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  • mysqli real_escape_string problem

    - by tridat
    When im inserting to the database on my dev server the text goes in fine, for example "that's" is "that's" in the db. when uploading the exact same code to production server (hosted on a reseller account at bluehost) "that's" becomes "that\'s", im not double escaping, its exactly the same code, what could be the issue here?

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  • (JBoss) Problem with .war project on production, while test works

    - by ikky
    Hello. I have a java project (using Spring mvc) which i have built and deployed on my local computer. It runs on a JBoss application server, and works fine on the local machine. The next step i do, is to copy the deployed project.war from the local machine to the server which has the same development environment as the local machine. I stop the JBoss server, delete the cache, and run the JBoss server again. When i now try to run one of the pages(xx.xxx.xxx:8080/webservice/test.htm), i get this exception: exception org.springframework.web.util.NestedServletException: Request processing failed; nested exception is java.lang.NullPointerException org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:583) root cause java.lang.NullPointerException com.project.db.DBCustomer.isCredentialsCorrect(DBCustomer.java:44) com.project.CreateHController.handleRequest(CreateHController.java:60) org.springframework.web.servlet.mvc.SimpleControllerHandlerAdapter.handle(SimpleControllerHandlerAdapter.java:48) org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:875) org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:807) org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:571) org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:501) javax.servlet.http.HttpServlet.service(HttpServlet.java:697) javax.servlet.http.HttpServlet.service(HttpServlet.java:810) org.jboss.web.tomcat.filters.ReplyHeaderFilter.doFilter(ReplyHeaderFilter.java:75) It seems like none of my classes are reachable. Does anyone have any idea of what is wrong? btw: as i said, the project works fine on the local machine.

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  • java double buffering problem

    - by russell
    Whats wrong with my applet code which does not render double buffering correctly.I am trying and trying.But failed to get a solution.Plz Plz someone tell me whats wrong with my code. import java.applet.* ; import java.awt.* ; import java.awt.event.* ; public class Ball extends Applet implements Runnable { // Initialisierung der Variablen int x_pos = 10; // x - Position des Balles int y_pos = 100; // y - Position des Balles int radius = 20; // Radius des Balles Image buffer=null; //Graphics graphic=null; int w,h; public void init() { Dimension d=getSize(); w=d.width; h=d.height; buffer=createImage(w,h); //graphic=buffer.getGraphics(); setBackground (Color.black); } public void start () { // Schaffen eines neuen Threads, in dem das Spiel l?uft Thread th = new Thread (this); // Starten des Threads th.start (); } public void stop() { } public void destroy() { } public void run () { // Erniedrigen der ThreadPriority um zeichnen zu erleichtern Thread.currentThread().setPriority(Thread.MIN_PRIORITY); // Solange true ist l?uft der Thread weiter while (true) { // Ver?ndern der x- Koordinate repaint(); x_pos++; y_pos++; //x2--; //y2--; // Neuzeichnen des Applets if(x_pos>410) x_pos=20; if(y_pos>410) y_pos=20; try { Thread.sleep (30); } catch (InterruptedException ex) { // do nothing } Thread.currentThread().setPriority(Thread.MAX_PRIORITY); } } public void paint (Graphics g) { Graphics screen=null; screen=g; g=buffer.getGraphics(); g.setColor(Color.red); g.fillOval(x_pos - radius, y_pos - radius, 2 * radius, 2 * radius); g.setColor(Color.green); screen.drawImage(buffer,0,0,this); } public void update(Graphics g) { paint(g); } } what change should i make.When offscreen image is drawn the previous image also remain in screen.How to erase the previous image from the screen??

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  • Zend redirect problem

    - by John
    I'm trying to redirect to http://localhost/site/public/admin/login from http://localhost/site/public but for some reason, it keeps redirecting to http://localhost/admin/login The code I am using is: $this->_response->setRedirect('/admin/login')->sendResponse(); This is really frustrating me, and any help would be grealy appreciated

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  • sql inner join problem

    - by Luke
    The following SQL query isn't working. I think the error is on the first line. SELECT SUBSTRING(tbl_news.comment, 1, 250) as tbl_news.comment, tbl_news.id, tbl_news.date, tbl_news.subject, tbl_users.username FROM tbl_news INNER JOIN tbl_users ON tbl_news.creator = tbl_users.id ORDER BY date DESC

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  • js regexp problem

    - by Alexander
    I have a searching system that splits the keyword into chunks and searches for it in a string like this: var regexp_school = new RegExp("(?=.*" + split_keywords[0] + ")(?=.*" + split_keywords[1] + ")(?=.*" + split_keywords[2] + ").*", "i"); I would like to modify this so that so that I would only search for it in the beginning of the words. For example if the string is: "Bbe be eb ebb beb" And the keyword is: "be eb" Then I want only these to hit "be ebb eb" In other words I want to combine the above regexp with this one: var regexp_school = new RegExp("^" + split_keywords[0], "i"); But I'm not sure how the syntax would look like. I'm also using the split fuction to split the keywords, but I dont want to set a length since I dont know how many words there are in the keyword string. split_keywords = school_keyword.split(" ", 3); If I leave the 3 out, will it have dynamic lenght or just lenght of 1? I tried doing a alert(split_keywords.lenght); But didnt get a desired response

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  • Apache url rewrite problem

    - by Ankit
    requests ----- should be written to new url /institute/dps ----- /institute.php?slug=dps /institute/abc ----- /institute.php?slug=abc /institute/123 ----- /institute.php?slug=123 I am using following rule in .htaccess RewriteRule ^institute/(.*)$ /institute.php?slug=$1 However, it's not working. the page insitute.php get's execution, but the query string always comes empty. Any suggestions?

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  • Having a problem inserting a foreign key data into a table using a PHP form

    - by Gideon
    I am newbee with PHP and MySQL and need help... I have two tables (Staff and Position) in the database. The Staff table (StaffId, Name, PositionID (fk)). The Position table is populated with different positions (Manager, Supervisor, and so on). The two tables are linked with a PositionID foreign key in the Staff table. I have a staff registration form with textfields asking for the relevant attributes and a dynamically populated drop down list to choose the position. I need to insert the user's entry into the staff table along with the selected position. However, when inserting the data, I get the following error (Cannot add or update a child row: a foreign key constraint fails). How do I insert the position selected by the user into the staff table? Here is some of my code... ... echo "<tr>"; echo "<td>"; echo "*Position:"; echo "</td>"; echo "<td>"; //dynamically populate the staff position drop down list from the position table $position="SELECT PositionId, PositionName FROM Position ORDER BY PositionId"; $exeposition = mysql_query ($position) or die (mysql_error()); echo "<select name=position value=''>Select Position</option>"; while($positionarray=mysql_fetch_array($exeposition)) { echo "<option value=$positionarray[PositionId]>$positionarray[PositionName]</option>"; } echo "</select>"; echo "</td>"; echo "</tr>" //the form is processed with the code below $FirstName = $_POST['firstname']; $LastName = $_POST['lastname']; $Address = $_POST['address']; $City = $_POST['city']; $PostCode = $_POST['postcode']; $Country = $_POST['country']; $Email = $_POST['email']; $Password = $_POST['password']; $ConfirmPass = $_POST['confirmpass']; $Mobile = $_POST['mobile']; $NI = $_POST['nationalinsurance']; $PositionId = $_POST[$positionarray['PositionId']]; //format the dob for the database $dobpart = explode("/", $_POST['dob']); $formatdob = $dobpart[2]."-".$dobpart[1]."-".$dobpart[0]; $DOB = date("Y-m-d", strtotime($formatdob)); $newReg = "INSERT INTO Staff (FirstName, LastName, Address, City, PostCode, Country, Email, Password, Mobile, DOB, NI, PositionId) VALUES ('".$FirstName."', '".$LastName."', '".$Address."', '".$City."', '".$PostCode."', '".$Country."', '".$Email."', '".$Password."', ".$Mobile.", '".$DOB."', '".$NI."', '".$PostionId."')"; Your time and help is surely appreciated.

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  • MySQL error problem

    - by comma
    I keep getting the error listed below but it only says line 1 what does this mean and how do I fix it? Here is the error I keep getting? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 here is the code. if (isset($_POST['info_submitted'])) { $user_id = '5'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); $skill = $_POST['skill']; $experience = $_POST['experience']; $year = $_POST['year']; if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, year) VALUES ('" . $skill . "', '" . $experience . "', '" . $year . "')"); } if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND year='" . $year . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; if (!mysqli_query($mysqli, $query2)) { print mysqli_error($mysqli); return; } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE learned_skills JOIN users_skills ON (users_skills.skill_id = learned_skills.id) SET skill = '$skill', experience = '$experience', year = '$year'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } }

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  • PHP and MySQL validating problem

    - by IPADvsSLATE
    I'm trying to check if a color is already entered into the database if it is the color should not be entered and stored into the database and the following error code <p>This color has already been entered!</p> should be displayed. But for some reason I cant get this to work, can someone please help me? The color names are entered into $_POST['color'] which is an array entered by the user. Here is the html code that collects the colors. <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> Here is the PHP & MySQL code. for($i=0; $i < count($_POST['color']); $i++) { $color = "'" . $_POST['color'][$i] . "'"; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT * FROM colors WHERE color = '$color' AND user = '$user_id' "); if(mysqli_num_rows($dbc) == TRUE) { echo '<p>This color has already been entered!</p>'; } else if(mysqli_num_rows($dbc) == 0) { // enter the color into the database }

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  • Problem with CSS DIV align

    - by Sergio
    If the doctype declaration is <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 TRANSITIONAL//EN"> what is the best way for horizontal alignment of the DIV's like these: <div id="outer"><div id="inner">Some text</div></div> The CSS is: #outer{ border-top:1px dotted #999; background-color: #F4F4F4; width:100%;} #inner{ width:500px;border:1px solid #F00; margin:auto;} The thing that I want to do is the inner DIV align at center (horizontally) inside the outer DIV. This CSS working fine if the doctype declaration is <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

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  • Casting problem cant convert from void to float C++

    - by Makenshi
    as i said i get this horrible error i dont really know what to do anymore float n= xAxis[i].Normalize(); thats where i get the error and i get it cuz normalize is a void function this is it void CVector::normalize() { float len=Magnitude(); this->x /= len; this->y /= len; } i need normalize to stay as void tho i tried normal casting like this float n= (float)xAxis[i].Normalize(); and it doesnt work also with static,dynamic cast,reinterpret,const cast and cant make it work any help would be really apreciated... thank you .<

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  • Android relative layout problem with gravity

    - by DixieFlatline
    How can i put textview with id="naslov" to the center? I also tried with layout_gravity="center" but that doesn't work either. <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent"> <TextView android:id="@+id/naslov" android:layout_width="wrap_content" android:layout_height="wrap_content" android:textSize="20dip" android:text="Povzetek" android:gravity="center"/> <TextView android:id="@+id/aha" android:layout_width="wrap_content" android:layout_height="wrap_content" android:textSize="10dip" android:text="Vseh oddaj:" android:layout_below="@id/naslov"/> </RelativeLayout>

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  • HTML: Nesting DIVs problem

    - by mawg
    I am coding a form generator. So far, so good, then I decided to give it a real test. I made a form with some nested each holding a few controls. I will post the HTML at the end. If you load it into a browser, it renders, but is obviously wrong. I had previously tested using the W3C validator and things were fine, but that was for non nested. When I validate a form with nested I get errors: Error Line 13, Column 117: document type does not allow element "DIV" here …style="position: absolute; top:88px; left: 256px; width: 145px; height: 21px;"> So, how do I correct that? What do I do with nested FIELDSETs? Here's the complete HTML <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN""http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title></title> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> </head> <body> <form action="C:\temp\an_elogger_test.php" method="get"><div class="TGroupBox" id="GroupBox1"> <fieldset style="position: absolute; top:24px; left:24px; width: 449px; height: 473px;"> <legend>GroupBox1</legend> <div class="TPanel" id="Panel1"> <fieldset style="position: absolute; top:64px; left:64px; width: 361px; height: 217px;"> <div class="TComboBox" id="ComboBox1" style="position: absolute; top:88px; left: 256px; width: 145px; height: 21px;"> <select name="ComboBox1"> </select> </div> <div class="TGroupBox" id="GroupBox2"> <fieldset style="position: absolute; top:80px; left:88px; width: 145px; height: 177px;"> <legend>GroupBox2</legend> <div class="TCheckBox" id="CheckBox1" style="position: absolute; top:112px; left: 104px; width: 97px; height: 17px;">CheckBox1<input type="checkbox" name="CheckBox1" value="CheckBox1Checked"></div> <div class="TCheckBox" id="CheckBox2" style="position: absolute; top:152px; left: 112px; width: 97px; height: 17px;">CheckBox2<input type="checkbox" name="CheckBox2" value="CheckBox2Checked"checked="checked"></div> </fieldset> </div> <div class="TRadioGroup" id="RadioGroup2"> <fieldset style="position: absolute; top:128px; left: 264px; width: 145px; height: 137px;"><legend>RadioGroup2</legend> eins: <input type="radio" name="RadioGroup2" value="eins" checked><br> zwei: <input type="radio" name="RadioGroup2" value="zwei"><br> drei: <input type="radio" name="RadioGroup2" value="drei"><br> </fieldset> </div> </fieldset> </div> <div class="TMemo" id="Memo1"><textarea name="Memo1" rows="8" cols="13" style="position: absolute; top:320px; left: 88px; width: 185px; height: 89px;"> </textarea> </div> <div class="TComboBox" id="ComboBox2" style="position: absolute; top:328px; left: 296px; width: 145px; height: 21px;"> <select name="ComboBox2"> <option value="a">a</option> <option value="b">b</option> <option value="c">c</option> <option value="d" selected="selected">d</option> <option value="e">e</option> </select> </div> </fieldset> </div> <div class="TPanel" id="Panel2"> <fieldset style="position: absolute; top:32px; left:520px; width: 425px; height: 449px;"> <div class="TPanel" id="Panel3"> <fieldset style="position: absolute; top:64px; left:552px; width: 345px; height: 185px;"> <div class="TMemo" id="Memo2"><textarea name="Memo2" rows="8" cols="13" style="position: absolute; top:88px; left: 584px; width: 185px; height: 89px;"> You may wish to leave this memo emptyOr perpahaps give instructions aboout what should be written here</textarea> </div> <div class="TEdit" id="Edit1" style="position: absolute; top:200px; left: 600px; width: 121px; height: 21px;"><input type="text" name="Edit1"value="Insert text here"></div> </fieldset> </div> <div class="TGroupBox" id="GroupBox3"> <fieldset style="position: absolute; top:272px; left:552px; width: 345px; height: 185px;"> <legend>GroupBox3</legend> <div class="TPanel" id="Panel4"> <fieldset style="position: absolute; top:304px; left:584px; width: 177px; height: 137px;"> <div class="TRadioGroup" id="RadioGroup1"> <fieldset style="position: absolute; top:312px; left: 600px; width: 97px; height: 105px;"><legend>RadioGroup1</legend> one: <input type="radio" name="RadioGroup1" value="one"><br> two: <input type="radio" name="RadioGroup1" value="two" checked><br> three: <input type="radio" name="RadioGroup1" value="three"><br> </fieldset> </div> </fieldset> </div> <div class="TEdit" id="Edit2" style="position: absolute; top:320px; left: 776px; width: 105px; height: 21px;"><input type="text" name="Edit2"></div> </fieldset> </div> </fieldset> </div> <div align="center" style="margin: auto"><input type="submit" name="submitButton" value="Submit" style="position:absolute;top:522px;"></div> </form> </body> </html>

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  • Table-per-type inheritance insert problem

    - by gzak
    I followed this article on making a table-per-type inheritance model for my entities, but I get the following error when I try to add an instance of a subclass to the database. Here is how I create the subtype: var cust = db.Users.CreateObject<Customer>(); // Customer inherits User db.Users.AddObject(cust); db.SaveChanges(); I get the following error when I make that last call: "A value shared across entities or associations is generated in more than one location. Check that mapping does not split an EntityKey to multiple store-generated columns." With the following inner exception: "An item with the same key has already been added." Any ideas on what I could be missing?

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  • What is the problem with my LinkedList class?

    - by user258367
    class LinkedList { private: int data; LinkedList *ptr; public: LinkedList(int i_data) { data = i_data; ptr = 0; { ~LinkedList() { delete ptr ; } void insert(LinkedList *node) { while(this->next != 0) this = this->next; this->next = node; } } I will be creating a head node like head = new LinkedList(4) and then will be calling like head->insert(new LinkedList(5)) and subsequently . Can you please tell me does above class represent a linkedlist . i think yes it has node which contain address of next node . Please correct me if i am wrong

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  • ASP.NET (C#) jQuery JSON data problem

    - by oraclee
    My JSON Data {"menu": { "id": "file", "value": "File", "popup": { "menuitem": [ {"value": "New", "onclick": "CreateNewDoc()"}, {"value": "Open", "onclick": "OpenDoc()"}, {"value": "Close", "onclick": "CloseDoc()"} ] } }} jQuery code: $(document).ready(function() { $("#Button1").click(function() { var asd = "test"; $.get("CallBack.Aspx", { asd: asd }, function(data) { $.each(data, function() { }) }) }) }) I need menuitem in values how to make ? "menuitem": [ { "value": "New", "onclick": "CreateNewDoc()" } ]

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  • Problem using the find function in MATLAB

    - by Peter Etchells
    I have two arrays of data that I'm trying to amalgamate. One contains actual latencies from an experiment in the first column (e.g. 0.345, 0.455... never more than 3 decimal places), along with other data from that experiment. The other contains what is effectively a 'look up' list of latencies ranging from 0.001 to 0.500 in 0.001 increments, along with other pieces of data. Both data sets are X-by-Y doubles. What I'm trying to do is something like... for i = 1:length(actual_latency) row = find(predicted_data(:,1) == actual_latency(i)) full_set(i,1:4) = [actual_latency(i) other_info(i) predicted_info(row,2) ... predicted_info(row,3)]; end ...in order to find the relevant row in predicted_data where the look up latency corresponds to the actual latency. I then use this to created an amalgamated data set, full_set. I figured this would be really simple, but the find function keeps failing by throwing up an empty matrix when looking for an actual latency that I know is in predicted_data(:,1) (as I've double-checked during debugging). Moreover, if I replace find with a for loop to do the same job, I get a similar error. It doesn't appear to be systematic - using different participant data sets throws it up in different places. Furthermore, during debugging mode, if I use find to try and find a hard-coded value of actual_latency, it doesn't always work. Sometimes yes, sometimes no. I'm really scratching my head over this, so if anyone has any ideas about what might be going on, I'd be really grateful.

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  • Looping through Markers with Google Maps API v3 Problem

    - by Oscar Godson
    I'm not sure why this isn't working. I don't have any errors, but what happens is, no matter what marker I click on, it clicks the 3rd one (which is the last one out of 4 markers. Array starts at 0, obviously) and shows the number "3", which is correct for THAT one, but I'm not clicking that one. Here is most of my code, just not the array of [place-name, coordinates] (var locations, which you will see): function initialize() { var latlng = new google.maps.LatLng(45.522015,-122.683811); var settings = { zoom: 15, center: latlng, disableDefaultUI:true, mapTypeId: google.maps.MapTypeId.SATELLITE }; var map = new google.maps.Map(document.getElementById("map_canvas"), settings); var infowindow = new Array(); var marker = new Array(); for(x in locations){ console.log(x); infowindow[x] = new google.maps.InfoWindow({content: x}); marker[x] = new google.maps.Marker({title:locations[x][0],map:map,position:locations[x][1]}); google.maps.event.addListener(marker[x], 'click', function() {infowindow[x].open(map,marker[x]);}); } } initialize() The console.log output is (its correct, and what i expect): 0 1 2 3 So, any ideas?

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  • Problem with writing a file to excel with spreadsheet

    - by winter sun
    I am trying to write excel file by using ruby 1.9 spreadsheet version 0.6.4.1 on windows. Everything is going ok, until I get to the book.write statement when I write book.write "c:/spreadsheet/excel-file.xls I keep getting the following error No such file or directory - c:/spreadsheet/excel-file.xls Can anyone tell me what I should change in this path name?

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  • Regex Problem(C#)

    - by oraclee
    Hi all; Html Code: <TD style="DISPLAY: none">999999999</TD> <TD class=CLS1 >Name</TD> <TD class=BLACA>271229</TD> <TD>220</TD> <TD>343,23</TD> <TD>23,0</TD> <TD>222,00</TD> <TD>33222,8</TD> <TD class=blacl>0</TD> <TD class=black>0</TD> <TD>3433</TD> <TD>40</TD> i need td in value how to make csharp, i wanna string array; 999999999 Name 271229 220 pls help

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  • CSS and position little problem

    - by Azzyh
    hello so i have a content box and this menu box.. now the menu box moves when you have the browser in normal fullsize, and if you change size of the browser... here is picture: What do i do wrong? Here is my code: #menu { position: absolute; background: #FFF; text-decoration: none; border: 1px solid #000; color: #000; padding-left: 14px; padding-right: 14px; margin: 12px; } #content { margin: auto; width: 800px; border: 1px solid #000; padding: 10px; }

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  • javascript problem

    - by Gourav
    I have created a dynamic table whose rows gets appended by click of the "Add" button, i want the user not to be able to submit the page if no value is entered in all the rows of the table. how do i achieve this The code is <html> <head> <script type="text/javascript"> function addRowToTable() { var tbl = document.getElementById('tblSample'); var lastRow = tbl.rows.length; var iteration = lastRow+1; var row = tbl.insertRow(lastRow); var cellLeft = row.insertCell(0); var textNode = document.createTextNode(iteration); cellLeft.appendChild(textNode); var cellRight = row.insertCell(1); var el = document.createElement('input'); el.type = 'text'; el.name = 'txtRow' + iteration; el.id = 'txtRow' + iteration; el.size = 40; cellRight.appendChild(el); } function validation() { var a=document.getElementById('tblSample').rows.length; for(i=0;i<a;i++) { alert(document.getElementById('tblSample').txtRow[i].value);//this doesnt work } return true; } </script> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> </head> <body> <form name ='qqq' action="sample.html"> <p> <input type="button" value="Add" onclick="addRowToTable();" /> <input type="button" value="Submit" onclick="return validation();" /> </p> <p> <table border="1" id="tblSample"> <tr> <td>1</td> <td>The 1st row</td> </tr> </table> </p> </form> </body> </html> Please suggest

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  • Mysql many to many problem (leaderborad/scoreboard)

    - by zoko2902
    Hi all! I'm working on a small project in regards of the upcoming World Cup. I'm building a roster/leaderboard/scoredboard based on groups with national teams. The idea is to have information on all upcoming matches within the group or in the knockout phase (scores, time of the match, match stats etc.). Currently I'm stuck with the DB in that I can't come up with a query that would return paired teams in a row. I have these 3 tables: CREATE TABLE IF NOT EXISTS `wc_team` ( `id` INT NOT NULL AUTO_INCREMENT , `name` VARCHAR(45) NULL , `description` VARCHAR(250) NULL , `flag` VARCHAR(45) NULL , `image` VARCHAR(45) NULL , `added` TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP , PRIMARY KEY (`id`) , CREATE TABLE IF NOT EXISTS `wc_match` ( `id` INT NOT NULL AUTO_INCREMENT , `score` VARCHAR(6) NULL , `date` DATE NULL , `time` VARCHAR(45) NULL , `added` TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP , PRIMARY KEY (`id`) , CREATE TABLE IF NOT EXISTS `wc_team_has_match` ( `wc_team_id` INT NOT NULL , `wc_match_id` INT NOT NULL , PRIMARY KEY (`wc_team_id`, `wc_match_id`) , I've simplified the tables so we don't go in the wrong direction. Now I've tried al kinds of joins and groupings I could think of, but I never seem to get. Example guery: SELECT t.wc_team_id,t.wc_match_id,c.id.c.name,d.id,d.name FROM wc_team_has_match AS t LEFT JOIN wc_match AS s ON t.wc_match_id = s.id LEFT JOIN wc_team AS c ON t.wc_team_id = c.id LEFT JOIN wc_team AS d ON t.wc_team_id = d.id Which returns: wc_team_id wc_match_id id name id name 16 5 16 Brazil 16 Brazil 18 5 18 Argentina 18 Argentina But what I really want is: wc_team_id wc_match_id id name id name 16 5 16 Brazil 18 Argentina Keep in mind that a group has more matches I want to see all those matches not only one. Any pointer or suggestion would be extremly appreciated since I'm stuck like a duck on this one :).

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  • As3 printing problem, blanks swf after print or cancel

    - by Carlos Barbosa
    Hey all! ok back at another issues in as3 printing Code: //Function to print entire screen function printFunction(event:MouseEvent):void { var myPrintJob:PrintJob = new PrintJob(); var oldScaleX:Number = root.scaleX; var oldScaleY:Number = root.scaleY; //Start the print job myPrintJob.start(); //Figure out the new scale var newScaleX:Number = myPrintJob.paperWidth/root.width; var newScaleY:Number = myPrintJob.paperHeight/root.height; //Shrink in both the X and Y directions by the same amount (keep the same ratio) if(newScaleX < newScaleY) newScaleY = newScaleX; else newScaleX = newScaleY; root.scaleX = newScaleX; root.scaleY = newScaleY; //Print the page myPrintJob.addPage(Sprite(root)); myPrintJob.send(); //Reset the scale to the old values root.scaleX = oldScaleX; root.scaleY = oldScaleY; } I cant seem to find anything thats really helpful with this. When i click cancel on the print dialog box, i get error below and it blanks out my swf.

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