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• Mysql Syntax :You have an error in your SQL syntax....

  - by jasmine

  I have written very very very!!! simple function: function editCategory() { $ID = urlencode($_GET['id']); $cname = mysql_fix_string($_POST['cname']); $kabst = mysql_fix_string($_POST['kabst']); $kselect = $_POST['kselect']; $subsl = $_POST['subsl']; $kradio = $_POST['kradio']; $ksubmit = $_POST['ksubmit']; if (isset($ksubmit)) { $query = "UPDATE category SET name = '$cname', description = '$kabst', published = '$kselect', home = '$kradio', subcat = '$subsl' WHERE id = $ID "; $result = mysql_query($query); if (mysql_affected_rows () == 1) { echo "ok"; } else{ echo mysql_error(); } } } error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 what is wrong? :(

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• How to add a column via a query which counts the total rows with a specific criteria in a table with circular relationship in MS ACCESS 2007

  - by Xaqron

  I have a simple table "Employees" with this fields: ID, ParentID, Name ParentID is Nullable since an employee may have no Manager. This table has a one-to-many relationship with itself: ID --one--to--many--> ParentID Now I want a query which returns this columns: Name, Count of rows where their ParentID equals to the current row ID (the row is the manager of that rows) Sample Table: ID | ParentID | Name ====================== 1 | 0 | John ---------------------- 2 | 1 | Bob ---------------------- 3 | 1 | Alice ---------------------- 4 | 3 | Jack This way I can find an employee is the manager of how many other employees. The result should be something like this: Name | Count of Employees ========================== John | 2 -------------- Bob | 0 -------------- Alice | 1 -------------- Jack | 0 How can I achieve this in MS ACCESS 2007? * I have tried built-in query builder without any success.

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• dilemma about mysql. using condition to limit load on a dbf

  - by ondrobaco

  hi, I have a table of about 800 000 records. Its basically a log which I query often. I gave condition to query only queries that were entered last month in attempt to reduce the load on a database. My thinking is a) if the database goes only through the first month and then returns entries, its good. b) if the database goes through the whole database + checking the condition against every single record, it's actually worse than no condition. What is your opinion? How would you go about reducing load on a dbf?

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• Help need to with MySQL query to join data spanning multiple tables and use data as column names

  - by gurun8

  I need a little help putting together a SQL query that will give me the following resultsets: and The data model looks like this: The tricky part for me is that the columns to the right of the "Product" in the resultset aren't really columns in the database but rather key/value pairs spanned across the data model. Table data is as follows: My apologies in advance for the image heavy question and the image quality. This just seemed like the easiest way to convey the information. It'll probably take someone less time to write the query statement to achieve the results than it did for me to assemble this question. By the way, the "product_option" table image is truncated but it illustrated the general idea of the data structure. The MySQL server version is 5.1.45.

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• Help needed with MySQL query to join data spanning multiple tables with data used as column names

  - by gurun8

  I need a little help putting together a SQL query that will give me the following resultsets: and The data model looks like this: The tricky part for me is that the columns to the right of the "Product" in the resultset aren't really columns in the database but rather key/value pairs spanned across the data model. Table data is as follows: My apologies in advance for the image heavy question and the image quality. This just seemed like the easiest way to convey the information. It'll probably take someone less time to write the query statement to achieve the results than it did for me to assemble this question. By the way, the "product_option" table image is truncated but it illustrated the general idea of the data structure. The MySQL server version is 5.1.45.

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• Is there any way to simplify a verbose SQL INSERT INTO(..) query?

  - by Soundar Rajan

  I have a table with one id (autonumber) field and 50 other fields. The table is normalized, these are 50 material properties etc. I want to copy a record from this table into the same table - only the autoincrement id will be different. The query I am using now is INSERT INTO tableName (field1,field2,....field50) SELECT field1,field2,....field50 from tableName WHERE autoid=1234; Note that I have to type in ALL the 50 field names, twice! Is there any way to shorten this query so I don't have to type all of them? Thanks.

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• Mysql: i need to get the offset of a item in a query.

  - by user305270

  Mysql: i need to get the offset of a item in a query. I have a image gallery: this show 6 image per stack, so when i request image 22 it shows images from 18 to 24. It should first get the offset of the image 22, then get the images from 18 to 24. Another example: i request the image number 62(and offset 62), it will select images with offset from 60 to 66. Is possible with a single query? Thanks ;)

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• How can I build my SQL query from these tables?

  - by vee

  Hi All, I'm thinking of building query from these 2 tables (on SQL Server 2008). I have 2 tables as shown below: Table 1 MemberId . MemberName . Percentage . Amount1 00000001 AAA 1.0 100 00000002 BBB 1.2 800 00000003 ZZZ 1.0 700 Table 2 MemberId . MemberName . Percentage . Amount2 00000002 BBB 1.5 500 00000002 BBB 1.6 100 00000002 BBB 1.6 150 The result I want is MemberId . MemberName . Percentage . Amount . NettAmount 00000001 AAA 1.0 100 100 00000002 BBB 1.2 800 50 <-- 800-(500+100+150) 00000002 BBB 1.5 500 500 00000002 BBB 1.6 650 650 00000003 ZZZ 1.0 700 700 50 comes from 800 in Table1 minus sum of Amount2 in table2 for MemberID=00000002 Plz someone help me to build the query to reach this result. Thank you in advance.

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• Join DELETE in MySql? How to?

  - by Camran

  I have this: $query="DELETE FROM classified, $sql_table WHERE classified.ad_id = '$id' AND classified.classified_id = $sql_table.classified_id AND classified.poster_password='$pass'"; I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE classified.ad_id = 'Bmw_M3_E46_Full_29920' AND classified.cla' at line 1 Any help? As you can see the $sql_table is linked to the classifieds table with the fields classified_id I need to JOIN DELETE somehow. Basically classified table is the main table, then every category has its own tables with vehicle data. classified table has a field called classified_id which is the same as the Here is the full query echoed: DELETE FROM classified, vehicles WHERE classified.ad_id = 'Bmw_M3_E46_410811305' AND classified.classified_id = vehicles.classified_id AND classified.poster_password='some_password' Why isn't this working, Should it be so hard to delete from multiple tables? Thanks

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• does mysql stored procedures support data types like array, hash,etc?

  - by Yang

  i am creating a mysql function which takes in a varchar and change it to a int based on a mapping table. select name, convert_to_code(country) from users where sex = 'male' here, the convert_to_code() function takes in a country name (e.g. Japan, Finland..) and change it to country code which is an integer (e.g. 1001, 2310..) based on a mapping table called country_maping like below: country_name (varchar) | country_code (int) Japan | 1001 Finland | 2310 Canada | 8756 currently, the stored function need to select country_code from country_mapping where country_name = country_name and return the query result. is that possible to create a hash data struct in SP to optimize the process so that it will not need to perform the query for each row matches the where clause. thanks in advance!

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• When does a MySQL Query actually execute in PHP?

  - by MJB

  This sounds like a really simple question, but I am new to PHP. If I have a statement like this: $r =& $db->query("insert into table (col1, col2) values (10, 20)"); Do I have to still execute it, or does it get executed when I reference it? I have another case where I have a select query, which seems logically to run only when I call fetchrow, but the code I am presented with (to fix) does not call execute or fetch.I would have expected it to, so I cannot tell if it is just that I don't get it, or that the missing execute statement is the problem. It also does not insert the record, but it does not throw an error I can find. Also, I am a little confused by the =& notation. I looked it up on google, and found a few mentions of it, but I am still not clear on it. Thanks.

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• When using Query Syntax in C# "Enumeration yielded no results". How to retrieve output

  - by Shantanu Gupta

  I have created this query to fetch some result from database. Here is my table structure. What exaclty is happening. DtMapGuestDepartment as Table 1 DtDepartment as Table 2 Are being used var dept_list= from map in DtMapGuestDepartment.AsEnumerable() where map.Field<Nullable<long>>("GUEST_ID") == DRowGuestPI.Field<Nullable<long>>("PK_GUEST_ID") join dept in DtDepartment.AsEnumerable() on map.Field<Nullable<long>>("DEPARTMENT_ID") equals dept.Field<Nullable<long>>("DEPARTMENT_ID") select dept.Field<string>("DEPARTMENT_ID"); I am performing this query on DataTables and expect it to return me a datatable. Here I want to select distinct department from Table 1 as well which will be my next quest. Please answer to that also if possible.

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• MySQL, how can I SELECT WHERE one field value doesn't occurs in another?

  - by Jules

  I'm trying to do a search on my test server, speed isn't so important. I want to find if a phrase, the whole contents of one field, occurs in any part (as a whole) doesn't occur in another field. Heres my current query which finds if the phrase does occur SELECT pads.padid, pads.programname, keywords.word FROM Pads JOIN keywords ON Pads.Padid = keywords.Padid WHERE pads.Programname = keywords.word AND RemoveMeDate = '2001-01-01 00:00:00' My problem is that the field word contains other words too. I need to produce a count of where there isn't a keywords record with keywords.word equal to pads.programname ? EDIT: So if I have these records Pads: PadID=3 ProgramName=my prog PadID=4 ProgramName=Bad prog PadID=5 ProgramName=Good prog PadID=6 ProgramName=other prog Keywords: PadID=3 word=fox prog PadID=3 word=pig prog PadID=4 word=big prog PadID=4 word=nice prog PadID=5 word=fox prog PadID=6 word=bad prog PadID=6 word=fox prog The query I want would retun a count of 3 and record 6 has bad prog

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• MySQL SELECT results from 1 table, but exclude results depending on another table?

  - by Brandon

  Hey, What SQL query would I have to use if I want to get the results from a table 'messages' but exclude rows that have the value in 'messages_view' where field messages.message=messages_view.id AND messages.deleted=1 AND messages_view.user=$somephpvariable In more laymen terms, I have a messages table with each message denoted by an 'id' as well as a messages_view table connected with a 'message' field. I want to get the rows in message that are not deleted (comes from messages_view) for a specific 'user'. 'deleted'=1 when the message is deleted. Here is my current SQL Query that just gets the values out of : SELECT * FROM messages WHERE ((m_to=$user_id) OR (m_to=0 AND (m_to_state='' OR m_to_state='$state') AND (m_to_city='' OR m_to_city='$city'))) Here is the layout of my tables: table: messages ---------------------------- id (INT) (auto increment) m_from (INT) <-- Represents a user id (0 = site admin) m_to (INT) <-- Represents a user id (0 = all users) m_to_state (VARCHAR) m_to_city (VARCHAR) table: messages_view ---------------------------- message (INT) <-- Corresponds to messages.id above user (INT) <-- Represents a user id deleted (INT) <-- 1 = deleted

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• MySQL Query, how to group and count in one row ?

  - by Akarun

  Hi All, To simplify, I have tree tables: products, products-vs-orders, orders products fields : 'ProductID', 'Name', 'isGratis', ... products-vs-orders fields : 'ProductID', 'OrderID' orders fields : 'OrderID', 'Title', ... Actually, I have a query like this: SELECT orders.OrderID, orders.Title, COUNT(`products`.`isGratis`) AS "Quantity", `products`.`isGratis` FROM `orders`, `products-vs-orders`, `products` WHERE `orders`.`OrderID` = `products-vs-orders`.`OrderID` AND `products-vs-orders`.`ProductID` = `products`.`ProductID` GROUP BY `products`.`PackID`, `products`.`isGratis` This query works and return this surch of result: OrderID, Title, Quantity, isGratis 1 My Order 20 0 1 My Order 3 1 2 An other 8 0 2 An other 1 1 How can I retrieve the count of products 'gratis' and 'paid' in to separate cols ? OrderID, Title, Qt Paid, Qt Gratis 1 My Order 20 3 2 An other 8 1 Thanks for your help

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• how to debug a query that has valid syntax, executes, but returns no results?

  - by Ty W

  So I'm writing a fairly involved query with a half dozen joins, a dependent subquery for [greatest-n-per-group] purposes, grouping, etc. It is syntactically valid, but I've clearly made at least one mistake because it returns nothing. In the past I've debugged valid queries that return nothing by removing joins, executing subqueries on their own, removing WHERE conditions, and removing grouping to see what I would get but so far this one has me stumped. Are there better tools or techniques to use for this sort of thing? This particular query is for MySQL if it matters for any platform-specific tools.

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• Prevent duplicate rows with all non-unique columns (only with MySQL)?

  - by letseatfood

  Ho do I prevent a duplicate row from being created in a table with two columns, neither of which are unique? And can this be done using MySQL only, or does it require checks with my PHP script? Here is the CREATE query for the table in question (two other tables exist, users and roles): CREATE TABLE users_roles ( user_id INT(100) NOT NULL, role_id INT(100) NOT NULL, FOREIGN KEY (user_id) REFERENCES users(user_id), FOREIGN KEY (role_id) REFERENCES roles(role_id) ) ENGINE = INNODB; I would like the following query, if executed more than once, to throw an error: INSERT INTO users_roles (user_id, role_id) VALUES (1, 2); Please do not recommend bitmasks as an answer. Thanks!

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• How do I make my MySQL query with joins more concise?

  - by John Hoffman

  I have a huge MySQL query that depends on JOINs. SELECT m.id, l.name as location, CONCAT(u.firstName, " ", u.lastName) AS matchee, u.email AS mEmail, u.description AS description, m.time AS meetingTime FROM matches AS m LEFT JOIN locations AS l ON locationID=l.id LEFT JOIN users AS u ON (u.id=m.user1ID) WHERE m.user2ID=2 UNION SELECT m.id, l.name as location, CONCAT(u.firstName, " ", u.lastName) AS matchee, u.email AS mEmail, u.description AS description, m.time AS meetingTime FROM matches AS m LEFT JOIN locations AS l ON locationID=l.id LEFT JOIN users AS u ON (u.id=m.user2ID) WHERE m.user1ID=2 The first 3 lines of each sub-statement divided by UNION are identical. How can I abide by the DRY principle, not repeat those three lines, and make this query more concise?

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• Creating a mySQL query using PHP form dropdowns - If user ignores dropdown, do not filter by that pa

  - by user303043

  Hello, I am creating a simple MySQL query that will be built from the user selecting options from 2 dropdowns. The issue I am having is that I would like each drop down to default that if they do not actually choose an option, do not filter by that dropdown parameter. So, if they come in, and simply hit submit without choosing from a dropdown they should see everything. If they come in and pick from only one of the dropdowns, the query will basically ignore filtering by the other dropdown. I tried making <OPTION VALUE='any'>Choose but my query didn't know what to do with the 'any' and just shows no results. Here is my code. Thank you very much for whatever help you can provide. FORM <form method="POST" action="<?php echo $_SERVER['REQUEST_URI']; ?>"> <select name="GameType"> <OPTION VALUE='any'>Choose Game Type <option value="Game1">Option 1</option> <option value="Game2">Option 2</option> <option value="Game3">Option 3</option> </select> <select name="Instructor"> <OPTION VALUE='any'>Choose Instructor <option VALUE="InstructorA">Instructor A</option> <option value="InstructorB">Instructor B</option> <option value="InstructorC">Instructor C</option> </select> <input type='submit' value='Search Videos'> </form> MYSQL <?PHP connection stuff $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "SELECT * FROM Videos WHERE GameType=\"{$_POST['GameType']}\" AND Instructor=\"{$_POST['Instructor']}\""; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { echo $db_field['ShortDescription'] . ", "; echo $db_field['LongDescription'] . ", "; echo $db_field['GameType'] . ", "; echo $db_field['NumberOfPlayers'] . ", "; echo $db_field['Instructor'] . ", "; echo $db_field['Stakes'] . ", "; echo $db_field['UserPermissionLevel'] . ", "; echo $db_field['DateCreated'] . "<BR>"; } mysql_close($db_handle); } else { print "Database NOT Found "; mysql_close($db_handle); } ?>

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• Is there a single query that can update a "sequence number" across multiple groups?

  - by Drarok

  Given a table like below, is there a single-query way to update the table from this: | id | type_id | created_at | sequence | |----|---------|------------|----------| | 1 | 1 | 2010-04-26 | NULL | | 2 | 1 | 2010-04-27 | NULL | | 3 | 2 | 2010-04-28 | NULL | | 4 | 3 | 2010-04-28 | NULL | To this (note that created_at is used for ordering, and sequence is "grouped" by type_id): | id | type_id | created_at | sequence | |----|---------|------------|----------| | 1 | 1 | 2010-04-26 | 1 | | 2 | 1 | 2010-04-27 | 2 | | 3 | 2 | 2010-04-28 | 1 | | 4 | 3 | 2010-04-28 | 1 | I've seen some code before that used an @ variable like the following, that I thought might work: SET @seq = 0; UPDATE `log` SET `sequence` = @seq := @seq + 1 ORDER BY `created_at`; But that obviously doesn't reset the sequence to 1 for each type_id. If there's no single-query way to do this, what's the most efficient way? Data in this table may be deleted, so I'm planning to run a stored procedure after the user is done editing to re-sequence the table.

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• How to show related content using like in mysql?

  - by halocursed

  I currently have a table for products with it's own set of tags and a table for news with it's own set of tags. I wanted to add related news to the products page so I was thinking of using like but since the column tags in the products page is something like (Products) tags- manutd, man utd, football (news) tags - manutd, blah, bruha [this one is related] (news) tags - man, utd, bruha [this one is not related] I wanted to use a query to show all news containing any of the tags(from products) seperated by commas using mysql. How should I go about constructing such a query? If there is a better way of doing this a little explanation would be helpful too. Thanks

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• Attention all SQL gods! Query help needed.

  - by gurun8

  I need a little help putting together a SQL query that will give me the following resultsets: and The data model looks like this: The tricky part for me is that the columns to the right of the "Product" in the resultset are really columns in the database but rather key/value pairs spanned across the data model. Table data is as follows: My apologies in advance for the image heavy question and the image quality. This just seemed like the easiest way to convey the information. It'll probably take someone less time to write the query statement to achieve the results. By the way, the "product_option" table image is truncated but it illustrated the general idea of the data structure. The MySQL server version is 5.1.45.

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• Converting my lightweight MySQL DB wrapper into MySQLi. Pesky Problems

  - by Chaplin

  Here is the original code: http://pastebin.com/DNxtmApY. I'm not that interested in prepared statements at the moment, I just want this wrapper updating to MySQLi so once MySQL becomes depreciated I haven't got to update a billion websites. Here is my attempt at converting to MySQLi. <? $database_host = "127.0.0.1"; $database_user = "user"; $database_pass = "pass"; $database_name = "name"; $db = new database($database_host, $database_user, $database_pass, $database_name); class database { var $link, $result; function database($host, $user, $pass, $db) { $this->link = mysqli_connect($host, $user, $pass, $db) or $this->error(); mysqli_select_db($db, $this->link) or $this->error(); } function query($query) { $this->result = mysqli_query($query, $this->link) or $this->error(); $this->_query_count++; return $this->result; } function countRows($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_num_rows($result); } function fetch($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result); } function fetch_num($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result, mysqli_NUM); } function fetch_assoc($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result, mysqli_ASSOC); } function escape($str) { return mysqli_real_escape_string($str); } function error() { if ( $_GET["debug"] == 1 ){ die(mysqi_error()); } else { echo "Error in db code"; } } } function sanitize($data) { //apply stripslashes if magic_quotes_gpc is enabled if(get_magic_quotes_gpc()) $data = stripslashes($data); // a mysqli connection is required before using this function $data = trim(mysqli_real_escape_string($data)); return $data; } However it chucks all sorts of errors: Warning: mysql_query(): Access denied for user 'www-data'@'localhost' (using password: NO) in /home/count/Workspace/lib/classes/user.php on line 7 Warning: mysql_query(): A link to the server could not be established in /home/count/Workspace/lib/classes/user.php on line 7 Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/count/Workspace/lib/classes/user.php on line 8 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, object given in /home/count/Workspace/lib/classes/database.php on line 31

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• Mysql Connection Error from 1.1.1 to 1.2.1

  - by Chromag

  I upgraded from 1.1.1 to 1.2.1 and I seem to be getting the following exception when it attempts to connect to MySQL: The last packet sent successfully to the server was 0 milliseconds ago. The driver has not received any packets from the server. at com.mysql.jdbc.Util.handleNewInstance(Util.java:407) at com.mysql.jdbc.SQLError.createCommunicationsException(SQLError.java:1116) at com.mysql.jdbc.MysqlIO.<init>(MysqlIO.java:343) ... Caused by: java.net.ConnectException: Connection refused at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:333) at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:195) I've confirmed that MySQL is indeed running and seems to be working fine. The following is the line from my application.conf file (with user/pass/db replaced): db=mysql:username:password@databasename I also tried using the full JDBC configuration. Did I miss something? This worked just fine in 1.1.1. I'm running MySQL 5.1.41. Thanks.

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• Write a SQL Query to replace values and include all the Dates.

  - by VJ

  Well I have this - Table DimDate- Date Table Employee- Id,Name,Points,Date Now the Employee table has points for everyday unless they did not come...so the Date does not have all the Dates entries... I mean for e.g in a week he did not come for 2 days the Employee table has only 5 rows...so I have this dimdate table which has all the dates till 2050 which I want to join with and add Zeros for the dates he does not have points. So I have written this query but does not work - Select E.EmployeeId,D.Date,isNull(E.Points,0) from DimDate D left join Employee E on D.Date between '01-01-2009'and '06-01-2009' where E.EmployeeId=1 The above query give multiple dates and I tried group by on Date but does not work.

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