Search Results

Search found 27768 results on 1111 pages for 'mysql connect'.

Page 270/1111 | < Previous Page | 266 267 268 269 270 271 272 273 274 275 276 277  | Next Page >

  • Why does this sql statement keep saying it is a boolean and not a parameter? (php/Mysql)

    - by ggfan
    In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

    Read the article

  • [MYSQL] select statement that combines similar rows with certain ids ?

    - by vegatron
    hi I have a warehouse_products table which defines how many products in the warehouses so lets say I have 20 records/rows in the table, some rows may contain the same product id but in a different warehouse I need to create select statement that give every product one row, and in this row I must have the quantity in warehouse A and warehouse B .. so in the end I will get for example 10 rows that contain all the data id domain_id warehouse_id wh_product_id quantity 2 1 2 2 84 3 1 1 3 221 4 1 3 3 0 5 1 1 3 14 6 1 1 2 73 7 1 1 1 123

    Read the article

  • How do I select the most recent entry in mysql?

    - by ggfan
    i want to select the most recent entry from a table and see if that entry is exactly the same as the one the user is trying to enter. How do I do a query to "select * from the most recent entry of 'posting'"? $query="Select * FROM //confused here (SELECT * FROM posting ORDER BY date_added DESC) WHERE user_id='{$_SESSION['user_id']}' AND title='$title' AND price='$price' AND city='$city' AND state='$state' AND detail='$detail' "; $data = mysqli_query($dbc, $query); $row = mysqli_fetch_array($data); if(mysqli_num_rows($data)>0) { echo "You already posted this ad. Most likely caused by refreshing too many times."; echo "<br>"; $linkposting_id=$row['posting_id']; echo "See the <a href='ad.php?posting_id=$linkposting_id'>Ad</a>"; } else { ...insert into the dbc }

    Read the article

  • Please help me out in fetching the desired result from below given DB table structure of MySQL..

    - by OM The Eternity
    Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

    Read the article

  • Recursive MySQL function call eats up too much memory and dies.

    - by kylex
    I have the following recursive function which works... up until a point. Then the script asks for more memory once the queries exceed about 100, and when I add more memory, the script typically just dies (I end up with a white screen on my browser). public function returnPArray($parent=0,$depth=0,$orderBy = 'showOrder ASC'){ $query = mysql_query("SELECT *, UNIX_TIMESTAMP(lastDate) AS whenTime FROM these_pages WHERE parent = '".$parent."' AND deleted = 'N' ORDER BY ".$orderBy.""); $rows = mysql_num_rows($query); while($row = mysql_fetch_assoc($query)){ // This uses my class and places the content in an array. MyClass::$_navArray[] = array( 'id' => $row['id'], 'parent' => $row['parent'] ); MyClass::returnPArray($row['id'],($depth+1)); } $i++; } Can anyone help me make this query less resource intensive?

    Read the article

  • MySQL Check and compare and if necessary create data.

    - by user2979677
    Hello I have three different tables Talk ID type_id YEAR NUM NUM_LETTER DATE series_id TALK speaker_id SCRIPREF DONE DOUBLE_SID DOUBLE_TYP LOCAL_CODE MISSING RESTRICTED WHY_RESTRI SR_S_1 SR_E_1 BCV_1 SR_S_2 SR_E_2 BCV_2 SR_S_3 SR_E_3 BCV_3 SR_S_4 SR_E_4 BCV_4 QTY_IV organisation_id recommended topic_id thumbnail mp3_file_size duration version Product_component id product_id talk_id position version Product id created product_type_id last_modified last_modified_by num_sold current_stock min_stock max_stock comment organisation_id series_id name subscription_type_id recipient_id discount_start discount_amount discount_desc discount_finish discount_percent voucher_amount audio_points talk_id price_override product_desc instant_download_status_id downloads instant_downloads promote_start promote_finish promote_desc restricted from_tape discontinued discontinued_reason discontinued_date external_url version I want to create a procedure that will check if select the id from talk and compare it with the id of product to see if there is a product id in the table and if there isn't then create it however my problem is that my tables talk and product can't talk, as id in talk is related to talk_id in product_component and id in product is related to product_id in product_component. Are there any ways for this to be done? I tried this, CREATE DEFINER=`sthelensmedia`@`localhost` PROCEDURE `CreateSingleCDProducts`() BEGIN DECLARE t_id INT; DECLARE t_restricted BOOLEAN; DECLARE t_talk CHAR(255); DECLARE t_series_id INT; DECLARE p_id INT; DECLARE done INT DEFAULT 0; DECLARE cur1 CURSOR FOR SELECT id,restricted,talk,series_id FROM talk WHERE organisation_id=2; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done=1; UPDATE product SET restricted=TRUE WHERE product_type_id=3; OPEN cur1; create_loop: LOOP FETCH cur1 INTO t_id, t_restricted, t_talk, t_series_id; IF done=1 THEN LEAVE create_loop; END IF; INSERT INTO product (created,product_type_id,last_modified,organisation_id,series_id,name,restricted) VALUES (NOW(),3,NOW(),2,t_series_id,t_talk,t_restricted); SELECT LAST_INSERT_ID() INTO p_id; INSERT INTO product_component (product_id,talk_id,position) VALUES (p_id,t_id,0); END LOOP create_loop; CLOSE cur1; END Just wondering if anyone could help me.

    Read the article

  • In a MySQL SELECT query, can I use my "AS column" in a WHERE specification?

    - by user556352
    In my database I calculate distance between nodes with: SELECT DISTINCT dest.name, AsText(orig.location), AsText(dest.location), round((glength(linestringfromwkb(linestring((orig.location), (dest.location)))))) as distance FROM nodes orig, nodes dest WHERE orig.name='GERP' I would like to add "and distance < dest.visibility" at the end, but am told that distance is an unknown column. Any insight very much appreciated.

    Read the article

  • Parallel MySQL queries for HTML table - WHILE(x or y)?

    - by Beti Chode
    I'm trying to create a table using PHP. What I need is a table with two columns. So I have an SQL table with 4 fields - primary key id, language, word and definition. The language for each is either Arabic or Russian. I want a table that does the following: | defintion | |____________________| | | | rus1 | arab1 | | rus2 | arab2 | | rus3 | arab3 | | rus4 | | So it divides the list by English word, creates a for each English word, then lists Russian equivalents in the left column and Arabic in the right. However there are often not the same number for both. What I am doing right now is running a WHILE loop in a WHILE loop. The outer loop is running fine but I think I am doing the inner loop wrong. Here is the bulk of the code: $definitions=mysql_query("SELECT DISTINCT definition FROM words") WHILE($row=mysql_fetch_array($definitions) { ECHO '<tr><th colspan="2">' . $row['definition'] . '</th></tr>'; $russian="SELECT * FROM words WHERE language='Russian' AND definition='".$row['definition']."'"; $arabic="SELECT * FROM words WHERE language='Arabic' AND definition='".$row['definition']."'"; WHILE($rus=mysql_fetch_array($russian) or $arb=mysql_fetch_array($arabic)) { ECHO '<tr><td>'.$rus['word'].'</td><td>'.$arb['word'].'</td></tr>'; } } Sadly I am getting soemthing like this: | defintion | |____________________| | | | rus1 | | | rus2 | | | rus3 | | | rus4 | | | | arab1 | | | arab2 | | | arab3 | Not sure what other way I can do this? I tried changing the or to || thinking the different precedence would cause another outcome, but then I get ONLY the Russian column. I'm out of ideas, you guys are my only hope!

    Read the article

  • What are advantages of using a one-to-one table relationship? (MySQL)

    - by byronh
    What are advantages of using a one-to-one table relationship as opposed to simply storing all the data in one table? I understand and make use of one-to-many, many-to-one, and many-to-many all the time, but implementing a one-to-one relationship seems like a tedious and unnecessary task, especially if you use naming conventions for relating (php) objects to database tables. I couldn't find anything on the net or on this site that could supply a good real-world example of a one-to-one relationship. At first I thought it might be logical to separate 'users', for example, into two tables, one containing public information like an 'about me' for profile pages and one containing private information such as login/password, etc. But why go through all the trouble of using unnecessary JOINS when you can just choose which fields to select from that table anyway? If I'm displaying the user's profile page, obviously I would only SELECT id,username,email,aboutme etc. and not the fields containing their private info. Anyone care to enlighten me with some real-world examples of one-to-one relationships?

    Read the article

  • What would be the most efficient way to do this search (mysql or text)?

    - by alex
    Suppose I have 500 rows of data, each with a paragraph of text (like this paragraph). That's it.I want to do a search that is not only based on words. (%LIKE%, not FULL_TEXT) What would be faster? SELECT * FROM ...WHERE LIKE "%query%"; This would put load on the database server. Select all. Then, go through each one and do .find = 0 This would put load on the web server. This is a website, and people will be searching frequently.

    Read the article

  • Is there a way to combine these 3 tables? (mysql)

    - by ggfan
    I'm creating a "flagged" func that flags users, postings, and comments. I am currently using three tables: "flagged_users" "flagged_postings" and "flagged_comments". And in each table, there's: flagged_id, user_id/posting_id/comment_id, reason. Is there a way to combine into just one table? or is 3 tables the best?

    Read the article

  • Is there something in MySQL like IN but which uses AND instead of OR?

    - by Skatox
    I need a SQL statement to retrieve records where it key (or any column) is in a associate table, for example: documentId termId 4 1 4 2 3 3 5 1 This: SELECT documentId FROM table WHERE termId IN (1,2,3) ...will retrieve any documentid value where the termid value is 1 or 2 or 3. Is there something like this but return documentid values where the termid values are 1 and 2 and 3? Like an IN but with AND.

    Read the article

  • MySQL query to find the most popular value in a column joined by another value in a second table

    - by Budove
    I have two tables: users: user_id, user_zip settings: user_id, pref_ex_loc I need to find the single most popular 'pref_ex_loc' from the settings table based on a particular user_zip, which will be specified as the variable $userzip. Here is the query that I have now and obviously it doesn't work. $popularexloc = "SELECT pref_ex_loc, user_id COUNT(pref_ex_loc) AS countloc FROM settings FULL OUTER JOIN users ON settings.user_id = users.user_id WHERE users.user_zip='$userzip' GROUP BY settings.pref_ex_loc ORDER BY countloc LIMIT 1"; $popexloc = mysql_query($popularexloc) or die('SQL Error :: '.mysql_error()); $exlocrow = mysql_fetch_array($popexloc); $mostpopexloc=$exlocrow[0]; echo '<option value="'.$mostpopexloc.'">'.$mostpopexloc.'</option>'; What am I doing wrong here? I'm not getting any kind of error from this either.

    Read the article

  • What is causing a Hibernate SQL query exception?

    - by Dark Star1
    Hi all and sorry in advance for this post but I've spent way too much time going around in circles so I'm hoping someone could shed a light on it here for me. I updated a webapp on Tomcat and I'm getting the following error which didn't exist on the previous version. Though I am quite confident that the part of code I modifed isn't to blame as I have tested the app on two different dev servers. The production server is configured thus: CentOS 5.4 virtual server with tomcat 5.5.23 running mysql 5.0.77. The two dev servers are: Windows XP SP2 running tomcat 5.5.23 with mysql 5.1.49 Mac OSX 10.6.6 Running tomcat 6 with mysql 5.1.51 The application was developed using struts (1.1 as far as I can gather) with hibernate 3 as the peristence layer. It only fails on the production server for some reason I can't fathom. I'd like to draw your attention to the java.sql.SQLException near the bottom. After some long searching I found this but because it was posted years ago (about 1 year before development started on this app I'm sure Hibernate has evolved from that version. as I can't find a way of implementing his solution. I use Eclipse Helios as an IDE. Thanks in advance for taking your time to read this, to all who manage to reply. javax.servlet.ServletException: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.action.login.LoginAction.execute(LoginAction.java:219) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) javax.servlet.ServletException: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.action.login.LoginAction.execute(LoginAction.java:219) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) java.lang.Exception: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.dao.GenericDAO.findOne(GenericDAO.java:204) at fr.company.dao.UserDAO.findOneUser(UserDAO.java:146) at fr.company.service.UserPeer.logUser(UserPeer.java:72) at fr.company.action.login.LoginAction.execute(LoginAction.java:127) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) Caused by: org.hibernate.exception.SQLGrammarException: could not execute query at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:65) at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43) at org.hibernate.loader.Loader.doList(Loader.java:2153) at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2029) at org.hibernate.loader.Loader.list(Loader.java:2024) at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:369) at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:300) at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:153) at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1128) at org.hibernate.impl.QueryImpl.list(QueryImpl.java:79) at org.hibernate.impl.AbstractQueryImpl.uniqueResult(AbstractQueryImpl.java:749) at fr.company.dao.GenericDAO.findOne(GenericDAO.java:198) ... 26 more Caused by: java.sql.SQLException: Unknown column 'user0_1_.poloSize' in 'field list' at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:2928) at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1571) at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:1666) at com.mysql.jdbc.Connection.execSQL(Connection.java:2994) at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:936) at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:1030) at com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.executeQuery(NewProxyPreparedStatement.java:76) at org.hibernate.jdbc.AbstractBatcher.getResultSet(AbstractBatcher.java:139) at org.hibernate.loader.Loader.getResultSet(Loader.java:1669) at org.hibernate.loader.Loader.doQuery(Loader.java:662) at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:224) at org.hibernate.loader.Loader.doList(Loader.java:2150) ... 35 more

    Read the article

  • cpan won't configure correctly on centos6, can't connect to internet

    - by dan
    I have Centos 6 setup and have installed perl-CPAN. When I run cpan it takes me through the setup and ends by telling me it can't connect to the internet and to enter a mirror. I enter a mirror, but it still can't install the package. What am I doing wrong? If you're accessing the net via proxies, you can specify them in the CPAN configuration or via environment variables. The variable in the $CPAN::Config takes precedence. <ftp_proxy> Your ftp_proxy? [] <http_proxy> Your http_proxy? [] <no_proxy> Your no_proxy? [] CPAN needs access to at least one CPAN mirror. As you did not allow me to connect to the internet you need to supply a valid CPAN URL now. Please enter the URL of your CPAN mirror CPAN needs access to at least one CPAN mirror. As you did not allow me to connect to the internet you need to supply a valid CPAN URL now. Please enter the URL of your CPAN mirror mirror.cc.columbia.edu::cpan Configuration does not allow connecting to the internet. Current set of CPAN URLs: mirror.cc.columbia.edu::cpan Enter another URL or RETURN to quit: [] New urllist mirror.cc.columbia.edu::cpan Please remember to call 'o conf commit' to make the config permanent! cpan shell -- CPAN exploration and modules installation (v1.9402) Enter 'h' for help. cpan[1]> install File::Stat CPAN: Storable loaded ok (v2.20) LWP not available Warning: no success downloading '/root/.cpan/sources/authors/01mailrc.txt.gz.tmp918'. Giving up on it. at /usr/share/perl5/CPAN/Index.pm line 225 ^CCaught SIGINT, trying to continue Warning: Cannot install File::Stat, don't know what it is. Try the command i /File::Stat/ to find objects with matching identifiers. cpan[2]>

    Read the article

  • Can't connect to computer via SBS2011 RWA

    - by sbrattla
    I've got an SBS 2011 Essentials server. Users a able to log on to Remote Web Access using their username and password. However, the trouble starts when a users attempts to log on remotely to his/her computer from the Remote Web Access website. When the user clicks on his/her computer (in the RWA website), the user is first presented with a window listing Publisher, Type, Remote Computer name and Gateway Server. Everything seems fine here, and the user clicks Connect. The user credentials are provided, and a connection is attempted. However, the logon attempt always fails with the message "The logon attempt failed". The logon attempt always generates three log events in the server log: EventId: 4672 - Special Logon EventId: 4624 - Logon EventId: 4634 - Logoff All events happens have the same timestamp. No events are logged on the client machine which the user attempts to log on to. Others have solved this by going to their IIS server and enable "Windows Authentication" for Rpc and RpcWithCert (in Default Web Site). However, this is in place on the server. I've also got RD CAPs and RD RAPs in place. As a side note; if i try to connect to any of the machines using the Remote Desktop Connection using the "Connect from anywhere" functionality - then things work flawlessly! In other words, the error only occurs when attempting to login to a computer via the Remote Web Access website. I've run out of ideas for how I can solve this (too many hours spent). Any ideas highly appreciated!

    Read the article

  • Can connect through Watchguard mobile VPN, but can't ping or access network drives

    - by johnnyb10
    We're having any issue in which some of our employess can no longer connect to our network drives when out of the office. We use Watchguard Mobile VPN (we have a Watchguard Firebox firewall) and the users are able to connect. That is, their status in the the VPN client says "Connected" and they have the correct IP address listed as the VPN Endpoint. The problem is, when they try to map drives, or even ping the IP address of a server on our network, it fails. Last week, we temporarily switched one of our Comcast modems to our backup DSL modem because the Comcast was accidentally shut off by Comcast, and the problem seemed to start around then. We've since switched back and the problem persists, so that doesn't seem to have been it (which makes sense). But we also made other changes at the time that might have thrown something off, although we feel like we've checked them all. Plus, some people can successfully connect to network drives through the VPN. Can someone please suggest some steps to help troubleshoot? We've checked the policies on our Watchguard box, and they seem fine. We've looked at the settings on the Mobile VPN client, but nothing seems like a probable cause. Thanks.

    Read the article

  • Unable to connect Xend with virt-manager

    - by Majid Azimi
    I have installed debian 6.0.1a. I have install all XEN stuff. including xen kernel, libvirtd, ... but when i want to connect xend, virt-manager shows me this: Verify that: A Xen host kernel was booted The Xen service has been started details: Unable to open connection to hypervisor URI 'xen:///': unable to connect to '/var/run/libvirt/libvirt-sock', libvirtd may need to be started: Permission denied Traceback (most recent call last): File "/usr/share/virt-manager/virtManager/connection.py", line 971, in _try_open None], flags) File "/usr/lib/python2.6/dist-packages/libvirt.py", line 111, in openAuth if ret is None:raise libvirtError('virConnectOpenAuth() failed') libvirtError: unable to connect to '/var/run/libvirt/libvirt-sock', libvirtd may need to be started: Permission denied here is uname output: Linux debian 2.6.32-5-xen-amd64 #1 SMP Tue Mar 8 00:01:30 UTC 2011 x86_64 GNU/Linux and also xend and libvirtd is runnig: root@debian:/home/mazimi# /etc/init.d/libvirt-bin status Checking status of libvirt management daemon: libvirtd running. root@debian:/home/mazimi# /etc/init.d/xend start Starting Xen daemons: xenstored xenconsoled xend. permissions for livbirt-sock: root@debian:/home/mazimi# ls -alih /var/run/libvirt/ total 12K 671017 drwxr-xr-x 3 root root 4.0K Apr 15 13:54 . 654083 drwxr-xr-x 18 root root 4.0K Apr 15 13:54 .. 670901 srwxrwx--- 1 root libvirt 0 Apr 15 13:54 libvirt-sock 670928 srwxrwxrwx 1 root libvirt 0 Apr 15 13:54 libvirt-sock-ro 670870 drwxr-xr-x 2 root root 4.0K Apr 15 02:34 qemu and also we have group named libvirt in /etc/group When running libvirtd with verbose mode it behaves kind of stange: root@debian:/var/log/libvirt# /usr/sbin/libvirtd --verbose 17:26:55.841: warning : qemudStartup:1832 : Unable to create cgroup for driver: No such device or address 17:26:56.128: warning : lxcStartup:1900 : Unable to create cgroup for driver: No such device or address and waits infinitely.

    Read the article

  • SQL Server 2008: Can't connect to remote server via management studio but can telnet in fine

    - by WarpKid
    Hi, I am in the process of trying to configure SQL Server 2008 to accept remote connections. I have been through all the documentation I can find and yet when I attempt to connect through management studio I get an error stating that the server could not be found. Interestingly I can connect through telnet to the remote server via the port that sql server is listening on. In the SQL Server logs I can see the connection attempt. So SQL Server is up and running and listening on the correct port - no firewall blocking it. It would appear that by default SQL Server is listening on port 50314 by default but management studio attempts to connect on port 1433.Weird. Server Management Studio = no dice. Anyone got any ideas? Server is set to allow remote connections - TCP IP is enabled, firewall is off. Thanks UPDATE FOR TO CLEAR THINGS UP A BIT We are seeing the connection attempt when we telnet in on port 50314 in the sql server logs. When we login through management studio we see it attempting connection on port 1433. There is no sign of this connection attempt in the logs.

    Read the article

< Previous Page | 266 267 268 269 270 271 272 273 274 275 276 277  | Next Page >