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  • jQuery - Save to SQL via PHP

    - by Kenny Bones
    This is probably easy for you guys, but I can't understand it. I want to save the filename of an image to it's own row in the SQL base. Basically, I log on to the site where I have my own userID. And each user has its own column for background images. And the user can choose his own image if he wants to. So basically, when the user clicks on the image he wants, a jquery click event occurs and an ajax call is made to a php file which is supposed to take care of the actual update. The row for each user always exist so there's only an update of the data that's necessary. First, I collect the filename of the css property 'background-image' and split it so I get only the filename. I then store that filename in a variable I call 'filename' which is then passed on to this jQuery snippet: $.ajax({ url: 'save_to_db.php', data: filename, dataType:'Text', type: 'POST', success: function(data) { // Just for testing purposes. alert('Background changed to: ' + data); } }); And this is the php: <?php require("dbconnect.php") ?> <?php $uploadstring = ($_POST['filename']); mysql_query("UPDATE brukere SET brukerBakgrunn = $uploadstring WHERE brukerID=" .$_SESSION['id'] .""; mysql_close(); ?> Basically, each user has their own ID and this is called 'brukerID' The table everything is in is called 'brukere' and the column I'm supposed to update is the one called 'brukerBakgrunn' When I just run the javascript snippet, I get this message box in return where it says: Background changed to: Parse error: syntax error, unexpected ';' in /var/www/clients/client2/web8/web/save_to_db.php on line 8 I actualle get this messagebox twice, not sure why. Line 8 in 'save_to_db.php' is this one: mysql_query("UPDATE brukere SET brukerBakgrunn = $uploadstring WHERE brukerID=" .$_SESSION['id'] .""; Not sure if you need to see db_connect.php as well. I can add that later if you need to see it. So what am I missing here?

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  • MySQL: difference of two result sets

    - by Zombies
    How can I get the set difference of two result sets? Say I have a result set (just one column in each): result1: 'a' 'b' 'c' result2: 'b' 'c' I want to minus what is in result1 by result2: result1 - result2 such that it equals: difference of result1 - result2: 'a'

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  • MySQL Non Index Queries Analysis

    - by Markii
    I'm using the log queries not using index but it logs all that use indexes but just more advanced or using IFs. Is there a parser or a program out there that can analyze the log and give me a literal output of saying "table.column should be a index" Thanks

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  • QTreeView incorrectly displays the SpinBox if item is checkable and when using QWindowsStyle

    - by Sharraz
    Hello, I'm having a problem with a QTreeView in my program: The SpinBox used to edit the double value of a checkable item is displayed incorrectly when using the Windows style. Only the up and down buttons of the SpinBox can be seen, but not any value. The following example code is able to reproduce the problem: #include <QtGui> class Model : public QAbstractItemModel { public: Model() : checked(false), number(0) {} Qt::ItemFlags flags(const QModelIndex & index) const { return Qt::ItemIsEnabled | Qt::ItemIsEditable | Qt::ItemIsSelectable | Qt::ItemIsUserCheckable; } QVariant data(const QModelIndex &index, int role) const { switch (role) { case Qt::DisplayRole: case Qt::EditRole: return QVariant(number); case Qt::CheckStateRole: return QVariant(checked ? Qt::Checked : Qt::Unchecked); } return QVariant(); } QVariant headerData(int section, Qt::Orientation orientation, int role) const { return QVariant(); } int rowCount(const QModelIndex &parent) const { return parent.isValid() ? 0 : 1; } int columnCount(const QModelIndex &parent) const { return parent.isValid() ? 0 : 1; } bool setData(const QModelIndex &index, const QVariant &value, int role) { switch (role) { case Qt::EditRole: number = value.toDouble(); emit dataChanged(index, index); return true; case Qt::CheckStateRole: checked = value.toInt(); emit dataChanged(index, index); return true; } return false; } QModelIndex index(int row, int column, const QModelIndex &parent) const { if (!row && !column && !parent.isValid()) return createIndex(0, 0); return QModelIndex(); } QModelIndex parent(const QModelIndex &child) const { return QModelIndex(); } private: bool checked; double number; }; int main(int argc, char *argv[]) { QApplication app(argc, argv); QApplication::setStyle(new QWindowsStyle()); QTreeView tree; tree.setModel(new Model()); tree.show(); return app.exec(); } The problems seems to have something to do with the checkbox. If Qt::ItemIsUserCheckable is removed, the SpinBox will be displayed correctly. If the number is replaced by a longer one like 0.01, it can be seen partially. Any idea how this problem can be solved? Do I use the checkbox correctly? Greets, Sharraz

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  • Rails: three most recent records by unique belongs_to associated record

    - by Dennis Collective
    class User has_many :comments end class Comment belongs_to :user named_scope :recent, :order => 'comments.created_at DESC' named_scope :limit, lambda { |limit| {:limit => limit}} named_scope :by_unique_users end what would I put in the :by_unique_users so that I can do Comment.recent.by_unique_users.limit(3), and only get one comment per user on sqlite named_scope :by_unique_user, :group = "user_id" works, but makes it freak out on postgres, which is deployed on production PGError: ERROR: column "comments.id" must appear in the GROUP BY clause or be used in an aggregate function

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  • Hibernate many-to-one - bad usage?

    - by DaveA
    Just trying out Hibernate (with Annotations) and I'm having problems with my mappings. I have two entity classes, AudioCD and Artist. @Entity public class AudioCD implements CatalogItem { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int id; private String title; @ManyToOne(cascade = { CascadeType.ALL }, optional = false) private Artist artist; .... } @Entity @Table(uniqueConstraints = { @UniqueConstraint(columnNames = { "name" }) }) public class Artist { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int id; @Column(nullable = false) private String name; ..... } I get AudioCD objects from an external source. When I try to persist the AudioCD the Artist gets persisted as well, just like I want to happen. If I try persisting another different CD, but Artist already exists I get errors due to constraint violations. I want Hibernate to recognise that the Artist already exists and shouldn't be inserted again. Can this be done via annotations? Or do I have to manage the persistence of the AudioCD and Artist seperately?

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  • MySQL: Check if first character is _not_ A-Z

    - by dbemerlin
    I have to create an SQL Query to get all rows starting with a specific character, except if the parameter passed to the (PHP) function is 0, in that case it should get every row that does not start with A - Z (like #0-9.,$ etc). What is the easiest and fastest way to get those rows? DB: MySQL 5.1 Column: title

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  • inner join in sql

    - by vini
    SELECT TotalItems.Total_Items ,TotalItems.No_Items_Present ,ItemsTable.No_Of_Items_Ret FROM TotalItems INNER JOIN ItemsTable ON ItemsTable.Item_Name= '" + DropItemName.SelectedValue + "'" this is my SQL query what I want is to retrieve two column values corresponding to the item I enter in my dropdown list from one table and the no_of_items_ret from another table satisfying the condition of the dropdownlist I'm getting all the values corresponding to any item I enter what should i do?

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  • Cannot resolve collation conflict in Union select

    - by phenevo
    Hi, I've got tqo queries: First doesn't work: select hotels.TargetCode as TargetCode from hotels union all select DuplicatedObjects.duplicatetargetCode as TargetCode from DuplicatedObjects where DuplicatedObjects.objectType=4 because I get error: Cannot resolve collation conflict for column 1 in SELECT statement. Second works: select hotels.Code from hotels where hotels.targetcode is not null union all select DuplicatedObjects.duplicatetargetCode as Code from DuplicatedObjects where DuplicatedObjects.objectType=4 Structure: Hotels.Code -PK nvarchar(40) Hotels.TargetCode - nvarchar(100) DuplicatedObjects.duplicatetargetCode PK nvarchar(100)

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  • SQL WHERE.. IN clause multiple columns

    - by ala
    i need to implement the following query in SQL Server select * from table1 WHERE (CM_PLAN_ID,Individual_ID) IN ( Select CM_PLAN_ID, Individual_ID From CRM_VCM_CURRENT_LEAD_STATUS Where Lead_Key = :_Lead_Key ) but the WHERE..IN clause allows only 1 column. How to compare 2 or more columns with another inner select?

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  • Hibernate Annotation (Pyramid Structure - same table)

    - by fatnjazzy
    Hi, I have a person table that contains the following fields: id, name, parent_id. the parent_id is actually a FK for column id. the data should look like this (Like a pyramid): "id" "name" "parent_id" "1" "I am the Top Father" "1" "2" "My Father Is 1" "1" "3" "My Father Is 2" "2" "4" "My Father Is 2" "2" How is my bean suppose to look like? Thanks

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  • Bruteforcing Blackberry PersistentStore?

    - by Haoest
    Hello, I am experimenting with Blackberry's Persistent Store, but I have gotten nowhere so far, which is good, I guess. So I have written a a short program that attempts iterator through 0 to a specific upper bound to search for persisted objects. Blackberry seems to intentionally slow the loop. Check this out: String result = "result: \n"; int ub = 3000; Date start = Calendar.getInstance().getTime(); for(int i=0; i<ub; i++){ PersistentObject o = PersistentStore.getPersistentObject(i); if (o.getContents() != null){ result += (String) o.getContents() + "\n"; } } result += "end result\n"; result += "from 0 to " + ub + " took " + (Calendar.getInstance().getTime().getTime() - start.getTime()) / 1000 + " seconds"; From 0 to 3000 took 20 seconds. Is this enough to conclude that brute-forcing is not a practical method to breach the Blackberry? In general, how secure is BB Persistent Store?

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  • How many indexes will actually get used?

    - by Ender
    I'm writing a page that does very simple search queries, resulting in something like: SELECT * FROM my_table WHERE A in (a1, a2, a3) AND B in (b1, b2) AND C in (c1, c2, c3, c4) AND And so on for a variable number of columns, usually ~5. If I create a separate index for each column (one for A, one for B, one for C, not (A,B,C)), will all of them be used in the above query?

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  • Disable nested sorting in dojo enhancedGrid

    - by JJ
    I'm currently trying to disable the nested sorting, as it does not pass the parameters for the nested sort to the store url (only the first sorted column gets passed over). I tried to set "nestedSorting: false" in the grid setup (programmatically), but the sorting is still being showed in the grid headers. Isn't it possible to disable the nested sort?

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  • How do I define a foreign key that points to a class of a different name in ActiveRecord with Rails?

    - by Mark
    Hi there, I have a model Follow that defines a user_id and a followed_user_id. If you've used Twitter, this should make sense. I'm trying to make followed_user_id point to a User model, so I can access the user that is being followed through f.followed_user (in the same way that if I have an Entry with belongs_to :user and a user_id column I can use entry.user to get the user.) How can I do this? Thanks!

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  • how to bind association in RoR

    - by ashok
    I have two tables, AppTemplate and AppTemplateMeta AppTemplate table has column id, MetaID, name etc. I have associated these two model like this class AppTemplate < ActiveRecord::Base set_table_name 'AppTemplate' belongs_to :app_template_meta, :class_name => "AppTemplateMeta", :foreign_key => 'MetaID' end If we fetch data using AppTemplate.all, I want associated meta details also. But currently it's not returning associated meta details. It just returns AppTemplate details. any guys can help me for this

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