Search Results

Search found 23821 results on 953 pages for 'mysql group by'.

Page 282/953 | < Previous Page | 278 279 280 281 282 283 284 285 286 287 288 289  | Next Page >

  • Some doubts about the use of usermod and groupmod command

    - by AndreaNobili
    I am not yet a true "Linux guy" and I have the following doubts about how exactly do the following shell procedure (a list of commands steps) founded in a tutorial that I am following (I want deeply understand what I am doing before do it): sudo passwd root then login again as root usermod -l miner pi usermod -m -d /home/miner miner groupmod -n miner pi exit So at the beginning it enable the root account and I have to login again in the system as root...this is perfectly clear for me. And now I have the followings doubts: 1) The usermod command: usermod -l miner pi usermod -m -d /home/miner miner Reading the official documentation of the usermod command I understand that this command modify the informations related to an existing account Reading the documentation it seems to me that the -l parmether modify the name of the user pi in miner and then the -m -d paramether move the contents of the old home directory to the new one (named miner) and use this new directory as home directory My doubt is: what exactly do the executions of these operation? I think that: Rename the existing pi user in miner Then move the content of the old home directory (the pi home directory? or what?) into a new directory (/home/miner) that now is the home directory for the miner user. Is it right? The the second doubt is related to this command groupmod -n miner pi It seems to me that change the group name from pi in miner But what exactly is a group in Linux and why is it used? Tnx

    Read the article

  • How to script GPO in Windows computers without Active Directory?

    - by Peteris Krumins
    Does anyone know how to script GPO for users in a Windows computer that is not on any Active Directory network? I can't use GPMC because it doesn't work without a domain. I have been searching the net for the last couple of hours and all the solutions that I find are related to GPMC. I'd imagine there are some objects in the GPO that are accessible via WMI? Does anyone know anything about that? I was unable to find any information about that. Here is the situation I am trying to script: I have 10 users on the machine, and I want to restrict what they are able to do on the machine. So I created 10 GPOs for each one of them. Now I want to apply a common policy to all of them. The only way to do it is to go through each of the GPO and do it manually. This is too time consuming, therefore I am seeking for a simpler solution. I was unable to find a way to copy GPO from a user to a user. That would make it much easier, I would create a GPO for 1st user, then copy it over to all the other users, but no luck, couldn't find a way to copy GPOs. The other method I tried was creating a GPO for the whole user group but it turns out you can't apply GPO to a group unless you use GPMC, which I can't cause the computer is not on any domain. So I am thinking about scripting this whole process, but again I can't find any examples of how to access particular GPO objects for particular users and modify properties through WMI. Any suggestions on the issue I am having? Thanks!

    Read the article

  • How to scrape a _private_ google group?

    - by John
    Hi there, I'd like to scrape the discussion list of a private google group. It's a multi-page list and I might have to this later again so scripting sounds like the way to go. Since this is a private group, I need to login in my google account first. Unfortunately I can't manage to login using wget or ruby Net::HTTP. Surprisingly google groups is not accessible with the Client Login interface, so all the code samples are useless. My ruby script is embedded at the end of the post. The response to the authentication query is a 200-OK but no cookies in the response headers and the body contains the message "Your browser's cookie functionality is turned off. Please turn it on." I got the same output with wget. See the bash script at the end of this message. I don't know how to workaround this. am I missing something? Any idea? Thanks in advance. John Here is the ruby script: # a ruby script require 'net/https' http = Net::HTTP.new('www.google.com', 443) http.use_ssl = true path = '/accounts/ServiceLoginAuth' email='[email protected]' password='topsecret' # form inputs from the login page data = "Email=#{email}&Passwd=#{password}&dsh=7379491738180116079&GALX=irvvmW0Z-zI" headers = { 'Content-Type' => 'application/x-www-form-urlencoded', 'user-agent' => "Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US) AppleWebKit/533.2 (KHTML, like Gecko) Chrome/6.0"} # Post the request and print out the response to retrieve our authentication token resp, data = http.post(path, data, headers) puts resp resp.each {|h, v| puts h+'='+v} #warning: peer certificate won't be verified in this SSL session Here is the bash script: # A bash script for wget CMD="" CMD="$CMD --keep-session-cookies --save-cookies cookies.tmp" CMD="$CMD --no-check-certificate" CMD="$CMD --post-data='[email protected]&Passwd=topsecret&dsh=-8408553335275857936&GALX=irvvmW0Z-zI'" CMD="$CMD --user-agent='Mozilla'" CMD="$CMD https://www.google.com/accounts/ServiceLoginAuth" echo $CMD wget $CMD wget --load-cookies="cookies.tmp" http://groups.google.com/group/mygroup/topics?tsc=2

    Read the article

  • How can I access the group of a linq group-by query from a nested repeater control?

    - by Duke
    I'm using a linq group by query (with two grouping parameters) and would like to use the resulting data in a nested repeater. var dateGroups = from row in data.AsEnumerable() group row by new { StartDate = row["StartDate"], EndDate = row["EndDate"] }; "data" is a DataTable from an SqlDataAdapter-filled DataSet. "dateGroups" is used in the parent repeater, and I can access the group keys using Eval("key.StartDate") and Eval("key.EndDate"). Since dateGroups actually contains all the data rows grouped neatly by Start/End date, I'd like to access those rows to display the data in a child repeater. To what would I set the child repeater's DataSource? I have tried every expression in markup I could think of; I think the problem is that I'm trying to access an anonymous member (and I don't know how.) In case it doesn't turn out to be obvious, what would be the expression to access the elements in each iteration of the child repeater? Is there an expression that would let me set the DataSource in the markup, or will it have to be in the codebehind on some event in the parent repeater?

    Read the article

  • How to parse the "<media:group>" using feedparser?

    - by Wayle.C
    The rss file is shown as below, i want to get the content in section media:group . I check the document of feedparser, but it seems not mention this. How to do it? Any help is appreciated. XYZ InfoX: Special hello http://www1.XYZInfoX.com/learninghello/home hello en Wed, 17 Mar 2010 08:50:06 GMT 2010-03-17T08:50:06Z en Voice of America http://www1.XYZInfoX.com/learninghello http://media.XYZInfoX.com/designimages/XYZRSSIcon.gif <item> <title>Who Were the Deadliest Gunmen of the Wild West?</title> <link>http://www1.XYZInfoX.com/learninghello/home/Deadliest-Gunmen-of-the-Wild-West-87826807.html</link> <description> The story of two of them: "Killin'" Jim Miller was an outlaw, "Texas" John Slaughter was a lawman | EXPLORATIONS </description> <pubDate>Wed, 17 Mar 2010 00:38:48 GMT</pubDate> <guid isPermaLink="false">87826807</guid> <dc:creator></dc:creator> <dc:date>2010-03-17T00:38:48Z</dc:date> *<media:group> <media:content url="http://media.XYZInfoX.com/images/archives_peace_comm_480_16mar_se.jpg" medium="image" isDefault="true" height="300" width="480" /> <media:content url="http://media.XYZInfoX.com/images/archives_peace_comm_230_16mar_se_edited-1.jpg" medium="image" isDefault="false" height="230" width="230" /> <media:content url="http://media.XYZInfoX.com/images/tex_trans_lawmans_230_16mar10_se.jpg" medium="image" isDefault="false" height="230" width="230" /> <media:content url="http://www.XYZInfoX.com/MediaAssets2/learninghello/dalet/se-exp-outlaws-part2-17mar2010.Mp3" type="audio/mpeg" medium="audio" isDefault="false" /> </media:group>* </item>

    Read the article

  • Fast way to get a list of group members in Active Directory with C#

    - by Jeremy
    In a web app, we're looking to display a list of sam accounts for users that are a member of a certain group. Groups could have 500 or more members in many cases and we need the page to be responsive. With a group of about 500 members it takes 7-8 seconds to get a list of sam accounts for all members of the group. Are there faster ways? I know the Active Directory Management Console does it in under a second. I've tried a few methods: 1) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); List<string> lst = grp.Members.Select(g => g.SamAccountName).ToList(); 2) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); PrincipalSearchResult<Principal> lstMembers = grp.GetMembers(true); List<string> lst = new List<string>(); foreach (Principal member in lstMembers ) { if (member.StructuralObjectClass.Equals("user")) { lst.Add(member .SamAccountName); } } 3) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); System.DirectoryServices.DirectoryEntry de = (System.DirectoryServices.DirectoryEntry)grp.GetUnderlyingObject(); List<string> lst = new List<string>(); foreach (string sDN in de.Properties["member"]) { System.DirectoryServices.DirectoryEntry deMember = new System.DirectoryServices.DirectoryEntry("LDAP://" + sDN); lst.Add(deMember.Properties["samAccountName"].Value.ToString()); }

    Read the article

  • (rsErrorOpeningConnection) Could not obtain information about Windows NT group/user

    - by ChelleATL
    I am trying to deploy a report to the Reporting Services Server but keep running up against this error: An error occurred during client rendering. An error has occurred during report processing. (rsProcessingAborted) Cannot create a connection to data source 'dataSource1'. (rsErrorOpeningConnection) Could not obtain information about Windows NT group/user 'DOMAIN\useradmin', error code 0x5. Here’s my situation: Everything is being ran using DOMAIN\useradmin and the report is using a remote database. Reporting Services and SQL Server are both ran under DOMAIN\useradmin. DOMAIN\useradmin is a windows AD login and is part of the server machine Administrators group. My test report is using a data source model that in turn is using a data source that is connection to a database on a different SQL Server. The data source is using “Credentials stored securely in the report server” with the options “Use as Windows credentials when connecting to the data source” and “Impersonate the authenticated user after a connection has been made to the data source.” I am using the credentials of DOMAIN\useradmin that is the db owner of the remote database. DOMAIN\useradmin is assigned the roles, System Administrator, System User and Browser, Content Manager, My Reports, Publisher, Report Builder. So if everything is being run under an über AD account, why I am getting this Could not obtain information about Windows NT group/user 'DOMAIN\useradmin' error? Under normal circumstances , an AD login with Publisher permissions will developing reports using a datasource model created by DOMAIN\useradmin but using one of the remote database’s users which is mapped from yet another AD login. I ran the following statements and non errors were returned: use master go xp_grantlogin 'DOMAIN\useradmin' go xp_logininfo 'DOMAIN\useradmin' go

    Read the article

  • How do I make a grouped select box grouped by a column for a given model in Formtastic for Rails?

    - by jklina
    In my Rails project I'm using Formtastic to manage my forms. I have a model, Tags, with a column, "group". The group column is just a simple hardcoded way to organize my tags. I will post my Tag model class so you can see how it's organized class Tag < ActiveRecord::Base class Group BRAND = 1 SEASON = 2 OCCASION = 3 CONDITION = 4 SUBCATEGORY = 5 end has_many :taggings, :dependent => :destroy has_many :plaggs, :through => :taggings has_many :monitorings, :as => :monitorizable validates_presence_of :name, :group validates_uniqueness_of :name, :case_sensitive => false def self.brands(options = {}) self.all({ :conditions => { :group => Group::BRAND } }.merge(options)) end def self.seasons(options = {}) self.all({ :conditions => { :group => Group::SEASON } }.merge(options)) end def self.occasions(options = {}) self.all({ :conditions => { :group => Group::OCCASION } }.merge(options)) end def self.conditions(options = {}) self.all({ :conditions => { :group => Group::CONDITION } }.merge(options)) end def self.subcategories(options = {}) self.all({ :conditions => { :group => Group::SUBCATEGORY } }.merge(options)) end def self.non_brands(options = {}) self.all({ :conditions => [ "`group` != ? AND `group` != ?", Tag::Group::SUBCATEGORY, Tag::Group::BRAND] }.merge(options)) end end My goal is to use Formtastic to provide a grouped multiselect box, grouped by the column, "group" with the tags that are returned from the non_brands method. I have tried the following: = f.input :tags, :required => false, :as => :select, :input_html => { :multiple => true }, :collection => tags, :selected => sel_tags, :group_by => :group, :prompt => false But I receive the following error: (undefined method `klass' for nil:NilClass) Any ideas where I'm going wrong? Thanks for looking :]

    Read the article

  • how to apply group by on xslt elements

    - by Amit
    Hello All, I need to group the value based on some attribute and populate it. below mentioned is i/p xml and if you see there are 4 rows for Users and for id 2,4 Division is same i.e. HR while generating actual o/p I need to group by Division ... Any help ??? I/P XML <Users> <User id="2" name="ABC" Division="HR"/> <User id="3" name="xyz" Division="Admin"/> <User id="4" name="LMN" Division="Payroll"/> <User id="5" name="PQR" Division="HR"/> </Users> expected Result: I need to group the values based on Division and populate i.e. <AllUsers> <Division value="HR"> <User> <id>2</id> <name>ABC</name> </User> <User> <id>5</id> <name>PQR</name> </User> </Division> <Division value="ADMIN"> <User> <id>3</id> <name>XYZ</name> </User> </Division> <Division value="Payroll"> <User> <id>4</id> <name>LMN</name> </User> </Division> </AllUsers>

    Read the article

  • Getting the first of a GROUP BY clause in SQL

    - by Michael Bleigh
    I'm trying to implement single-column regionalization for a Rails application and I'm running into some major headaches with a complex SQL need. For this system, a region can be represented by a country code (e.g. us) a continent code that is uppercase (e.g. NA) or it can be NULL indicating the "default" information. I need to group these items by some relevant information such as a foreign key (we'll call it external_id). Given a country and its continent, I need to be able to select only the most specific region available. So if records exist with the country code, I select them. If, not I want a records with the continent code. If not that, I want records with a NULL code so I can receive the default values. So far I've figured that I may be able to use a generated CASE statement to get an arbitrary sort order. Something like this: SELECT *, CASE region WHEN 'us' THEN 1 WHEN 'NA' THEN 2 ELSE 3 END AS region_sort FROM my_table WHERE region IN ('us','NA') OR region IS NULL GROUP BY external_id ORDER BY region_sort The problem is that without an aggregate function the actual data returned by the GROUP BY for a given row seems to be untameable. How can I massage this query to make it return only the first record of the region_sort ordered groups?

    Read the article

  • Permutations distinct under given symmetry (Mathematica 8 group theory)

    - by Yaroslav Bulatov
    Given a list of integers like {2,1,1,0} I'd like to list all permutations of that list that are not equivalent under given group. For instance, using symmetry of the square, the result would be {{2, 1, 1, 0}, {2, 1, 0, 1}}. Approach below (Mathematica 8) generates all permutations, then weeds out the equivalent ones. I can't use it because I can't afford to generate all permutations, is there a more efficient way? Update: actually, the bottleneck is in DeleteCases. The following list {2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 1, 1, 1, 0, 0, 0} has about a million permutations and takes 0.1 seconds to compute. Apparently there are supposed to be 1292 orderings after removing symmetries, but my approach doesn't finish in 10 minutes removeEquivalent[{}] := {}; removeEquivalent[list_] := ( Sow[First[list]]; equivalents = Permute[First[list], #] & /@ GroupElements[group]; DeleteCases[list, Alternatives @@ equivalents] ); nonequivalentPermutations[list_] := ( reaped = Reap@FixedPoint[removeEquivalent, Permutations@list]; reaped[[2, 1]] ); group = DihedralGroup[4]; nonequivalentPermutations[{2, 1, 1, 0}]

    Read the article

  • West Palm Beach Developers&rsquo; Group Celebrates its Fifth Anniversary as a Member of INETA

    - by Sam Abraham
    Earlier this week marked our fifth anniversary as an INETA group, a fact that we had forgotten but thankfully INETA remembered. In celebrating our membership, INETA sent us a certificate recognizing our membership which we will be sharing with our members at our upcoming meeting. It‘s been a great two-year tenure for me as group co-coordinator working with Venkat Subramanian who had been involved with the group since its inception. Moving into the future we hope to grow both group membership and leadership. We continue to strive to bring added value to our membership which can only happen with your ideas, feedback and involvement in our community-driven group. Our next almost sold-out meeting will be taking place on 8/28/2012 6:30PM (Register at: http://www.fladotnet.com/Reg.aspx?EventID=607) . Will Strohl, DotNetNuke’s Technical Evangelist will be presenting to us an overview on getting started with DNN’s latest 6.2 version all while taking us on a deep dive into its built-in social networking integration features. There is still time to register, but don’t procrastinate! Our September meeting will feature Jonas Stawski, Microsoft MVP sharing with us on SignalR while October will bring us the much anticipated visit by our Microsoft Developer Evangelist Joe Healy who will be talking to us about the latest with Windows 8. Joe will be also presenting in Miami the next day after our event in case you miss his West Palm appearance. We look forward to meeting you at our upcoming meetings. All the best --Sam Abraham

    Read the article

  • Calculate Age using Date Field

    - by BRADINO
    So if you have a database table that has DOB borthdays as date fields, this is an easy way to query that table based on age parameters. The following examples assume that the date of birth date field is dob and the table name is people. Find people who are 30 years old SELECT DATE_FORMAT( FROM_DAYS( TO_DAYS( now( ) ) - TO_DAYS( `dob` ) ) , '%Y' ) +0 AS `age` FROM `people` HAVING `age` = 30 Find people who are 31-42 years old SELECT DATE_FORMAT( FROM_DAYS( TO_DAYS( now( ) ) - TO_DAYS( `dob` ) ) , '%Y' ) +0 AS `age` FROM `people` HAVING `age`>= 31 AND `age` <= 42 Find oldest person SELECT MAX(DATE_FORMAT( FROM_DAYS( TO_DAYS( now( ) ) - TO_DAYS( `dob` ) ) , '%Y' ) +0) AS `age` FROM `people` Find youngest person SELECT MIN(DATE_FORMAT( FROM_DAYS( TO_DAYS( now( ) ) - TO_DAYS( `dob` ) ) , '%Y' ) +0) AS `age` FROM `people`

    Read the article

  • Advice for good web server development setup.

    - by John Berryman
    A month or so ago I created my first LAMP stack and implemented a simple web site that exercised each letter in that acronym. However my development setup was much less than ideal. I don't really have a local test server, but instead I was writing all of my CGI scripts in vim while ssh'ed into the remote machine as root. Now I intend to start more serious development. Question: What is a good setup so that development goes as easily as possible? I would like to understand what is available to me along the lines of an IDE, subversion (or alternatives), uploading and downloading content, and just best practices. I'm pretty new at all of this. Also, feel free to point me at good websites. There's plenty of websites, but only people who are already heavily developing web content are able to quickly determine if they are good websites.

    Read the article

  • Oracle VM Administration: Oracle VM Server for x86 - new Training

    - by Antoinette O'Sullivan
     Oracle VM Administration: Oracle VM Server for x86 - new course just released. This 3 day hands-on course teaches students how to build a virtualization platform using the Oracle VM Manager and Oracle VM Server for x86. Students learn how deploy and manage highly configurable, inter-connected virtual machines. The course teaches students how to install and configure Oracle VM Server for x86 as well as details of network and storage configuration, pool and repository creation, and virtual machine management. You can follow this class that brings you great hands-on experience either in-class or from your own desk.

    Read the article

  • I have written an SQL query but I want to optimize it [closed]

    - by ankit gupta
    is there any way to do this using minimum no of joins and select? 2 tables are involved in this operation transaction_pci_details and transaction SELECT t6.transaction_pci_details_id, t6.terminal_id, t6.transaction_no, t6.transaction_id, t6.transaction_type, t6.reversal_flag, t6.transmission_date_time, t6.retrivel_ref_no, t6.card_no,t6.card_type, t6.expires_on, t6.transaction_amount, t6.currency_code, t6.response_code, t6.action_code, t6.message_reason_code, t6.merchant_id, t6.auth_code, t6.actual_trans_amnt, t6.bal_card_amnt, t5.sales_person_id FROM TRANSACTION AS t5 INNER JOIN ( SELECT t4.transaction_pci_details_id, t4.terminal_id, t4.transaction_no, t4.transaction_id, t4.transaction_type, t4.reversal_flag, t4.transmission_date_time, t4.retrivel_ref_no, t4.card_no, t4.card_type, t4.expires_on, t4.transaction_amount, t4.currency_code, t4.response_code, t4.action_code, t3.message_reason_code, t4.merchant_id, t4.auth_code, t4.actual_trans_amnt, t4.bal_card_amnt FROM ( SELECT* FROM transaction_pci_details WHERE message_reason_code LIKE '%OUT%'|| message_reason_code LIKE '%FAILED%' /*we can add date here*/ UNION ALL SELECT t2.transaction_pci_details_id, t2.terminal_id, t2.transaction_no, t2.transaction_id, t2.transaction_type, t2.reversal_flag, t2.transmission_date_time, t2.retrivel_ref_no, t2.card_no, t2.card_type, t2.expires_on, t2.transaction_amount, t2.currency_code, t2.response_code, t2.action_code, t2.message_reason_code, t2.merchant_id, t2.auth_code, t2.actual_trans_amnt, t2.bal_card_amnt FROM ( SELECT transaction_id FROM TRANSACTION WHERE transaction_type_id = 8 ) AS t1 INNER JOIN ( SELECT * FROM transaction_pci_details WHERE message_reason_code LIKE '%appro%' /*we can add date here*/ ) AS t2 ON t1.transaction_id = t2.transaction_id ) AS t3 INNER JOIN ( SELECT* FROM transaction_pci_details WHERE action_code LIKE '%REQ%' /*we can add date here*/ ) AS t4 ON t3.transaction_pci_details_id - t4.transaction_pci_details_id = 1 ) AS t6 ON t5.transaction_id = t6.transaction_id

    Read the article

  • Post SQL 2008 R2 Launch Thurs 15th London - UK SQL Server User Group is having a Social Event @ the

    - by tonyrogerson
    The UK SQL Server User Group is organising a Social event for SQL and SQL Server professionals, the event will be held after the SQL Server 2008 R2 launch event and is a short walk from that venue. See site for more information: http://sqlserverfaq.com/events/222/Social-for-SQL-and-SQL-Server-professionals-SQL-quiz-meet-your-peers-ask-the-group-Q-A.aspx We are putting some light bites on, if you are coming then do let us know through the site. Neil Hambly who is the London UK SQL Server User Group...(read more)

    Read the article

  • mp3 file streaming/download - apache server memory issue

    - by Manolis
    I have a website, in which users can upload mp3 files (uploadify), stream them using an html5 player (jplayer) and download them using a php script (www.zubrag.com/scripts/). When a user uploads a song, the path to the audio file is saved in the database and i'm using that data in order to play and show a download link for the song. The problem that i'm experiencing is that, according to my host, this method is using a lot of memory on the server, which is dedicated. Link to script: http://pastebin.com/Vus8SRa7 How should I handle the script properly? And what would be the best way to track down the problem? Any ideas on cleaning up the code? Any help much appreciated.

    Read the article

  • Inserting data to database from Android

    - by Angel
    I have to build an application where the requirement is that my clients will send data from their Android device and I have to save that data to a database. I have done the part of coding that inserts data from Android emulator to my XAMPP database on localhost, now I have to implement the real thing. How can I connect the devices where my application will be installed to the XAMPP database I have created so that the data they send can be inserted into it?

    Read the article

  • Correct DB details produce “Database server was not found” (Prestashop Installation)

    - by Steve
    At stage 3 of the Prestashop Installation, I enter the DB details which I know to be correct, and I receive the error: Database server was not found. Please verify the login, password, and database server name fields. The server is localhost, and I have verified the database name and username. Why can Prestashop not find the server? This occurs when choosing InnoDB and MyIsam. If I change the server from localhost to the public hostname I receive the same error.

    Read the article

  • embedding LEFT OUTER JOIN within INNER JOIN

    - by user3424954
    I am having some problems with one of the question's answered in the book "SQL FOR MERE MORTALS". Here is the problem statement Here is the Database Structure Here is the answer which I am unable to comprehend Here is an answer which looks perfect to me Now the problem with the first answer I am having is: We first use LEFT OUTER JOIN for recipe class and recipes. So it selects all recipe class rows but only matching recipes. Perfecty fine as the question is demanding. Lets call this result set R. Now in the next step when we use INNER JOIN to join RecipieIngridients, it should filter out the rows from R in which Recipie ID doesn't match with the Recipe Id in Recipie Ingredients and hence filtering out the related Recipe class and recipe description also(Since it filters out the entire row of R). So this contradicts with the problem which demands all recipieID and RecipieDescription to be displayed from Recipe_Classes Table in this very step only. How can it be correct. Or Am i Missing some concept.

    Read the article

  • Should all foreign table references use foreign key constraints

    - by TecBrat
    Closely related to: Foreign key restrictions -> yes or no? I asked a question on SO and it led me to ask this here. If I'm faced with a choice of having a circular reference or just not enforcing the restraint, which is the better choice? In my particular case I have customers and addresses. I want an address to have a reference to a customer and I want each customer to have a default billing address id and a default shipping address id. I might query for all addresses that have a certain customer ID or I might query for the address with the ID that matches the default shipping or billing address ids. I'm not sure yet how the constraints (or lack of) will effect the system as my application and it's data age.

    Read the article

  • Having a generic data type for a database table column, is it "good" practice?

    - by Yanick Rochon
    I'm working on a PHP project where some object (class member) may contain different data type. For example : class Property { private $_id; // (PK) private $_ref_id; // the object reference id (FK) private $_name; // the name of the property private $_type; // 'string', 'int', 'float(n,m)', 'datetime', etc. private $_data; // ... // ..snip.. public getters/setters } Now, I need to perform some persistence on these objects. Some properties may be a text data type, but nothing bigger than what a varchar may hold. Also, later on, I need to be able to perform searches and sorting. Is it a good practice to use a single database table for this (ie. is there a non negligible performance impact)? If it's "acceptable", then what could be the data type for the data column?

    Read the article

  • Jokes search engine / PHP based search engine on database

    - by matt74tm
    I'm looking for a script, functioning like the Google homepage that fetches data from a database rather than the internet. This is not intended to be a search engine, but a repository of jokes that can be pulled depending on the keywords typed. No sophisticated search techniques are required - keyword based is perfectly fine. If some mechanism of up/down-voting jokes can be incorporated, that would be fantastic, but I'm presuming that will be an entirely different game.

    Read the article

< Previous Page | 278 279 280 281 282 283 284 285 286 287 288 289  | Next Page >