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  • Problem with rake db:migrate

    - by Shreyas Satish
    When I try rake db:migrate, I get the following error: !!! The bundled mysql.rb driver has been removed from Rails 2.2. Please install the mysql gem and try again: gem install mysql. rake aborted! no such file to load -- mysql And when I try to "gem install mysql" Building native extensions. This could take a while... ERROR: Error installing mysql: ERROR: Failed to build gem native extension. /usr/bin/ruby extconf.rb Can't find header files for ruby. Gem files will remain installed in /usr/lib/ruby/gems/1.8/gems/mysql-2.8.1 for inspection. I checked the rubygems folder and mysql gem has been installed. Any ideas? Cheers

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  • How to select a MAX value from column in Query Builder in Kohana framework?

    - by Victor Czechov
    I need to INSERT a data to table, but before a query I must to know the MAX value from column position, than to INSERT a data WHERE my SELECTED before position+1. Is it possible with query builder? following my first comment I did query: $p = DB::select(array(DB::expr('MAX(`position`)', 'p')))->from('supercategories')->execute(); echo $p; the error: ErrorException [ Notice ]: Undefined offset: 1 MODPATH\database\classes\kohana\database.php [ 505 ] 500 */ 501 public function quote_column($column) 502 { 503 if (is_array($column)) 504 { 505 list($column, $alias) = $column; 506 } 507 508 if ($column instanceof Database_Query) 509 { 510 // Create a sub-query

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  • How can I choose different hints for different joins for a single table in a query hint?

    - by RenderIn
    Suppose I have the following query: select * from A, B, C, D where A.x = B.x and B.y = C.y and A.z = D.z I have indexes on A.x and B.x and B.y and C.y and D.z There is no index on A.z. How can I give a hint to this query to use an INDEX hint on A.x but a USE_HASH hint on A.z? It seems like hints only take the table name, not the specific join, so when using a single table with multiple joins I can only specify a single strategy for all of them. Alternative, suppose I'm using a LEADING or ORDERED hint on the above query. Both of these hints only take a table name as well, so how can I ensure that the A.x = B.x join takes place before the A.z = D.z one? I realize in this case I could list D first, but imagine D subsequently joins to E and that the D-E join is the last one I want in the entire query. A third configuration -- Suppose I want the A.x join to be the first of the entire query, and I want the A.z join to be the last one. How can I use a hint to have a single join from A to take place, followed by the B-C join, and the A-D join last?

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  • What is the easiest way to find a sql query returns a result or not?

    - by bala3569
    Consider the following sql server query , DECLARE @Table TABLE( Wages FLOAT ) INSERT INTO @Table SELECT 20000 INSERT INTO @Table SELECT 15000 INSERT INTO @Table SELECT 10000 INSERT INTO @Table SELECT 45000 INSERT INTO @Table SELECT 50000 SELECT * FROM ( SELECT *, ROW_NUMBER() OVER(ORDER BY Wages DESC) RowID FROM @Table ) sub WHERE RowID = 3 The result of the query would be 20000 ..... Thats fine as of now i have to find the result of this query, SELECT * FROM ( SELECT *, ROW_NUMBER() OVER(ORDER BY Wages DESC) RowID FROM @Table ) sub WHERE RowID = 6 It will not give any result because there are only 5 rows in the table..... so now my question is What is the easiest way to find a sql query returns a result or not?

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  • How to join a table in symfony (Propel) and retrieve object from both table with one query

    - by Jean-Philippe
    Hi, I'm trying to get an easy way to fetch data from two joined Mysql table using Propel (inside Symfony) but in one query. Let's say I do this simple thing: $comment = CommentPeer::RetrieveByPk(1); print $comment->getArticle()->getTitle(); //Assuming the Article table is joined to the Comment table Symfony will call 2 queries to get that done. The first one to get the Comment row and the next one to get the Article row linked to the comment one. Now, I am trying to find a way to make all that within one query. I've tried to join them using $c = new Criteria(); $c->addJoin(CommentPeer::ARTICLE_ID, ArticlePeer::ID); $c->add(CommentPeer::ID, 1); $comment = CommentPeer::doSelectOne($c); But when I try to get the Article object using $comment->getArticle() It will still issue the query to get the Article row. I could easily clear all the selected columns and select the columns I need but that would not give me the Propel object I'd like, just an array of the query's raw result. So how can I get a populated propel object of two (or more) joined table with only one query? Thanks, JP

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  • Kohana Database Library - How to Execute a Query with the Same Parameters More Than Once?

    - by Noah Goodrich
    With the following bit of code: $builder = ORM::factory('branch')->where('institution_id', $this->institution->id)->orderby('name'); I need to first execute: $count = $builder->count_all(); Then I need to execute: $rs = $builder->find_all($limit, $offset); However, it appears that when I execute the first query the stored query parameters are cleared so that a fresh query can be executed. Is there a way to avoid having the parameters cleared or at least copy them easily without having to reach directly into the Database driver object that stores the query parameters and copy them out? We are using Kohana 2.3.4 and upgrading is not an option.

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  • How can I use a php array in a mysql search query?

    - by ThinkingInBits
    I was going to use the scuttle solution on: http://www.pui.ch/phred/archives/2005/04/tags-database-schemas.html for handling searches on my website. I was wondering how I could take the search input from a user and turn it into a single query. For instance, let's say a user inputted 'blue dogs' in their search query... How could I dynamically update the query to include ('blue', 'dogs') in union and intersection queries?

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  • Get the last checked checkboxes...

    - by Sara
    Hi everyone, I'm not sure how to accomplish this issue which has been confusing me for a few days. I have a form that updates a user record in MySQL when a checkbox is checked. Now, this is how my form does this: if (isset($_POST['Update'])) { $paymentr = $_POST['paymentr']; //put checkboxes array into variable $paymentr2 = implode(', ', $paymentr); //implode array for mysql $query = "UPDATE transactions SET paymentreceived=NULL"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentdate='0000-00-00'"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentreceived='Yes' WHERE id IN ($paymentr2)"; $result = mysql_query($query); $query = "UPDATE transactions SET paymentdate=NOW() WHERE id IN ($paymentr2)"; $result = mysql_query($query); foreach ($paymentr as $v) { //should collect last updated records and put them into variable for emailing. $query = "SELECT id, refid, affid FROM transactions WHERE id = '$v'"; $result = mysql_query($query) or die("Query Failed: ".mysql_errno()." - ".mysql_error()."<BR>\n$query<BR>\n"); $trans = mysql_fetch_array($result, MYSQL_ASSOC); $transactions .= '<br>User ID:'.$trans['id'].' -- '.$trans['refid'].' -- '.$trans['affid'].'<br>'; } } Unfortunately, it then updates ALL the user records with the latest date which is not what I want it to do. The alternative I thought of was, via Javascript, giving the checkbox a value that would be dynamically updated when the user selected it. Then, only THOSE checkboxes would be put into the array. Is this possible? Is there a better solution? I'm not even sure I could wrap my brain around how to do that WITH Javascript. Does the answer perhaps lie in how my mysql code is written? Thanks - I sincerely appreciate it!!!

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  • rake db:create gives some problem when used from limited account

    - by Xinxua
    I am using mysql 5.1 and mysql gems version is 2.73 This is giving the following error message when I try to run it from a limited account in my XP. If try it using the admin account, it works fine. I think this is wierd because it cannot be the problem of mysql gem. (in F:/Temp/wassup) !!! The bundled mysql.rb driver has been removed from Rails 2.2. Please install the mysql gem and try again: gem install mysql. rake aborted! 5: Access is denied. - C:/Program Files/Ruby/lib/ruby/gems/1.8/gems/mysql-2.7. 3-x86-mswin32/ext/mysql.so (See full trace by running task with --trace) I need to work from the limited account. Can anyone let me know why is this happening?

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  • Help with IF THEN breaking when comparing results from MYSQL query.

    - by roydukkey
    I'm have a problem with an invite system. The if statement seems to break. It shows the message "Fail" but the UPDATE statement still executes. Why do both the THEN and the ELSE excute? $dbConn = new dbConn(); // Check if POST user_username and user_hash are matching and valid; both are hidden for fields $sql = "SELECT user_username " . "FROM table_users " . "WHERE user_id=".mysql_real_escape_string($_POST["user_id"])." " . "AND user_hash='".mysql_real_escape_string($_POST["user_hash"])."' " . "AND user_enabled=0;"; $objUser = $dbConn->query($sql); // If result contains 1 or more rows if( mysql_num_rows($objUser) != NULL ){ $objUser = mysql_fetch_assoc($objUser); $ssnUser->login( $objUser["user_username"] ); $sql = "UPDATE table_users SET " . "user_enabled=1, " . "user_first_name='".mysql_real_escape_string($_POST["user_first_name"])."', " . "user_last_name='".mysql_real_escape_string($_POST["user_last_name"])."', " . "user_password='".mysql_real_escape_string( md5($_POST["user_password"]) )."' " . "WHERE user_id=".mysql_real_escape_string($_POST["user_id"]).";"; $dbConn->query($sql); echo "Success"; header( "Refresh: 5; url=/account/?action=domains" ); } else { echo "Fail"; } This dbConn Class is as follows: class dbConn{ var $username = "xxxx_admin"; var $password = "xxxxxxxx"; var $server = "localhost"; var $database = "xxxx"; var $objConn; function __construct(){ $conn = mysql_connect( $this->server, $this->username, $this->password, true ); if( !$conn ){ die("Could not connect: ".mysql_error() ); } else { $this->objConn = $conn; } unset($conn); } function __destruct(){ mysql_close( $this->objConn ); unset( $this ); } function query( $query, $db = false ){ mysql_select_db( $db != false ? $db : $this->database, $this->objConn ); $result = mysql_query( $query ); unset($query,$db); return $result; } }

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  • How to determine the browser of the user using PHP?

    - by ron8
    How to determine the browser of the user using PHP? So that if the users browser is IE then the variable $alert="onbeforeunload" and if it is not IE, for example Firefox (else) then $alert="onload. Help is much appreciated. Thanks Also please note that I can not install browscap.ini on my PHP server.

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  • SQL query - choosing 'last updated' record in a group, better db design?

    - by Jimmy
    Hi, Let's say I have a MySQL database with 3 tables: table 1: Persons, with 1 column ID (int) table 2: Newsletters, with 1 column ID (int) table 3: Subscriptions, with columns Person_ID (int), Newsletter_ID (int), Subscribed (bool), Updated (Datetime) Subscriptions.Person_ID points to a Person, and Subscription.Newsletter_ID points to a Newsletter. Thus, each person may have 0 or more subscriptions to 0 or more magazines at once. The table Subscriptions will also store the entire history of each person's subscriptions to each newsletter. If a particular Person_ID-Newsletter_ID pair doesn't have a row in the Subscriptions table, then it's equivalent to that pair having a subscription status of 'false'. Here is a sample dataset Persons ID 1 2 3 Newsletters ID 4 5 6 Subscriptions Person_ID Newsletter_ID Subscribed Updated 2 4 true 2010-05-01 3 4 true 2010-05-01 3 5 true 2010-05-10 3 4 false 2010-05-15 Thus, as of 2010-05-16, Person 1 has no subscription, Person 2 has a subscription to Newsletter 4, and Person 3 has a subscription to Newsletter 5. Person 3 had a subscription to Newsletter 4 for a while, but not anymore. I'm trying to do 2 kinds of query. A query that shows everyone's active subscriptions as of query time (we can assume that updated will never be in the future -- thus, this means returning the record with the latest 'updated' value for each Person_ID-Newsletter_ID pair, as long as Subscribed is true (if the latest record for a Person_ID-Newsletter_ID pair has a Subscribed status of false, then I don't want that record returned)). A query that returns all active subscriptions for a specific newsletter - same qualification as in 1. regarding records with 'false' in the Subscribed column. I don't use SQL/databases often enough to tell if this design is good, or if the SQL queries needed would be slow on a database with, say, 1M records in the Subscriptions table. I was using the Visual query builder tool in Visual Studio 2010 but I can't even get the query to return the latest updated record for each Person_ID-Newsletter_ID pair. Is it possible to come up with SQL queries that don't involve using subqueries (presumably because they would become too slow with a larger data set)? If not, would it be a better design to have a separate Subscriptions_History table, and every time a subscription status for a Person_ID-Newsletter-ID pair is added to Subscriptions, any existing record for that pair is moved to Subscriptions_History (that way the Subscriptions table only ever contains the latest status update for any Person_ID-Newsletter_ID pair)? I'm using .net on Windows, so would it be easier (or the same, or harder) to do this kind of queries using Linq? Entity Framework? Thanks!

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  • How can you access two identically-named columns in a MySQL LEFT JOIN query?

    - by George Edison
    I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255) Then I use PHP to perform the following query: SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id The only problem is: how do I access table_x.id and table_tags.id in the results? Here is the PHP code: $query = "SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id"; $results = mysql_query($query); while($row = mysql_fetch_array($results)) { // how do I now access table_x.id and table_tags.id ??? }

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  • Entity Framework + MySQL - Why is the performance so terrible?

    - by Cyril Gupta
    When I decided to use an OR/M (Entity Framework for MySQL this time) for my new project I was hoping it would save me time, but I seem to have failed it (for the second time now). Take this simple SQL Query SELECT * FROM POST ORDER BY addedOn DESC LIMIT 0, 50 It executes and gives me results in less than a second as it should (the table has about 60,000 rows). Here's the equivalent LINQ To Entities query that I wrote for this var q = (from p in db.post orderby p.addedOn descending select p).Take(50); var q1 = q.ToList(); //This is where the query is fetched and timed out But this query never even executes it times out ALWAYS (without orderby it takes 5 seconds to run)! My timeout is set to 12 seconds so you can imagine it is taking much more than that. Why is this happening? Is there a way I can see what is the actual SQL Query that Entity Framework is sending to the db? Should I give up on EF+MySQL and move to standard SQL before I lose all eternity trying to make it work? I've recalibrated my indexes, tried eager loading (which actually makes it fail even without the orderby clause) Please help, I am about to give up OR/M for MySQL as a lost cause.

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  • MySQL - What is wrong with this query or my database? Terrible performance.

    - by Moss
    SELECT * from `employees` a LEFT JOIN (SELECT phone1 p1, count(*) c, FROM `employees` GROUP BY phone1) b ON a.phone1 = b.p1; I'm not sure if it is this query in particular that has the problem. I have been getting terrible performance in general with this database. The table in question has 120,000 rows. I have tried this particular query remotely and locally with the MyISAM and InnoDB engines, with different types of joins, and with and without an index on phone1. I can get this to complete in about 4 minutes on a 10,000 row table successfully but performance drops exponentially with larger tables. Remotely it will lose connection to the server and locally it brings my system to its knees and seems to go on forever. This query is only a smaller step I was trying to do when a larger query couldn't complete. Maybe I should explain the whole scenario. I have one big flat ugly table that lists a bunch of people and their contact info and the info of the companies they work for. I'm trying to normalize the database and intelligently determine which phone numbers apply to individual people and which apply to an office location. My reasoning is that if a phone number occurs multiple times and the number of occurrence equals the number of times that the street address it is attached to occurs then it must be an office number. So the first step is to count each phone number grouping by phone number. Normally if you just use COUNT()...GROUP BY it will only list the first record it finds in that group so I figured I have to join the full table to the count table where the phone number matches. This does work but as I said I can't successfully complete it on any table much larger than 10,000 rows. This seems pathetic and this doesn't seem like a crazy query to do. Is there a better way to achieve what I want or do I have to break my large table into 12 pieces or is there something wrong with the table or db?

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  • Can someone recommend a good tutorial on MySQL indexes, specifically when used in an order by clause

    - by Philip Brocoum
    I could try to post and explain the exact query I'm trying to run, but I'm going by the old adage of, "give a man a fish and he'll eat for a day, teach a man to fish and he'll eat for the rest of his life." SQL optimization seems to be very query-specific, and even if you could solve this one particular query for me, I'm going to have to write many more queries in the future, and I'd like to be educated on how indexes work in general. Still, here's a quick description of my current problem. I have a query that joins three tables and runs in 0.2 seconds flat. Awesome. I add an "order by" clause and it runs in 4 minutes and 30 seconds. Sucky. I denormalize one table so there is one fewer join, add indexes everywhere, and now the query runs in... 20 minutes. What the hell? Finally, I don't use a join at all, but rather a subquery with "where id in (...) order by" and now it runs in 1.5 seconds. Pretty decent. What in God's name is going on? I feel like if I actually understood what indexes were doing I could write some really good SQL. Anybody know some good tutorials? Thanks!

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