Search Results

Search found 57023 results on 2281 pages for 'object to string'.

Page 282/2281 | < Previous Page | 278 279 280 281 282 283 284 285 286 287 288 289  | Next Page >

  • Regular Expression to match a string

    - by Adam Witko
    Hi, I've got two possible string inputs that my application will receive, and if it matches the following two strings, I need it regex.ismatch() to return true: "User * has logged out" "User * has joined" I'm not that good at regex and just can't figure out how to go about matching the above. Any help would be great!!!

    Read the article

  • Java lang object

    - by Neeraj
    why java Object class has two methods hashcode() and equals()? One of them looks redundant and its percolated to the bottom most derived class?

    Read the article

  • a string doesn't exist in the current context

    - by Strider007
    the following is a part of my code. string lsStatus; lsStatus = ((Tv10DBLookup)(Sender)).EditValue.ToString(); while im debuging the code, im getting the following: "lsStatus is not in the context" ! Knowing that (Tv10DBLookup)(Sender)).EditValue is returning the value "Closed" what does this mean ?

    Read the article

  • managed object subclasses are not generating implementation files and are incorrectly named

    - by mkc842
    In Xcode 4.6, I generated plenty of managed object subclass files without any problem. But now that I'm trying to do it in Xcode 5, it generates only a .h file. The header file has the correct properties, but it takes the name of my project, rather than the name of the core data entity I selected. Just to be sure I hadn't forgotten something, I carefully followed these steps . What could be going on? Thanks

    Read the article

  • Is `std::string(strerror(errno))` dangerous?

    - by StackedCrooked
    At some places in my code, I print debug messages like this: int ret = getLinkSpeed(device.getSysName(), linkSpeed); if (ret < 0) { logDebug("Failed to obtain port speed for this device. Error: " + std::string(strerror(errno))); } From the documentation it is not entirely clear if strerror will return 0 under certain conditions (which would cause my code to crash). Does anyone know if it's safe?

    Read the article

  • Accessing class variable with string name?

    - by coure06
    I have a class like this $.fn.dimeBar = function(custom) { var var1 = 'test1'; var var2 = 'test2'; if(sometest){ //how can i access var1 or var2 here by using string name of variables //some thing like alert(this['var1']) -- should alert: 'test1' } }

    Read the article

  • Find out which object being added to NSMutableArray is nil

    - by Raphael Caixeta
    I started a project using ARC, and I'm inserting a few objects into an NSMutableArray. The objects have all started out as NSStrings, and when attempting to add these objects into the array, I get the following error: Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: ' -[__NSArrayM insertObject:atIndex:]: object cannot be nil This array is holding several objects. Is there a quick way for me to find which of the objects I'm attempting to put into the array is nil?

    Read the article

  • string concatenation in Groovy seems unconvenient

    - by Zombies
    My goal is to write this: println "this should be 3: ($1+2)" //this is invalid groovy, it won't run Yet this is valid in ruby. Is there a way I can put statements that will eval inside a string or must I use complete variables names? I am basically looking for the Ruby equivalent of: puts "this shoud be 3: #{1+2}" #this is valid ruby

    Read the article

  • Sorting an object?

    - by dfjhdfjhdf
    How to sort this object lexicographically by its keys: var obj = {'somekey_B' : 'itsvalue', 'somekey_A' : 'itsvalue'); so that it outputs like this: for (k in obj) { alert(k + ' : ' + obj[k]); //first "somekey_A : itsvalue"; then "somekey_B : itsvalue" }

    Read the article

  • object reference set in java

    - by landon9720
    I need to create a Set of objects. The concern is I do not want to base the hashing or the equality on the objects' hashCode and equals implementation. Instead, I want the hash code and equality to be based only on each object's reference identity (i.e.: the value of the reference pointer). I'm not sure how to do this in Java. The reasoning behind this is my objects do not reliably implement equals or hashCode, and in this case reference identity is good enough.

    Read the article

  • Problem with Javascript object and accessing property which exists

    - by Newbie
    I have something like this: var test = {}; function blah() { test[2] = 'filled'; } console.log(test); //result test -> 2:"filled" console.log(test[2]); //result undefined I don't understand why I'm getting 'undefined' in the second instance when according to the first instance, the property of that object clearly exists! Does anyone have any ideas? Thanks

    Read the article

  • .NET & Worflow, SqlTrackingQuery.GetWorkflows() on wire correct - presented object not

    - by UKShots
    With windows workflow when using the tracking service, the SqlTrackingQuery.GetWorkflows() method returns correctly the workflow type and assembly version on the wire from the DB query - but when one comes to query the returned SqlTrackingWorkflowInstance object it's WorkflowType.AssemblyQualifiedName property is returned as the current assembly version of the workflow type (i.e. it looks to matching on FQ type name only and not version). Anyone know how to get to the actual returned data (other than either a custom query or hook)?

    Read the article

  • Loop through array, print with string.

    - by Adam
    I have a simple array like: var myArr=["one","two","three"]; an I have a counting loop, which increases the value of var i by one. What I want to do is print the next value from the array each time the loop runs, next to a text string, like so: alert('value number '+myArr[i]+); But for some reason I can't get this to work. The following code works, so I'm assuming I'm not calling the counter right: alert('value number '+myArr[0]+);

    Read the article

< Previous Page | 278 279 280 281 282 283 284 285 286 287 288 289  | Next Page >