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  • Can't seem to get C TCP Server-Client Communications Right

    - by Zeesponge
    Ok i need some serious help here. I have to make a TCP Server Client. When the Client connects to server using a three stage handshake. AFterwards... while the Client is running in the terminal, the user enters linux shell commands like xinput list, ls -1, ect... something that uses standard output. The server accepts the commands and uses system() (in a fork() in an infinite loop) to run the commands and the standard output is redirected to the client, where the client prints out each line. Afterward the server sends a completion signal of "\377\n". In which the client goes back to the command prompt asking for a new command and closes its connection and exit()'s when inputting "quit". I know that you have to dup2() both the STDOUT_FILENO and STDERR_FILENO to the clients file descriptor {dup2(client_FD, STDOUT_FILENO). Everything works accept when it comes for the client to retrieve system()'s stdout and printing it out... all i get is a blank line with a blinking cursor (client waiting on stdin). I tried all kinds of different routes with no avail... If anyone can help out i would greatly appreciate it TCP SERVER CODE include #include <sys/socket.h> #include <stdio.h> #include <string.h> #include <netinet/in.h> #include <signal.h> #include <unistd.h> #include <stdlib.h> #include <errno.h> //Prototype void handle_client(int connect_fd); int main() { int server_sockfd, client_sockfd; socklen_t server_len, client_len; struct sockaddr_in server_address; struct sockaddr_in client_address; server_sockfd = socket(AF_INET, SOCK_STREAM, 0); server_address.sin_family = AF_INET; server_address.sin_addr.s_addr = htonl(INADDR_ANY); server_address.sin_port = htons(9734); server_len = sizeof(server_address); bind(server_sockfd, (struct sockaddr *)&server_address, server_len); /* Create a connection queue, ignore child exit details and wait for clients. */ listen(server_sockfd, 10); signal(SIGCHLD, SIG_IGN); while(1) { printf("server waiting\n"); client_len = sizeof(client_address); client_sockfd = accept(server_sockfd, (struct sockaddr *)&client_address, &client_len); if(fork() == 0) handle_client(client_sockfd); else close(client_sockfd); } } void handle_client(int connect_fd) { const char* remsh = "<remsh>\n"; const char* ready = "<ready>\n"; const char* ok = "<ok>\n"; const char* command = "<command>\n"; const char* complete = "<\377\n"; const char* shared_secret = "<shapoopi>\n"; static char server_msg[201]; static char client_msg[201]; static char commands[201]; int sys_return; //memset client_msg, server_msg, commands memset(&client_msg, 0, sizeof(client_msg)); memset(&server_msg, 0, sizeof(client_msg)); memset(&commands, 0, sizeof(commands)); //read remsh from client read(connect_fd, &client_msg, 200); //check remsh validity from client if(strcmp(client_msg, remsh) != 0) { errno++; perror("Error Establishing Handshake"); close(connect_fd); exit(1); } //memset client_msg memset(&client_msg, 0, sizeof(client_msg)); //write remsh to client write(connect_fd, remsh, strlen(remsh)); //read shared_secret from client read(connect_fd, &client_msg, 200); //check shared_secret validity from client if(strcmp(client_msg, shared_secret) != 0) { errno++; perror("Invalid Security Passphrase"); write(connect_fd, "no", 2); close(connect_fd); exit(1); } //memset client_msg memset(&client_msg, 0, sizeof(client_msg)); //write ok to client write(connect_fd, ok, strlen(ok)); // dup2 STDOUT_FILENO <= client fd, STDERR_FILENO <= client fd dup2(connect_fd, STDOUT_FILENO); dup2(connect_fd, STDERR_FILENO); //begin while... while read (client_msg) from server and >0 while(read(connect_fd, &client_msg, 200) > 0) { //check command validity from client if(strcmp(client_msg, command) != 0) { errno++; perror("Error, unable to retrieve data"); close(connect_fd); exit(1); } //memset client_msg memset(&client_msg, 0, sizeof(client_msg)); //write ready to client write(connect_fd, ready, strlen(ready)); //read commands from client read(connect_fd, &commands, 200); //run commands using system( ) sys_return = system(commands); //check success of system( ) if(sys_return < 0) { perror("Invalid Commands"); errno++; } //memset commands memset(commands, 0, sizeof(commands)); //write complete to client write(connect_fd, complete, sizeof(complete)); } } TCP CLIENT CODE #include <sys/types.h> #include <sys/socket.h> #include <stdio.h> #include <string.h> #include <netinet/in.h> #include <arpa/inet.h> #include <unistd.h> #include <stdlib.h> #include <errno.h> #include "readline.c" int main(int argc, char *argv[]) { int sockfd; int len; struct sockaddr_in address; int result; const char* remsh = "<remsh>\n"; const char* ready = "<ready>\n"; const char* ok = "<ok>\n"; const char* command = "<command>\n"; const char* complete = "<\377\n"; const char* shared_secret = "<shapoopi>\n"; static char server_msg[201]; static char client_msg[201]; memset(&client_msg, 0, sizeof(client_msg)); memset(&server_msg, 0, sizeof(server_msg)); /* Create a socket for the client. */ sockfd = socket(AF_INET, SOCK_STREAM, 0); /* Name the socket, as agreed with the server. */ memset(&address, 0, sizeof(address)); address.sin_family = AF_INET; address.sin_addr.s_addr = inet_addr(argv[1]); address.sin_port = htons(9734); len = sizeof(address); /* Now connect our socket to the server's socket. */ result = connect(sockfd, (struct sockaddr *)&address, len); if(result == -1) { perror("ACCESS DENIED"); exit(1); } //write remsh to server write(sockfd, remsh, strlen(remsh)); //read remsh from server read(sockfd, &server_msg, 200); //check remsh validity from server if(strcmp(server_msg, remsh) != 0) { errno++; perror("Error Establishing Initial Handshake"); close(sockfd); exit(1); } //memset server_msg memset(&server_msg, 0, sizeof(server_msg)); //write shared secret text to server write(sockfd, shared_secret, strlen(shared_secret)); //read ok from server read(sockfd, &server_msg, 200); //check ok velidity from server if(strcmp(server_msg, ok) != 0 ) { errno++; perror("Incorrect security phrase"); close(sockfd); exit(1); } //? dup2 STDIN_FILENO = server socket fd? //dup2(sockfd, STDIN_FILENO); //begin while(1)/////////////////////////////////////// while(1){ //memset both msg arrays memset(&client_msg, 0, sizeof(client_msg)); memset(&server_msg, 0, sizeof(server_msg)); //print Enter Command, scan input, fflush to stdout printf("<<Enter Command>> "); scanf("%s", client_msg); fflush(stdout); //check quit input, if true close and exit successfully if(strcmp(client_msg, "quit") == 0) { printf("Exiting\n"); close(sockfd); exit(EXIT_SUCCESS); } //write command to server write(sockfd, command, strlen(command)); //read ready from server read(sockfd, &server_msg, 200); //check ready validity from server if(strcmp(server_msg, ready) != 0) { errno++; perror("Failed Server Communications"); close(sockfd); exit(1); } //memset server_msg memset(&server_msg, 0, sizeof(server_msg)); //begin looping and retrieving from stdin, //break loop at EOF or complete while((read(sockfd, server_msg, 200) != 0) && (strcmp(server_msg, complete) != 0)) { //while((fgets(server_msg, 4096, stdin) != EOF) || (strcmp(server_msg, complete) == 0)) { printf("%s", server_msg); memset(&server_msg, 0, sizeof(server_msg)); } } }

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  • setting up freedns with an existing domain

    - by romeovs
    I've been running a webserver off of a pc at a static IP succesfully for the past 5 months. recently however, I've moved into another appartment and my ISP only provides a dynamic IP (my IP changes from time to time). I'm not an internet genius but I was thinking to fix this by using a Dynamic DNS provider. So I got on the web and found freedns. I'm a bit confused about how to set up everything though. I've managed to succesfully install the IP updater daemon on my web server. Then, in my registrars control panel, I set the NS records to point at ns1 through ns4.afraid.org (removing the old NS records). I'm not certain what I should do with the A records though (for now they are still pointing to the old static IP address). I have A records for www, blog, irc, etc. but I cannot point them at my new IP address, because it isn't Could someone explain this in the clearest possible sense (perhaps elaborating on what happens at each step of the DNS process). I never really knew what the A records are for anyway. (note that I haven't really found any documentation at the freedns website, or on google)

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  • Asynch a synchronous method with await async

    - by Sahil Malik
    SharePoint, WCF and Azure Trainings: more information Stock this in “bag of tricks”, but very frequently we run into APIs that do not offer Asynch methods.But between C# ‘s amazing set of features, and asynch await keywords, there is a lot you can do. For instance, consider this code - Read full article ....

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  • Making Money by Building a Portfolio of Established Websites

    There are many ways that you can use a website to make money. However, you will need to understand that not all of these methods will require of you to sell a certain product or service directly to the visitor on your site. In addition to this, you can make money from more than one site, instead of trying to make a lot of money from a single site.

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  • A little gem from MPN&ndash;FREE online course on Architectural Guidance for Migrating Applications to Windows Azure Platform

    - by Eric Nelson
    I know a lot of technical people who work in partners (ISVs, System Integrators etc). I know that virtually none of them would think of going to the Microsoft Partner Network (MPN) learning portal to find some deep and high quality technical content. Instead they would head to MSDN, Channel 9, msdev.com etc. I am one of those people :-) Hence imagine my surprise when i stumbled upon this little gem Architectural Guidance for Migrating Applications to Windows Azure Platform (your company and hence your live id need to be a member of MPN – which is free to join). This is first class stuff – and represents about 4 hours which is really 8 if you stop and ponder :) Course Structure The course is divided into eight modules.  Each module explores a different factor that needs to be considered as part of the migration process. Module 1:  Introduction:  This section provides an introduction to the training course, highlighting the values of the Windows Azure Platform for developers. Module 2:  Dynamic Environment: This section goes into detail about the dynamic environment of the Windows Azure Platform. This session will explain the difference between current development states and the Windows Azure Platform environment, detail the functions of roles, and highlight development considerations to be aware of when working with the Windows Azure Platform. Module 3:  Local State: This session details the local state of the Windows Azure Platform. This section details the different types of storage within the Windows Azure Platform (Blobs, Tables, Queues, and SQL Azure). The training will provide technical guidance on local storage usage, how to write to blobs, how to effectively use table storage, and other authorization methods. Module 4:  Latency and Timeouts: This session goes into detail explaining the considerations surrounding latency, timeouts and how to assess an IT portfolio. Module 5:  Transactions and Bandwidth: This session details the performance metrics surrounding transactions and bandwidth in the Windows Azure Platform environment. This session will detail the transactions and bandwidth costs involved with the Windows Azure Platform and mitigation techniques that can be used to properly manage those costs. Module 6:  Authentication and Authorization: This session details authentication and authorization protocols within the Windows Azure Platform. This session will detail information around web methods of authorization, web identification, Access Control Benefits, and a walkthrough of the Windows Identify Foundation. Module 7:  Data Sensitivity: This session details data considerations that users and developers will experience when placing data into the cloud. This section of the training highlights these concerns, and details the strategies that developers can take to increase the security of their data in the cloud. Module 8:  Summary Provides an overall review of the course.

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  • IPv6 routing to another interface

    - by Robert
    I'm trying to get an IPv6 enabled router to forward data from one interface to the other and I'm having issues. When following this example (http://www.cisco.com/en/US/tech/tk872/technologies_configuration_example09186a0080ba6106.shtml) I am able to get full connectivity between all 3 routers in my simulator. However when I try to use only 1 router; I can't get connectivity to the other interfacs on the same router. My PC is directly attached to FA 0/1 and it can ping the router's interface. However it can not ping any other interface on the router(which unless I'm missing something it should be able to do). The router on the other hand can ping everything. I thought static routes might help; but the router already has routes for everything. I'm thinking the packet should come in; router looks up the destination in it's ipv6 routing table and then realizes it's for itself, and should respond. I thought maybe it couldn't respond directly; so I tried pinging a device like 2001:0000:0000:1000::2, but i don't get a response. I'm running on IOS 12.4. I'm missing something(hopefully simple), but I just can't see what it is. With only 1 router; how do I enable my PC to talk to the other subnets? Thank you in advance, Robert Topology: R1 FA 0/0: 2001:0000:0000:0000::1/52 FA 0/1: 2001:0000:0000:1000::1/52 FA 1/0: 2001:0000:0000:2000::1/52 Loopback 0: 2001:0000:0000:3000::1/52 PC: 2001:0000:0000:2000::2/52 PC plugs directly into FA 1/0 on the router. --- Configuration --- ipv6 cef ipv6 unicast routing interface Loopback0 no ip address ipv6 address 2001:0000:0000:3000::1/52 ipv6 enable ! interface FastEthernet0/0 no ip address duplex auto speed auto ipv6 address 2001:0000:0000::1/52 ipv6 enable ! interface FastEthernet0/1 no ip address duplex auto speed auto ipv6 address 2001:0000:0000:1000::1/52 ipv6 enable ! interface FastEthernet1/0 no ip address duplex auto speed auto ipv6 address 2001:0000:0000:2000::1/52 ipv6 enable --- end of config --- --- routing table --- IPV6Lab#show ipv6 route IPv6 Routing Table - 10 entries Codes: C - Connected, L - Local, S - Static, R - RIP, B - BGP U - Per-user Static route I1 - ISIS L1, I2 - ISIS L2, IA - ISIS interarea, IS - ISIS summary O - OSPF intra, OI - OSPF inter, OE1 - OSPF ext 1, OE2 - OSPF ext 2 ON1 - OSPF NSSA ext 1, ON2 - OSPF NSSA ext 2 C 2001:0000:0000::/52 [0/0] via ::, FastEthernet0/0 L 2001:0000:0000::1/128 [0/0] via ::, FastEthernet0/0 C 2001:0000:0000:1000::/52 [0/0] via ::, FastEthernet0/1 L 2001:0000:0000:1000::1/128 [0/0] via ::, FastEthernet0/1 C 2001:0000:0000:2000::/52 [0/0] via ::, FastEthernet1/0 L 2001:0000:0000:2000::1/128 [0/0] via ::, FastEthernet1/0 C 2001:0000:0000:3000::/52 [0/0] via ::, Loopback0 L 2001:0000:0000:3000::1/128 [0/0] via ::, Loopback0 L FE80::/10 [0/0] via ::, Null0 L FF00::/8 [0/0] via ::, Null0 --- end of routing table ---

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  • Guidelines For Link Building

    If done well, link building can sky rocket your search engine page rank. Stick to natural simulation methods instead of opting for tempting shortcuts which can get your website blocked by search engines. Here are a set of guidelines that you should follow for link building:

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  • Validating User Input with ASP.NET 3.5

    In the first part of this three-part series explaining the basics of user input validation in ASP.NET 3.5 you were introduced to the concepts of user input validation and saw a sample configuration of the RequiredFieldValidator web controls. In this part you will learn about several types of input validation web controls and their methods of configuration.... Charter Business Bundle? Get High Speed Internet & Telephone for Only $99/Monthly. Limited-Time Offer!

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  • Configuring Linux Network

    - by Reiler
    Hi I'm working on some software, that runs on a Centos 5.xx installation. I'ts not allowed for our customers to log in to Linux, everything is done from Windows applications, developed by us. So we have build a frontend for the user to configure network setup: Static/DHCP, ip-address, gateway, DNS, Hostname. Right now I let the user enter the information in the Windows app, and then write it on the Linux server like this: Write to /etc/resolv.conf: Nameserver Write to /etc/sysconfig/network: Gateway and Hostname Write to /etc/sysconfig/network-scripts/ifcfg-eth0: Ipaddress, Netmask, Bootproto(DHCP or Static) I also (after some time) found out that I was unable to send mail, unless I wrote in /etc/hosts: 127.0.0.1 Hostname All this seems to work, but is there a better/easier way to do this? Also, I read the network configuration nearly the same way, but if I use DHCP, I miss som information, for instance the Ip-address. I know that I can get some information from the commandline (ifconfig), but I dont get for instance Hostname, Gateway and DNS. Is there a commandline tool that will display this?

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  • Is it OK to repeat code for unit tests?

    - by Pete
    I wrote some sorting algorithms for a class assignment and I also wrote a few tests to make sure the algorithms were implemented correctly. My tests are only like 10 lines long and there are 3 of them but only 1 line changes between the 3 so there is a lot of repeated code. Is it better to refactor this code into another method that is then called from each test? Wouldn't I then need to write another test to test the refactoring? Some of the variables can even be moved up to the class level. Should testing classes and methods follow the same rules as regular classes/methods? Here's an example: [TestMethod] public void MergeSortAssertArrayIsSorted() { int[] a = new int[1000]; Random rand = new Random(DateTime.Now.Millisecond); for(int i = 0; i < a.Length; i++) { a[i] = rand.Next(Int16.MaxValue); } int[] b = new int[1000]; a.CopyTo(b, 0); List<int> temp = b.ToList(); temp.Sort(); b = temp.ToArray(); MergeSort merge = new MergeSort(); merge.mergeSort(a, 0, a.Length - 1); CollectionAssert.AreEqual(a, b); } [TestMethod] public void InsertionSortAssertArrayIsSorted() { int[] a = new int[1000]; Random rand = new Random(DateTime.Now.Millisecond); for (int i = 0; i < a.Length; i++) { a[i] = rand.Next(Int16.MaxValue); } int[] b = new int[1000]; a.CopyTo(b, 0); List<int> temp = b.ToList(); temp.Sort(); b = temp.ToArray(); InsertionSort merge = new InsertionSort(); merge.insertionSort(a); CollectionAssert.AreEqual(a, b); }

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  • Using Dynamic LINQ to get a filter for my Web API

    - by Espo
    We are considering using the Dynamic.CS linq-sample included in the "Samples" directory of visual studio 2008 for our WebAPI project to allow clients to query our data. The interface would be something like this (In addition to the normal GET-methods): public HttpResponseMessage List(string filter = null); The plan is to use the dynamic library to parse the "filter"-variable and then execute the query agains the DB. Any thoughts if this is a good idea? Is it a security problem?

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  • Opt For the Expert Services of an SEO Consultant

    Targeted traffic is very essential for bringing in business to your online website. You must use the right tools and be aware of the right methods when you pursue an online venture. If you are looking for ways to increase targeted traffic to your website and increase your web presence you should resort to the services of a good SEO consultant.

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  • Hiding "Syntax OK" from apache2ctl output

    - by Oscar Barrett
    I am checking whether a particular apache module is installed using apache2ctl -M. When listing the modules, apache runs a syntax check on the configuration files which prints out "Syntax OK" if everything is fine. However, this message doesn't seem to be coming from STDOUT or STDERR as it shows even if all output is redirected to /dev/null. i.e. $ sudo apache2ctl -M Loaded Modules: core_module (static) log_config_module (static) ... Syntax OK $ sudo apache2ctl -M >/dev/null Syntax OK How is this being outputted, and is it possible to hide?

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  • How to have 2 windows machines on the same network with the same IP address

    - by Stu
    I have a custom made ADC device that is spitting out data by addressed UDP packets. I have that device plugged into a 4 port switch. I have one windows embedded standard 7 machine which is the normal recipient of that data. To be able to receive the data (Using LabVIEW) the windows network adapter IPv4 settings must have a static IP address that corresponds to the UDP packet destination. I would like to add a second windows machine (This one is just regular Win 7 Pro) to simultaneously catch the data, however with all devices connected to the switch, the Win 7 Pro machine recognizes an IP address conflict and will not take the setting for the required static IP address. (The network adaptor settings show that the correct value has been entered but ipconfig shows that it is not actually set.) Neither windows machine needs to transmit network data, they only need to be able to receive the UDP data from the ADC device. Is there any way to disable this IP address conflict detection 'feature' of windows networking?

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  • White Label SEO Service - Making Money Online

    The online world is gaining popularity day by day. Almost everything is possible sitting at home just at a click of a mouse. As a matter of fact, there are several methods or programs especially the ones involving selling SEO that have come up lately, which can help you make some good money online.

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  • How to get the blocks seen by the player?

    - by m4tx
    I'm writing a Minecraft-like game using Ogre engine and I have a problem. I must optimize my game, because when I try draw 10000 blocks, I have 2 FPS... So, I got the idea that blocks display of the plane and to hide the invisible blocks. But I have a problem - how do I know which blocks at a time are visible to the player? And - if you know of other optimization methods for such a game, write what and how to use them in Ogre.

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  • Can connect to WAN via PC but router doesnt.

    - by user16877
    I have a very strange problem regarding the office network. We are currenltly in a executive suite and when i connect to wan via ethernet cable i get dhcp assigned IP address in my network config. I hooked up the linksys router to the wall expecting it to receive all the necessary ip info but that didnt work. So we have been assigned static ip address to put in to our router later but even with the static ip router doesnt seem to connect to internet. But using the same ip address and assigning to laptop works. I m very puzzled what might be the cause of this so any help is really appreciated.

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  • How to install PyQt on Mac OS X 10.6

    - by Albert
    I want to install PyQt. This seems kind of complicated to install on OS X. I haven't found any precompiled packages of it (are there any? I would really prefer those). So I downloaded PyQt. And SIP, because it depends on that. These files: http://www.riverbankcomputing.co.uk/static/Downloads/PyQt4/PyQt-mac-gpl-4.7.3.tar.gz http://www.riverbankcomputing.co.uk/static/Downloads/sip4/sip-4.10.2.tar.gz Did a python configure.py && make && sudo make install on SIP -- installed without any problems. Tried the same on PyQt -- and failed of course: /Library/Frameworks/QtCore.framework/Headers/qglobal.h:288:2: error: #error "You are building a 64-bit application, but using a 32-bit version of Qt. Check your build configuration." Ok, so I tried with python configure.py --use-arch=i386. Same error. Any idea?

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  • how to use iptables to block the IP of device connected to openwrt router

    - by scola
    I have two routers(A,B).the A connect to internet with IP:192.168.1.1 The openwrt router B connect the lan of A by bridge with static IP:192.168.1.111. I am learning to use iptables to control the devices connected to B(wlan) . I use my phone to connect wifi of B,the phone's IP is IP:192.168.1.100.it can surf the internet normally. I want to block the phone's IP to make the phone can not connect to internet. refer to http://bredsaal.dk/some-small-iptables-on-openwrt-tips iptables -A input_wan -s 192.168.1.100 --jump REJECT iptables -A forwarding_rule -d 192.168.1.100 --jump REJECT but it do not work.the phone still connect to internet normally. and I tried other chain(INPUT,OUTPUT,FORWARD).so many chains confused me. iptables -I OUTPUT -o br-lan -s 192.168.1.100 -j DROP and it do not work again. I'm sure that the iptables have no problem. root@OpenWrt:/etc# iptables -L|grep Chain Chain INPUT (policy ACCEPT) Chain FORWARD (policy DROP) Chain OUTPUT (policy ACCEPT) Chain forward (1 references) Chain forwarding_lan (1 references) Chain forwarding_rule (1 references) Chain forwarding_wan (1 references) Chain input (1 references) Chain input_lan (1 references) Chain input_rule (1 references) Chain input_wan (1 references) Chain output (1 references) root@OpenWrt:/etc# ifconfig br-lan Link encap:Ethernet HWaddr 0C:82:68:97:57:BA inet addr:192.168.1.111 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::e82:68ff:fe97:57ba/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:14976 errors:0 dropped:0 overruns:0 frame:0 TX packets:7656 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:2851980 (2.7 MiB) TX bytes:1902785 (1.8 MiB) eth0 Link encap:Ethernet HWaddr 0C:82:68:97:57:BA UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:58201 errors:0 dropped:11 overruns:0 frame:0 TX packets:45012 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:54591348 (52.0 MiB) TX bytes:5711142 (5.4 MiB) Interrupt:4 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:312 errors:0 dropped:0 overruns:0 frame:0 TX packets:312 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:39961 (39.0 KiB) TX bytes:39961 (39.0 KiB) mon.wlan0 Link encap:UNSPEC HWaddr 0C-82-68-97-57-BA-00-48-00-00-00-00-00-00-00-00 UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:4900 errors:0 dropped:0 overruns:0 frame:0 TX packets:0 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:32 RX bytes:1223807 (1.1 MiB) TX bytes:0 (0.0 B) wlan0 Link encap:Ethernet HWaddr 0C:82:68:97:57:BA UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:37346 errors:0 dropped:0 overruns:0 frame:0 TX packets:49662 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:32 RX bytes:3808021 (3.6 MiB) TX bytes:54486310 (51.9 MiB) root@OpenWrt:/etc/config# cat network config 'interface' 'loopback' option 'ifname' 'lo' option 'proto' 'static' option 'ipaddr' '127.0.0.1' option 'netmask' '255.0.0.0' config 'interface' 'lan' option 'ifname' 'eth0' option 'type' 'bridge' option 'proto' 'static' option 'ipaddr' '192.168.1.111' option 'netmask' '255.255.255.0' option 'gateway' '192.168.1.1' option dns 192.168.1.1 and how to use iptables to control the network of wlan? Thanks in advance and sorry for poor English.

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  • SEO Secrets - Fighting Against the Domain Age Tide

    There are a whole range of tactics you can adopt to improve your rankings in the search engines. Using well researched and optimised keyword phrases and creating quality backlinks are the obvious methods. You do need to be aware of the age of your domain however and how that can effect your site's perceived trust rating in the search engines.

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  • Trying to get DNS services running on Windows Server 2008 R2, what am I getting wrong ?

    - by LaserBeak
    Ok, So I am basically trying to get a home server pc up that will provide Domain name services, act as Mail server and web server. I have one static IP, well it's not officially static but hasn't changed in two years so I'll call it static. I have done the following: Configured router NAT/virtual port forward UDP/TCP port 53 to the internal IP of my server 192.168.1.16, in adapter settings specified the manual settings: 192.168.1.16 IP, gateway 192.168.1.1, Subnet: 255.255.255.0 and loopback DNS: 127.0.0.1 Using my public my public IP Checked using http://www.canyouseeme.org/ that port 53 is open and is not being blocked by my ISP. It can see services on this port. Registered Domain name (mydomain.com.au) Updated whois database through the domain registrars site and registered NameServer names: ns0.mydomain.com.au and ns2.mydomain.com.au, both have been associated with my single public IP. (Waited 24 hours) Update the nameserver for mydomain.com.au: primary ns0.mydomain.com.au secondary: ns2.mydomain.com.au (waited 24+ hours) Installed Server 2008 R2, install web server role and DNS role. Webserver works when I enter my public IP into browser of any PC/mobile, get IIS7 welcome page. In DNS server: Created new forward lookup zone: ; ; Database file mydoman.com.au.dns for mydomain.com.au zone. ; Zone version: 10 ; @ IN SOA mydomain.com.au. mydomain.testdomain.com. ( 10 ; serial number 900 ; refresh 600 ; retry 86400 ; expire 3600 ) ; default TTL ; ; Zone NS records ; @ NS ns0.mydomain.com.au. @ NS ns1.mydomain.com.au. ; ; Zone records ; @ A 192.168.1.16 www A 192.168.1.16 The Domain name services will however not work, the whois database updated with ns0.mydomain.com.au etc. but when I type in my site name www.mydomain.com.au from an external machine it will not open site and I can't even ping it (Can't find host) When I check the ns0.mydomain.com.au NS record using a tool Like: http://www.squish.net/dnscheck/ I get: Security: Server ns0.mydomain.com.au (XXX.XXX.XXX.XX <- my public IP) is recursive Domain exists but there is no such record Any ideas, thanks...

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  • Recursion in F#

    - by MarkPearl
    Things are slowly coming together – I was able to look at a bit of F# code and intuitively know what it was going to do (yay)… So today I saw a blog post by Bob Palmer on Fibonacci numbers in F# which inspired me to look at bit into recursion. First the C# example… class Program { public static void CountDown(int n) { switch (n) { case 0: Console.WriteLine("End of Count"); break; default: Console.WriteLine(n); CountDown(n-1); break; } } static void Main(string[] args) { CountDown(10); Console.ReadLine(); } }   In F#, the equivalent would look something like this… open System let rec CountDown n = match n with | 0 -> Console.WriteLine("End of Count"); | n -> Console.WriteLine(n); CountDown (n-1); CountDown 10 Console.ReadLine()   Pretty simple stuff. With F# you when making recursive calls you need to explicitly declare that the function is recursive with the “rec” keyword. Otherwise the code is pretty easy to read and self explanatory.

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  • Hierarchies in SQL, Part II, the Sequel

    In a followup to his first article on Hierarchies, Gus Gwynn takes a look at the performance of a few different methods of querying a hierarchy. Learn how the HierarchyID stacks up. Are you sure you can restore your backups? Run full restore + DBCC CHECKDB quickly and easily with SQL Backup Pro's new automated verification. Check for corruption and prepare for when disaster strikes. Try it now.

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  • why are my players drawn top the side of my viewport

    - by Jetbuster
    Following this admittedly brilliant and clean 2d camera class I have a camera on each player, and it works for multiplayer and i've divided the screen into two sections for split screen by giving each camera a viewport. However in the game it looks like this I'm not sure if thats their position relative to the screen or what The relevant gameScreen code, the makePlayers is setup so it could theoretically work for up to 4 players private void makePlayers() { int rowCount = 1; if (NumberOfPlayers > 2) rowCount = 2; players = new Player[NumberOfPlayers]; for (int i = 0; i < players.Length; i++) { int xSize = GameRef.Window.ClientBounds.Width / 2; int ySize = GameRef.Window.ClientBounds.Height / rowCount; int col = i % rowCount; int row = i / rowCount; int xPoint = 0 + xSize * row; int yPoint = 0 + ySize * col; Viewport viewport = new Viewport(xPoint, yPoint, xSize, ySize); Vector2 playerPosition = new Vector2(viewport.TitleSafeArea.X + viewport.TitleSafeArea.Width / 2, viewport.TitleSafeArea.Y + viewport.TitleSafeArea.Height / 2); players[i] = new Player(playerPosition, playerSprites[i], GameRef, viewport); } //players[1].Keyboard = true; } public override void Draw(GameTime gameTime) { base.Draw(gameTime); foreach (Player player in players) { GraphicsDevice.Viewport = player.PlayerCamera.ViewPort; GameRef.spriteBatch.Begin(SpriteSortMode.Immediate, BlendState.AlphaBlend, SamplerState.PointClamp, null, null, null, player.PlayerCamera.Transform); map.Draw(GameRef.spriteBatch); // Draw the Player player.Draw(GameRef.spriteBatch); // Draw UI screen elements GraphicsDevice.Viewport = Viewport; ControlManager.Draw(GameRef.spriteBatch); GameRef.spriteBatch.End(); } } the player's initialize and draw methods are like so internal void Initialize() { this.score = 0; this.angle = (float)(Math.PI * 0 / 180);//Start sprite at it's default rotation int width = utils.scaleInt(picture.Width, imageScale); int height = utils.scaleInt(picture.Height, imageScale); this.hitBox = new HitBox(new Vector2(centerPos.X - width / 2, centerPos.Y - height / 2), width, height, Color.Black, game.Window.ClientBounds); playerCamera.Initialize(); } #region Methods public void Draw(SpriteBatch spriteBatch) { //Console.WriteLine("Hitbox: X({0}),Y({1})", hitBox.Points[0].X, hitBox.Points[0].Y); //Console.WriteLine("Image: X({0}),Y({1})", centerPos.X, centerPos.Y); Vector2 orgin = new Vector2(picture.Width / 2, picture.Height / 2); hitBox.Draw(spriteBatch); utils.DrawCrosshair(spriteBatch, Position, game.Window.ClientBounds, Color.Red); spriteBatch.Draw(picture, Position, null, Color.White, angle, orgin, imageScale, SpriteEffects.None, 0.1f); } as I said I think I'm gonna need to do something with the render position but I'm to entirely sure what or how it would be elegant to say the least

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  • C# TextBox

    A TextBox control accepts user input on a Form. In this article, I will discuss how to create a TextBox control in Windows Forms at design-time as well as run-time. After that, I will continue discussing various properties and methods available for the TextBox control.

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