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• Read XML with PHP

  - by sea_1987

  I am trying to check a field in some XML that is returned from an outside. The XML is returned in a variable call $out and when you view the source of the page you get a XML output of the following, <?xml version="1.0" encoding="UTF-8"?> <ResponseBlock Live="FALSE" Version="3.51"> <Response Type="AUTH"> <OperationResponse> <TransactionReference>23-9-1334895</TransactionReference> <TransactionCompletedTimestamp>2010-04-30 15:59:05</TransactionCompletedTimestamp> <AuthCode>AUTH CODE:TEST</AuthCode> <TransactionVerifier>AlaUOS1MOnN/iwc5s2WPDm5ggrCLwesUnHs9h+W0N3CRaln2W6lh+6dtaRFFhLdwfnw6y7lRemyJUYl9a3dpWfzORE6DaZkFMb+dIb0Ne1UxjFEJkrEtjzx/i8KSayrIBrT/yGZOoOT42EZ9loc+UkdGk/pqYvj8bZztvgBNo2Ak=</TransactionVerifier> <Result>1</Result> <SettleStatus>0</SettleStatus> <SecurityResponseSecurityCode>1</SecurityResponseSecurityCode> <SecurityResponsePostCode>1</SecurityResponsePostCode> <SecurityResponseAddress>1</SecurityResponseAddress> </OperationResponse> <Order> <OrderInformation>This is a test order</OrderInformation> <OrderReference>Order0001</OrderReference> </Order> </Response> </ResponseBlock> I want check what value is in the 'Result' field. I am unsure how to access the information using PHP, so far I have, $xml = simplexml_load_string($out); Many Thanks

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• Removing related elements using XSLT 1.0

  - by pmdarrow

  I'm attempting to remove Component elements from the XML below that have File children with the extension "config." I've managed to do this part, but I also need to remove the matching ComponentRef elements that have the same "Id" values as these Components. <Fragment> <DirectoryRef Id="MyWebsite"> <Component Id="Comp1"> <File Source="Web.config" /> </Component> <Component Id="Comp2"> <File Source="Default.aspx" /> </Component> </DirectoryRef> </Fragment> <Fragment> <ComponentGroup Id="MyWebsite"> <ComponentRef Id="Comp1" /> <ComponentRef Id="Comp2" /> </ComponentGroup> </Fragment> Based on other SO answers, I've come up with the following XSLT to remove these Component elements: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" /> <xsl:template match="Component[File[substring(@Source, string-length(@Source)- string-length('config') + 1) = 'config']]" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Unfortunately, this doesn't remove the matching ComponentRef elements (i.e. those that have the same "Id" values). The XSLT will remove the component with the Id "Comp1" but not the ComponentRef with Id "Comp1". How do I achieve this using XSLT 1.0?

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• Create x509 certificate with openssl/makecert tool

  - by Zé Carlos

  I'm creating a x509 certificate using makecert with the following parameters: makecert -r -pe -n "CN=Client" -ss MyApp I want to use this certificate to encrypt and decrypt data with RSA algoritm. I look to generated certificate in windows certificate store and everything seems ok (It has a private key, public key is a RSA key with 1024 bits and so on..) Now i use this C# code to encrypt data: X509Store store = new X509Store("MyApp", StoreLocation.CurrentUser); store.Open(OpenFlags.ReadOnly); X509Certificate2Collection certs = store.Certificates.Find(X509FindType.FindBySubjectName, "Client", false); X509Certificate2 _x509 = certs[0]; using (RSACryptoServiceProvider rsa = (RSACryptoServiceProvider)_x509.PrivateKey) { byte[] dataToEncrypt = Encoding.UTF8.GetBytes("hello"); _encryptedData = rsa.Encrypt(dataToEncrypt, true); } When executing the Encrypt method, i receive a CryptographicException with message "Bad key". I think the code is fine. Probably i'm not creating the certificate properly. Any comments? Thanks ---------------- EDIT -------------- If anyone know how to create the certificate using OpenSsl, its also a valid answer for me.

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• No resource type specified (at 'id' with value '@+id\st')

  - by Refaat

  I'm new at android programming, I'm now trying to make some buttons, I configured these buttons using the following code: The MainActivity class : public class MainActivity extends Activity { /** Called when the activity is first created. */ Button st,nd,center; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); st = (Button)findViewById(R.id.st); st = (Button)findViewById(R.id.center); st = (Button)findViewById(R.id.nd); } } and the XML Layout: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@drawable/background" > <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Hello from animation!!" /> <button android:layout_width="100dp" android:layout_height="50dp" android:text="1st half" android:id="@+id\st" /> // and the other two points defined the same way </LinearLayout> And i got that syntax error: error: Error: No resource type specified (at 'id' with value '@+id\st'). // and the same error with the other two buttons HINT: The R class is imported and accessible from the MainActivity class but it can't read R.id.

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• Hibernate - Problem in parsing mapping file (.hbm.xml)

  - by Yatendra Goel

  I am new to Hibernate. I have an exception while running an Hibernate-based application. The exception is as follows: 16 [main] INFO org.hibernate.cfg.Environment - Hibernate 3.3.2.GA 16 [main] INFO org.hibernate.cfg.Environment - hibernate.properties not found 16 [main] INFO org.hibernate.cfg.Environment - Bytecode provider name : javassist 31 [main] INFO org.hibernate.cfg.Environment - using JDK 1.4 java.sql.Timestamp handling 94 [main] INFO org.hibernate.cfg.Configuration - configuring from resource: /hibernate.cfg.xml 94 [main] INFO org.hibernate.cfg.Configuration - Configuration resource: /hibernate.cfg.xml 219 [main] INFO org.hibernate.cfg.Configuration - Reading mappings from resource : app/data/City.hbm.xml 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(12) Attribute "coloumn" must be declared for element type "property". 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(13) Attribute "coloumn" must be declared for element type "property". 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(14) Attribute "coloumn" must be declared for element type "property". It seems that it is not finding coloumn attribute of the property element in the mappings file but my mappings file do have the coloumn attribute. Below is the mappings file (City.hbm.xml) <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="app.data"> <class name="City" table="CITY"> <id column="CITY_ID" name="cityId"> <generator class="native"/> </id> <property name="cityDisplyaName" coloumn="CITY_DISPLAY_NAME" /> <property coloumn="CITY_MEANINGFUL_NAME" name="cityMeaningFulName" /> <property coloumn="CITY_URL" name="cityURL" /> </class> </hibernate-mapping>

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• I need a true mouseOver...

  - by invertedSpear

  Ok, so mouseOver and RollOver, and their respective outs work great as long as your mouse is actually over the item, or one of it's children. My problem is that I may have another UI component "between" my mouse and the item I want to process the mouse/rollover(maybe a button that is on top of a canvas, but is not a child of the canvas). The mouse is still over the component, there's just something else that it's over at the same time. Any tips or help how to deal with this? Let me know if I'm not being clear enough. Here is a simplified code example detailing my question copy/paste that into your flex/flash builder and you'll see what I mean: <?xml version="1.0" encoding="utf-8"?> <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" width="500" height="226" creationComplete="ccInit()"> <mx:Script> <![CDATA[ private function ccInit():void{ myCanv.addEventListener(MouseEvent.ROLL_OVER,handleRollOver); } private function handleRollOver(evt:MouseEvent):void{ myCanv.setStyle("backgroundAlpha",1); myCanv.addEventListener(MouseEvent.ROLL_OUT,handleRollOut); } private function handleRollOut(evt:MouseEvent):void{ myCanv.setStyle("backgroundAlpha",0); myCanv.removeEventListener(MouseEvent.ROLL_OUT,handleRollOut); } ]]> </mx:Script> <mx:Canvas id="myCanv" x="10" y="10" width="480" height="200" borderStyle="solid" borderColor="#000000" backgroundColor="#FFFFFF" backgroundAlpha="0"> </mx:Canvas> <mx:Button x="90" y="50" label="Button" width="327" height="100"/> </mx:Application>

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• ZipArchive on the iPhone unzips files but they are empty

  - by user345131

  I'm trying to use ZipArchive on the iPhone to unzip a simple text file. It returns with no error but the file is empty. I would love to know why this doesn't work. I am using the following methods: -(void)alert:(NSString*)message { UIAlertView *myAlert = [[UIAlertView alloc] initWithTitle:@"" message:message delegate:self cancelButtonTitle:@"Ok" otherButtonTitles:nil, nil]; [myAlert show]; [myAlert release]; } -(void)unzip { NSString *sourcepath = [[NSBundle mainBundle] pathForResource:@"secret" ofType:@"zip"]; NSString*filename = @"secret.txt"; NSArray *docPaths =NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask, YES); NSString *destinationpath = [docPaths objectAtIndex: 0]; if (filename != nil ) destinationpath = [destinationpath stringByAppendingPathComponent: filename]; ZipArchive* za = [[ZipArchive alloc] init]; if( [za UnzipOpenFile:sourcepath Password:@""] ) { BOOL ret = [za UnzipFileTo:destinationpath overWrite:YES]; if( NO==ret ) [self alert:@"Problem"]; else [self alert:@"Success"]; [za UnzipCloseFile]; } [za release]; NSString *test = [[NSString alloc] initWithContentsOfFile:destinationpath encoding:NSASCIIStringEncoding error:nil]; [self alert:test]; }

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• java.lang.ExceptionInInitializerError Exception when creating Application Context in Spring

  - by cyotee

  I am practicing with Spring, and am getting a java.lang.ExceptionInInitializerError exception when I try to instantiate the context. The Exception appears below, with my code following it. I have simplified my experiment from before. The Exception Oct 17, 2012 5:54:22 PM org.springframework.context.support.AbstractApplicationContext prepareRefresh INFO: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@570c16b7: startup date [Wed Oct 17 17:54:22 CDT 2012]; root of context hierarchy Exception in thread "main" java.lang.ExceptionInInitializerError at org.springframework.context.support.AbstractRefreshableApplicationContext.createBeanFactory(AbstractRefreshableApplicationContext.java:195) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:128) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:535) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:449) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83) at helloworld.HelloWorldTest.main(HelloWorldTest.java:13) Caused by: java.lang.NullPointerException at org.springframework.beans.factory.support.DefaultListableBeanFactory.<clinit>(DefaultListableBeanFactory.java:105) ... 7 more My configuration XML <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:c="http://www.springframework.org/schema/c" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <bean id="messageContainer" class="helloworld.MessageContainer"> <property name="message" value="Hello World"> </property> </bean> <bean id="messageOutputService" class="helloworld.MessageOutputService"> </bean> My test class. package helloworld; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class HelloWorldTest { /** * @param args */ public static void main(String[] args) { ApplicationContext context = new ClassPathXmlApplicationContext("HelloWorldTest-context.xml"); MessageContainer message = context.getBean(MessageContainer.class); MessageOutputService service = context.getBean(MessageOutputService.class); service.outputMessageToConsole(message); } }

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• MXML composite container initialization error

  - by mkorpela

  I'm getting an odd error from my composite canvas component: An ActionScript error has occurred: Error: null at mx.core::Container/initialize()[C:\autobuild\galaga\frameworks\projects\framework\src\mx\core\Container.as:2560] at -REMOVED THIS FOR STACK OVERFLOW-.view::EditableCanvas/initialize()[.../view/EditableCanvas .... It seems to be related to the fact that my composite component has a child and I'm trying to add one in the place I'm using the component. So how can I do this correctly? Component code looks like this (EditableCanvas.mxml): <?xml version="1.0" encoding="utf-8"?> <mx:Canvas xmlns:mx="http://www.adobe.com/2006/mxml"> <mx:Script> <mx:Image id="editTextImage" source="@Embed('/../assets/icons/small/edit.png')"/> </mx:Canvas> The code that is using the code looks like this: <view:EditableCanvas width="290" height="120" backgroundColor="#FFFFFF" horizontalScrollPolicy="off" borderStyle="solid" cornerRadius="3"> <mx:Text id="textContentBox" width="270" fontFamily="nautics" fontSize="12" text="{_text}"/> </view:EditableCanvas>

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• cookies handling on webrequest and response

  - by manish patel

  I have created a application that has a function mainpost. It is created to post data on a https sites. Here I want to handle cookies in this function. How can I do this task? public string Mainpost(string website, string content) { // this is what we are sending string post_data = content; // this is where we will send it string uri = website; // create a request HttpWebRequest request = (HttpWebRequest) WebRequest.Create(uri); request.KeepAlive = false; request.ProtocolVersion = HttpVersion.Version10; request.Method = "POST"; // turn our request string into a byte stream byte[] postBytes = Encoding.ASCII.GetBytes(post_data); // this is important - make sure you specify type this way request.ContentType = "application/x-www-form-urlencoded"; request.ContentLength = postBytes.Length; Stream requestStream = request.GetRequestStream(); // now send it requestStream.Write(postBytes, 0, postBytes.Length); requestStream.Close(); // grab te response and print it out to the console along with the status // code HttpWebResponse response = (HttpWebResponse)request.GetResponse(); string str = (new StreamReader(response.GetResponseStream()).ReadToEnd()); Console.WriteLine(response.StatusCode); return str; }

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• How do I use XML Builder to create xml in rails?

  - by Angela

  I am trying the following, but the output XML is badly formed: def submit xml = Builder::XmlMarkup.new xml.instruct! xml.mail xml.documents xml.document xml.template xml.source "gallery" xml.name "Postcard: Image fill front" @xml_display = xml end I need it to look more like this: <?xml version="1.0" encoding="UTF-8"?> <mail> <documents> <document> <template> <source>gallery</source> <name>Postcard: Image fill front</name> </template> <sections> <section> <name>Text</name> <text>Hello, World!</text> </section> <section> <name>Image</name> <attachment>...attachment id...</attachment> </section> </sections> </document> </documents> <addressees> <addressee> <name>John Doe</name> <address>123 Main St</address> <city>Anytown</city> <state>AZ</state> <postal-code>10000</postal-code> </addressee> </addressees> </mail>

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• Uploading to S3 using Curl

  - by Carl Crawley

  Hi All, I'm currently using cURL to upload a file from my server to S3 using AJAX to call the script. So I have the following: $fullfilepath = '/server/sitepath/files/' . $_POST['file']; $upload_url = 'https://'.$_POST['buckets'].'.s3.amazonaws.com/'; $params = array( 'key'=>$_POST['key'], 'AWSAccessKeyId'=>$_POST['AWSAccessKeyId'], 'acl'=>$_POST['acl'], 'success_action_status'=>$_POST['success_action_status'], 'policy'=>$_POST['policy'], 'signature'=>$_POST['signature'], 'Content-Type'=>$_POST['Content-Type'], 'file'=>"@$fullfilepath" ); $ch = curl_init(); curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_URL, $upload_url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $params); $response = curl_exec($ch); curl_close($ch); echo $response; However, I'm getting an S3 error as follows when it posts and I'm unsure why because I'm not passing JSON to it. <?xml version="1.0" encoding="UTF-8"?> <Error><Code>InvalidPolicyDocument</Code><Message>Invalid Policy: Invalid JSON.</Message><RequestId>B29469C6151BE0E8</RequestId><HostId>BFPk6W2kt1b6hTtx0mEq6dWdN/IhO0gNR5bct//7LAOwJxm1C3PrxS4RPv1blzJ8</HostId></Error> I've googled it for the last hour or so and can't seem to figure it out. If I change the order of the Array fields, it gives me a different error - I believe the order of the posted fields is important somehow. any help would be much appreciated! C

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• WebService Stubs WSDL Axis2

  - by tt0686

  Good afternoon in my timezone. I have a wsdl file with the following snippet of code: <schema targetNamespace="http://util.cgd.pt" xmlns="http://www.w3.org/2001/XMLSchema"> <import namespace="http://schemas.xmlsoap.org/soap/encoding/" /> <complexType name="Attribute"> <sequence> <element name="fieldType" nillable="true" type="xsd:string" /> <element name="dataType" nillable="true" type="xsd:string" /> <element name="name" nillable="true" type="xsd:string" /> <element name="value" nillable="true" type="xsd:string" /> </sequence> </complexType> <complexType name="ArrayOffAttribute"> <complexContent> <restriction base="soapenc:Array"> <attribute ref="soapenc:arrayType" wsdl:arrayType="tns3:Attribute[]" /> </restriction> </complexContent> </complexType> When i use jax-rpc or Axis1 to generate the stubs the type Attribute is generated, but when i use Axis2 the type Attribute is not generated and a new type is created ArrayOffAttribute, this new type extends the axis2.databinding.types.soapencoding.Array and permits to add elements through the array.addObject(object), my question is, i am migrating one Java EE application from webservices using jax-rpc to start using Axis2, and the methods are using the Attribute type to fullfill attributes fields, now in Axis2 and do not have attribute type , what should i use in the ArrayOffAttribute.addObject(?) ? Could be something wrong with Axis2 ? i am stop here :( Thanks in advance Best regards

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• Malware - Technical anlaysis

  - by nullptr

  Note: Please do not mod down or close. Im not a stupid PC user asking to fix my pc problem. I am intrigued and am having a deep technical look at whats going on. I have come across a Windows XP machine that is sending unwanted p2p traffic. I have done a 'netstat -b' command and explorer.exe is sending out the traffic. When I kill this process the traffic stops and obviously Windows Explorer dies. Here is the header of the stream from the Wireshark dump (x.x.x.x) is the machines IP. GNUTELLA CONNECT/0.6 Listen-IP: x.x.x.x:8059 Remote-IP: 76.164.224.103 User-Agent: LimeWire/5.3.6 X-Requeries: false X-Ultrapeer: True X-Degree: 32 X-Query-Routing: 0.1 X-Ultrapeer-Query-Routing: 0.1 X-Max-TTL: 3 X-Dynamic-Querying: 0.1 X-Locale-Pref: en GGEP: 0.5 Bye-Packet: 0.1 GNUTELLA/0.6 200 OK Pong-Caching: 0.1 X-Ultrapeer-Needed: false Accept-Encoding: deflate X-Requeries: false X-Locale-Pref: en X-Guess: 0.1 X-Max-TTL: 3 Vendor-Message: 0.2 X-Ultrapeer-Query-Routing: 0.1 X-Query-Routing: 0.1 Listen-IP: 76.164.224.103:15649 X-Ext-Probes: 0.1 Remote-IP: x.x.x.x GGEP: 0.5 X-Dynamic-Querying: 0.1 X-Degree: 32 User-Agent: LimeWire/4.18.7 X-Ultrapeer: True X-Try-Ultrapeers: 121.54.32.36:3279,173.19.233.80:3714,65.182.97.15:5807,115.147.231.81:9751,72.134.30.181:15810,71.59.97.180:24295,74.76.84.250:25497,96.234.62.221:32344,69.44.246.38:42254,98.199.75.23:51230 GNUTELLA/0.6 200 OK So it seems that the malware has hooked into explorer.exe and hidden its self quite well as a Norton Scan doesn't pick anything up. I have looked in Windows firewall and it shouldn't be letting this traffic through. I have had a look into the messages explorer.exe is sending in Spy++ and the only related ones I can see are socket connections etc... My question is what can I do to look into this deeper? What does malware achieve by sending p2p traffic? I know to fix the problem the easiest way is to reinstall Windows but I want to get to the bottom of it first, just out of interest.

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• java.lang.ClassNotFoundException: org.springframework.ui.ModelMap

  - by aelshereay

  I create a simple webapp using tomcat 6, spring 2.5.6 and maven. The problem is when I boot up tomcat, I am getting the following errors: SEVERE: StandardWrapper.Throwable java.lang.NoClassDefFoundError: org/springframework/ui/ModelMap ... Caused by: java.lang.ClassNotFoundException: org.springframework.ui.ModelMap The ModelMap class does exist in spring-2.5.6.jar and spring-context-2.5.6.jar, I also have some other spring jars. All of them are being deployed to tomcat correctly, when I check the application WEB-INF (deployed to tomcat) I found all those jars there! I have only one @Controller that has a @RequestMapping("/home.htm") showForm(ModelMap model) method. My applicationContext is quite simple: <?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.directwebremoting.org/schema/spring-dwr http://www.directwebremoting.org/schema/spring-dwr-3.0.xsd" default-autowire="byName"> <context:component-scan base-package="org.myapp"/> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/view/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans>

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• XmlSerialize a custom collection with an Attribute

  - by roomaroo

  I've got a simple class that inherits from Collection and adds a couple of properties. I need to serialize this class to XML, but the XMLSerializer ignores my additional properties. I assume this is because of the special treatment that XMLSerializer gives ICollection and IEnumerable objects. What's the best way around this? Here's some sample code: using System.Collections.ObjectModel; using System.IO; using System.Xml.Serialization; namespace SerialiseCollection { class Program { static void Main(string[] args) { var c = new MyCollection(); c.Add("Hello"); c.Add("Goodbye"); var serializer = new XmlSerializer(typeof(MyCollection)); using (var writer = new StreamWriter("test.xml")) serializer.Serialize(writer, c); } } [XmlRoot("MyCollection")] public class MyCollection : Collection<string> { [XmlAttribute()] public string MyAttribute { get; set; } public MyCollection() { this.MyAttribute = "SerializeThis"; } } } This outputs the following XML (note MyAttribute is missing in the MyCollection element): <?xml version="1.0" encoding="utf-8"?> <MyCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> What I want is <MyCollection MyAttribute="SerializeThis" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> Any ideas? The simpler the better. Thanks.

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• innerHTML doesn't work correctly with xhtml in Chrome

  - by Desperadeus

  Hi! I've got a trouble with Chrome5.0.375.70, but FF 3.6.3 and Opera 10.53 are OK. Below is the line of code: document.getElementById('content').innerHTML = data.documentElement.innerHTML; The data object from the code is a document (typeof(data) == 'object') and I've got it by ajax request to chapter01.xhtml: <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE html [ <!ENTITY D "&#x2014;"> <!ENTITY o "&#x2018;"> <!ENTITY c "&#x2019;"> <!ENTITY O "&#x201C;"> <!ENTITY C "&#x201D;"> ]> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Alice's Adventures in Wonderland by Lewis Carroll. Chapter I: Down the Rabbit-Hole</title> <link rel="stylesheet" type="text/css" href="style.css"/> <link rel="stylesheet" type="application/vnd.adobe-page-template+xml" href="page-template.xpgt"/> </head> <body> <div class="title_box"> <h2 class="chapnum">Chapter I</h2> <h2 class="chaptitle">Down the Rabbit-Hole</h2> <hr/> </div> The Chrome cuts all before body and as a result link to css in header is missed; user can't see formatted text and images. How can I fix it or bypass?

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• hint and textview with right gravity and a singleline

  - by codeScriber

  I've opened a bug but i was wondering if anyone encountered this issue and knows a workaround. If you define a text view with a hint inside it, give it right gravity (android:gravity="right") then if you define android:singleLine=true or android:maxLines="1" or android:scrollHorizonatally="true" you don't see the hint. removing the right gravity returns the hint to the left side, removing all the tree params i mentioned above puts the hint on the right side. i want my hint on the right, but i need a single horizontal line... here's the sample layout that doesn't show the hint: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="wrap_content" android:padding="5dp"> <EditText android:layout_width="fill_parent" android:layout_gravity="center_vertical|right" android:layout_height="wrap_content" android:layout_margin="6dp" android:textSize="16sp" android:paddingRight="5dp" android:id="@+id/c" android:gravity="right" android:hint="hello!!!" android:scrollHorizontally="true" android:maxLines="1" android:singleLine="true"/> </LinearLayout> i checked on 1.6 and 2.1 emulators and it reproduces 100%, i'm prettysure it's a bug, i don't see the connection between single line and the hint.... what's more the hint got it's own layout in the TextView (mLayout and mHintLayout both exists, in onDraw if the text length is 0 mHintLayout if mHint is not null is used).

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• xmlEncoder not writing in netBeans

  - by Greg

  Hi, I am trying to use the xmlEncoder to write to xml file in net-beans but it doesnt work. Here is the call to the writing function: dbManipulator.writeStudents(deps); where deps = new Hashtable<String, Department>(); dbManipulator = new DataBaseManipulator(); Department is an class-object I made, and here is writeStudents method which is located in the DataBaseManipulator class: public void writeStudents(Hashtable<Integer, Student> students) { XMLEncoder encoder = null; try { encoder = new XMLEncoder(new FileOutputStream(".\\test\\Students.xml")); } catch(Exception e){} encoder.writeObject(students); encoder.close(); }//end of function writeStudents() Any ideas why it isnt working? I tried changing the hashtable to vector but still the xml file looks like that after the writing: <?xml version="1.0" encoding="UTF-8"?> <java version="1.6.0_18" class="java.beans.XMLDecoder"> <object class="java.util.Hashtable"/> </java> Thanks in advance, Greg

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• How to parse this xml document?

  - by dfjhdfjhdf

  Get such a XML document with the help of ajax (var data = request.responseXML;), how do I parse the contacts?: <?xml version="1.0" encoding="UTF-8"?> <Alladresses xmlns="http://somedomain.org/doc/2007-08-02/"> <Owner> <ID>gut74hfowesdfj49fjsifhryh8e8rta3uyhw4</ID> <Name>Mr.Bin</Name> </Owner> <Contacts> <Person> <Name>Greg</Name> <Phone>3254566756</Phone> </Person> <Person> <Name>Smith</Name> <Phone>342446446</Phone> </Person> <Person> <Name>Yuliya</Name> <Phone>675445566867</Phone> </Person> </Contacts> </Alladresses>

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• Reading text files line by line, with exact offset/position reporting

  - by Benjamin Podszun

  Hi. My simple requirement: Reading a huge ( a million) line test file (For this example assume it's a CSV of some sorts) and keeping a reference to the beginning of that line for faster lookup in the future (read a line, starting at X). I tried the naive and easy way first, using a StreamWriter and accessing the underlying BaseStream.Position. Unfortunately that doesn't work as I intended: Given a file containing the following Foo Bar Baz Bla Fasel and this very simple code using (var sr = new StreamReader(@"C:\Temp\LineTest.txt")) { string line; long pos = sr.BaseStream.Position; while ((line = sr.ReadLine()) != null) { Console.Write("{0:d3} ", pos); Console.WriteLine(line); pos = sr.BaseStream.Position; } } the output is: 000 Foo 025 Bar 025 Baz 025 Bla 025 Fasel I can imagine that the stream is trying to be helpful/efficient and probably reads in (big) chunks whenever new data is necessary. For me this is bad.. The question, finally: Any way to get the (byte, char) offset while reading a file line by line without using a basic Stream and messing with \r \n \r\n and string encoding etc. manually? Not a big deal, really, I just don't like to build things that might exist already..

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• Deploy GWT Application to Google App Engine using NetBeans

  - by Yan Cheng CHEOK

  Hello, I try to deploy a GWT application, to Google App Engine using NetBeans. I had successful run GWT sample http://code.google.com/webtoolkit/doc/latest/tutorial/create.html using Personal GlassFish v3 Prelude Domain, by 1) Copy generated source code from StockWatcher to C:\Projects\StockWatcherNetbeans\src\java\com\google\ 2) Modify C:\Projects\StockWatcherNetbeans\nbproject\gwt.properties gwt.module=com.google.gwt.stockwatcher.StockWatcher 3) Select Personal GlassFish v3 Prelude Domain, and run. All works fine! Now, I try to select Google App Engine server, and run. However, I get the error "There is no appengine web project opened!" I check... There is file called C:\Projects\StockWatcherNetbeans\war\WEB-INF\appengine-web.xml with content <?xml version="1.0" encoding="UTF-8"?> <appengine-web-app xmlns="http://appengine.google.com/ns/1.0" xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:schemaLocation='http://kenai.com/projects/nbappengine/downloads/download/schema/appengine-web.xsd appengine-web.xsd'> <application>StockWatcherNetbeans</application> <version>1</version> </appengine-web-app> I am using NetBeans 6.7.1 GWT4NB (GWT Plugin for NetBeans) 2.6.12 Google App Engine plugin for NetBeans from http://kenai.com/downloads/nbappengine/1.0_NetBeans671/updates.xml Anything I had missed out? Even when I right click to the project, the Deploy to Google App Engine options is disabled. And yes, please do not ask me why not use Eclipse.

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• accessing a value of a nested hash

  - by st

  Hello! I am new to perl and I have a problem that's very simple but I cannot find the answer when consulting my perl book. When printing the result of Dumper($request); I get the following result: $VAR1 = bless( { '_protocol' => 'HTTP/1.1', '_content' => '', '_uri' => bless( do{\(my $o = 'http://myawesomeserver.org:8081/counter/')}, 'URI::http' ), '_headers' => bless( { 'user-agent' => 'Mozilla/5.0 (X11; U; Linux i686; en; rv:1.9.0.4) Gecko/20080528 Epiphany/2.22 Firefox/3.0', 'connection' => 'keep-alive', 'cache-control' => 'max-age=0', 'keep-alive' => '300', 'accept' => 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8', 'accept-language' => 'en-us,en;q=0.5', 'accept-encoding' => 'gzip,deflate', 'host' => 'localhost:8081', 'accept-charset' => 'ISO-8859-1,utf-8;q=0.7,*;q=0.7' }, 'HTTP::Headers' ), '_method' => 'GET', '_handle' => bless( \*Symbol::GEN0, 'FileHandle' ) }, 'HTTP::Server::Simple::Dispatched::Request' ); How can I access the values of '_method' ('GET') or of 'host' ('localhost:8081'). I know that's an easy question, but perl is somewhat cryptic at the beginning. Thank you, St.

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• how to dispaly image in grid view reading imageUrl from xml using sax parser in android

  - by Pramod kuamr

  thanks for answer but i am able to read xml file from url but i need if in xml imageUrl is there so show in grid view ..this is my xml file and read URL <?xml version="1.0" encoding="UTF-8"?> <channels> <channel> <name>ndtv</name> <logo>http://a3.twimg.com/profile_images/670625317/aam-logo--twitter.png</logo> <description>this is a news Channel</description> <rssfeed>ndtv.com</rssfeed> </channel> <channel> <name>star news</name> <logo>http://a3.twimg.com/profile_images/740897825/AndroidCast-350_normal.png</logo> <description>this is a newsChannel</description> <rssfeed>starnews.com</rssfeed> </channel> </channels>

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• UTF8 charset, diacritical elements, conversion problems - and Zend Framework form escaping

  - by imanc

  Hey, I am writing a webapp in ZF and am having serious issues with UTF8. It's using multi lingual content through Zend Form and it seems that ZF heavily escapes all of these characters and basically just won't show a field if there's diacritical elements 'é' and if I use the HTML entity equivalent e.g. é it gets escaped so that the user will see 'é'. Zend Form allows for having non escaped data, but trying to use this is confusing, and it seems it'd need to be used all over the place. So, I have been told that if the page and the text is in UTF8, no conversion to htmlentities is required. Is this true? And if the last question is true, then how do I convert the source text to UTF8? I am comfortable setting up apache so that it sends a default UTF8 charset heading, and also adding the charset meta tag to the html, but doing this I am still getting messed up encoding. I have also tried opening the translation csv file in TextWrangler on OSX as UTF8, but it has done nothing. Thanks! L

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