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  • Hibernate not Loading a class

    - by Noor
    Hi, I have a class Auction that contains a Class Item and Users but when I am getting the class, the class item and Users are not being loaded. Auction Class Mapping File: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Dec 28, 2010 9:14:12 PM by Hibernate Tools 3.4.0.Beta1 --> <hibernate-mapping> <class name="com.BiddingSystem.Models.Auction" table="AUCTION"> <id name="AuctionId" type="long"> <column name="AUCTIONID" /> <generator class="native" /> </id> <property name="StartTime" type="java.util.Date"> <column name="STARTTIME" /> </property> <property name="EndTime" type="java.util.Date"> <column name="ENDTIME" /> </property> <property name="StartingBid" type="long"> <column name="STARTINGBID" /> </property> <property name="MinIncrement" type="long"> <column name="MININCREMENT" /> </property> <many-to-one name="CurrentItem" class="com.BiddingSystem.Models.Item" fetch="join" cascade="all"> <column name="ItemId" /> </many-to-one> <property name="AuctionStatus" type="java.lang.String"> <column name="AUCTIONSTATUS" /> </property> <property name="BestBid" type="long"> <column name="BESTBID" /> </property> <many-to-one name="User" class="com.BiddingSystem.Models.Users" fetch="join"> <column name="UserId" /> </many-to-one> </class> </hibernate-mapping> When I am doing this: Query query=session.createQuery("from Auction where UserId="+UserId); List <Auction> AllAuctions= new LinkedList<Auction>(query.list()); The Users and Item are null

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  • How to synchronize two (or n) replication processes for MS SQL databases?

    - by Yauheni Sivukha
    There are two master databases and two read-only copies updated by standard transactional replication. It is needed to map some entity from both read-only databases, lets say that A databases contains orders and B databases contains lines. The problem is that replication to one database can lag behind replication of second database, and at the moment of mapping R-databases will have inconsistent data. For example. We stored 2 orders with lines at 19:00 and 19:03. Mapping process started at 19:05, but to the moment of mapping A database replication processed all changes up to 19:03, but B database replication processed only changes up to 19:00. After mapping we will have order entity with order as of 19:03 and lines as of 19:00. The troubles are guaranteed:) In my particular case both databases have temporal model, so it is possible to fetch data for every time slice, but the problem is to identify time of latest replication. Question: How to synchronize replication processes for several databases to avoid situation described above?

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  • JQUERY, getting two BINDs/Clicks to play nice together?

    - by nobosh
    I have the following line of code: <li id="1" class=" "> <a href="">Parking Lot</a> <span id="1" class="list-edit">edit</span> </li> I then have two binds: $("#lists li").click(function(){....... $(".list-edit").click(function(){......... The problem I'm having is I need the LI to contain the EDIT span because of CSS styling reasons, I have a big blue background. But this is preventing me from binding the EDIT btn. Is there a way to get these two to play nice? Thxs

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  • C#: Union of two ICollections? (equivlaent of Java's addAll())

    - by Rosarch
    I have two ICollections of which I would like to take the union. Currently, I'm doing this with a foreach loop, but that feels verbose and hideous. What is the C# equivalent of Java's addAll()? Example of this problem: ICollection<IDictionary<string, string>> result = new HashSet<IDictionary<string, string>>(); // ... ICollection<IDictionary<string, string>> fromSubTree = GetAllTypeWithin(elementName, element); foreach (IDictionary<string, string> dict in fromSubTree) // hacky { result.Add(dict); } // result is now the union of the two sets

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  • Layout question with BlackBerry IDE FieldManagers; how to emulate HTML's rowspan

    - by canadiancreed
    Hello all I'm trying to create a page where a list of items are displayed in a row where there are multiple columns on the left, but only one on the right, encased within a horizontialFieldManager. Currently I have the following code to attempt to do the following: VerticalFieldManager mainScreenManager = new VerticalFieldManager(); mainScreenManager.add(titleField); for (int i = 0; i < 10; i++) { HorizontalFieldManager itemAreaManager = new HorizontalFieldManager(); VerticalFieldManager itemTextFieldsAreaManager = new VerticalFieldManager(); itemTextFieldsAreaManager.add(new RichTextField(contentArticleTitle[i])); itemTextFieldsAreaManager.add(new RichTextField(contentArticleDate[i])); itemTextFieldsAreaManager.add(new SeparatorField()); itemAreaManager.add(itemTextFieldsAreaManager); itemAreaManager.add(new ButtonField("", 0)); mainScreenManager.add(itemAreaManager); }; add(mainScreenManager); Now the issue I'm experiencing is probably obvious to those familiar with managers; the horizontialFieldManager has the first item added to it consuming the entire width available, thereby never showing the button. What I'm wondering is how can I tell this in an extended class to only take up a certain percentage of the available width? I've tried subLayout and setting the width to be a certain amount, but it will just show the button instead of the text (pretty much same problem, just reversed)

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  • How do I toggle two images using jQuery and radio buttons?

    - by trench
    This isn't pretty, but I think you'll get what I'm trying to do. <label><input name="jpgSel" type="radio" value="0">jpg 1</label><br /> <label><input name="jpgSel" type="radio" value="1">jpg 2</label><br /> <div id="showjpg"></div> and $(document).ready(function() { $("select").change(function () { if ($("jpgSel:checked").val() == 1) { $('#showjpg').attr({ src: 'one.jpg', alt: 'one dot jpg' }); } else { $('#showjpg').attr({ src: 'two.jpg', alt: 'two dot jpg' }); } });

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  • ask. help me to compare two array of integers and the order does not matter.

    - by stdnoit
    [Example] <1 2 3 4 = <3 1 2 4 <1 2 3 4 != <3 4 1 1 and ummm it is in java. cant use hashmap table or anything just pure without library. I know there are two ways. 1. sort them and compare the array index by index 2. use two for loops and compare the outer index with the inner index. ( i have been trying with this but still not working) for(int i = 0; i < n; i++) { for(int j = 0; j < n; j++) { if(a[i] != a[j] && j == n) return false; } } return true; anything wrong with the code ? thanks

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  • Need to change layout of radio buttons! help needed

    - by James
    I've got 2 radio buttons and i want to put them next to each other. Right now theyre like Radio button 1 Radio button 2 i want to make it Radio button 1 Radio button 2 This is my code for the radio buttons, any help? <RadioGroup android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="vertical"> <RadioButton android:id="@+id/radio_male" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Male" android:layout_below="@id/gender"/> <RadioButton android:id="@+id/radio_female" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Female" /> </RadioGroup>

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  • I want to exchange the Value of a column in two different rows in Microsoft SQL server

    - by Silmaril89
    Hi, I want to do the following two SQL Queries in Microsoft SQL SERVER UPDATE Partnerships SET sortOrder = 2 WHERE sortOrder = 1; UPDATE Partnerships SET sortOrder = 1 WHERE sortOrder = 2; The only problem is, I don't allow for sortOrder to contain the same value, it is a unique key. How could I get around this, because the first query violates the unique key rule and terminates? Or will I have to get rid of the unique key rule I have? Thanks!

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  • Facebook Connect in iPhone app: Able to have two sessions?

    - by TheGambler
    Does anyone know if you are able to have two sessions save in one iphone app? I don't mean two sessions active. I want to be able to let someone switch between facebook accounts in my app without having to logout and back in. To my understanding a sessions state is saved in user preferences and is resumed when you basically say [ session resume ]. What I'm wondering is if I can choose which session to resume based on the uid? If so then I can choose which session to resume. Thanks to all that reply.

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  • How to place two <g> side by side in an svg?

    - by A_user
    Hello all I am new to html5 and svg tag.I want to ask a question about svg html element. Here is my code <html> <div> <svg width = "1335" height = "400"> // I want to have two svg:g side by side one of more width and second of less width such that width of svg = first g + second g <g> // All the elements inside g should have same width as g </g> <g> </g> </svg> <div> </html> I have tried it using transform.But failed. Is it possible to have two g elements side by side as I can't set x and y of g ? Can any one guide me of doingthis another way.

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  • php/mysql question, retrieving information

    - by chance
    Hey SO, I have a question, pretty new at PHP and MySql but was curious is it possible to display only the most recent column to a table, from a database? I know it is possible to display a list of all information, or if you have just one column of information in your table to display that using the Here is my code for my basic script (just loads 1 column of information) I would like it to only print out the recent column i added to the table $con = mysql_connect ("localhost","username","password"); if (!$con) { die ('Could not connect:' . mysql_error()0; } mysql_select_db("db_name", $con); $result = mysql_query(Select column FROM table"); while($row = mysql_fetch_array($result)) { echo $row['column']; } mysql_close($con); * keep in mind, im not looking for someone to shoot me my code with it completed, though it would be handy, however just giving me the options of what I have to do, or what the script is called would be plentiful enough for my research, thanks!

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  • Splitting values into groups evenly

    - by Paul Knopf
    Let me try to explain the situation the best I can. Lets say I have 3 values 1, 2, 3 I tell an algorithm to split this values into x columns. Lets say x = 2 for clarification. The algorithm determines that the group of values is best put into two columns the following way. 1st column 2nd column --------------------------- 1 3 2 Each column has an even number (totals, not literals) value. Now lets say I have the following values 7, 8, 3, 1, 4 I tell the algorithm that I want the values split into 3 columns. The algorithm now tells me that the following is the best fit. 1st column 2nd column 3rd column 8 7 3 1 4 Notice how the columns arent quiet even, but it is as close as it can get. A little over and a little under is considered ok, as long as the list is AS CLOSE TO EVEN AS IT CAN BE. Anybody got any suggestions? Know any good methods of doing this?

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  • mysql: Can I use two "where"s? Like, "SELECT * FROM table WHERE something and something"?

    - by KeriLynn
    I have a table with my products and I'm trying to write a page that would pull bracelets with certain colors from the database. So here's what I have right now (in php): $query = "SELECT * FROM products WHERE (products.colors LIKE '%black%')"; But I only want to select rows where the value for the column "category" equals "bracelet". I've tried a few different things, but I keep getting warnings and errors. I appreciate any help you can give, thank you!

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  • Duplication in mysql/php

    - by user1334095
    I have a problem in the code.i have two tables 'sms' and 'bd_paid_bribe'.sms table has a column 'Message' and bd_paid_bribe table has a column 'c_addi_info'.when i execute the code first time all the values of Message column are inserted into c_addi_info column.when i enter a record for the second time instead of inserting the new record, all the records of Message column are inserted into bd_paid_bribe column.can u modify the code and provide a solution to avoid duplication and to insert only the newly added record. <?php $con=mysql_connect('localhost','root',''); if(!$con) { die("couldn't connect"); } mysql_select_db("ipab2",$con); $rs2=mysql_query(" select max(sms_index) from tab3"); do { $rs=mysql_query("insert into tab3(sms_index)select max(sms_index) from sms"); $rs3=mysql_query("SELECT max(sms_index) FROM sms"); $rs1=mysql_query("insert into bd_paid_bribe(c_addi_info) select Message from sms "); }while($rs2>$rs3); ?>

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  • how do i insert into two table all at once in a stored procedure?

    - by user996502
    Doing a project for school so any help would be great thank you! I have two tables how do i insert into two tables? so both tables are linked. First table called Customer with primary key called CID that auto increments CREATE TABLE [dbo].[Customer]( [CID] [int] IDENTITY(1,1) NOT NULL, [LastName] [varchar](255) NOT NULL, [FirstName] [varchar](255) NOT NULL, [MiddleName] [varchar](255) NULL, [EmailAddress] [varchar](255) NOT NULL, [PhoneNumber] [varchar](12) NOT NULL CONSTRAINT [PK__CInforma__C1F8DC5968DD69DC] PRIMARY KEY CLUSTERED ( And a second table called Employment that has a foreign key linked to the parent table CREATE TABLE [dbo].[Employment]( [EID] [int] IDENTITY(1,1) NOT NULL, [CID] [int] NOT NULL, [Employer] [varchar](255) NOT NULL, [Occupation] [varchar](255) NOT NULL, [Income] [varchar](25) NOT NULL, [WPhone] [varchar](12) NOT NULL, CONSTRAINT [PK__Employme__C190170BC7827524] PRIMARY KEY CLUSTERED (

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  • How to combine two 32-bit integers into one 64-bit integer?

    - by Bei337
    I have a count register, which is made up of two 32-bit unsigned integers, one for the higher 32 bits of the value (most significant word), and other for the lower 32 bits of the value (least significant word). What is the best way in C to combine these two 32-bit unsigned integers and then display as a large number? In specific: leastSignificantWord = 4294967295; //2^32-1 printf("Counter: %u%u", mostSignificantWord,leastSignificantWord); This would print fine. When the number is incremented to 4294967296, I have it so the leastSignificantWord wipes to 0, and mostSignificantWord (0 initially) is now 1. The whole counter should now read 4294967296, but right now it just reads 10, because I'm just concatenating 1 from mostSignificantWord and 0 from leastSignificantWord. How should I make it display 4294967296 instead of 10?

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