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  • I want to read a big text file

    - by Rozer
    I want to read a big text file, what i decided to create four threads and read 25% of file by each one. and then join them. but its not more impressive. can any one tell me can i use concurrent programming for the same. as my file structure have some data as name contact compnay policyname policynumber uniqueno and I want to put all data in hashmap at last. thanks

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  • "Ambiguous column name" error on one particular server

    - by jazbit
    This simple query throws the "Ambiguous column name TaskID" error on one db-server only. This is ridiculous. We tested this with the same database structure on different servers and different versions of ms sql (2005/2008), and it's only THIS particular client's server that throws the error. I'm actually frustrated. SELECT Tasks.TaskID FROM Tasks INNER JOIN TaskHelpers ON TaskHelpers.TaskID = Tasks.TaskID order by TaskID Yes, I know I can put "Tasks.TaskID" into the order by clause, but for some reasons I can't.

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  • Why can't I SELECT a parent field that doesn't have a child?

    - by myaccount
    (rest_branches) is the table of restaurants. (phone_numbers) is another table which contains the restaurants phone_numbers, and it has a field called (branch_id) which references the restaurant id. When I try: SELECT * FROM rest_branches NATURAL JOIN phone_numbers I only get the restaurants which have a phone_number. What should I do to get all restaurants even if they don't have a phone number?

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  • mysql extra columns with same name from two tables

    - by salmane
    Table 1 has columns : entry_id user_id ... Table 2 has columns : entry_id user_id ... the user_id entry is not always the same so I would like to extract both of them so I can later on compare them in my script SELECT * FROM table1 as t1 INNER JOIN table2 as t2 on t1.entry_id=t2.entry_id WHERE t1.user_id='%s' I would like to extract t1.user_id and t2.user_id ...the problem is the result array has only user_id thank you

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  • help with sql query - in access 2007

    - by Gold
    hi i have 2 tables table items has 144602 records table A has 27721 records code in items = BAR8 in A i want to show all records that equal i try this: SELECT Items.Code, A.BAR8 FROM Items INNER JOIN A ON Items.Code = A.BAR8; and i get 28048 records !!! i need to get 27721 , how to do it ? thank's in advance

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  • difference between where and nested queries

    - by Chris H
    I'm not able to figure out the difference between these queries. I'm pretty sure that the first one is an equi-join. I'm not sure how the second one ISN'T the same as the first. The sub query in #2 selects all Ids from S, and then it returns all R's that also have those ID's, no? SELECT R.cname FROM R, S, WHERE R.Id = S.Id SELECT R.cname FROM R WHERE R.Id IN (SELECT S.Id FROM S)

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  • What would be better, (1 database + 4 tables) or (2 databases + 2 tables each) ?

    - by griseldas
    Hi there, I would like to be advised on what would be better (in regards to performance) A) 1 DATABASE with 4 tables or B) 2 DATABASES (same server), each with 2 tables. The tables size and usage are more or less similar, so the 2 tables on Database 1 would be similar usage/size to the 2 tables on database 2 The tables could have +500,000 records and the 2 tables on each database are not related (no join queries etc between them) Thanks in advance for your comments

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  • Firebird 2.1 + EXISTS = query bug?

    - by Atlas
    Using Delphi 2009 + Firebird 2.1.3. Database is ODS 11.1, default char set is UTF8. My prepared query is as follows: SELECT a.po_id, a.po_no FROM purchase_order a WHERE EXISTS (SELECT 1 FROM sales_order_item z1 JOIN purchase_order_item z2 ON z2.so_item_id = z1.so_item_id AND z2.po_id = a.po_id WHERE z1.so_id = :soid) ORDER BY a.po_no Now when I loop this say 1000 times because I have 1000 x so_id, the CPU usage get at 100% for FBSERVER.EXE Anyone encountered this problem?

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  • Django. Invalid keyword argument for this function. ManyToMany

    - by sagem_tetra
    I have this error: 'people' is an invalid keyword argument for this function class Passage(models.Model): name= models.CharField(max_length = 255) who = models.ForeignKey(UserProfil) class UserPassage(models.Model): passage = models.ForeignKey(Passage) people = models.ManyToManyField(UserProfil, null=True) class UserProfil(models.Model): user = models.OneToOneField(User) name = models.CharField(max_length=50) I try: def join(request): user = request.user user_profil = UserProfil.objects.get(user=user) passage = Passage.objects.get(id=2) #line with error up = UserPassage.objects.create(people= user_profil, passage=passage) return render_to_response('thanks.html') How to do correctly? Thanks!

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  • Sql string adding problem

    - by Woland
    SELECT a.one + ' test ' +b.two from table1 a right join table1 on a.id =b.id The problem is that when one is null then it the whole string is null, is there some kind of trick to bypass this problem msSQL 2005

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  • Using Joins vs Entity associations

    - by shivesh
    I am learning Entity framework and linq-to-entities. It's possible to get cross values from multiple tables using JOINS (join keyword) or using the navigation fields ( associations) in which case the framework knows how to reference the cross data. My question is what to use when?

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  • Set the right two characters (if there are any) to capitals?

    - by Hyflex
    Below is my data: Data Here 94/452O Data more 94/4522i Data bla 94/111 Data bla 94/459es Data bla 94/444 items is automatically generated by some previous code but it could come out like: items = ["Data Here 94/452O", "Data more 94/4522i", "Data bla 94/111", "Data bla 94/459es", "Data bla 94/444"] Now currently I'm appending the following: "\n".join(items).replace("4ke", "9") with a few other .replaces however I want it to replace/change the characters on the end of the numbers with a capital letter instead of lowercase... Output: Data Here 94/452O Data more 94/4522I Data bla 94/111 Data bla 94/459ES Data bla 94/444

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  • MYSQL - Query to check against other table (hard to explain...)

    - by Sam
    I have a query that gets a list of emails who have subscribed for a newsletter trial which lasts 30 days.. $thirty = time() - 3024000; SELECT c.email FROM tbl_clients AS c JOIN tbl_clientoptions AS o ON o.client = c.id WHERE o.option = 'newsletter' AND c.datecreated $thirty What I want to do is do a check in that same query so it also returns clients OVER 30 days old if they have the tbl_clientoptions.option = 'trialoverride' (ie; a row in the client options table with the value "trialoverride") basic columns are: TBL_CLIENTS id,name,email,datecreated TBL_CLIENTOPTIONS id,client,option

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  • PHP MySQL query help

    - by user547794
    Hello, I am trying to use this query to return every instance where the variable $d['userID'] is equal to the User ID in a separate table, and then echo the username tied to that user ID. Here's what I have so far: $uid = $d['userID']; $result = mysql_query("SELECT u.username FROM users u LEFT JOIN comments c ON c.userID = u.id WHERE u.id = $uid;")$row = mysql_fetch_assoc($result); echo $row['username'];

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  • Selecting count(*) while checking for a value in the results

    - by Rob
    SELECT COUNT(*) as Count, IF(sch.HomeTeamID = 34,true,false) AS Hawaii FROM schedule sch JOIN schools s ON s.ID = 83 WHERE (sch.HomeTeamID = 83 OR sch.AwayTeamID = 83) AND sch.SeasonID = 4 I'm trying to use count() to simplify my result but also include a field that represents wether any of the results' specific column contained a certain value. Is this possible? I'd basically like a row response with all the info I need.

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  • What is the best way to find the period of a (repeating) list in Mathematica?

    - by Arnoud Buzing
    What is the best way to find the period in a repeating list? For example: a = {4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2} has repeat {4, 5, 1, 2, 3} with the remainder {4, 5, 1, 2} matching, but being incomplete. The algorithm should be fast enough to handle longer cases, like so: b = RandomInteger[10000, {100}]; a = Join[b, b, b, b, Take[b, 27]] The algorithm should return $Failed if there is no repeating pattern like above.

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  • Website Design Templates

    - by user347834
    I am looking fr someone to make me two website templates for my site for free. Here is a quick design of what I want:(Took me 2 minutes in Paint) http:/ /i50.tinypic.com/33p9aut.jpg (You have to push backspace on the first link to join up the http:/ and the other /)and http://i50.tinypic.com/2qmogoo.jpg Email me at [email protected] or [email protected] for more information

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  • Get top rated item using AVG mysql

    - by user1876234
    I want to find top rated item using AVG function in mysql, right now my query looks like this: SELECT a.title, AVG(d.rating) as rating FROM in8ku_content a JOIN in8ku_content_ratings d ON a.id = d.article_id ORDER BY rating DESC Problem is that it takes AVG of all items and the result is not accurate, what should be changed here to get correct result ? Tables: in8ku_content [id, title] in8ku_content_ratings [id, article_id, rating]

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  • MySQL 'user_id' in where clause is ambiguous problem

    - by HoMe
    How can I correct the problem I keep getting from the code below which states 'user_id' in where clause is ambiguous. Thanks for the help in advance. Here is the mysql table. SELECT user.*, user_info.* FROM user INNER JOIN user_info ON user.user_id = user_info.user_id WHERE user_id='$user_id'

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