I want to write some code which takes any positive, even number (greater than 2) and gives me the smallest pair of primes that sum up to this number.
I need this program to handle any integer up to 9 digits long.
My aim is to make something that looks like this:
Please enter a positive even integer ( greater than 2 ) :
10
The first primes adding : 3+7=10.
Please enter a positive even integer ( greater than 2 ) :
160
The first primes adding : 3+157=160.
Please enter a positive even integer ( greater than 2 ) :
18456
The first primes adding : 5+18451=18456.
I don't want to use any library besides stdio.h. I don't want to use arrays, strings, or anything besides for the most basic toolbox: scanf, printf, for, while, do-while, if, else if, break, continue, and the basic operators (<,, ==, =+, !=, %, *, /, etc...).
Please no other functions especially is_prime.
I know how to limit the input to my needs so that it loops until given a valid entry.
So now I'm trying to figure out the algorithm.
I thought of starting a while loop like something like this:
#include <stdio.h>
long first, second, sum, goldbach, min;
long a,b,i,k; //indices
int main (){
while (1){
printf("Please enter a positive integer :\n");
scanf("%ld",&goldbach);
if ((goldbach>2)&&((goldbach%2)==0)) break;
else printf("Wrong input, ");
}
while (sum!=goldbach){
for (a=3;a<goldbach;a=(a+2))
for (i=2;(goldbach-a)%i;i++)
first = a;
for (b=5;b<goldbach;b=(b+2))
for (k=2;(goldbach-b)%k;k++)
sum = first + second;
}
}
