Php 5 and mysql connecting gives error ...code and error in there check out and plz..plz help....
- by user309381
**mysql_query() [function.mysql-query]: Access denied for user 'SYSTEM'@'localhost' (using password: NO) in C:\wamp\www\photo_gallery\includes\database.php  on line 56
Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\wamp\www\photo_gallery\includes\database.php on line 56
The Query has problemAccess denied for user 'SYSTEM'@'localhost' (using password: NO)
i have set the password for root and grant privilege all for root.Why it soes show like 
SYSTEM@localhost i dont have SYSTEM .**
class MySQLDatabase
{
    public $connection;
    function _construct()
    {
        $this-open_connection();
    }
    public function open_connection()
    {   /*
        $DB_SERVER = "localhost";
        $DB_USER = "root";
        $DB_PASS = "";
        $DB_NAME = "photo_gallery";*/
        $this-connection = mysql_connect($DBSERVER,$DBUSER,$DBPASS);
        if(!$this-connection)
        {
            die("Database Connection Failed" . mysql_error());
        }
        else
        {
            $db_select = mysql_select_db($DBNAME,$this-connection);
            if(!$db_select)
            {
                die("Database Selection Failed" . mysql_error());
            }
        }
    }
    function mysql_prep($value)
    {
        if (get_magic_quotes_gpc())
        {
             $value = stripslashes($value);
        }
        // Quote if not a number
        if (!is_numeric($value))
        {
            $value = "'" . mysql_real_escape_string($value) . "'";
        }
        return $value;
}
public function close_connection()
{
    if(isset($this->connection))
    {
        mysql_close($this->connection);
        unset($this->connection);
    }
}
public function query($sql)
{
    //$sql = "SELECT*FROM users where id = 1";
    $result = mysql_query($sql);
    $this->confirm_query($result);
    //$found_user = mysql_fetch_assoc($result);
    //echo $found_user;
    return $found_user;
}
private function confirm_query($result)
{
    if(!$result)
    {
        die("The Query has problem" . mysql_error());
    }
}
}
$database = new MySQLDatabase();
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