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  • jQuery code not executed

    - by Jan-Frederik Carl
    Hello, I would like to rephrase my previous question which no one could answer. My problem is that a jQuery-script does not execute a command though it "runs" it. I can see it in the debug mode where the debugger hits the command. Nonetheless, the command is not executed.

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  • Validation Control

    - by James
    I placed some validation controls on my grid view template. The only problem is that it is taking a lot of space vertically. Is there a property to set to solve this problem?

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  • Retreiving data from grid view cell to a text box

    - by Bader
    Hello , i am trying to retrieve a cell data to a textbox , that will happen when i select any row in the grid view , the textbox will take the new value i already enabled auto post back to the textbox here is my code protected void GridView2_SelectedIndexChanged(object sender, EventArgs e) { TextBox3.Text = GridView2.Rows[GridView2.SelectedIndex].Cells[2].Text; } however , there is not error in the syntax , it doesn't retrieve any thing in the textbox , any suggestions ? i am using using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.SqlClient; using System.Data.Sql; i work in C# , Visual studio 2010 express web developer

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  • Error in OnClientClick in C#?

    - by Champ
    I want a popup to be populated to user before deleting the record I have tried OnClientClick and class to handle it with JavaScript/jQuery but with no success ERROR Type 'System.Web.UI.WebControls.HyperLinkField' does not have a public property named 'OnClientClick'. Control <asp:HyperLinkField OnClientClick="return confirm('Are you sure you would like to delete the selected landing page?')" datanavigateurlfields="id" datanavigateurlformatstring="ViewLandingPages.aspx?id={0}&delete=yes" HeaderText="Delete" Text="Delete" /> EDIT : also tried adding a class (for handling it with jquery ) but with no success

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  • How can I change column fore color in DataGridview as per condition?

    - by Ashish
    hi, i have one table like employee and one of its row is 'status' if status value is 'approve' then i want to show that row in green color and else i want to show it in red color. i have tried following but not working if (e.Row.RowType == DataControlRowType.Header) { string status = DataBinder.Eval(e.Row.DataItem, "IsApprove").ToString(); if (status == "pending") { e.Row.ForeColor = System.Drawing.Color.Red; // Change the row's Text color } } ALSO THIS ONE private void gvleavedetail_cellformatting(object sender, datagridviewcellformattingeventargs e) { // if the column is the artist column, check the // value. if (this.gvleavedetail.columns[e.columnindex].name == "artist") { if (e.value != null) { // check for the string "pink" in the cell. string stringvalue = (string)e.value; stringvalue = stringvalue.tolower(); if (stringvalue == "high") { e.cellstyle.backcolor = color.pink; } } } But in this case i'm getting error for datagridviewcellformattingeventargs I'm using VS2010

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  • Asp.Net Scrapping Grid Pages

    - by SH
    I need cod in C#. Look, i am trying to post the search.aspx page which contains Asp.Net grid. When grid is rendered it loads very first page on the screen and then there are number of pages in the grid header. I scrap first page, and now i want to move on to the next page. All this is being done using following code: HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create("http://pubrec3.hillsclerk.com/oncore/search.aspx?" + param); myRequest.Method = "GET"; myRequest.KeepAlive = false; HttpWebResponse webresponse; try { webresponse = (HttpWebResponse)myRequest.GetResponse(); Encoding enc = System.Text.Encoding.GetEncoding(1252); StreamReader loResponseStream = new StreamReader(webresponse.GetResponseStream(), enc); string r = loResponseStream.ReadToEnd(); loResponseStream.Close(); webresponse.Close(); //if (GetRecordCount(r)) ExtractResultTable(bd, ed, r); } catch (Exception ex) { } The above code grabs first page... and now i have to move on to the next page. This is the link which produces a grid with 3 pages. http://pubrec3.hillsclerk.com/oncore/search.aspx?bd=01/01/2008&ed=12/31/2008&bt=O&lb=1000000&ub=1000000000&d=5/6/2010&pt=-1&dt=D,%20MTG&st=consideration Using above code i need to load the 2nd page with the same search criteria but the records found in 2nd page. and then so on. I know there is a trick to navigate through the grid pages. I used it but it did not work on this page. the trick is, you can pass __EVENTTARGET and __EVENTARGUMENT in query string to navigate through the gird but it does not work on this website. I am desperately searching a way, how to cope with this website. i really want this done. i do not want any code but a way to nevigate throgh the grid using query string if it does work. Otherwise please be specific to the problem.

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  • Reset the focus to Grid item

    - by Senthilkumar
    Hi I am currently working on setting tab order for my appliction. When I click some item inside grid view or datagrid it display pop up, How can access the client id of the particular item (cell) which caused the pop up to appear.. ?? And also how can reset the focus back top that item in grid view.. can anyone help??

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  • Navigate through .Net Grid

    - by SH
    is there a way to navigate through gird found on this page by passing parameters in query string? http://pubrec3.hillsclerk.com/oncore/search.aspx?bd=01/01/2008&ed=12/31/2008&bt=O&lb=1000000&ub=1000000000&d=5/6/2010&pt=-1&dt=D,%20MTG&st=consideration Or any code suggestion? All example could i need in C#.

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  • Insert and remove Template textbox column in grid view

    - by user1545215
    class TextColumn : ITemplate { private string controlId; private string cssClass; public TextColumn(string id, string cssClass = "inputFromTo") { controlId = id; this.cssClass = cssClass; } public void InstantiateIn(Control container) { TextBox txt = new TextBox(); txt.ID = controlId; txt.CssClass = cssClass; container.Visible = true; container.Controls.Add(txt); } } /******************* Add column code snippet ***************/ TemplateField dentry = new TemplateField(); TemplateField dexit = new TemplateField(); TemplateField dslack = new TemplateField(); dentry.ItemTemplate = new TextColumn("txtHH" + nameCount + "DEntry"); dexit.ItemTemplate = new TextColumn("txtHH" + nameCount + "DExit"); dslack.ItemTemplate = new TextColumn("txtHH" + nameCount + "DSlack"); gvOfcBlowingReport.Columns.Insert(startPoint, dentry); gvOfcBlowingReport.Columns.Insert(startPoint + 1, dexit); gvOfcBlowingReport.Columns.Insert(startPoint + 2, dslack); /***************** Remove column code snippet ************/ gvOfcBlowingReport.Columns.RemoveAt(startPoint - 1); gvOfcBlowingReport.Columns.RemoveAt(startPoint - 2); gvOfcBlowingReport.Columns.RemoveAt(startPoint - 3); // after executing this code all the columns vanish. Anyone know how to remove this text box template column?

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  • Index outof range? Automatica generate field .How to manipulate GridView2.Columns as BoundField;

    - by mike
    Index outof range?GridView2.Columns[6] as BoundField I use Automatica generate field . How to manipulate GridView2.Columns as BoundField with auto-generate feather? JobPostDataContext db = new JobPostDataContext(); var query = from j in db.JobLists join u in db.UserLists on j.UserID equals u.UserID where j.JobTitle.Contains(this.TextBox1.Text) select new { j.JobID, j.JobTitle, j.Summary, j.Details, j.CompanyName, j.CompanyEmail, j.DatePosted, j.UserID, u.City, u.State, u.Country }; GridView2.DataSource = query; GridView2.DataBind(); BoundField DatePosted = GridView2.Columns[6] as BoundField; DatePosted.DataFormatString = "{0:MMM,dd yy}";

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  • ASP.NET C# - do you need a separate datasource for each gridview? [closed]

    - by Brian McCarthy
    Do you need a separate datasource for each gridview if each gridview is accessing the same database but different tables in the database? I'm getting an error on AppSettings that says non-invocable member. What is the problem with it? Here's the c# code-behind: protected void Search_Zip_Plan_Age_Button_Click(object sender, EventArgs e) { var _with1 = this.ZipPlan_SqlDataSource; _with1.SelectParameters.Clear(); _with1.ConnectionString = System.Configuration.ConfigurationManager.AppSettings("PriceFinderConnectionString").ToString; _with1.SelectCommand = "ssp_get_zipcode_plan"; _with1.SelectParameters.Add("ZipCode", this.ZipCode.Text); _with1.SelectParameters.Add("PlanCode", this.PlanCode.Text); _with1.SelectParameters.Add("Age", this.Age.Text); _with1.SelectCommandType = SqlDataSourceCommandType.StoredProcedure; _with1.CancelSelectOnNullParameter = false; Search_Results_GridView.DataBind(); } thanks!

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  • ASPx GridView , combobox inside of detailed grid, all the time has null value on Updating

    - by evgelen
    I have a combobox inside of detailed Devexpress grid. In edit mode on Updating event the combobox always has e.OldValues and e.NewValues always null, even when you change it.. any ideas or work around ??? Please see my code below <-PropertiesComboBox DataSourceID="DataSource" TextField="Name" ValueField="ID" ValueType="System.Int32" protected void ASPxGridView2_RowUpdating(object sender, ASPxDataUpdatingEventArgs e) { object test1 = e.NewValues["Email"]; e.Cancel = true; }

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  • SP Gridview link button column not working

    - by Dilse Naaz
    Hi I have one sharepoint custom page application which is rendering from a user control. In the user control page, i had used SPGridview for displaying data. My first column is Title Column (link button column), when the user click on the link, then one popup window will open with corresponding data. But the problem is the link button is not working properly. But this application is working as fine in asp.net application. My code is shown below.. <asp:UpdatePanel runat="server" ID="UpdatePanel2"> <ContentTemplate> <SharePoint:SPGridView ID="dgApplicationBox" CellPadding="0" Height="100%" runat="server" ForeColor="Black" Font-Size="10px" Font-Names="Verdana" AutoGenerateColumns="False" AllowPaging="True" Width="100%" BorderStyle="None" BorderWidth="0px" PageSize="10" BorderColor="White" BackColor="White" OnRowDataBound="dgApplicationBox_RowDataBound" DataKeyNames="ApplicationID" OnSelectedIndexChanged="dgApplicationBox_SelectedIndexChanged" OnPageIndexChanging="dgApplicationBox_PageIndexChanging" CssClass="ms-listviewtable" AlternatingRowStyle-CssClass="ms-alternating"> <SelectedRowStyle Font-Bold="True" ForeColor="Black" BackColor="#CE5D5A"></SelectedRowStyle> <EditRowStyle Font-Size="10px" Font-Names="Verdana,Arial,Helvetica,sans-serif"></EditRowStyle> <HeaderStyle Font-Size="11px" Height="20px" Font-Bold="True" ForeColor="Black" BackColor="#E7E8EC"> </HeaderStyle> <PagerStyle HorizontalAlign="Center" ForeColor="#414E61" Font-Size="5px" Font-Names="arial" Height="10px" BackColor="#EBF3FF"></PagerStyle> <RowStyle /> <Columns> <asp:TemplateField HeaderText="Title" HeaderStyle-CssClass="ms-vb"> <ItemTemplate> <asp:LinkButton ID="lbtnSubject" Text='<%# Bind("UDF5") %>' runat="server" OnClick="lbtnSubject_Click"></asp:LinkButton> </ItemTemplate> <HeaderStyle HorizontalAlign="Left" CssClass="ms-vh2" Font-Bold="true" /> <ItemStyle HorizontalAlign="Left" CssClass="ms-vb2" /> </asp:TemplateField> <asp:TemplateField HeaderText="Request No."> <ItemTemplate> <asp:Label ID="lblReqNo" Text='<%# Bind("UDF1") %>' runat="server" /> </ItemTemplate> <HeaderStyle HorizontalAlign="Left" CssClass="ms-vh2" Font-Bold="true" /> <ItemStyle HorizontalAlign="Left" CssClass="ms-vb2" /> </asp:TemplateField> <asp:BoundField DataField="CreatedOn" HeaderText="Created On" DataFormatString="{0:MM/dd/yyyy}" HeaderStyle-HorizontalAlign="Left" ItemStyle-HorizontalAlign="Left"> <HeaderStyle CssClass="ms-vh2" Font-Bold="true"></HeaderStyle> <ItemStyle CssClass="ms-vb2"></ItemStyle> </asp:BoundField> <asp:BoundField DataField="Name" HeaderText="Form Type" HeaderStyle-HorizontalAlign="Left" ItemStyle-HorizontalAlign="Left"> <HeaderStyle CssClass="ms-vh2" Font-Bold="true"></HeaderStyle> <ItemStyle CssClass="ms-vb2"></ItemStyle> </asp:BoundField> <asp:TemplateField HeaderText="History"> <HeaderStyle CssClass="ms-vh2" Font-Bold="true"></HeaderStyle> <ItemStyle HorizontalAlign="Center" VerticalAlign="Middle" Width="21px" CssClass="ms-vb2"> </ItemStyle> <ItemTemplate> <asp:LinkButton ID="lbtnView" runat="server" OnClick="lbtnView_Click" >View</asp:LinkButton> </ItemTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="Application Id" Visible="False"> <ItemTemplate> <asp:Label ID="lblApplicationId" runat="server" Text='<%# Bind("ApplicationId") %>'></asp:Label> </ItemTemplate> <HeaderStyle HorizontalAlign="Left" CssClass="ms-vh2" Font-Bold="true" /> <ItemStyle HorizontalAlign="Left" CssClass="ms-vb2" /> </asp:TemplateField> </Columns> </SharePoint:SPGridView> </ContentTemplate> </asp:UpdatePanel> when the user click on the link button, this code will works.. try { clearSession(); Session["DigitalSignature"] = null; Button btnDetails = sender as Button; DataTable dt = (DataTable)dgApplicationBox.DataSource; GridViewRow gvRow = (GridViewRow)(sender as LinkButton).Parent.Parent; Session["AppId"] = ((Label)gvRow.FindControl("lblApplicationId")).Text; string subject = ((LinkButton)gvRow.FindControl("lbtnSubject")).Text; WFInfo objWFInfo = new WFInfo(); objWFInfo.InitWorkflowProperty(Convert.ToInt32(Session["AppId"].ToString()), Session["CurrentUser"].ToString()); Session["FormId"] = objWFInfo.FormID.ToString(); string strFilname = objWFInfo.GetFormName(objWFInfo.ApplicationCategoryID.ToString()); string WindowName = strFilname; strFilname += ".aspx"; Session["CategoryId"] = objWFInfo.ApplicationCategoryID.ToString(); //pnlSubmitModal_ModalPopupExtender.Show(); ScriptManager.RegisterStartupScript(this, this.GetType(), "starScript", "popUpWindow('" + strFilname + "?tittle=" + subject + "', 800, 690,'" + WindowName + "');", true); this.Controls.Add(new LiteralControl("<script>alert('hi');</script>")); if (Session["CurrentUser"] != null) { ApplicationForm objApplication = new ApplicationForm(); objApplication.markRead(Convert.ToInt32(Session["AppId"].ToString()), Session["CurrentUser"].ToString()); } bindFolderData(); } If i click on the link button, there will be only post back occuring. but not the popup window open.. Please help me for resolving this problem. thanks in advance..

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  • devexpress gridview's loading panel problem

    - by subash
    i have a div which contains devexpress grid ondeleting a record in the grid it shows a loading panel and the diaplys the updated grid. The problem is that the loading panel appears in the left top corner of the browser and not in the center of the grid where it should be? can any one guide me in that

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  • css pagination for GridView

    - by nCdy
    my css : /* for greed view */ .pagination { font-size: 80%; } .pagination a { text-decoration: none; color: #15B; } .pagination a, .pagination span { display: block; float: left; padding: 0.3em 0.5em; margin-right: 5px; margin-bottom: 5px; } .pagination .current { background: #26B; color: #fff; border: solid 1px #AAE; } .pagination .current.prev, .pagination .current.next{ color:#999; border-color:#999; background:#fff; } but .pagination .current doesn't appears on current page and I can's see the border on it. What am I doing wrong ?

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  • Pinterest Gridview implementation on iOS

    - by Amal
    I want to implement a grid view like the one in Pinterest I thought about implementing as 3 table views. But I was not able to scroll them together well. When I implemented the scrollViewDidScroll and set the contentOffset for the table views other the scrollView , the scrolling became slow and unusable. Another implementation I did was of was having a set of images to load and calling the viewDraw function in scrollViewDidScroll. THe ViewDraw function just draws the necessary images and removes the rest of the images from the memory which were already drawn but wont be visible . this too makes the ScrollView Scrolling slow. And another issue with it is that there are white(background color) patches before the images are drawn. What should be the best way to implement this grid view ?

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  • Exporting data from a gridview to different excel worksheets

    - by Alex
    I am binding data from a dataset to a grid and exporting data from the grid to an excel.if the the number of items in the grid is greater than 50000,an error message is displayed. So i want to split the data and display it in different worksheets in excel.(Am working in a web application) using this code for exporting to excel gvExcel.DataSource = DTS; gvExcel.DataBind(); Response.AddHeader("content-disposition", "attachment; filename= filename.xls"); Response.ContentType = "application/excel"; StringWriter sw = new StringWriter(); HtmlTextWriter htw = new HtmlTextWriter(sw); gvExcel.RenderControl(htw); // Style is added dynamically Response.Write(style); Response.Write(sw.ToString()); Response.End(); Can anyone help me on this??

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  • How to roll back changes in gridview in case of incorrect input

    - by Mustafa A. Jabbar
    Hi, I have a DataGridView that is bound to a list of object. It has some columns that the user can edit. There are certain inputs that are not allowed for a row as a whole. How can I roll back if the user enters invalid inputs in some cell. I tried using the RowValidating event handler but it was not called after cell value has been changed. Even when I implemet CellValueChanged, I still cannot roll back the changes. Any idea how to accomplish this

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