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  • PHP/MySQL allowing current user to edit there account information

    - by user1837896
    i have created 2 pages update.php edit.php we start on edit.php so here is edit.php's script <?php session_start(); $id = $_SESSION["id"]; $username = $_POST["username"]; $fname = $_POST["fname"]; $password = $_POST["password"]; $email = $_POST["email"]; mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); echo "MySQL Connection Established! <br>"; mysql_select_db("a2670376_Pass") or die(mysql_error()); echo "Database Found! <br>"; $query = "UPDATE members SET username = '$username', fname = '$fname', password = '$password' WHERE id = '$id'"; $res = mysql_query($query); if ($res) echo "<p>Record Updated<p>"; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> <form action="update.php" method="post"> <input type="hidden" name="id" value="<?=$id;?>"> ScreenName:<br> <input type='text' name='username' id='username' maxlength='25' style='width:247px' name="username" value="<?=$username;?>"/><br> FullName:<br> <input type='text' name='fname' id='fname' maxlength='20' style='width:248px' name="ud_img" value="<?=$fname;?>"/><br> Email:<br> <input type='text' name='email' id='email' maxlength='50' style='width:250px' name="ud_img" value="<?=$email;?>"/><br> Password:<br> <input type='text' name='password' id='password' maxlength='25' style='width:251px' value="<?=$password;?>"/><br> <input type="Submit"> </form> now here is the update.php page where i am having the MAJOR problem <?php session_start(); mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); mysql_select_db("a2670376_Pass") or die(mysql_error()); $id = (int)$_SESSION["id"]; $username = mysql_real_escape_string($_POST["username"]); $fname = mysql_real_escape_string($_POST["fname"]); $email = mysql_real_escape_string($_POST["email"]); $password = mysql_real_escape_string($_POST["password"]); $query="UPDATE members SET username = '$username', fname = '$fname', email = '$email', password = '$password' WHERE id='$id'"; mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ echo "<p>($id) Record Updated<p>"; }else{ echo "<p>($id) Not Updated<p>"; } ?> now on edit.php i fill out the form to edit the account "test" while i am logged into it now once the form if filled out i click on |Submit!| button and it takes me to update.php and it returns this (0) Not Updated (0) <= id of user logged in Not Updated <= MySql Error from mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ i want it to update the user logged in and if i am not mistaken in this script it says $id = (int)$_SESSION["id"]; witch updates the user with the id of the person who is logged in but it isnt updating its saying that no tables were effected if it helps heres my MySql Database picture just click here http://i50.tinypic.com/21juqfq.png if this could possibly be any help to find the solution i have 2 more files delete.php and delete_ac.php they have can remove users from my sql database and they show the user id and it works there are no bugs in this script at all PLEASE DO NOT MAKE SUGGESTIONS FOR THE SCRIPTS BELOW delete.php first <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASSWORD"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // select record from mysql $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); ?> <table border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" style="bgcolor: #FFFFFF"><strong><img src="http://i47.tinypic.com/u6ihk.png" height="30" widht="30">Delete data in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>UserName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>FullName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Password</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Date</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Ip</strong></td> <td align="center" bgcolor="#FFFFFF">&nbsp;</td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['username']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['fname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['password']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['date']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['ip']; ?></td> <td bgcolor="#FFFFFF"><a href="delete_ac.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php // close while loop } ?> </table> <?php // close connection; sql_close(); ?> and now delete_ac.php <table width="500" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" bgcolor="#FFFFFF"><strong><img src="http://t2.gstatic.com/images? q=tbn:ANd9GcS_kwpNSSt3UuBHxq5zhkJQAlPnaXyePaw07R652f4StmvIQAAf6g" height="30" widht="30">Removal Of Account</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"> <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="javascript00"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Delete data in mysql from row that has this id $sql="DELETE FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); // if successfully deleted if($result){ echo "Deleted Successfully"; echo "<BR>"; echo "<a href='delete.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> </td> </tr> </table>

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  • Location of Embedly (JQuery-Preview) Results

    - by user749798
    Embedly/Jquery-Preview has been fantastic. However, I'm trying to change the location of the preview result, and having trouble. Right now, the result appears right below the input field...but I'd rather have it in a separate part of the page. Is there a way to do this? I've tried changing the location of the selector and loading divs, but that hasn't helped. It seems to ignore those divs and put it right below the submit button. Below is my code: <form accept-charset="UTF-8" action="private" class="new_comment" data-remote="true" id="new_comment" method="post"> <input class="photo_comm" id="comment_comment" name="comment[comment]" placeholder="add a comment or link..." size="30" type="text" /><span type="text" id="counter">1000</span> <input class="btn btn-primary btn-mini" data-disable-with="Submitting..." name="commit" type="submit" value="Post" /> </form> <!-- Placeholder that tells Preview where to put the loading icon--> <div class="loading"> <img src='http://embedly.github.com/jquery-preview/images/loading-rectangle.gif'> </div> <!-- Placeholder that tells Preview where to put the selector--> <div class="selector"></div> $('#comment_comment').preview({ key:'60f1dcdf3258476794784148a6eb65e7', // Sign up for a key: http://embed.ly/pricing selector : {type:'rich'}, preview : { submit : function(e, data){ e.preventDefault(); $.ajax({ dataType: 'script', url: this.form.attr('action'), type: 'POST', data: data }); }, }, autoplay : 0, maxwidth : 400, display : {display : 'rich'} });

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  • How do I fork correctly in a perl module for znc?

    - by rarbox
    I'm currently writing an IRC bot. The scripts are loaded as perl modules in ZNC but the bot gets disconnected with an Input/Output error if I create a forked process. This is a working example script without fork, but this causes the bot to freeze until the script finishes doing its task. package imdb; use warnings; use strict; sub new { my ($class) = @_; my $self = {}; bless( $self, $class ); return( $self ); } sub OnChanMsg { my ($self, $nick, $channel,$text) = @_; #unless (my $pid = fork()) { my $result = a_slow_process($text); ZNC::PutIRC( "PRIVMSG $channel :$result" ); # exit; #} return( ZNC::CONTINUE ); } sub OnShutdown { my ( $me ) = @_; } sub a_slow_process { my $input = shift; sleep 10; return "You said $input."; } 1; The fork code that is causing the error is commented out. How do I fix this? Edited to add: I was told that ZNC::PutIRC should not be put in the child process.

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  • CSS: Possible to define styles mid way through an html document?

    - by Dr. Zim
    In ASP.NET MVC, there are these snippets of html called view templates which appear when their matching data appears on the screen. For example, if you have a customer order and it has a vendor address, the vendor address view template shows up populated with data. Unfortunately, these don't have access to "MasterPages" nor are aware of their CSS surroundings. Instead of loading these up with style tags, is there any way to create partial CSS files that could work for that particular html snippet, a sort of in-line CSS style section? It would be really nice to plop this down just before we render the partial view: <style type="text/css"> input { margin: .2em .2em; overflow: hidden; width: 18.8em; height: 1.6em; border: 1px solid black;} </style> to have the 15 or so input fields in that particular Html snippet be formatted the same. These are swapped out, so the positions of the input fields change. This may also imply a CSS reset on each partial view.

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  • jQuery Form Validation being bypassed

    - by user1953681
    Can someone tell me what is wrong with my jQuery validation? It is not validating my form, rather, just ignoring the code resulting in no check of the inputs. Form: <form class="form" accept-charset="UTF-8" action="URL-to-complete-form" method="POST" onsubmit="return validateForm();"> <input class="form-name" type="text" placeholder="Name"></div> <input class="form-email" type="text"placeholder="Email"></div> <input style="background-color: #fc8f12;" type="submit" value="Subscribe"> </div> </form> Javascript: function validateForm() { // Validate Name var title = $(".form-name").val(); if (title=="" ||title=="Name" || title==null) { } else { alert("Please enter a name!"); } // Validate Email var email = $(".form-email").val(); if ((/(.+)@(.+){2,}\.(.+){2,}/.test(email)) || email=="" || email=="Email" || email==null) { } else { alert("Please enter a valid email"); } return false; } Thank you all for your time and help.

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  • How to show a form field ONLY if another is selected in JavaScript or jQuery?

    - by Sam
    I have a form, like so: <form action="" method="post"> <select name="pageType"> <option value="main">Main Page</option> <option value="sub">Sub Page</option> <option value="sub-sub">Sub-Sub Page</option> </select> <br /> <label>Choose Sub Sub Name:</label> <input type="text" name="sub-sub-name" /> <br /> <input type="submit" name="submit" value="GO!" /> </form> What I would like to achive is for this text field (and it's label): <label>Choose Sub Sub Name:</label> <input type="text" name="sub-sub-name" /> to only appear if the 3rd option (sub sub page) is selected from the drop down and not show up otherwise. How can this be done with either javascript or the jquery framework? EDIT by the way, it would be nice if this can be achieved without the page needing to refresh and losing previously submitted form data. I know form data can still be kept using variables that store the values even on page refresh, but I was hoping for that effect that I see on a lot of sites where the additional text area (or other form element) just appears without page refresh.

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  • ArrayList<Int> Collections.Sort and LineNumberReader Help How to

    - by user1819551
    I have a issue i can't get it to work now let going to the point a explain in the code thanks. This is my class: what I want to do is insert the Integers sort the list and buffer writer in a column with out coma. Now I getting this: [1110018, 1110032, 1110056, 1110059, 1110063, 1110085, 1110096, 1110123, 1110125, 1110185, 1110456, 1110459] I want like this: 111xxxxx 111xxxx xxxx....... I can't do it in single array, have to be in ArrayList. This is my collecting: list.addNumbers(numbers); list.display(); This is my writer: Is buffered coma.write("\n"+list.display()); coma.flush();<br/> Here is my class: public class IdCount {<br/> private ArrayList<Integer> properNumber = new ArrayList<>(); public void addNumbers(Integer numbers) { properNumber.add(numbers); Collections.sort(properNumber); } public String display() { //(I try .toString() Not work) return properNumber.toString(); } My second issue is LineNumberReader: This is my collecting and my writing: try { Reader input = new BufferedReader( new FileReader(inputFile)); try (Scanner in = new Scanner(input)) { while (in.hasNext()) { //(More Code) asp = new LineNumberReader(input); int rom = 0; while (asp.readLine()!=null){ rom++; } System.out.println(rom); coma.write(rom); This one will not write anything an my System Print give me only 12 0 in column.

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  • show data in another cell after press enter

    - by klox
    i have this code <tr> <td width="300"> <label for="tag">Model</label> </td> <td> <td width="10">:</td> </td> <td> <td> <td width="450" align="left"> <input type="text" id="tags1" name="model"> </td> </td> </td> </tr> if i type inside textfield "E" i want inside another cell show like: <tr> <td><label><h6>this version <input type.......show E> <br>87.5-108.0</br></h6></label> </td> </tr> but if type "J" will show: <tr> <td><label><h6>this version <input type......show J> <br>87.5-107.9</br></h6></label> </td> </tr> what's code that can make it works after press enter?

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  • Cannot clear the form after Submit using the Validation plugin in jQuery

    - by novellino
    Hello, I an quite new to jQuery and I have a problem while trying to create a form. I am using the Validation plugin for validate the email (one the form's field). When I click the Submit button I want to call my own function because I want to save the data in an XML file. This is my button: (as I understood the plugin uses "submit" for understand the button) <input type="submit" name="submit" class="submit" id="submit_btn" value="Send"/> and here is the script for the validation: <script type="text/javascript"> $(document).ready(function() { //this is my form $("#contactForm").validate(); /*save the valid data in the xml*/ $(".submit").click(function() { var email = $("input#email").val(); var subject = $("input#subject").val(); var message = $("textarea#message").val(); if (email == "" || !$("#contactForm").valid()) { return false; } var dataString = 'email='+ email + '&subject=' + subject + '&message=' + message; //alert("DATA: " +dataString); $.ajax({ type: "POST", url: "SaveData.jsp", data: dataString, success: function(data){} }); return false; }); }); </script> In general it works ok but I have two basic problems. When I click the button in the beginning having all the form empty, I get no message for the field required. Also when the data are valid and I am doing the submit, the form does not become clear after the submit. If I deleted this script code, these actions are working properly but I can not save the data! Does anyone know what is wrong? Thanks a lot!

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  • How do I determine if form field is empty with jQuery?

    - by user338413
    I've got a form with two fields, firstname and lastname. The user does not have to fill in the fields. When the user clicks the submit button, a jquery dialog displays with the data the user entered in the form. I only want to show the data for the fields that were entered. I'm trying to do an if statement and use the length() function but it isn't working. Help would be great! Here is my dialog jquery script: $(function(){ //Initialize the validation dialog $('#validation_dialog').dialog({ autoOpen: false, height: 600, width: 600, modal: true, resizable: false, buttons: { "Submit Form": function() { document.account.submit(); }, "Cancel": function() { $(this).dialog("close"); } } }); // Populate the dialog with form data $('form#account').submit(function(){ $("p#dialog-data").append('<span>First Name: </span>'); $("p#dialog-data").append('<span>'); $("p#dialog-data").append($("input#firstname").val()); $("p#dialog-data").append('</span><br/>'); if (("input#lastname").val().length) > 0) { $("p#dialog-data").append('<span>Last Name: </span>'); $("p#dialog-data").append('<span>'); $("p#dialog-data").append($("input#lastname").val()); $("p#dialog-data").append('</span><br/>'); }; $('#validation_dialog').dialog('open'); return false; }); });

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  • How to upload files to server using JSP/Servlet?

    - by Thang Pham
    How can I upload files to server using JSP/Servlet? I tried this: <form action="upload" method="post"> <input type="text" name="description" /> <input type="file" name="file" /> <input type="submit" /> </form> However, I only get the file name, not the file content. When I add enctype="multipart/form-data" to the <form>, then request.getParameter() returns null. During research I stumbled upon Apache Common FileUpload. I tried this: FileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); List items = upload.parseRequest(request); // This line is where it died. Unfortunately, the servlet threw an exception without a clear message and cause. Here is the stacktrace: SEVERE: Servlet.service() for servlet UploadServlet threw exception javax.servlet.ServletException: Servlet execution threw an exception at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:313) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:637)

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  • Syntactical analysis with Flex/Bison part 2

    - by Imran
    Hallo, I need help in Lex/Yacc Programming. I wrote a compiler for a syntactical analysis for inputs of many statements. Now i have a special problem. In case of an Input the compiler gives the right output, which statement is uses, constant operator or a jmp instructor to which label, now i have to write so, if now a if statement comes, first the first command (before the else) must be give out when the assignment of the if is yes then it must jump to the end because the command after the else isnt needed, so after this jmp then the second command must be give out. I show it in an example maybe you understand what i mean. Input adr. Output if(x==0) 10 if(x==0) Wait 5 20 WAIT 5 else 30 JMP 50 Wait 1 40 WAIT 1 end 50 END like so. I have an idea, maybe i can do it whith a special if statement like IF exp jmp_stmt_end stmt_seq END when the if statement is given in the input the compiler has to recognize the end ofthe statement and like my jmp_stmt in my compiler ( you have to download the files from http://bitbucket.org/matrix/changed-tiny) only to jump to the end. I hope you understand my problem.thanks.

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  • Bootstrap - Typehead on multiple inputs

    - by Clem
    I have two text intputs, both have to run an autocompletion. The site is using Bootstrap, and the « typeahead » component. I have this HTML : <input type="text" class="js_typeahead" data-role="artist" /> <input type="text" class="js_typeahead" data-role="location" /> I'm using the « data-role » attribute (that is sent to the Ajax controller as a $_POST index), in order to determine what kind of data has to be retrieved from the database. The Javascript goes this way : var myTypeahead = $('input.js_typeahead').typeahead({ source: function(query, process){ var data_role; data_role = myTypeahead.attr('data-role'); return $.post('/ajax/typeahead', { query:query,data_role:data_role },function(data){ return process(data.options); }); } }); With PHP, I check what $_POST['data-role'] contains, an run the MySQL query (in this case, a query either on a list of Artists, or a list of Locations). But the problem is the second "typeahead" returns the same values than the first one (list of Artists). I assume it's because the listener is attached to the object « myTypeahead », and this way the "data-role" attribute which is used, will always be the same. I think I could fix it by using something like : data_role = $(this).attr('data-role'); But of course this doesn't work, as it's a different scope. Maybe I'm doing it all wrong, but at least maybe you people could give me a hint. Sorry if this has already been discussed, I actually searched but without success. Thanks in advance, Clem (from France, sorry for my english)

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  • Unable to send '+' through AJAX post?

    - by Harish Kurup
    I am using Ajax POST method to send data, but i am not able to send '+'(operator to the server i.e if i want to send 1+ or 20k+ it will only send 1 or 20k..just wipe out '+') HTML code goes here.. <form method='post' onsubmit='return false;' action='#'> <input type='input' name='salary' id='salary' /> <input type='submit' onclick='submitVal();' /> </form> and javascript code goes here, function submitVal() { var sal=document.getElementById("salary").value; alert(sal); var request=getHttpRequest(); request.open('post','updateSal.php',false); request.setRequestHeader("Content-Type","application/x-www-form-urlencoded"); request.send("sal="+sal); if(request.readyState == 4) { alert("update"); } } function getHttpRequest() { var request=false; if(window.XMLHttpRequest) { request=new XMLHttpRequest(); } else if(window.ActiveXObject) { try { request=new ActiveXObject("Msxml2.XMLHTTP"); } catch(e) { try { request=new ActiveXObject("Microsoft.XMLHTTP"); } catch(e) { request=false; } } } return request; } in the function submitVal() it first alert's the salary value as it is(if 1+ then alerts 1+), but when it is posted it just post's value without '+' operator which is needed... is it any problem with query string, as the PHP backend code is working fine...

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  • select failing with C program but not shell

    - by Gary
    So I have a parent and child process, and the parent can read output from the child and send to the input of the child. So far, everything has been working fine with shell scripts, testing commands which input and output data. I just tested with a simple C program and couldn't get it to work. Here's the C program: #include <stdio.h> int main( void ) { char stuff[80]; printf("Enter some stuff:\n"); scanf("%s", stuff); return 0; } The problem with with the C program is that my select fails to read from the child fd and hence the program cannot finish. Here's the bit that does the select.. //wait till child is ready fd_set set; struct timeval timeout; FD_ZERO( &set ); // initialize fd set FD_SET( PARENT_READ, &set ); // add child in to set timeout.tv_sec = 3; timeout.tv_usec = 0; int r = select(FD_SETSIZE, &set, NULL, NULL, &timeout); if( r < 1 ) { // we didn't get any input exit(1); } Does anyone have any idea why this would happen with the C program and not a shell one? Thanks!

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  • Piping EOF problems with stdio and C++/Python

    - by yeus
    I got some problems with EOF and stdio. I have no idea what I am doing wrong. When I see an EOF in my program I clear the stdin and next round I try to read in a new line. The problem is: for some reason the getline function immediatly (from the second run always, the first works just as intended) returns an EOF instead of waiting for a new input from py python process... Any idea? alright Here is the code: #include <string> #include <iostream> #include <iomanip> #include <limits> using namespace std; int main(int argc, char **argv) { for (;;) { string buf; if (getline(cin,buf)) { if (buf=="q") break; /*****///do some stuff with input //my actual filter program cout<<buf; /*****/ } else { if ((cin.rdstate() & istream::eofbit)!=0)cout<<"eofbit"<<endl; if ((cin.rdstate() & istream::failbit)!=0)cout<<"failbit"<<endl; if ((cin.rdstate() & istream::badbit)!=0)cout<<"badbit"<<endl; if ((cin.rdstate() & istream::goodbit)!=0)cout<<"goodbit"<<endl; cin.clear(); cin.ignore(numeric_limits<streamsize>::max()); //break;//I am not using break, because I //want more input when the parent //process puts data into stdin; } } return 0; } and in python: from subprocess import Popen, PIPE import os from time import sleep proc=Popen(os.getcwd()+"/Pipingtest",stdout=PIPE,stdin=PIPE,stderr=PIPE); while(1): sleep(0.5) print proc.communicate("1 1 1") print "running"

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  • Codeigniter: Simple ajax submit not working

    - by Kevin Brown
    jQuery: $('#welcome-message').submit(function() { // inside event callbacks 'this' is the DOM element so we first // wrap it in a jQuery object and then invoke ajaxSubmit $(this).ajaxSubmit({}); $(this).fadeTo(400, 0, function () { // Links with the class "close" will close parent $(this).slideUp(400); }); return false; }); Controller: function welcome_message() { if(isset($_POST['welcome_message'])) { $this-_my_private_function(); } } private function _my_private_function() { $id = $this->session->userdata('id'); $profile['welcome_message'] = '0'; $this->db->update('be_user_profiles',$profile, array('user_id' => $id)); redirect('home', 'location'); } html: <?php print form_open('home/welcome_message',array('class'=>'horizontal','id'=>'welcome-message'))?> <p> Before you can complete the assessment, you need to complete your profile. Once that's done you'll be ready! After you have completed the assessment, you will be able to view the results from your profile. </p> <input type="checkbox" value="0" name="welcome_message" checked="false"> Don't show me this again </input> <p> <input class="button submit" type="submit" class="close-box" value="Close" /> </p> <?php print form_close()?> This should be working. My hypothesis is that the data isn't being passed to the function...but I really have no idea! It works when I visit the function in the url.

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  • Convert image color space and output separate channels in OpenCV

    - by Victor May
    I'm trying to reduce the runtime of a routine that converts an RGB image to a YCbCr image. My code looks like this: cv::Mat input(BGR->m_height, BGR->m_width, CV_8UC3, BGR->m_imageData); cv::Mat output(BGR->m_height, BGR->m_width, CV_8UC3); cv::cvtColor(input, output, CV_BGR2YCrCb); cv::Mat outputArr[3]; outputArr[0] = cv::Mat(BGR->m_height, BGR->m_width, CV_8UC1, Y->m_imageData); outputArr[1] = cv::Mat(BGR->m_height, BGR->m_width, CV_8UC1, Cr->m_imageData); outputArr[2] = cv::Mat(BGR->m_height, BGR->m_width, CV_8UC1, Cb->m_imageData); split(output,outputArr); But, this code is slow because there is a redundant split operation which copies the interleaved RGB image into the separate channel images. Is there a way to make the cvtColor function create an output that is already split into channel images? I tried to use constructors of the _OutputArray class that accepts a vector or array of matrices as an input, but it didn't work.

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  • photo upload with codeigniter

    Hi friends, I know there are many tutorials online, but I could not make them work :( maybe something particularly wrong with my system :/ My Controller localpath is: /localhost/rl/applications/backend/controller/ Controller: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '100'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); $this->load->view('add_image', $error); } else { $data = array('upload_data' => $this->upload->data()); $data['id'] = $this->input->post['id_work']; $this->load->view('add_image', $data); } } My View localpath is: /localhost/rl/applications/backend/view/ View: echo form_open_multipart('do_upload'); <ul class="frm"> <li><label>File: *</label><input type="file" name="userfile" class="frmlmnt" size="50" /></li> <li><label></label><input type="submit" class="btn" value="Upload" /></li> </ul> </form> Maybe I do something wrong with path

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  • Styling individual radio buttons in drupal form

    - by Andrew
    I have this group of radio buttons in which each of individual button has of its own position set through style attribute. I would like to how can I archive the same by using drupal form api. I found how to style as whole but, not as individual control within group. Here's how my html code look like - <input type="radio" name="base_location" checked="checked" value="0" style="margin-left:70px;float:left;"/><span style="float:left;">District</span> <input type="radio" name="base_location" value="1" style="margin-left:50px;float:left;"/><span style="float:left;">MRT</span> <input type="radio" name="base_location" value="2" style="margin-left:60px;float:left;"/><span style="float:left;">Address</span> And this is the drupal code I'm stuck at - $form['base_location'] = array( '#type' => 'radios', '#title' => t('base location'), '#default_value' => variable_get('search_type', 0), '#options' => array( '0'=>t('District'), '1'=>t('MRT'), '2'=>t('Address')), '#description' => t('base location'), I'm aware of #type=radio existence. However, I do not know how to group all my radio buttons together in this regard. If I use same array key for all of them, they would collide each other. If I don't, they aren't seen as part of the same group. I thank you in advance.

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  • jquery how to make insertBefore work only once, on first click?

    - by user313271
    jquery $(function(){ $('#4').click(function() { $('<input name="if4" type="text" value="other price>"').insertBefore('form textarea'); }); }); html <form> < input name="name" type="text" value="Enter your name" /><br /> < input name="contacts" type="text" value="Contact info" /><br /> < select name="services"> < option value="1">1</option> < option value="2">2</option> < option value="3">3</option> < option id="4" value="Other">4</option> < /select><br /> < textarea name="description">Description</textarea><br /> < /form> And one more question about it, when i press on option number 4 two time,there appears 2 new fields, is there any way how to fix it, that new field appear only 1 time, after first click ?

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  • Terminate function on System.in .. possible?

    - by Ronald
    I am currently working on a project where I have to make an agent to interact with a server. Each 50ms, the server will receive the last thing I outputted to System.out and send me a new set of lines as a 'state' through the System.in printstream to analyze and send my next message to System.out. Also, if the server receives multiple outputs from me, it only regards the most recent one. .. As for my question: My program originally constructed a tree and then analyzed each leaf node to see which would be optimal, and then waited around for the next input, but I can recursively do a deeper tree search that would make my output 'better' (and again and again to keep returning a better result). Using this and the fact that if the server receives multiple outputs, it only takes the most recent one, I could do each level, print my result and start the next level. But here comes my problem... I can't be stuck in some complex algorithm while I am supposed to receiving the next input as I will then miss it. So I was wondering if there is a way to cancel anything else I am doing when I receive something via System.in and then go back to the beginning of the function and start the search again with the new set of input (and rinse and repeat..) I hope this all makes sense, Thank ye all

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  • OnSubmit does work right in the Validation plugin in jQuery

    - by novellino
    Hello, I an quite new to jQuery and I have a problem while trying to create a form. I am using the Validation plugin for validate the email (one the form's field). When I click the Submit button I want to call my own function because I want to save the data in an XML file. This is my button: (as I understood the plugin uses "submit" for understand the button) <input type="submit" name="submit" class="submit" id="submit_btn" value="Send"/> and here is the script for the validation: <script type="text/javascript"> $(document).ready(function() { //this is my form $("#contactForm").validate(); /*save the valid data in the xml*/ $(".submit").click(function() { var email = $("input#email").val(); var subject = $("input#subject").val(); var message = $("textarea#message").val(); if (email == "" || !$("#contactForm").valid()) { return false; } var dataString = 'email='+ email + '&subject=' + subject + '&message=' + message; //alert("DATA: " +dataString); $.ajax({ type: "POST", url: "SaveData.jsp", data: dataString, success: function(data){} }); return false; }); }); In general it works ok but I have two basic problems. When I click the button in the beginning having all the form empty, I get no message for the field required. Also when the data are valid and I am doing the submit, the form does not become clear after the submit. If I deleted this script code, these actions are working properly but I can not save the data! Does anyone know what is wrong? Thanks a lot!

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  • jquery change event not working with IE6

    - by manivineet
    It is indeed quite unfortunate that my client still uses IE6. using jquery 1.4.2 The problem is that I open a window using a click event and do some edit operation in the new window. I have a 'change' event attached to the row of a table which has input fields. Now when the window loads for the first time and I make a change in the input for the FIRST time, the change event does not fire. however, on a second try it starts working. I have noticed that I e.g. I run a dummy page, i.e. create a new page(i work with visual studio) and run that page individually , the 'change' event works just fine. what it going on? and what can i do, besides going back to 1.3.2 (by the way that doesn't work either, but haven't fully tested it yet) <!--HTML--> <table id="tbReadData"> <tr class="nenDataRow" id="nenDr2"> <td> <input type="text" class="nenMeterRegister" value="1234" /> </td> <tr /> <table> <script type="text/javascript"> $(document).ready(function(){ $('#tbReadData').find('tr').change(function() { alert('this works'); } }); </script>

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  • Asp.net Hidden field not having value in code behind, but *is* retaining value after postbacks

    - by KallDrexx
    In my ASCX, I have an asp.net hidden field defined as <asp:HiddenField ID="hdnNewAsset" runat="server" />. In the Code Behind I have the following code: protected void Page_Load(object sender, EventArgs e) { _service = new ArticleDataService(PortalId); if (!IsPostBack) { string rawId = Request[ArticleQueryParams.ArticleId]; DisplayArticleDetails(rawId); } if (hdnNewAsset.Value.Trim() != string.Empty) ProcessNewAsset(); } Now, in my frontend, I have a javascript function to react to an event and set the hidden field and trigger a postback: function assetSelected(assetGuid) { $('input[id*="hdnNewAsset"]').val(assetGuid); __doPostBack() } What's happening is that my hidden field is being set in the markup (chrome shows [ <input type=?"hidden" name=?"dnn$ctr466$Main$ctl00$hdnNewAsset" id=?"dnn_ctr466_Main_ctl00_hdnNewAsset" value=?"98d88e72-088c-40a4-9022-565a53dc33c4">? ] for $('input[id*="hdnNewAsset"]')). However, when the postback occurs, hdnNewAsset.Value is an empty string. What's even more puzzling is that at the beginning of Page_Load Request.Params["dnn$ctr466$Main$ctl00$hdnNewAsset"] shows 98d88e72-088c-40a4-9022-565a53dc33c4, and after the postback my hidden field has the same value (so the hidden field is persisting across postbacks), yet I cannot access this value via hdnNewAsset.Value. Can anyone see what I"m doing wrong?

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