the app. How do I clue this controller in? My code in RootViewController looks like this: MyUIViewController* controller = [[MyUIViewController alloc] init]; int width = self.view.frame.size.width; int height = self.view.frame.size.height; int bitmapBytesPerRow = width * 4; unsigned char *offscreenData = calloc(bitmapBytesPerRow * height, sizeof(unsigned char)); CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); CGContextRef offscreenContext = CGBitmapContextCreate(offscreenData, width, height, 8, bitmapBytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast); CGContextTranslateCTM(offscreenContext, 0.0f, height); CGContextScaleCTM(offscreenContext, 1.0f, -1.0f); [(CALayer*)[controller.view layer] renderInContext:offscreenContext]; At that point, the offscreen memory buffers contents are portrait-oriented, even when the window is in landscape orientation. Ideas?

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  • html code in anchor tag text in c# razor

    - by Tripping
    I am trying to show the rupee sign: ₹ code: &#8377 ; in my anchor tag. I have tried a few things but nothing works ... please help @{ string _text = String.Format("{0} {1} {2} {3} {4}", @Html.DisplayFor(model => model.NoOfBedrooms), "bedroom flat", @Html.DisplayFor(model => model.TransactionTypeDescription), @Html.Raw(&#8377;), @Html.DisplayFor(model => model.Price)); string _rental = ""; if (Model.TransactionType == 2) { _rental = " per month"; } else { _rental = ""; }; string _linkText = _text + _rental; } @Html.ActionLink(_linkText, "Details", "Property", new { id = Model.PropertyId }, null)

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  • Bad practice to have models made up of other models?

    - by mattruma
    I have a situation where I have Model A that has a variety of properties. I have discovered that some of the properties are similar across other models. My thought was I could create Model B and Model C and have Model A be a composite with a Model B property and a Model C property. Just trying to determine if this is the best way to handle this situation.

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  • Default controller name is removed on browser refresh (CodeigniterPHP/Nginx issue?)

    - by tim peterson
    For all pages in my codeigniter app except my default controller, when I refresh the browser the url isn't affected as one would expect. However for my default controller, main.php, when when I refresh the browser at "http://localhost/main" or "http://mysite.com/main", the main part is stripped off the url. So the browser bar shows just "http://localhost" or "http://mysite.com". Totally lost on where to start with this but was just wondering if anyone has come across this before...? Here's what I think could be the relevant part of my nginx.conf (if Nginx is the problem). if ($request_uri ~* ^(/main(/index)?|/index(.php)?)/?$) { rewrite ^(.*)$ / permanent; }

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  • ASP.NET MVC Unit Testing Controllers - Repositories

    - by Brian McCord
    This is more of an opinion seeking question, so there may not be a "right" answer, but I would welcome arguments as to why your answer is the "right" one. Given an MVC application that is using Entity Framework for the persistence engine, a repository layer, a service layer that basically defers to the repository, and a delete method on a controller that looks like this: public ActionResult Delete(State model) { try { if( model == null ) { return View( model ); } _stateService.Delete( model ); return RedirectToAction("Index"); } catch { return View( model ); } } I am looking for the proper way to Unit Test this. Currently, I have a fake repository that gets used in the service, and my unit test looks like this: [TestMethod] public void Delete_Post_Passes_With_State_4() { //Arrange var stateService = GetService(); var stateController = new StateController( stateService ); ViewResult result = stateController.Delete( 4 ) as ViewResult; var model = (State)result.ViewData.Model; //Act RedirectToRouteResult redirectResult = stateController.Delete( model ) as RedirectToRouteResult; stateController = new StateController( stateService ); var newresult = stateController.Delete( 4 ) as ViewResult; var newmodel = (State)newresult.ViewData.Model; //Assert Assert.AreEqual( redirectResult.RouteValues["action"], "Index" ); Assert.IsNull( newmodel ); } Is this overkill? Do I need to check to see if the record actually got deleted (as I already have Service and Repository tests that verify this)? Should I even use a fake repository here or would it make more sense just to mock the whole thing? The examples I'm looking at used this model of doing things, and I just copied it, but I'm really open to doing things in a "best practices" way. Thanks.

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  • JPA: what is the proper pattern for iterating over large result sets?

    - by Caffeine Coma
    Let's say I have a table with millions of rows. Using JPA, what's the proper way to iterate over a query against that table, such that I don't have all an in-memory List with millions of objects? I suspect that the following will blow up if the table is large: List<Model> models = entityManager().createQuery("from Model m", Model.class).getResultList(); for (Model model : models) { // do something with model } Is pagination (looping and manually updating setFirstResult()/setMaxResult()) really the best solution?

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  • How can I hook up an IBAction method to a plain view for a touch up event?

    - by Thanks
    I have created a blank new view-based application project in Xcode. It generated a myProjectViewController and an nib for it. In that nib for that view controller, there is just one view. I wanted to test some event handling stuff and created an -(IBAction) method that will just log a "hello world" when I touch the view. But for some reason, IB doesn't give me a chance to hook up the action. What am I doing wrong there? I also tried to put a UIView as subview there. When I drag from that to File's Owner (whoose class is the myProjectViewController, where I have the IBAction in the header), doesn't even mention the IBAction. But it actually should, right?

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  • View / ViewModel - what is the sense (in a WPF control)?

    - by TomTom
    Not as funny as it sounds. Normally the View / ViewModel should decouple the presentation from the business logic. Good. Now, a Control in WPF is basically invisible unless made different (with the exceptions of UserControl and Window that have XAML directly attached). The Style is putting in the "visual presentation" - which basically means a Control does not need a view mechanism as WPF already has one? In addition. the ViewModel is actually part of the Control, or? Just fighting with that stuff. I know in ASP.NET, WinForms the separation makes a lot of sense - but there, basically, controls HAVE an intrinsic look. In WPF, I have some where it makes sense (derived from UserControl), but for the majority of the controls I write, the View & ViewModel look like pretty much totally superflous thanks to the already presenting view mechanism.

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  • If I create a transient property in the model, isn't this managed by core data then?

    - by mystify
    Just to grok this: If I had a transient property, lets say averagePrice, and I mark that as "transient" in the data modeler: This will not be persistet, and no column will be created in SQLite for that? And: If I make my own NSManagedObject subclass with an averagePrice property, does it make any sense to model that property in the xcdatamodel file? Would it make a difference if I would simply create a property in my subclass and not model that in the entity? (I think: yes, it doesn't matter at all ... but not sure)

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  • Oracle: Is there a way to get the column data types for a view?

    - by rally25rs
    For a table in oracle, I can query "all_tab_columns" and get table column information, like the data type, precision, whether or not the column is nullable. In SQL Developer or TOAD, you can click on a view in the GUI and it will spit out a list of the columns that the view returns and the same set of data (data type, precision, nullable, etc). So my question is, is there a way to query this column definition for a view, the way you can for a table? How do the GUI tools do it?

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  • How to call a php controller method using jquery?

    - by chandru_cp
    I am developing a web application and i am integrating jquery in it... Now looking for ajax calls with jquery to my controller function.... jquery.ajax() would be useful i think so... But how to call my controller method.... $.ajax({ type: "POST", url: "", data: "", contentType: "application/json; charset=utf-8", async: false, dataType: "json", success: function(jsonObj) { function loadbookdetails() { //Paging $college=$_SESSION['college']; $this->load->library('pagination'); $data['bookdetails'] = $this->librarymodel->selectbook($college); //$data['rackOptionData'] = $this->librarymodel->selectrack(); if(empty($data['bookdetails'])) { $data['comment'] = 'no record found!'; } $this->load->view('bookdetials',$data); } I am fetching this records here how to use it with jquery.ajax() function and how to convert $data to json and use it with jquery and iterate with a table...

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  • How can I display the camera view in the main window in real time?

    - by Mongrel Warfare
    I'm trying to make an augmented reality application with a waypoint structure, like Yelp, and I'm wondering how to set up my main view so that it displays the camera view on the whole screen. I've heard of using the UIImagePickerController Class, but I'm unsure how to manipulate the code so that it doesn't actually take a picture, but just stays in the view mode. Any help would be appreciated, thanks!

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  • Type casting Collections using Conversion Operators

    - by Vyas Bharghava
    The below code gives me User-defined conversion must convert to or from enclosing type, while snippet #2 doesn't... It seems that a user-defined conversion routine must convert to or from the class that contains the routine. What are my alternatives? Explicit operator as extension method? Anything else? public static explicit operator ObservableCollection<ViewModel>(ObservableCollection<Model> modelCollection) { var viewModelCollection = new ObservableCollection<ViewModel>(); foreach (var model in modelCollection) { viewModelCollection.Add(new ViewModel() { Model = model }); } return viewModelCollection; } Snippet #2 public static explicit operator ViewModel(Model model) { return new ViewModel() {Model = model}; } Thanks in advance!

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  • How to show empty view when ListView is empty?

    - by Sheehan Alam
    Here is my layout. For some reason the empty view (TextView in this case) always appears, even when the List is not empty. I thought the ListView would automatically detect when to show the empty view. How can I hook up the empty view properly? <RelativeLayout android:id="@+id/LinearLayoutAR" android:layout_height="fill_parent" android:layout_width="fill_parent"> <ListView android:layout_width="fill_parent" android:layout_height="fill_parent" xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/ARListView"></ListView> <ProgressBar android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/arProgressBar" android:layout_centerHorizontal="true" android:layout_centerVertical="true"></ProgressBar> <!-- Here is the view to show if the list is emtpy --> <TextView android:id="@id/android:empty" android:layout_width="match_parent" android:layout_height="match_parent" android:text="No Results" /> </RelativeLayout>

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  • Passing ViewModel for backbone.js from MVC3 Server-Side

    - by Roman
    In ASP.NET MVC there is Model, View and Controller. MODEL represents entities which are stored in database and essentially is all the data used in a application (for example, generated by EntityFramework, "DB First" approach). Not all data from model you want to show in the view (for example, hashs of passwords). So you create VIEW MODEL, each for every strongly-typed-razor-view you have in application. Like this: using System; using System.Collections.Generic; using System.Linq; using System.Web; namespace MyProject.ViewModels.SomeController.SomeAction { public class ViewModel { public ViewModel() { Entities1 = new List<ViewEntity1>(); Entities2 = new List<ViewEntity2>(); } public List<ViewEntity1> Entities1 { get; set; } public List<ViewEntity2> Entities2 { get; set; } } public class ViewEntity1 { //some properties from original DB-entity you want to show } public class ViewEntity2 { } } When you create complex client-side interfaces (I do), you use some pattern for javascript on client, MVC or MVVM (I know only these). So, with MVC on client you have another model (Backbone.Model for example), which is third model in application. It is a bit much. Why don`t we use the same ViewModel model on a client (in backbone.js or another framework)? Is there a way to transfer CS-coded model to JS-coded? Like in MVVM pattern, with knockout.js, when you can do like this: in SomeAction.cshtml: <div style="display: none;" id="view_model">@Json.Encode(Model)</div> after that in Javascript-code var ViewModel = ko.mapping.fromJSON($("#view_model").get(0).innerHTML); now you can extend your ViewModel with some actions, event handlers, etc: ko.utils.extend(ViewModel, { some_function: function () { //some code } }); So, we are not building the same view model on the client again, we are transferring existing view model from server. At least, data. But knockout.js is not suitable for me, you can`t build complex UI with it, it is just data-binding. I need something more structural, like backbone.js. The only way to build ViewModel for backbone.js I can see now is re-writing same ViewModel in JS from server with hands. Is there any ways to transfer it from server? To reuse the same viewmodel on server view and client view?

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  • Visual-C++ Linker Error

    - by LordByron
    I have a class called MODEL in which public static int theMaxFrames resides. The class is defined in its own header file. theMaxFrames is accessed by a class within the MODEL class and by one function, void set_up(), which is also in the MODEL class. The Render.cpp source file contains a function which calls a function in the Direct3D.cpp source file which in turn calls the set_up() function through a MODEL object. This is the only connection between these two source files and theMaxFrames. When I try to compile my code I get the following error messages: 1Direct3D.obj : error LNK2001: unresolved external symbol "public: static int MODEL::theMaxFrames" (?theMaxFrames@MODEL@@2HA) 1Render.obj : error LNK2001: unresolved external symbol "public: static int MODEL::theMaxFrames" (?theMaxFrames@MODEL@@2HA) 1C:\Users\Byron\Documents\Visual Studio 2008\Projects\xFileViewer\Debug\xFileViewer.exe : fatal error LNK1120: 1 unresolved externals

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  • In which controller do you put the CRUD for the child part of a relationship?

    - by uriDium
    I am using ASP.Net MVC but this probably applies to all MVC patterns in general. My problem, for example I have companies and in each company I have a list of contacts. When I have selected a company I can see its details and a list of the contacts for that company. When I want to add a new contact for that company, should the implementation of that action go into the company controller as an "AddContact" action or should it go into the contact controller into a "New" action and we pass the Company ID in the URL? What is the usual way of dealing with this sort of thing in ASP.Net MVC? Is there a better stategy?

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  • How can I keep the the logic to translate a ViewModel's values to a Where clause to apply to a linq query out of My Controller?

    - by Mr. Manager
    This same problem keeps cropping up. I have a viewModel that doesn't have any persistent backing. It is just a ViewModel to generate a search input form. I want to build a large where clause from the values the user entered. If the Action Accepts as a parameter SearchViewModel How do I do this without passing my viewModel to my service layer? Service shouldn't know about ViewModels right? Oh and if I serialize it, then it would be a big string and the key/values would be strongly typed. SearchViewModel this is just a snippet. [Display(Name="Address")] public string AddressKeywords { get; set; } /// <summary> /// Gets or sets the census. /// </summary> public string Census { get; set; } /// <summary> /// Gets or sets the lot block sub. /// </summary> public string LotBlockSub { get; set; } /// <summary> /// Gets or sets the owner keywords. /// </summary> [Display(Name="Owner")] public string OwnerKeywords { get; set; } In my controller action I was thinking of something like this. but I would think all this logic doesn't belong in my Controller. ActionResult GetSearchResults(SearchViewModel model){ var query = service.GetAllParcels(); if(model.Census != null){ query = query.Where(x=>x.Census == model.Census); } if (model.OwnerKeywords != null){ query = query.Where(x=>x.Owners == model.OwnerKeywords); } return View(query.ToList()); }

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  • Where is the best place to call the .tolist(); inside my controller classes or inside my model repository classes

    - by john G
    I have the following action method, inside my asp.net mvc web application:- public JsonResult LoadZoneByDataCenter(string id) { var zonelist = repository.getrealtedzone(Convert.ToInt32(id)).ToList(); //code goes here Which calls the following model repository method:- public IQueryable<Zone> getrealtedzone(int? dcid) { return tms.Zones.Where(a=> a.DataCenterID == dcid || dcid == null); } Currently I am calling the .tolist() which will interpret the Database from my action method, but my question is where is the best place to call the .tolist() inside the controller or inside the model classes and why ? thanks

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  • Send copy of class to view class so it can render him? ( iPhone )

    - by Johannes Jensen
    I'm making a game for the iPhone, and I have a class called Robot. Then I have a class called View, which renders everything. I want to send a copy of my Robot, which I defined in my ViewController, and I send it to gameView (which is View *gameView), like this: robot = [Robot new]; [gameView setRobot: [robot copy]]; I tried to make a copy but that didn't work, I could also do it with a pointer to Robot (&robot) but sometimes it just crashes ? I tried this in my View.h @interface definition: @property (copy) Robot* robot; but I get the error /RobotsAdventure/Classes/View.h:24: error: setter '-robot' argument type does not match property type :/ Help? I'm pretty new at this, heh.

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  • What special configuration is needed to have a domain controller with DNS on a VM in Hyper-V?

    - by Michael J. Gray
    I have a server running Windows Server 2012 and it only has the Hyper-V role. I have a VM also running Windows Server 2012 and it has the Active Directory: Directory Services and DNS ([example.com]) roles. It has been promoted to a domain controller for [example.com]. In the virtualization host I have joined the domain successfully. On a laptop on the network, it can ping my DNS that is inside the VM on the virtualization host. However, it can't resolve anything through the DNS. I figured it was a firewall issue where the DNS had the firewall allow rule, but the virtualization host did not. I added that, but it didn't fix the issue. On my laptop, I get "UnKnown can't find [example.com]: No response from server" immediately. There's no time out, it just comes back right away. What have I overlooked?

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