Search Results

Search found 33321 results on 1333 pages for 'php qt'.

Page 259/1333 | < Previous Page | 255 256 257 258 259 260 261 262 263 264 265 266  | Next Page >

• PHP/MySQL: Storing and retrieving UUIDS

  - by Greg

  I'm trying to add UUIDs to a couple of tables, but I'm not sure what the best way to store/retrieve these would be. I understand it's far more efficient to use BINARY(16) instead of VARCHAR(36). After doing a bit of research, I also found that you can convert a UUID string to binary with: UNHEX(REPLACE(UUID(),'-','')) Pardon my ignorance, but is there an easy way to this with PHP and then turn it back to a string, when needed, for readability? Also, would it make much difference if I used this as a primary key instead of auto_increment? EDIT: Found part of the answer: $bin = pack("h*", str_replace('-', '', $guid)); How would you unpack it?

  Read the article

• reading binary code of a file...in PHP

  - by Val

  How can I read the binary code(to get the 1s and 0s) of a file. $filename = "something.mp3"; $handle = fopen($filename, "rb"); $contents = fread($handle, filesize($filename)); fclose($handle); I tried this but it shows some strange characters... i presume that this is the formated binary...? I was hoping to get the 1's and 0's instead.... also i am not looking only .mp3 files it could be anything .e.g: .txt , .doc , .mp4, .php .jpg,.png etc.... Thanks

  Read the article

• php: sort and count instances of words in a given string

  - by superUntitled

  Hello, I need help sorting and counting instances of the words in a string. Lets say I have a collection on words: happy beautiful happy lines pear gin happy lines rock happy lines pear How could I use php to count each instance of every word in the string and output it in a loop: There are $count instances of $word So that the above loop would output: There are 4 instances of happy. There are 3 instances of lines. There are 2 instances of gin.... Thank you for your genius.

  Read the article

• Caching HTML output with PHP

  - by Mohamed Amine

  Hi! I would like to create a cache for my php pages on my site. I did find too many solutions but what I want is a script which can generate an HTML page from my database ex: I have a page for categories which grabs all the categories from the DB, so the script should be able to generate an HTML page of the sort: my-categories.html. then if I choose a category I should get a my-x-category.html page and so on and so forth for other categories and sub categories. I can see that some web sites have got URLs like: wwww.the-web-site.com/the-page-ex.html even though they are dynamic. thanks a lot for help

  Read the article

• Re-order mysql rows using PHP

  - by dave e

  | id | url | title | menu_id | ------+--------+--------+---------- | 1 | http://| link 1 | 1 | | 2 | http://| link 2 | 2 | | 3 | http://| link 3 | 3 | | 4 | http://| link 4 | 4 | Hi, I was wondering if its possible using PHP to reorder the above to something like below. I am trying to generate a menu which can easily be reordered by clicking an up or down arrow. I have no idea where to start. Any help would be much appreciated. | id | url | title | menu_id | ------+--------+--------+---------- | 1 | http://| link 1 | 2 | | 2 | http://| link 2 | 4 | | 3 | http://| link 3 | 3 | | 4 | http://| link 4 | 1 |

  Read the article

• Setting up path mapping in PHP and Eclipse

  - by jax

  I have just setup my website locally so I can test my pages more easily. Eclipse has been configured to use an XAMPP server locally. The problem is that I want to map my project to a certain place in my website. ie. In my Eclipse PHP project I have a folder called com I want this to map to /com in the webstie. I tried to do this in the mapping section of the Eclipse server setup but it didn't work. When I type http://localhost/com/ It should go to my project folder, however, when I type other folder it should use the normal website folders. how can I do this?

  Read the article

• Creating a PHP call home "time bomb" to protect my interests

  - by RC

  Hi everyone, I produced a PHP web app for a client some months back that is hosted on their own server. I have still not been paid for this work, and they are giving me the runaround. It turns out that I still have remote admin access to their server, so I can make code changes. What I was thinking of doing was to move the core kernel off-site onto one of my own servers, and program in some kind of callback or include that gets the kernel (critical functions) from my server. Give it two weeks or so for their backups to catch this change, and then pull the plug and exercise leverage. If I do this, they will pay immediately, because the site is a critical one for a very large and influential client of theirs. What is the most effective and easiest way of doing this? What code do I use? Thanks for any pointers.

  Read the article

• ready to use design pattern APIs for PHP?

  - by ajsie

  i know that in Java you can use their built-in APIs for design pattern. eg. if you want to use the observer pattern, you just have to extend your Subject class with the Observable class. is this possible for PHP? are there any libraries for the design patterns ready to use. in this way you don't have to reinvent the wheel and you also let many developers follow a standard. does Zend library have these API:s?

  Read the article

• POST data to permant json file using PHP

  - by doxsi

  using a url, my idea is the any user can post data. For example via http://myweb.com/index.php?name=Peter&surname=Brown Using the "jedwards" answer, present here , I am hable to create a json an d save it to a file. <? /* This needs to be at the top of your file, without ANYTHING above it */ session_start(); /* ... */ if(!array_key_exists('entries', $_SESSION)) { $_SESSION['entries'] = array(); } $_SESSION['entries'][] = array("name" => $_GET["name"], "surname" => $_GET["surname"]); $json_string = json_encode($_SESSION['entries']); My problem is taht his is not permant amongst different session or user. It work only on the same session. On different sessionthe json built start from the beginning. Any idea about that?

  Read the article

• recaptcha image and curl + php

  - by user253530

  $page = $curl->post($baseUrl.'/submit.php', array('url'=>$address,'phase'=>'1','randkey'=>$randKey[0],'id'=>'c_1')); $exp = explode('recaptcha_image',$page); The id recaptcha_image is not found although if i echo $page; the webpage will be displayed and surprisingly even the recpatcha div (with the image itself). Curl shouldn't load the image for recaptcha but somehow it does though when i try to find the div, it is not there. Is there a way to capture the url of the recaptcha image?

  Read the article

• RUNNING PHP IN NETBEANS

  - by user216112

  i have netbeans 6.8 with all bundle faetures. now i m running my php file Binary Search h1 {color: blue} Computer guess number by using binary search Input your hidden number: (1-99) Here; } else { if ($max_num==-1 && $min_num==-1) { $max_num = 100; $min_num = 0; $result_num = $hid_num; } else { if ($comparision == "bigger") { $min_num = $guess_num; } else if ($comparision == "smaller") { $max_num = $guess_num; } } $guess_num = ($max_num + $min_num)/2; setType($guess_num,"integer"); print "Computer guess $guess_num "; if ($guess_num == $result_num) { $flag_num = -1; } if ($flag_num == -1) { print Congratulation, Computer win " Here; } else { print Your intruction: Bigger Smaller Here; } } ? but the erreor coming in the "HTTP 404 NOT FOUND" I THINK SERVER HAS BEEN NOT BEEN SET.SO WHAT SHOULD I DO TO RUN IT

  Read the article

• PHP form validation submit problem

  - by TaG

  Every time I try to submit the form and I have not entered nothing in the year field I get Incorrect year! how can I still submit the form without having to enter a year. In other words leaving the year field blank and not getting a warning? Here is the PHP code. if(preg_match('/^\d{4,}$/', $_POST['year'])) { $year = mysqli_real_escape_string($mysqli, $_POST['year']); } else { $year = NULL; } if($year == NULL) { echo '<p class="error">Incorrect year!</p>'; } else { //do something }

  Read the article

• PHP Image content type problem

  - by Mirko

  Hi everybody, I have a specific problem, and cant get over it. For my latest project I need a simple PHP script that display an image according to its ID sent through URL. Here's the code: header("Content-type: image/jpeg"); $img = $_GET["img"]; echo file_get_contents("http://www.somesite.hr/images/$img"); The problem is that the image doesn't show although the browser recognizes it (i can see it in the page title), instead I get the image URL printed out. It doesn't work neither on a server with remote access allowed nor with one without. Also, nothing is printed or echoed before the header. I wonder if it is a content type error, or something else. Thanks in advance.

  Read the article

• how can i strip formatting from word document using php

  - by shazia

  I want to display a word file and then extract the content and display it in a separate textarea. i want to do away with the formatting as well. this is what i get when i get the read the text file using php ??????ÿÿÿÿ???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????Running Head: INTERNATIONAL BUSINESS International Business [Name of the writer] [Name of the institution] International Business Question 1 Increasing returns to scale (or economies of scale) in production is an indisputable phenomenon characterizing real world production, and, as such, they have long been recognized as a principal source of economic prosperity. Nonetheless, they have never played a major role in this is the code $fh = fopen($newname, 'r'); $contents => fread($fh, filesize($newname)); fclose($fh); unlink($newname); echo "<br/>"; echo $contents; how can i get rid of all these charecters. Thanks

  Read the article

• MD5 hash validation failing for unknown reason in PHP

  - by Sennheiser

  I'm writing a login form, and it converts the given password to an MD5 hash with md5($password), then matches it to an already-hashed record in my database. I know for sure that the database record is correct in this case. However, it doesn't log me in and claims the password is incorrect. Here's my code: $password = mysql_real_escape_string($_POST["password"]); ...more code... $passwordQuery = mysql_fetch_row(mysql_query(("SELECT password FROM users WHERE email = '$userEmail'"))); ...some code... elseif(md5($password) != $passwordQuery) { $_SESSION["noPass"] = "That password is incorrect."; } ...more code after... I tried pulling just the value of md5($password) and that matched up when I visually compared it. However, I can't get the comparison to work in PHP. Perhaps it is because the MySQL record is stored as text, and the MD5 is something else?

  Read the article

• PHP / javascript live chat using too much bandwidth

  - by David

  So I am learning about javascript, so I am making a live chat system with PHP and javascript. I have it so the javascript refreshes the log (each message gets logged in a file on the server), and it refreshes every second. Im using firebug to monitor the resource usage, and I see under the net tab each times its updated, and the bytes add up really fast. I know I can change it to update less, but is there a way that when a user on the other end I'm talking to, when the send a message, it gets sent to the server, then an alert gets sent to me saying that the chatlog needs to update somehow. That way it only updates when the log is updated. let me know, thanks

  Read the article

• php - track down premature headers leak

  - by user151841

  I'm using set_cookie() on a site. After adding some functionality, I'm getting Warning: Cannot modify header information - headers already sent by... error. The line number it references as to where the headers initiated from is the very line where set_cookie() is! And I checked, it's not being called twice. How can I track down these premature headers? I looked at the source code and didn't see any stray characters or anything before the error message starts ( I'm using xdebug, so the first thing is a , which I thought was me, but is actually the beginning of the xdebug message ). I've grepped my code for extra echo and so forth -- nothing. Can PHP tell me when and where the headers are starting? Or are they really starting on the set_cookie line, and if so, how have I gotten myself into this situation, and how do I get out?

  Read the article

• Real time web site using PHP or ASP.NET

  - by Roman

  Hey Guys, I'm looking for a way to put real time features into my web site. The idea is asynchronous communication between 2 people - like a chat session. If I use the chat example - I'd like the second person to know that the first one has sent a message to him, without refreshing or doing something active on the web page. Polling is not a good idea here - so is there any other solution? the back-end could be ASP.NET or PHP (ASP.NET preferred). Help would be much appreciated, Thanks, Roman

  Read the article

• PHP exec not working with gcc

  - by teehoo

  I just spent a few hours pulling my hair out over this. I'm trying to get gcc to compile a file from within PHP. $command = "/usr/bin/gcc /var/www/progpad/temp/tNu7rq.c -o /var/www/progpad/temp/tNu7rq.out"; exec($command, $output, $returnVal); echo $returnVal."<br />"; //returns 1 echo json_encode($output); //returns [] I'm running this on my own ubuntu server and both /var/www/progpad/ /var/www/progpad/temp/ have chmod 777 set. If I copy and paste the command string, and paste it into the terminal it works perfectly. Also if I replace the command string with something like $command = "echo test > test.txt"; Then this has no problem creating the text file. What could I possibly be doing wrong here???

  Read the article

• Preg_match class name from PHP file

  - by talentedmrjones

  I have a script that recursively scans a directory pulling out class names from php files, and storing those classes names in an array. This is working nicely even through the rather large Zend Framework library folders. The issue is that classes that extend other classes are not being included in the array. Here is my current preg_match: if (preg_match("/class\s*(\w*)\s*\{/i",strip_comments(file_get_contents($file)),$matches)) $classes[] = $matches[1]; I know that the last \s* is not right; there should be something there that can catch "{" or " extends Some_Other_Class {" .

  Read the article

• Connecting a PHP front-end to a back-end java service

  - by christopher-mccann

  I am currently using various back-end services and I want to use PHP to simply query these services and perform the final page construction. These services could be coded in any number of programming langauges such as Erlang, Java, Python etc. However I am unsure of the best way to actually interface the back-end services with the web app. Requests to these services would be both synchronous and asynchronous. Would I use something like SOAP or JSON-RPC?? Any help greatly appreciated.

  Read the article

• PHP Array Efficiency and Memory Clarification

  - by CogitoErgoSum

  When declaring an Array in PHP, the index's may be created out of order...I.e Array[1] = 1 Array[19] = 2 Array[4] = 3 My question. In creating an array like this, is the length 19 with nulls in between? If I attempted to get Array[3] would it come as undefined or throw an error? Also, how does this affect memory. Would the memory of 3 index's be taken up or 19? Also currently a developer wrote a script with 3 arrays FailedUpdates[] FailedDeletes[] FailedInserts[] Is it more efficient to do it this way, or do it in the case of an associative array controlling several sub arrays "Failures" array(){ ["Updates"] => array(){ [0] => 12 [1] => 41 } ["Deletes"] => array(){ [0] => 122 [1] => 414 [1] => 43 } ["Inserts"] => array(){ [0] => 12 } }

  Read the article

• Simple image displaying php error

  - by Rani dubey

  In a query say i have a image path that have multiple images stored as path=http://localhost/images/xyz.When i run the code: <?php //Retrieves data from MySQL mysql_connect("localhost", "root", "") or die ("Could not save image name Error: " . mysql_error()); mysql_select_db("dawat") or die("Could not select database"); $data = mysql_query("SELECT 'images_path' FROM images_tbl") or die(mysql_error()); //Puts it into an array $file_path = 'http://localhost/images/xyz'; while($row = mysql_fetch_assoc( $data )) {//Outputs the image and other data $src=$file_path.$row["images_path"]; echo "<img src=".$src."> <br>"; } ?> Everything is working fine,but only images are not showing.On place of images it is showing small thumnails.Please suggest what to do.... Sql query i used is: CREATE TABLE images_tbl( images_id INT NOT NULL AUTO_INCREMENT, images_path VARCHAR(200) NOT NULL, submission_date DATE, PRIMARY KEY (images_id) );

  Read the article

• Fastest PHP Routine To Match Words

  - by Volomike

  What is the fastest way in PHP to take a keyword list and match it to a search result (like an array of titles) for all words? For instance, if my keyword phrase is "great leather shoes", then the following titles would be a match... Get Some Really Great Leather Shoes Leather Shoes Are Great Great Day! Those Are Some Cool Leather Shoes! Shoes, Made of Leather, Can Be Great ...while these would not be a match: Leather Shoes on Sale Today! You'll Love These Leather Shoes Greatly Great Shoes Don't Come Cheap I imagine there's some trick with array functions or a RegEx (Regular Expression) to achieve this rapidly.

  Read the article

• Jquery Ajax not receiving php response correctly

  - by Theo

  I'm sending a JSON response from php to jquery: foreach ( $obj as $o ) { $a[ $o->key] = utf8_encode($o->id); } die(json_encode($a)); my html/jquery code is: $.ajax({ type:'POST', url: "imoveis/carrega_bairros", data: ({cidade:10}), dataType:"json", success: function(ret) { alert(ret) if(ret.success) { // ... } else alert("error"); } }); The json response is perfect (i get it on the console), but jquery is receiving a NULL ret object and it alerts "error". What's the problem???

  Read the article

< Previous Page | 255 256 257 258 259 260 261 262 263 264 265 266  | Next Page >