Resolve bash variable containted in another variable
- by kogut
I have code like that:
TEXT_TO_FILTER='I would like to replace this $var to proper value'
var=variable
All I want to get is:
TEXT_AFTER_FILTERED="I'd like to replace this variable to proper value"
So I did:
TEXT_AFTER_FILTERED=`eval echo $TEXT_TO_FILTER`
TEXT_AFTER_FILTERED=`eval echo $(eval echo $TEXT_TO_FILTER)`
Or even more weirder things, but without any effects.
I remember that someday I had similar problem and I did something like that:
cat << EOF > tmp.sh
echo $TEXT_TO_FILTER
EOF
chmod +x tmp.sh
TEXT_AFTER_FILTERED=`. tmp.sh`
But this solution seems to be to much complex.
Have any of You heard about easier solution?
