Search Results

Search found 31806 results on 1273 pages for 'learner php'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 278/1273 | < Previous Page | 274 275 276 277 278 279 280 281 282 283 284 285  | Next Page >

  • Entity-attribute-value model using codeigniter / php

    - by John Stewart
    SO I am trying to create a way to structure my database to be able customize forms. I looked into EAV pattern and here is my db structure: Table form - form_id - form_name - form_added_on - form_modified_at Table: form_fields - field_id - form_id - field_type (TEXT, RADIO etc..) - field_default_value - field_required Table: form_data - data_id - field_id - form_id - field_value so now I can store any custom form into the database and if I want to get the values for an individual form I can simply join it by "form_id" .. the problem: I want to be able to search through all the forms for a specific field value. How can I do that with EAV model? Also, I thought about just storing the custom data as a serialized (JSON) object but then I am not sure how can I query that data. Please note that I am using Codeigniter with MYSQL. So if conversation can use Codeigniter libraries if needed.

    Read the article

  • Need some help to determine the amount of recursive calls in PHP

    - by Ben Fransen
    Hi all, I've got a, I think fairly easy question, but this is bugging me for a while now. So I figured, maybe I can get some help here. Since recursive functions are always a bit tricky, and sometimes a bit unclear to me, I keep struggling to create a nice working solution to get my menudata. In one of my classes I have this function, which gives me all menu-items recursivly. The thing I want is to determine at which recursionlevel a certain object was retrieved so I can create a nicely looking HTML output with indents for the levels of nesting. public function GetObjectList($parentID = 0, $objectlist = null) { if(is_null($objectlist)) { $objectlist = new ObjectList("Model_Navigation"); } $query = MySQL::Query("SELECT * FROM `Navigation` WHERE `WebsiteID` = ".SITE_ID. " AND `LanguageID` = ".LANG_ID." AND `ParentID` = ".$parentID); while($result = MySQL::FetchAssoc($query)) { $object = new Model_Navigation(); $object->ID = $result["ID"]; $object->WebsiteID = $result["WebsiteID"]; $object->LanguageID = $result["LanguageID"]; $object->ParentID = $result["ParentID"]; $object->Name = $result["Name"]; $object->Page = Model_Page::GetObjectByID($result["PageID"]); $object->ExternalURL = $result["ExternalURL"]; $object->Index = $result["Index"]; $object->Level = [here lies my problem]; $objectlist->Add($object); self::GetObjectList($object->ID, $objectlist); } return $objectlist; } Hope to hear from you! Greetings from Holland, Ben Fransen

    Read the article

  • How to simplify my country select menu PHP/mysql

    - by user342391
    I have a select menu that displays countries. It looks at the DB and judging by the value in the db shows the option as selected. Is there a simpler way off doing this than: if ($country == 'AG') {echo '<option value="AG" selected="selected">Antigua</option>';} else {echo '<option value="AG">Antigua</option>';}; if ($country == 'AR') {echo '<option value="AR" selected="selected">Argentina</option>';} else {echo '<option value="AR">Argentina</option>';}; if ($country == 'AM') {echo '<option value="AM" selected="selected">Armenia</option>';} else {echo '<option value="AM">Armenia</option>';}; if ($country == 'AW') {echo '<option value="AW" selected="selected">Aruba</option>';} else {echo '<option value="AW">Aruba</option>';}; if ($country == 'AU') {echo '<option value="AU" selected="selected">Australia</option>';} else {echo '<option value="AU">Australia</option >';}; if ($country == 'AT') {echo '<option value="AT" selected="selected">Austria</option>';} else {echo '<option value="AT">Austria</option>';}; if ($country == 'AZ') {echo '<option value="AZ" selected="selected">Azerbaijan</option>';} else {echo '<option value="AZ">Azerbaijan</option>';}; if ($country == 'BS') {echo '<option value="BS" selected="selected">Bahamas</option>';} else {echo '<option value="BS">Bahamas</option>';}; if ($country == 'BH') {echo '<option value="BH" selected="selected">Bahrain</option>';} else {echo '<option value="BH">Bahrain</option>';}; There are a lot of countries and doing this would be madness wouldn't it????

    Read the article

  • PHP IP Validation Help

    - by Zubair1
    Hello, I am using this IP Validation Function that i came across while browsing, it has been working well until today i ran into a problem. For some reason the function won't validate this IP as valid: 203.81.192.26 I'm not too great with regular expressions, so would appreciate any help on what could be wrong. If you have another function, i would appreciate if you could post that for me. |--------------------------------------------| The code for the function is below: |--------------------------------------------| public static function validateIpAddress($ip_addr) { global $errors; $preg = '#^(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}' . '(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$#'; if(preg_match($preg, $ip_addr)) { //now all the intger values are separated $parts = explode(".", $ip_addr); //now we need to check each part can range from 0-255 foreach($parts as $ip_parts) { if(intval($ip_parts) > 255 || intval($ip_parts) < 0) { $errors[] = "ip address is not valid."; return false; } return true; } return true; } else { $errors[] = "please double check the ip address."; return false; } }

    Read the article

  • PHP form validation question?

    - by GeNx
    Is it necessary to validate a name or street address? when I have it coded in the following format. And if so why? $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $name = mysqli_real_escape_string($mysqli, htmlentities($_POST['name']));

    Read the article

  • How to parse an XML file using PHP?

    - by Jack
    Here I have a variable 'response' which is obtained by parsing an XML file. $url = 'http://xxxxx.xml'; $ch = curl_init($url); $response = curl_exec($ch); The url structure is as follows - <user> <id>734</id> <name>Peter Parker</name> - <status> <favorited>false</favorited> </status> </user> How to access each bit of info like id,name,favorited from response?

    Read the article

  • PHP count total files in directory AND subdirectory function

    - by Neoweiter
    I need to get a total count of JPG files within a specified directory, including ALL it's subdirectories. No sub-sub directories. Structure looks like this : dir1/ 2 files subdir 1/ 8 files total dir1 = 10 files dir2/ 5 files subdir 1/ 2 files subdir 2/ 8 files total dir2 = 15 files I have this function, which doesn't work fine as it only counts files in the last subdirectory, and total is 2x more than the actual amount of files. (will output 80 if I have 40 files in the last subdir) public function count_files($path) { global $file_count; $file_count = 0; $dir = opendir($path); if (!$dir) return -1; while ($file = readdir($dir)) : if ($file == '.' || $file == '..') continue; if (is_dir($path . $file)) : $file_count += $this->count_files($path . "/" . $file); else : $file_count++; endif; endwhile; closedir($dir); return $file_count; }

    Read the article

  • Php - Looping For Different CSS

    - by bob
    MySQL $selectSize = "SELECT * FROM products"; $querySize = $db->select($selectSize); while ($product = $db->fetcharray($querySize)) { HTML <ul> <li>Product A</li> <li>Product B</li> <li class='right'>Product C</li> <li>Product D</li> <li>Product E</li> <li class='right'>Product F</li> </ul> Question While getting the product, I want the Product C and Product F or any product after 3 loops will have class='right' to the list style. Let me know Thanks

    Read the article

  • Incorrect table name, php/mysql

    - by user296516
    Hi guys, I've got this code mysqli_query ( $userdatabase, 'CREATE TABLE `user_'.$emailreg.'` ( ID int NOT NULL AUTO_INCREMENT PRIMARY KEY, IP varchar(10), FLD1 varchar(20), FLD2 varchar(40), FLD3 varchar(25), FLD4 varchar(25), FLD5 varchar(25) )' ); echo ( mysqli_error ($userdatabase) ); that works fine on my localhost, but when I upload it to the server, it starts giving me a "Incorrect table name '[email protected]'" error. any idea? Thanks!

    Read the article

  • @readfile in php??

    - by Jonathan
    I hate that google can not search for symbols. I saw this in some sample code and wondered why there is an @ sign before the readfile function: @readfile($filename); What does it mean different to without an @ symbol?

    Read the article

  • find and replace values in a flat-file using PHP

    - by peirix
    I'd think there was a question on this already, but I can't find one. Maybe the solution is too easy... Anyway, I have a flat-file and want to let the user change the values based on a name. I've already sorted out creating new name+value-pairs using the fopen('a') mode, using jQuery to send the AJAX call with newValue and newName. But say the content looks like this: host|http:www.stackoverflow.com folder|/questions/ folder2|/users/ And now I want to change the folder value. So I'll send in folder as oldName and /tags/ as newValue. What's the best way to overwrite the value? The order in the list doesn't matter, and the name will always be on the left, followed by a |(pipe), the value and then a new-line. My first thought was to read the list, store it in an array, search all the [0]'s for oldName, then change the [1] that belongs to it, and then write it back to a file. But I feel there is a better way around this? Any ideas? Maybe regex?

    Read the article

  • How Easy Is It to Hijack Session Vars on GoDaddy (PHP)

    - by yar
    This article states that If your site is run on a shared Web server, be aware that any session variables can easily be viewed by any other users on the same server. On a larger host like GoDaddy, are there really no protections in place against this? Could it really be that easy? If it is that easy, where are the session vars of the other users on my host so I can check them out? Edit: I didn't believe it, but here's my little program which shows that this is true! I wonder if those are really the same as the value stored in the cookies on the users' machine?

    Read the article

  • I need help with creating a data structure in PHP

    - by alex
    What I need to do is have a data structure that shows jobs organised into 14 day periods, but only when an id is the same. I've implemented all sorts of stuff, but they have failed miserably. Ideally, maybe a SQL expert could handle all of this in the query. Here is some of my code. You can assume all library stuff works as expected. $query = 'SELECT date, rig_id, comments FROM dor ORDER BY date DESC'; $dors = Db::query(Database::SELECT, $query)->execute()->as_array(); This will return all jobs, but I need to have them organised by 14 day period with the same rig_id value. $hitches = array(); foreach($dors as $dor) { $rigId = $dor['rig_id']; $date = strtotime($dor['date']); if (empty($hitches)) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } else { $found = false; foreach($hitches as $key => $hitch) { $hitchStartDate = $hitch['startDate']; $dateDifference = abs($hitchStartDate - $date); $isSameHitchTimeFrame = $dateDifference < (Date::DAY * 14); if ($rigId == $hitch['rigId'] AND $isSameHitchTimeFrame) { $found = true; $hitches[$key]['dors'][] = $dor; } } if ($found === false) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } } } This seems to work OK splitting up by rig_id, but not by date. I also think I'm doing it wrong because I need to check the earliest date. Is it possible at all to do any of this in the database query? To recap, here is my problem I have a list of jobs with all have a rig_id (many jobs can have the same) and a date. I need the data to be organised into hitches. That is, the rig_id must be the same per hitch, and they must span a 14 day period, in which the next 14 days with the same rig_id will be a new hitch. Can someone please point me on the right track? Cheers

    Read the article

  • web design question (php/ajax)

    - by tom smith
    Hi guys... Hope this isn't a waste of your time. I'm working on a project, and it occured to me that there's a chunk of code out there, that should allow me to see how others have implemented this. I've got a project where I'm going to have a page, with a sel box. the user will select an item from the selList, and based on the item selected, a separate section of the page (areaB) will change in terms of the content/tbls being displayed. i then want to allow the user to go through a series of subpages in areaB, where the user goes through a submit/cancel/confirm process, where the stuff in areaB changes, with the rest of the page remaining the same... i'm trying to figure out the best approach to implement the on both client/server side. i could just have an ugly "if block" where i have abunch of logic, and i completely regen the page each time the user selects an action.. i could have an approach that might involve divs/frames, where i then just regen the targeted frame/div area.. is this even possible?? i could have some form of ajaxy process, which would only alter the targeted section(s) of the page... so.. i'm trying to talk to anyone who has ideas on how to do this, or more ideally, if you know of a good code (client/server) side example of this... that i can examine. i'd really appreciate it!! i've got a more detailed overview but didn't know if it would be cool to post it here... thanks.. tom

    Read the article

  • Lamda functions in php

    - by Oden
    Hey, Im really interested in the way of using lamda functions. Does it make sense to use them in a high-level programming language? If yes, why? Is this really just a function embedded in a function, (Like this) or is there more behind?

    Read the article

  • PHP array ordering

    - by Melonheadjr44
    Hi, I was wondering how I could sort this array, when I use asort right now it does 14 17 16 15. How would I go to have 14 15 16 17 array(4) { [15]=> array(9) { [2025]=> string(80) "20:25 à 21:15 Spectacle / L'histoire d'un coeur / Auditorium, É.S.P. De La Salle" [2135]=> string(71) "21:35 à 22:25 Spectacle / Transfugue 2 / Auditorium, É.S.P. De La Salle" [1430]=> string(64) "14:30 à 15:30 Mise en lecture/Théâtre la Catapulte / De La Salle" [110]=> string(44) "11:00 à 13:00 Inscription / Pavillon Tabaret" [1330]=> string(49) "13:30 à 14:30 CÉRÉMONIE D'OUVERTURE / De La Salle" [1550]=> string(61) "15:50 à 16:40 Spectacle/Université Laurentienne / De La Salle" [170]=> string(57) "17:00 à 17:50 Spectacle/Université d'Ottawa / De La Salle" [1750]=> string(45) "17:50 à 19:00 REPAS DE L'AMITIÉ / De La Salle" [1915]=> string(76) "19:15 à 20:05 Spectacle / Attendre la pluie / Auditorium, É.S.P. De La Salle" } [16]=> array(8) { [1845]=> string(81) "18:45 à 19:35 Spectacle / Mimes d'horreur / Salle Académique, Université d'Ottawa" [1955]=> string(73) "19:55 à 20:45 Spectacle / Déroute / Salle Académique, Université d'Ottawa" [8]=> string(45) "08:30 à 11:30 Atelier / ABC du jeu dramatique" [13]=> string(41) "13:00 à 16:00 Atelier / Théâtre physique" [1130]=> string(28) "11:30 à 13:00 DÎNER LIBRE / " [1620]=> string(29) "16:20 à 18:20 SOUPER LIBRE / " [220]=> string(58) "22:00 à 23:30 BAL MASQUÉ / l'Agora du centre universitaire" [210]=> string(47) "21:00 à 22:00 Rétroaction / Université d'Ottawa" } [17]=> array(4) { [950]=> string(79) "09:50 à 10:40 Spectacle / Raison d'être / Salle Académique, Université d'Ottawa" [110]=> string(76) "11:00 à 11:50 Spectacle / Potionnée / Salle Académique, Université d'Ottawa" [120]=> string(28) "12:00 à 13:00 DÎNER LIBRE / " [1330]=> string(48) "13:30 à 14:30 CÉRÉMONIE DE CLÔTURE / De La Salle" } [14]=> array(1) { [150]=> string(49) "15:00 à 16:30 Préparation technique / De La Salle" } }

    Read the article

  • Login and register page PHP

    - by Ben
    How do I make a log in (as one document) and register (as another document) page for my site using PHPMyAdmin? So that people can register and log into my site. Thanks! Benjamin

    Read the article

  • how to find the directory already is there or not in php

    - by zahir hussain
    hi i want know find the directory is already there or not... if not i would like to create the directory... my coding is below... $da = getdate(); $dat = $da["year"]."-".$da["mon"]."-".$da["mday"]; $m = md5($url)."xml"; if(is_dir($dat)) { chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "yes"; } else { mkdir($dat,0777,true); chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "not"; } thanks and advance

    Read the article

  • [PHP] Associate different data

    - by Alex Cane
    I will try to be as clear as possible because I can't get anybody to help me around, I am trying to associate some data from a 'videos' table with their respective ID. Lets say, I have column ID, title, serie, season, episode. I am getting my data : <? $result = mysql_query("SELECT * FROM videos WHERE serie = '".$row['serie']."' AND season = '".$row['season']."'"); $total_rows = mysql_num_rows($result); ?> (that is in the page where you see the video itself) So now I can get the number of episodes from a serie and season. What I'm trying to do is have a link for the next episode, and aa link for the previous one. In the URL I am working with the id, so http://website.com/view/id/'video id here'/ So how can I get the ID of the following and previous episodes of the same season AND serie? Help will be much appreciated! The easiest thing I thought of is <?=$row['id'] + 1?> <?=$row['id'] - 1?> But the thing is that it's mixed videos, so it wont work 100%

    Read the article

  • php - replace array elements with another array's elements?

    - by Simpson88Keys
    Not sure how to go about this... But, I have two arrays, one with updated information, another with outdated information... There are a lot more elements in the second array, but I'm looking to "update" the outdated one with the updated information. Here's what the arrays look like: //Outdated Array ( [0] => Array ( [anum] => 3236468462 [cid] => 4899097762 [mid] => 1104881401 [na_title] => [na_fname] => JOHN [m_initial] => [na_lname] => DOE [na_suffix] => [na_addr1] => 1234 SAMPLE AVENUE [na_addr2] => [na_city] => NORWALK [state] => OH [zip] => [zip_plus_4] => [route] => R002 [dma_code] => 510334 ) ) //Updated Array ( [1] => Array ( [0] => YUD990 [1] => 98 [2] => 1234 Sample Avenue [3] => [4] => Norwalk [5] => OH [6] => 44857-9215 [7] => 3236468462 ) ) To clarify, I want to: (1) Match up the value for [7] from the updated array with the value for [anum] in the outdated array, and then update [na_addr1], [na_addr2], [na_city], [state], [zip], [zip_plus_4] in the outdated array with the values for [2],[3],[4],[5],[6] (I know I'll need to split the updated [6] in order to get it to map corrected to the outdated) Feel like I'm making this very confusing... sorry about that...

    Read the article

  • PHP urlize function

    - by Maxime
    Hello guys, I'm using this function on my website to transform user input into acceptable URL: function urlize($url) { $search = array('/[^a-z0-9]/', '/--+/', '/^-+/', '/-+$/' ); $replace = array( '-', '-', '', ''); return preg_replace($search, $replace, utf2ascii($url)); } function utf2ascii($string) { $iso88591 = "\\xE0\\xE1\\xE2\\xE3\\xE4\\xE5\\xE6\\xE7"; $iso88591 .= "\\xE8\\xE9\\xEA\\xEB\\xEC\\xED\\xEE\\xEF"; $iso88591 .= "\\xF0\\xF1\\xF2\\xF3\\xF4\\xF5\\xF6\\xF7"; $iso88591 .= "\\xF8\\xF9\\xFA\\xFB\\xFC\\xFD\\xFE\\xFF"; $ascii = "aaaaaaaceeeeiiiidnooooooouuuuyyy"; return strtr(mb_strtolower(utf8_decode($string), 'ISO-8859-1'),$iso88591,$ascii); } I'm having a problem with it though, with numbers. For some reason when I try: echo urlize("test 23342"); I get "test-eiioe". Why is that and how can I fix it? Thank you very much!

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 274 275 276 277 278 279 280 281 282 283 284 285  | Next Page >