Search Results

Search found 33911 results on 1357 pages for 'mysql select'.

Page 276/1357 | < Previous Page | 272 273 274 275 276 277 278 279 280 281 282 283  | Next Page >

  • How do I create a timed ban on an account? (PHP/mysql)

    - by ggfan
    I want to create a function that allows me to ban an account for 10days. In the dbc, I have a field called "ban" and Boolean of 1=notban, 0=ban. I also have a field called "date_banned" which is just the timestamp of when the user got banned. My question is how do I create a time frame of 10days from the date the user was banned? ex: James was banned on "2010-05-03 20:43:48". So how can I go about adding 10days to the timestamp? And after 10days, it would set the "ban" equal to 1(which is not banned).

    Read the article

  • How to create wordpress-like option table and get values for each row? (PHP-MySQL)

    - by Nacho
    Hi guys. I'm looking to create an options table in my db that makes every record a system option, so i can work with a little number of fields. my db has the following structure: 3 columns named id, name, and value following data is inserted as an example -- id - name - value 1 - uri - www.example.com 2 - sitename - Working it out 3 - base_folder - /folder1/folder2/ 4 - slogan - Just a slogan for the site -- that way i can include a large number of customizable system options very easily the problem is that i don't know how to retrieve them how do i get the value of uri and store it as a var? and better yet, how do i get, for exmaple, values of id 1 and 4 only without making a query each time? (i assume multiple queries are useless and a pretty ugly method) i know the question is pretty basic but i'm lost here. i'd really appreciate your answer! Thanks in advance

    Read the article

  • Removing rows from MySQL table where the timestamp is over one day old?

    - by Rob
    I found the exact same question here. But it isn't working for me. I've modified it a bit, manipulated it, and I can't figure it out. I'm trying to remove rows that are over a day old. Here is my code: if (isset($_POST['prune'])) { $sql = "DELETE FROM logs WHERE time < date('now', '-1 days')"; mysql_query($sql); echo 'Logs older than one day removed.'; } Fairly simple question I suppose, but its bugging the hell out of me. I would appreciate any help. In case it makes a difference, the column is a TIMESTAMP type.

    Read the article

  • Please help me out in fetching the desired result from below given DB table structure of MySQL..

    - by OM The Eternity
    Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

    Read the article

  • Is there a way to combine these 3 tables? (mysql)

    - by ggfan
    I'm creating a "flagged" func that flags users, postings, and comments. I am currently using three tables: "flagged_users" "flagged_postings" and "flagged_comments". And in each table, there's: flagged_id, user_id/posting_id/comment_id, reason. Is there a way to combine into just one table? or is 3 tables the best?

    Read the article

  • Converting a list into a select with jquery

    - by Davemof
    I'm trying to convert the following list into a select list so it can be submitted via a form - the element within the lists will become the value of each option: <ul class="selected connected-list ui-sortable" style="height: 279px;"> <li class="ui-helper-hidden-accessible" style=""></li> <li title="Owner Name 1 - " class="ui-state-default ui-element ui-draggable" style="display: block; position: relative; top: 0px; left: 0px;"><span class="ui-icon-arrowthick-2-n-s ui-icon"></span>Owner Name 1 - <em class="thenumber">4.4796E+11</em><a class="action" href="#"><span class="ui-corner-all ui-icon ui-icon-minus"></span></a></li> <li title="David Moffat - " class="ui-state-default ui-element" style="display: block; position: relative; top: 0px; left: 0px;"><span class="ui-icon ui-icon-arrowthick-2-n-s"></span>David Moffat - <em class="thenumber">07730423005</em><a class="action" href="#"><span class="ui-corner-all ui-icon ui-icon-minus"></span></a></li> </ul> This should convert to the following format: <select style="display:none" class="selectoption" name="p_num[]" multiple="multiple"> <option value="">4.4796E+11</option> <option value="">07730423007</option> </select> I have tried the following jquery code, but after many hours I'm pulling my hair out: $('a.sendform').click(function(){ $('ul.selected').each(function() { var $select = $('<select />'); $(this).find('li').each(function() { var $option = $('<option />'); $option.attr('value', $(this).('em')).html($(this).html()); $select.append($option); }); $(this).replaceWith($select); }); }); Any help might save my remaining hair. Many thanks David

    Read the article

  • how to split data using mysql [closed]

    - by user75238
    I want to display images on left side and right side on my website. For example in this code I have 8 images and I want to split them 4 on the left side and 4 on the right side. In between them I want to put text. How can I do this? $display_image2=mysql_query("select id_topic,topic_title,image2 from topics where image2 not like '' order by id_topic desc limit 8")or die (mysql_error()); This is an image clarify what I want to do: http://oi50.tinypic.com/wsok1t.jpg

    Read the article

  • What is causing a Hibernate SQL query exception?

    - by Dark Star1
    Hi all and sorry in advance for this post but I've spent way too much time going around in circles so I'm hoping someone could shed a light on it here for me. I updated a webapp on Tomcat and I'm getting the following error which didn't exist on the previous version. Though I am quite confident that the part of code I modifed isn't to blame as I have tested the app on two different dev servers. The production server is configured thus: CentOS 5.4 virtual server with tomcat 5.5.23 running mysql 5.0.77. The two dev servers are: Windows XP SP2 running tomcat 5.5.23 with mysql 5.1.49 Mac OSX 10.6.6 Running tomcat 6 with mysql 5.1.51 The application was developed using struts (1.1 as far as I can gather) with hibernate 3 as the peristence layer. It only fails on the production server for some reason I can't fathom. I'd like to draw your attention to the java.sql.SQLException near the bottom. After some long searching I found this but because it was posted years ago (about 1 year before development started on this app I'm sure Hibernate has evolved from that version. as I can't find a way of implementing his solution. I use Eclipse Helios as an IDE. Thanks in advance for taking your time to read this, to all who manage to reply. javax.servlet.ServletException: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.action.login.LoginAction.execute(LoginAction.java:219) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) javax.servlet.ServletException: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.action.login.LoginAction.execute(LoginAction.java:219) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) java.lang.Exception: org.hibernate.exception.SQLGrammarException: could not execute query at fr.company.dao.GenericDAO.findOne(GenericDAO.java:204) at fr.company.dao.UserDAO.findOneUser(UserDAO.java:146) at fr.company.service.UserPeer.logUser(UserPeer.java:72) at fr.company.action.login.LoginAction.execute(LoginAction.java:127) at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:484) at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:274) at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482) at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at fr.company.util.EncodingFilter.doFilter(EncodingFilter.java:37) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:525) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:875) at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665) at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528) at org.apache.tomcat.util.net.MasterSlaveWorkerThread.run(MasterSlaveWorkerThread.java:113) at java.lang.Thread.run(Thread.java:636) Caused by: org.hibernate.exception.SQLGrammarException: could not execute query at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:65) at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43) at org.hibernate.loader.Loader.doList(Loader.java:2153) at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2029) at org.hibernate.loader.Loader.list(Loader.java:2024) at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:369) at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:300) at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:153) at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1128) at org.hibernate.impl.QueryImpl.list(QueryImpl.java:79) at org.hibernate.impl.AbstractQueryImpl.uniqueResult(AbstractQueryImpl.java:749) at fr.company.dao.GenericDAO.findOne(GenericDAO.java:198) ... 26 more Caused by: java.sql.SQLException: Unknown column 'user0_1_.poloSize' in 'field list' at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:2928) at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1571) at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:1666) at com.mysql.jdbc.Connection.execSQL(Connection.java:2994) at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:936) at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:1030) at com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.executeQuery(NewProxyPreparedStatement.java:76) at org.hibernate.jdbc.AbstractBatcher.getResultSet(AbstractBatcher.java:139) at org.hibernate.loader.Loader.getResultSet(Loader.java:1669) at org.hibernate.loader.Loader.doQuery(Loader.java:662) at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:224) at org.hibernate.loader.Loader.doList(Loader.java:2150) ... 35 more

    Read the article

  • Postfixadmin Invalid Query

    - by Jm Cruz
    This is my first time running a postfixadmin, so in my setup.php, I'm getting this error DEBUG INFORMATION: Invalid query: Unknown column 'create_date' in 'mailbox' I'm running it with MySQL. So if i'm right, my guess is that i need to create a column? under mailbox table on the postfix database? but how or whats the right syntax into creating a timedate column? My knowledge with mysql and postfix are very minimal btw. Thanks in advance.

    Read the article

  • What email server should I choose?

    - by DCC
    I need a secure email server installed in debian-lenny with users in a mysql table. Also users are from multiple domains. Quota should be in mysql or a global variable for all users. What are my options ? THanks in advance for your help.

    Read the article

  • HAProxy + Percona XtraDB Cluster

    - by rottmanj
    I am attempting to setup HAproxy in conjunction with Percona XtraDB Cluster on a series of 3 EC2 instances. I have found a few tutorials online dealing with this specific issue, but I am a bit stuck. Both the Percona servers and the HAproxy servers are running ubuntu 12.04. The HAProxy version is 1.4.18, When I start HAProxy I get the following error: Server pxc-back/db01 is DOWN, reason: Socket error, check duration: 2ms. I am not really sure what the issue could be. I have verified the following: EC2 security groups ports are open Poured over my config files looking for issues. I currently do not see any. Ensured that xinetd was installed Ensured that I am using the correct ip address of the mysql server. Any help with this is greatly appreciated. Here are my current config Load Balancer /etc/haproxy/haproxy.cfg global log 127.0.0.1 local0 log 127.0.0.1 local1 notice maxconn 4096 user haproxy group haproxy debug #quiet daemon defaults log global mode http option tcplog option dontlognull retries 3 option redispatch maxconn 2000 contimeout 5000 clitimeout 50000 srvtimeout 50000 frontend pxc-front bind 0.0.0.0:3307 mode tcp default_backend pxc-back frontend stats-front bind 0.0.0.0:22002 mode http default_backend stats-back backend pxc-back mode tcp balance leastconn option httpchk server db01 10.86.154.105:3306 check port 9200 inter 12000 rise 3 fall 3 backend stats-back mode http balance roundrobin stats uri /haproxy/stats MySql Server /etc/xinetd.d/mysqlchk # default: on # description: mysqlchk service mysqlchk { # this is a config for xinetd, place it in /etc/xinetd.d/ disable = no flags = REUSE socket_type = stream port = 9200 wait = no user = nobody server = /usr/bin/clustercheck log_on_failure += USERID #only_from = 0.0.0.0/0 # recommended to put the IPs that need # to connect exclusively (security purposes) per_source = UNLIMITED } MySql Server /etc/services Added the line mysqlchk 9200/tcp # mysqlchk MySql Server /usr/bin/clustercheck # GNU nano 2.2.6 File: /usr/bin/clustercheck #!/bin/bash # # Script to make a proxy (ie HAProxy) capable of monitoring Percona XtraDB Cluster nodes properly # # Author: Olaf van Zandwijk <[email protected]> # Documentation and download: https://github.com/olafz/percona-clustercheck # # Based on the original script from Unai Rodriguez # MYSQL_USERNAME="testuser" MYSQL_PASSWORD="" ERR_FILE="/dev/null" AVAILABLE_WHEN_DONOR=0 # # Perform the query to check the wsrep_local_state # WSREP_STATUS=`mysql --user=${MYSQL_USERNAME} --password=${MYSQL_PASSWORD} -e "SHOW STATUS LIKE 'wsrep_local_state';" 2>${ERR_FILE} | awk '{if (NR!=1){print $2}}' 2>${ERR_FILE}` if [[ "${WSREP_STATUS}" == "4" ]] || [[ "${WSREP_STATUS}" == "2" && ${AVAILABLE_WHEN_DONOR} == 1 ]] then # Percona XtraDB Cluster node local state is 'Synced' => return HTTP 200 /bin/echo -en "HTTP/1.1 200 OK\r\n" /bin/echo -en "Content-Type: text/plain\r\n" /bin/echo -en "\r\n" /bin/echo -en "Percona XtraDB Cluster Node is synced.\r\n" /bin/echo -en "\r\n" else # Percona XtraDB Cluster node local state is not 'Synced' => return HTTP 503 /bin/echo -en "HTTP/1.1 503 Service Unavailable\r\n" /bin/echo -en "Content-Type: text/plain\r\n" /bin/echo -en "\r\n" /bin/echo -en "Percona XtraDB Cluster Node is not synced.\r\n" /bin/echo -en "\r\n" fi

    Read the article

  • mysqld_multi stop doesn't seem to work

    - by gravyface
    mysqld_multi stop 1 followed by (repeatedly, a few moments later) mysqld_multi report 1 returns: Reporting MySQL servers MySQL server from group: mysqld1 is running The instances work fine and when I reboot, I have to start the instances to get them to come back up (a separate issue I need to resolve), but the stop command doesn't seem to do anything. It truly doesn't stop the instance because in the instance log file I see this: 120619 11:12:39 mysqld_safe A mysqld process already exists after trying to run start after.

    Read the article

  • 'ALTER table' for all tables in a database

    - by BassKozz
    How can I run the following for every table in a database: ALTER table [table_name] type=innodb; I don't want to have to manually run it for each table, but rather run it for all tables in a database. As an aside: If your curious as to why I am running this: http://bugs.mysql.com/bug.php?id=1341 & http://bugs.mysql.com/bug.php?id=1287

    Read the article

  • Secure LAMP server for production use

    - by WalterJ89
    What is the procedure for securing a Linux, Apache, MySQL, PHP Server (or even Perl) for production use? Other than setting the MySql password and the root password for linux what other (maybe not so obvious) steps should be taken? Also what steps can I take if I was going to be extra paranoid that may not normally be nessasary? this is for a basic single site use but must be secure. Thank you. (sorry if this was asked before)

    Read the article

  • All password with '$' inside (phpmyadmin) won't work [UTF-8 problem]

    - by Tristan
    Hello, i set up a dedicaced server with a tutorial. I set in PHP : mbstring.language=UTF-8 mbstring.internal_encoding=UTF-8 mbstring.http_input=UTF-8 mbstring.http_output=UTF-8 mbstring.detect_order=auto But each time there is a $ in the password (i have one for the root of mysql + other script) the password won't work. For example, I just removed the $ in the password for a script, and it worked. When i connect @root on mysql via phpmyadmin : don't work When i connect @root via PHP : works What can i do for this problem please ?

    Read the article

  • phpmyadmin import database table from google spreadsheet

    - by phunehehe
    I'm managing a small website, which allows people to register as members. Previously I used a google form to manage member registration, but now as the number of users becomes quite big I am switching to mysql. Currently I have around 500 members in the database, saved in a google spreadsheet. How can I do a bulk import from a google spreadsheet to a table in mysql? BTW I'm using phpmyadmin, so a solution for phpmyadmin is preferable :) Thanks.

    Read the article

  • migrating innodb ib* files to different server and distribution.

    - by 3molo
    One of our customers had a break in on an old centos 4.4 machine, so I booted a debian live cd and copied the whole /var/lib/mysql. I then, on a new debian, copied the desired database and ibdata+iblogfiles, and removed the "autoextend" bits from my.cnf - restarted mysql. But I get 'Incorrect information in file'. Paths are the same as the old centos server, and permissions and ownership is correct. What am I missing?

    Read the article

< Previous Page | 272 273 274 275 276 277 278 279 280 281 282 283  | Next Page >